What mass of Ca(OH)2 is contained in 1500 mL of 0.0250 M Ca(OH)2 solution?


Your answer:


1.85 g



2.34 g



2.78 g



3.17 g

Answers

Answer 1

We need moles of Ca(OH)_2

Molarity=Moles/Volume in L0.025=Moles/1.5Moles=1.5(0.025)Moles=0.0375mol

Molar mass of Ca(OH)_2=74g/mol

Now

Mass=Molar mass×MolesMass=0.0375×74Mass=2.77g

Option C

Answer 2

The mass of Ca(OH)₂ in the given solution is approximately 2.78 grams, which corresponds to option C) 2.78 g.

Given: Volume = 1500 mL, Concentration (Molarity) = 0.0250 M, and Compound = Ca(OH)₂ .

First, convert mL to L: Volume = 1500 mL × (1 L / 1000 mL) = 1.5 L.

Use the formula for calculating the number of moles: Moles = Concentration × Volume.

Moles = 0.0250 mol/L × 1.5 L = 0.0375 mol.

The molar mass of Ca(OH)₂  can be calculated:

Ca(OH)₂  molar mass = (1 * atomic mass of Ca) + (2 * atomic mass of O) + (2 * atomic mass of H)

= (1 * 40.08 g/mol) + (2 * 16.00 g/mol) + (2 * 1.01 g/mol)

= 74.09 g/mol.

Now, calculate the mass using the calculated moles and molar mass:

Mass = Moles × Molar mass

Mass = 0.0375 mol × 74.09 g/mol = 2.78 g.

Therefore, the mass of Ca(OH)₂  in the given solution is approximately 2.78 grams, which corresponds to option C) 2.78 g.

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The complete question is:

What mass of Ca(OH)₂ is contained in 1500 mL of 0.0250 M Ca(OH)₂ solution?

A) 1.85 g

B) 2.34 g

C) 2.78 g

D) 3.17 g


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An aqueous solution has a hydroxide ion concentration of 1.20 × 10–2 M at 25°C. Calculate the pOH of the solution.

Answers

Given↷

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pOH of the solutionAnswer ↷

pOH = 1.92Solution ↷

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Let's see

25°C is normal room temperature denotion

pOH

[tex]\\ \rm\Rrightarrow -log[OH^-][/tex]

[tex]\\ \rm\Rrightarrow -log[1.2\times 10^{-2}][/tex]

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[tex]\\ \rm\Rrightarrow -log1.2-log10^{-2}[/tex]

[tex]\\ \rm\Rrightarrow -0.0791812460476+2[/tex]

[tex]\\ \rm\Rrightarrow 2.0791812460476[/tex]

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