When these equations are solved, the value of x is 4 and the value of y is 3. Therefore, the value of x + y = 7.
To solve the system of equations, we will use the elimination method.
First, we multiply the first equation by 3 and the second equation by 5.
3(3x + 5y = 9)
5(5x + 3y = 7)
Then, we add the equations together:
9x + 15y = 27
25x + 15y = 35
Now, we subtract the second equation from the first to eliminate the x terms:
-16y = -8
y = 0.5
Next, we plug this value for y into one of the original equations and solve for x:
3x + 5(0.5) = 9
3x = 8.5
x = 2.83
Finally, we plug the values of x and y into the original equation to verify that they are correct:
3(2.83) + 5(0.5) = 9
So, the value of x is 2.83 and the value of y is 0.5. Therefore, the value of x + y = 2.83 + 0.5 = 3.33.
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What will the width of the paper need to be ?
Triangle EFG is dilated by a scale factor of 2/3 to form a triangle E'F'G'. What is the measure of side E'F'?
By using scale factor formula we can evaluate the measure of side EF.
What happens when we dilate a triangle?When a triangle is dilated by scale factors.The base and height change by the scale factor s while the area changes by a factor of s^2. While the scale distances between points dilations do not change angles.Dilation is used to make the objects larger or smaller.
How do you find scale factor?The scale factor can be calculated when the new dimensions and the original dimensions are given. The basic formula to find the scale factor of a figure is Scale factor = Dimension of the new shape ÷ Dimension of the original shape.
From the question ΔE'F'G' is the image formed by the dilation of preimage ΔEFG.
Therefore,
2/3 =[tex]E_{1}[/tex][tex]F_{1}[/tex]/EF
EF=3/2[tex]E_{1}[/tex][tex]F_{1}[/tex]
By substituting any value of F'G' given in the equation we can evaluate the measure of side FG.
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1. The ratio of peaches in a box is constant. The table below compares the number of peaches that are in the box.
boxes peaches
2 6
blank 9
5 blank
6 18
2. The ratio of strawberries in a box is
constant. the table below compares the number of strawberries that are in the boxes
boxes strawberries
2 blank
4 12
5 15
8 blank
please help
The table representing ratio of peaches in a box should be completed as follows;
Boxes Peaches
2 6
3 9
5 15
6 18
The table representing ratio of strawberries in a box should be completed as follows;
Boxes Strawberries
2 6
4 12
5 15
8 24
How to complete the tables?In order to have a proportional relationship and equivalent ratios that is constant, the variables x for boxes and y for peaches must have the same constant of proportionality. Next, we would determine the constant of proportionality (k) based on the given parameters:
Constant of proportionality (k) = y/x
Constant of proportionality (k) = 6/2 = 18/6
Constant of proportionality (k) = 3.
When y = 9 peaches, the value of x is given by;
x = y/k
x = 9/3
x = 3 boxes.
When x = 5 boxes, the value of y is given by;
y = kx
y = 3(5)
y = 15 peaches.
Question 2:Also, we would determine the constant of proportionality (k) based on the given parameters:
Constant of proportionality (k) = y/x
Constant of proportionality (k) = 12/4 = 15/5
Constant of proportionality (k) = 3.
When x = 2 boxes, the value of y is given by;
y = kx
y = 3(2)
y = 6 strawberries.
When x = 8 boxes, the value of y is given by;
y = kx
y = 3(8)
y = 24 strawberries.
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what are the domain and range of the function f(x)=2^x+1
Answer: The domain is all values of x that make the expression defined. The range is the set of all valid y values
Step-by-step explanation:
Therefore , the solution of the given problem of function comes out to be Domain: (-∞, ∞) and Range: (0,∞).
What is function?Any input will only result in one or zero outcomes for the function. The expression does not define the function if there are several outputs for a given input. Each value of x must have only one output value of y variable in order for anything to be a function.
Here,
Given : f(x)=[tex]2^{x}[/tex]+1
If a value has not been added, an exponential function's curve normally approaches a horizontal asymptote at y=0 or the x-axis. The curve changes if it has.
The asymptote is unaffected by this function's addition on the exponent because it does not apply to the entire function.
The values of its y-axis remain between 0 and. This is the set of y values, or the range.
However, depending on the leading coefficient, the range of exponentials can vary. If the value is negative, the graph turns inside-out and the range reaches -. It's also lacking in this.
The exponent's addition to 1 moves the function to the left without changing the range.
The x values in exponential functions are often unaffected and all are taken into account in the function. The domain stays the same even while it changes. Its range is (0,∞)
Range: (0,∞)
Therefore , the solution of the given problem of function comes out to be
Domain: (-∞, ∞) and Range: (0,∞).
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HELP DUE IN 15 MINS!
The opposite angles of a parallelogram are congruent.
True
False
Answer:
True
Step-by-step explanation:
A rectangle is a parallelogram with four right angles, opposite sides parallel, opposite sides congruent, opposite angles congruent, consecutive angles are supplementary, and the diagonals bisect each other.
Hope it is helpful....Which of the following numbers is 90 divisible by?
2, 3, 4, 5, 6, 9, and 10 only
A. 2, 3, 4, 5, 6, 9, and 10 only B. 2, 3, 5, 6, 9 and 10 only
C. 2, 3, 6, 9, and 10 only D. 2, 5, 9, and 10 only
Answer:
B
Step-by-step explanation:
90/2= 45
90/3= 30
90/5= 18
90/6= 15
90/9= 10
90/10= 9
90/4= 22.5
The table shows information about the masses of some dogs.
a) Work out the minimum number of dogs that could have a mass of more than
27 kg
b) Work out the maximum number of dogs that could have a mass of more than
27 kg
a) The minimum number of dogs that could have a mass of more than 27 kg is 6.
b) The maximum number of dogs that could have a mass of more than 27 kg is 18.
We have a table which shows information about the masses of some dogs.
Now , we need to determine the minimum number of dogs could have a mass more than 27 kg . Let us see dogs with mass of more than 27 kg present in the following intervals , 20≤x<30 and 30≤x<40 with 12 and 6 respectively.
But we wants minimum of 12 and 6 is 6 .
so, the minimum number of dogs with mass more than 27 kg is 6.
b) We need to determine maximum number of dogs with mass more than 27 kg ,so Maximum is equals to sum of number of dogs present in interval 20≤x<30 and in interval 30≤x<40 = 12+6 = 18. So, required maximum number of dogs are 18.
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Complete question:
The above table shows information about the masses of some dogs.
a) Work out the minimum number of dogs that could have a mass of more than 27 kg
b) Work out the maximum number of dogs that could have a mass of more than 27 kg
NO LINKS Consider the isosceles trapezoid.
What is the value of y?
Answer:
y = 9 x= -11
Step-by-step explanation:
opposite angles of a trapezoid are supplementary.
The two angles of the same base in an isosceles triangle are congruent.
-6x-16 = 50
-6x = 66
x= -11
The supplementary of 50 is 130
3x+16y+19 = 130
-33 +16y +19 = 130
16y = 144
y = 9
The sum of all 4 angles is 360 degrees
a. Complete the table to show the length of the field for each given width.
Width (feet) Length (feet) 0 50 100 150 200 250 300
b. Define the function (w) to represent the length of the field as
The length of the field for the missing width is 350 ft. and the function (w) to represent the length of the field is w = (l-50)
What is a function?A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Given that a table for showing the relation between length and width of a field;
Width (w) Length (l)
0 50
100 150
200 250
300 350
We see, that, width is 50 less than the length.
Therefore, the function (w) to represent the length of the field will be =
w = l-50
Hence, the length of the field for the missing width is 350 ft. and the function (w) to represent the length of the field is w = (l-50)
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Solve the system by graphing
2x-3y=-6
7x-3y=9
Following is the graph of two given equations.
The mapping of functions of two variables onto a Cartesian coordinate system, which is made up of a horizontal x-axis, or abscissa, and a vertical y-axis, or ordinate, is done analytically through the use of graphs. The intersection of each axis, which is a real number line, at its zero point is known as the origin.
On solving the two equations,
2x-3y=-6 ....(1)
7x-3y=9 .....(2)
Firstly we will find common points by elimination -
The common points are - (3,4)
Then We can find all the values of equation (1)
2x-3y=-6
x 0 3 -3
y 2 4 0
7x-3y=9
x 0 3 10
y -3 4 20.33
The respective graph is attached below
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Write your own statical question.Can someone give me one to right down please
can I explain what statistical mean
Mike has $25 in his savings account. He earns $8 for every lawn he mows, and he plans to put it all in savings. Write and solve an inequality to find how many lawns would he have to mow to earn at least $65 1. Define the wariable: 2. Write the inequality and solve: 3. Answer the problem:
2x × 3y(4 - 8) + 8(4y - 2x)
Answer:
5.3
Step-by-step explanation:
Solve 12 (10x + 3 -8y)
Answer:
120x - 96y + 32
Step-by-step explanation:
12 (10x + 3 -8y)
We use the distributive property to solve
120x - 96y + 32
One of the most important when writing the order of an equation is always written the number with the variable first; that is why the answer is
120x - 96y + 32
The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
Answer:
-4,-2,2
Step-by-step explanation:
look where line reaches zero
What is the circumference of the circle? Assume pi = 3.14
Answer:
5 x 2 x 3.14 = 31.4
Formula of circumference:
radius(half of your diameter or given radius) x pi(3.14 or 22/7 depending on what they tell you to use for pi) x 2(just always there when finding circumference)
Answer:
Circumference : 31.4 cm
Step-by-step explanation:
Circumference = 2× 3.14 × 5 cm
= 10× 3.14 cm
= 31.4 cm
ILL MARK YOU BRAINLEST IF YOU AWNSER PLEASE!! look at the photo and what is the measure of x? help me please!!
Wanda has 5 different fish in a small, crowded tank. She decides to randomly scoop up individual fish and transfer them to a new tank until a total of 4 fish have been moved. How many sequences of 4 fish are possible?
Answer:
64 sequences of 4 fish are possible.
Just one question I only need the answer (I will give brainly) pls do #4 and if you feel like being a nice person you could do 5 to
A spinner with equal sections numbered from 1 to 5 is spun twice. Raul is finding the probability that both spins will result in an even number. Find his mistake and explain what he should have done instead.
(2/5) x (1/4) =(2/10)
please help im really just about to cry myself to sleep and call it a day bcs im off the edge rn and i have to deal with school at the same time T_T
Answer:
his mistake is that he didn't need to remove one even number on the spinner so we just need to take 2/5x1/5equals2/25
5. Suppose you went on vacation but forgot your smart phone
charging cable. Your phone battery died after two full days
(48 hours) of use. This situation is modeled by the equation
f(h) = 48, where h is the hours of cell phone use and
f(h)is the percentage of battery life left.
What is the upper bound of the parameter h?
hrs
What is the lower bound of the parameter h? •
hrs
The upper and lower bounds of the parameter h is found to be 0 and 1 respectively.
What is upper and lower bound of a function?
A number U serves as an upper bound for a function f, meaning that for any x, f(x) ≤ U. A number L serves as a function's lower bound, ensuring that for all x, f(x) ≥ L.
Given,
[tex]f(h) = \frac{48-h}{48}[/tex]
where f(h) = Percentage of battery left
h = Hours of cell phone use
Lower Bound of parameter h,
h = 0 ( When percentage is 100%)
f(h) = [tex]\frac{48 - 0}{48}[/tex] = 1
Upper bound of parameter h,
h = 48 (When percentage is 0%)
f(h) = [tex]\frac{48-48}{48}[/tex] = 0
Therefore the upper bound of h is 0 and lower bound of h is 1.
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The area of different squares are shown. For each square, write an expression using a square root that can be used to estimate the length of one side.
Help me please! greatly appreciated if so!
Answer:
...
Step-by-step explanation:
since the area of a square is side² then we can just square root the area and find the side
first one to the left would be √16, which would equal 4, which in this case is correct
first one the right is √220 which is about 18.832
bottom left √65 which is about 8.062
bottom left √83 which is about 9.110
In a rhombus MNLP, diagonals intersect each other at point O. If m∠MNL is 120° and the length of the side is 8 in, find m∠MNO, m∠MON, and NP. A (5pts) Find m∠MNO. Answer
In a rhombus, all sides are equal and the diagonals intersect each other at a 90 degree angle and bisect each other.
Diagonal of a rhombus bisects the angles of the rhombus at the vertex.
So as m∠MNL is 120°,
∠MNO = ∠LNO = 120/2 = 60°
The diagonals intersect each other at a 90 degree angle, therefore
m∠MON = 90°
Considering ΔMNO, right angled at O.
cos(∠MNO) = NO/ MN
cos(60) = NO/ 8
NO = 0.5×8 = 4
NP = NO + OP
NP = 2NO
NP = 2×4
NP = 8 in
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Help ASAP plz need answer:)
What are the opposites of 8, −3.5, 1.15, and 7/1/4
The point A has coordinates (0,6)What point do we get when we reflect A across the x-axis and then across the y-axis?
(Choice A)
A
(Choice B)
B
(Choice C)
C
(Choice D)
D
(Choice E)
E
PLEASE ANSWER ASAP!!!!!!!!!!!!!!!! I'LL GIVE BRAINLIEST!!!!!!!!
Answer:
The answer is C
Step-by-step explanation:
opposite of y-axis.
PLEASE HELP ILL BRAINLIEST YOU
Answer:
let's take AC as x
AB is half of AC making it ½x
½x+½x+x+x=120
3x=120
[tex] \frac{3x}{3} = \frac{120}{3} [/tex]
x =120÷3
x=40
therefore AC is 40 while AB is 20
Answer:
AB = 20 ft
AC = 40 ft
Step-by-step explanation:
Perimeter of a rectangle = 2(l+b)
Perimeter (given) = 120 ft.
AB = ½ of AC
AC = 2 AB
Let x be the length of AB.
Then, AC = 2x
Now,
2(2x+x) = 120
2×(3x) = 120
6x = 120
x = 120/6 = 20 ft.
2x = 2×20 = 40 ft.
AB = 20 ft.
AC = 40 ft
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 224 cars owned by students had an average age of 5.06 years. A sample of 233 cars owned by faculty had an average age of 7.19 years. Assume that the population standard deviation for cars owned by students is 3.42 years, while the population standard deviation for cars owned by faculty is 2.81 years. Determine the 95% confidence interval for the difference between the true mean ages for cars owned by students and faculty. Step 2 of 3 : Calculate the margin of error of a confidence interval for the difference between the two population means. Round your answer to six decimal places.
The difference between the population means - 3.4 and -1.84 when calculated is found to be -2.62 years.
The 95% confidence interval for the difference in true mean ages of cars owned by students and faculty is between -3.4 and -1.84 years.
We know that the sample of 138 cars which belongs to the students have an average age of 5.13 years. The standard deviation = 3.45 years.
Then again,
A sample of 111 cars which belongs to the faculty have an average age of 7.75 years. The standard deviation= 2.08 years.
So the difference between them will be , s - f
= 3.45 - 2.08 = 1. 37
and the mean will be , mean of students - mean of faculty =
-2.62.
This is the point of difference between their means.
The SD is found to be as 0.3961.
and MOE is 0.78
with these details now we will calculate the required intervals,
The lower end is found to be as -2.62 - 0.78 = -3.4
The upper end is found to be as -2.62 + 0.78 = -1.84
Therefore, the mean difference between the cars is - 3.4 and -1.84.
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4/3 divided by 12= simplified and fraction form!
Answer:
[tex]{\huge\pink{\fbox{{࿐αɴѕωєя࿐}}}}[/tex]
[tex] \frac{4}{3} \div 12 \\ = \frac{4}{3} \times \frac{1}{12} \\ = \frac{4}{3 \times 12} \\ = \frac{4}{36} \\ = \frac{1}{9 } \\ = 0.11[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
[tex] \huge\red{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]
Answer:
1/9 is the answer
4/3 x 1/12 just multiply but the reciprocal
hope this helps
have a good day :)
Step-by-step explanation:
David launches a rock straight up over the edge of a 60-foot cliff and into the ocean. after 4 seconds, the rock reaches a maximum height of 108 feet. Six seconds later, the rock enters the ocean.
A) Write a function to model the scenario
B) Create a table of at least five values to represent the scenario
C) Identify how you see the X- and Y- intercepts in the table, graph, and equation.
Answer:
David launches a rock straight up over the edge of a 60-foot cliff and into the ocean. After 4 seconds, the rock reaches a maximum height of 108 feet. Six seconds later, the rock enters the ocean. . Create a graph to represent the scenario. The graph should include at least the x- and y-intercepts and the vertex. (A complete graph consists of axis labels and appropriate scales, ordered pairs for each identified point, the function, and appropriate domain/range.) . Write a function to model the scenario. Part C. Create a table of values to represent the scenario. Be sure to include at least five values. Values should include at least the x- and y-intercepts and the vertex. Part D. Identify how you see the x- and y-intercepts and vertex in the table, graph, and equation. (Hint: You may want to rewrite the equation in equivalent forms.)
Step-by-step explanation: