Whats 4/5 X 3/8?
I am super confused!!

Answer:

whats the _?

Nvm you factorise the y(2x_3)

In the circle the measure of the angle is given as 31°

The measure of a particular arc can be computed by splitting its length (s) up, and then dividing it by the radius of the circle (r).

The outcome is measured in radians, but this can be converted to degrees too - just multiply it with 180 and divide it all by pi (3.14).

From the figure we have

25 + 37 = 62

62 / 2

= 31 degrees

Hence the calculated measure of Y is given as 31 degrees

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Your friend would take 11.6 hours to clean the gutters when working alone.

We have,

A rate is a ratio that is used for comparing two different kinds of quantities which have different units. A rate of change is a rate that describes how one quantity changes in relation to another quantity.

Here, we have

Given: You can clean the gutters of your house in 6 hours working together you and your friend can clean the gutters in 3.5 hours let x be the time in hours.

We have to determine an equation to find how long your friend would take to clean the gutters when working alone.

Your Work rate = 1/5

Your and your friend's work rate = 1/3.5

Your friend's rate = 1/3.5 - 1/5 = 3/35

t = 1/(3/35) = 35/3 = 11.6hours

Hence, your friend would take 11.6 hours to clean the gutters when working alone.

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The difference was negative, indicating that the sequence is monotonic and decreasing.

To determine if a sequence is monotonic, we need to look at whether it is increasing or decreasing. In this case, we are considering the sequence 6−8n. The difference test involves subtracting one term from the next to see if the result is positive, negative or zero. If the result is positive, then the sequence is decreasing. If it is negative, then the sequence is increasing. If it is zero, then the sequence is constant.

In this case, we apply the difference test by subtracting sn from sn+1 to get (6-8(n+1)) - (6-8n) = -8. Since this result is negative, we can conclude that the sequence is decreasing. Therefore, we can say that the sequence 6−8n is monotonic decreasing.

In summary, a difference test is a useful tool for determining if a sequence is monotonic. By calculating the difference between consecutive terms, we can tell whether the sequence is increasing, decreasing, or constant. In this case, the difference was negative, indicating that the sequence is monotonic decreasing.

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Using the formula P(A?B) = P(A) + P(B) - P(A and B), we can find the probability of both A and B:

P(A and B) = P(A) + P(B) - P(A?B) = 0.50 + 0.45 - 0.80 = 0.15

Using the formula P(A|B) = P(A and B) / P(B), we can find the conditional probability of A given B:

P(A|B) = P(A and B) / P(B) = 0.20 / 0.40 = 0.5

To check if A and B are independent, we need to see if P(A|B) = P(A).

P(A) = 0.30

P(A|B) = 0.50

Since P(A|B) is not equal to P(A), A and B are not independent.

The probability of at least one foul-up occurring can be found using the formula:

P(at least one foul-up) = 1 - P(no foul-up)

We can find P(no foul-up) by using the fact that A, B, and C are independent events:

P(no foul-up) = P(not A) * P(not B) * P(not C)

= (1 - 0.02) * (1 - 0.01) * (1 - 0.04)

= 0.9304

Therefore,

P(at least one foul-up) = 1 - P(no foul-up)

= 1 - 0.9304

= 0.0696

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To solve this problem, we can use the concept of combinations. We want to select 4 leaders from a group of 30 students, so the total number of ways to select 4 leaders is:

30C4 = (30*29*28*27)/(4*3*2*1) = 27,405

Now, let's consider the number of ways to select 4 leaders where no girls are selected. Since there are 16 girls in the class, we must select all 4 leaders from the group of 14 boys. The number of ways to do this is:

14C4 = (14*13*12*11)/(4*3*2*1) = 10,626

Therefore, the number of ways to select 4 leaders where at least one girl is selected is:

27,405 - 10,626 = 16,779

So there are 16,779 ways to select the 4 leaders so that at least one girl is selected.

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According to unitary method, Marques made 2 three-point shots and 6 free throws in the game.

Let's say Marques made x three-point shots and y free throws. Since a three-point shot is worth three points and a free throw is worth one point, we can write two equations to represent the total number of points scored and the total number of shots made:

3x + y = 12 (equation 1)

x + y = 8 (equation 2)

We can now use the unitary method to solve for x and y. We want to find the value of one three-point shot, so we can rearrange equation 1 to get:

3x = 12 - y

x = (12 - y) / 3

Similarly, we want to find the value of one free throw, so we can rearrange equation 2 to get:

y = 8 - x

We can substitute the second equation into the first equation to get:

3x = 12 - (8 - x)

3x = 4 + x

2x = 4

x = 2

Now that we know that Marques made 2 three-point shots, we can substitute this value into equation 2 to get:

y = 8 - x

y = 8 - 2

y = 6

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The value of angle c is 86.

We have,

a = 68

b = 26

We are assuming that in the triangle there are three angles:

a, b, and c

Now,

The sum of the angles in the triangle is 180.

So,

a + b + c = 180

68 + 26 + c = 180

94 + c = 180

c = 180 - 94

c = 86

Thus,

The value of angle c is 86.

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The complete question.

Given that angle a = 68° and angle b = 26° in the triangle.

Find the angle c.

The iterated integral for evaluating the given expression over the region D is: ∫_{0}^{2π} ∫_{3sinθ}^{3cosθ} ∫_{0}^{10-2sinθ} z f(r,θ,z) dz r dr dθ

To set up the iterated integral for evaluating the given expression over the region D, we first need to express the limits of integration for the variables r, θ, and z in terms of the geometry of the region.

From the given information, we know that the region D is a solid right cylinder whose base is the region between the circles r = 3sinθ and r = 3cosθ, and whose top lies in the plane z = 10 - 2sinθ.

The limits of integration for z will be from the bottom of the cylinder to its top, which is from z = 0 to z = 10 - 2sinθ.

The limits of integration for r will be from the inner circle to the outer circle, which is from r = 3sinθ to r = 3cosθ.

Finally, the limits of integration for θ will be from 0 to 2π, since we need to cover the entire circular base of the cylinder.

Therefore, the iterated integral for evaluating the given expression over the region D is:

∫_{0}^{2π} ∫_{3sinθ}^{3cosθ} ∫_{0}^{10-2sinθ} z f(r,θ,z) dz r dr dθ

where f(r,θ,z) is the integrand, which is not specified in the problem statement.

Note that the order of integration can be changed, depending on the specific function f(r,θ,z) and the ease of integration.

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The dimensions of the rectangle with an area of 1,000 m² and the smallest possible perimeter are: m (smaller value) = 25 m (larger value) = 40

To find the dimensions of a rectangle with area 1,000 m2 and the smallest possible perimeter, we need to use the formula for the perimeter of a rectangle, which is P = 2(l + w), where l and w are the length and width of the rectangle, respectively.

Since the area of the rectangle is given as 1,000 m2, we can express the length in terms of the width as l = 1000/w. Substituting this into the formula for perimeter, we get: P = 2(1000/w + w).

To find the smallest possible perimeter, we need to minimize this expression by taking its derivative with respect to w and setting it equal to zero: dP/dw = -2000/w^2 + 2 = 0 Solving for w, we get: w = sqrt(1000) ≈ 31.62 m.

Substituting this value back into the expression for the perimeter, we get: P = 2(1000/sqrt(1000) + sqrt(1000)) ≈ 126.5 m.

Therefore, the dimensions of the rectangle with the smallest possible perimeter and area 1,000 m2 are: m (smaller value) = sqrt(1000) ≈ 31.62 m m (larger value) = 1000/sqrt(1000) ≈ 31.62 m Note that both values are the same, as expected from the problem statement.

To minimize the perimeter of a rectangle with a given area, the rectangle should be as close to a square as possible. The area of a rectangle is given by the formula A = length × width, where A = 1,000 m². Let's find the square root of the area: √1,000 ≈ 31.62. Since the dimensions must be whole numbers, we'll look for the nearest factors of 1,000. The closest factors are 25 and 40.

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The polygons that make up the design are octagons and squares

The polygon B is regular

Given that we have

The shape in the figure

In the figure, we can see that the composite figure is made up of

12 octagons and 6 squares

So, the shapes are octagons and squares

The polygon is a regular polygon

Because the side lengths are regular and straight

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The expressions will be equivalent only if y = 68

We know that the two expressions are equivalent, then we can write the equation:

3(x + 25) - 7 = 3x +y

Now we can solve this equation for y, we will get:

y = 3(x + 25) - 7 - 3x

Simplify the right side, we will get:

y = 3x + 75 - 7 - 3x

y = 75 - 7

y = 68

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The angular coordinate, angular velocity, and angular acceleration of the flywheel are: (a) At t = 0, θ = θ0 = 0.5 rad, ω = 0, and α = 12π²θ0 = 23.55 rad/s².

(b) At t = 0.125 s, θ = 0.267 rad, ω = 4.116 rad/s, and α = -69.08 rad/s².

The given equation for the angular displacement of the flywheel is θ=θ0e(-3πcos(4πt)). Here, θ0 = 0.5 rad. To find the angular velocity and angular acceleration, we need to differentiate θ with respect to time.

θ = θ0e(-3πcos(4πt))

ω = dθ/dt = -12π²θ0e(-3πcos(4πt))sin(4πt)

α = d²θ/dt² = -48π³θ0e(-3πcos(4πt))(cos(4πt) - 2)sin(4πt)

Substituting t = 0, we get:

(a) At t = 0, θ = θ0 = 0.5 rad, ω = dθ/dt = 0, and α = d²θ/dt² = 12π²θ0 = 23.55 rad/s².

(b) At t = 0.125 s, θ = 0.267 rad, ω = dθ/dt = 4.116 rad/s, and α = d²θ/dt² = -69.08 rad/s².

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(1)  The samples being compared should be independent of each other.

(2) The populations from which the samples are drawn should follow a normal distribution.

(3) The two samples being compared should have equal variances.

To use a two-sample f-test, three conditions must be met.

Firstly, the samples being compared should be independent of each other. Independence means that the observations in one sample do not influence or depend on the observations in the other sample. This condition is important to ensure that the variability between the samples is not confounded or biased by any relationship or dependence between the observations.

Secondly, the populations from which the samples are drawn should follow a normal distribution. The assumption of normality is required for the f-test to accurately assess the differences in means between the two groups. If the data deviates significantly from a normal distribution, alternative non-parametric tests may be more appropriate.

Finally, the two samples being compared should have equal variances. This assumption, known as the assumption of equal variances or homogeneity of variances, implies that the variability within each group is similar. Violation of this assumption can affect the accuracy of the f-test results. In cases where the variances are unequal, modified versions of the f-test, such as the Welch's t-test, can be used.

In summary, the three conditions for using a two-sample f-test are independence between samples, normality of the populations, and equality of variances. These conditions ensure that the f-test accurately evaluates the differences in means between the two groups being compared.

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For a particle in a one-dimensional box, the probability of finding the particle within a certain region can be calculated using the wave function and the probability density function.

The wave function for the lowest-energy level (ground state) in a one-dimensional box is given by:

ψ(x) = √(2/L) * sin(πx/L)

where L is the length of the box.

To find the probability of finding the particle within a region, we need to integrate the squared modulus of the wave function over that region.

Let's calculate the probability of finding the particle within 0.01 nm of the center of the box for a box of length 1 nm:

Length of the box (L) = 1 nm

Region of interest (x within 0.01 nm of the center) = [-0.005 nm, 0.005 nm]

Probability = ∫[-0.005, 0.005] |ψ(x)|^2 dx

Substituting the wave function, we have:

Probability = ∫[-0.005, 0.005] |√(2/L) * sin(πx/L)|^2 dx

           = ∫[-0.005, 0.005] (2/L) * sin^2(πx/L) dx

Evaluating this integral will give us the probability of finding the particle within the specified region.

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Answer:

7,000,000 :)

Hope this helps!

Answer:

7,000,000

Step-by-step explanation:

The probability of randomly selecting 3 plain M&M's in a row and having them all be brown is approximately 0.529%.

To calculate the probability of selecting 3 brown plain M&M's in a row, we need to first find the probability of selecting a brown M&M on the first pick, which is 13/52 (since there are 13 brown M&M's out of 52 total M&M's).

Then, for the second pick, there will be one less M&M in the bag and one less brown M&M, so the probability of selecting a brown M&M on the second pick is 12/51. Finally, for the third pick, there will be two less M&M's in the bag and two less brown M&M's, so the probability of selecting a brown M&M on the third pick is 11/50. To find the probability of all three events happening, we multiply the probabilities together:
(13/52) x (12/51) x (11/50) = 0.00529 or 0.529%

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Yes, the set S of all polynomials of the form c1 + c2x + c3x^3, with c1, c2, and c3 belonging to the real numbers (R), is a vector space. To prove this, we need to show that S satisfies the following properties:

1. Closure under addition: Given any two polynomials P1 = a1 + a2x + a3x^3 and P2 = b1 + b2x + b3x^3 in S, their sum P1 + P2 = (a1 + b1) + (a2 + b2)x + (a3 + b3)x^3 is also in S, since the coefficients are real numbers.

2. Closure under scalar multiplication: Given a polynomial P = c1 + c2x + c3x^3 in S and a scalar k ∈ R, the product kP = (kc1) + (kc2)x + (kc3)x^3 is also in S, as the coefficients are still real numbers.

3. Existence of additive identity: The zero polynomial, 0 = 0 + 0x + 0x^3, is in S, and adding it to any polynomial P in S results in P itself (P + 0 = P).

4. Existence of additive inverse: Given a polynomial P = c1 + c2x + c3x^3 in S, its additive inverse -P = (-c1) + (-c2)x + (-c3)x^3 is also in S. Adding P and -P results in the zero polynomial (P + (-P) = 0).

5. Associativity and commutativity of addition, as well as distributive properties of scalar multiplication, are inherited from the real numbers.

Thus, S is a vector space since it satisfies all the required properties.

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Vibrant Flavors has more ways by 28,907,631 ways.

The problem asks us to find the number of ways to choose 7 brownies out of 30 kinds at Rustic Tastes and the number of ways to choose 7 brownies out of 40 kinds at Vibrant Flavors.

The number of ways to choose 7 brownies out of 30 kinds at Rustic Tastes can be calculated using the formula for combinations, which is:

C(30, 7) = 30! / (7! * (30-7)!) = 5,461,512

This means that there are 5,461,512 ways to choose a box of 7 brownies from Rustic Tastes.

Similarly, the number of ways to choose 7 brownies out of 40 kinds at Vibrant Flavors is:

C(40, 7) = 40! / (7! * (40-7)!) = 34,369,143

This means that there are 34,369,143 ways to choose a box of 7 brownies from Vibrant Flavors.

Therefore, Vibrant Flavors has more ways to get a box of 7 brownies by:

34,369,143 - 5,461,512 = 28,907,631 ways.

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The dimensions of the rectangle are 14 m by 7 m, and the minimum perimeter is: P = 14 + 2(7) = 28 m.

To find the minimum perimeter and dimensions of the enclosure, we can use the formula for the area of a rectangle: A = lw, where A is the area, l is the length, and w is the width.

Let's call the length of the rectangle x, and the width y. Since the fence will only have three sides, we know that one side of the rectangle will be the river. Therefore, the perimeter of the fence will be:

P = x + 2y

We want to minimize the perimeter, so we need to minimize the expression x + 2y. To do this, we can use the fact that the area is given as 98 m^2. We can set up an equation for the area in terms of x and y:

xy = 98

Now we can solve for one of the variables in terms of the other. Let's solve for y:

y = 98/x

Substituting this expression for y into the expression for the perimeter, we get:

P = x + 2(98/x)

To minimize P, we can take the derivative with respect to x and set it equal to zero:

dP/dx = 1 - 196/x^2 = 0

Solving for x, we get:

x = 14

Substituting this value for x into the equation for y, we get:

y = 7

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The surface area of the right rectangular prism with given dimensions is equal to 207.4 square centimeters.

Surface area of the right rectangular prism

= 2 ( length × width + width × height + height × length )

In the diagram,

length of the right rectangular prism = 6.7cm

Width of the right rectangular prism = 6.0cm

Height of the right rectangular prism = 5cm

Substitute the values in the formula we get,

Surface area of the right rectangular prism

= 2 × ( 6.7 × 6 + 6 × 5 + 5 × 6.7 )

= 2 × ( 40.2 + 30 + 33.5 )

= 2 ×  103.7

= 207.4 square centimeters.

Therefore, the surface area of the prism with length 6.7 cm , width 6.0 cm and height 5cm is equal to 207.4 square centimeters.

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The price difference between buying 12 cookies individually and buying them by the dozen is $0.40

Note that from the question, the price of Cookies A is $0.20 for each cookie, so to buy 12 cookies solely, Thus Trisha would need to pay:

12 * $0.20

= $2.40

Since price of Cookies A is $2.00 per dozen, to buy 12 cookies by the dozen, Trisha will pay:

1 * $2.00

= $2.00

Hence the difference in price of buying 12 cookies solely and buying by the dozen is:

$2.40 - $2.00

= $0.40

Therefore, the price is $0.40 cheaper for Trisha to buy 12 cookies by the dozen than to buy them individually.

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Answer:

84[tex]m^{2}[/tex]

Step-by-step explanation:

Bottom:

3 x 4 = 12

Top:

3 x 4 = 12

Right side:

3 x 5 = 15

Left side:

3 x 5 = 15

Front:

4 x 5 = 20

Back:

4 x 5 = 20

Add it all up:

12 + 12 + 15 + 15 + 20 + 20 = 84 [tex]m^{2}[/tex]

Helping in the name of Jesus.

Answer:

Dividing this figure into rectangles, and then adding the areas of those rectangles:

4(24) + 4(12) + 8(8) + 16(16)

= 96 + 48 + 64 + 256 = 464 square units

The total number of social security numbers that are possible are 900,000,000.

In the social security number first digit can only fall between 1 and 9, leaving us only nine options because the first three digits cannot all be zeros. There are still 10 possibilities for each of the second and third digits because they may both still be any integer between 0 and 9.

Therefore, the total number of different social security numbers that can be formed is using the combinations,

= 9 × 10⁸

= 900,000,000

So, there are 900,000,000 different possible social security numbers.

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To find the equation of the tangent line to the curve of f at (0,1), we need to find the derivative of f at x=0. Since f(x) = 32 is a constant function, its derivative is 0. Therefore, the slope of the tangent line is 0.

Since the tangent line passes through the point (0,1), we can write its equation in the form y = mx + c, where m is the slope (which we just found to be 0) and c is the y-intercept.

So the equation of the tangent line is simply y = 1.
Since f(x) = 32 is a constant function, its derivative f'(x) will be 0 for all x values. Therefore, the slope (m) of the tangent line L at any point on the curve of f is also 0.

However, the given point (0,1) is not on the curve f(x) = 32, as f(0) = 32, not 1. So, there cannot be a tangent line L to the curve of f at (0,1).

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1) The height of the arrow after two seconds is 27.8 meters

2) The time it takes for the arrow to hit the ground after it is fired is approximately 3.27 seconds.

3) The time when the arrow is 10 meters in the air is approximately 0.63 seconds.

1) To find the height of the arrow after 2 seconds, we need to substitute t = 2 in the equation:

h(2) = -9.8(2)² + 32(2) + 3

h(2) = -39.2 + 64 + 3

h(2) = 27.8

2) To find the time it takes for the arrow to hit the ground, we need to find the value of t when h(t) = 0. This is because when the arrow hits the ground, its height is zero. So we can set h(t) = 0 and solve for t:

-9.8t² + 32t + 3 = 0

Using the quadratic formula, we get:

t = (-32 + √(32² - 4(-9.8)(3))) ÷ (2(-9.8))

t = (-32 +√(1280.4)) ÷ (-19.6)

t = 3.27

3) To find the time when the arrow is 10 meters in the air, we need to solve the equation h(t) = 10 for t:

-9.8t² + 32t + 3 = 10

-9.8t² + 32t - 7 = 0

Using the quadratic formula, we get:

t = (-32 +√(32² - 4(-9.8)(-7))) ÷ (2(-9.8))

t = (-32 + √(1033.6)) ÷ (-19.6)

t = 0.63

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The complete question is:

An archer shoots an arrow up into the air the height h(t) in meters of the arrow after t seconds is modeled by h(t) = -9.8t^2 + 32t + 3

1) What is the height of the air after two seconds?

2) How long will it take for the air to hit the ground after it is fired?

3) At what time will the arrow be 10 m in the air?

(1) The simplest polynomial function with the zeros of 2, -1, and 1 is x³ - 2x² - x + 2.

(2) The simplest polynomial function with the zeros of  0, -2, and √3 is x³ + 2√3x² - 2x² - 2√3x.

(3) The simplest polynomial function with the zeros of  2i, 1 and -2 is x³ + 2x² - 5x - 8.

The simplest polynomial function with the zeros of 2, -1, and 1 is determined as;

f(x) = (x - 2)(x + 1)(x - 1)

f(x) = (x² - x - 2)(x - 1)

f(x) = x³ - 2x² - x + 2

The simplest polynomial function with the zeros of  0, -2, and √3 is calculated as;

f(x) = x(x + 2)(x - √3)

f(x) = x³ + 2√3x² - 2x² - 2√3x

The simplest polynomial function with the zeros of  2i, 1 and -2 is calculated as;

f(x) = (x - 2i)(x + 2i)(x - 1)(x + 2)

f(x) = (x² + 4)(x - 1)(x + 2)

f(x) = x³ + 2x² - 5x - 8

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The change in angular momentum of the bolt is 11.25 kg m²/s.

Angular momentum is a measure of an object's tendency to keep rotating. It is calculated as the product of the object's moment of inertia and its angular velocity. The change in angular momentum is given by the torque applied to the object over a certain time interval. In this case, 45 Nm of torque is applied to a large bolt in 0.25s, and we need to find the change in angular momentum of the bolt.

To find the change in angular momentum, we need to first calculate the moment of inertia of the bolt. This depends on the shape and size of the bolt. Once we have the moment of inertia, we can use the formula:

Change in angular momentum = torque x time interval

Substituting the given values, we get:

Change in angular momentum = 45 Nm x 0.25 s = 11.25 Nms

Therefore, the change in angular momentum of the bolt is 11.25 Nms. This means that the bolt's tendency to rotate has increased by this amount due to the torque applied to it.

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The expected number of visitors to  buy more than one costume is 48.

64 visitors purchased no costume,

376 purchased exactly one costume.

The number of visitors who purchased more than one costume is 47 .visitors

Total visitors visited the website

= 64visitors + 376 visitors + 47

= 487

Out of the 487 visitors who purchased at least one costume, 376 purchased exactly one costume.

To estimate how many visitors would buy more than one costume out of the expected 500 visitors,

Use the concept of proportions,

47 visitors / 487 visitors = x visitors / 500 visitors

Cross-multiplying, we get,

⇒x visitors = 500 visitors ×  47 visitors / 487 visitors

Simplifying this expression, we get,

⇒ x visitors = 48.2546 visitors

⇒ x visitors ≈ 48 visitors (Rounding to the nearest whole number)

Therefore, the expected number of about 48 visitors to buy more than one costume out of the 500 expected visitors.

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