Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
Step-by-step explanation: Step by Step Solution
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STEP
1
:
Equation at the end of step 1
((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
2
:
Equation at the end of step 2
(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
3
:
Equation at the end of step 3
((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
4
:
Multiplying Exponential Expressions:
4.1 Multiply (x-4) by (x-4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-4) and the exponents are :
1 , as (x-4) is the same number as (x-4)1
and 1 , as (x-4) is the same number as (x-4)1
The product is therefore, (x-4)(1+1) = (x-4)2
Equation at the end of step
4
:
(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
5
:
5.1 Rewrite (1-x) as (-1) • (x-1)
Multiplying Exponential Expressions:
5.2 Multiply (x-1) by (x-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-1) and the exponents are :
1 , as (x-1) is the same number as (x-1)1
and 1 , as (x-1) is the same number as (x-1)1
The product is therefore, (x-1)(1+1) = (x-1)2
STEP
7
:
Pulling out like terms
7.1 Pull out like factors :
-x - 2 = -1 • (x + 2)
Multiplying Exponential Expressions:
7.2 Multiply (x + 2) by (x + 2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+2) and the exponents are :
1 , as (x+2) is the same number as (x+2)1
and 1 , as (x+2) is the same number as (x+2)1
The product is therefore, (x+2)(1+1) = (x+2)2
STEP
9
:
Pulling out like terms
9.1 Pull out like factors :
-x - 3 = -1 • (x + 3)
Multiplying Exponential Expressions:
9.2 Multiply (x + 3) by (x + 3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+3) and the exponents are :
1 , as (x+3) is the same number as (x+3)1
and 1 , as (x+3) is the same number as (x+3)1
The product is therefore, (x+3)(1+1) = (x+3)
((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
10
:
Equation at the end of step 10
(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
11
:
STEP
12
:
Pulling out like terms
12.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
12
:
((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
13
:
STEP
14
:
Pulling out like terms
14.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
14
STEP
15
STEP
16
:
Pulling out like terms
16.1 Pull out like factors :
-x - 4 = -1 •
Equation at the end of step
16
:
STEP
17
:
STEP
18
:
Pulling out like terms
18.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Multiplying Exponential Expressions:
18.2 Multiply (x + 4) by (x + 4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+4) and the exponents are :
1 , as (x+4) is the same number as (x+4)1
and 1 , as (x+4) is the same number as (x+4)1
The product is therefore, (x+4)(1+1) = (x+4)2
Equation at the end of step
18
:
(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)
STEP
19
:
STEP
20
:
Pulling out like terms
20.1 Pull out like factors :
-x - 1 = -1 • (x + 1)
Multiplying Exponential Expressions:
20.2 Multiply (x + 1) by (x + 1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+1) and the exponents are :
1 , as (x+1) is the same number as (x+1)1
and 1 , as (x+1) is the same number as (x+1)1
The product is therefore, (x+1)(1+1) = (x+1)2
Equation at the end of step
20
:
((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)
STEP
21
:
21.1 Rewrite (2-x) as (-1) • (x-2)
Multiplying Exponential Expressions:
21.2 Multiply (x-2) by (x-2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-2) and the exponents are :
1 , as (x-2) is the same number as (x-2)1
and 1 , as (x-2) is the same number as (x-2)1
The product is therefore, (x-2)(1+1) = (x-2)2
22.1 Multiply (x-3) by (x-3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-3) and the exponents are :
1 , as (x-3) is the same number as (x-3)1
and 1 , as (x-3) is the same number as (x-3)1
The product is therefore, (x-3)(1+1) = (x-3)2
Final result :
(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
what is three-fourths times a square of a number
just write the equation
Answer:
3/4(x^2)
Step-by-step explanation:
........................
Plant a is 25 ft tall and plant b is 2ft tall.Plant A grows 2ft per week and plant B grows 21/5 feet per week. In how many days will the height of both the plants reach same
Answer:
10.5 weeks
Step-by-step explanation:
is you graph the following system, the point of intersection is (10.45, 45.9)
Plant A: y = 2x + 25
Plant B: y = 21/5x + 2
Write an equation of a line with slope 4 that passes through the point (3.5,5) in slope-intercept form.
Answer:
Step-by-step explanation:
slope-intercept formula.. y= mx + b
so that's the form we want to get to
use the point-slope formula to get there y-y1 = m(x-x1)
m= slope and (x1,y1) is your given point
y-5 = 4(x-3.5)
y-4 = 4x - 14
y = 4x -14 +4
y = 4x -10
this looks like the slope-intercept form :)
The equation of a line with slope 4 that passes through the point (3.5,5) in slope-intercept form is y = 4x - 9 where y-intercept is -9
What is a linear equation?It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.
If in the linear equation one variable is present then the equation is known as the linear equation in one variable.
We have:
The slope of the line = 4
The line passes through a point (3.5, 5)
We know the equation of the line that has slope m and y-intercept c:
y = mx + c
y = 4x + c (m = 3)
Point (3.5, 5) must satisfy the above line equation:
5 = 4(3.5) + c
c = -9 put this value in the line equation we get:
y = 4x -9
Thus, the equation of a line with slope 4 that passes through the point (3.5,5) in slope-intercept form is y = 4x - 9 where y-intercept is -9
Learn more about the linear equation here:
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D File
C:/Users/tonia/Desktop/YEAR%201.2/ADVANCED%20CALC/BSM%201207%
Highlight
Erase
+
Draw
2
A' Read aloud
b) A project has the following activities and other characteristics:
Activity Preceding Most
Most
activity optimistic likely
Most
pessimistic
A
B
С
D
E
F
G
H
1
А
A
C С.
D
B
E,F
G
4.
1
6
2.
5
3
3
1
7
5
12
5
11
6
9
4
19
16
15
30
8
17
15
27
7
28
Required
i) Draw the PERT network diagram.
Identify the critical path
Determine the mean project completion time.
iv) Find the probability that the project is completed in 36 weeks.
(16 marks)
וחו
P
100% 14
here to search
Answer:
Oh what a questionI cannot understand
Use _________ to isolate the variable.
A
reciprocals
B
subtraction
C
an expression
D
inverse operations
Answer:
Answer: D) inverse operations
Subtraction is the inverse operation of addition
Step-by-step explanation:
please mark as brainliest!!
John deposits $25 at the end of each month in a savings account with 6.4% annual interest compounded monthly. What is his account balance at the end of 15 years? *
Answer:
$ 65.13
Step-by-step explanation:
John deposits $25 at the end of each month in a savings account with 6.4% annual interest compounded monthly. What is his account balance at the end of 15 years? *
The formula for compound interest =
A = P(1 + r/n)^nt
Where
P = Initial amount deposited = $25
r = Interest rate = 6.4% = 0.064
n = number of times interest is compound = monthly = 12 times
t = time in years = 15 years
A = $25 × (1 + 0.064/12)^12 × 15
A = $65.13
His account balance at the end of 15 years is $65.13
simplify
plzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
[tex]12a {}^{9}b {}^{7} [/tex]
hope it helps
explanation in the pic above
please help, will give brainliest!!
Answer:
The answer is A.
Step-by-step explanation:
Hope this helped have an amazing day!
Write an equation to represent the following statement.
The product of 12 and k is 84.
Solve for k.
Answer:
12(k)=84 k=7
Step-by-step explanation:
84/12=7
A bike covers 150 km distance. with 3 liters of petrol than what distance it will cover with 5 liters of petrol?
Answer:
The bike will cover 250 km of distance with 5 liters of petrol.
Step-by-step explanation:
First, we have to calculate the amount of distance the bike will be able to cover in 1 liter of petrol.
[tex]\frac{150 \ km}{3 \ liters}[/tex]
[tex]= 50 \ km/liter[/tex]
Therefore, for every liter, the bike will be able to travel 50 km of distance.
Now, let's multiply the distance travelled by each liter with the total number of liters.
[tex]\frac{50 \ km}{liter} \cdot 5 \ liters[/tex]
[tex]= 250 \ km[/tex]
Finally, we have our answer: the bike will cover 250 km of distance with 5 liters of petrol.
Hope this helped!
Answer:
Step-by-step explanation:
150 / 3 = 50 km per liter sooo
5 * 50 = 250 Km
plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
Circle 1=6x+2y
Rectangle 4 = 3x+y
Circle 4 = 5x
Step-by-step explanation:
4x+3y and 2x-y can be added to find result for the circle.
Let C1 represent circle 1
4x+3y+2x-y=C1\\
Combining\:like\:terms\\
4x+2x+3y-y=C1
6x+2y=C1
So, The result is: C1=6x+2y
Now, We need to solve:
Let R1 represent rectangle 4
x+4y + R1 = 4x+5y
R1=4x+5y-(x+4y)
R1=4x+5y-x-4y
R1=4x-x+5y-4y
R1=3x+y
So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y
Now, We need to solve the equation:
Let C4= Circle 4
2x-y+3x+y=C4
Combining the like terms
2x+3x-y+y=C4
5x=C4
So, Solving 2x-y+3x+y=C4 we get C4 = 5x
The sample standard deviation, divided by the square root of N , results in the _____________________________.
Answer:
Standard Error
Step-by-step explanation:
The standard error is the ratio of the sample standard deviation and the square root of the sample size used.
Standard Error (S. E) = s / √n
Where ;
s = sample standard deviation ; n = sample size
You make $5 an hour in tips working at a restaurant and $7 an hour in tips working at a landscaping
company
In one week, you work 15 hours and you earn $97. Write system of linear equations to determine
the number of hours you work at each job.
Answer:
5x + 7y = 97
x + y = 15
The solution to these equations is (4,11)
Step-by-step explanation:
What is the solution to 40+40-20•0+3+125=
Answer:
188
i think, i'm not that sure what the dot in. "20.0" is. i cant tell if its for mutiplcation or a decimal
The solution to an equation is the result of solving the equation
The solution to 40 + 40 - 20 . 0 + 3 + 125 is 208
The equation is given as:
[tex]40 + 40 - 20 \cdot 0 + 3 + 125[/tex]
Evaluate the products of 20 and 0
[tex]40 + 40 - 20 \cdot 0 + 3 + 125 = 40 + 40 -0 + 3 + 125[/tex]
Add the terms of the expression
[tex]40 + 40 - 20 \cdot 0 + 3 + 125 = 208[/tex]
Hence, the solution to 40 + 40 - 20 . 0 + 3 + 125 is 208
Read more about equations and solutions at:
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What is the approximate value of sin C?
B
13.93
5
A
13
12
O A. 0.93
OB. 0.36
O C. 2.79
D. 0.38
Answer: 0.36
Step-by-step explanation:
Ap3x
ASAP can someone help and explain this to me
Answer:
[tex]d = 15.0[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra II
Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point C (7, -4)
Point D (-8, -5)
Step 2: Find distance d
Substitute [DF]: [tex]d = \sqrt{(-8-7)^2+(-5+4)^2}[/tex]Subtract/Add: [tex]d = \sqrt{(-15)^2+(-1)^2}[/tex]Exponents: [tex]d = \sqrt{225+1}[/tex]Add: [tex]d = \sqrt{226}[/tex]Evaluate: [tex]d = 15.0333[/tex]Round: [tex]d = 15.0[/tex]Determine whether the graph shows a positive correlation, a negative correlation, or no correlation. If there is a positive or negative correlation, describe its meaning in the situation.
Average Cycling Speed
A graph titled Average Cycling Speed has minutes on the x-axis and miles per hour on the y-axis. Points are at (5, 15), (10, 13), (15, 11), (20, 10), (25, 9).
Answer:
Positive correlation.
Step-by-step explanation:
The miles per hour increases as the cycling speed increases.
If they drove for 4.75 hours, how far did they drive?
Answer:
332.5 miles
Step-by-step explanation:
let me know if its right :)
find the greatest common factor of 56 and 64
Answer:
8 is the greatest common factor
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
HELP DOES ANYONE GET THIS? This is my “math help” class and I still don’t understand
Answer:
there are dots outside of the allotted area
Step-by-step explanation:
I've never taken a math help class but from your paper one can assume you have to point out the error in the graph. Its a bit fuzzy so I cant see the numbers or labels but you take what you learned for how to graph and apply it here.
For example:
The dots should stay inside the graph. Not on the outside
The numbers that are on the side, the axis, they should all progress in a specific sequence. Like 2,4,6,8,10. It needs to stay constant. Not 2,4,6,8,19
Same for both x and y axis^
I'm not sure if that helps much with what your doing seeing as the instructions apply what you've already learned, but I hope you do good!
Answer quick please
Answer:
The answer should be x = 6
Aubree invested $4,400 in an account paying an interest rate of 2.4% compounded
quarterly. Assuming no deposits or withdrawals are made, how long would it take, to
the nearest tenth of a year, for the value of the account to reach $6,880?
Answer:
We conclude that the time required to get a total amount of $6,880.00 from compound interest on a principal of $ 4,400.00 at an interest rate of 2.4% per year and compounded 4 times per year is 18 years and 8 months.
Step-by-step explanation:
We know the formula
[tex]A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}[/tex]
where
A denotes the Accrued Amount (principal + interest) P denotes the Principal Amount r denoted the Annual Interest Rate t denotes the Time Period in yearsn denotes the number of compounding periods per unit tGiven
Total amount A = $6,880
Principle amount P = $4,400
Interest Rate r = 2.4% = 0.024 per year
Compounded quarterly = n = 4
Thus, the time period can be fetched using the simplified-derived equation suchs as:
t = ln(A/P) / n[ln(1 + r/n)]
substituting the values
t = ln(6,880.00/4,400.00) / ( 4 × [ln(1 + 0.006/4)] )
t = 18.8 years
Therefore, we conclude that the time required to get a total amount of $6,880.00 from compound interest on a principal of $ 4,400.00 at an interest rate of 2.4% per year and compounded 4 times per year is 18 years and 8 months.
Answer:
The answer is actually 18.7 -.-
Step-by-step explanation:
Geometry help please explain
Answer:
<A and <C
Step-by-step explanation:
If EA and EC are congruent, the angles <A and <C are also congruent
Answer:
angle A congruent to angle C
2
Which of the following are within the solution to x + 28 > 50 ?
(Select all that apply.)
A 10
B
15
C 22
D
25
E
30
Answer:
25 , 30
Step-by-step explanation:
x > 50 -28
x > 22
x is greater than 22.
Answer:
Step-by-step explanation:
D and E because x must be greater than 23
If ABCD is dilated by a factor of 2, the coordinate of d would be:
Answer:
the coordinate of D is 6,4
Answer:
D=(6,-4)
Step-by-step explanation:
Solve the following system of equations:
8x+14y=4
-6x-7y=-10
Answer:
(4,–2)
Took the quiz
BRAINIEST FOR THE FIRST ANSWER
Which could be his next step?
(3)(5) +
(1/5)+(3 (1)+() (1)
o (305) (
35) +(304)+(35)
+(5)
+
5+
Answer:
d
Step-by-step explanation:
please help me on this!
Answer:
1) Jina is not a member of the Music Club.
2) Three students are a member of the Music Club but not the Math Club.
3 Mary and Dan are in all three clubs.
Step-by-step explanation:
Look at the diagram and notice how each club has its own circle. If a student is in that circle, then they are a member of that club. When circles overlap, that overlap space means that a student is a member of two or all three clubs, depending on how many and which circles overlap.
1) Looking at Jina's location on the diagram, she is in the overlap between the math and chess club circles. However, her position does NOT overlap with the Music Club circle, therefore she is not a member of the Music Club.
2) Let's look at the students of the Music Club circle and its overlaps with the Chess Club circle, but NOT the overlaps with the Math Club circle. We can see that Lucy, Josh, and Juan are in these locations, therefore there are three students who are members of the Music Club but not the Math Club.
3) To find which students are in all three clubs, you would look at the middle of the diagram where all three circles overlap. The students listed in this location are Mary and Dan, therefore they are in all three clubs.
Andrew wants to buy 3 video games that are $50 each. He earns $80 a week. In how many weeks will he have enough money to buy the games?
Group of answer choices
Answer:
He will have enough money after 2 weeks.
Step-by-step explanation:
If he wants to buy 3 video games that are $50 each, he would need $150. He makes $80 a week. By the second week, he will have earned $160, which is enough for all 3 games.
Evaluate (−23)×(−23)3 by using the Laws of Exponents
Given:
[tex]\left(-\dfrac{2}{3}\right)\times \left(-\dfrac{2}{3}\right)^3[/tex]
To find:
The value of given expression by using the Laws of Exponents.
Solution:
We have,
[tex]\left(-\dfrac{2}{3}\right)\times \left(-\dfrac{2}{3}\right)^3[/tex]
Using the Laws of Exponents, we get
[tex]=\left(-\dfrac{2}{3}\right)^{1+3}[/tex] [tex][\because a^ma^n=a^{m+n}][/tex]
[tex]=\left(\dfrac{-2}{3}\right)^{4}[/tex]
[tex]=\dfrac{(-2)^4}{(3)^4}[/tex] [tex][\because \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}][/tex]
[tex]=\dfrac{(-2)\times (-2)\times (-2)\times (-2)}{(3)\times (3)\times (3)\times (3)}[/tex]
[tex]=\dfrac{16}{81}[/tex]
Therefore, the value of given expression is [tex]\dfrac{16}{81}[/tex].