When a ray of light traveling in air hits a tilted plane parallel slab (of glass, say), it emerges parallel to the original ray but shifted transversely. Carefully draw out the situation and use Snell’s law to derive the amount of the transverse shift, x, as a function of the tilt angle of the slab, θ, its thickness, d, and its index of refraction, n. Find the exact expression with no approximations. We recommend you do this out all in variables because it's a useful formula to have. Also, you will want this for the following questions. However, since the auto-grader has difficulty with these formulas, use n=1.5, d=1.0 cm, and θ = 45° and enter a numerical answer. Give your answer in cm to two significant figures.

Answers

Answer 1

Answer:

  x =  0.4654 cm

Explanation:

In this exercise we use the law of refraction

           n₁ sin θ₁ = n₂ sin θ₂

apply this formula to the first surface, where n₁ is the index of refraction of air (n₁ = 1) and n₂ is the index of refraction of glass (n₂ = n)

            θ₂ = sin⁻¹ (sin θ₁ / n)         (1)

having this angle we use trigonometry to find the value of the point where it comes out when we reach the other side

refracted ray

            tan θ₂ = x₂ / d

            x₂ = d tan θ₂

this value is the distance displaced by the refracted ray

now let's find the distance at which the incident beam should exit

           tan θ₁ = x₁ / d

           x₁ = d tan θ₁

the displacement of the ray is the difference between these two distances, we will call it x

           x = x₁ - x₂

            x = d tan θ₁ - d tan θ₂

           x = d (tan θ₁ - tan θ₂)        (2)

the easiest way to do the calculations is to find tea2 from the binding 1 and then perform the calculation with equation 2

calculate

            θ₂ = sin⁻¹ (sin 45 /1.5)

             θ₂ = 28.13º

             x = 1.0 (tan 45 - tan 28.13)

             x =  0.4654 cm

When A Ray Of Light Traveling In Air Hits A Tilted Plane Parallel Slab (of Glass, Say), It Emerges Parallel

Related Questions

What are three ways synthetic polymers affect the environment?

Answers

Answer:

-Some synthetic polymers use materials from Earth that are nonrenewable.

-They can end up as waste products that sometimes can’t be recycled.

-They sometimes release toxins into the environment.

Explanation:

Synthetic polymers are types of polymers that are man made, that is they are polymers that are made in the labs or industries from chemical substances.

Such polymers include nylon, polyester, and polyethylene among others. These polymers are used to make many clothes and plastics that we use and see around.

Synthetic polymers have a range of disadvantages which includes. being non-biodegradable, these polymers and especially plastics may end up as waste products and pollutes the environment and end up in livers and lakes and this would be toxic for aquatic animals.

An aluminum cup of mass 150 g contains 800 g of water in thermal equilibrium at 80.0°C. The combination of cup and water is cooled uniformly so that the temperature decreases by 1.50°C per minute. At what rate is energy being removed by heat? Express your answer in watts.

Answers

Answer:

Heat Flow Rate : ( About ) 87 W

Explanation:

The heat flowing out of the system each minute, will be represented by the following equation,

Q( cup ) + Q( water ) = m( cup ) [tex]*[/tex] c( al ) [tex]*[/tex] ΔT + m( w ) [tex]*[/tex] c( w ) [tex]*[/tex] ΔT

So as you can see, the mass of the aluminum cup is 150 grams. For convenience, let us convert that into kilograms,

150 grams = .15 kilograms - respectively let us convert the mass of water to kilograms,

800 grams = .8 kilograms

Now remember that the specific heat of aluminum is 900 J / kg [tex]*[/tex] K, and the specific heat of water = 4186 J / kg [tex]*[/tex] K. Therefore let us solve for " the heat flowing out of the system per minute, "

Q( cup ) + Q( water ) = .15 [tex]*[/tex] ( 900 J / kg [tex]*[/tex] K )  [tex]*[/tex] 1.5 + .8 [tex]*[/tex] ( 4186 J / kg [tex]*[/tex] K ) [tex]*[/tex] 1.5,

Q( cup ) + Q( water ) = 5225.7 Joules

And the heat flow rate should be Joules per minute,

5225.7 Joules / 60 seconds = ( About ) 87 W

A student is trying to decide what to wear.His bedroom is at 20.0 °C.His skin temperature is 35.0 °C.The area of his exposed skin is 1.50 m².People all over the world have skin that is dark in the infrared,with emissivity about 0.900.Find the net energy transfer from his body by radiation in 10.0 min.

Answers

Answer:

vgghcgkxcjpfiffj,ncfzfzujfzxxxoifkc xuzrusdoxTXcxgifdhh

What do Equations 1 and 2 predict will happen to the single-slit diffraction pattern (intensity, fringe width, and fringe spacing) as the slit width is increased.

Equation 1:
Sinθ = mλ/ω

Equaiton 2:
I= Io [Sinθ (πωλ/πωλ/Rλ)

Answers

Answer:

the firtz agrees with the expression for the shape of the curve of diracion of a slit

Explanation:

The diffraction phenomenon is described by the expression

              a sin θ = m λ

where a is the width of the slit, t is the angle from the center of the slit, l is the wavelength and m is an integer that corresponds to the maximum diffraction.

the previous equation qualitatively describes the curve of the diffraction phenomenon the equation takes the form

             I = I₀ [(sin ππ a y / R λ) / π a y / Rλ]²

             I = I₀ ’[sin π a y /Rλ]²

             I₀ ’= I₀ / (π a y /Rλ)²

By reviewing the two expressions given

equation 1

 w sin θ = m λ

where w =a  w   is the slit width

we see that the firtz agrees with the expression for the shape of the curve of diracion of a slit

Equation 2

the squares are missing

Which scientist proved experimentally that a shadow of the circular object illuminated 18. with coherent light would have a central bright spot?
A. Young
B. Fresnel
C. Poisson
D. Arago

Answers

Answer:

Your answer is( D) - Arago

Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y2 (measured in coulombs per square meter). Find the total charge on the disk.

Answers

Answer:

the total charge on the disk 256pi Coulombs

Explanation:

Pls see attached file

Two slits are separated by 0.370 mm. A beam of 545-nm light strikes the slits, producing an interference pattern. Determine the number of maxima observed in the angular range−26.0° ≤ θ ≤ 26.0°.

Answers

Answer:

There are 586maxima

Explanation:

Pls see attached file

A narrow beam of light containing red (660 nm) and blue (470 nm) wavelengths travels from air through a 2.60 cm thick flat piece of crown glass and back to air again. The beam strikes the glass at a 28.0° incident angle.
A) At what angles do the two colors emerge?
B) By what distance are the red and blue separated when they emerge?

Answers

Answer:

A: 28°

B. 1x10^-3M

Explanation:

See attached file

A motorcycle travels up one side of a hill over the top and down the other side. The crest of the hill can be considered to be a circular arc with radius of 45.0 m. Determine the maximum speed that the cycle can have while moving over the crest without losing contact with the road.

Answers

Answer:

The maximum speed of the motorcycle should be 21 m/s

Explanation:

Since the hill is considered to be a circular arc, the motorcycle will experience centripetal force that tends to flip it away from the center of the hill.

Since the motorcycle does not lose contact with the ground, it means that the weight of the motorcycle downwards just balances the centripetal force on the motorcycle.

we know that the centripetal force on the motorcycle is equal to

centripetal force = [tex]\frac{mv^{2} }{r}[/tex]

where m is the mass of the motorcycle,

v is the velocity of the motorcycle,

and r is the radius of the hill = 45.0 m

Also we now that the weight of the motorcycle is equal to

weight = mg

where m is still the mass of the motorcycle,

and g is the acceleration due to gravity = 9.81 m/s

Equating the both forces since they are equal, we'll have

[tex]\frac{mv^{2} }{r}[/tex] = mg

the mass of the motorcycle will cancel out, and we'll be left with

[tex]v^{2} = gr[/tex]

[tex]v = \sqrt{gr}[/tex]

[tex]v = \sqrt{9.81*45}[/tex]

[tex]v = \sqrt{441.45}[/tex]

[tex]v[/tex] = 21 m/s

A merry-go-round is a common piece of playground equipment. A 3.0-m-diameter merry-go-round, which can be modeled as a disk with a mass of 300 kg , is spinning at 23 rpm. John runs tangent to the merry-go-round at 4.4 m/s, in the same direction that it is turning, and jumps onto the outer edge. John's mass is 30 kg.

Required:
What is the merry-go-round's angular velocity, in rpm, after John jumps on?

Answers

Answer:

The merry-go-round's angular velocity 23.84 RPM

Explanation:

Given;

diameter of merry go round, d = 3 m

radius of the merry go round, R = 1.5 m

mass of the merry go round, m = 300 kg

angular velocity = 23 rpm

velocity of John, v = 4.4 m/s

mass of John, m = 30 kg

Apply conservation of angular momentum;

[tex]L_i = L_f[/tex]

[tex]I \omega_i + mvR = (I + mR^2)\omega _f[/tex]

where;

I is moment of inertia of disk

[tex]I = \frac{1}{2} mR^2\\\\I = \frac{1}{2} *300*1.5^2\\\\I = 337.5 \ kg.m^2[/tex]

Substitute in this value in the above equation;

[tex]337.5(2\pi \frac{23}{60} ) + (30*4.4*1.5) = (337.5 + 30*1.5^2) \omega_f\\\\812.9925 \ + \ 198 = 405 \omega _f\\\\1010.9925 = 405 \omega _f\\\\\omega _f = \frac{1010.9925}{405} \\\\\omega _f = 2.496 \ rad/s[/tex]

1 rad/s = 9.5493 rpm

2.496 rad/s = 23.84 RPM

Therefore, the merry-go-round's angular velocity 23.84 RPM

Two long parallel wires separated by 4.0 mm each carry a current of 24 A. These two currents are in the same direction. What is the magnitude of the magnetic field at a point that is between the two wires and 1.0 mm from one of the two wires

Answers

Answer:

Explanation:

Magnetic field at a a point R distance away

B = μ₀ / 4π X 2I / R where I is current

Magnetic field due to one current

=  10⁻⁷ x 2 x 24 / 1 x 10⁻³

48 x 10⁻⁴ T

Magnetic field due to other current

=  10⁻⁷ x 2 x 24 / 3x 10⁻³

16 x 10⁻⁴ T

Total magnetic field , as they act in opposite direction, is

= (48 - 16 ) x 10⁻⁴

32 x 10⁻⁴ T .

A parallel–plate capacitor is initially charged by connecting it to a battery. The battery is then disconnected. If the distance between the plates is increased, what happens to the charge on the capacitor and the voltage across it?

a. The charge remains fixed and the voltage decreases.
b. The charge decreases and the voltage remains fixed.
c. The charge remains fixed and the voltage increases.
d. The charge decreases and the voltage increases.

Answers

Answer:

t the battery of potential difference  V be used to charge the capacitor of capacitance  C.

∴ the charge stored in the capacitor      q=CV

Now the battery is disconnected, so the the charge  of the capacitor becomes constant

i.e    q=constant     OR     CV=constant                .............(1)

Capacitance of parallel plate capacitor        C=  

d

Aϵ  

o

​  

 

​  

 

So if the distance between the plates is increased, then the capacitance will decrease which is compensated by the increase  in voltage across the capacitor according to equation (1).

Also the energy stored in the capacitor          E=  

2C

q  

2

 

​  

 

⟹E∝  

C

1

​  

                (∵q=constant)

Thus energy will increase due to the decrease in capacitance.

Explanation:

A negatively charged object is located in a region of space where the electric field is uniform and points due north. The object may move a set distance d to the north, east, or south. Write the three possible movements by the change in electric potential energy (Ue) of the object.

Answers

Answer:

the three possible movements by the change in electric potential energy (Ue) of the object are NORTH EAST SOUTH

Explanation:

This is because When the object moves south, the force is in the direction of the displacement, and positive work is done with decreasing electric potential energy.

The opposite is true if the particle moves north—that is, negative work is done with increasing electric potential energy.

No work is done and the electric potential energy is constant if the motion is perpendicular to the electric field.

A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? All potentials are measured relative to infinity. (There may be more than one correct choice.)

Answers

Hello. This question is incomplete. The full question is:

A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? All potentials are measured relative to infinity. (There may be more than one correct choice.)

A) The potential is lowest, but not zero, at the center of the sphere.  B) The potential at the center of the sphere is zero.  C) The potential at the center of the sphere is the same as the potential at the surface.  D) The potential at the surface is higher than the potential at the center.  E) The potential at the center is the same as the potential at infinity

Answer:

C) The potential at the center of the sphere is the same as the potential at the surface.

Explanation:

When a conductive sphere has charges that distribute evenly on its surface, it means that its interior has a zero charge cap. As a result, the outside of this sphere has a charge distribution that will be the same if the center of the sphere were charged. In this way, the center and the surface of the sphere become identical in relation to the point charge potential. In other words, this means that the null interior of the sphere has a constant potential that makes the distribution of charges within the sphere exactly equal to the distribution of charges outside the sphere.

The statement that should be true regarding the sphere is The potential at the center of the sphere.

Potential at the sphere center:

Here the normal formula should be used i.e.  kq/R that should be determined by considering the potential at infinity also it does not contain any intervening dielectric like zero.

Also,

kq/R+c,

Here c is constant is necessary to fit with respect to the zero potential.

Hence, The statement that should be true regarding the sphere is The potential at the center of the sphere.

Learn more about sphere here: https://brainly.com/question/16684376

A small solid conductor with radius a is supported by insulating, nonmagnetic disks on the axis of a thin-walled tube with inner radius b. The inner andouter conductors carry equal currents i in oppositedirections.

Required:
a. Use Ampere's Law to find the magnetic field at any pointin the volume between the conductors.
b. Write the expression for the flux dΦB through anarrow strip of length l parallel to the axis , of width dr, at a distancer from the axis of the cableand lying in a plane containing the axis.
c. Integrate your expression from part B over the volumebetween the two conductors to find the total flux produced by acurrent i in the central conductor.
d. Use equation U=(1/2)LI2 to calculate the energy stored in the magnetic field for alength l of the cable.

Answers

Answer:

Pls see attached file

Explanation:

Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and the axis of the second is rotated θ = 65° from the vertical.

Required:
a. What is the intensity of the light after it passes through the first polarizer in W/m2?
b. What is the intensity of the light after it passes through the second polarizer in W/m2?

Answers

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

Find:

a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Isaac drop ball from height og 2.0 m, and it bounces to a height of 1.5 m what is the speed before and after the ball bounce?

Answers

Explanation:

It is given that, Isaac drop ball from height of 2.0 m, and it bounces to a height of 1.5 m.

We need to find the speed before and after the ball bounce.

Let u is the initial speed of the ball when he dropped from height of 2 m. The conservation of energy holds here. So,

[tex]\dfrac{1}{2}mu^2=mgh\\\\u=\sqrt{2gh} \\\\u=\sqrt{2\times 9.8\times 2} \\\\u=6.26\ m/s[/tex]

Let v is the final speed when it bounces to a height of 1.5 m. So,

[tex]\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 1.5} \\\\v=5.42\ m/s[/tex]

So, the speed before and after the ball bounce is 6.26 m/s and 5.42 m/s respectively.

A telewision weighs 8.50 pounds. How many grams is this? (Hint: You need to
use two unit conversion fractions. 1 pound equals about 0.454 kg.)​

Answers

Answer:

3859 g

Explanation:

1 pound = 0.454 kg

therefore, 8.50 ponds = 0.454*8.50 = 3.859

to covert kilograms into grams you need to multiply it by 1000

=3.859*1000

= 3859 grams

Astronomers have recently observed stars orbiting at very high speeds around an unknown object near the center of our galaxy. For stars orbiting at distances of about 1014 m from the object, the orbital velocities are about 106 m/s. Assume the orbits are circular, and estimate the mass of the object, in units of the mass of the sun (MSun = 2x1030 kg). If the object was a tightly packed cluster of normal stars, it should be a very bright source of light. Since no visible light is detected coming from it, it is instead believed to be a supermassive black hole.

Answers

Answer:

The mass of the object is 745000 units of the sun

Explanation:

We know that the centripetal force with which the stars orbit the object is represented as

[tex]F_{c}[/tex] = [tex]\frac{mv^{2} }{r}[/tex]

and this centripetal force is also proportional to

[tex]F_{c}[/tex] = [tex]\frac{kMm}{r^{2} }[/tex]

where

m is the mass of the stars

M is the mass of the object

v is the velocity of the stars = 10^6 m/s

r is the distance between the stars and the object = 10^14 m

k is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2

We can equate the two centripetal force equations to give

[tex]\frac{mv^{2} }{r}[/tex] = [tex]\frac{kMm}{r^{2} }[/tex]

which reduces to

[tex]v^{2}[/tex] = [tex]\frac{kM}{r}[/tex]

and then finally

M = [tex]\frac{rv^{2} }{k}[/tex]

substituting values, we have

M = [tex]\frac{10^{14}*(10^{6})^{2} }{6.67*10^{-11} }[/tex] = 1.49 x 10^36 kg

If the mass of the sun is 2 x 10^30 kg

then, the mass of the the object in units of the mass of the sun is

==> (1.49 x 10^36)/(2 x 10^30) = 745000 units of sun

Electromagnetic waves are traveling in the vacuum of space. Calculate the wavelengths of these electromagnetic waves with the following frequencies. (Enter the first wavelength in pm and the second wavelength in cm.)
(a) 2.00 x 1019 Hz
(b) 4.50 x109 Hz

Answers

Answer:

(a) 1.5×10⁻¹¹ m.

(b) 6.7×10⁻² m

Explanation:

Note: All Electromagnetic wave travels in with the same speed, which 3×10⁸ m/s

(a) Give a frequency of 2.00×10¹⁹ Hz.

Using the equation of a wave,

V = λf................ Equation 1

Where V = Speed of electromagnetic wave, λ = wavelength, f = frequency.

make λ the subject of the equation

λ = V/f................. Equation 2

Given: f = 2.00×10¹⁹ Hz.

Constant: v = 3×10⁸ m/s.

Substitute into equation 2

λ = 3×10⁸/2.00×10¹⁹

λ = 1.5×10⁻¹¹ m.

(b) Similarly using

λ = v/f

Given: f = 4.5×10⁹ Hz, and v = 3×10⁸ m/s.

Substitute these values into equation 2 above.

λ = 3×10⁸/4.5×10⁹

λ = 6.7×10⁻² m

15pts! brainliest to who answers!If Kyla picks up a grocery bag, using 10 N of force to lift it 1.5 m off the floor, how much work did Kyla do on the bag?

Answers

Explanation:

work = force x distance

w = 10 x 1.5 = 15Nm

The work done on the bag is the product of the force applied on it and the displacement of the bag. The work done to lift the bag up to 1.5 m by applying a force of 10 N is 15 J.

What is work done ?

When a force applied to an object make a displacement of  the body or stopes its motion, the force is said to be work done on the object. Thus, work done can be taken as the product of force and displacement.

Work done like force is a vector quantity thus characterized with magnitude and direction.  Work done is equivalent to the energy required to make the object displaced.

Given the force = 10 N

displacement = 1.5 m

work done  = force × displacement

w = 10 N × 1.5 m = 15 J.

Therefore, the work done on the car is 15 J.

Find more on work done:

brainly.com/question/30073908

#SPJ6

Three point charges (some positive and some negative) are fixed to the corners of the same square in various ways, as the drawings show. Each charge, no matter what its algebraic sign, has the same magnitude. In which arrangement (if any) does the net electric field at the center of the square have the greatest magnitude?

Answers

Answer:

The magnitude of the net field located at the center of the square is the same in every of arrangement of the charges.

You want the output current from the secondary coil of a transformer to be 10 times the input current to the primary coil. The ratio of the number of turns N2/N1 must be:_____________.
A. 100
B. 10
C. 1
D. 0.1

Answers

Answer:

D. 0.1

Explanation:

Using transformer equation,

N2/N1 = I1/I2................... Equation 1

Where N2 = secondary coil, N1 = primary coil, I1 = input current, I2 = output current.

make I2  the subject of the equation

I2 = I1/(N2/N1)............ Equation 2

From equation 2 above, For the output current of the secondary coil to be 10 times the input current, N2/N1 = 0.1

Hence the right option is D. 0.1

An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the new acceleration would be _____ m/s/s.

Answers

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

The electron beam inside a television picture tube is 0.40 {\rm mm} in diameter and carries a current of 50 {\rm \mu A}. This electron beam impinges on the inside of the picture tube screen.
How many electrons strike the screen each second?
The electrons move with a velocity of 4.0\times10^7\;{\rm m/s}. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 {\rm mm}?
Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the power delivered to the screen by the electron beam? (Hint: What potential difference produced the field that accelerated electrons? This is an emf.)

Answers

Answer:

A.3.13x10^14 electrons

B.330A/m²

C.9.11x10^5N/C

D. 0.23W

.pls see attached file for explanations

The fractional change of reacting mass to energy in a fission reactor is about 0.1%, or 1 part in a thousand. For each kilogram of uranium that is totally fissioned, how much energy is released

Answers

Answer:

9*10^13 J

Explanation:

Given that

mass of the material, m = 0.001 kg

speed of light, c = 3*10^8 m/s

To solve this, we would be adopting Einstein's mass - energy relation...

E = mc²

Where

E = Energy, in joules

m = mass, in kg

c = speed of light, in m/s

E = 0.001 * (3*10^8)²

E = 0.001 * 9*10^16

E = 9*10^13 J

Thus, the total energy released would be 9*10^13 J

A solenoid of 200 turns carrying a current of 2 A has a length of 25 cm. What is the magnitude of the magnetic field at the center of the solenoid?

Answers

Answer:

Explanation:

For magnetic field in a solenoid , the formula is

B = μ₀ n I

Where n is number of turns per unit length and i is current

Putting the values

B = 4π x 10⁻⁷ x (200 / .25) x 2

= 2.00 x 10⁻³ T  

The temperature gradient between the core of Mars and its surface is approximately 0.0003 K/m. Compare this temperature gradient to that of Earth. What can you determine about the rate at which heat moves out of Mars’s core compared to Earth?

Answers

Answer:

The temperature gradient between the core of Mars and its surface is lower than that on Earth. So, heat moves outward more slowly on Mars than on Earth.

Explanation:

Answer:

The temperature gradient between the core of Mars and its surface is lower than that on Earth. So, heat moves outward more slowly on Mars than on Earth.

Explanation:

Edmentum sample answer

wrench is to Hammer as ​

Answers

Answer:

Pencil is to pen

Step by step explanation:

They are similar items, as they are both tools, but are different as to how they function.

An apple falls from a tree and hits your head with a force of 9J. The apple weighs 0.22kg. How far did the apple fall?

Answers

Answer:

The apple fell at a distance of 4.17 m.

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work.

In the International System of Units, work is measured in Joule. Joule is equivalent to Newton per meter.  

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves.  

Work=Force*distance* cosine(angle)

On the other hand, Newton's second law says that the acceleration of a body is proportional to the resultant of forces on it acting and inversely proportional to its mass. This is represented by:

F=m*a

where F is Force [N], m is Mass [kg] and a Acceleration [m / s²]

In this case, the acceleration corresponds to the acceleration of gravity, whose value is 9.81 m / s². So you have:

Work= 9 JF=m*a=0.22 kg*9.81 m/s²= 2.1582 Ndistance= ?angle=0 → cosine(angle)= 1

Replacing:

9 J= 2.1582 N* distante* 1

Solving:

[tex]distance=\frac{9J}{2.1582 N*1}[/tex]

distance= 4.17 m

The apple fell at a distance of 4.17 m.

Other Questions
For what values of a the following expressions are true: |a|=a In the aftermath of 'The Great Recession', how would you describe the economic growth scenario for the U.S. economy? Explain your answer. Describe the steps involved in treating a drug or substance addiction One number is 6 more than another. Their product is -9. Need help fast use the cross product property to solve the proportion5/r = 9/10 II NEED HELP!!!!!!!! Are the graphs of the lines in the pair parallel? Explain. y = 2/3x 17 4x 6y = 6 4x-6y=-6 Yes, since the slopes are the same and the y-intercepts are the same. A )No, since the y-intercepts are different. B)No, since the slopes are different. C)Yes, since the slopes are the same and the y-intercepts are different. Which sentence from the passage includes a coordinating conjunction? a. This format has infinite variations, but imagine one that goes like this: A man is driving in his old car and pulls up next to a new, shiny car at a stop light. (paragraph 7) b. One common, and very persuasive, type of advertisement is known as the association ad. (paragraph 2) c. As it turns out, just a few formats characterize the majority of ads. (paragraph 1) d. These types of advertisements may also present an entire socioeconomic or cultural group that it intends the viewer to associate with the product. (paragraph 5) Which of the following theorems verifies that DEF= XYZ? Write them in a standard form. -6+4q+(-6q)6+4q+(6q)minus, 6, plus, 4, q, plus, left parenthesis, minus, 6, q, right parenthesis ? The company has a bank loan and has incurred (but not recorded) interest expense of $3,500 for the year ended December 31, 2018. The company must pay the interest on January 2, 2019. Match each excerpt from song of myself by Walt Whitman to the poetic devices used One instrument playing is normally indicated by the word - Sola - tutti - solo - soli The volume of a right circular cylinder can be approximated as follows:Volume = r2h;where r is the radius of the cylinder and h is the height of the cylinder; is a constant that is roughly equal to 3.Using the simple approximation above, calculate the volume of a right circular cylinder with a radius of 2 meters and a height of 9 meters.A.2,916 m3B.14 m3C.108 m3D.324 m3 A man bought certain number of litchesat 20 per Rs 100 and an equal no. of 30 perRs 100. He mixed them and sold them at25per Rs 100. Find hisgain or losspercent? What were apartheid laws?A. They were laws that helped South Africa establish a newconstitution.B. They were laws that forced European powers to grantindependence to their colonies.C. They were laws that established trade agreements across Africa.D. They were laws that limited the rights of black South Africans. WILL MARK BRAINLIEST PLEASE HELP x What is the length of in the right triangle below? A.150B.25C.D.625 Consider a country that is operating under a system of flexible exchange rates. If the central bank in this country imposes an expansionary monetary policy, it would be likely to experience:_________ I. a depreciation of its currency; II. short-term capital outflows; III. an appreciation of its currency. WILL GIVE BRAINLIEST Find the value of x, rounded to the nearest degree. 26 25 28 62