1 mole of methane (CH₄) is burned it releases 461.9 KJ of heat then the ΔH for the combustion of 8.0 g of methane is 230.1 kJ.
To calculate the ΔH for the combustion of 8.0 g of methane, we need to first convert the mass of methane to moles.
The molar mass of methane (CH₄) is:
C: 12.01 g/mol
H: 1.01 g/mol
4 x H: 4.04 g/mol
Molar mass of CH₄ = 12.01 + 4.04 = 16.05 g/mol
So, 8.0 g of CH₄ is equal to:
n = m/M = 8.0 g / 16.05 g/mol = 0.498 moles of CH₄
Now, we can use the molar heat of combustion to calculate ΔH:
ΔH = n x ΔHcomb
ΔHcomb is the molar heat of combustion, which is given as 461.9 kJ/mol.
ΔH = 0.498 moles x 461.9 kJ/mol = 230.1 kJ
Methane is a chemical compound with the formula CH₄. It is a colorless, odorless, and flammable gas that is the primary component of natural gas. Methane is the simplest hydrocarbon and the main component of biogas and landfill gas. It is also a potent greenhouse gas and a major contributor to climate change. Methane is used as a fuel for heating, cooking, and electricity generation, as well as in industrial processes such as chemical synthesis and metal production.
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When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have
A. one equivalence point.
B. a pH of 7 at the equivalence point.
C. two distinct equivalence points
D. two equivalence points below 7.
E. no equivalence point
When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have: two distinct equivalence points. The answer is C.
There are two distinct steps in the titration curve, the first equivalence point is the point at which the base has reacted with all of the H+ ions from the first acidic hydrogen, while the second equivalence point is the point at which the base has reacted with all of the H+ ions from the second acidic hydrogen.
The pH at the first equivalence point will be less than 7, and the pH at the second equivalence point will be greater than 7, indicating that the solution is acidic for the first equivalence point and basis for the second equivalence point.
The Ka1 and Ka2 values for diprotic acids are typically different because the first hydrogen ion is more strongly bound to the molecule than the second hydrogen ion, resulting in different dissociation constants for each hydrogen ion.
Therefore, the pH vs. volume plot of the titration of a diprotic acid with a strong base will have two distinct equivalence points if Ka1 and Ka2 are significantly different.
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Loneliness
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Define radioactive half-life. Use the terms parent isotope & daughter isotope in your answer.
Answer:
Radioactive half-life refers to the amount of time it takes for half of the parent isotopes in a radioactive substance to decay into their respective daughter isotopes. The parent isotope is the original, unstable radioactive isotope that undergoes radioactive decay, while the daughter isotope is the resulting isotope after the decay process. During each half-life, the amount of parent isotope decreases by half, while the amount of daughter isotope increases correspondingly. This process continues in subsequent half-lives until all of the parent isotopes have decayed into their daughter isotopes.
write a balanced net ionic equation for the neutralization of equimolar amounts of hno2 and koh. indicate whether the ph after neutralization is greater than, equal to, or less than 7. values of ka and kb are listed in appendix c.
The concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.
The balanced net ionic equation for the neutralization of equimolar amounts of HNO₂ and KOH is:
HNO₂ (aq) + OH- (aq) → NO₂⁻ (aq) + H₂O (l)
After the neutralization, the resulting solution contains the NO₂⁻ ion, which is the conjugate base of HNO₂. Since HNO₂ is a weak acid (with a pKa of 3.15, according to appendix c), the NO₂⁻ ion is a weak base. The reaction of NO₂⁻- with water is:
NO₂⁻ (aq) + H₂O (l) ⇌ HNO₂ (aq) + OH⁻- (aq)
The equilibrium constant for this reaction is Kb = [HNO₂][OH-] / [NO₂⁻].
Since NO₂⁻ is a weak base, the concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.
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Which of the following explains the relationship between surface area of a solid solute and its dissolution in a solvent? a.) As surface area increases, the time necessary for complete dissolution decreases. b.) As surface area decreases, the time necessary for complete dissolution decreases. c.) Surface area does not affect the time necessary for complete dissolution.
The correct answer is a.) As surface area increases, the time necessary for complete dissolution decreases.
This is because the rate of dissolution is proportional to the surface area of the solute exposed to the solvent. When the surface area of the solute is increased, the solvent molecules have more area to come into contact with the solute and dissolve it. Increasing the surface area of a solid solute increases the area available for solvent molecules to interact with the solute. Therefore, the solute particles dissolve faster, and the time necessary for complete dissolution decreases. This is why substances are often ground into smaller particles to increase their surface area, which enhances their solubility and dissolution rate.
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When treated with base, the following compound undergoes an intramolecular aldol reaction to give a product containing a ring. Propose a structure for this product. base C11H180 + H20 . . • Consider EIZ stereochemistry of alkenes. • Do not show stereochemistry in other cases. • If there is more than one major product possible, draw all of them. Draw organic products only • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. •
Separate multiple products using the + sign from the drop-down menu.
The product obtained after the intramolecular aldol reaction of 2-pentanone (C5H10O) with a strong base is a six-membered cyclic ring with a double bond and an alcohol group.
When treated with a base, the compound C11H18O undergoes an intramolecular aldol reaction to give a product containing a ring. To propose a structure for this product, follow these steps:
Identify the carbonyl group (C=O) in the compound, which will act as the electrophile in the reaction.Identify the alpha-hydrogen adjacent to the carbonyl group, which will act as the nucleophile upon deprotonation by the base.Deprotonate the alpha-hydrogen using the base to form an enolate ion.Perform a nucleophilic attack by the enolate ion on the carbonyl group within the same molecule, resulting in the formation of a new C-C bond.Tautomerize the product, if necessary, to give the final aldol product with an alkene group (considering E/Z stereochemistry of alkenes).If there is more than one major product possible, draw all of them.The product structure is shown below: Thus, the product obtained after the intramolecular aldol reaction of 2-pentanone (C5H10O) with a strong base is a six-membered cyclic ring with a double bond and an alcohol group.
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What is the purpose of sulfuric acid in a Fischer esterification reaction?
Sulfuric acid is added to Fischer's esterification reaction as an acid catalyst to increase the pace of the reaction while also going about as a drying-out specialist.
The Fischer esterification is an acid-catalyzed harmony reaction. The reaction proceeds slowly and adding sulfuric acid increases the pace of the reaction. Concentrated sulfuric acid is used to give the greatest yield to the item.
Fischer esterification or Fischer-Speier esterification is a special sort of esterification by refluxing a carboxylic acid and a liquor in the presence of an acid catalyst. The reaction was first described by Emil Fischer and Arthur Speier in 1895. Fischer esterification is a natural reaction used to change a carboxylic acid and a liquor over completely to an ester using a strong acid catalyst. It is also known as Fischer-Speier Esterification.
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Hydrogen peroxide is a compound made from two elements: hydrogen and oxygen. Water is also a compound made from hydrogen and oxygen. What makes these two compounds different?
Pls help!!
Answer:
Explanation:
Hydrogen peroxide (H2O2) and water (H2O) are both compounds made up of hydrogen and oxygen, but they have different chemical structures and properties.
Water is a simple compound made up of two hydrogen atoms and one oxygen atom that are covalently bonded together. Water is a polar molecule, which means that it has a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom. This polarity allows water molecules to interact with each other and other polar substances, making it an excellent solvent for many substances.
Hydrogen peroxide, on the other hand, is a compound made up of two hydrogen atoms and two oxygen atoms that are covalently bonded together. The two oxygen atoms are bonded together in a single covalent bond, while the other oxygen atom is bonded to one of the hydrogen atoms. Hydrogen peroxide is a highly reactive and unstable compound that readily decomposes into water and oxygen gas. It is often used as a disinfectant or bleaching agent due to its strong oxidizing properties.
In summary, the main differences between hydrogen peroxide and water are their chemical structures and properties. Water is a simple, stable, and polar molecule, while hydrogen peroxide is a more complex and reactive compound with oxidizing properties.
a buffer solution contains 0.11 mol of acetic acid and 0.14 mol of sodium acetate in 1.00 l. the ka of acetic acid is 1.8 x 10-5. part a: what is the ph of this buffer? round your answer to two places past the decimal.
The buffer solution has a pH of 4.85.
To determine the pH of the buffer solution, we first need to calculate the concentration of both the conjugate acid (acetic acid) and conjugate base (sodium acetate) in the solution. Using the given information, we can calculate the concentrations as follows:
[acetic acid] = 0.11 mol/1.00 L = 0.11 M
[sodium acetate] = 0.14 mol/1.00 L = 0.14 M
Next, we need to determine the pKa of acetic acid, which is given as 1.8 x 10⁻⁵. We can use the Henderson-Hasselbalch equation to calculate the pH of the buffer solution:
pH = pKa + log([A⁻]/[HA])
where [A-] is the concentration of the conjugate base and [HA] is the concentration of the conjugate acid.
Substituting the values into the equation, we get:
pH = 4.74 + log(0.14/0.11) = 4.85
Therefore, the pH of the buffer solution is 4.85.
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How many grams of oxygen are there in a 50L gas cylinder at 21 degrees Celsius and a pressure of 15. 7atm
Answer:
It's 1.0407 Kilograms of oxygen (O2) in that container
Explanation:
according to ideal gas law:
[tex]PV = nRT[/tex]
P: pressure, V: volume, n: moles, R: gas constant = 0.0821, T: temperature in Kelvin
Temperature in Kelvin = Temperature in Celsius + 273
Gas constant (R) is changed by changing pressure units (while using atm, R = 0.0821 atm•L/mol•K )
by substituting with given data:
[tex]15.7 * 50 = n*0.0821*(21+273)[/tex]
[tex]n = \frac{50*15.7}{0.0821 * 294} = 32.522 mol[/tex]
So, O2 mass (Molar mass of O2 = 32 g/mol) = 32.522 * 32 = 1040.709 grams = 1.0407 kilograms
write a set of possible quantum numbers (n, l , m l, m s) for an electron in a 7d {x^2-y^2} orbital.
The set of quantum numbers for an electron in a 7d {x²-y²} orbital would be:
n = 7, l = 2, m_l = ±2, m_s = ±1/2
The principal quantum number, n, describes the energy level of the electron, which in this case is 7 since the electron is in the seventh energy level. The angular momentum quantum number, l, describes the shape of the orbital, which for a d orbital can range from 0 to 2. The magnetic quantum number, m_l, describes the orientation of the orbital in space, which for a d orbital can range from -l to +l. Since the orbital in question is {x²-y²}, it has two lobes that lie along the x- and y-axes and two lobes that lie along the z-axis, which corresponds to m_l = ±2. Finally, the spin quantum number, m_s, describes the direction of the electron's spin, which can be either +1/2 or -1/2.
It's worth noting that electrons in the same orbital must have different spin quantum numbers, according to the Pauli exclusion principle. Therefore, the two electrons in the 7d {x²-y²} orbital would have opposite spin quantum numbers, i.e. one would have m_s = +1/2 and the other would have m_s = -1/2.
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coitünsup Isolmer
4. Sulfur dioxide (SO₂) is a compound used to preserve grapes. How many moles
are in a 23.8 g sample of sulfur dioxide? The molar mass of SO₂ is 64 g/mol. Use
dimensional analysis, show all work to receive full credit. (4 pts)
a. 0.37 mol SO₂
b. 1.2 mol SO₂
c. 0.5 mol SO₂
d. 44 mol SO₂
Answer:
a. 0.37 mol SO₂
Explanation:
The number of moles in a sample can be calculated by dividing the mass of the sample by its molar mass. In this case, the number of moles of SO₂ in a 23.8 g sample would be:
23.8 g SO₂ × (1 mol SO₂ / 64 g SO₂) = 0.37 mol SO₂
So the correct answer is (a) 0.37 mol SO₂.
if the resulting solution has a volume of 1.7 l , what is the minimum mass of caso4(s) needed to achieve equilibrium?
The minimum mass of [tex]CaSO_{4}[/tex](s) needed to achieve equilibrium in a 1.7 L solution is approximately 4.08 grams.
How to determine the minimum mass required to achieve equilibrium?Step 1: Find the solubility of [tex]CaSO_{4}[/tex] in water at the given temperature.
The solubility of [tex]CaSO_{4}[/tex] in water at room temperature is approximately 2.4 grams per liter (g/L).
Step 2: Calculate the amount of [tex]CaSO_{4}[/tex] that will dissolve in 1.7 L of water.
Use the solubility value from Step 1:
Amount of [tex]CaSO_{4}[/tex] = Solubility × Volume
Amount of [tex]CaSO_{4}[/tex] = 2.4 g/L × 1.7 L
Amount of [tex]CaSO_{4}[/tex]4 ≈ 4.08 grams
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a 9.5 l container at 1.7 atm has 0.50 mol c3h6, a van der waals gas with . what is the temperature (k)?
A 9.5 l container at 1.7 atm has 0.50 mol C₃H₆ , a vander waal gas, the temperature will be 393.65 K.
The formula of ideal gas equation is
PV= nRT
where P is the pressure of the gas, V is the volume of the gas, n is the no of moles of gas, R is gas constant and T is the temperature.
Here,
P=1.7 atm
V= 9.5 l
n= 0.50 mol
Converting 1.7 atm into Kpa
P= 1.7 atm × 101.325 Kpa/1 atm
P=172.2525 KPa
Putting these values in the equation PV=nRT
172.2525 KPa × 9.5 l = 0.5 mol×8.314 l.KPa/mol.K.T
⇒1636.39875 l. KPa= 4.157 l.KPa/ K.T
⇒T= 393.6489
⇒T= 393.65 approx
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what are the reduced mass and moment of inertia of 23 na35 cl? the equilibrium internuclear distance re is 236 pm. whatarethevaluesofe forthestateswithj 1andj 2?
The reduced mass of NaCl= 14.45 amu.
moment of inertia= [tex]= 0.809 \times 10^{-43} kg m^2[/tex]
E value For J=1 is E(1) = 0.360 [tex]cm^{-1}[/tex] and for J=2 is E(2) = 0.720[tex]cm^{-1}[/tex]
To find the reduced mass and moment of inertia of a diatomic molecule like NaCl, we need to know the masses of the two atoms (Na and Cl) and the equilibrium internuclear distance.
The mass of Na is approximately 23 atomic mass units (amu), while the mass of Cl is approximately 35 amu.
The reduced mass of the system can be calculated using the following formula:
μ [tex]= m_1m_2 / (m_1 + m_2)[/tex]
where [tex]m_1[/tex] and [tex]m_2[/tex] are the masses of the two atoms.
μ = (23 amu x 35 amu) / (23 amu + 35 amu)
= 14.45 amu
The moment of inertia of a diatomic molecule is given by the formula:
[tex]I = \mu r^2[/tex]
where μ is the reduced mass of the system and r is the internuclear distance.
[tex]I = 14.45 amu \times (236 pm)^2[/tex]
[tex]= 0.809 \times 10^{-43} kg m^2[/tex]
To find the values of E for the states with J=1 and J=2, we need to know the rotational constant (B) of the molecule. The rotational constant is related to the moment of inertia by the formula:
[tex]B = h / (8\pi^2cI)[/tex]
where h is Planck's constant, c is the speed of light, and I is the moment of inertia.
[tex]B = (6.626\times 10^{-34} J s) / (8\pi^2\times 3\times 10^8 m/s \times0.809\times 10^{-43} kg m^2)[/tex]
[tex]= 0.180 cm^{-1}[/tex]
The energy of a rotational state with quantum number J is given by the formula:
E(J) = B J(J+1)
For J=1, E(1) = 0.360 [tex]cm^{-1}[/tex]
For J=2, E(2) = 0.720[tex]cm^{-1}[/tex]
Note: The values of E are very small because they correspond to rotational transitions, which typically have lower energies than electronic transitions.
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2) a) Write the chemical reaction showing hydrogen carbonate polyatomic ion acting as an acid in water.
b) Write the chemical reaction showing hydrogen carbonate polyatomic ion acting as a base in water.
3) Acidic solutions have pH
than 7, while basic solutions have pH.
Neutral solutions have pH.
4) In a certain aqueous solution, the concentration of [H*] = 1.0 x 10-4 mol/L.
a) Calculation the pH of this solution. Show your work.
b) Is this solution acidic, neutral, or basic?
5) In another solution, the concentration of (H*1 = 1.0 × 10° mol/L.
a) Calculation the pH of this solution. Show your work.
b) Is this solution acidic, neutral, or basic?
c) Can a basic solution have any H* ions in it?
Answer:
2a) The chemical reaction showing hydrogen carbonate polyatomic ion (HCO3-) acting as an acid in water is:
HCO3- + H2O → H3O+ + CO32-
In this reaction, the hydrogen carbonate ion donates a hydrogen ion (H+) to water, forming hydronium ion (H3O+) and carbonate ion (CO32-).
2b) The chemical reaction showing hydrogen carbonate polyatomic ion (HCO3-) acting as a base in water is:
HCO3- + H2O ↔ H2CO3 + OH-
In this reaction, the hydrogen carbonate ion accepts a hydrogen ion (H+) from water, forming carbonic acid (H2CO3) and hydroxide ion (OH-).
3) Acidic solutions have a pH less than 7, while basic solutions have a pH greater than 7. Neutral solutions have a pH of 7.
4a) The pH of a solution can be calculated using the formula:
pH = -log[H+]
Given [H+] = 1.0 x 10^-4 mol/L, we have:
pH = -log(1.0 x 10^-4) = 4
Therefore, the pH of the solution is 4.
4b) Since the pH of the solution is less than 7, it is acidic.
5a) The pH of a solution can be calculated using the formula:
pH = -log[H+]
Given [H+] = 1.0 x 10^0 mol/L, we have:
pH = -log(1.0 x 10^0) = 0
Therefore, the pH of the solution is 0.
5b) Since the pH of the solution is 0, it is highly acidic.
5c) No, a basic solution cannot have any H+ ions in it. Basic solutions have a higher concentration of hydroxide ions (OH-) than hydrogen ions (H+).
The Ostwald Process is used to make Nitric Acid in a one step process where ammonia is burnt in 900 degrees Celsius at 10 atm in the presence of platinum/rhodium catalyst. Explain:
(a) Why a temperature of 900 degrees Celsius is used.
(b) Why is a pressure of 10 atm used?
(c) Economic consideration.
Nitric acid is created by the Ostwald process. Platinum is utilised as a catalyst. Nowadays, catalysts consisting of 90% platinum and 10% rhodium are in use. The temperature is 800 °C.
What key byproduct is produced during the ammonia oxidation steps of the Ostwald nitric acid manufacturing process?The first phase in Ostwald's method for producing nitric acid includes oxidising ammonia gas with oxygen gas to produce nitric oxide gas and steam.
How does the Ostwald process produce nitric acid? What conditions are necessary to obtain the Optimum product?Significant steps in the Ostwald process: A catalytic chamber is filled from the top with a 1:10 combination of ammonia and clean, filtered air.
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what is the mass of 6.02×1022 6.02 × 10 22 atoms of argon?
Answer:
3.6 g
Explanation:
No. of moles = No. of atoms / Avogadro's No.
= 6.02 × 10^22 / 6.02 × 10^23
= 0.1 moles of argon
No. of moles = mass/ molar mass
molar mass of argon = 36 g/mol
Therefore, mass of argon = No. of moles × molar mass
= 0.1 × 36
= 3.6 g of argon
True/false....
The effective nuclear charge acting on an electron is larger than the actual nuclear charge.
Effective nuclear charge is always lesser than the actual nuclear charge because of the inner core electrons shielding outer core electrons. so, the statement given is false.
The effective nuclear charge is said to be the the actual amount of positive charge experienced by an electron in a multi-electron atom. It is defined as the net positive charge pulling these electrons towards the nucleus. The stronger the pull on the outermost electrons that is valence electrons towards the nucleus, the higher the effective nuclear charge.
It is the magnitude of positive charge in an atom from the pull on the valence electrons towards the positively charged nucleus. An increase in atomic number associated with a decrease in atomic radius will result in a higher effective nuclear charge of an electron. It increases with increasing atom number and with decreasing atomic radius as you go across a period.
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A compound is composed of 79.4% carbon, 8.9% hydrogen, and 11.7% oxygen by weight. If it has a molar mass of 272 g/mol, what is its molecular formula?
calcium reacts with sulfur (s8) forming calcium sulfide. what is the theoretical yield (g) of cas(s) that could be prepared from 1.94 g of ca(s) and 3.40 g of sulfur(s)?
The theoretical yield (g) of `CaS` that could be prepared from `1.94 g` of `Ca(s)` and `3.40 g` of `S8` is `0.958 g`.
Mass of calcium (Ca) = 1.94 g
Mass of sulfur (S) = 3.40 g
The reaction is,
`Ca(s) + S8 -> CaS(s)`
Molar mass of Ca = 40 g/mol
Molar mass of S8 = 8 × 32.06 g/mol = 256.48 g/mol
As per the reaction 1 mol of Ca reacts with 1 mol of S8 to yield 1 mol of CaS. So, from 1 mol of Ca, we get 1 mol of CaS. Hence, from `40 g` of Ca, we get `CaS of 80 g`.
Now, calculating the number of moles of Ca, we have
`(1.94 g)/(40 g/mol)`= `0.0484 mol`
Calculating the number of moles of S, we have
`(3.40 g)/(256.48 g/mol)`= `0.01326 mol`
From the balanced equation, it is seen that 1 mole of Ca reacts with 1 mole of S to form 1 mole of CaS. Since S is the limiting reactant, 0.01326 moles of CaS can be obtained from 0.01326 moles of S. 1 mole of CaS weighs
40 + 32.06 = 72.06 g.
So, `0.01326 mol` of CaS weighs `0.958 g`. Hence, the theoretical yield of `CaS` is `0.958 g`.
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1 mole of Powdered Aluminum Hydroxide Al(OH)3, reacts with 3 moles of aqueous hydrochloric Acid (HCl)to produce 1 mole aqueous Aluminum Chloride (AlCl3) and 3 moles of water.
the reaction would result in 1 mole of aluminium chloride and 3 moles of water from a starting mole of 1 mole of powdered aluminium hydroxide, which would require 3 moles of hydrochloric acid to thoroughly react with it.
What is the balanced chemical equation?The balanced chemical equation for the reaction between powdered aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) is:
[tex]2 Al(OH)3 + 6 HCl \rightarrow 2 AlCl3 + 6 H2O[/tex]
This equation shows that 2 moles of aluminum hydroxide react with 6 moles of hydrochloric acid to produce [tex]2[/tex] moles of aluminum chloride and [tex]6[/tex] moles of water.
The mole ratio between aluminum hydroxide and hydrochloric acid is 1:3, and the mole ratio between aluminum chloride and water is also 1:3, as per the stoichiometry of the balanced equation.
Therefore, if you start with 1 mole of powdered aluminum hydroxide, you would need 3 moles of hydrochloric acid to completely react with it, and the resulting reaction would produce 1 mole of aluminum chloride and 3 moles of water.
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g part d: trans-1,2-dibromocyclopentane - construct a model of trans-1,2-dibromocyclopentane and its mirror image (use the models from part c). 1. how many carbons in this compound are chiral, bonded to four different groups? 2. are the molecules superimposable? 3. does a plane of symmetry exist in the molecule? 4. can this compound exist as a pair of enantiomers?
1) The structure of the compound shows that two carbons are bonded and chiral,
2) they are not superimposable and
3) no plane of symmetry exists between them.
4) Yes, trans-1,2-dibromocyclopentane can exist as a pair of enantiomers.
To construct a model of trans-1,2-dibromo cyclopentane and its mirror image, the structure of the compound is need to be known. Here's the structural formula of trans-1,2-dibromocyclopentane:
Br H
| |
Br H
\ /
C=C
| |
C-C
| |
C-C
| |
C-C
| |
H H
There are two carbons in trans-1,2-dibromocyclopentane that are chiral, bonded to four different groups. They are the two carbons in the cyclopentane ring that are not part of the double bond.
No, the molecules are not superimposable. If we try to align the two molecules, we'll find that the bromine atoms on one molecule will not align with the hydrogen atoms on the other molecule.
No, there is no plane of symmetry in the molecule. If we try to draw a plane that would divide the molecule into two equal halves, we'll find that it is not possible without cutting through at least one of the chiral carbons.
Yes, trans-1,2-dibromocyclopentane can exist as a pair of enantiomers. Since there are two chiral carbons in the molecule, there are four possible stereoisomers. However, since the molecule has a plane of symmetry, two of these stereoisomers are identical to their mirror image, and therefore achiral. The remaining two stereoisomers are enantiomers, meaning they are mirror images of each other and cannot be superimposed.
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what is the mass percent of chlorine in iron(ii) chloride?
The mass percent of chlorine in Iron(II) chloride is 55.93%.
Iron(II) chloride is a chemical compound that has the formula FeCl₂. It is also known as ferrous chloride. Iron(II) chloride is an ionic compound. It is made up of positively charged iron ions (Fe2+) and negatively charged chloride ions (Cl−).The formula mass of FeCl₂ can be calculated as follows:
Formula mass of FeCl₂ = Atomic mass of Fe + (Atomic mass of Cl × 2)
Formula mass of FeCl₂ = 55.85 + (35.45 × 2) = 126.75.
The mass percent of chlorine in Iron(II) chloride can be calculated using the following formula:
Mass percent of chlorine = (Mass of Cl in FeCl₂ ÷ Formula mass of FeCl₂) × 100%
The mass of chlorine in one mole of FeCl₂ is equal to the product of the number of chlorine atoms in one mole of FeCl₂ and the atomic mass of chlorine.The number of chlorine atoms in one mole of FeCl₂ is 2, and the atomic mass of chlorine is 35.45.
Mass of Cl in FeCl₂ = Number of Cl atoms × Atomic mass of Cl
Mass of Cl in FeCl₂ = 2 × 35.45 = 70.9
Now, let's substitute the mass of chlorine and the formula mass of FeCl₂ into the formula to calculate the mass percent of chlorine. Mass percent of chlorine = (Mass of Cl in FeCl₂ ÷ Formula mass of FeCl₂) × 100%
Mass percent of chlorine = (70.9 ÷ 126.75) × 100% = 0.5593 × 100% = 55.93%.
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two metals, A and B are placed in direct contact in an insulated container. Metal a has a mass of 50g and an initial temperature of 150C, and metal B had a mass of 50g and an initial temperature of 50c. If the equilibrium of the two metals is 75c, which metal has a higher specific heat?
Answer: A is better trust me I qualified my sats
Explanation:
a polystyrene molecule has a molar mass of 18,000 g/mol. calculate the number of monomer units (the degree of polymerization) for this molecule.
This polystyrene molecule is roughly 173 percent polymerized.
What is the polymerization formula?Multiply the molecular weight of the monomer by the polymer's molecular mass. Tetrafluoroethylene, for instance, has a molecular mass of 1,20,000; its degree of polymerization is computed as 1,20,000 / 100 = 1,200. Hence, 1,200 is the degree of polymerization.
A polymer called polystyrene is created by repeating units of styrene monomers. By dividing the molar mass of the styrene monomer by the quantity of monomer units (degree of polymerization) present in the polymer, one may get the molar mass of polystyrene, which is 18,000 g/mol.
Let's call the styrene monomer's molar mass M. Then, we may create the following equation:
18,000 g/mol = M × n
where n is the degree of polymerization (the number of monomer units).
Rearranging the equation, we can solve for n:
n = 18,000 g/mol ÷ M
The periodic chart shows the molar mass of styrene as the total of the atomic masses of its component elements as follows:
M(styrene) = 104.15 g/mol (28.05 g/mol for carbon x 8 + 1.01 g/mol for hydrogen x 8)
When we enter this number into the equation, we obtain:
n = 18,000 g/mol ÷ 104.15 g/mol ≈ 173
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in order to apply silicone oil/grease to a glass joint, use your fingers to smear the grease on the smaller part of the joint. True or False?
Grease can be applied with a syringe, wood splint because If grease is allowed with fingers there is a possibility the reagent will dissolve the grease and become contaminated. So, the statement is false.
The grease lubricants can come from many sources. Raw materials of the grease includes the base fluids, additives and thickeners used to make lubricating oils and grease may contain paper fiber, plastic debris, iron oxide, and chips from a drum liner.
The hardness and size of the greases over rolled particles may damage the bearing surfaces which gives a noticeable increase in overall bearing noise but not to the degree that the bearing fatigue life is adversely affected. If grease is allowed with fingers there is a possibility the reagent will dissolve the grease and become contaminated so it can't be used with fingers.
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The point at which indicator undergoes colour change is called end point titration. True or False?
The given statement "The point at which indicator undergoes color change is called end point titration. " is True.
The endpoint of a titration is the point at which the indicator being used undergoes a color change, indicating that the reaction between the analyte and the titrant is complete. The choice of indicator depends on the nature of the reaction being studied and the pH range in which the reaction occurs. The indicator is selected such that its color changes at the pH at which the reaction is complete. For example, phenolphthalein is commonly used as an indicator in acid-base titrations because it changes from colorless to pink in the presence of a base, indicating the endpoint of the titration.
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why must some solid remain in contact with a solution of a sparingly soluble salt in order to ensure equilibrium?
A 5.0 l vessel holds 3.0 mol n2, 2.0 mol f2, and 1.0 mol h2 at 273 k. what is the partial pressure of fluorine? a. 453 kpa b. 907 kpa c. 1,361 kpa d. 2,722 kpa
The correct option is a. 453 kPa
To find the partial pressure of fluorine in the given mixture of gases, we need to use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas.
PV = nRT
where R is the gas constant.
First, we need to calculate the total number of moles of gas in the vessel:
[tex]n_t_o_t_a_l[/tex] = [tex]n_N[/tex]₂ + [tex]n_F[/tex]₂ + [tex]n_H[/tex]₂
[tex]n_t_o_t_a_l[/tex] = 3.0 mol + 2.0 mol + 1.0 mol
[tex]n_t_o_t_a_l[/tex] = 6.0 mol
Next, we need to calculate the total pressure of the gas mixture using the ideal gas law:
[tex]P_t_o_t_a_l[/tex]= ([tex]n_t_o_t_a_l[/tex] * R * T) / V
where T = 273 K and V = 5.0 L. The gas constant R has a value of 8.31 J/mol K.
[tex]P_t_o_t_a_l[/tex]= (6.0 mol * 8.31 J/mol K * 273 K) / 5.0 L
[tex]P_t_o_t_a_l[/tex] = 269.9 kPa
Now, we can use Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases:
[tex]P_t_o_t_a_l[/tex]= [tex]P_N[/tex]₂ + [tex]P_F[/tex]₂ + [tex]P_H[/tex]₂
We are given the number of moles of each gas, so we can calculate the mole fraction of fluorine:
[tex]X_F[/tex]₂ = n_F₂ / n_total
[tex]X_F[/tex]₂ = 2.0 mol / 6.0 mol
[tex]X_F[/tex]₂ = 0.333
The mole fraction of fluorine is 0.333, so we can use it to calculate the partial pressure of fluorine:
[tex]P_F[/tex]₂ = [tex]X_F[/tex]₂* [tex]P_t_o_t_a_l[/tex]
[tex]P_F[/tex]₂ = 0.333 * 269.9 kPa
[tex]P_F[/tex]₂= 90.0 kPa
Therefore, the partial pressure of fluorine in the mixture of gases is 90.0 kPa or 0.90 atm.
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