Answer:
The dissecting microscope provides a lower magnification than the compound microscope, but produces a three-dimensional image
Explanation:
The movement of materials through the channel protein that does not require energy:
Answer: Passive processes.
Explanation: Passive processes don't require the cell to expand any of its own energy in order to move. There are two types of passive processes: osmosis and diffusion. Diffusion is higher to lower, while osmosis is lower to higher.
What is the name of the bond that is created when two amino acids join?
* hydrogen bond
nitrogen bond
Opeptide bond
Tonic bond
Answer:
The answer is Peptide bond
Explanation:
Amino acids join together to create peptides and peptides join together to create proteins.
Answer: C: Peptide Bonds
Explanation:
Just Took The Assessment, Passed with An 100
what are some characteristics of the animal kingdom
Answer:
Explanation:
Lions
HELPPPP
Which of these statements is true about the behavior of light?
A. Light behaves like a longitudinal electromagnetic wave.
B. Light consists of electric and magnetic fields that are parallel to one another.
C. Light waves vibrate in only one direction.
D. Light behaves as a wave or a particle depending on the situation.
Answer:
b
Explanation:
Answer: The answer is D... Hope this helps :) Please mark Brainliest
Explanation:
Which kind of diagram compares the numbers of organisms in the different
trophic levels of a food chain or food web?
O A. Energy pyramid
B. Pyramid of numbers
O C. Pyramid of biomass
O D. Food pyramid
Answer:
B
Explanation:
What would most likely happen to a cell undergoing mitosis if you introduced an inhibitor to Aurora B at prometaphase
Answer:
Nuclear division will not occur in that cell
Please find the explanation below
Explanation:
Mitosis is a type of cell division in which two genetically identical daughter cells form from a single cell. The mitotic process occurs in stages, which includes the PROMETAPHASE described in this question. Prometaphase is the second stage of mitosis i.e after prophase and before metaphase.
Prometaphase stage is characterized by the degradation of the nuclear envelope in order to allow the sister chromatids to be separated into opposite poles. Also, a protein called KINETOCHORE forms at the centromere in order for the microtubules to attach to them in subsequent stages.
If an inhibitor is introduced into the cell at PROMETAPHASE stage, the activities described above, which are important for the separation of the chromatids, will not occur. Hence, the likely effect on the cells is INABILITY of NUCLEAR DIVISION TO OCCUR.
The most likely outcome of the addition of an inhibitor to Aurora B in prometaphase of a cell undergoing mitosis is the fact that sister chromatid arms would not separate (Option B).
Aurora B is a crucial regulator of accurate mitosis that localizes to the chromosomes during prophase, the centromeres during metaphase, and the mitotic spindle during anaphase.During prometaphase, this protein (Aurora B) regulates the association of motor proteins with the kinetochore, which s a structure associated with duplicated chromatids in eukaryotic cells.The interactions of the kinetochores with microtubules of the mitotic spindle modulate the movement of chromosomes during prometaphase and metaphase, and subsequent segregation during anaphase.In conclusion, the most likely outcome of the addition of an inhibitor to Aurora B in prometaphase of a cell undergoing mitosis is the fact that sister chromatid arms would not separate (Option B).
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Direction: Label the parts of the female reproductive system.
Hope this helps if its not I'm so sorry
Consider this microscopic image of bacteria. Spherical bacteria is shown. Which type of bacteria is shown in the image? bacillus coccus spirillum cholera
Answer:
The answer is Coccus
Explanation:
13
Who constructed the first multistep carcinogenesis model for colorectal cancer?
(1 Point)
B. Vogelstein
J. Fraumeni
J. Watson
C. Venter
Answer:
B.Vogelstein.
I'm not sure tbh
Which of the following would lead to an increase in species biodiversity in Florida?
A.releasing snails from South America into the wild. В.
letting wild boar from England invade people's farm land
C.
clearing land for a new entertainment theme park
D. protecting an endangered species in state or national forests
Answer: D
Explanation:
Ensuring that they don't lose their habitat and protecting them is key. Not adding in other invasive species or overexploitation. Conserving would cut the pollution (and if done globally it would cut back global warming). So if we protect the current species more will come or the current will evolve and be able to reproduce.
Protecting an endangered species in state or national forests would lead to an increase in species biodiversity in Florida.
What are Endangered species?A species that is threatened with extinction in the near future, either globally or within a certain political jurisdiction, is known as an endangered species.
Invasive species, habitat degradation, poaching, and other issues may put endangered animals in danger. Numerous species have their worldwide conservation status listed on the IUCN Red List, and a number of other organizations evaluate the condition of species in specific regions.
Many countries have laws that preserve species that depend on conservation, such as those that prohibit hunting, limit land development, or establish protected areas.
Therefore, Protecting an endangered species in state or national forests would lead to an increase in species biodiversity in Florida.
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How is a Punnett square used to determine the probability of inheriting genes ?
Answer:
The diagram is used by biologists to determine the probability of an offspring having a particular genotype. The Punnett square is a tabular summary of possible combinations of maternal alleles with paternal alleles. The Punnett square is a visual representation of Mendelian inheritance.
Explanation:
An example of a Punnett square:
tt and TT
t . t
T tT . tT
T tT tT
I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!
Answer:
The diagram is used by biologists to determine the probability of an offspring having a particular genotype. The Punnett square is a tabular summary of possible combinations of maternal alleles with paternal alleles. ... The Punnett square is a visual representation of Mendelian inheritance.
Explanation:
Macroevolution _____. select all that apply.
A. refers to evolution AT the species level. -no(that's micro. macro=above)
B. includes evolution at the population and community level. -no (that's micro)
C. analyzes the history of life over time. (was correct ody ssey)
D. refers to evolution ABOVE the species level (was correct ody ssey)
E. is based on direct observation -no (that's micro too)
Answer:
C
Explanation:
lol it says it in the question which ones are correct
In the non-random-mating exercise the percentage and frequency data for the genes were unaffected by the non-random mating. True False
Answer:
False
Explanation:
When non-random mating is being carried out, percentage and frequency data are usually affected because non-random mating have the tendency of changing the gene frequencies in a population. These non-random mating usually occurs when individuals choose to mate with superior physical traits or as a result of physical accessibility. The phenotypic characteristics are also greatly influenced by the biotic and abiotic environment they dwell in or other physical characteristics.
20 POINTS PLZ HELP PLZ
Do
Sponges,
Cnidarians,
Roundworms,
Annelids,
Mollusks,
Arthropods,
Echinoderms,
Vertebrates,
Representative organism
Answer:
Cnidarian
Explanation:
Once you inoculate the rabbit plasma containing media for the coagulase test, how long do you wait to read the sample results
Answer:
12 to 14 hours
Explanation:
The coagulase test may be called an overnight incubation test and is used to find the presence of bound coagulase that are attached to the bacterial walls. It take between 12 to 14 hours to read the sample result. This period is equivalent of an overnight incubation.
3. On a particular planet, it takes 850 J for a 50 kg remote probe to launch
itself up 2 m. What is the gravitational field strength on the planet?
Answer:
the gravitational field strength is 8.5 N/kg .
Explanation:
PE = mgh
where,
PE is Potential Energy
m is the mass
g (a) is the acceleration
h is the height
Substitute the value we get
→ 850 = 50×a × 2
→ 850 = 100×a
→ a = 850/100
→ a = 8.5m/s²
Acceleration is 8.5m/s².
Now, Calculating the Gravitational Field Strength
Organism that can that can breed/produce fertile offspring_________
A-Ecosystem
B-organism
C-Ecology
D-species
E-abiotic
F-Biotic
G-community
H-population
Darwin's next insight was to compare process in nature to artificial selection. By doing so, he developed a scientific hypothesis to explain how evolution occurs. This is where Darwin made his ______ contribution and his strongest break with the past.
1. (a) What are the requirements of an "ideal" antimicrobial drug?
Answer:
An ideal antimicrobic: - soluble in body fluids, - selectively toxic, - nonallergenic, - reasonable half life (maintained at a constant therapeutic concentration) - unlikely to elicit resistance, - has a long shelf life, - reasonably priced.
Which of the following is NOT a characteristic of a monocot?
Flower parts in multiples of three
Major leaf veins reticulated
Embryo with single cotyledon
Pollen with single furrow or pore
Answer:
Embryo with single cotyledon
Explanation:
Monocot, also known as monocotyledonous plants are a group of flowering plants (angiosperms) that possess one seed-leaf or cotyledon, which is contrary to the two-seed leaves possessed by dicots. Monocot plants have other characteristics that differentiate them from dicots as follows:
- Their flower parts are in multiples of three.
- It's major leaf veins are reticulated
- Pollen with single furrow or pore
However, the embryo of monocots are with a single cotyledon.
Dissus the relationship between prokaryotic and eukaryotic cell
in relation to:
(a) Cell evolution
(b) Cell structure and genetic materials
(c) Mode of feeding
(d) Adaptation to the environment
Answer:
b is the answer 70%sure
Explanation:
because i read that last year and nobe of the others was in the book only b
Why we use two op_amp when 1+A2<A1
all of the populations of living things in an area is called a
Answer:
Community. All the populations of all the different species that live together in a particular area. Ecosystem. All the organisms that live in a place, along with their physical environment. Biosphere.
Answer:
cummunity
Explanation:
Biology fund nutrition
Answer:
The food we eat - our diet - is made up of different biological molecules which gives us energy and contain chemicals we need to grow and repair ourselves and help our cells function in our body.
Carbohydrates and fats are made up of carbon, hydrogen and oxygen.
Proteins contain carbon, hydrogen, oxygen and nitrogen.
How many moles of HCI are neede to prepare 150 mL of a 1.2 M
solution?
0.18 moles HCl
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Unit 0
Conversion: 1000 mL = 1 LAqueous Solutions
Molarity = moles of solute / liters of solutionExplanation:Step 1: Define
150 mL
1.2 M
x moles
Step 2: Identify Conversions
mL to L conversion
Step 3: Convert
[tex]\displaystyle 150 \ mL(\frac{1 \ L}{1000 \ mL} )[/tex] = 0.15 L
Step 4: Solve for Moles
Substitute [Molarity]: [tex]\displaystyle 1.2 \ M = \frac{x \ moles \ HCl}{0.15 \ L}[/tex]Isolate x: [tex]\displaystyle 0.18 \ moles \ HCl = x[/tex]Rewrite: [tex]\displaystyle x = 0.18 \ moles \ HCl[/tex]Step 5: Check
We are given 2 sig figs. Follow sig fig rules and round.
Since our final answer is in 2 sig figs, there is no need to round.
Answer:
0.18 moles HCl
Explanation:
A plasmid 41 twists and 6 right handed writhes. What is the Lk for this plasmid?
Answer: Lk for this plasmid = 47
Explanation:
The formula to compute Lk is given by :-
Topological Linking Number (Lk): Twist (Tw) + Writhe (Wr)
Given: A plasmid 41 twists and 6 right handed writhes.
i.e. Twist (Tw) = 41 , Writhe (Wr) = 6
Then, Topological Linking Number (Lk) for this plasmid : = 41+6
= 47
Hence, the Lk for this plasmid = 47
Drag each tile to the correct location.
Sort the following statements as facts, theories, or laws.
Answer: Fact- the Pacific Plate is moving at a rate of approximately 7 cm per year.
Earth's atmosphere is composed primarily of nitrogen and oxygen.
Theory- some diseases are caused by microorganisms that grow and reproduce in a living host.
Laws- the electrical current through a conductor is directly proportional to the voltage across the conductor.
In a closed system the sum of all momenta within the system is constant.
Explanation:
I just took the test
the first or smallest level of organization in the human body is the
Answer:
chemicals
Explanation:
it goes from chemicals to cells to tissues to organs to organ tissues and then organism
Answer:
chemicals
Explanation:
Explain why a risk management officer would have a higher position in a health care company than a nurse has in a hospital.
Answer:
Once a new process is adopted organization-wide, the quality manager can measure and evaluate the effect that the new process has on patient outcomes, and the risk manager can monitor whether the new process reduces adverse events related to the process.
Explanation:
In the ladder analogy of the DNA molecule, the "steps of the ladder are.....
Sugars
O Joined sugar and phosphate
O Paired nitrogen bases
In the ladder analogy of the DNA molecule, the "steps of the ladder" are paired nitrogen bases.
What are nitrogen bases?The DNA molecule is made up of two strands of nucleotides that create a double helix as they coil around one another. The sugar molecule, the phosphate group, and the nitrogenous base are the three parts that make up a nucleotide. The nitrogenous bases serve as the ladder's rungs or "steps," pairing with one another to form hydrogen bonds that hold the DNA molecule's two strands together.
The nitrogenous bases adenine (A), thymine (T), cytosine (C), and guanine (G) are the four types found in DNA (G). The genetic code of an organism is made up of base pairs, which always couple adenine with thymine and cytosine with guanine. The genetic information that is transferred from one generation to the next is determined by the arrangement of these base pairs along the DNA molecule.
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