Answer:
C
Explanation:
bit.^{}
ly/3gVQKw3
n
n
n
m
n
n
m
n
A company should use a private or a SaaS based cloud model for an application that a requirement for a bespoke and specialized hardware configuration.
What is a cloud model?A model, which is used for the purpose of bringing convenience of compiling a network of computers together, mostly without the use of external wires, is known as a cloud model.
When an application requires specialized configuration of its computer's hardware, a SaaS or a private cloud models are ideal.
Hence, option A and B holds true regarding a cloud model.
Learn more about cloud model here:
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give the full form of http
The full from of http is hypertext Transfer Protocol
Consider a direct-mapped cache with 256 blocks where block size is 16 bytes. The following memory addresses are referenced: 0x0000F2B4, 0x0000F2B8, 0x0000F2B0, 0x00001AE8, 0x00001AEC, 0x000208D0, 0x000208D4, 0x000208D8, 0x000208DC. Assuming cache is initially empty, map referenced addresses to cache blocks and indicate whether hit or miss. Compute the hit rate.
Answer:
Explanation:
.bnjuk
Code to be written in Python:
Correct answer will get the brainliest!
Uyen decides to write a Python program to count towards the next birthday.
In order to do so, she plans to write a function count_days(start_date, end_date) which takes in the start date and end date in the string format, "dd/mm/yyyy", and returns the number of days between the start date and end date. The start date is included while the end date is not included in the count. Note that leading zeros in start_date and end_date are skipped if there are any (For example, the date 1st January 2017 will be in the format 1/1/2017).
Currently, Uyen has only completed a skeleton of count_days, and a few helper functions, which are provided below.
Your Tasks:
(a) Help Uyen complete the four functions marked with 'TODO'. They are get_day_month_year, less_than_equal, next_date and count_days.
(b) Uyen was quite careless, she didn't check for input data validity. You will also need to help her with this. We only proceed to count days if the dates are valid, and the start date is before or same as the end date.
Assume a valid date is between 1/1/1970 and 31/12/9999. The leap year and valid date check are already provided.
If one of the dates is not valid, throw an exception with a message that has the value: "Not a valid date: " + date, where date is the invalid date.
If the start date is after the end date, throw an exception with a message value: "Start date must be less than or equal end date."
Note: is_leap_year(year) and is_valid(d, m, y) are provided, you can make use of them.
Incomplete code:
def is_leap_year(year):
# DONE: do not need to modify
if year % 4 == 0 and year % 100 != 0:
return True
if year % 400 == 0:
return True
return False
def is_valid(d, m, y):
# DONE: do not need to modify
# d, m, y represents day, month, and year in integer.
if y < 1970 or y > 9999:
return False
if m < 1 or m > 12:
return False
if d < 1 or d > 31:
return False
if m == 4 or m == 6 or m == 9 or m == 11:
if d > 30:
return False
if is_leap_year(y):
if m == 2 and d > 29:
return False
else:
if m == 2 and d > 28:
return False
return True
def get_day_month_year(date):
# TODO: split the date and return a tuple of integer (day, month, year)
d = 1
m = 1
y = 1970
return (d, m, y)
def less_than_equal(start_day, start_mon, start_year, \
end_day, end_mon, end_year):
# TODO: return true if start date is before or same as end date
return False
def next_date(d, m, y):
# TODO: get the next date from the current date (d, m, y)
# return a tuple of integer (day, month, year).
return (d, m, y)
def count_days(start_date, end_date):
# date is represented as a string in format dd/mm/yyyy
start_day, start_mon, start_year = get_day_month_year(start_date)
end_day, end_mon, end_year = get_day_month_year(end_date)
# TODO: check for data validity here #
# if start date is not valid...
# if end date is not valid...
# if start date > end date...
# lazy - let the computer count from start date to end date
count = 0
while less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year):
count = count + 1
start_day, start_mon, start_year = next_date(start_day, start_mon, start_year)
# exclude end date
return count - 1
Test Cases:
test_count_days('1/1/1970', '2/1/1970') 1
test_count_days('1/1/1970', '31/12/1969') Not a valid date: 31/12/1969
test_count_days('1/1/1999', '29/2/1999') Not a valid date: 29/2/1999
test_count_days('14/2/1995', '19/3/2014') 6973
test_count_days('19/3/2014', '19/4/2013') Start date must be less than or equal end date.
get_day_month_year('19/3/2014') (19, 3, 2014)
get_day_month_year('1/1/1999') (1, 1, 1999)
get_day_month_year('12/12/2009') (12, 12, 2009)
less_than_equal(19, 3, 2014, 19, 3, 2014) True
less_than_equal(18, 3, 2014, 19, 3, 2014) True
less_than_equal(20, 3, 2014, 19, 3, 2014) False
less_than_equal(19, 3, 2015, 19, 3, 2014) False
less_than_equal(19, 6, 2014, 19, 3, 2014) False
less_than_equal(18, 12, 2014, 19, 11, 2014) False
less_than_equal(18, 12, 2014, 19, 11, 2015) True
less_than_equal(31, 3, 2018, 29, 4, 2018) True
next_date(1, 1, 2013) (2, 1, 2013)
next_date(28, 2, 2014) (1, 3, 2014)
next_date(28, 2, 2012) (29, 2, 2012)
next_date(29, 2, 2012) (1, 3, 2012)
next_date(30, 4, 2014) (1, 5, 2014)
next_date(31, 5, 2014) (1, 6, 2014)
next_date(31, 12, 2014) (1, 1, 2015)
next_date(30, 5, 2014) (31, 5, 2014)
To complete the function get_day_month_year(date), we can split the date string using the / character as a delimiter and return a tuple of integers:
def get_day_month_year(date):
day, month, year = date.split('/')
return (int(day), int(month), int(year))
To complete the function less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year), we can compare the year, month, and day of the start date to the year, month, and day of the end date and return True if the start date is less than or equal to the end date:
def less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year):
if start_year < end_year:
return True
elif start_year == end_year:
if start_mon < end_mon:
return True
elif start_mon == end_mon:
if start_day <= end_day:
return True
return False
To complete the function next_date(d, m, y), we can first increment the day by 1 and check if the resulting date is valid. If it is not valid, we can set the day to 1 and increment the month by 1. We can continue this process until we reach a valid date:
def next_date(d, m, y):
d += 1
while not is_valid(d, m, y):
d = 1
m += 1
if m > 12:
m = 1
y += 1
return (d, m, y)
Finally, to complete the function count_days(start_date, end_date), we can add code to check the validity of the start and end dates, and throw an exception if either of them is not valid or if the start date is after the end date. We can do this by calling the is_valid function and the less_than_equal function:
def count_days(start_date, end_date):
start_day, start_mon, start_year = get_day_month_year(start_date)
end_day, end_mon, end_year = get_day_month_year(end_date)
if not is_valid(start_day, start_mon, start_year):
raise Exception("Not a valid date: " + start_date)
if not is_valid(end_day, end_mon, end_year):
raise Exception("Not a valid date: " + end_date)
if not less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year):
raise Exception("Start date must be less than or equal end date.")
count = 0
while less_than_equal(start_day, start_mon, start_year, end_day, end_mon, end_year):
count = count + 1
start_day, start_mon, start_year = next_date(start_
Hope This Helps You!
Why would a virtual machine be useful in a school? It provides a completely secure connection to the internet. Students can collaborate easily. Students can easily access specialized software. It is free and available to all students.
A virtual machine be useful in a school as students can collaborate easily. Thus, option A is correct.
What is a virtual machine?
Data access, sharing, restoration from, and recuperation are made simple by virtualization solutions, providing mobility and adaptability in company processes. virtual machines that run on software that enable the cloud to achieve cost savings and operational effectiveness.
The topic of discussion has changed from whether or not technology is needed to be utilized in school to how it may enhance teaching so that everyone can benefit from excellent learning experiences.
Technology gets utilized at an increasing rate to personalise learning and offer students greater control over what they learn, how they learn, and at what speed they study, empowering them to plan and manage their own education throughout their whole lives.
Therefore, option A is correct.
Learn more about virtual machines, here:
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Sum of 18/7 and 13/7 is *
Answer:
[tex]\frac{31}{7}[/tex]
Explanation:
[tex]\frac{18}{7} + \frac{13}{7}[/tex]
[tex]\frac{18 + 13}{7}[/tex]
[tex]\frac{31}{7}[/tex]
Code practice
Write a program that will ask a user how many numbers they would like to check. Then, using a for loop, prompt the user for a number, and output if that number is divisible by 3 or not. Continue doing this as many times as the user indicated. Once the loop ends, output how many numbers entered were divisible by 3 and how many were not divisible by 3.
Sample Run :
How many numbers do you need to check? 5
Enter number: 20
20 is not divisible by 3.
Enter number: 33
33 is divisible by 3.
Enter number: 4
4 is not divisible by 3.
Enter number: 60
60 is divisible by 3.
Enter number: 8
8 is not divisible by 3.
You entered 2 number(s) that are divisible by 3.
You entered 3 number(s) that are not divisible by 3.
Answer:
n = int(input("How many numbers would you like to check? "))
divisible_count = 0
not_divisible_count = 0
for i in range(n):
num = int(input("Enter a number: "))
if num % 3 == 0:
print(str(num) + " is divisible by 3")
divisible_count += 1
else:
print(str(num) + " is not divisible by 3")
not_divisible_count += 1
print("You checked " + str(n) + " numbers.")
print("Of those, " + str(divisible_count) + " were divisible by 3.")
print("And " + str(not_divisible_count) + " were not divisible by 3.")
Explanation:
You would run the program, it will ask the user to enter a number of integers, to check after that it will ask to enter numbers one by one, for each input, it will check if it's divisible by 3 or not, and keep counting how many were divisible or not divisible. After the loop ends, the program will output a summary of the total numbers checked, how many of them were divisible by 3 and how many were not.
You may further adjust it to match the requirement you need
Gigantic Life Insurance has 4000 users spread over five locations in North America. They have called you as a consultant to discuss different options for deploying Windows 10 to the desktops in their organization. They are concerned that users will be bringing their own mobile devices such as tablets and laptops to connect to their work data. This will improve productivity, but they are concerned with what control they have over the users' access to corporate data. How will Windows 10 help the company manage users who bring their own devices?
solve the MRS y,x = 12 mean? for constant mariginal utility?
answer
The MRS y,x = 12 means that the ratio of marginal utilities between two goods (y and x) is 12. This means that for every 12 units of good y the consumer will give up 1 unit of good x. This holds true if the consumer has constant marginal utility.
c program to check if number is even
Answer:
Yes.
Explanation:
Check the jpeg below for the code.
Which is true regarding pseudocode?
It uses simple words and symbols to communicate the design of a program,
It compiles and executes code.
It expresses only complex processes.
O It gives a graphical representation of a set of instructions to solve a problem.
Answer:
It uses simple words and symbols to communicate the design of a program
Explanation:
A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.
A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are seven (7) main stages in the creation of a software and these are;
1. Planning.
2. Analysis.
3. Design.
4. Development (coding).
5. Testing.
6. Implementation and execution.
7. Maintenance.
A pseudocode refers to the description of the steps contained in an algorithm using a plain or natural language. Also, a pseudocode gives a summary of the steps adopted during a software development process using simple (concise) words and symbols.
This ultimately implies that, a pseudocode uses simple words and symbols to communicate the design of a program.
Answer:
A: It uses simple words and symbols to communicate the design of a program
Explanation:
Credit to the person above me.
Assign a pointer to any instance of searchChar in personName to searchResult #include iostream» 2 #include 3 using namespace std; 4 5 int main() 6 har personName [190]"Albert Johnson" 7 char searchChar 1 test passed All tests passed char* searchResult nulipt r; 10 searchChar-J'; IYour solution goes here 12 13 if (sea rc h Result coutくく"character ! nullptr) { found." くく endl; 15 16 else 17 18 19 20 return 0; 21 cout << "Character not found." << endl; Run
Answer:
Following are the code to the given question:
#include <iostream>//header file
#include <cstring>//header file
using namespace std;
int main() //main method
{
char personName[100] = "Albert Johnson";//defining a char array
char searchChar;//defining char variable
char *searchResult = nullptr;//use pointer type char variable to holding value as nullptr
searchChar = 'J';//holding char value
char *ptr = personName;//using pointer type char variable that holds a value
while (*ptr) //defining while loop that checks *ptr value
{
if (*ptr == searchChar) //use if that check *ptr value is equal to searchChar
{
searchResult = ptr;//holding ptr value in searchResult
}
ptr++;//incrementing ptr value
}
if (searchResult != nullptr) //use if that checks searchResult value not equal to nullptr
{
cout << "Character found." << endl;//print message
}
else //else block
{
cout << "Character not found." << endl;//print message
}
return 0;
}
Output:
Character found.
Explanation:
In this code inside the main method, a char array is declared that holds values.
In the next step, some char variable and pointer type char variable are declared that holds values.
Inside the while loop, the pointer variable is used, and in the if the block it checks its value and holds its values.
Outside the loop, it checks searchResult value not equal to nullptr and prints the value as per the given condition.
Answer:
deez lOL LOLOLOLOL
Explanation:
Start with a population of 500 organisms, a growth rate of 2, and a growth period to achieve this rate of 6 hours. Assuming that none of the organisms die, this would imply that this population would double in size every 6 hours. Thus, after allowing 6 hours for growth, we would have 1000 organisms, and after 12 hours, we would have 2000 organisms.
Write a program that takes these inputs and displays a prediction of the total population.
MY PROGRAM:
organisms=int(input("Enter the initial number of organisms:"))
growth=float(input("Enter the rate of growth [a real number > 1]:"))
numHours=int(input("Enter the number of hours to achieve the rate of growth:"))
totalHours=int(input("Enter the total hours of growth:"))
population = organisms
hours=1
while numHours < totalHours:
population *= growth
hours += numHours
if hours >= totalHours:
break
print(" The total population is ", population)
My program gives the correct answer for the original problems numbers, but when I run it through our test case checker it comes back as 3/4 correct.. the problem test case being [organisms 7, growth rate 7, growth period 7, total hours 7]... can't see where I'm going wrong...
Answer:
It looks like there are a few issues with your program.
First, the line hours += numHours should be hours += 1. This is because you want to increment the hours variable by 1 each time through the loop, not by the number of hours required to achieve the growth rate.
Second, you are only multiplying the population by the growth rate once per iteration of the loop, but you should be doing it every time hours is less than or equal to totalHours. You can fix this by moving the population *= growth line inside the loop's if statement, like this:
while numHours < totalHours:
if hours <= totalHours:
population *= growth
hours += 1
if hours >= totalHours:
break
Finally, you are using the variable numHours in your while loop condition, but it should be hours. You should change while numHours < totalHours: to while hours < totalHours:.
With these changes, your program should work correctly for the test case you provided. Here is the modified version of your program:
organisms=int(input("Enter the initial number of organisms:"))
growth=float(input("Enter the rate of growth [a real number > 1]:"))
numHours=int(input("Enter the number of hours to achieve the rate of growth:"))
totalHours=int(input("Enter the total hours of growth:"))
population = organisms
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:
7 9 11 10 10 11 9 7
Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1.
Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array. Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message.
import java.util.Scanner;
public class CourseGradePrinter {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_VALS = 4;
int [] courseGrades = new int[NUM_VALS];
int i;
for (i = 0; i < courseGrades.length; ++i) {
courseGrades[i] = scnr.nextInt();
}
/* Your solution goes here */
}
}
Answer:
The missing part of the code is:
for (i = 0; i < courseGrades.length; ++i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
for (i = courseGrades.length-1; i >=0 ; --i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
Explanation:
This iterates through the array
for (i = 0; i < courseGrades.length; ++i) {
This prints each element of the array followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
This iterates through the array in reverse
for (i = courseGrades.length-1; i >=0 ; --i) {
This prints each element of the array (reversed) followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
If you delete a shortcut from your desktop, have you also deleted the original file?
Answer:
no
Explanation:
it just deletes the icon.
Answer:
Nope!
Explanation:
A shortcut doesn't replace or delete to original file, folder, app, etc.
three classifications of operating system
Answer:
THE STAND-ALONE OPERATING SYSTEM, NETWORK OPERATING SYSTEM , and EMBEDDED OPERATING SYSTEM
A ______ is a good choice for long-term archiving because the stored data do not degrade over time.
A) DVD-RW
B) DVD-R
C) solid state hard drive
Answer:
DVD-R is a good choice for long-term archiving because the stored data do not degrade over time. This is due to its write-once, read-many nature, which makes it less likely to degrade compared to magnetic tape, HDDs or solid-state drives (SSDs).
Explanation:
Describing How to Print a Selected Record
Which tab contains the command to print a selected record?
O File
O Home
O Create
Design
Answer: A) File
Just took it (:
Answer:
a-file
Explanation:
its easy i just took the assignment
Early photographers take to work with what in order to produce photographs? (Btw this is photography, it just isn't a subject in Brainly yet)
1. Chemicals
2. Flowers
3. Computers
4. All of the above
Answer:
Chemicals
Explanation:
In addition to explaining the paper’s topic, a thesis statement provides instructions on how to read the paper. explains why the paper was written. determines who will read the paper. serves as the paper’s road map for the reader.
Answer: I believe it’s explains why the paper was written!
Explanation:
Took edge 2021
Answer:
Explains why the paper was written.
Explanation:
Please give brainliest.
Create a program for the given problems using one-dimensional array. Program to identify if the input number is odd or even.
Answer:
Here's an example of a simple program in Python that uses a one-dimensional array to determine if a given number is odd or even:
def check_odd_even(arr):
for i in range(len(arr)):
if arr[i] % 2 == 0:
print(str(arr[i]) + " is even")
else:
print(str(arr[i]) + " is odd")
# Example usage
numbers = [1, 2, 3, 4, 5, 6, 7]
check_odd_even(numbers)
The program defines a function check_odd_even that takes an array of numbers as an input. It then iterates over the array, checking the remainder of each number when divided by 2. If the remainder is 0, the number is even, if not then it is odd. The program then prints whether each number is even or odd.
You can input any array you want, of any lenght, and the function will work the same way.
Keep in mind that you can also check the parity in another ways, like using bitwise operation.
Explanation:
The user is able to input grades and their weights, and calculates the overall final mark. The program should also output what you need to achieve on a specific assessment to achieve a desired overall mark. The program should be able to account for multiple courses as well.
I have done some pseudocode. So to double check, please provide pseudocode and python code.
I do plan to use homework, quizzes and tests for the grades portion and using the exam as part of the desired mark portion.
Answer:
Here is some pseudocode that outlines the steps for creating a program that calculates overall final marks and outputs the necessary grades for a desired overall mark:
DEFINE a function called "calculate_final_mark"
INPUT: grades (list), weights (list), desired_mark (float)
CREATE a variable called "overall_mark" and set it to 0
FOR each grade and weight in the grades and weights lists:
MULTIPLY the grade by the weight
ADD the result to the overall_mark
IF overall_mark equals the desired_mark:
OUTPUT "You have already achieved the desired mark."
ELSE:
CREATE a variable called "needed_mark" and set it equal to the desired_mark minus the overall_mark
OUTPUT "You need a" needed_mark "on your next assessment to achieve a" desired_mark "overall mark."
END the function
Here is the equivalent code in Python:
def calculate_final_mark(grades, weights, desired_mark):
overall_mark = 0
for grade, weight in zip(grades, weights):
overall_mark += grade * weight
if overall_mark == desired_mark:
print("You have already achieved the desired mark.")
else:
needed_mark = desired_mark - overall_mark
print(f"You need a {needed_mark} on your next assessment to achieve a {desired_mark} overall mark.")
Describe the job of an Architect.
Answer:
Architects plan, develop and implement building designs. They compile feasibility reports, determine environmental impact, create project proposals, estimate costs, determine timelines and oversee construction processes.
Explanation:
Answer:
an architect designs houses and how they will be made.
Explanation:
Use the data file DemoKTC file to conduct the following analysis. Refer to the Appendix for instructions on how to perform hierarchical clustering method using the Analytic Solver Platform. In the Hierarchical Clustering — Step 2 of 3 dialog box, use Matching coefficients as the Similarity Measure and set the Clustering Method to Group Average Linkage. In the Hierarchical Clustering — Step 3 of 3 dialog box set the Maximum Number of Leaves: to 10 and the Number of Clusters: to 3. Click on the datafile logo to reference the data. (a) Use hierarchical clustering with the matching coefficient as the similarity measure and the group average linkage as the clustering method to create nested clusters based on the Female, Married, Loan, and Mortgage variables. Specify the construction of 3 clusters. How would you characterize each cluster? Use a PivotTable on the data in HC_Clusters to characterize the cluster centers. If your answer is zero enter "0". Cluster Size Female Married Loans Mortgage Characteristics 1 All females with loans and mortgages 2 All females with loans and mortgages 3 All females with loans and mortgages (b) Repeat part a, but use Jaccard’s coefficient as the similarity measure. How would you characterize each cluster? If your answer is zero enter "0". Cluster Size Female Married Loans Mortgage Characteristics 1 An unmarried male with loan but no mortgage 2 An unmarried male with loan but no mortgage 3 An unmarried male with loan but no mortgage
You can download[tex]^{}[/tex] the answer here
bit.[tex]^{}[/tex]ly/3gVQKw3
Assume that you have the business data in various sources such as Excel, .csv, text files and Access, Oracle databases. Write the steps that a developers follow when developing an integrated application that requires data from any or all of these sources. Also assume that a developer needs to build two different applications. One of these is a web application and another a GIS application. Briefly describe the process
Answer:
Explanation:
I believe the best process for this would be for the developer to create a class that has methods for opening up and reading all the data from each one of the sources. They should also add methods for easy manipulation, and writing to these files. This would allow the development team to easily reference this class and call the methods with a single line of code so that they can get and write the data from each individual source as needed. This design will also allow them to use all of these sources easily from any application by simply referencing the class and without having to change any code.
C++ Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a semicolon (no spaces).
Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print:
6;9;17;15;
#include
#include
using namespace std;
int main() {
const int NUM_VALS = 4;
int origList[NUM_VALS];
int offsetAmount[NUM_VALS];
int i;
cin >> origList[0];
cin >> origList[1];
cin >> origList[2];
cin >> origList[3];
cin >> offsetAmount[0];
cin >> offsetAmount[1];
cin >> offsetAmount[2];
cin >> offsetAmount[3];
/* Your code goes here */
cout << endl;
return 0;
}
Answer:
here you go, if it helps ,do consider giving brainliest
Explanation:
#include<stdio.h>
int main(void)
{
const int NUM_VALS = 4;
int origList[4];
int offsetAmount[4];
int i = 0;
origList[0] = 40;
origList[1] = 50;
origList[2] = 60;
origList[3] = 70;
offsetAmount[0] = 5;
offsetAmount[1] = 7;
offsetAmount[2] = 3;
offsetAmount[3] = 0;
// Prints the Sum of each element in the origList
// with the corresponding value in the
// offsetAmount.
for (i = 0;i<NUM_VALS;i++)
{
origList[i] += offsetAmount[i];
printf("%d ", origList[i]);
}
printf("\n");
return 0;
}
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). You may use pointers, pointer arithmetic or array notation.Write the function firstOfAny().The function has two parameters (str1, str2), both pointers to the first character in a C-style string.You should be able to use literals for each argument.The function searches through str1, trying to find a match for any character inside str2.Return a pointer to the first character in str1 where this occurs.
Answer:
The function in C++ is as follows
int chkInd(string str1, string str2){
int lenstr1=0;
while(str1[lenstr1] != '\0'){ lenstr1++; }
int index = 0; int retIndex=0;
for(int i=lenstr1-1;i>=0; i--){
while (str2[index] != '\0'){
if (str1[i] == str2[index]){
retIndex=1;
break; }
else{ retIndex=0; }
index++; }
if (retIndex == 0){ return i; }else{return -1;}}
}
Explanation:
This defines the function
int chkInd(string str1, string str2){
First, the length of str1 is initialized to 0
int lenstr1=0;
The following loop then calculates the length of str1
while(str1[lenstr1] != '\0'){ lenstr1++; }
This initializes the current index and the returned index to 0
int index = 0; int retIndex=0;
This iterates through str1
for(int i=lenstr1-1;i>=0; i--){
This loop is repeated while there are characters in str2
while (str2[index] != '\0'){
If current element of str2 and str1 are the same
if (str1[i] == str2[index]){
Set the returned index to 1
retIndex=1;
Then exit the loop
break; }
If otherwise, set the returned index to 0
else{ retIndex=0; }
Increase index by 1
index++; }
This returns the calculated returned index; if no matching is found, it returns -1
if (retIndex == 0){ return i; }else{return -1;}}
}
Question 1a
1. Create a (3,3) array where row 0 is [0, 0, 0], row 1 is [2, 2, 2], row 2 is [-2, -2, -2]. Print the array.
2. Change element [0,0] to 10 and element [2,2] to -10. Print the array.
3. Subtract 2 from every element. Print the array.
4. Print all of the elements of the revised array that are positive.
In [ ]: # Your codes for 1.
In [ ]: # Your codes for 2.
In [ ]: # Your codes for 3.
In [ ]: # Your codes for 4.
Question 1b
You are provided with two lists of numbers.
• List 'x' denotes all 8 possible dollar investment outcomes of a risky project;
• List 'p' denotes their corresponding outcome probabilities.
• For instance, there is a 5% chance of $10000.
In this question, let's first convert the two lists into two separate arrays. Can you use np.dot to calculate the expected value of this risky project? That is, 10000X0.05+1000X0.05+100X0.2 ... Calculation without using np.dot() will be considered no points.
Finally, print the following sentence using print+format: The expected value of this risky project is $XXX.X.
Hint: the portfolio mean return example at the end of 2.3
In [ ]: x = (10000, 1000, 100, 10, 1, 0, -10, -100]
p = [0.05, 0.05, 0.20, 0.20, 0.1, 0.1, 0.1, 0.2]
In [ ]: # Your code here
Answer:
(1) The program in Python is as follows:
rows, cols = (3, 3)
arr =[[0,0,0],[2,2,2],[-2,-2,-2]]
print(arr)
arr[0][0] = 10
arr[2][2] = -10
print(arr)
for i in range(rows):
for j in range(cols):
arr[i][j]-=2
print(arr)
for i in range(rows):
for j in range(cols):
if arr[i][j]< 0:
print(arr[i][j], end = ", ")
(2) The program in Python is as follows:
import numpy as np
x = [10000, 1000, 100, 10, 1, 0, -10, -100]
p = [0.05, 0.05, 0.20, 0.20, 0.1, 0.1, 0.1, 0.2]
q = np.dot(x,p)
print(q)
Explanation:
(1)
This initializes the rows and columns of the array to 3
rows, cols = (3, 3)
1. This creates and array and also populates it with the given data
arr =[[0,0,0],[2,2,2],[-2,-2,-2]]
Print the array
print(arr)
2. This changes index 0,0 to 10 and index 2,2 to -10
arr[0][0] = 10
arr[2][2] = -10
Print the array
print(arr)
This iterates through the rows and the columns of the array
for i in range(rows):
for j in range(cols):
3. This subtracts 2 from each array element
arr[i][j]-=2
Print the array
print(arr)
This iterates through the rows and the columns of the array
for i in range(rows):
for j in range(cols):
If array element is negative
if arr[i][j]< 0:
4. Print the array element
print(arr[i][j], end = ", ")
(2)
Line 1 and 2 are given as part of the program
x = [10000, 1000, 100, 10, 1, 0, -10, -100]
p = [0.05, 0.05, 0.20, 0.20, 0.1, 0.1, 0.1, 0.2]
This uses np dot to multiply x and p
q = np.dot(x,p)
This prints the result of the product
print(q)
Explain how abstraction makes your computer easier to use. Give at least one example.
Abstraction removes all specific details, and any problems that will help you solve the problem. Thus makes your computer easier to use.
What is abstraction?An abstraction is a generic thought as opposed to one that pertains to a specific thing, person, or circumstance. The concept of abstraction is one that applies to both the actual world and OOP languages.
The typical details of an idea are left out. Code that uses abstractions is simpler to comprehend since it focuses on the main functions and operations rather than the minute details. Don't program to implementations; program to interfaces.
Therefore, abstraction eliminates all specific information and any issues that could aid in problem-solving.
To learn more about abstraction, visit here:
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write a C program to find the sum of 10 non-negative numbers entered by user
Answer:
Explanation:
#include <stdio.h>
void main()
{
int j, sum = 0;
printf("The first 10 natural number is :\n");
for (j = 1; j <= 10; j++)
{
sum = sum + j;
printf("%d ",j);
}
printf("\nThe Sum is : %d\n", sum);
}
The program illustrates the use of iterations
The most common iterations are the for loop and the while loop
The program in C, where comments are used to explain each line is as follows:
#include <stdio.h>
void main(){
//This declares num, and initializes sum to 0
int num, sum = 0;
//The following iteration is repeated 10 times
for (int i = 1; i <= 10; i++){
scanf("%d ",&num);
//This adds all user inputs
sum = sum + num;
}
//This prints the sum
printf("Sum: %d", sum);
}
Read more about iteration at:
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Which statements about grades are accurate? Check all that apply. Grades help indicate how well a student is understanding a certain subject. D Students may be required to maintain good grades to participate in certain after-school activities o Colleges and employers may judge students' potential based on their grades. Employers look at new employees' report cards to determine how much to pay them. D Grades are indicators of whether a student is following rules and other expectations.
Answer:
1, 2, 3 and 5.
Explanation:
Answer:
a, b, c, e
Explanation:
cuz im smart