What’s the equation of the horizontal asymptote

Answer:

Step-by-step explanation:

x^2 + 18x + 81 = 0

x^2 + 9x + 9x + 81 = 0

x(x+9) + 9(x+9) = 0

(x + 9)(x + 9) = 0

(x + 9) = 0

x + 9 = 0

x = 0 - 9

Answer:

[tex]3x + 4y = - 2 \\ 4y = - 3x - 2) \div 4 \\ y = - \frac{3}{4} x - \frac{1}{2} \\ \boxed{ m = - \frac{3}{4}}[/tex]

Answer:

dont know

Step-by-step explanation:

sorry

9514 1404 393

Answer:

  a) see attached for the drawings

  b) p = 8n -4

  c) a(n) = 4n(n -3) +13  for n > 1; a(1) = 1

  d) none

Step-by-step explanation:

a) The overall dimensions of the next two stages of the pattern will be 7×7 and 9×9. Excluding the 4 "ears", the central squares are 5×5 and 7×7. The drawings are shown in the attachment.

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b) The sequence of perimeter values is ...

  4, 12, 20, 28, 36, ...

This is an arithmetic sequence with a common difference of 8. A suitable formula for the perimeter p of stage n is ...

  p = 8n -4

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c) The sequence of area values is ...

  1, 5, 13, 29, 53, ...

The first differences are ...

  4, 8, 16, 24, ...

and the second differences are ...

  4, 8, 8, ...

At no level are the differences "common", so this sequence cannot be described by a polynomial function. After the first one, the second differences are common, so the sequence after the first term can be described by a quadratic function.

The function describing the sequence must be defined in two parts:

  [tex]a(n)=\begin{cases}1&\text{ for $n = 1$}\\4n(n-3)+13&\text{ for $n>1$}\end{cases}[/tex]

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d) Because the function must be piecewise defined, the area sequence is not any of the types of sequences listed. After the first term, it is a quadratic sequence.

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Additional comment

The leading coefficient of the quadratic formula for the area sequence is half the second difference. When 4n² is subtracted from the sequence of areas, the remaining arithmetic sequence has a common difference of -12. In order to bring the total of these quadratic and arithmetic sequences up to the correct area value, 13 must be added. This formula would give a(1) = a(2) = 5, which is not the correct value for a(1). Hence, that must be defined separately.

Answer:

the product of -3 and +50 is -150

(-3)×+(50)=-150

Answer:

Step-by-step explanation:

-3 × 50 =

-150

Answer:

w= 8/7

Step-by-step explanation:

1. divide the numbers

[tex]12w-1*10=6-2w[/tex]

2. multiply the numbers

[tex]12-10=6-2w[/tex]

3. rearrange terms

[tex]12-10=-2w+6[/tex]

4. add 10 to both sides of the equation

[tex]12w-10+1-=-2w+6+10[/tex]

5. simplify

[tex]12w=-2w+16[/tex]

6. add 2w to both sides of the equation

[tex]12w+2w=-2w+16+2w[/tex]

7. simplify

[tex]14w=16[/tex]

8.divide both sides of the equation by the same term

14w/14 = 16/14

9. simplify

w = 8/7

Answer:

[tex]w = 2[/tex]

Step-by-step explanation:

[tex] \frac{(12w - 20)}{2} = 6 - 2w[/tex]

[tex]6w + \frac{ - 20}{2} = 6 - 2w[/tex]

[tex]6w + \frac{( - 10.2)}{(1.2)} = 6 - 2w[/tex]

[tex]6w + 10 = 6 - 2w[/tex]

[tex]6w - 10 + 2w = 6 - 2w + 2w[/tex]

[tex]6w + 2w - 10 = 6 - 2w + 2w[/tex]

[tex]8w - 10 = 6 - 2w + 2w[/tex]

[tex]8w - 10 = - 2w + 2w + 6[/tex]

[tex]8w - 10 = 6[/tex]

[tex]8w - 10 + 10 = 6 + 10[/tex]

[tex]8w = 6 + 10[/tex]

[tex]8w = 16[/tex]

[tex] \frac{8w}{8} = \frac{16}{8} [/tex]

[tex]w = \frac{16}{8} [/tex]

[tex]w = \frac{2.8}{1.8} [/tex]

[tex]w = 2[/tex]

[tex]Thank \: you!!![/tex]

Answer

0.128>0.218 ,0.218>0.128, 0.128<0.218, 0.218>0.128

Step-by-step explanation:

Answer:

a) f(0)=3*0+1 =0+1= 1

b)f(2)=3*2+1=6+1=7

c)f(-2)=3*(-2)+1=-6+1=-5

Answer:

Step-by-step explanation:

f(x) = 3x+1

f(0) = 3x + 1

f(0) = 3*0+1

f(0) = 0+1

f(0) = 1

f(2) = 3x+1

f(2) = 3*2+1

f(2) = 6+1

f(2) = 7

f(-2) =3x+1

f(-2) =3*-2+1

f(-2) = -6+1

f(-2) = -5

f(-2) =

Answer:

area of the shape below is

53cm^2

.......

Answer:

Your answer is -5

Step-by-step explanation:

On paper;

Answer:

0.72

Step-by-step explanation:

64 hundredths= 0.64

8 hundredths= 0.08

0.64 + 0.08 = 0.72

Answer:

.72

Step-by-step explanation:

You just add 64 and 8 (equal to 72) and make sure it's in the hundredths (.00) Hope this is helpful.

Answer:

24,000

Step-by-step explanation:

615 ≈ 600

38 ≈ 40

600 × 40 = 24,000

Therefore, 615 × 38 ≈ 24,000

Answer:

jzjzhsjoqhzjs I I shxaoaas

Answer:

parrelel

Step-by-step explanation:

Answer:

1st figure out how many feet in 1 yard

Then you can take that number <x>

X x 5

Step-by-step explanation:

Answer:

1.67 yards or 5/3

Step-by-step explanation:

I just looked it up

Answer:

answer is y=1x/6 +2. or y= X+ 12/6

Step-by-step explanation:

y-3 = 1/6(x-6)

y-3= 1x/6 -1

y = 1x/6 -1+3

y. = 1x/6 +2. or y= X+ 12/6

Answer:

y = -1/2x - 5/2

Step-by-step explanation:

y = 2x – 1

Current slope is 2, perpendicular is opposite inverse which is -1/2.

y-intercept through point (-5, 0):

y = mx + b

0 = -1/2(-5) + b

0 = 5/2 + b

b = -5/2

Use the perpendicular slope and b above to form new equation of line:

y = mx + b

y = -1/2x - 5/2

Answer:

(-6, 4.5)

Step-by-step explanation:

Answer:

ki

Step-by-step explanation:

The equation that models the situation is f(t) = 10 + 9t.

The carpenter has already shingled 10 garage roofs . The initial amount he has already shingled is like a constant in the equation.

He shingles at a constant rate of 9 per day. This means each day the carpenter shingles 9 roofs.

let

f(t) = number of garage roofs the carpenter shingles

t = time in days.

If the carpenter shingles 9 roofs per day , he will shingle 9 × t roof for t days.

To model the equation where he had already shingled 10 roofs and his shingling rate, can be represented as follows:

read more: https://brainly.com/question/22965839?referrer=searchResults

The missing factor that makes the equation true is 0.2.

According to the question;

Let the missing factor be represented as x.

In essence; by dividing both sides of the equation by 1.1; we have;

Read more:

https://brainly.com/question/21335695

The number of groups that can be chosen from the team of 17 depends on

the given conditions of the selection.

The correct responses are;

Reasons:

The combination of n objects taking r at a time is given as follows

[tex]_nC_r = \dbinom{n}{r}[/tex]

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = [tex]\dbinom{17}{9}[/tex] = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = [tex]\dbinom{9}{5} \times \dbinom{8}{4}[/tex]

[tex]\dbinom{9}{5} \times \dbinom{8}{4} = 126 \times 70 = 8,820[/tex]

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is [tex]\dbinom{17}{9} - \dbinom{9}{9}[/tex]

[tex]\dbinom{17}{9} - \dbinom{9}{9} = 24,310 - 1 = 24,309[/tex]

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

[tex]\dbinom{8}{8} \times \dbinom{9}{1} + \dbinom{8}{7} \times \dbinom{9}{2} + \dbinom{8}{6} \times \dbinom{9}{3} = 2,649[/tex]

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are [tex]\dbinom{15}{9} + 2 \times \dbinom{15}{8}[/tex]

[tex]\dbinom{15}{9} + 2 \times \dbinom{15}{8} = 5,005 + 2 \times 6,435 = 17,875[/tex]

(d) Two team members must work together or not at all is [tex]\dbinom{15}{7} - \dbinom{15}{9}[/tex]

[tex]\dbinom{15}{7} - \dbinom{15}{9} = 6,435 - 5,005 = 1,430[/tex]

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

Learn more here:

https://brainly.com/question/2790592

https://brainly.com/question/6949387

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

  -7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

  -14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

  -9 ≤ 3x ≤ 19

Divide all parts by 3.

  -3 ≤ x ≤ 19/3

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Additional comment

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

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For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

  |f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

  |f(x)| > g(x)   ⇒   f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

Answer:

[tex]\sqrt{3} xy^{3}[/tex]×(4x+5)

Step-by-step explanation:

6[tex]\sqrt{3} x^{2} y^{3} - 2\sqrt{3} x^{2} y^{3} + x \sqrt{75} y^{3}[/tex]        simplify

4[tex]\sqrt{3} x^{2} y^{3} +x\sqrt{75} y^{3}[/tex]          collect like terms

[tex]\sqrt{3} xy^{3}[/tex]×(4x+[tex]\sqrt{25}[/tex])      factored out [tex]\sqrt{3} x y^{3}[/tex]

[tex]\sqrt{3} xy^{3}[/tex]×(4x+5)        simplify

Answer:

12.4

Step-by-step explanation:

do 9x11 (the cross)

then divide that by 8, so 99/8

that equals 12.375 which rounded to the nearest tenth is 12.4

Answer:

(assuming we're deciding decimals by decimals)

Dividing decimals is alot like regular decimal dividing. First, you must move the decimal places so it becomes a whole number. This makes it easier and less confusing as steps go on. Now we can divide regularly as we go on, making sure to put the amount of decimal spots we moved back in the answer.

Answer:

The first step is to make the divisor a whole number by multiplying it by a power of 10. When you multiply the divisor by a power of 10, you must multiply the dividend by the same power of 10. Then divide. Check your answer using estimation.

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

Given info:

6885 ÷ 46

Here, we have given divisor (43) & dividend (6885). And in problem they asked to find quotient & remainder.

Let's solve!!

[tex] \sf{46 \overline{\bigg)68885 \bigg(}149← \red{Quotient}} \\ \sf \underline{ 46 \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \sf{228 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \sf{ \underline{ - 184 \: \: \: \: \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\ \sf0445 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \underline{ \sf - 414 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \sf{031 \red{←Remainder}} \\ [/tex]

[tex] \therefore \: \sf{Quotient = 149 \: and \: Remainder \: = 31} \\ [/tex]

[tex] \sf{Now,} \\ [/tex]

[tex] \sf{Divisor \times Quotient + Remainder } \\ [/tex]

[tex] \sf = 46 \times 149 + 31 \\ [/tex]

[tex] \sf = 6854 + 31 \\ [/tex]

[tex] \sf{ = 6885} \\ [/tex]

[tex] \sf = \red{ Dividend}. \\ [/tex]