3x-8=3(x-4)+1 plz plz help me fast is it infinite or no or one solution
Answer:
no solution
Step-by-step explanation:
solve the equation
3x - 8 = 3(x-4) + 1
3x - 8 = 3x - 11
3x + 3 = 3x
x + 3 = x
A number x plus 3 cannot equal a number x.
the given equation has no solutions.
The equation 3x - 8 = 3(x - 4) + 1 is a linear equation. To determine the number of solutions, we can simplify and analyze the equation.
Expanding the right side of the equation, we have 3x - 8 = 3x - 12 + 1.
Simplifying further, we get 3x - 8 = 3x - 11.
By subtracting 3x from both sides, we have -8 = -11.
However, this leads to a contradiction. -8 is not equal to -11.
Since the equation leads to a contradiction, there is no solution to the equation.
In conclusion, the given equation has no solutions.
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In the figure shown, what is the measure of angle x?
O1) 100 degrees
O 2) 110 degrees
O3) 120 degrees
O4) 140 degrees
Answer:
C.) 120 or Option C is incorrect.
The answer is B.) 110
Step-by-step explanation:
See screenshot below
Hope this helps!
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Prove each of the following identities.
(e) (2 - sec^2 x)/(sec^2 x + 2tan x) = (cos x - sin x)/(cos x + sin x)
(f) cot^2 x - cot^2 y = (cos^2 x - cos^2 y)/(sin^2 x * sin^2 y)
The given trigonometry proof is given below
(a)[tex]\frac{1}{1+\sin (\theta)}+\frac{1}{1-\sin (\theta)}=2 \sec ^2(\theta)[/tex]
Manipulating left side
[tex]$$\begin{aligned}&\frac{1}{1+\sin (\theta)}+\frac{1}{1-\sin (\theta)} \\&\text { Simplify } \frac{1}{1+\sin (\theta)}+\frac{1}{1-\sin (\theta)}: \frac{2}{(\sin (\theta)+1)(-\sin (\theta)+1)} \\&=\frac{2}{(1+\sin (\theta))(1-\sin (\theta))}\end{aligned}$$[/tex]
Rewrite using trig identities
[tex]=\frac{2}{\cos ^2(\theta)}[/tex]
Use the basic trigonometric identity: [tex]\frac{1}{\cos (x)}=\sec (x)[/tex]
[tex]$$=2 \sec ^2(\theta)$$[/tex]
(b)[tex]\frac{\cos (x)}{1+\sin (x)}=\sec (x)-\tan (x)[/tex]
Manipulating right side
[tex]$$\sec (x)-\tan (x)$$[/tex]
Express with sin, cos
[tex]=\frac{1-\sin (x)}{\cos (x)}[/tex]
Rewrite using trig identities
[tex]=\frac{\cos (x)}{1+\sin (x)}[/tex]
(c)Manipulating right side[tex]$\tan (x)-\cot (x)$[/tex]
Express with sin, [tex]$\cos$[/tex]
[tex]$$\begin{aligned}&=\frac{-\cos ^2(x)+\sin ^2(x)}{\cos (x) \sin (x)} \\&\sin ^2(x)=1-\cos ^2(x) \\&=\frac{1-\cos ^2(x)-\cos ^2(x)}{\cos (x) \sin (x)} \\&=\frac{1-2 \cos ^2(x)}{\sin (x) \cos (x)}\end{aligned}$$[/tex]
(d) [tex]\frac{\sin (x)}{1-\cot (x)}+\frac{\cos (x)}{1-\tan (x)}=\sin (x)+\cos (x)[/tex]
Manipulating left side
[tex]\frac{\sin (x)}{1-\cot (x)}+\frac{\cos (x)}{1-\tan (x)}[/tex]
Express with sin, cos
[tex]=\cos (x)+\sin (x)[/tex]
(e)Manipulating left side
[tex]\frac{2-\sec ^2(x)}{\sec ^2(x)+2 \tan (x)}[/tex]
Express with sin, cos
[tex]=\frac{-1+2 \cos ^2(x)}{1+2 \cos (x) \sin (x)}$$[/tex]
Rewrite using trig identities
[tex]=\frac{\cos (x)-\sin (x)}{\cos (x)+\sin (x)}$$[/tex]
(f)Manipulating left side [tex]$\cot ^2(x)-\cot ^2(y)$[/tex]
Express with sin, cos
[tex]=\frac{\cos ^2(x) \sin ^2(y)-\cos ^2(y) \sin ^2(x)}{\sin ^2(x) \sin ^2(y)}$$[/tex]
Rewrite using trig identities
[tex]=\frac{\cos ^2(x)-\cos ^2(y)}{\sin ^2(x) \sin ^2(y)}$$[/tex]
Trigonometry is the field of mathematics that deals with certain angles' functions and how to use such functions in computations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).
The area of mathematics known as trigonometry examines the link between the ratios of a right-angled triangle's sides to its angles. Trigonometric ratios, such as sine, cosine, tangent, cotangent, secant, and cosecant, are employed to analyze this connection.
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5. How many different singing quartets can be formed from a class of 30 singers?
Answer:
7
Step-by-step explanation:
since a quartet consists of 4 people, it's basically asking how many groups of 4 can you make out of 30.
You can do this in your head or divide: 30 / 4 =7 r2
-3 + 4x = 41
What's x
Answer:
x=11 I hope it helps you
Step-by-step explanation:
The solution to the system is
( , )
Answer:
x = ½
y = 3
Step-by-step explanation:
—Math0,8 –4x = –0,4y ==> –4x + 0,4y = –0,8
6x + 0,4y = 4,2 ==> 6x + 0,4y = 4,2
______________–
–10x = –5,0
x = –5/–10
x = 1/2
–4x + 0,4y = –0,8
–4(½) + 0,4y = –0,8
–2 + 0,4y = –0,8
0,4y = –0,8 + 2
y = 1,2/0,4
y = 3
x = ½
y = 3
Follow my account^^
All edges of a cube are expanding at a rate of 2 centimeters per second.
(a) How fast is the volume changing when each edge is 2 centimeter(s)?
(b) How fast is the volume changing when each edge is 14 centimeter(s)?
Answer:
Part a → dv/dt = 24 cm³/per secondPart b → dv/dt = 1176 cm³/per secondStep-by-step explanation:
As all edges of a cube are expanding at a rate of 2 centimeters per second.
i.e ds/dt = 2 cm/s
The formula of volume of cube: V = s³
Differentiating the volume:
dv/dt = 3s²
Write ds/dt following derivative of volume
dv/dt = 3s² ds/dt
plug in the value: ds/dt = 2 cm/s
dv/dt = (3s²) (2)
dv/dt = 6s²
Given the edge is 2cm.
so plug in the value: s=2
dv/dt = 6s²
= 6(2)²=6(4)=24 cm³/per second
SIMILARLY,
When the edge is 14cm
dv/dt = 6s²
plug in the value: s=14
dv/dt = 6s²
= 6(14)²=6(196)=1176 cm³/per second
Thus,
Part a → dv/dt = 24 cm³/per secondPart b → dv/dt = 1176 cm³/per secondThe volume will be:
(a) 24 cm³
(b) 1176 cm³
Given:
Expanding rate,
2 cm/secLet,
The edge of a cube be "x cm".(a)
When,
x = 2 cmthen,
→ [tex]\frac{dx}{dt} = 2 \ cm/sec[/tex]
Let,
The volume of cube be "V"→ [tex]V = x^3[/tex]
→ [tex]\frac{dV}{dt} = 3x^2 \frac{dx}{dt}[/tex]
[tex]= 3\times 2^2\times 2[/tex]
[tex]= 3\times 4\times 2[/tex]
[tex]= 24 \ cm^3[/tex]
(b)
When,
x = 14 cmthen,
→ [tex]\frac{dx}{dt} = 2 \ cm/sec[/tex]
Let,
The volume of cube be "V"→ [tex]V = x^3[/tex]
→ [tex]\frac{dV}{dt} = 3x^2 \frac{dx}{dt}[/tex]
[tex]=3\times 14^2\times 2[/tex]
[tex]= 1176 \ cm^3[/tex]
Thus the above answer is correct.
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using arc length formula find s when r=24 and θ=π/2
48π
24π
12π
Answer:
12π
Step-by-step explanation:
The formula for arc length is given as:
[tex] s = \frac{\theta}{360\degree} \times 2\pi r[/tex]
Plug r = 24 and θ=π/2 in the above formula, we fi d:
[tex] s = \frac{\frac{\pi}{2}}{360\degree} \times 2\pi \times 24\\\\
s = \frac{\frac{\pi}{2}}{2 \pi} \times 48\pi\\\\
s = \frac{\pi}{2\times 2 \pi} \times 48\pi \\\\
s = \frac{\pi}{4\pi} \times 48\pi \\\\
\huge \purple {\boxed{s = 12\pi}} \\
[/tex]
Step-by-step explanation:
ghjkkknn. bjkkmn. bhcddfkkkk answer in image
solve this please.
Answer:
94
Step-by-step explanation:
Answer:
T<5,-2>
Step-by-step explanation:
It goes to the the right 5 and down 2 but it is put in a proper format
Please help its 50 points
Reflect on why you think the main character in "The White Umbrella" throws away her hard won prize.
Answer: The reason why the narrator throw the umbrella down the sewer after the car accident is that the umbrella symbolized the rejection of her mother The narrator feel ashamed about her working mother who cannot afford her the standard of living like she's seen in her friends. in the end, she feel ashamed of this and the umbrella remind her of her shameful thought about her mother
Step-by-step explanation:
Answer:
At first, she was upset. She had seen how Eugenie Roberts’s mother acted to her child and how she had treated them, with kindness and utmost interest. She was jealous because her mother had been working all of the time. After her mother came to pick them up, she told her mother she wanted her to quit her job, she didn't want her to work, she wanted to feel like every kid and have her mother there with her to let her know she loved her. And then she had gotten into an accident, in her anger, her mother tilted her head back and closed her eyes, waiting for the yelling people to approach her car. But she thought her mother was dead, she screamed at her mother to open her eyes, before her mother told her to be quiet because people were already going to yell at her and she couldn't take any more yelling. She threw her umbrella in the sewer. Deciding to never be that angry with her mother, for working again.
I hope this helps! :)
a campaign manager for a political candidate releases a series of advertisements
Is 5 in the solution of x+3>8?
Answer: D) No; If x is 5, the expression on the left simplifies to 8, making the inequality false.
In other words, if x = 5, then x+3 becomes 5+3 which ultimately becomes 8, but this is not greater than 8 on the right side.
Your steps could look like this
x+3 > 8
5+3 > 8 ... replace x with 5
8 > 8 ... this is a false inequality
Carrie has a stamp collection she is very proud of. She buys a frame to display her favorite stamps. The frame is 6 inches wide, and a row of 7 stamps fits perfectly across it.
How wide is each stamp?
PLS HELP I WILL GIVE U 30 POINTS !!!!!!!
The balance in Alex's bank account is $675. The account
earns 6% simple interest calculated twice per year. If Alex
makes no deposits or withdrawals for 2 full years, the
balance in his account (rounded to the nearest dollar) will
be -
Select one:
O
$852
$715
$837
$756
Answer:
$852
Step-by-step explanation:
From the given question, the following are given:
Present value, PV = $675
Rate, r = 6% = 0.06
Number of years, n = 2 years
Number of times per year, m = 2
The balance in his account is the future value (FV), so that;
Future value = PV[tex](1+r)^{nm}[/tex]
= 675[tex](1+0.06)^{(2*2)}[/tex]
= 675 x 1.26248
= 852.174
Future value = $852
Thus, the balance in Alex's account would be $852.
Convert the following equation
into slope-intercept form.
8x - 2y = -14
HELPPP ITS AN EMERGENCY!!!!!!
Answer:
The equation in point-slope is [tex]\mathbf{y+5=3(x-6)}[/tex]
Step-by-step explanation:
We need to write the point-slope form of the equation of the line passing through the point (6,-5) and perpendicular to the line [tex]y=-\frac{1}{3}x+4[/tex]
The general form of point-slope is; [tex]y-y_1=m(x-x_1)[/tex]
where m is slope and [tex](x_1,y_1)[/tex] is the point
We need to calculate slope.
We are given equation of line [tex]y=-\frac{1}{3}x+4[/tex] that is perpendicular to the required line.
The equation is given in slope-intercept form [tex]y=mx+b[/tex] where m is slope.
Comparing both equations we get m= -1/3
But we know that when lines are perpendicular their slopes are opposite reciprocal of each other i.e [tex]m=-\frac{1}{m}[/tex]
So, slope of required line is m = 3 (opposite reciprocal of -1/3)
Now, the equation in point-slope form having slope m=3 and point (6,-5) is
[tex]y-y_1=m(x-x_1)\\y-(-5)=3(x-6)\\y+5=3(x-6)[/tex]
So, The equation in point-slope is [tex]\mathbf{y+5=3(x-6)}[/tex]
The volume of two identical cubes is related to the edge length of the cubes.
Which function represents the combined volume of these cubes?
Fy = 2x
G y = x3
Hy = 8x3
Jy = 2x2
f(x)=3x-9; horizontal stretch factor of 6
The Horizontal stretch of the function f(x)=3x-9 by a factor of 6 is g(x)=x/2-9 .
The graph of the function y=f(x/a) represents a Horizontal Stretch by a factor of a of the graph y=f(x) , where a>0 and a≠1 .
To find the horizontal stretch we divide the input by a ,
In the given question
f(x)=3x-9 , is horizontally stretch by a factor of 6.
So we divide the inputs by 6 .
On dividing the inputs by 6 , we get
f(x/6)=3(x*1/6)-9 (...as 3/6=1/2)
Let g(x) represents the horizontal stretch of f(x) by factor 6 , So
g(x)=x/2-9
Therefore , the Horizontal stretch of the function f(x)=3x-9 by a factor of 6 is g(x)=x/2-9 .
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What is the solution to the system of equations that is graphed below?
Answer:
(-4,-3)
Step-by-step explanation:
will give brainliest!! please help me!!
Answer:
D
Step-by-step explanation:
A local fabric store advertises three and one-half yards of fabric for $4.50. If their everyday price per year is $1.15, is it less expensive to buy the fabric while it is on sale?
Answer:
one spool of thread costs $1.89
Step-by-step explanation:
$8.99x3=$26.97
$32.64-$26.97=$5.76
$5.76 divided by 3=$1.89
Solve for 8:
-0.2 = 8 +(-0.8)
what is 14 radical 2 divided by radical 2
Answer: either 14
Step-by-step explanation:
how do you find the perpendicular distance between a line segment and a point? (photo attached) i’m stuck
Answer:
Exact Distance = [tex]\frac{4\sqrt{10}}{5}[/tex]
Approximate Distance = 2.529822
============================================
Explanation:
This process is quite involved if you don't know the shortcut formula. I'll go over the long method first, and then show the shortcut in the next section.
First we'll need the equation of the line through points O and M. Use of the slope formula will show line OM has slope -1/3, which you are correct in stating.
Then use point slope form to determine the equation of line OM is y = (-1/3)x+11/3. This converts to the standard form x+3y = 11.
For anything in the form Ax+By = C, the equation perpendicular to this is of the form Bx-Ay = D. The A,B coefficients swap, and one item is negated. This helps form the negative reciprocal slope needed for the perpendicular line.
Compare x+3y = 11 to Ax+By = C. We see that A = 1 and B = 3.
So Bx-Ay = D turns into 3x-y = D. Then plug in the coordinates of H(-3,2) and compute to get
3x-y = 3(-3)-2 = -9-2 = -11. So D = -11
The equation 3x-y = D turns into 3x-y = -11 which is the equation of the line through point H and this line is perpendicular to line OM.
At this point, we have this system of equations
x+3y = 11
3x-y = -11
Solve that system however you wish. Substitution may be the best choice. Doing so leads to the intersection point (-2.2, 4.4)
The last step is to apply the distance formula between the points H(-3,2) and the intersection point (-2.2, 4.4)
The distance you should get is [tex]\frac{4\sqrt{10}}{5} \approx 2.529822[/tex]
I'm skipping steps because listing everything out would take up way too much space in my opinion.
--------------------------------------------------------
The first section goes over a fairly lengthy process of finding the perpendicular distance. Luckily, there's a shortcut.
Consider an equation of the form Ax+By=C, aka standard form. Now consider a point P located at (m,n) that is not on the line Ax+By = C. We can find the distance from P to the line using this formula below
[tex]d = \frac{|Am+Bn-C|}{\sqrt{A^2+B^2}}[/tex]
In this case, A = 1, B = 3 and C = 11 found back in the previous section. So you'll still need to calculate the equation of line OM.
Also, we'll use (m,n) = (-3,2) which are the coordinates of point H
From here it's a fairly straightforward computation
[tex]d = \frac{|Am+Bn-C|}{\sqrt{A^2+B^2}}\\\\d = \frac{|1*(-3)+3*2-11|}{\sqrt{(1)^2+(3)^2}}\\\\d = \frac{|-8|}{\sqrt{1+9}}\\\\d = \frac{8}{\sqrt{10}}\\\\[/tex]
Optionally we can rationalize the denominator like so
[tex]d = \frac{8}{\sqrt{10}}\\\\d = \frac{8\sqrt{10}}{\sqrt{10}\sqrt{10}}\\\\d = \frac{8\sqrt{10}}{\sqrt{10*10}}\\\\d = \frac{8\sqrt{10}}{\sqrt{100}}\\\\d = \frac{8\sqrt{10}}{10}\\\\d = \frac{2*4\sqrt{10}}{2*5}\\\\d = \frac{4\sqrt{10}}{5}\\\\d \approx 2.529822\\\\[/tex]
There are different ways to write down the answer, but they all represent the same number.
In a class, there are 18 girls and 14 boys. If the teacher selects two students at random to attend a party with the principal, what is the probability that the two students are the same sex?
Answer:
0.492 is the answer
Step-by-step explanation:
The probability that the two students are the same sex is 0.49.
Since the class contain 32 (18+14) children out of which 18 girls and 14 boys.
First step
Using general multiplication rule
P(Two girls)=P(First girls)×P(Second girl; First girl)
P(Two girls)=18/32×17/31
P(Two girls)=18×17/32×31
P(Two girls)=306/992
P(Two boys)=P(First boys)×P(Second boys; First boys)
P(Two girls)=14/32×13/31
P(Two girls)=14×13/32×31
P(Two girls)=182/992
Second step
Use addition rule for mutually exclusive events
P(Same sex)=P(Two girls)×P(Two boys)
P(Same sex)=306/992×182/992
P(Same sex)=306+182/992
P(Same sex)=488/992
P(Same sex)=61/124
P(Same sex)=0.49
Inconclusion the probability that the two students are the same sex is 0.49.
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I'm stuck on 2 choices? Can I have help?
Answer:
it has to be whole numbers
Step-by-step explanation:
because all of them are whole number no matter if there negative or positive
PLEASE HELP 100 points ASAP!
Question & Answer choices attached!
Answer:
C. Graph B
Step-by-step explanation:
y ≥ 2x + 3
y ≤ -2x - 4
To find which side of the line the answer is, we can set y and x to 0 and see if the equation is true or false (this only works if the cordance of (0,0) does not lie on the line)
0 ≥ 2(0) + 3
0 ≥ 3 FALSE (the side of the line that should be shaded is the one that does not include the cordance of (0,0))
0 ≤ -2(0) - 4
0 ≤ - 4 FALSE (the side of the line that should be shaded is the one that does not include the cordance of (0,0))
please helpppp!!!!!!!
-42=-7+5x
Solve for x
Answer:
x = -7
Step-by-step explanation:
-42=-7+5x
-42 + 7 = 5x
5x = - 35
x = -35/5
x = - 7
Hope it helps!
Answer:
x = -7
Step-by-step explanation:
Given equation:
[tex]-42 = -7 + 5x[/tex]
Simplify the equation.[tex]-42 = 5x -7[/tex]
2. Flip the equation.
[tex]5x + 7 = -42[/tex]
3. Add 7 to each side.
[tex]5x - 7 + 7 = -42 + 7[/tex]
[tex]5x = -35[/tex]
4. Divide both sides by 5.
[tex]\frac{5x}{5}[/tex] = [tex]\frac{-35}{5}[/tex]
5. Divide the fraction.
[tex]-35[/tex] ÷ [tex]5[/tex] = [tex]-7[/tex]