Answer:
The answer is option D
Step-by-step explanation:
32m + 56mp
First factor out the HCF out
The HCF of 32and 56 is 8
So we have
8 ( 4m + 7mp)
next factor m out
We have the final answer as
8m( 4 + 7p)Hope this helps you
Eric completed 1/3 of his homework before dinner and then 2/7 after dinner. How much homework did Eric complete?
The homework completed by Eric will be equal to 13/21.
What is the fraction?
The fraction is defined as the division of the whole part into an equal number of parts.
To add fractions, you first have to set the denominators equal to each other. To do this, you find the LCD (least common denominator) of the two fractions until you find a shared number.
To do this, list out the multiples of each number (3x1=3,3x2=6,3x3=9, and so on. Do this also with 7) The LCD for 3 and 7 is 21. 3x7=21, and 7x3=21. You want to set each fraction’s denominator equal to 21.
You want to multiply each side of 1/3 by 7. 1/3 would become 7/21. You’d do this because 3x7=21, and if you multiply the bottom by you need to multiply the top by. 7x3=21 so you multiply both sides by 3 to get 6/21.
Now you have 7/21 and 6/21 and can add them. Now that they are equal, you can ignore the denominator and just add the numerators. 7+6=13 so Eric completed 13/21 of his homework.
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Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him
Answer:
60 miles
Step-by-step explanation:
Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?
Statement 1. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own
Statement 2. If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds
Solution
A. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
Let Brian speed=b
Ashok speed=a
Brian's walking speed=2(a-b)
b=2(a-b)
Divide both sides by 2
b/2=a-b
Ashok catches up in (time)= distance /( relative rate
=30/(a-b)
=30/(b/2)
=30÷b/2
=30*2/b
=60/b.
By that time Brian will cover a distance of
distance=rate*time
=b*60/b
=2(a-b)*60/2(a-b)
=60 miles
(2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
5a=3(a+b)
5a=3a+3b
5a-3a=3b
2a=3b
I'm marking people brainliest. ------ One of the solutions to this inequality is _____ (-1,-2) (-1, 2) (0.5,2) (-2, -1)
Answer:
(-1, -2)
Step-by-step explanation:
Look up each point in the choices on the graph. If it is on the line or in the shaded area it is a solution.
Answer: (-1, -2)
Answer:
First & Last
Step-by-step explanation:
See what is in the red portion(Shaded or line), that is what can work to the inequality.
(-1, -2) -- In the red(works)
(-1, 2) -- Out of the red(Nope)
(0, 5.2) -- Out of the red(Nope)
(-2, -1) -- In the red(works)
do these problems and get 100 points 1. Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. c 22 and 15 2 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. d 13.2 and 6.7 3 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. e 34 and 12 4 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. f 23 and 44
Answer:
[tex]7 < x < 37[/tex] -- Triangle 1
[tex]6.5 < x < 19.9[/tex] -- Triangle 2
[tex]22 < x < 46[/tex] -- Triangle 3
[tex]21 < x < 67[/tex] -- Triangle 4
Step-by-Step Explanation:
Given
2 sides of a triangle
1. 22 and 15
2. 13.2 and 6.7
3. 34 and 12
4. 23 and 44
Required
Determine the range of the third side in the above triangles
Triangle 1: 22 and 15
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]22 + x > 15[/tex]
[tex]22 + 15 > x[/tex]
[tex]15 + x > 22[/tex]
Solving
[tex]22 + x > 15[/tex]
Make x the subject of formula
[tex]x > 15 - 22[/tex]
[tex]x > -7[/tex]
Solving
[tex]22 + 15 > x[/tex]
[tex]37 > x[/tex]
Solving
[tex]15 + x > 22[/tex]
Make x the subject of formula
[tex]x > 22 - 15[/tex]
[tex]x > 7[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]37 > x[/tex] and [tex]x > 7[/tex]
Rewrite both inequalities
[tex]x < 37[/tex] and [tex]7 < x[/tex]
Combine the two inequalities
[tex]7 < x < 37[/tex]
Triangle 2: 13.2 and 6.7
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]13.2 + x > 6.7[/tex]
[tex]13.2 + 6.7 > x[/tex]
[tex]6.7 + x > 13.2[/tex]
Solving
[tex]13.2 + x > 6.7[/tex]
Make x the subject of formula
[tex]x > 6.7 - 13.2[/tex]
[tex]x > -6.5[/tex]
Solving
[tex]13.2 + 6.7 > x[/tex]
[tex]19.9 > x[/tex]
Solving
[tex]6.7 + x > 13.2[/tex]
Make x the subject of formula
[tex]x > 13.2 - 6.7[/tex]
[tex]x > 6.5[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]19.9 > x[/tex] and [tex]x > 6.5[/tex]
Rewrite both inequalities
[tex]x < 19.9[/tex] and [tex]6.5 < x[/tex]
Combine the two inequalities
[tex]6.5 < x < 19.9[/tex]
Triangle 3: 34 and 12
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]34 + x > 12[/tex]
[tex]34 + 12 > x[/tex]
[tex]12 + x > 34[/tex]
Solving
[tex]34 + x > 12[/tex]
Make x the subject of formula
[tex]x > 12 - 34[/tex]
[tex]x > -22[/tex]
Solving
[tex]34 + 12 > x[/tex]
[tex]46 > x[/tex]
Solving
[tex]12 + x > 34[/tex]
Make x the subject of formula
[tex]x > 34 - 12[/tex]
[tex]x > 22[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]46 > x[/tex] and [tex]x > 22[/tex]
Rewrite both inequalities
[tex]x < 46[/tex] and [tex]22 < x[/tex]
Combine the two inequalities
[tex]22 < x < 46[/tex]
Triangle 4: 23 and 44
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]23 + x > 44[/tex]
[tex]23 + 44 > x[/tex]
[tex]23 + x > 44[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 23 - 44[/tex]
[tex]x > -21[/tex]
Solving
[tex]23 + 44 > x[/tex]
[tex]67 > x[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 44 - 23[/tex]
[tex]x > 21[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]67 > x[/tex] and [tex]x > 21[/tex]
Rewrite both inequalities
[tex]x < 67[/tex] and [tex]21 < x[/tex]
Combine the two inequalities
[tex]21 < x < 67[/tex]
the baseball team equipment manager received a shipment of new baseballs. out of 200 balls 12.5% had defects. How many baseballs were without defects?
Answer:
175 balls
Step-by-step explanation:
If 12.5 percent of the balls had defects, then [tex]100-12.5=87.5[/tex]% of balls didn't have defects.
We can find 87.5 percent of 200 by converting 87.5 to a decimal.
87.5% as a decimal is 0.875.
Now we multiply this decimal by 200.
[tex]200\cdot0.875 = 175[/tex]
So, 175 balls didn't have defects.
Hope this helped!
which ones have no solution? a. -14x+23=14x-23 b. 14x+23=14x-23 c. -23x-14=14x-23 d. 14x-23=14x-23
Answer:
B and D
Step-by-step explanation:
B: 14x and 14x cancel out, so there would be no x left.
D: 14 x and 14x cancel out, as well as -23 and -23, therefore leading to no solution.
Hope this is helpful! :)
Answer:
The answer is B
Step-by-step explanation:
I got this answer on Khan Academy.
Hope this helps! :)
Show that: (sec theta - cosec theta) (1 + tan theta + cot theta) = sec theta tan theta - cosec theta cot theta)
Answer:
see derivation below
Step-by-step explanation:
Show that:
( sec(t) - cosec(t) ) ( 1 + tan(t) + cot(t) ) =
sec(t) tan(t) - cosec(t) cot(t)
Some trigonometric definitions used:
tan(t) = sin(t)/cos(t)
cot(t) = cos(t)/sin(t)
sec(t) = 1/cos(t)
csc(t) = 1/sin(t)
some trigonometric identities used:
sin^2(t) + cos^2(t) = 1 ......................(1)
rewrite left-hand side in terms of sine and cosine
(1/cos(t) - 1/sin(t) ) ( 1 + sin(t)/cos(t) + cos(t)/sin(t) )
Simplify using common denominator sin(t)cos(t)
= ( (sin(t) - cos(t))/(sin(t)*cos(t)) ) * ( ( sin(t)cos(t) + sin^2(t) + cos^2(t)) / ( sin(t)cos(t) ) )
= ( sin(t) -cos(t) ) * (1 + sin(t)cos(t) ) / ( sin^2(t) cos^2(t) ) ...... using (1)
Expand by multiplication
= ( sin(t) -cos(t) + sin^2(t)cos(t) - sin(t)cos^2(t) ) / ( sin^2(t) cos^2(t) )
Rearrange by factoring out sin(t) and cos(t) in numerator
= ( sin(t) (1-cos^2(t) - cos(t)(1-sin^2(t) ) / ( sin^2(t) cos^2(t) )
= ( sin^3(t) - cos^3(t) ) /( sin^2(t) cos^2(t) ) .........................using (1)
Cancel common factors
= sin(t)/(cos^2(t)) - cos(t)/(sin^2(t))
Rewrite using trigonometric definitions
= sec(t)tan(t) - csc(t)cot(t) as in Right-Hand Side
The height of a right cylinder is 3 times the radius of the base. The volume of the cylinder is 24π cubic units. What is the height of the cylinder? 2 units 4 units 6 units 8 units
Answer:
6 unitsStep-by-step explanation:
Let, Radius = r units
Height ( h ) = 3r units
Volume ( V ) = 24π units³
Now,
Let's find the height of the cylinder:
[tex]\pi {r}^{2} h \: = 24\pi[/tex]
[tex] {r}^{2} (3r) = 24[/tex]
Calculate the product
[tex]3 {r}^{3} = 24[/tex]
Divide both sides of equation by 3
[tex] \frac{3 {r}^{ 3} }{3} = \frac{24}{3} [/tex]
Calculate
[tex] {r}^{3} = 8[/tex]
Write the number in the exponential form with an exponent of 3
[tex] {r}^{3} = {2}^{3} [/tex]
Take the root of both sides of the equation
[tex]r = 2[/tex]
Replacing value,
Height = 3r
[tex] = 3 \times 2[/tex]
Calculate
[tex] = 6 \: units[/tex]
Hope this helps..
Best regards!!
Answer:
[tex]\boxed{6 \: \mathrm{units}}[/tex]
Step-by-step explanation:
The formula for volume of cylinder is:
[tex]V=\pi r^2 h\\V:volume\\r:radius\\h:height[/tex]
[tex]V=24\pi\\h=3r[/tex]
Solve for r.
[tex]24\pi =\pi r^2 (3r)[/tex]
Cancel [tex]\pi[/tex] on both sides.
[tex]24=3r^3[/tex]
Divide 3 on both sides.
[tex]8=r^3[/tex]
Cube root on both sides.
[tex]2=r[/tex]
The radius of the base is 2 units.
Solve for h.
[tex]24\pi =\pi (2)^2 h[/tex]
Cancel [tex]\pi[/tex] on both sides.
[tex]24=4h[/tex]
Divide both sides by 4.
[tex]6=h[/tex]
Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F. 21 G. 27 H. 30
Answer:
E
Step-by-step explanation:
i guess the dotted lines outline a square
so get the area of the square which is 6×6=36
then don't focus on the shaded part but unshaded you'll see two right angled triangles
[tex]a = 1 \div2b \times h[/tex]
you will get a total for both as 21
then get the area of the square 36-21=15
so the area becomes 15
Ans ASAP!! But one request can u give IN pic WITH steps?..... Plzlzlzlzlz?? 1rst one will be the BRAINLIEST.. But I want complete ans!
Answer:
The parts are 24 and 16
Step-by-step explanation:
Let's call the two parts x and y. We can write the following system:
x + y = 40 -- Equation 1
1/4x = 3/8y -- Equation 2
2x = 3y -- Equation 3 (Multiply Equation 2 by 8 to get rid of denominators)
2x + 2y = 80 -- Equation 4 (Multiply Equation 1 by 2)
3y + 2y = 80 -- (Substitute 2x = 3y into Equation 4)
5y = 80 -- (3y + 2y = 5y)
y = 16 -- (Divide by 5)
x + 16 = 40 -- (Substitute y = 16 into Equation 1)
x = 24 -- (Subtract 16)
PLS SOLVE THIS QUESTION. The first one to get it right get's a brainliest.
Answer:
-3
Step-by-step explanation:
You have get a graphing calculator and press y=.
Then you would type in the equation.
Then click second, graph after you type the equation.
Then scan through the t graph for the value that causes the equation to be 0
Find the sum of all integers between 550 and 850 which are divisible by 11.
Answer:
19008
Step-by-step explanation:
550 is equal to 11 multiplied by 50.
1. Solve for multiples of 11 between 550 and 850
11 · 51 = 561
11 · 52 = 572
11 · 53 = 583
11 · 54 = 594
11 · 55 = 605
11 · 56 = 616
11 · 57 = 627
11 · 58 = 638
11 · 59 = 649
11 · 60 = 660
11 · 61 = 671
11 · 62 = 682
11 · 63 = 693
11 · 64 = 704
11 · 65 = 715
11 · 66 = 726
11 · 67 = 737
11 · 68 = 748
11 · 69 = 759
11 · 70 = 770
11 · 71 = 781
11 · 72 = 792
11 · 73 = 803
11 · 74 = 814
11 · 75 = 825
11 · 76 = 836
11 · 77 = 847
2. Add the products together
= 19008
Suppose you are interested in testing wheter the mean earning of men in the general social survey is representative of the earning of the entire U.S. Male population. If there are 372 men in the general social survey sample and approximately 128 million men in the population, calculate the degrees of freedom for this single-sample t test.
Answer:
371
Step-by-step explanation:
According to the given situation the calculation of degrees of freedom for this single-sample t test is shown below:-
Degrees of freedom is N - 1
Where N represents the number of Men
Now we will put the values into the above formula.
= 372 - 1
= 371
Therefore for calculating the degree of freedom we simply applied the above formula.
ali needs to solve the equation x^2 + 6x + 22 = 0 by completing the square. which pair of steps is the most efficient way to begin?
a. x^2 + 6x + 9 = -22 + 9
b. x^2 + 6x + 36 = -22 + 36
c. x^2 + 6x + 3 = -22 + 3
d. x^2 + 6x + 81 = -22 + 81
Answer:
a. x² + 6x + 9 = -22 + 9
Step-by-step explanation:
they moved the 22 to the right by subtracting it. this leaves a binomial on the left side, which if what you want to solve it.
then they completed the square by dividing b (6) by 2 = 3. then squaring 3 to get 9.
if you added 9 to the left, then you have to add 9 to the right, therefore resulting in -22 + 9.
Answer:
In TTM/Imagine Math it is top left or a.
Step-by-step explanation:
At the end of any year a car is worth 5%
less than what it was worth at the beginning
of the year. If a car was worth $9 500 in
December 2016, then its value in January
2016 was
Answer:
Step-by-step explanation:
Multiply $9500 by .05 (5%) to get 475. That is 5% of $9500. Now subtract 475 from 9500 to get 9025. That is your answer!
The value of car in month of January is, [tex]\$ 9975[/tex]
Percentage :It is given that, At the end of any year a car is worth 5% less than what it was worth at the beginning of the year.
Since, car was worth $9 500 in December 2016.
Then, the value of car in month of January is, 105 % of value of car in moth of December.
So that, value of car in month of January is,
[tex]=9500*\frac{105}{100}\\ \\=9500*1.05=9975[/tex]
The value of car in month of January is, [tex]\$ 9975[/tex]
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HELP!! DISCRETE DATA
Answer:
Hey there!
Discrete Data is the number of friends you invited to your last birthday party.
Hope this helps :)
Answer:
a) The number of friends you invited to your last party.
Step-by-step explanation:
Let’s take a step back what is discrete, and what continuous?
Discrete
This is the type of data with certain whole numbers not 2.36 only 2 or 3.
Continuous
This is the data being specific like 1.373.
So a)
The is discrete because you can only have like 5 friends not 7.49 friends.
b)
This is continuous because height can be 5.26 feet.
c)
Time is continuous because there can be 4.3739 minutes.
d)
Weight is also continuous it can be 6339.373 pounds.
To make a chocolate sponge cake for 8 people you need:
300g flour
100g cocoa
400g sugar
350g butter
1 egg
a) How much of each ingredient do you need to make a cake for 10 people?
b) if you only had 60g of cocoa,how much of each ingredient would you now need?
Answer:
this is som A sorry if you can't read it
Graph [tex]y=\frac{2}{3} x[/tex] Which of the following statements are true?
Answer:
A,C,D
Step-by-step explanation:
When b=0, there is a proportional relationship.
The slope in y=mx+b is the value next to x.
Using RISE/RUN when there is a change of 3 units in x, there is a change of 2 units in y.
A cube has a side length of 5 cm. Determine the surface area of the largest pyramid that will fit inside the cube. Round if necessary.
Answer:
The surface area of the pyramid is 80.9 cm²
Step-by-step explanation:
The side length, s of the cube is given as 5 cm
Therefore, the largest pyramid that can fit into the cube will have a base side length, s = The side length of the cube = 5 cm
The height, h of the largest pyramid = The height of the cube = 5 cm.
The surface area of a pyramid = Area of base, A + 1/2 × Perimeter of base, P × Slant height, S
The slant height of the pyramid = √(h² + (s/2)²) = √(5² + (5/2)²) = (5/2)×√5
The perimeter of the base = 4×5 = 20 cm
The area of the base = 5×5 = 25 cm²
The surface area of a pyramid = 25 + 1/2×20×(5/2)×√5 = 80.9 cm².
The surface area of a pyramid = 80.9 cm².
In order to win a quiz contest, Olga must score more than 400400400 points. She earns 121212 points for each right answer, and loses 444 points for each wrong answer. Write an inequality that represents the number of right answers (R)(R)left parenthesis, R, right parenthesis and wrong answers (W)(W)left parenthesis, W, right parenthesis Olga can give to win the contest.
Answer: The number of points added for r right answers is 12r. The number of points taken away for w wrong answers is 4w, so Olga's total points will be
... 12r -4w
To win, she needs this number to be more than 400. Your inequality is ...
... 12r -4w > 400
Answer:12r -4w > 400
Step-by-step explanation:
At a local high school football game, twice the number of students attended as adults. If student tickets were $6.50, adult tickets were $9.00, and the total receipts for the game were $4972, how many students attended the game?
452 students
484 students
512 students
376 student
Answer:
454
Step-by-step explanation:
set up a system of equation
let y be the number of students
let x be the number of adults
because there are twice the amount of students attended as adults, we can use y=2x as one equation
the other equation will be 6.5y+9x=4972 because this represents the total amount of money
plug 2x for y : 6.5(2x)+9x=4972 : x=226
plug 226 in for the first equation : y=2(226) : y=452
which binomial is the additive inverse of 5 + 2C
Answer:
-5-2c
Step-by-step explanation:
The additive inverse of a term must be the opposite of it.
●-(5+2c)
●-5-2c
Answer:
Step-by-step explanation:
The additive inverse is just the opposite of the binomial in terms of the signs. The additive inverse of 5 + 2C is -(5 + 2C) which is, without parenthesis, -5 - 2C.
What is the slope of the line through the points (2,8) and (5,7)
Answer:
-1/3
Step-by-step explanation:
The slope of the line can be found by
m = (y2-y1)/(x2-x1)
= ( 7-8)/(5-2)
= -1/3
Answer:
-1/3.
Step-by-step explanation:
The slope can be found by doing the rise over the run.
In this case, the rise is 8 - 7 = 1.
The run is 2 - 5 = -3.
So, the slope is 1 / -3 = -1/3.
Hope this helps!
Factor the polynomial expression x2 + 5.
Answer:
Step-by-step explanation:
Please write this as x^2 + 5.
Roots are ±i√5.
The corresponding factors of x^2 + 5 are (x + i√5) and (x - i√5)
Find the interquartile range for a data set having the five-number summary: 7.8, 17.1, 23.6, 31.1, 36.9
Answer:
Interquartile Range: 21.549999999999997 = 21.55
Step-by-step explanation:
aljebra questions anum counted the money she had in her purse and money box . When she doubbled the amount in her purse and add it to the amount in money box she gets rs 1700 . When she triples the amount in her purse and add in to money box she gets rs 2200. How much money does she have in her purse
Answer:
Money in her purse is Rs. 500.
Step-by-step explanation:
Let the money in her purse = Rs. [tex]x\\[/tex]
Let the money in her Money box = Rs. [tex]y[/tex]
As per question statement,
Double the money in her purse (i.e. [tex]2 \times x[/tex]) and add it to the amount in money box, she gets Rs. 1700.[tex]2x+y=1700[/tex] ........ (1)
Triple the money in her purse (i.e. [tex]3\times x[/tex]) and add it to amount in money box ([tex]y[/tex]), she gets Rs. 2200.[tex]3x+y=2200[/tex] ....... (2)
To find: Money in her purse = ? i.e. [tex]x=?[/tex]
Let us solve for [tex]x[/tex] using the two linear equations.
We can use substitution method here i.e. find value of one variable from one equation and then substitute that value in other equation.
Using equation (1), we get the value of [tex]y[/tex] as follows:
[tex]y=1700-2x[/tex]
Now, let us put this value of y in equation (2) to find the value of [tex]x[/tex]:
[tex]3x+1700-2x=2200\\\Rightarrow x+1700 = 2200\\\Rightarrow x=2200-1700\\\Rightarrow x = Rs.\ 500[/tex]
Money in her purse is Rs. 500.
PLEASE ANSWER THIS FAST Will the red square and the orange square always equal the blue square? What colored square is the hypotenuse?
Step-by-step explanation:
The area of the blue square will always equal the sum of the area of the orange and red rectanglesThe pythagorian theorem:
a²+b² = c²
now let a be the side of the red triangle and b the side of the orange one
so a² is the area of the red triangle and b² is the area of the orange one
Let c be the side of the blue rectangle
so c² is the area of it
then what we concluded is right
the hypotenuse is the blue side since it is the larger onedid this several times but still didn't get the answer .pls do try this :)
Answer:
x=-15/2 and x=1
x=6 and x=3/4
Step-by-step explanation:
You have the following equations:
[tex]\frac{4x-3}{x+2}=\frac{2x}{x+5}[/tex]
[tex]\frac{2}{x-2}+\frac{3}{x}-\frac{9}{x+3}[/tex]
To solve both equations you can first multiply by the m.c.m of the denominators, and then solve for x, just as follow:
first equation:
[tex][\frac{4x-3}{x+2}=\frac{2x}{x+5}](x+2)(x+5)\\\\(4x-3)(x+5)=2x(x+2)\\\\4x(x)+4x(5)-3(x)-3(5)=2x(x)+2x(2)\\\\4x^2+20x-3x-15=2x^2+4x\\\\4x^2-2x^2+20x-3x-4x-15=0\\\\2x^2+13x-15=0[/tex]
In this case you use the quadratic formula:
[tex]x_{1,2}=\frac{-13\pm \sqrt{(13)^2-4(2)(-15)}}{2(2)}\\\\x_{1,2}=\frac{-13 \pm 17}{4}\\\\x_1=-\frac{15}{2}\\\\x_2=1[/tex]
Then, for the first equation the solutions are x=-15/2 and x=1
second equation:
[tex][\frac{2}{x-2}+\frac{3}{x}=\frac{9}{x+3}]x(x-2)(x+3)\\\\2x(x+3)+3(x-2)(x+3)=9x(x-2)\\\\2x^2+6x+3(x^2+3x-2x-6)=9x^2-18x\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\2x^2+6x+3x^2+3x-18-9x^2+18x=0\\\\-4x^2+27x-18=0[/tex]
Again, you use the quadratic formula:
[tex]x_{1,2}=\frac{-27\pm \sqrt{(27)^2-4(-4)(-18)}}{2(-4)}\\\\x_{1,2}=\frac{-27\pm 21}{-8}\\\\x_1=6\\\\x_2=\frac{3}{4}[/tex]
Then, the solutions for the second equation are x=6 and x=3/4
The baseball team has a double-header on Saturday. The probability that they will win both games is 50%. The probability that they will win just the first game is 65%, What is the probability that the team will win the 2nd game given that they have already won the first game? (PLEASE SHOW YOU'RE WORK)
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
Find the vertex of the graph
Answer:
(-3, -11)
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