What type of system is represented by the image below?


Group of answer choices

Isolated system

Closed system

Open system

Semi-open system

The maximum displacement angle observed in the experiment can be calculated based on the acceleration of the cart and the value of g.

What is Displacement Angle?

Displacement angle is the angle through which an object has moved or rotated with respect to a reference point or position. In the case of a pendulum, it refers to the maximum angle the pendulum swings away from its vertical position before reversing direction due to the force of gravity.

The maximum displacement angle observed in the experiment depends on the initial velocity of the pendulum and the acceleration of the cart. When the cart is pushed with maximum acceleration a, the pendulum initially experiences a force due to its inertia, which causes it to move at an angle. The angle of displacement is directly proportional to the initial velocity of the pendulum.

Based on the theory of pendulums, the maximum angle of displacement is given by:

θ = arcsin(a/g)

Where θ is the maximum angle of displacement, a is the acceleration of the cart, and g is the acceleration due to gravity (approximately 9.81 m/[tex]s^{2}[/tex]).

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The star has a luminosity that is approximately 195.8 times that of the Sun.

The luminosity of a star is directly proportional to its mass to the power of approximately 3.5. This relationship is known as the mass-luminosity relation. Using this relation, we can calculate the luminosity of the star relative to the Sun as follows:

L_star/L_sun = (M_star/M_sun)^3.5

where L_star is the luminosity of the star, M_star is the mass of the star, L_sun is the luminosity of the Sun, and M_sun is the mass of the Sun.

Substituting the given values, we get:

L_star/L_sun = (6.6)^3.5

Using a calculator, we find:

L_star/L_sun = 195.8

Therefore, the star has a luminosity that is approximately 195.8 times that of the Sun.

What is luminosity?

Luminosity is a measure of the total amount of energy emitted by a star, galaxy, or other astronomical object per unit time. It is a fundamental property of an astronomical object and is related to its size, temperature, and composition.

Luminosity is often compared to the concept of brightness, which is a measure of the amount of light received by an observer from an astronomical object.

Luminosity is typically measured in units of watts (W) or solar luminosities (L☉), where one solar luminosity is equal to the luminosity of the Sun (about 3.828 x 10^26 W).

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Answer:

Transistors and Their Uses

Transistors are electronic devices that are used to amplify and switch electronic signals. They are widely used in various applications, from small electronic devices to large industrial systems. Here are some common uses of transistors:

1. Amplification: Transistors are commonly used in audio amplifiers, where they amplify weak audio signals to produce a louder sound. They are also used in radio and television receivers to amplify the weak signals received from antennas.

2. Switching: Transistors are used as switches in electronic circuits, where they can be turned on or off to control the flow of current. They are commonly used in digital circuits, where they can be used to turn on or off individual bits of data.

3. Voltage Regulation: Transistors can be used as voltage regulators, where they can be used to regulate the output voltage of a power supply. They are commonly used in electronic devices such as computers and televisions, where a stable voltage supply is required.

4. Oscillation: Transistors can be used in oscillator circuits to produce a steady periodic waveform, such as a sine wave. These circuits are commonly used in electronic devices such as radios and televisions.

5. Logic Gates: Transistors are used in logic gates, which are the building blocks of digital circuits. They can be used to implement Boolean logic functions such as AND, OR, and NOT.

6. Memory: Transistors are used in memory circuits, such as dynamic random-access memory (DRAM), where they are used to store data. DRAM is commonly used in computers as the main memory.

7. Power Control: Transistors can be used in power control circuits, where they can be used to control the amount of power delivered to a load. They are commonly used in electronic devices such as motor controllers and power supplies.

In conclusion, transistors are versatile devices that are used in a wide range of electronic applications. They can be used for amplification, switching, voltage regulation, oscillation, logic gates, memory, and power control. Transistors have revolutionized the field of electronics and have enabled the development of many modern electronic devices.

Answer:

they used to transition of current and flow of them like amplifier

The option B. 2340.1 s is correct. It takes 2340.1 s  for the sound to travel to your location when a huge explosion at a distance of 500 miles away can be heard.

Given the distance the sound of explosion can be heard (d) = 500miles

the temperature of the air is (T) = 20°C = 20 + 273 = 293K

1 mile = 1.6km then 500 miles = 500 * 1.6 = 800km

The time up to which the sound can be heard = t

The speed of sound at normal temperature = 331m/s

Then the speed of sound in air at 20°C is (v) = [tex]331 * \sqrt{T/273}[/tex]

Also time is calculated as distance per unit speed such that t = d/v

Then, t =[tex]800km/331 * \sqrt{T/273} = 800 * 10^3/331 * \sqrt{293/273} = 2413/1.03[/tex]

t =  2340.1 s

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Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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The correct answer is 45 J, because in an isolated system, the total amount of energy remains constant.

The energy stored in the system before the slingshot went off and launched the rock must be equal to the energy stored in the system after the rock is launched, which is 45 J. Therefore, the correct answer is 45 J.

What is an isolated system?

An isolated system is a physical system that does not exchange any matter or energy with its surroundings. In other words, an isolated system is a closed system that does not allow the transfer of mass or energy across its boundary.

In an isolated system, the total amount of energy is constant. This means that energy cannot be created or destroyed, but it can be converted from one form to another. For example, if an isolated system contains a certain amount of thermal energy, this energy can be transferred from one part of the system to another, but the total amount of thermal energy in the system remains constant.

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Answer: if the predator sees the light bugs easier than the dark bugs then the bright bug will most likely go extinct

Explanation:

The final velocities of the two blocks after the collision are:

Block 1: 2.32 m/s to the right

Block 2: 2.43 m/s to the left

We can use the conservation of momentum and the conservation of kinetic energy to solve this problem.

Since the collision is perfectly elastic, the total kinetic energy before and after the collision should be the same.

Let's first calculate the momentum of each block before the collision:

Momentum of block 1 = mass x velocity = 4.0 kg x 5.5 m/s = 22.0 kg m/s to the right

Momentum of block 2 = mass x velocity = 4.5 kg x (-2.5 m/s) = -11.25 kg m/s to the left

The total momentum before the collision is:

P_before = 22.0 kg m/s - 11.25 kg m/s = 10.75 kg m/s to the right

Now, let's use the conservation of momentum to find the velocity of the blocks after the collision. Since the momentum is conserved, the total momentum after the collision should also be 10.75 kg m/s to the right.

Let the final velocity of block 1 be v1 and the final velocity of block 2 be v2. Then we have:

Momentum of block 1 after collision = mass x velocity = 4.0 kg x v1

Momentum of block 2 after collision = mass x velocity = 4.5 kg x v2

Total momentum after collision = 4.0 kg x v1 + 4.5 kg x v2 = 10.75 kg m/s to the right

We also know that the total kinetic energy before and after the collision should be the same. The kinetic energy of a block is given by:

Kinetic energy = 0.5 x mass x velocity^2

The total kinetic energy before the collision is:

KE_before = 0.5 x 4.0 kg x (5.5 m/s)^2 + 0.5 x 4.5 kg x (-2.5 m/s)^2 = 30.625 J

The total kinetic energy after the collision is:

KE_after = 0.5 x 4.0 kg x v1^2 + 0.5 x 4.5 kg x v2^2

Since the collision is perfectly elastic, we know that the kinetic energy is conserved, so KE_before = KE_after.

Therefore, we can set these two equations equal to each other and solve for v1:

0.5 x 4.0 kg x (5.5 m/s)^2 + 0.5 x 4.5 kg x (-2.5 m/s)^2 = 0.5 x 4.0 kg x v1^2 + 0.5 x 4.5 kg x v2^2

Simplifying this equation gives:

15.875 = 2.0 v1^2 + 5.0625

10.8125 = 2.0 v1^2

v1^2 = 5.40625

v1 = ±2.32 m/s

Since block 1 was originally moving to the right, we can discard the negative solution and conclude that the final velocity of block 1 after the collision is:

v1 = 2.32 m/s to the right

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The equivalent resistance of 5 resistors in parallel, each having a value of "R" is R/5.

A parallel circuit is an electrical circuit that has two or more paths for the current to flow through. In a parallel circuit, the components are connected in such a way that the voltage across each component is the same, while the current through each component may be different

The given circuit has 5 resistors arranged parallel to each other.

The equivalent resistance of 5 resistors in parallel, each having a value of "R" is given by:

1/R_eq = 1/R + 1/R + 1/R + 1/R + 1/R

Simplifying the equation, we get:

1/R_eq = 5/R

Multiplying both sides by R, we get:

R_eq = R/5

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Since they are not at a height above the ground where gravity can act on them, A ball thrown straight upwards and a bone on the floor both have zero gravitational potential energy.

If an object is placed at a height above (or below) the zero height, it has gravitational potential energy. If an object is not in its equilibrium position on an elastic material, it has elastic potential energy.

The term gravitational potential energy refers to the energy that an item stores as a result of its elevation above the Earth's surface. This energy is a result of an object being subjected to gravity. EP=mgh.

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The image formed when an object is placed at the center of the curvature of a concave mirror is real.

When an object is placed at the center of curvature (D₀ = R) of a concave mirror, the image formed is known as the real and inverted image.

The image characteristics are as follows:

Nature: Real and Inverted

The image formed by a concave mirror when an object is placed at the center of curvature is a real image, which means that the light rays actually converge at a point in front of the mirror, forming an inverted image.

Size:

The size of the image formed at the center of curvature of the concave mirror is the same as the size of the object. Therefore, the image size is equal to the object size.

Position:

The position of the image formed is at the center of curvature (C) of the concave mirror. Hence, the distance of the image from the mirror is equal to the distance of the object from the mirror, i.e., Dᵢ = D₀ = R.

Real or Virtual:

The image formed is real because the light rays converge at a point in front of the mirror, and the image can be obtained on a screen.

Magnification:

The magnification of the image formed is unity, which means that the size of the image is the same as that of the object. Hence, the magnification is equal to one.

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To determine whether the line will be active when the heater is switched on, we need to calculate the current that will flow through the circuit when the heater is in operation. We can use Ohm's law, which states that current is equal to voltage divided by resistance, or I = V/R.

The resistance of the heater can be calculated using the formula:

R = V^2/P

where V is the voltage and P is the power of the heater.

In this case, the resistance of the heater is:

R = 240^2/2.75 kW = 20.87 Ω

Using Ohm's law, we can now calculate the current that will flow through the circuit when the heater is on:

I = V/R = 240/20.87 = 11.5 A

Since the current required by the heater (11.5 A) is greater than the circuit breaker rating (10 A), the circuit breaker will trip when the heater is switched on, and the line will not be active.

When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.

The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched

We'll start by determining the spring's string constant. Specifics below:

Extension (e) = 6.0 cm

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.25 × 9.8 = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 6

Divide both sides by 6

K = 2.45 / 6

K = 0.40 N/cm

The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:

Mass (m) = 0.80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.80 × 9.8 = 7.84 N

Spring constant (K) = 0.40 N/cm

Extension (e) = ?

F = Ke

7.84 = 0.40 × e

Divide both sides by 0.40

e = 7.84 / 0.40

e = 19.6 cm

We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.

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For a vector field:

a) the streamline equation is y = Ce^(-0.5ax²+abty)

b) three streamlines include; y = e^(-0.5x²+bt), y = 2e^(-0.5x²+bt), y = 3e^(-0.5x²+bt)

c) direction of flow at points (2,3) is (3a, -2a+3bt)

a) To find the streamline equation, use the definition that the velocity vector is tangent to the streamline at every point along the streamline. Let (x,y) be a point on a streamline, then:

dx/dt = a y

dy/dt = -a x + abt

Using the chain rule:

dy/dx = (dy/dt)/(dx/dt) = (-a x + abt)/(a y)

Integrating both sides:

ln |y| = -0.5 a x² + abt y + C

where C is a constant of integration. Solving for y:

y = Ce^(-0.5ax²+abty)

This is the equation of a streamline.

b) To plot the streamlines, use the equation we derived in part (a) and choose different values of C to get different streamlines. For example, if we choose C = 1, 2, 3, then the streamlines will be:

y = e^(-0.5x²+bt), y = 2e^(-0.5x²+bt), y = 3e^(-0.5x²+bt)

c) To indicate the direction of the flow on each streamline at point (2,3), we need to evaluate the velocity vector at that point.

V = (ay,-ax + abt,0)

At point (2,3):

V = (3a, -2a+3bt, 0)

The direction of the flow is given by the direction of the velocity vector. In this case, the velocity vector points in the direction of (3a, -2a+3bt), which depends on the values of a, b, and t.

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The right answer is C. Space plays a significant role in Florida culture. Space plays a significant role in Florida culture.

The natural environment, history, diversified population, and well-liked attractions like beaches and amusement parks are some of the influences on Florida's culture.

Although Florida has benefited economically and educationally from space-related activity, focusing on this industry as a significant part of the state's culture could have negative effects. Moreover, emphasizing space-related operations could put other crucial industries, like healthcare or environmental conservation.

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Answer:

The motion of objects in regard to other objects is called relative motion.

Explanation:

Relative motion is the motion of an object in relation to another object or point. It is the description of the movement of an object with respect to a frame of reference or another object in motion. The concept of relative motion is used to describe the motion of objects in everyday life, such as the motion of a car on a highway relative to the motion of other cars or the motion of a person walking on a moving train relative to the motion of the train. The velocity and direction of an object's relative motion are determined by comparing its motion to the motion of a chosen reference point or object.

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The amount of work done as the block travels from point P to (a) point Q is 0.096J, (b) the top of the loop is 0.072J, the  potential energy when the block is (c) at point P is 0.121 J, (d) at Q is 0.024 J, (e) at top is 0.048 J

Given the mass of small block (m) = 0.019kg

The radius of loop (R) = 13cm.

The height of point P (H) = 5R = 5 *13 = 65cm

the gravitational potential energy of the block-Earth system is taken to be zero at the bottom of the loop.

We know that the potential energy is calculated as (PE) = m*g*h where g is the gravitational acceleration = [tex]9.8m/s^2[/tex]

(a) The work done by the gravitational force on the block as the block travels from point P to point Q is: W = F * d = m*g*d

the distance from point P to Q = 4R = 4 * 13 = 52cm

W =[tex](0.019 kg)*(9.8 m/s^2)*(4R) = 0.096J[/tex]

(b) The work done by the gravitational force on the block as the block travels from point P to the top of the loop is:

Here the displacement from point P to top of loop = H - 2R = 3R = 39cm

W = m*g*h = [tex](0.019 kg)*(9.8 m/s^2)*(3R) = 0.072J[/tex]

(c) The gravitational potential energy of the block-Earth system at point P is: PE = mgh = [tex](0.019 kg) * (9.8 m/s^2) * (5R) = 0.121 J[/tex]

(d) The gravitational potential energy of the block-Earth system at point Q is: PE = mgh = [tex](0.019 kg) * (9.8 m/s^2) * (R) = 0.024 J[/tex]

(e) The gravitational potential energy of the block-Earth system at the top of the loop is:

PE = mgh =[tex](0.019 kg)*(9.8 m/s^2)*(2R) = 0.048 J[/tex]

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The tension in cable B is 87.5 N, see the computation in the section below

Tension in cable A = 800sin30 = 400 N

Tension in cable B = 800cos30 = 693.33 N

Total Tension = 400 + 693.33 = 1093.33 N

Tension in cable B = 1093.33 - 800 = 293.33 N

Tension in cable B = 293.33/2 = 87.5 N

The tension in cable B, attached to an adjoining building, is 87.5 N in order to hang a sign weighing 800 N so that cable A, attached to the store, makes a 30.0° angle.

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Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

Since the helicopter is flying horizontally at a constant speed, we know that the net force acting on it must be zero.

The weight of the helicopter can be calculated as :

weight = mass x gravity

weight = 2750 kg x 9.81 m/s²

weight = 26977.5 N

Since the net force acting on the helicopter is zero, we can write:

forward force - backward force + lift force + weight = 0

Substituting the given values, we get

forward force - 7510 N + lift force + 26977.5 N = 0

Simplifying the equation, we get:

forward force + lift force = 7510 N - 26977.5 N

forward force + lift force = -19467.5 N

Since the helicopter is flying at a constant speed, we know that the forward force created by the propellers must be equal in magnitude to 7510 N. Therefore, we can write:

7510 N + lift force = -19467.5 N

Solving for the lift force, we ge:

lift force = -26977.5 N

Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

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The journey is completed at an average speed of 285.7 km/h.

10 kilometres is the distance. Time is measured in 30 minute increments. We are aware that time*speed equals distance. Thus, the formula for speed is: speed = distance/time (10/0.5) = 100/5 = 20 km/h. That is speed = distance  time. Alternatively, you can calculate the time by dividing the distance travelled by the speed.

We may divide the total distance travelled by the amount of time spent driving to determine the average speed:

Average speed = total distance/time spent driving

Total distance = 2,000 km

Time spent driving = 7 hours

Average speed = 2,000 km / 7 hours

Average speed = 285.7 km/hour

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a) The spanner was dropped from a height of 24.2 meters. b)The impact velocity of the spanner is 21.6 meters per second.

Simply put, velocity is the rate at which something travels in a specific direction.

We can use the equations of motion to solve this problem.

a) To calculate the height from which the spanner was dropped, we can use the equation:

[tex]h = (1/2)gt^2[/tex]

where h is the height, g is the acceleration due to gravity, and t is the time taken to fall.

Substituting the given values, we get:

[tex]h = (1/2) \times 9.81 m/s^2 \times (2.2 s)^2 \\= 24.2 meters[/tex]

Therefore, the spanner was dropped from a height of 24.2 meters.

b) To calculate the impact velocity of the spanner, we can use the equation:

v = gt

where v is the final velocity, g is the acceleration due to gravity, and t is the time taken to fall.

Substituting the given values, we get:

[tex]v = 9.81 m/s^2 \times 2.2 s \\= 21.6 m/s[/tex]

Therefore, the impact velocity of the spanner is 21.6 meters per second.

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When light is travelling through ice, its wavelength is 4.50 10⁻⁷ metres.

Since glass has a higher index of refraction than air, light travels more slowly through glass than through air (n=c/v). Although the wavelength does not change, the frequency does because the speed does.

The following equation describes the relationship between the wavelengths of light in two different media:

n1 * λ1 = n2 * λ2

We may rewrite this equation to get the wavelength of the light in the second medium while assuming that the light's frequency stays constant: λ2 = (n1 / n2) * λ1

For water, the refractive index is about 1.333, and for ice, it is about 1.31. Therefore, we have:

λ2 = (1.333 / 1.31) * 4.42×10⁻⁷ m

λ2 = 4.50×10⁻⁷ m

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The weight of the satellite orbiting the earth is 3068.25 Newtons.

This is calculated using the equation

Weight = Mass x Acceleration or

W = m x g.

Where, m = 8695 kg and

g = 0.35 m/s2.

Therefore,  W = 8695 kg x 0.35 m/s2 = 3068.25 N.

A satellite is an artificial object that orbits a planet or other astronomical body. It is used for communication, navigation, weather forecasting, and other purposes.

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The train's displacement in the first 5.39384 s of motion is 24.0 m.

We can use the kinematic equation:

v = u + at

where:

v = final velocity = 12.2844 m/s

u = initial velocity = 0 m/s (train starting from rest)

a = acceleration

t = time = 7.06 s

Solving for acceleration:

v = u + at

a = (v - u) / t

a = (12.2844 m/s - 0 m/s) / 7.06 s

a = 1.736 m/s²

Now, we can use another kinematic equation to find the displacement in the first 5.39384 s:

s = ut + 0.5at²

where:

s = displacement

u = initial velocity = 0 m/s

a = acceleration = 1.736 m/s²

t = time = 5.39384 s

s = 0 + 0.5(1.736 m/s²)(5.39384 s)²

s = 24.0 m

Therefore, the train's displacement in the first 5.39384 s of motion is 24.0 m.

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The net electric field at point A is -1.12 108 N/C in size.

In light of the fact that both the charge q1 and the other charge q2 are equal to zero. According to the equation, one charge is positive and the other is negative. Both charges are of similar size. This indicates that the two supplied charges on the system will add up to a total charge of zero.

E = k*q/r²

where E is the electric field, q is the charge, r is the distance from the charge, and k is Coulomb's constant, which has a value of 8.99 × 10^9 N·m²/C².

d1 = d2 = (1/2) * (0.1 m) = 0.05 m

E1 = k*q1/d1² = (8.99 × 10⁹ N·m²/C²) * (5 × 10⁻⁶ C) / (0.05 m)² = 1.8 × 10⁸ N/C

E2 = k*q2/d2² = (8.99 × 10^⁹ N·m²/C²) * (10 × 10⁻⁶ C) / (0.05 m)² = 3.6 × 10⁸ N/C

E net = E1 - E2 = 1.8 × 10⁸ N/C - 3.6 × 10⁸ N/C = -1.12 108 N/C.

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Answer:

Amps are units of current.

Volts are units of voltage.

Ohms are units of resistance.

Explanation:

You're welcome.

Tide are waves on oceans. The 5th day tide are know as extreme and called the king or spring tide, while the 13th day tide are called the neap tide.

Tides are long waves that move across the oceans as a result of the moon's effect on the gravitational forces of the earth and, to a lesser extent, the sun.

The tides on day 5 are extreme because both the moon and the sun contribute equally to tide formation; these are known as spring or king tides. The diagram will be drawn so that the sun, moon, and earth are all in the same straight line.

The tides are not extreme on day 13 because the sun cancels out the moon tides. It is referred to as neap tide, which means "powerless tide." The diagram will depict all three (the sun, moon, and earth) arranged at a right angle.

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1.Luminous Intensity-It can be expressed as luminous intensity with a unit known as Candela.

2.Light Ray- It refers to the light traveling in one direction in a straight line.

3.Incident Rays- Rays of light that point towards and strike a surface.

4.Candela- It is the fundamental unit of luminous intensity.

5.Transparent-Allow light to easily pass through.

6.Dispersion-It is the process of splitting white light into its constituent colors ROYGBIV.

7.Refracted Rays-Rays that formed when a light goes through a surface and bend due to a change of material.

8.Opaque- It does not let light pass through.

9.Photometry-It refers to the amount of light power emanating from a point source within a solid angle

10.Brightness-It deals with the measurement of visible light as perceived by the human eye.

11.Translucent- Allow light to pass through but distant the light during the passage.

12.Beam of light-It is a group of rays given out from a source.

13.Non-Luminous Objects- These are objects that cannot emit their own light.

14.Reflected Rays- Rays of light that bounce off of a surface.

15.Non-Luminous Objects-Those that cannot emit their own light.

Luminous intensity is a measure of the amount of light emitted from a point source in a particular direction per unit time. It is expressed in the SI unit of candela (cd).

Luminous intensity is a fundamental concept in photometry, which is the study of the measurement of visible light as perceived by the human eye. The luminous intensity of a light source depends on various factors such as the amount of power it emits, the wavelength of light, and the efficiency of the source in converting electrical energy into light.

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Asteroid A has a kinetic energy of 94,000,000 J.

Such a body is predicted to strike the planet once per million years or so and produce energy about equal to 10,000 megatons of TNT, slightly more than the energy released during a nuclear war and sufficient to trigger a nuclear winter scenario (see graph above).

The following equation determines an object's kinetic energy:

KE = 0.5 * m * v².

Then, we could type:

m_A = 5.0 * m_B (mass of Asteroid A)

v_A = 2.0 * v_B (velocity of Asteroid A)

Asteroid B's kinetic energy is listed as 4,700,000 J. When we substitute the mass and velocity estimates for asteroid B, we obtain:

KE_B = 0.5 * m_B * v_B² = 4,700,000 J

Solving for the mass of Asteroid B, we get:

m_B = 2 * KE_B / v_B²

The equation for the mass of asteroid A is given by replacing this expression for m B with m A = 10 * KE B / v B².

The following results are obtained by substituting the two asteroids' masses and velocities in the kinetic energy formula:

KE_A = 0.5 * m_A * v_A²

= 0.5 * (10 * KE_B / v_B²) * (2 * v_B)²

= 20 * KE_B

As a result, asteroids A and B have kinetic energies that are 20 times greater than each other.

KE_A = 20 * 4,700,000 J

= 94,000,000 J

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