what's newtons second law​

Explanation:

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The distance in light years from earth to Star is 7.1 Light Years.

We have the distance from earth to a star is 6.8 × 10¹³ kilometers.

We have to convert it into light years.

Light year is a unit of astronomical distance equivalent to the distance that light travels in one year.

1 Light year = 9.4607 × 10¹³ km

According to the question, we have -

Distance from Earth to Star = 6.8 × 10¹³ km.

Now -

1 Light year = 9.4607 × 10¹² km

or

9.4607 × 10¹²km = 1 Light years

1 km = [tex]$\frac{1}{9.4607\times 10^{12} }[/tex] Light years

Therefore -

6.8 × [tex]10^{13}[/tex] km = [tex]$\frac{6.8\times 10^{13} }{9.4607\times 10^{12} }[/tex] = 0.71 x 10 = 7. 1 Light Years.

Therefore, the distance in light years from earth to Star is 7.1 Light Years.

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Explanation:

356 species of diff turtles

The time taken by the croissant before it strike on the head is 5.4 s

Lets assume the height of the man is 1.3 m

Given height of the Eiffel Tower is 144.3 m

So the distance croissant travel before it hits the man on the head

= 144.3 - 1.3 m

= 143 m

According to the Second Equation of Motion which relates distance with the acceleration and time, we can say that

[tex]S = ut + \frac{1}{2} a t^{2}[/tex]

here u = 0

a = g = 9.81 m/s²

S = 143 m

therefore [tex]S = \frac{1}{2} gt^{2}[/tex]

[tex]t = \sqrt{\frac{2S}{g} }[/tex]

[tex]t = \sqrt{\frac{2 * 143}{9.81} }[/tex]

[tex]t = \sqrt{29.154}[/tex]

t = 5.4 s

Therefore, if the air resistance is neglected the croissant will drop 5.4 s before it tagged the man on his head.

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Answer:

Seems like you desperately need answers

The potential energy change is 1.47 KJ or 1470 J. The weight of the person is given 60 kg. Thus vertical height of the person is 2.5 m.

Potential energy is a form of energy, generated by virtue of the position of an object in the gravitational field. Potential energy depends on the mass, acceleration and height from the ground at which the object is placed/

Thus, P = Mgh. Where m is mass, h is height and g be the acceleration due to gravity, which is equal to 9.8 m/s². It is given that the mass of the person is 60 kg.

The potential energy in the gravitational field is 1.47 KJ or 1470 J, now the height h of the person can be calculated as follows:

h = p/mg.

  = 1470 J/ (60 Kg × 9.8 m/s²)

  = 2.5 m

Therefore, the vertical height of the hanging person is 2.5 m.

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Answer:

B

Explanation:

Answer:

condensation, precipitation, evaporation, transpiration

Explanation:

condensation is when gas condenses into liquid, precipitation is when water comes from the sky like in rain, evaporation is when water is converted from liquid to gas, transpiration is when water is evaporated from leaves.

The ratio of the wavelength in air of the sound emitted by this vibrating string and the wavelength of the wave on the string is 2:1.

f = n/2L(√T/μ)

where;

μ = 0.0048 kg / 2 m = 0.0024 kg/m

f = 2/(2 x 2) (√48/0.0024)

f = (¹/₂)(√20,000)

f = (¹/₂)(141.42)

f = 70.71 Hz

v = √T/μ

v = (√48/0.0024)

v = 141.42 m/s

λ = v/f

λ = (141.42) / (70.71)

λ = 2 m

Speed of sound in air, v = 332 m/s

λ = v/f

λ = 332 / 70.71

λ = 4.7 m

Ratio of the wavelengths = 4.7 m / 2m = 2.3/1 ≈ 2 : 1

Thus, the ratio of the wavelength in air of the sound emitted by this vibrating string and the wavelength of the wave on the string is 2:1.

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Answer:

c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

[tex] 90 = u*5.55 + \frac {1}{2}*(-9.8)*5.55^{2}[/tex]

[tex] 90 = u5.55 - 4.9*30.8025[/tex]

[tex] 90 = u5.55 - 150.93225[/tex]

Rearranging the equation, we have;

[tex] u5.55 = 90 + 150.93225[/tex]

[tex] u5.55 = 240.93225[/tex]

[tex] u = \frac {240.93225}{5.55}[/tex]

Initial velocity, u = 43.41 ≈ 41 m/s

Answer:

The range is 15.15 m and the time in the air is 1.01 s

Explanation:

Horizontal Motion

When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

To calculate the time the object takes to hit the ground, we use the equation below:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:

[tex]\displaystyle d=15\cdot\sqrt{\frac {2*5}{9.8}}=15*1.01[/tex]

d = 15.15 m

The time in the air is:

[tex]\displaystyle t=\sqrt{\frac{2*5}{9.8}}[/tex]

t = 1.01 s

The range is 15.15 m and the time in the air is 1.01 s

Answer:

it most likly right I'm not 100% sure

Answer:

there yah go that's the answer

Answer:

can i have the toy car after your done asking questions with it

Explanation:

Answer:

  90°

Explanation:

The intensity of the transmitted light is proportional to the square of the cosine of the angle between polarizer axes. That cosine is zero when the angle is 90°.

By relativistic energy, the proton speed is 0.024c.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

The kinetic energy is

KE = E - Eo

From the question above, we know that :

mp = 1.6 x 10¯²⁷ kg

me = 9.1 x 10¯³¹ kg

c = 3 x 10⁸ m/s

ve = 0.75c

Find the rest energy of electron

Eo = me . c²

Eo = 9.1 x 10¯³¹ . (3 x 10⁸)²

Eo = 8.19 x 10¯¹⁴ joule

Eo = 8.19 x 10¯¹⁴ / (1.6 x 10¯¹⁹) eV

Eo = 511875 eV

Determine the total energy of electron

E = Eo / √(1 - ve²/c²)

E = 511875 / √(1 - (0.75c)²/c²)

E = 511875 / 0.66

E = 773882.26 eV

Calculate the kinetic energy of electron

KE = E - Eo

KE = 773882.26 - 511875

KE = 262007.26 eV

Find the rest energy of proton

Eo = mp . c²

Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²

Eo = 1.44 x 10¯¹⁰ joule

Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV

Eo = 900000000 eV

Determine the total energy of proton

E = KE + Eo

E = 262007.26 + 900000000

E = 900262007.3 eV

Find the speed of proton

900262007.3 = 900000000 / √(1 - v²/c²)

√(1 - v²/c²) = 0.9997

1 - v²/c² = 0.9994

v²/c² = 1 - 0.9994

v²/c² = 5.82 x 10¯⁴

v² = 5.82 x 10¯⁴ c²

v = 0.024c

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Answer:

Explanation:

A. Encouragement

Answer:

Taking the value of acceleration due to gravity as 9.8 m/s^2, the object fell for about 122.5 metres.

The free body that shows the ball falling at terminal velocity is B. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.

It should be noted that at terminal velocity, the ball will stop accelerating and the net force on the ball will be zero.

In this case, for the net force to be zero, equal, their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂

Since F₁ = 20 N, then F₂ = -F₁ = -20 N

Therefore, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.

Therefore, the correct option is B.

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A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Which free body diagram shows the ball falling at terminal velocity? A free body diagram with one force pointing downward labeled F Subscript g Baseline 20 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N. A free body diagram with 2 forces. The first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 5 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 30 N.

Answer:

O electric potential

Explanation:

Answer:

[tex]electric \: potential[/tex]

Explanation:

[tex]hope \: helps \\ and \: brainliest \: if \: helped[/tex]

Answer:

best answer would be a

Explanation:

d is just a law

c is just the start of a paragraph

and b would be a revision or addtion to the already amendments

Answer:

Radiation

Explanation:

The form of heat that does not require matter or particles to happen is known as radiation.

The weight as measured on the bathroom scale is the force due to gravity. The correct option is b.

The weight of an object is the force acting on it due to gravity in science and engineering.

Weight is defined as a vector quantity in some standard textbooks, as the gravitational force acting on the object. Others define weight as a scalar quantity, the magnitude of gravity.

This is frequently expressed in the formula W = mg, where W is the weight, m is the object's mass, and g is the gravitational acceleration.

Bathroom scales for home use show your weight on a dial or a digital screen. These scales weigh you in one of two ways: mechanically, with springs, or electronically, with circuits that bend under weight, changing the current flowing through them.

Thus, the correct option is b.

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Answer:

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

Explanation:

Supongamos que el gas se comporta idealmente y que el proceso es isotérmico y adiabático. El trabajo efectuado por el gas en el proceso equivale al área bajo la curva de la gráfica PV. Puesto que es una línea recta y que tanto la presión como el volumen son variables positivas, tenemos que esa área es la suma del rectángulo inferior (límite inferior de la presión) y el triángulo superior (entre los límites inferior y superior de la presión). Es decir:

[tex]W = P_{min}\cdot (V_{2}-V_{1})+\frac{1}{2}\cdot (P_{max}-P_{min})\cdot (V_{2}-V_{1})[/tex] (1)

Donde:

[tex]W[/tex] - Trabajo de frontera ejercido por el gas, medida en joules.

[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Volúmenes del gas antes y después de la expansión, medidas en metros cúbicos.

[tex]P_{min}[/tex] - Límite inferior de la presión del gas, medida en pascales.

[tex]P_{max}[/tex] - Límite superior de la presión del gas, medida en pascales.

Si sabemos que [tex]V_{1} = 0.06\,m^{3}[/tex], [tex]V_{2} = 0.13\,m^{3}[/tex], [tex]P_{min} = 125,432\,Pa[/tex] y [tex]P_{max} = 168,793\,Pa[/tex], entonces el trabajo de frontera ejercido por el gas es:

[tex]W = (125,432\,Pa)\cdot (0.13\,m^{3}-0.06\,m^{3})+\frac{1}{2}\cdot (168,793\,m-125,432\,m) \cdot (0.13\,m^{3}-0.06\,m^{3})[/tex]

[tex]W = 10,297.875\,J[/tex]

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

The electric field cannot and must not be of uniform magnitude if the volume is filled with an insulating material carrying charge described by a volume charge density

Consider a gaussian surface in the shape of a rectangular box with two faces perpendicular to the direction of the field. Also, assuming this surface has a volume charge density that fills it up, it would therefore contain some charge. The net flow out of this box is nonzero. The field must be stronger on one side than the other. The field's magnitude cannot be uniform. Because the field’s magnitude cannot be uniform, therefore it is also impossible for it to be mandatorily uniform. A uniform magnitude thus defies gaussian postulate.

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Answer:

540m/s

Explanation:

Given parameters:

Frequency of the wave = 18000Hz

Wavelength of the wave = 0.03m

Unknown:

How fast is the wave traveling = ?

Solution:

How fast the wave is traveling is a measure of the speed of the wave;

     Speed of wave  = frequency x wavelength

Now insert the given parameters and solve;

   Speed of wave  = 18000 x   0.03  = 540m/s

Answer:

whats the question???

Answer:

125m

Explanation:

25m/s x 5 = 125

Answer:

15000kgm/s

Explanation:

Given parameters:

Speed of the car  = 12m/s

Mass of car and passengers = 1250Kg

Unknown:

Momentum of the car  = ?

Solution:

Momentum is the quantity of motion a body posses;

  Momentum  = mass x velocity

Now insert the given parameters and solve;

  Momentum  = 12 x 1250  = 15000kgm/s