Which expressions represent the length of side MN?



Choose 2 answers:



A. 4 • sin (65)



B. 1. 9 • cos (65)



C. 4/sin (65)



D. 1. 9/cos (65)



PLEASE HELP!!

In a circle with a 44 degree central angle, the minor arc MPQ's angle measure is 316 degrees.

We must first get the measure of the central angle MNQ that intercepts this arc in order to determine the measure of the minor arc MPQ. Because minor arc MPQ and minor arc MP are next to each other, their sum equals the minor arc MPNQ's measure.

MPNQ = MPQ + arc MP

If we substitute 44 degrees for the minor arc's measurement (MP), we obtain,

∠MPQ + 44 = 360

When we solve for MPQ, we obtain, ∠MPQ = 360 - 44

MPQ equals 316 degrees. As a result, 316 degrees is the minor arc MPQ's measure.

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the intersection point is approximately (2.215421, 3.256684). For the first question, the initial value problem is given by the differential equation f'(u) = 5(cost - sinus) with the initial condition f(3xN) = 3.

To solve this problem, we can separate the variables and integrate both sides as follows:

f'(u) = 5(cosu - sinu)
∫ f'(u) du = ∫ 5(cosu - sinu) du
f(u) = 5sinu + 5cosu + C

Using the initial condition f(3xN) = 3, we can solve for the constant C:

f(3xN) = 5sin(3xN) + 5cos(3xN) + C = 3
C = 3 - 5sin(3xN) - 5cos(3xN)

Thus, the solution to the initial value problem is given by:

f(u) = 5sinu + 5cosu + 3 - 5sin(3xN) - 5cos(3xN)

For the second question, we are asked to find the intersection points of the two curves y = 16/* and y = x + 1 using Newton's method. To applyhttps://brainly.com/question/2228446 we need to find the function f(x) that represents the difference between the two curves:

f(x) = 16/x - (x + 1)

The intersection points correspond to the roots of f(x), which can be found using Newton's method:

x_{n+1} = x_n - f(x_n)/f'(x_n)

where x_n is the nth approximation of the root. We start with an initial guess of x_0 and iterate until we reach a desired level of accuracy. For example, if we start with x_0 = 1, the iterations are as follows:

x_1 = 1 - (16/1 - (1 + 1))/(16/1^2 + 1) = 2.5
x_2 = 2.5 - (16/2.5 - (2.5 + 1))/(16/2.5^2 + 1) = 2.267857
x_3 = 2.267857 - (16/2.267857 - (2.267857 + 1))/(16/2.267857^2 + 1) = 2.219208
x_4 = 2.219208 - (16/2.219208 - (2.219208 + 1))/(16/2.219208^2 + 1) = 2.215430
x_5 = 2.215430 - (16/2.215430 - (2.215430 + 1))/(16/2.215430^2 + 1) = 2.215421

Thus, the intersection point is approximately (2.215421, 3.256684).

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The expression that is equivalent is as shown in option J

The equivalent expression is solved using the exponents or powers

The power relationship represented by the equation (c⁸(d⁶)³) / c² is division and multiplication

The division deals with c and we have

(c⁸(d⁶)³) / c² = (c³(d⁶)³)

The multiplication dal with d and we have

(c⁶(d⁶)³) = (c⁶(d¹⁸)

hence we have the correction option as J (c⁶(d¹⁸)

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The expression for the given statement is √3².

We have,

The expression that can be written from the statement.

3 square root = √3

Second power of x = x²

Now,

We can write the expression as,
= √3²

Thus,

The expression for the given statement is √3².

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Answer:

Step-by-step explanation:

12 ÷ 2 × 3 − ( 7 − 5 )

= 6 × 3 - 2 (since 7 - 5 = 2)

= 18 - 2

= 16

Answer is C

The value of the expression is 16.

The order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction), is a set of rules used to determine the sequence in which calculations are performed.

In this case, we start with the parentheses first: 7 - 5 = 2. Then, we perform multiplication and division from left to right: 12 ÷ 2 = 6, 6 × 3 = 18. we subtract the result of the parentheses: 18 - 2 = 16. Therefore, the answer is c. 16.

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Answer:

when it's maintain supplimentary , it means that the sum of the angles given is 180° , In this case let one of the angle be x and the other is given as 125° .

therefore

125° + x = 180°

x = 180° - 125° = 55°

the compliment of x is the angle which when added to x givens 90° , Let the angle be y.

therefore

x + y = 90°

y = 90° - x = 90° - 55° = 35°

35° is the answer

Becky is currently 38 years old and Joey is currently 18 years old.

Let's start by assigning variables to their ages. Let Joey's age be "J" and Becky's age be "B".

From the first piece of information, we know that Joey is 20 years younger than Becky. This can be expressed as:

J = B - 20

Now, let's use the second piece of information. In two years, Becky will be twice as old as Joey. So, we can set up an equation:

B + 2 = 2(J + 2)

We add 2 to Becky's age because in two years she will be that much older. On the right side, we add 2 to Joey's age because he will also be two years older. Then we multiply Joey's age by 2 because Becky will be twice his age.

Now, we can substitute the first equation into the second equation:

B + 2 = 2((B - 20) + 2)

Simplifying the right side:

B + 2 = 2B - 36

Add 36 to both sides:

B + 38 = 2B

Subtract B from both sides:

38 = B

So, Becky is currently 38 years old. Using the first equation, we can find Joey's age:

J = B - 20
J = 38 - 20
J = 18

So, Joey is currently 18 years old.

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The cucumber is also considered a vegetable due to its culinary usage in salads and savory dishes.

Vegetables are edible plants that are commonly used as a food source. They are a primary source of vitamins, minerals, fiber, and other nutrients that are important for maintaining good health.

From a biological perspective, Sheila would most likely classify the apples and lemons as fruits. In botanical terms, fruits are the mature ovary of a flowering plant, containing seeds. Both apples and lemons contain seeds and develop from the ovary of a flower, so they are classified as fruits. The tomato and cucumber, on the other hand, are classified as vegetables.

While the tomato also develops from the ovary of a flower and contains seeds, it is considered a vegetable in culinary terms due to its savory flavor and common usage in savory dishes.

Therefore, The cucumber is also considered a vegetable due to its culinary usage in salads and savory dishes.

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Answer:

The answer to your problem is, 259,644

Step-by-step explanation:

an = 1880 ( it 25% [tex])^{t}[/tex]

= 1880 x (1.25[tex])^{t}[/tex]

ai = 1880, r will equal 1.25

Sn = [tex]\frac{aill-r^{4} }{l = r}[/tex]

[tex]S_{16}[/tex] = [tex]\frac{1880(l-1.25^{16}) }{l - 1.25}[/tex]

= 259,644

Thus the answer to your problem is, 259,644

The expression a⁻¹³/a⁻⁶ can be written as a⁻⁷ in aⁿ form.

We have been given the expression

a⁻¹³/a⁻⁶

We know that whenever there is a minus sign in the power, we need to consider a reciprocal of the number

Hence,

a⁻¹³ will become 1/a¹ and a⁻⁶ will become 1/a⁶

Hence the numerator and denominator will interchange to get

a⁶/a¹³

Now, we know that when a number is broght from denominator to the numerator, there is a minus sign added to the power. Hence we will get

a⁶ X a⁻¹³

Since the two numbers have the same base- a, we can add the powers up as there is multiplication sign in between to get

a⁶ ⁺ ⁽⁻¹³⁾

= a⁶ ⁻ ¹³

= a⁻⁷

Hence, the expression a⁻¹³/a⁻⁶ can be written as a⁻⁷ in aⁿ form.

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After 6 hours, approximately 19.66 milligrams of the drug will remain in the patient's bloodstream.


To find the remaining amount of the drug in the patient's bloodstream after 6 hours, we'll use the decay function given: A(t) = P(1 - r)^t, where:

- A(t) is the remaining amount after t hours
- P is the initial amount (75 milligrams in this case)
- r is the decay rate per hour (20% or 0.20)
- t is the number of hours (6 hours)

Step 1: Plug in the given values into the formula.
A(t) = 75(1 - 0.20)^6

Step 2: Calculate the expression inside the parentheses.
1 - 0.20 = 0.80

Step 3: Replace the expression in the formula.
A(t) = 75(0.80)^6

Step 4: Raise 0.80 to the power of 6.
0.80^6 ≈ 0.2621

Step 5: Multiply the result by the initial amount.
A(t) = 75 × 0.2621 ≈ 19.66

So, approximately 19.66 milligrams of the drug will remain in the patient's bloodstream after 6 hours, rounded to the nearest hundredth.

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The radius of the circular fountain is approximately 17 feet.

The formula for the volume of a circular fountain is given by V = πr^2h, where V is the volume, r is the radius, and h is the depth. In this case, we are given that the depth of the fountain is 3 feet and the volume is 1800 cubic feet. So we can plug in these values into the formula and solve for r as follows:

1800 = πr^2(3)

Simplifying this equation, we get:

r^2 = 600/π

Taking the square root of both sides, we get:

r = sqrt(600/π)

Using a calculator to approximate the value of sqrt(600/π), we get:

r ≈ 17

Therefore, the radius of the circular fountain is approximately 17 feet when rounded to the nearest whole number.

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i) T3(x) = 1 + x + x^2 + x^3/3

ii) R3(x) = x^4/4 + x^5/5

iii) The maximum value of f(4)(x) on the interval |x| ≤ 0.1 is 144.

iv) Yes, Taylor's inequality holds true for R3(0.1) since the maximum value of f(4)(x) on the interval |x| ≤ 0.1 is less than or equal to 144, which is smaller than the upper bound of 625/24.

i) To find T3(x), we start by calculating the derivatives of f(x) up to order 3:

f(x) = 1 + x + x^2 + x^3 + x^4 + x^5

f'(x) = 1 + 2x + 3x^2 + 4x^3 + 5x^4

f''(x) = 2 + 6x + 12x^2 + 20x^3

f'''(x) = 6 + 24x + 60x^2

Then, we evaluate these derivatives at x = 0:

f(0) = 1

f'(0) = 1

f''(0) = 2

f'''(0) = 6

Using these values, we can write the Taylor polynomial of f at x = 0 with degree 3 as:

T3(x) = f(0) + f'(0)x + f''(0)x^2/2 + f'''(0)x^3/6

= 1 + x + x^2 + x^3/3

ii) To find R3(x), we use the remainder formula for Taylor polynomials:

R3(x) = f(x) - T3(x)

Substituting f(x) and T3(x) into this formula and simplifying, we get:

R3(x) = x^4/4 + x^5/5

iii) To find the maximum value of f(4)(x) on the interval |x| ≤ 0.1, we first calculate the fourth derivative of f(x):

f(x) = 1 + x + x^2 + x^3 + x^4 + x^5

f''''(x) = 24 + 120x

Then, we evaluate this derivative at x = ±0.1 and take the absolute value to find the maximum value:

|f(4)(±0.1)| = |24 + 12| = 36

Since 36 is the maximum value of f(4)(x) on the interval |x| ≤ 0.1, we know that the upper bound for the remainder formula is 625/24.

iv) Taylor's inequality states that the absolute value of the remainder Rn(x) for a Taylor polynomial of degree n at a point x is bounded by a constant multiple of the (n+1)th derivative of f evaluated at some point c between 0 and x. Specifically, we have:

|Rn(x)| ≤ M|x-c|^(n+1)/(n+1)!

where M is an upper bound for the (n+1)th derivative of f on the interval containing x.

In this case, we have n = 3, x = 0.1, and c = 0. The (n+1)th derivative of f is f(4)(x) = 24 + 120x.

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Answer:

Step-by-step explanation:

DE/EC.

Just-in-time (JIT) delivery is a supply chain management strategy that aims to improve efficiency and reduce inventory costs by having materials and goods delivered exactly when they are needed in the production process.

This approach requires suppliers to be able to respond to the customer's production schedule, ensuring timely deliveries to prevent disruptions. As a result, JIT delivery shifts greater responsibility for physical distribution activities from the supplier to the business customer, who needs to closely monitor inventory levels and maintain efficient communication with suppliers.

However, JIT delivery does not typically lead to larger, less frequent deliveries, nor does it inherently increase physical distribution costs. In fact, it may reduce costs by minimizing inventory storage expenses. Additionally, e-commerce order systems and computer networks are often utilized to facilitate the communication and coordination required for effective JIT delivery.

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71.38 in word form is Seventy-one and thirty-eight hundredths.

What is the decimal number?

The accepted method for representing both integer and non-integer numbers is the decimal numeral system. Decimal notation is the term used to describe the method of representing numbers in the decimal system.

A number is a numerical unit of measurement and labeling in mathematics. The natural numbers 1, 2, 3, 4, and so on are the first examples. Number words are a linguistic way to express numbers.

To write decimals in word form, you can read the whole number part, write "and," and then read the decimal part according to place value.

For example: 0.25 can be written as "zero and twenty-five hundredths"

Hence, the correct answer is 'D. Seventy-one and thirty-eight hundredths'.

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There are infinitely many possible solutions for the lengths of the three sides of the triangle.

What is triangle?

A triangle is a three-sided polygon with three angles. It is a fundamental geometric shape and is often used in geometry and trigonometry.

If we call x the length of the smallest side, then the other two sides are x+1 and x+2 (since they are three consecutive integers). According to the triangle inequality, the sum of any pair of sides must be greater than the length of the third side.

Therefore, we have:

x + (x+1) > (x+2) (and also x + (x+2) > (x+1) and (x+1) + (x+2) > x)

Simplifying each inequality, we get:

2x + 1 > x + 2 (and also 2x + 2 > x + 1 and 2x + 3 > x)

Which gives:

x > 1

So the smallest side must be greater than 1 cm.

Now, to find the length of the three sides, we can choose any value greater than 1 for x. For example, if we take x=2, then the three sides are:

2 cm, 3 cm, and 4 cm

If we take x=3, then the three sides are:

3 cm, 4 cm, and 5 cm

And so on. Therefore, there are infinitely many possible solutions for the lengths of the three sides of the triangle.

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To show that the decision boundary of the CLOSE classifier is a linear hyperplane, we need to show that it can be represented as sign(w · x + b), where w is the weight vector, b is the bias term, and sign is the sign function that outputs +1 or -1 depending on whether its argument is positive or negative.

Let x be a test example, and let d+ = ||x - C+|| be the distance from x to the center of the positive examples, and d- = ||x - C-|| be the distance from x to the center of the negative examples. The CLOSE classifier assigns x to the positive class if d+ < d-, and to the negative class otherwise. Equivalently, it assigns x to the positive class if

||x - C+[tex]||^2[/tex] - ||x - C-[tex]||^2[/tex] < 0.

Expanding the squares and simplifying, we get

(x · x - 2C+ · x + C+ · C+) - (x · x - 2C- · x + C- · C-) < 0,

which is equivalent to

2(w · x) + (C+ · C+ - C- · C-) - 2(w · (C+ - C-)) < 0,

where w = C+ - C- is the vector pointing from the center of the negative examples to the center of the positive examples. Rearranging, we get

w · x + b < 0,

where b = (C- · C-) - (C+ · C+) is a constant.

Thus, the decision boundary of the CLOSE classifier is a hyperplane defined by the equation w · x + b = 0, and the classifier assigns a test example x to the positive class if w · x + b > 0, and to the negative class otherwise.

To compute the values of w and b in terms of C+ and C-, we can use the definition of w and b above. We have

w = C+ - C-,

b = (C- · C-) - (C+ · C+).

To compute the dual weights α's, we need to solve the dual optimization problem for the support vector machine (SVM) with a linear kernel:

minimize 1/2 ||w||^2 subject to yi(w · xi + b) >= 1 for all i,

where yi is the class label of the i-th training example, and xi is its feature vector. The dual problem is

maximize Σi αi - 1/2 Σi Σj αi αj yi yj xi · xj subject to Σi αi yi = 0 and αi >= 0 for all i,

where αi is the dual weight corresponding to the i-th training example. The number of support vectors is the number of training examples with nonzero dual weights.

In our case, the training examples are the positive and negative centers C+ and C-, so we have n+ + n- = 2 training examples. The feature vectors are simply the centers themselves, so xi = C+ for i = 1 and xi = C- for i = 2. The class labels are yi = +1 for i = 1 (positive example) and yi = -1 for i = 2 (negative example). Plugging these into the dual problem, we get

maximize α1 - α2 - 1/2 α[tex]1^2[/tex] d(C+, C+) - 2α1α2 d(C+, C-) - 1/2 α[tex]2^2[/tex] d(C-, C-) subject to α1 - α2 = 0 and α1,

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Answer:

Triangles: 4(1/2)(12)(10) = 240 ft^2

Square: 10^2 = 100 ft^2

Total Surface Area: 340 ft^2

In 2029, there will be an estimated A, 8.66 billion people in the world.

C, t = (ln(N/N₀))/k is the equation rewritten to solve for t.

Part A:

Using the given exponential growth model, find the population in 2029 as follows:

N = N₀e^kt

N₀ = 7.95 billion (present population)

k = 1.08% = 0.0108 (rate of increase)

t = 2029 - 2022 = 7 (number of years)

N = 7.95 billion × e^(0.0108×7)

N ≈ 8.66 billion

Therefore, the world's population is expected to be 8.66 billion in 2029. Answer choice A is correct.

Part B:

To solve for t, isolate it on one side of the exponential growth model equation. Taking the natural logarithm of both sides:

ln(N/N₀) = kt

Divide both sides by k:

t = ln(N/N₀)/k

Therefore, the equation rewritten to solve for t is t = (ln(N/N₀))/k. Answer choice C is correct.

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For question 2, the zoologists can conduct an analysis of variance (ANOVA) test to investigate whether the four different diets impact the weight gains of the 6-month baby elephants. The ANOVA test will compare the mean weight of each diet group to determine if there is a statistically significant difference between them. If the test shows that there is a significant difference, then the zoologists can conclude that the diets are impacting the weight gains of the baby elephants.

For question 3, the researchers can also conduct an ANOVA test to investigate whether the nursery locations affect the growth of oak trees. The test will compare the mean circumference growth of the oak trees at each nursery location to determine if there is a statistically significant difference between them. If the test shows that there is a significant difference, then the researchers can conclude that the nursery locations are impacting the growth of the oak trees.

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ABC4 base 16 is equal to 43972 in base ten (decimal).

In order to represent any given number, numerals might be numbers, symbols, figures, or sets of figures.

To convert the number ABC4 base 16 to a numeral in base ten (decimal), we can use the positional notation system. Each digit in the number represents a power of 16, starting from the rightmost digit.

The rightmost digit is 4, which represents 4 x 16⁰ = 4 x 1 = 4.

The next digit is C, which represents 12 (since C is equivalent to the decimal number 12), and it is in the second position from the right. So the value of the second digit is 12 x 16¹ = 12 x 16 = 192.

The next digit is B, which represents 11, and it is in the third position from the right. So the value of the third digit is 11 x 16² = 11 x 256 = 2816.

The leftmost digit is A, which represents 10, and it is in the fourth position from the right. So the value of the fourth digit is 10 x 16³ = 10 x 4096 = 40960.

Now we can add up the values of each digit to get the decimal equivalent of the number:

4 + 192 + 2816 + 40960 = 43972

Therefore, ABC4 base 16 is equal to 43972 in base ten (decimal).

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Mandy's home computer system is expected to be worth $1,576.11.

Mandy's home computer system is expected to depreciate at a rate of 10% per year. After 1 year, the value of the computer system will be 90% of its original value.

After 2 years, it will be worth 90% of that value, or 0.9 × 0.9 = 0.81 times the original value. Continuing in this way, we can write the value of the computer system after n years as [tex]0.9^n[/tex] times its original value. Thus, after 9 years, the computer system will be worth [tex]0.9^n[/tex] times its original value:

Value after 9 years = 4995 × [tex]0.9^n[/tex]

Using a calculator, we find that the value is approximately $1,576.11 when rounded to the nearest hundredth. Therefore, after 9 years, Mandy's home computer system is expected to be worth $1,576.11.

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If they each work 22 hours, Marsha will earn about $35.75 more than Tamekia.

To compare how much more money Marsha will earn than Tamekia, we can use the averages of their respective hourly rates and then multiply by the number of hours worked.

Tamekia's average hourly rate: ($6.00 + $6.25) / 2 = $6.125
Marsha's average hourly rate: ($7.50 + $8.00) / 2 = $7.75

Now, we'll multiply their average hourly rates by the number of hours worked, which is 22 hours.

Tamekia's total earnings: $6.125 x 22 = $134.75
Marsha's total earnings: $7.75 x 22 = $170.50

Finally, we'll subtract Tamekia's earnings from Marsha's earnings to find the difference:

$170.50 - $134.75 = $35.75

So, Marsha will earn about $35.75 more than Tamekia if they each work 22 hours.

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Marsha will earn $38.50 more than Tamekia if they each work 22 hours.

The volume of the regular pyramid is 1188 cm³.

A regular pyramid is a pyramid whose base is a regular polygon and whose lateral edges are all equal in length.

To calculate the volume of the regular pyramid, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is C. 1188 cm³

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The size of three angles of the triangle are 55 degrees, 55 degrees, and 15 degrees. The three consecutive odd numbers are 9, 11, and 13 and three consecutive even numbers are 32, 34, and 36.

1.To find the size of each angle in the triangle, we know that the sum of all angles in a triangle is 180 degrees. So we can set up an equation:

(2x + 5) + (2x + 5) + (x - 10) + 65 = 180

Simplifying and solving for x, we get:

5x + 55 = 180

5x = 125

x = 25

Now we can substitute x back into the expressions for each angle and simplify:

2x + 5 = 55 degrees

2x + 5 = 55 degrees

x - 10 = 15 degrees

Therefore, the three angles of the triangle are 55 degrees, 55 degrees, and 15 degrees.

2. Let's call the first odd number x. Then the next two consecutive odd numbers would be x + 2 and x + 4. We know that the sum of these three numbers is 33, so we can set up an equation:

x + (x + 2) + (x + 4) = 33

Simplifying and solving for x, we get:

3x + 6 = 33

3x = 27

x = 9

Therefore, the three consecutive odd numbers are 9, 11, and 13.

3. Let's call the first even number x. Then the next two consecutive even numbers would be x + 2 and x + 4. We know that the sum of these three numbers is 102, so we can set up an equation:

x + (x + 2) + (x + 4) = 102

Simplifying and solving for x, we get:

3x + 6 = 102

3x = 96

x = 32

Therefore, the three consecutive even numbers are 32, 34, and 36.

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The area of the donut sign with a radius of 3 feet is approximately 84.8 square feet when rounded to the nearest 10th.

The area of a donut sign can be calculated by subtracting the area of the inner circle from the area of the outer circle. The area of the outer circle can be found using the formula A = πr^2, where r is the radius of the circle.

Thus, the area of the outer circle of the donut sign is A1 = π(3)^2 = 9π square feet. Similarly, the area of the inner circle is A2 = π(0.5)^2 = 0.25π square feet, where the radius of the inner circle is 0.5 feet (which is the radius of the circular hole in the donut sign).

Therefore, the area of the donut sign can be calculated as A1 - A2 = 9π - 0.25π = 8.75π square feet. Using the value of π ≈ 3.14, we get the area of the donut sign as approximately 27.43 square feet. Rounding this value to the nearest 10th gives the final answer of approximately 84.8 square feet.

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Answer:b=30

Step-by-step explanation:

Alternate angles are the same so the angle opposite 30=125
125+30=155.but angles on a straight line=180
So we subtract 180-155 which leaves us with 25 for the top angle in the triangle.Angles in a triangle must add to 180 so we do, 125+25=150
180-150=30

the new coordinates of the rhombus W'X'Y'Z' after a dilation with scale factor k=3 are: [tex]W'(3,0), X'(12,-3), Y'(15,-12), Z'(6,-9)[/tex]

To find the new coordinates of the image after dilation, we need to multiply the coordinates of each vertex by the scale factor k = 3.

Let's start with vertex W(1,0):

Multiply the x-coordinate by  [tex]3: 1 *\times 3 = 3[/tex]

Multiply the y-coordinate by [tex]3: 0 \times 3 = 0[/tex]

So the new coordinates of W' are [tex](3,0).[/tex]

Next, let's look at vertex X(4,-1):

Multiply the x-coordinate by [tex]3: 4 \times 3 = 12[/tex]

Multiply the y-coordinate by [tex]3: -1 \times 3 = -3[/tex]

So the new coordinates of X' are [tex](12,-3).[/tex]

Now for vertex Y(5,-4):

Multiply the x-coordinate by [tex]3: 5 \times 3 = 15[/tex]

Multiply the y-coordinate by [tex]3: -4 \times3 = -12[/tex]

So the new coordinates of Y' are  [tex](15,-12).[/tex]

Finally, let's consider vertex Z(2,-3):

Multiply the x-coordinate by  [tex]3: 2 \times 3 = 6[/tex]

Multiply the y-coordinate by  [tex]3: -3 \times3 = -9[/tex]

So the new coordinates of Z' are [tex](6,-9)[/tex]  .

Therefore, the new coordinates of the rhombus  [tex]W'X'Y'Z'[/tex] after a dilation with scale factor k=3 are:

[tex]W'(3,0)[/tex]

[tex]X'(12,-3)[/tex]

[tex]Y'(15,-12)[/tex]

[tex]Z'(6,-9)[/tex]

Learn more about coordinates here:

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