What’s (3 , 1)reflected over the x-axis

Answer:

x + 3x = 1172, where x is the cost of the coffee table and 3x equals the cost of the couch.  

4x = 1172  

x = 293  

thus, 3x = 293

293 x 3= 879

The couch is $879 and the coffee table is $293

Answer:

Step-by-step explanation: reduce mean divide so 400 divided by 4 =28

Answer:

[tex]x = 4 \sqrt{3} [/tex]

Step-by-step explanation:

[tex] \frac{8}{2} = 4 \\ 4 \times \sqrt{3} = 4 \sqrt{3} [/tex]

Answer: 58 i think

Step-by-step explanation: i guess you have to add sorry if it wrong

The value of the expression 8x² + 6x - 8 below when x=2 is 36.

The expression can be evaluated by following the steps below:

8x² + 6x - 8 in x = 2 means that the variable x will be replaced by the given number which is 2.

8*2² + 6*2 - 8

8*4 + 12 - 8

32 + 16 - 8 = 36

This therefore means that when x= 2 in 8x² + 6x - 8 , the value gotten will be 36.

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Answer:

-6

Step-by-step explanation:

You can solve all math problems via  Photo math application, you can download it from the store for free, it is easy to write the question via the camera and quickly display the final result with the solution steps.

Answer:

The volume is 384 cm^2.

Step-by-step explanation:

The equation for a pyramid is the base area times the height divided by 3, so [tex]a^2h/3[/tex]. In this case, we know the side length but we do not know the height. We can use the Pythagorean Theorem to get:

6^2 + b^2 = 10^2

36 + b^2 = 100

b^2 = 64

b = 8

Therefore, our height is 8. Plug this into the equation to get:

12^2 (8) / 3

144 (8) / 3

1152 / 3

384

Therefore , R(N) = 100 + 400 (N+1)(2N+1) + 800 x N2 N3 and area are the formulas for R(N) for the function f(x) = (5x)2 on [1, 5] and the function f(x) = (5x)2 in terms of N. R(N) = 767(approx) (approx).

Each x value in the domain has one but only one y value range, according to the rule of a function. Definition. If there is only one and only one value of x variable such that f(x) = y, then the function is one-to-one.

Here,

In the given question, we have to find a formula for R(N) for the function f(x) =(5x)^2 on [1, 5] in terms of N.

The given function is f(x)=(5x)^2 on [1, 5].

Ax = (5-1)/N

Ax = 4/N

X = 1+iAx

X = 1+i4/N

f(x) = 25X^2

f(x) = 25(1+i4/N)^2

f(x) = 25(1+i8/N+16/N^2 i^{2})

R(N) = 1ƒ(X) Ax

Now putting the value of f(x) and Ax

R(N)==1 [25 (1+ &i + 16i2)]

R(N) = 1001 (1 +Ni + 16i2)

N100 (1+i+12)N

100 (N += i +122)+16 N(N+1)(2N+1)(+1)(2N+1)

R(N)=100 (N + √2/ N(N+1) x 100

R(N) =2/6× N + 100 × 5 × N(N+1) + 100 x 2

[tex]\lim_{n \to \infty}[/tex] R(N) = 100 + 400 + 800/3

[tex]\lim_{n \to \infty}[/tex] R(N) = 766.67

[tex]\lim_{n \to \infty}[/tex] R(N) = 767(approx)

Therefore , the solution of the given problem of function comes out to be [tex]\lim_{n \to \infty}[/tex] R(N) = 767(approx).

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Answer:

A. -9/2

Step-by-step explanation:

Rate of change of y in respect to x = change in y/change in x

Using two pairs of values, say (-6, 33) and (-2, 15),

Rate of change = (15 - 33)/(-2 - (-6))

Rate of Change = -18/4

Simplify

Rate of change = -9/2

Answer:

46

Step-by-step explanation:

Therefore , the solution of the given problem of circle comes out to be Area = 154 meter square  or 49π meter square option 1 is correct.

A moving point on a plane is followed so that its distance from a specific point remains constant to produce the circular form known as a circle. The English term circle derives from the Greek word kirkos, which meaning hoop or ring. Area of circle= πr²

Here,

Given :

Diameter of circle : 14

Radius =14/2 =  7 meters

and

Using formula

Area= πr²

=> Area = π7²

=>Area = 22/7 * 7²

=> Area = 22*7

=> Area = 154 meter square or 49π meter square

Therefore , the solution of the given problem of circle comes out to be Area = 154 meter square  or 49π meter square option 1 is correct.

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Answer: A the first one 49π square meters

Answer:

d

Step-by-step explanation:

so the first part is multiplication and the second part is division bc it's a fraction hope this helps <3

The density in terms of  pounds per cubic foot is 101.2 pounds/ft³

The unitary method is a method in which you find the value of a unit and then the value of a required number of units.

Given here; 6900 g for every 4.05 quarts thus expressing in terms of pounds per cubic foot we get = 15.22/0.15039

                                                  = 101.2

Hence, The density in terms of  pounds per cubic foot is 101.2 pounds/ft³

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Answer:

Given that we know the base of the parabola is at the origin, and that it is symetrical about the y-axis, we can simplify the equation to

y=ax2=14px2" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">y=ax2=14px2y=ax2=14px2

which corresponds to the given equation a=14p" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">a=14pa=14p given above.

Since y=6" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">y=6y=6 when x=2" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">x=2x=2,

6=a(2)2=4a" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">6=a(2)2=4a6=a(2)2=4a

and

a=32" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">a=32a=32

Thus we have

32=14p12p=2p=16" role="presentation" style="display: table-cell !important; line-height: 0; text-indent: 0px; text-align: center; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 3.337em; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; width: 10000em; position: relative;">32=14p12p=2p=1632=14p12p=2p=16

So, the receiver should be placed 16" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">1616 of a foot, or 2 inches, above the base.

Answer:

0.29

Step-by-step explanation:

Total number of students = 35

Number of students who got B = 10

Probability that a student earns grade B :

Probability = required outcome / Total possible outcomes

P(grade B) = 10 / 35 = 0.2875

= 0.29

Answer:

D is correct option 840 meters

Step-by-step explanation:

S=vt

S= (24)(35)

S= 840 meters

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{6}-\stackrel{y1}{7}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{2}}} \implies \cfrac{ -1 }{ 2 } \implies - \cfrac{ 1 }{ 2 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{- \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{2}) \\\\\\ y-7=- \cfrac{ 1 }{ 2 }x+1\implies {\Large \begin{array}{llll} y=- \cfrac{ 1 }{ 2 }x+8 \end{array}}[/tex]

Answer:

a= 5

b= 9

c= -7

d= 12

Step-by-step explanation:

The number of atoms that are there in 400 grams of hydrogen will be 2.408 × 10^26.

Scientific notation is a method of displaying very large or very small numbers in a more simplified format. We know that entire numbers can be extended indefinitely, but such large numbers cannot be written on a piece of paper.

In this case, there are 6.02 × 10^23 atoms in 1 gram of hydrogen.

The number of atoms that are there in 400 grams of hydrogen will be:

= 6.02 × 10^23 × 400

= 2408 × 10^23

= 2.408 × 10^3 × 10^23

= 2.408 × 10^26

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Therefore , (1, 3), (2, 5), (3, 7) (4, 9) and (1, 3), (2, 3), (3, 3) (4, 3) are the relations that represent a function.  

According to a function's rule, every x value in the domain has one and only one range of y values. Definition. A one-to-one function exists when there is just one and only one value of x such that f(x) = y.

Here,

The relationship is (1, 3), (2, 5), and (2, 7) (4, 9)

Given that 2 is repeated, the connection is not a function.

The relationship is (1, 3), (2, 5), and (3, 7) (4, 9)

Since there are no repeating numbers, the relation is a function.

The relationship stated is (1, 3), (1, 5), and (1, 7). (4, 9)

The relationship is not a 1 repeated function.

The relationships are (1, 3), (2, 3), and (3, 3). (4, 3)

Since there are no repeating numbers, the relation is a function.

The relationship stated is (1, 2), (2, 5), and (2, 1) (4, 5)

As 2 repeated, the relationship is not a function.

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Answer:

C. = 69.5

Step-by-step explanation:

The median or the average between 80 and 59 is 69.5

Hope this helps! :)

Answer:

19,29,76

Step-by-step explanation:

x=first number

x+10=second number

4x=third number

add three numbers to equal 124.

x+(x+10)+4x=124

6x=114

x=19 first number

x+10 0r

19+10=29 second number

4x or

4(19)=76 third number

19+29+76=124

124=124

Answer:

Step-by-step explanation:

The area of the flooring:

Cost of flooring:

Answer:

Step-by-step explanation:

3.14x (3)^2

28.3ft

Answer:

The area of the circle is 28.3 [tex]ft^2[/tex].

Step-by-step explanation:

The formula to find the area of a circle is [tex]\pi r^2[/tex], where [tex]r[/tex] represents the radius of the circle. In this case, the area would be [tex]3.14 * 3^2 = 3.14 * 9 = 28.26[/tex] ≈ 28.3 [tex]ft^2[/tex].

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Please find the table in the attached file.

mean and standard deviation difference: [tex]\bar{d}=\frac{\Sigma d}{n} =\frac{-4-6-.......-4-4}{8}=-4.125 \\\\S_d=\sqrt{\frac{\Sigma (d-\bar{d})^2 }{n-1}}=\sqrt{\frac{(-4 + 4.125)^2 +.......+(-4 +4.125)^2 }{8-1}}= 1.246[/tex]

For point a:

hypotheses are:

[tex]H_0 : \mu_d \geq -3\\\\H_a : \mu_d < -3\\\\[/tex]

degree of freedom:

[tex]df=n-1=8-1=7[/tex]

 From t table, at[tex]\alpha = 0.05[/tex], reject null hypothesis if [tex]t <-1.895[/tex].

test statistic:  

[tex]t=\frac{\bar{d}-\mu_d }{\frac{s_d}{\sqrt{d}}}=\frac{ -4.125- (-3)}{\frac{1.246}{ \sqrt{8}}} =-2.55[/tex]

because the [tex]t=-2.553 <-1.895[/tex], removing the null assumption. Data promotes a food product manufacturer's assertion with a likelihood of Type 1 error of 0.05.

For point b:

From t table, at [tex]\alpha =0.01[/tex], removing the null hypothesis if [tex]t<-2.998[/tex].

because [tex]t=-2.553 >-2.908[/tex], fail to removing the null hypothesis.  

The data do not help the foodstuff producer's point with the likelihood of a .01-type mistake.

For point c:

Hypotheses are:

[tex]H_0: \mu_d \geq -5\\\\H_a: \mu_d < -5[/tex]

Degree of freedom:

[tex]df=n-1=8-1=7[/tex]

From t table, at [tex]\alpha =0.05[/tex], removing the null hypothesis if [tex]t <-1.895[/tex].

test statistic:  [tex]t=\frac{\bar{d}-\mu_d}{\frac{s_d}{\sqrt{n}}} =\frac{-4.125-(-5)}{\frac{1.246}{\sqrt{8}}}=1.986[/tex]

Since [tex]t-1.986 >-1.895[/tex], The null hypothesis fails to reject. The results do not support the packaged food producer's claim with a Type 1 error probability of 0,05.

From t table, at[tex]\alpha= 0.01[/tex], reject null hypothesis if[tex]t<-2.998[/tex].

Since [tex]t=1.986>-2.998[/tex] , fail to reject null hypothesis.  

Data do not support the claim of the producer of the dietary product with the probability of Type 1 error of .01.

No Alisa do not have enough fence.

The perimeter of an object is given by adding the side lengths of the object.

Given that Alisa needs 4.65 feet of fencing to complete the fence she is building. She has a piece of fencing that is 4 ft long.

We need to determine whether she have enough fencing or not,

Since we know that the fencing can be considered as perimeter of the building,

So, if she only has 4 ft long fence, she cannot cover a 4.65 ft long fence.

Hence Alisa do not have enough fence.

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