When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer 1

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs


Related Questions

when air gets hot, it rises and forms…

Answers

Answer:

Gas

Explanation:

Hot air rises because gases expand as they heat up. When air heats up and expands, its density also decreases.

What is 1/3 a millisecond in seconds (decimal form)? (0._ s)​

Answers

Answer:

I don't know

Explanation:

plz

plz mark me as brainlist

Which of the following statements about electromagnetic radiation it true? A.electromagnetic waves with long wavelength are more energetic then electromagnetic waves with short wavelength. B.all electromagnetic radiation carries the same amount of energy. C.electromagnetic radiation in a vacuum can change frequently to become more or less energetic. D.electromagnetic waves with high frequency are more energetic then electromagnetic waves with low frequency

Answers

Given what we know, we can confirm that option D,  Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency is true.

Why are high-frequency waves more energetic?

High-frequency waves are synonymous with short wavelengths. This means that the waves are oscillating much quicker and therefore carry more kinetic energy within them. This is transformed and released as electromagnetic radiation, which is the reason why high-frequency waves are more energetic than low-frequency electromagnetic waves.

Therefore, we can confirm that the statement "Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency" is true.

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What shape is the graph produced by a force vs acceleration graph?

A. Linear
B. Quadratic
C. Circular
D. Triangular

Answers

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

Since Force, F = ma where m = mass and a = acceleration. For constant mass, F ∝ a. That is, F is directly proportional to acceleration, a.

Since this is a linear relationship, the graph of force vs acceleration will be linear.

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

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Please HELP!!

Diagram's BELOW↓

1. What is the mass of the object experimented on in this situation?

a. 10 kg
b. 15 kg
c. 20 kg
d. 25 kg


2. What is the net force on this object?

a. 20 N to the left
b. 10 N up
c. 10 N down
d. 35 N to the right


Thank you in advance! Very appreciated! (I will mark brainliest) :)

Answers

1. 20
2. 35n to the right

The mass of the object experimented in the situation will be equal to 20 kg in each case. Hence, option C is correct.

What is Acceleration?

Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.

It is a vector quantity because it has both magnitude and direction.

The given data as per the question is,

Force, F = 30 N

Acceleration, a = 1.5 m/s²

[tex]Force = mass*acceleration[/tex]

30 N = m × 1.5

m = 30/1.5

m = 20 kg.

Therefore, the mass of the object is 20 kg.

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1.protozoo ore ?
A. multicellular organisms B. one - Celled animals
C. amembers of the group Protocista
D. unicellulor Plants​

Answers

Answer:

c

Explanation:

amembers of the group protocista

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

Answers

We have that for the Question, it can be said that With respect to this axis, the magnitude of the torque due to the weight and ,the thrust is

TW=19740N-mTT=130387.39N-m

From the question we are told

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

a)

Generally the equation for the Torque due to weight  is mathematically given as

[tex]TW=Engine weight*2.50*sin32\\\\TW=14900*2.50*sin32[/tex]

TW=19740N-m

b)

Generally the equation for the Torque due to thrust  is mathematically given as

[tex]TT=Engine thrust*2.50*cos32\\\\TT=61500*2.50*cos32\\\\[/tex]

TT=130387.39N-m

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in order to keep heat in or out, you need a(n)

Answers

Answer:

What is instillation

Explanation:

A 500-kg golf cart is moving on level ground in a circular path of radius 10 m with a speed of 12 m/s. What is the centripetal force acting on the cart?

Answers

Answer:

7200N

Explanation:

Centripetal force is directly proportional to the product of the mass and the square of the velocity and inversely proportional to the radius given.

Starting from rest, a student pulls a (25.0 A) kg box a distance of (4.50 B) m across the floor using a (134 C) N force applied at 35.0 degrees above horizontal. The coefficient of kinetic friction is 0.220 between the floor and the box. Find the work done by the pulling force. Give your answer in joules (J) and with 2 significant figures.

Answers

A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.

Starting from rest, a student pulls a 25.0 kg box a distance of 4.50 m across the floor using a 134 N force applied at 35.0 degrees above horizontal.

We can calculate the work  (W) done by the pulling force using the following expression.

[tex]W = F \times d \times cos\theta = 134 N \times 4.50 m \times cos35.0\° = 4.9 \times 10^{2} J[/tex]

where,

F: puling forced: displacementθ: angle between F and d

The friction between the floor and the box. does not influence the work done by the pulling force.

A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.

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can anyone heelp me pls pls

Answers

Answer:

Explanation:

Answer in the pic.. hope it helps

SEND HELP :<<

A meteor falls from the sky to the Earth. The meteor already had an initial velocity downward when it was spotted. If it hit the Earth at 335 m/s after being seen for 30 seconds, then what was the initial velocity of the meteor?

Answers

Answer:

335 - 30 g

Explanation:

V = Vo + g*T = 335

Vo + 9.8*30 = 335

Vo =

A baseball is hit straight up in the air with an initial velocity of 38 m/s
How long does it stay in the air?
How high does it go?

Answers

The time of motion or time spent in air by the baseball is 7.76 seconds.

The maximum height attained by the baseball is 73.67 m.

The given parameters;

initial velocity of the baseball, u = 38 m/s

The time of motion of the baseball is calculated using the first kinematic equation as follows;

v = u - gt

where;

t is the time to reach maximum heightv is the final velocity of the ball at the maximum height = 0

0 = u -gt

gt = u

[tex]t = \frac{u}{g} \\\\\t = \frac{38}{9.8} \\\\t = 3.88 \ s[/tex]

The time spent in the air = time of entire motion = 2(3.88 s) = 7.76 seconds

The maximum height attained by the ball is calculated using the second kinematic equation as shown below;

[tex]h = ut -\frac{1}{2} gt^2\\\\h = (38\times 3.88)\ - \ (0.5 \times 9.8 \times 3.88^2)\\\\h = 73.67 \ m[/tex]

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The lantern rises up because the __________ of the _________inside the lantern is _________ compared to the air around it

liquid

Gas

Density

fire

less dense

the same density

more dense

paper

Answers

density, fire, less dense

Answer:

gass fire and the same density

Explanation:

part A
Explain how the students can measure the distance the cars travel.

part B
Explain how the students could measure the time it takes the cars to travel the distance you explained in the first part.

Answers

Answer:

Part A: By using the formula, distance = speed x time

Part B: By using the formula, time = distance ( calculated in the first part) ÷ speed

A race car rounding a corner at a constant speed of 200 miles per hour.

Answers

Answer:

Yes since it is changing direction

Explanation:

A race car rounding a corner at a constant speed of 200 miles per hour

describe an experiment to demonstrate surface tension in a liquid​

Answers

Answer:

mę břöőda I dunno this answer

Explanation:

hope you find it

Surface Tension in a Liquid

Materials for Experiment

cereal bowl water ground black pepper liquid soap a toothpick

Procedure for Experiment

Fill a bowl with water Shake the black pepper onto the surface of the water (Notice how it stays afloat on the water? That is the surface tension holding the layer up) Take a toothpick and put the end into soap so that it coats the end Gently touch the surface of the water with the toothpick Did you see how the pepper shoots back in all directions? What must the soap be doing to the surface tension? Soap is something that actually breaks down the cohesive powers of water, making it have less surface tension. If you mix some soap with water and make a water droplet on your counter again, what do you think the shape would look like? Give it a try!

A trouble-making youth is standing on a bridge, and wants to drop a water balloon on an unsuspecting passerby. A man is jogging on a path below the bridge with a constant speed of 4.2 m/s. The bridge is 11.6 m above the ground. If the balloon is to land right at the jogger's feet, at what horizontal distance x from the bridge should he be when the youth drops the balloon?

Answers

Answer:

Explanation:

Time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should be when the youth drops the balloon with velocity 4.2 m/s.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should  be when the youth drops the balloon with velocity 4.2 m/s.

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A string is wrapped around a solid cylinder with mass M and radius R. The free end of the string is held in place, allowing the cylinder to fall. Recall that the moment of inertia of a solid cylinder rotated about its center is given by MR2/2. All answers to this problem should be symbolic, purely in terms of the variables M, R, and g. (a) Find the linear acceleration (in m/s2) of the cylinder and the tension in the string (in Newtons) as the cylinder falls. (b) Now suppose the cylinder is hollow instead of solid. The moment of inertia of a hollow cylinder rotated about its center is given by MR2. What is the acceleration and tension in this case?

Answers

Answer:

I will use (a / R) for alpha the angular acceleration

T R = I a / R     torque equals angular acceleration for cylinder

M g - T = M a    linear acceleration of center of mass

T = M (g - a) = I a / R^2 from first equation

If I = 1/2 M R^2 then M ( g - a) = M a / 2    from above

or g = 3 a / 2  and a = 2 g / 3

Also we have T = M (g - a) = M (g - 2 g / 3) = g / 3

Substitute I = M R^2 for the hollow cylinder

Looks like a = g/2 for hollow cylinder

Ex 1) A Major League baseball pitcher throws a baseball straight up into the air and the ball travels for 4
seconds reaching a height of 52 m before returning to the pitchers hand exactly at the height that he released
it. With what velocity does the baseball strike the pitchers hand on the way back down?

Answers

Answer:

52 / 4 = 13 m/s

Explanation:

An astronaut standing on a platform on a foreign planet drops a hammer. If the hammer falls 9.0 meters vertically in 2.5 seconds, what is the acceleration due to gravity on that planet?

Answers

Answer: 1.646 m/s²

Explanation:

The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,

   d = Vot + 0.5at²

where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,

  6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²

Determining the value of a,

   a = 1.646 m/s²

The box is pushed to the left with 30 N of force, but does not move. What is the Friction Force?​

Answers

However here coefficient of friction is not given so unable to calculate.

You can calculate it by below formula.

The formula given by

[tex]\\ \sf\longmapsto F_f=\mu N[/tex]

Or

[tex]\\ \sf\longmapsto F_f=\mu mg[/tex]

u is coefficient of friction

N is normal reaction.

Here..

box doesn't move means the force if limiting friction is greater than applied force.

If you traveled 50m/s for 60 seconds, how far did you travel? Remember speed=distance/time


Question options:


300 m/s



500 m/s



3,000 m/s



300 km/h

Answers

Answer:

3,000 m

Explanation:

speed = distance/time

distance = speed * time

= 50 * 60

= 3000 m

The seat on a carnival ride is fixed on the end of an 12.60-m-long beam, pivoted at the other end. If the beam sweeps through an angle of 141°, what is the distance through which the rider moves?

Answers

The distance through which the rider at the end of the beam moves is;

L = 15.5 m

We are told that the beam on which the carnival ride is fixed is 12.6m in length.

Since the seat is at the end of the beam with the other end pivoted and the beam sweeps through an angle of 141°, then we can say that the radius of this arc formed by the swing is;

Radius; r = 12.6 m

Also, θ = 141°

The distance through which the driver moves will be the length of the arc formed by the beam at angle of 141°.

Formula for length of arc is given as;

L = 2πr(θ/360)

Plugging in the relevant values gives;

L = 2π × 12.6 × 141/360

L = 15.5 m

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Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?

Answers

Explanation:

s=(v^2-u^2)/2g

=(0-3^2)/2*10

= 0.45m

What happened to an enzyme’s structure as it exceeds the typical human body temperature

Answers

Enzymes. ... This is because heat energy causes more collisions, with more energy, between the enzyme molecules and other molecules. However, if the temperature gets too high, the enzyme is denatured and stops working. A common error in exams is to write that enzymes are killed at high temperatures.

9) A policeman investigating an accident measures the skid marks left by a car. He determines that 9) the distance between the point that the driver slammed on the brakes and the point where the car came to a stop was 28.0 m. From a reference manual he determines that the coefficient of kinetic friction between the tires and the road under the prevailing conditions was 0.300. How fast was the car going wh~er applied the brakes? (This car was not equipped with anti-lock brakes.)

Answers

Answer:

Explanation:

Provided the car did not collide with anything during its slide,

Kinetic energy will convert to work of friction

½mv² = Fd

½mv² = μmgd

       v = √(2μgd)

       v = √(2(0.300)(9.81)(28.0))

       v = 12.8377...

       v = 12.8 m/s

Bob is riding in a roller coaster, and is at the top of a vertical loop (shown below). The radius of the loop is 18 meters. If his apparent weight is just 28% of his actual weight, what is the speed of the roller coaster? Show all your steps.

Answers

At the top, N + mg = ma
0.28mg + mg = ma
0.28g + g = V^2/r
V = ( 1.28 x 9.8 x 18 )^1/2 = 15m/s

A faulty fireworks rocket launches but never discharges. If the rocket launches
with an initial velocity of 33.0 ft/s at an angle of 85.0°, how far away from the
launch site does the rocket land?

Answers

Answer:

a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0∘ above the horizontal. During the flight, the rocket explodes into two pieces of equal mass (see Fig. 8.32). (a) What horizontal distance from the launch point will the center of mass of the two pieces be after both have landed on the ground? (b) If one piece lands a horizontal distance of 26.0 m from the launch point, where does the other piece land?

PLEASE I NEED HELP WITH 6 and 8 !!!! I will love u sm

Answers

Answer:

Explanation:

006

They are acting in opposite directions. Therefore the net force is found by subtraction. The sign is the same as the larger number.

Net Force = 99.6 - 52.8 = 46.8 N acting in the same direction as the 99.6  which is upward.

008

If the two forces act in the same direction, the net force is found by addition.

Net Force = 99.6 + 52.8  = 152.4 N downward.

They’re acting in opposite directions o
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