what will be possible title in brake system?

The speed of the block when it reaches the bottom of the board would be 3.19 m/s.

Let's start by finding the height of the board when the block starts to slide. The maximum angle α0 at which the block will remain stationary on the board is given by:

μs = tan(α0)

Solving for α0, we get:

α0 = tan^-1(μs) = tan^-1(0.550) = 29.59 degrees

The height of the board when the block starts to slide is given by:

h = 4.00 m sin(α0)

h = 4.00 m sin(29.59 degrees)

h = 2.09 m

Now let's find the work done by friction. The friction force is given by:

f= μk * N

where N is the normal force acting on the block. The normal force is equal in magnitude and opposite in direction to the component of the gravitational force acting perpendicular to the board, which is given by:

N = mg cos(α)

where m is the mass of the block, g is the acceleration due to gravity, and α is the angle of the board. The kinetic friction force does negative work, which is equal to:

Wf = -f * d

where d is the distance the block travels down the board. The work done by gravity is equal to the change in potential energy, which is given by:

Wg = mgh

where h is the height of the board. At the bottom of the board, all of the potential energy has been converted to kinetic energy, so we have:

1/2 * m * v^2 = mgh - f * d

Solving for v, we get:

v = sqrt(2gh - 2μk(N/m) * d)

We can now substitute the values we have found:

h = 2.09 m

μk = 0.400

N = mg cos(α0) = mg cos(29.59 degrees)

d = 4.00 m

Substituting these values and solving for v, we get:

v = sqrt(2gh - 2μk(N/m) * d)

v = sqrt(2 * 9.81 m/s^2 * 2.09 m - 2 * 0.400 * (m * g * cos(29.59 degrees)/m) * 4.00 m)

v = 3.19 m/s

Therefore, the speed of the block when it reaches the bottom of the board is 3.19 m/s.

Learn more about speed in https://brainly.com/question/28224010

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6 feet 4 inches

6 feet 4 inchesThe tallest U.S. president was Abraham Lincoln at 6 feet 4 inches (193 centimeters)

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