When a lead rider's left arm is bent at the elbow with their index finger pointing straight up, it means double file formation.
When riding in groups, hand signals are a crucial aspect of communication. The group should create a double-file formation when the lead rider's left arm is bent at the elbow and their index and middle fingers are pointed straight up. Wider hallways are best suited for heavy-headed formations (T-formation with a couple of individuals in front) or double-file formations because soldiers can spread out and walk shoulder to shoulder at the front of the file. When opposing doors are visible, the single file configuration is constricting and slowly moving.
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What are the 5 types of electrical incidents?
Electrical burns can occur in a variety of ways, including arc burns, low voltage burns, high voltage burns, mouth burns, flash burns, and flame burns.
What are electrical incidents?Electric shock, a serious electrical mishap, or a fatal electrical event are all considered electrical incidents.
For the purposes of reporting and analysis, incident definition types let you attribute the appropriate type to safety events. Having only the two types of incidents—Accident and Near Miss—is one strategy.
An occurrence or scenario that has a number of serious repercussions and necessitates the implementation of special measures by one or more emergency responder agencies is referred to as a big incident.
Any electrical incident that results in or has the potential to result in: death or serious bodily harm to a person; significant property damage; or a serious risk to the public safety must be reported, according to the Electrical Safety (General) Regulations of 2019.
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2. A 1.0 kg roller coaster is at the top of a 25m hill, and has a velocity of 8 m/s.
a. Determine the velocity of the roller coaster when it is halfway down the hill, at height of 12.5 m. (Ignore Friction)
b. What is the velocity of the roller coaster at the bottom of the hill assuming a force due to friction of 3.0 N, and the length of the hill is 45.0 m.
SHOW ALL WORK!
The car's acceleration can be calculated as: a = v2/R = (18.0 m/s) 2/(12.0 m) = 27.0 m/s2. The conventional method can be used to determine net force: 13500 N is equal to Fnet = m•a = (500 kg)•(27.0 m/s2).
What happens to a roller coaster's speed as it climbs a hill?It may slow down or decelerate when traveling uphill or straight ahead. Roller coasters accelerate as they travel down hills due to the force of gravity dragging them downward.
How do roller coasters use math?Calculus and other fundamental mathematical concepts are used to calculate the maximum speed, the angles of ascent and descent, and the height necessary for the automobile to climb the next hill. The roller coaster's safety is further ensured by these calculations.
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Marissa’s car accelerates at an average rate of 3. 6 m/s2. Calculate how long it takes her car to accelerate from 26. 4 m/s to 28. 6 m/s
It will take 1.5 seconds for Marissa's car to accelerate from 26. 4 m/s to 28. 6 m/s.
Acceleration can be calculated by looking at the change in velocity over a specific period of time. It is an important concept in physics as it is used to explain the motion of objects in the real world.
Acceleration is a measure of how quickly an object is changing its velocity on average, and it is usually expressed in meters per second squared (m/s2).
This simple calculation of Marissa's car acceleration can be determined by using the formula: Delta speed / Acceleration rate = Time taken.
In this case, that would be 2.2 m/s (28.6-26.4) / 3.6 m/s2
= 0.6 s or 1.5 sec (rounded up).
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How much current flows through the bottom wire in the figure(Figure 1) ?
Express your answer to two significant figures and include the appropriate units.
The current through the bottom of the wire is 0.415 A and the negative sign of the current indicates that current flows from left to right from the bottom wire.
The current through various parts of the circuit is as shown in figure.
Here we have to calculate the current I_5.
Applying Kirchoff's loop rule on each of the loops in the circuit, Consider the left triangle, for it, we have
[tex]$$\begin{aligned}& \left(I_1\right) 6 \Omega+\left(I_3\right) 12 \Omega-9 \mathrm{~V}=0 \\& \Rightarrow 6 I_1+12 I_3=9 \\& \Rightarrow I_1=\frac{9}{6}-\frac{12}{6} I_3 \\& \Rightarrow I_1=1.5-2 I_3-----(1)\end{aligned}$$[/tex]
For the centre of the triangle, we have
[tex]$$\begin{aligned}& \left(I_4\right) 24 \Omega-\left(I_3\right) 12 \Omega=0 \\& \Rightarrow I_4=\frac{12}{24} I_3 \\& \Rightarrow I_4=\frac{I_3}{2}-----(2)\end{aligned}$$[/tex]
And for the right triangle, we have
[tex]$$\begin{aligned}& \left(I_2\right) 10 \Omega+\left(I_4\right) 24 \Omega-15 \mathrm{~V}=0 \\& \Rightarrow I_2=\frac{15}{10}-\frac{24}{10} I_4 \\& \Rightarrow I_2=1.5-2.4 I_4------(3)\end{aligned}$$[/tex]
The junction rule applied at the left corner gives
I_1 =I_3+I_5
=I_5 =I_1-I_3
=1.5-2 I_3-(I_3)=1.5-3 I_3--------(4)
And applying the junction rule at the right corner,
I_4 =I_2+I_5
I_5 =I_4-I_2
=I_4-(1.5-2.4 I_4)=3.4 I_4-1.5-------(5)
Using equation (2) [tex]$I_4=\frac{I_3}{2}$[/tex], equation (5) can be written as
[tex]$$\begin{aligned}I_5 & =3.4\left(\frac{I_3}{2}\right)-1.5 \\\end{aligned}$$[/tex]==1.7 I_3-1.5
Solving equations (4) and (6), we have
1.5-3 I_3=1.7 I_3-1.5
(1.5+1.5)=(1.7+3.0) I_3
3.0=4.7 I_3
[tex]\Rightarrow I_3=\frac{3.0}{4.7} \mathrm{~A}[/tex]
Hence the current in the bottom wire is given by
[tex]I_5 & =1.7\left(\frac{3.0}{4.7}\right)-1.5 \\[/tex] =1.085-1.5 =-0.415 A
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Assume that you have a mass of 50.0 kg. Earth has a
mass of 5.97 X1024 kg and a radius of 6.38X 10 m.
What is the force of gravitational attraction
between you and Earth?
The force of gravitational attraction is 489.18N
Gravitation is a study of how two masses interact, one of which is heavier and the other lighter, and force is the force that attracts all bodies towards itself in this universe. Gravitational force is a central force that is exerted along the line joining the q of two masses, and the direction of that force depends only on their position with respect to the source mass.Gravitational force: The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
Where,
F is the gravitational force between two bodies
m1 is the mass of the first body = 50 Kg
m2 is the mass of the second body = [tex]5.97 * 10^{24} Kg[/tex]
r is the distance between the centres of two bodies = [tex]6.38 * 10^{6} m[/tex]
G = gravitational constant = [tex]6.67 * 10^{-11}[/tex]
Putting these values in above equation we get: F = 489.18N
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Elliot is going to start strength training at home. He does not have any weights and is
brand new to strength training but is young and healthy. What would be a good
household object to use to for strength training? (1 point)
O a can of soup
O a box of tissues
O a gallon of water
O a paperback book
Answer:
A gallon of water would be a good household object to use for strength training.
Explanation:
Gallon jugs of water typically weigh around 8.3 lbs, which can provide a good amount of resistance for strength training exercises such as bicep curls, shoulder presses, and tricep dips. Additionally, the handle on the jug of water makes it easy to grip and use for various exercises. Cans of soup and boxes of tissues are generally too light to provide enough resistance for strength training, and a paperback book may not be sturdy enough to use for certain exercises.
A sealed cylinder of length l and cross sectional area A contains n molecules of an gas at kelvin temperature T. What is the force acting on the cylinder marked A due to the gas?
A. NRT/l
B. NRT/lA
C. NkBT/lA
D. NkBT/l
I know it has to be option D but I have no idea how to get to that answer.
At kelvin temperature T, cylinder A includes n molecule of a gas, and the force exerted by the gas on the cylinder is NkBT/l.
Force is what?When two bodies interact, it refers to any form of pushing or pulling that one body exerts on the other. A vector quantity, that is. For instance, a person pushes or pulls on something to provide force, such as opening a door.
What variety of forces exist?Contact forces that act at a remove forces are the two different types of forces. Your daily use of force is evident. Basically, pressure and pull are forces.
Briefing:Formulas,
-P = F/A
-n = n/Na
-PV = nRT
= NKT (R = KNa)
- Volume of cylinder: A* l
F=PA
P = NKbT / V
P = NKbT / A* l
F = NkBT / A * l (A)
Cross out A,
Final, F = NkBT/l.
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how many electrons are on the move in a circuit where a current of 2.0 A flows for 2.0 minutes?
The number of electrons that move in a circuit where a current of 2.0 A flows for 2.0 minutes will be [tex]1.5X10^2^2[/tex]. The correct option is C.
What is current?Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current.
A current of 2A passes through a wire for 20 minutes. The number of electrons that crossed the cross-section in this period is
Given that,
Current =2A
Time t= 20min = 20×60s
Let,
n and e be the number and charge of electrons in time t.
So,
The total charge, q(say) in the wire is
q = ne
Hence, the current flowing in time t is
I = q/t
I = ne/t
n = It/e
[tex]n=\frac{2(20X60)}{1.6X10^{-19}} \\\\n=\frac{2400}{1.6X10^{-19}}\\\\n=1.5X10^{22}[/tex]
Thus, the answer is [tex]1.5X10^2^2[/tex], means the correct option is C.
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Your question seems incomplete, the missing options are:
[tex]1.5X10^{21}\\\\1.5X10^{20}\\\\1.5X10^{22}\\\\1.5X10^{21}\\\\1.5X10^{23}[/tex]
If you pound a feather with a hammer, which one feels a greater force? a. always the hammer both feather moves, then it felt the greater force. b. therwise the force the same on both. c. always the feather d. The size of the force is always exactly the same on both of them.
If you pound a feather with a hammer, which one feels a greater force always the hammer both feather moves, then it felt the greater force.
What is the force?
Force is an influence that produces a change in the motion of an object. It is measured in units of mass times acceleration, or newtons (N). Force is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to accelerate, decelerate, remain in motion, change direction, or alter shape. Examples of forces include gravity, friction, tension, and magnetism. Forces can also be generated by electrical, thermal, and nuclear energy. All forces are generated by the interaction of two objects and can be balanced or unbalanced. Unbalanced forces will cause an object to move or accelerate and balanced forces will cause an object to remain stationary or in motion at a constant speed.
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The image below shows the combined wave for Sound A + B, where Sound A has a higher frequency than Sound B. What is the frequency of Sound A?
The frequency of Sound A is 440.3 Hz.
What is the resultant frequency of the two sound waves?The resultant frequency of the sound A and sound B is calculated as follows;
Mathematically, the relationship between period and frequency of a wave is given as;
F = 1 / T
where;
T is the period of the waveThe resultant frequency from the given graph is calculated as;
The period of the sound in the image = 0.3 s
F = 1 / T
F = 1 / 0.3 s
F = 3.3 Hz
If sound B = 437 Hz, the frequency of sound A which is greater is calculated as;
F ( A ) = 437 Hz + 3.3 Hz
F ( A ) = 440.3 Hz
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If a ball is rolling with 5 pounds of force, how much force will be needed to stop the ball from rolling and why?
A
It would take 25 pounds of force to stop the ball from rolling because it takes five times as much force to stop as object.
B
It would take 2. 5 pounds of force to stop the ball from rolling because it takes half of the amount of force to stop an object.
C
It would take 10 pounds of force to stop the ball from rolling because it takes double the amount of force to stop an object.
D
It would take 5 pounds of force to stop the ball from rolling because the same amount of force must be used to stop the object
It would take 5 pounds of force, that is equal force, to stop the ball from rolling because the same amount of force must be used to stop the object.
According to Newton's third law of motion, every action which is occurring in nature has an equal as well as an opposite reaction. For instance, if a particular object A happens to exert a force on another object B, then object B will also be exerting an equal as well as an opposite force on object A.
If a particular ball is rolling with 5 pounds of force then the same amount of reaction will be required to bring it to rest. That is, equal force of 5 pounds will be required to stop the ball.
Hence, option D is the correct option.
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A 3.09 x 10-4 T magnetic field points directly east. A loop of area 0.0471 m2 faces directly northeast. What is the magnetic flux through the loop?
Answer:
1.03 * 10^-5
Explanation:
The magnetic flux through the loop is approximately 1.317 × [tex]10^{(-5)[/tex]T·m².
To calculate the magnetic flux through a loop, we use the formula:
Φ = B × A × cos(θ)
Where:
Φ is the magnetic flux
B is the magnetic field strength
A is the area of the loop
θ is the angle between the magnetic field and the normal to the loop
Given:
Magnetic field strength (B) = 3.09 × [tex]10^{(-4)[/tex] T (east direction)
Area of the loop (A) = 0.0471 m²
The loop faces directly northeast
To find the angle θ, determine the angle between the magnetic field direction (east) and the normal to the loop (northeast).
Since the loop faces northeast, the angle between the normal to the loop and the east direction is 45 degrees (90 degrees divided by 2).
Now calculate the magnetic flux:
Φ = B × A × cos(θ)
Φ = (3.09 × [tex]10^{(-4)[/tex] T) × (0.0471 m²) × cos(45°)
Using the value of cos(45°) as 0.7071:
Φ = (3.09 × [tex]10^{(-4)[/tex] T) × (0.0471 m²) ×0.7071
Φ = 1.317 × [tex]10^{(-5)[/tex] T·m²
Therefore, the magnetic flux through the loop is approximately 1.317 × [tex]10^{(-5)[/tex] T·m².
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When you step on the break, the car engine rotation rate decreases from 10 rad/s to 6.3 rad/s in 5.0 s. What is the magnitude of the average angular acceleration
The average angular acceleration has a value of 0.74 rad/s2.
What leads to a reduction in angular speed?Applying a force tangential to the rim and in the direction of the instantaneous velocity of the piece of the rim you are applying the force to will most likely increase the angular speed. Reversing the direction of the force will slow down the angular speed.
What are the positions of and when rotation is accelerating?(rad/s)/s or rad/s2 are the units of angular acceleration. If rises, is a positive number. is negative if it decreases. Remember that the positive direction is counterclockwise and the negative direction is clockwise.
F = m r α . τ=mr2α. τ = m r 2 α
initial rotaton speed=10rad/s
final speed=6.3rad/s
time=5sec.
α=(10-6.3)/5 =.74rad/s
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A full stop means that there is a complete cessation of the forward movement of the vehicle, or _________ with no forward motion.
A full stop means that there is a complete cessation of the forward movement of the vehicle, or stop with no forward motion.
If two or more automobiles arrive at a four-way stop at the same time, the car to the right shall proceed first. "If two or more automobiles arrive at a four-way stop at the same moment, the car on the right shall proceed first."
Your headlights will allow you to see roughly 400 feet ahead of you. You should travel at a speed that permits you to stop within this distance, which is around 50 miles per hour.
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Write a complete scientific explanation to account for why the heavier ball caused more flour to spread out
When a ball moves with faster velocity, then a greater impulse force is Imparted that causes more flour to spread out.
The momentum of a system remains constant unless the system is acted on by an external force in which case the acceleration of center of mass satisfies. The force on a system of particles is the external force because the internal force is zero.
The external force is equal to the change in momentum of the system and is proportional to the acceleration of the center of mass. For a fixed choice of system, if there are no external forces acting on the system then the momentum of the system is constant is constant.
The external force may be zero in one direction but not others. The component of the system momentum is constant in the direction that the external force is zero. The component of system momentum is not constant in a direction in which external force is not zero.
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A worker is testing a multiple pulley system to estimate the heaviest object that he could lift. The largest downward force he can exert is equal to his weight, 875 N. When the worker moves the rope 1. 5 m, the object moves 0. 25 m. What is the heaviest object that he could lift?
Force is positive if the mass accelerates downward. Use the formula T = M x A to determine the tension in the rope.
How is the force in a pulley system calculated?That direction is the pull that is referred to as tension. As a result, the tension will point toward the string or rope and away from the mass.
A mass suspended by a string is pulled upward by the string, exerting an upper force that shifts the tension to the upper side.
For instance, you should know that T = 9g x 2m/s2 = 18gm/s2 or 18N when trying to calculate T in a straightforward pulley system with a linked mass of 9g and an upward acceleration of 2m/s2 (newtons). The direction in which a string expands changes when it passes over an ideal massless pulley, but the string's tension is unaffected.
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calculate the current,if charges is 100c pass through
Answer:
An amp is one C per second. Two minutes is 120 seconds. So current is 10 C/120 sec which is 1/12 th of an Amp.
Coolant is forced through the engine and other system parts by the _____. [ Choose ] The _____ transfers engine coolant heat to the outside air. [ Choose ] Coolant flow and engine operating temperature are controlled by the _____. [ Choose ] _____ is mixed with water to produce the engine coolant. [ Choose ] A(n) _____ permits coolant circulation through the engine when the thermostat is closed. [ Choose ] The fan switch, or _____, is a temperature-sensitive switch that controls fan motor operation. [ Choose ] The engine is connected to the radiator by the _____. [ Choose ] The _____ draws air through the radiator. [ Choose ] A disc with fan-like blades that spins and produces pressure and flow is known as a(n) _____. [ Choose ] The center section of the radiator made up of tubes and cooling fins is called the _____.
Answer:
1. Water pump
2. Radiator
3. Thermostat
4. AntiFreeze
5. Bypass Valve
6. Thermo switch
7. Radiator hoses
8. Fan
9. Water Pump Impeller
10. Core
Explanation:
Based on Cooling System Fundamentals, we have the following;
1. Coolant is forced through the engine and other system parts by the WATER PUMP.
2. The RADIATOR transfers engine coolant heat to the outside air.
3. Coolant flow and engine operating temperature are controlled by the THERMOSTAT.
4. ANTIFREEZE is mixed with water to produce the engine coolant.
5. A(n) BYPASS VALVE permits coolant circulation through the engine when the thermostat is closed.
6. The fan switch, or THERMO SWTICH is a temperature-sensitive switch that controls fan motor operation.
7. The engine is connected to the radiator by the RADIATOR HOSES.
8. The FAN draws air through the radiator.
9. A disc with fan-like blades that spins and produces pressure and flow is known as a(n) WATER PUMP IMPELLER
10. The center section of the radiator made up of tubes and cooling fins is called the CORE.
Question 912 points Two hydrogen isotopes fuse to form hellum, as shown below. The mass of helium is 3.12 hydrogen atoms. Select the equation you would use to determine how much energy was * 108 m/s H+, H He+energy O E-0.12 x 10-kg)x3 x 108 m/sp? O E=3.12 x 10 kg) x 108 m/s??
How much power flows through a circuit with 5 amps and 120 volts?
Can I get help??? again
it's timed #TheStruggleIsReal
The density of an object is .835 g/cm3. If its volume is 34 cm3, what is the mass of the object?
A. 0.02 g
B. 0.41 g
C. 28.39 g
D. 40.72 g
Answer:
C. 28.39 gram
Explanation:
Steps:
m = V × ρ
= 34 cubic centimeter × .835 gram/cubic centimeter
= 28.39 gram
Which of the following is an example of erosion in action ?
Example of erosion: Wind carries small pieces of rock away from the side of a mountain.
Which of the following are examples of erosion?Erosion is the procedure by which the surface of the Earth gets worn down. Erosion can be created by natural elements such as erosion as wind and glacial ice. But everyone who has ever seen a picture of the Grand Canyon knows that nothing strikes the erosion slow steady movement of the water when it comes to commuting the Earth
Rain, rivers, floods, lakes, and the ocean convey away bits of soil and sand and slowly wash away the deposit. Rainfall produces four types of soil erosion: splash erosion, sheet erosion, rill erosion, and ravine erosion.
So we can conclude that Erosion is a ruinous force that wears away land features.
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In an 11v11 adult game, I see a defender challenge for the ball. The defender misses the ball and with their momentum they accidentally but careelessly trip the opponent. The ball rolls over the touchline. What is the restart
For the Direct free kick, the game restarted.
What does a soccer direct free kick entail?There are two different kinds of free kicks used in soccer: direct and indirect.The term "direct free kick" refers to a kick that can be used as a direct strike.Indirect free kicks require a second touch before the ball can be used as a shot at goal.
A direct penalty kick is what?If a player attacks an opponent in a way that the referee deems to be irresponsible, reckless, or employing excessive force, the referee will award a direct free kick.jumps, kicks, or makes an attempt to kick.
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What does the energy hill represent on an energy diagram?
A. The additional potential energy the reactants must gain in order to
react
B. The final amount of potential energy of the products of the
reaction
C. The potential energy the reactants have stored in molecular bonds
D. The potential energy gained by the products when a reaction
happens
Answer:
In my opinion I think the answer is C you don't have to choose C
Answer:
A The additional potential energy the reactants must gain in order toreact
Explanation:
Convert 10.3 m/s to rotations per minute (rpm)
A 10.0-g bullet is fired into a stationary block of wood having mass m 5 5.00 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m/s. What was the original speed of the bullet
The original speed of the bullet was 300.6 m/s.
What is the best meaning of mass?A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.
Given:
mV bi +MV wi =mV b +M Vwf
where m= mass of bullet =10 g=10^−2 ∣kg
M= mass of wood block =5 kg
V bI = initial mass of bullet
Vwi = initial mass of wood block and V bf =V wf
=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V
bi = 10 −2 5.01×0.6 V
bi =300.6 m/s
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An engine creates a 2230 N force that pushes a car forward 58.3 m in 9.40 s. how much power does the engine produce? (unit = W)
Given :
An engine creates a 2230 N force that pushes a car forward 58.3 m in 9.40 s.
To Find :
How much power does the engine produce in Watt.
Solution :
We know, Work done is given by :
[tex]W = F.d\\\\W = 2230 \times 58.3 \ J\\\\W = 130009\ J[/tex]
Now, Power is given by :
[tex]Power = \dfrac{Work \ Done}{Time \ Taken}\\\\P = \dfrac{130009}{9.4}\ W\\\\P = 13830.74\ W[/tex]
Therefore, power produced by engine is 13830.74 W.
Which of these situations describe the motion shown in the motion diagram at point a?
consider the following situations:
a car is moving along a straight road at a constant speed.
a car is moving along a straight road while slowing down.
a car is moving along a straight road while speeding up.
a hockey puck slides along a horizontal icy (frictionless) surface.
a hockey puck slides along a rough concrete surface.
a cockroach is speeding up from rest.
a rock is thrown horizontally; air resistance is negligible.
a rock is thrown horizontally; air resistance is substantial.
a rock is dropped vertically; air resistance is negligible.
a rock is dropped vertically; air resistance is substantial.
The right response is a hockey puck slides along a horizontal icy frictionless surface and as a car is going along a straight road at a constant pace, according to the motion diagram.
The car is shown in the diagram starting at point a. The arrows remain pointing in the same way. This indicates that the thing is travelling directly forward. The arrows stay stationary at A. This indicates that the thing is travelling continuously.
The speed of the puck is not impacted by friction while it is moving on an ice rink surface. So, it is reasonable to suppose that it is moving at a constant speed before to impact.
The work done is zero only if there is no non-conservative force, such as friction, because the kinetic energy does not vary and the car is going along a straight, horizontal road. The work done will be force into displacement if there is friction.
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Particles q1 = -8.99 uC, q2 = +5.16 uC, and q3 = -89.9 uC are in a line. Particles q1 and q2 are separated by 0.220m and particles q2 and q3 are separated by 0.330m. What is the net force on particle q1?
Answer: -39200.45 Nm^2/C^2 This is rough work
Explanation:
So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.
IntroductionHi! Here I will explain the net force of three charges that interacts. Remember that this question can be solved using Coulomb's Law. Coulomb's Law states that the interaction force between two interacted charges will be proportional to the magnitude of the charges that have specific interaction but inversely proportional to the square of the value of the distance between each other. So, with this concept, we can calculate the magnitude of coulomb force with this equation:
[tex] \boxed{\sf{\bold{F = k \cdot \frac{q_1 \cdot q_2}{(r_{12})^2}}}} [/tex]
Formula UsedOn this condition, the net force will be felt only by the first charge, so we must define the position of the first charge as a fixed one. So, we can calculate the magnitude of coulomb force concerning the first charge with this equation:
[tex] \boxed{\sf{\bold{\sum F_{q1} = k \cdot (\frac{q_1 \cdot q_2}{(r_{12})^2} + \frac{q_1 \cdot q_3}{(r_{13})^2})}}} [/tex]
With the following condition:
[tex] \sf{\sum F_{q1}}[/tex] = the net force will be felt by the first charge (N)k = constant of coulomb ≈ [tex] \sf{9 \times 10^{9}}[/tex] N.m²/C².[tex] \sf{q_1}[/tex] = first charge (C)[tex] \sf{q_2}[/tex] = second charge (C)[tex] \sf{q_3}[/tex] = third charge (C)[tex] \sf{r_{12}}[/tex] = the distance between first and second charge (m)[tex] \sf{r_{13}}[/tex] = the distance between first and third charge (m)Problem SolvingWe know that:[tex] \sf{q_1}[/tex]= first charge = -8.99 [tex] \sf{\mu C}[/tex] = [tex] \sf{-8.99 \times 10^{-6}}[/tex] C.[tex] \sf{q_2}[/tex]= second charge = +5.16 [tex] \sf{\mu C}[/tex] = [tex] \sf{+5.16 \times 10^{-6}}[/tex] C.[tex] \sf{q_3}[/tex]= third charge = -89.9 [tex] \sf{\mu C}[/tex] = [tex] \sf{-8.99 \times 10^{-5}}[/tex] C.[tex] \sf{r_{12}}[/tex] = the distance between first and second charge = 0.220 m = [tex] \sf{2.2 \times 10^{-1}}[/tex] m.[tex] \sf{r_{13}}[/tex] = the distance between first and third charge = 0.220 + 0.550 m = [tex] \sf{5.5 \times 10^{-1}}[/tex] m.What was asked?[tex] \sf{\sum F_{q1}}[/tex] = the net force will be felt by the first charge = ... NStep by Step:[See the attached image to know how to solve this problem]
Conclusion:So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.
Learn More:Basic explanation about Coulomb's Law https://brainly.com/question/26892767How to count net force of three charged particles that placed at each of three corners of an equilateral triangle https://brainly.com/question/13437206A 3 kg toy car is moving at 4 m/s. Calculate the Ek if the car were moving TWICE as fast. Include units
The kinetic energy would be 96 J, for the car moving at 4m/s and with 3kg mass.
The kinetic energy (Ek) of the toy car is given by Ek = ½ mv2, where m is the mass of the car (3 kg) and v is the velocity (4 m/s). Thus, the kinetic energy of the car is 24 J. If the car were moving twice as fast (8 m/s), the kinetic energy would be 96 J. The units are Joules (J).
What is kinetic energy?Kinetic energy is the energy of a body or system due to its motion. It is the energy that an object has due to its motion. Kinetic energy is equal to one half of the mass of the object multiplied by the square of its velocity.
Learn more about Kinetic energy:
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