You would have to travel to a latitude of approximately 80.5 degrees north of the equator (or south, depending on your hemisphere) to see the noontime sun at your zenith on October 3rd.
To see the noontime sun at your zenith on October 3rd (or any other date), you would have to be located at a latitude equal to the complement of the Sun's declination on that date. The declination is the angle between the plane of the Earth's equator and the line connecting the Earth to the Sun, and it varies throughout the year due to the tilt of the Earth's axis of rotation.
On October 3rd, the Sun's declination is approximately 9.5 degrees south of the equator. To find the latitude at which the noontime Sun would be directly overhead, we take the complement of this declination, which is:
90 degrees - 9.5 degrees = 80.5 degrees
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The basketball started at a height of about 4 feet above the ground. While dribbling the ball traveled downward until it hit the ground, then it returned to its initial height. What is the distance and what is the displacement?
Answer:Assuming that the basketball is dropped from rest and bounces back up to its initial height of 4 feet, we can use the equations of motion to find the distance and displacement.
The distance traveled by the basketball is the total length of the path it travels, which can be calculated by adding up the distance traveled during each phase of the motion. During the first phase, the ball falls from a height of 4 feet to the ground, a distance of 4 feet. During the second phase, the ball bounces back up from the ground to a height of 4 feet, covering the same distance of 4 feet. Therefore, the total distance traveled by the basketball is:
Distance = 4 + 4 = 8 feet
The displacement of the basketball, on the other hand, is the straight-line distance between its initial and final positions. Since the basketball returns to its initial height of 4 feet, its displacement is equal to zero. Therefore:
Displacement = 0 feet
Explanation:
The mass of the water in the tank is 50 kg. What is the amount of heat supplied by the heating coil in the first 20minutes?
The mass of the water in the tank is 50 kg. The amount of heat supplied by the heating coil in the first 20 minutes is 10,450 J. The specific heat capacity of water is 4.18 J/g°C, and the mass of the water in the tank is 50 kg.
The amount of heat supplied by the heating coil in the first 20 minutes can be calculated using the formula Q = mcΔT, where Q is the amount of heat, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
First, we need to determine the change in temperature of the water. From the problem statement, we know that the temperature of the water increased from 20°C to 70°C. Therefore, [tex]\Delta T = (70^{\circ}C - 20^{\circ}C) = 50^{\circ}C[/tex].
Next, we need to determine the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C.
Now, we can calculate the amount of heat supplied by the heating coil using the formula Q = mcΔT.
[tex]Q = (50 \;kg) \times (4.18 J/g^{\circ}C) \times (50^{\circ}C)[/tex]
Q = 10,450 J
Therefore, the amount of heat supplied by the heating coil in the first 20 minutes is 10,450 J.
In summary, the problem involves finding the amount of heat supplied by the heating coil in the first 20 minutes to heat a tank of water from 20°C to 70°C.
The solution involves using the formula Q = mcΔT, where Q is the amount of heat, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. The specific heat capacity of water is 4.18 J/g°C, and the mass of the water in the tank is 50 kg.
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A) Find the tension in each of the two ropes supporting a hammock if one is at an angle of θ1 = 10 ∘ above the horizontal and the other is at an angle of θ2 = 33 ∘ above the horizontal. The person sleeping in the hammock (unconcerned about tensions and ropes) has a mass of 66 kg . Express your answer using two significant figures.
T1= ? N
B) Express your answer using two significant figures.
T2= ? N
(a) The tension in the rope at an angle of 10° above the horizontal is approximately 798.5.4 N.
(b) The tension in the rope at an angle of 33° above the horizontal is approximately937.7 N.
What is the tension in the rope?To find the tension in each rope, we can use the fact that the net force in the vertical direction must be zero since the person in the hammock is at rest. Let T1 and T2 be the tensions in the ropes, and let the x-axis point to the right and the y-axis point upward.
A) The forces acting on the person are their weight (mg) downward and the tensions T1 and T2 in the two ropes, which make angles θ1 and θ2 with the horizontal.
The vertical components of the tensions are T1sinθ1 and T2sinθ2, respectively, and the horizontal components are T1cosθ1 and T2cosθ2.
Therefore, we can write:
T1sinθ1 + T2sinθ2 = mg (vertical equilibrium)
T1cosθ1 = T2cosθ2 (horizontal equilibrium)
Solving for T1 and T2, we get:
T1 = (mgcosθ2) / (sinθ1cosθ2 + sinθ2cosθ1)
T1 = (66)(9.81 )(cos(33°)) / (sin(10°)cos(33°) + sin(33°)cos(10°))
T1 ≈ 798.5.4 N
B) Similarly, we can use the horizontal equilibrium equation to find T2:
T2 = T1cosθ1 / cosθ2 = (798.5 N)(cos(10°)) / cos(33°) ≈ 937.7 N
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Which therapy is associated with light waves, but not sound waves? breaking down kidney stones acoustically targeting the delivery of a drug cauterizing an incision or wound ablating tumors
Cauterizing an incision or wound therapy is the therapy that is associated with light waves, but not sound waves. The correct option is (C).
A medical treatment called cauterizing an incision or wound includes burning or coagulating tissues with heat or electricity in order to stop bleeding or hasten wound healing. The main objective of cauterization is to produce a thermal action that closes off blood vessels in order to provide hemostasis and stop excessive bleeding.
During surgical procedures, cauterization is frequently performed to stop bleeding, remove or destroy aberrant tissue, or close off blood arteries. In some medical treatments, such as the removal of skin tags or warts, it is also utilized.
Hence, the therapy is associated with light waves, but not sound waves cauterizing an incision or wound. Option (C) is correct.
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The complete question is:
A: breaking down kidney stones
B: acoustically targeting the delivery of a drug
C: cauterizing an incision or wound
D: ablating tumors
I need to know the answers for 2 and 3
The ride's spring constant is 8625 N/m.
The Nerf gun's spring has a spring constant of 920 N/m.
How to calculate spring constant?To find the spring constant:
F = kx
where F = force applied to the spring, k = spring constant, and x = displacement of the spring.
Find the force applied to the spring, using Newton's second law:
F = ma
where m = combined mass of the Peas and their car, and a = acceleration of the car as it comes to a stop.
Since the car is initially moving at a constant velocity of 1.0 m/s, its initial acceleration is 0 m/s². Therefore, the only acceleration acting on the car is the deceleration caused by the spring.
To find the deceleration, using the equation:
v² = u² + 2as
where v = final velocity (0 m/s), u = initial velocity (1.0 m/s), a = acceleration, and s = displacement (0.20 m).
Rearranging this equation to solve for a:
a = (v² - u²) / (2s) = (0 - 1.0²) / (2 x 0.20) = -2.5 m/s²
Using Newton's second law to find the force applied to the spring:
F = ma = 690 kg × (-2.5 m/s²) = -1725 N
Finally, use the formula F = kx to solve for k:
k = F / x = -1725 N / (-0.20 m) = 8625 N/m
Therefore, the spring constant of the ride is 8625 N/m.
3) To find the spring constant, use the formula:
v = √(kx² / m)
where v = velocity of the dart, k = spring constant, x = displacement of the spring (0.04 m), and m = mass of the dart (0.92 g = 0.00092 kg).
Solving for k:
k = m v² / x² = 0.00092 kg × (16 m/s)² / (0.04 m)² = 920 N/m
Therefore, the spring constant of the spring used in the Nerf gun is 920 N/m.
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7. You are handed two mystery materials and told to determine which one accepts
negative charges more easily. Using a positively charged, helium-filled balloon that is
tied to a tabletop with a 1 m long string, describe a simple experiment that will help you
identify the more attractive material.
The experiment compares two materials by rubbing them with a positively charged balloon to see which one attracts the balloon more. The material that attracts the balloon more has a higher tendency to accept negative charges.
To determine which material accepts negative charges more easily, a simple experiment can be conducted using a positively charged, helium-filled balloon and a 1 m long string.
First, the balloon is rubbed against each of the mystery materials for the same amount of time to transfer some of the positive charges to the materials. The balloon can be positively charged by rubbing it against a wool sweater or a person's hair.
Next, the string is tied to a tabletop, and the balloon is held by the string close to one of the mystery materials. If the material attracts the balloon, it indicates that the material has a greater ability to accept negative charges and is therefore more attractive to the positively charged balloon.
Similarly, the same experiment can be repeated with the other mystery material. The material that attracts the balloon more strongly indicates that it has a greater tendency to accept negative charges.
This experiment works on the principle of electrostatics, where opposite charges attract each other. The positively charged balloon is attracted to the negatively charged material, and the strength of the attraction is proportional to the ability of the material to accept negative charges.
In summary, the experiment involves rubbing both mystery materials with a positively charged balloon and testing which one is more attractive to the balloon using a string tied to a tabletop. The material that attracts the balloon more strongly indicates that it has a greater tendency to accept negative charges.
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PLEASE HELP!!
AR stands for Radio Detection And Ranging. How does this technology work?
1: Radio waves are sent by a transmitter and the receiver picks them up at location down-range.
2: Radio waves are sent by a transmitter and reflect back to a receiver when they run into an object
AR, or Radar, is a technology that uses radio waves to detect and locate objects in its vicinity. Radio waves are sent by a transmitter and reflect back to a receiver when they run into an object. The correct option is 2.
A radar system typically consists of a transmitter that emits high-frequency radio waves, a receiver that detects the reflected waves, and a processor that interprets the data received.
When the radio waves encounter an object, they bounce off of it and return to the radar's receiver. The time it takes for the waves to bounce back and the characteristics of the returning signal are analyzed by the processor to determine the object's location, speed, and direction of movement.
Radar technology is widely used in a range of applications, including air traffic control, weather forecasting, military surveillance, and maritime navigation. It has also been adapted for use in automotive safety systems, such as collision avoidance and adaptive cruise control.
In summary, radar technology works by emitting radio waves from a transmitter, which bounce off of objects and are detected by a receiver. The characteristics of the reflected waves are analyzed to determine the location and movement of the objects in the radar's vicinity. The correct option is 2.
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Two identical test dummies are each dropped from a height of 3. 00 m. The first is dropped onto the concrete, and the skull fractures. The 2nd is dropped in the same manner also onto concrete but is also wearing a bicycle helmet and the skull does not fracture. Use the terms force, impulse, and time to explain why the two identical test dummies dropped in the same manner had very different outcomes
Dummy without a helmet experienced a higher force of impact causing a fracture, while the helmet reduced the risk of fracture by absorbing some of the impact energy.
The difference in outcome between the two identical test dummies dropped from the same height can be explained by the concepts of force, impulse, and time.
Force refers to the push or pull exerted on an object, while impulse refers to the change in momentum caused by a force acting over time. Time, on the other hand, refers to the duration of an event or the period during which a force acts on an object.
When the first dummy was dropped onto the concrete without a helmet, the force of impact caused a significant impulse in a very short amount of time. The skull could not withstand this sudden change in momentum, resulting in a fracture.
However, the second dummy wearing a bicycle helmet experienced a lower force of impact due to the helmet's ability to absorb some of the impact energy. This spread out the impulse over a longer period of time, reducing the overall force acting on the skull and minimizing the risk of fracture.
In summary, the use of a bicycle helmet reduces the force of impact by absorbing some of the energy and increasing the time it takes for the impulse to act on the skull. This demonstrates the importance of protective gear in reducing the risk of injury in potentially hazardous situations.
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A body has moved from its initial position at original along x-axis to final position x=5m under the influence of a force given by f =(4x)i n. what is the work done by the force in moving the body from its initial position to its final position ?
135J is the work done by the force in moving the body from its initial position to its final position
Define work done
The work done by a force is calculated as the product of the object's displacement and its component of the applied force in the displacement direction. Pushing a block firmly results in work being completed; the body moves more swiftly. The work is noted as completed.
A shift in an object's position is referred to as "displacement". It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol. For instance, an object's position changes if it moves from position A to position B.
w=∫Fdx
=∫ 7−2x+3x^2 dx
=[7x− 22x^2+ 33x^2] 0 to 5
=[7x−x^2+x^3] 0 to 5
=[35−25+125]−0
=135J
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4 major functions of the skeletal system
The functions of the skeletal system are support, movement, production of cells and protection.
The bones, muscles, ligaments, and tendons make up a skeletal system in the human body. It serves as body's support system to enable correct movement and bodily function. The skeleton gives the entire body structural support, allowing us to sit, stand, and move freely. In addition, fragile organs the brain, heart, and lungs are safeguarded by the bones of the skull, ribs, and spinal column.
Additionally, the skeletal system makes blood cells and stores minerals. The production of these cells, and platelets all essential for immune system and blood clotting take place in the bone marrow, which is found inside numerous bones. In addition, our ability to move and engage in activities like running, jumping, and dancing is made possible by our bones working in tandem with our muscles and joints.
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A +32. 2 uC charge feels a 0. 544 N
force from a +12. 3 uC charge. How
far apart are they?
(u stands for micro. )
[?] m
I thought I got it right, but apparently I did the math wrong and I can’t figure out where I messed up. Can someone help me out?
By using, Coulomb's Law the two charges are: approximately 0.248 meters apart.
To find the distance between a +32.2 µC charge and a +12.3 µC charge that experience a 0.544 N force, we can use Coulomb's Law.
Coulomb's Law states that the force (F) between two charges (q1 and q2) is proportional to the product of the charges and inversely proportional to the square of the distance (r) between them. The formula for Coulomb's Law is F = k * (q1 * q2) / r², where k is the electrostatic constant, approximately 8.99 x 10^9 N m²/C².
In this case, q1 = +32.2 µC, q2 = +12.3 µC, and F = 0.544 N. First, we need to convert the charges from microcoulombs (µC) to coulombs (C) by multiplying by 10^-6: q1 = 32.2 x 10^-6 C and q2 = 12.3 x 10^-6 C.
Now we can plug these values into Coulomb's Law formula:
0.544 N = (8.99 x 10^9 N m²/C²) * (32.2 x 10^-6 C) * (12.3 x 10^-6 C) / r²
Next, we will solve for r:
r² = (8.99 x 10^9 N m²/C²) * (32.2 x 10^-6 C) * (12.3 x 10^-6 C) / 0.544 N
r² ≈ 0.0615 m²
Now, take the square root of both sides to find r:
r ≈ 0.248 m
So, the two charges are approximately 0.248 meters apart.
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Complete question:
A +32. 2 u C charge feels a 0. 544 N force from a +12. 3 uC charge. How far apart are they?
(u stands for micro. )
A centrifuge has a diameter of 18cm. It is able to spin at 10,000 rpm.
A. What is the centripetal acceleration of the centrifuge?
B. If we place a 10 9 gram sample into the centrifuge, what is the force on the sample?
C. How many times greater than the force of gravity is this force?
About 10,080 times more force than gravity is exerted on the sample in the centrifuge.
A. To calculate the centripetal acceleration of the centrifuge, you can use the formula:
a_c = rω²
where a_c is centripetal acceleration, r is the radius of the centrifuge, and ω is angular velocity. First, we need to convert the diameter to the radius (r = 0.09 m) and RPM to radians per second (ω = 10,000 RPM * 2π / 60 ≈ 1047.2 rad/s).
a_c = 0.09 m * (1047.2 rad/s)² ≈ 98,960 m/s²
B. To find the force on the 10-gram sample, we can use the formula:
F = m * a_c
where F is force, m is the mass of the sample (0.01 kg), and a_c is the centripetal acceleration from part A.
F = 0.01 kg * 98,960 m/s² ≈ 989.6 N
C. To determine how many times greater than the force of gravity this force is, we can divide the force by the gravitational force on the sample:
F_gravity = m * g
F_gravity = 0.01 kg * 9.81 m/s² ≈ 0.0981 N
Force ratio = F / F_gravity ≈ 989.6 N / 0.0981 N ≈ 10,080
So, the force on the sample in the centrifuge is approximately 10,080 times greater than the force of gravity.
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On a planet other than earth, the acceleration due to gravity is more than on earth. if you float in water on this planet, you would
a. find it easier to float on earth.
b. harder to float on earth.
c. same effort to float on earth
d. you would sink on earth
e. have a greater buoyant force on earth
The buoyant force experienced by an object immersed in a fluid is given by the equation:
Buoyant force = (Density of fluid) x (Volume of fluid displaced) x (Acceleration due to gravity)
Since the density of water is constant, the only factor that changes when we compare floating in water on different planets is the acceleration due to gravity.
If the acceleration due to gravity is more on the other planet, then the buoyant force experienced by the object will also be more compared to the buoyant force experienced on Earth, given the same volume of fluid displaced. Therefore, the object would find it easier to float on the other planet than on Earth.
So the correct answer is: a. find it easier to float on earth.
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1. A boy moves on a skateboard at a constant velocity of 3 m-s-'. The
combined mass of the boy and the skateboard is 40 kg. He catches a bag of
flour of mass 5 kg that is thrown to him horizontally at 6 m-s-!. Determine
the velocity of the boy after catching the bag of flour. (2 m-s ' in his original
direction)
The velocity of the boy and skateboard after catching the bag of flour is 2.25 m/s in his original direction. We can use the conservation of momentum to solve this problem.
The initial momentum of the system (boy, skateboard, and flour) is:
p initial = (40 kg) x (3 m/s)
= 120 kg·m/s
When the boy catches the bag of flour, there is no net external force on the system, so the total momentum remains constant.
Therefore, the final momentum of the system is also 120 kg·m/s. Let v be the final velocity of the boy and skateboard.
Then the momentum of the flour is:
p flour = (5 kg) x (6 m/s)
= 30 kg·m/s
The total momentum of the boy and skateboard is:
p boy + skateboard = (40 kg) x (v)
So we can write the conservation of momentum equation as:
p initial = p boy + skateboard + p flour
Solving for v, we get:
v = (p initial - p flour) / (40 kg)
Plugging in the numbers, we get:
v = (120 kg·m/s - 30 kg·m/s) / (40 kg)
= 2.25 m/s
Therefore, the velocity of the boy and skateboard after catching the bag of flour is 2.25 m/s in his original direction.
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A person gets their 800 kg car stuck in a rut, then spend the remaining 4 hours of the afternoon trying to push the car out of the rut. How much work did the person do over those 4 hours?
To calculate the amount of work done, we need to know the force exerted by the person and the distance the car was moved. Work is calculated using the formula: Work = Force × Distance. Without the information about the force exerted and the distance the car was moved, it is not possible to determine the exact amount of work done by the person over the 4 hours spent pushing the 800 kg car.
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A group of science students take a class trip to a coastal area to learn more about heat energy and heat transfer concepts. Choose the primary type of
heat transfer that occurs in the situations that follow. If heat transfer is not responsible for the situation that is described, choose letter d, "No heat
transfer took place. "
A student burned his finger on a hot charcoal grill
.
O Conduction
O Convection
O Radiation
O No heat transfer took place.
Heat transfer that occurs in the situations that follow. If heat transfer is not responsible for the situation that is conduction
Option A is correct.
Conduction :Conduction is the cycle by which heat energy is communicated through impacts between adjoining particles or atoms. In contrast to gases, where the distance between the particles is greater, solids and liquids have a higher rate of conduction.
Conduction is the interaction by which intensity is moved from the more sizzling finish to the colder finish of an item. Heat spontaneously flows along a temperature gradient, and the object's thermal conductivity, or k, is its capacity to conduct heat.
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A toaster is listed as 1560 w. when it is plugged into a 120 v circuit and starts to make toast, how many amperes will it draw
The toaster will draw 13.0 amperes when plugged into a 120-volt circuit.
To calculate the amperage that the toaster will draw, we can use Ohm's Law which states that the current flowing through a circuit is equal to the voltage divided by the resistance.
However, we need to first determine the resistance of the toaster.
From the given information, we know that the toaster is rated at 1560 watts and is operating at 120 volts.
Therefore, we can calculate the resistance using the formula R = [tex]V^{2}[/tex] / P, where V is the voltage and P is the power.
R = [tex](120)^{2}[/tex] / 1560 = 9.23 ohms
Now that we know the resistance, we can use Ohm's Law to calculate the current drawn by the toaster:
I = V / R = 120 / 9.23 = 13.0 A
Therefore, the toaster will draw 13.0 amperes when plugged into a 120-volt circuit.
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Why are Buildings in UAE made with glazed glass?
The buildings in UAE made with glazed glass is because of their low maintenance and ease of installation.
Glazed glass means the glass that is used for buildings and architectural purposes. The glass facades are specifically energy efficient and support green glazing. In UAE buildings, the majority of glazing is to achieve a shading co-efficient of 0.25 which results in high-performance glazing. Glass transmits up to 80% of natural daylight and ensures cost savings.
Glass buildings help in energy efficiency in Eastern countries. Adopting glass on buildings is not easy in Middle Eastern countries due to extreme weather conditions. But the technologies made it possible and glass become a widely used material in the Middle East.
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What produces electricity from a chemical reaction and cannot be run in reverse
Please describe this graph
a. Explain the relationship between variables.
b. State if it is a linear or nonlinear graph
c. Give an example of what this graph could be about.
To describe the graph we need to explain the specific concepts mentioned below:
a. The relationship between variables on a graph refers to how one variable changes in response to the other. This can be positive (both variables increase or decrease together), negative (one variable increases while the other decreases), or no relationship (no discernible pattern between the two variables).
b. A graph can be classified as linear or nonlinear based on the shape of the relationship between the variables. A linear graph forms a straight line, indicating a constant rate of change between the variables. A nonlinear graph has a curve or irregular shape, indicating a variable rate of change between the variables.
c. An example of a graph could be a scatter plot of people's ages (x-axis) and their monthly income (y-axis). If the points form a straight line with a positive slope, it would indicate a linear relationship, meaning that as people's ages increase, their income generally increases as well.
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Design an experimental set up to show that white light is made up of different colours of light
Using a prism to split white light into its component colors is a classic experimental setup that demonstrates that white light is made up of a range of colors.
One classic experimental setup to demonstrate that white light is made up of different colors of light is the use of a prism. Here are the steps to set up the experiment:
Start with a source of white light, such as a flashlight or a lamp.
Shine the white light onto a prism, which is a triangular-shaped piece of glass or plastic.
The prism will refract or bend the light, splitting it into its different colors, which are the colors of the rainbow (red, orange, yellow, green, blue, indigo, and violet).
Observe the spectrum of colors that are produced on the other side of the prism.
To make the colors more visible, place a white screen or piece of paper behind the prism.
You can also use a spectroscope, which is a tool that separates light into its component wavelengths, to measure the wavelengths of each color in the spectrum.
This experiment shows that white light is not a single color, but is made up of a range of colors.
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Suzie Skydiver with her parachute has a mass of 46kg. Before opening her chute what force of air pressure will she have when she reaches terminal velocity
Before opening her chute, Suzie Skydiver would experience a force of air pressure of approximately 450 N at terminal velocity.
Terminal velocity is the point where the force of air resistance, or drag, acting on the skydiver becomes equal in magnitude to the force of gravity pulling the skydiver down. At this point, the net force acting on the skydiver is zero, and they fall at a constant velocity. At terminal velocity, Suzie Skydiver is falling at a constant rate, meaning that the force of gravity pulling her down is balanced by the force of air resistance pushing her up.
This force of air resistance, also known as drag, can be calculated using the formula:
F = 1/2 * rho * v^2 * Cd * A,
where F is the force of drag, rho is the density of the air,
v is the velocity of the object,
Cd is the drag coefficient
A is the cross-sectional area of the object.
Assuming that Suzie Skydiver falls in a typical skydiving posture with a drag coefficient of around 1.0 and a cross-sectional area of 1.0 square meter,
Using the standard atmospheric density of 1.2 kg/m³,
We can calculate that her terminal velocity is approximately 54 m/s.
At this velocity, the force of air resistance, or drag, acting on Suzie Skydiver is equal in magnitude to the force of gravity, which is approximately 450 N.
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If you were to take a volleyball scuba diving with you what would be its new volume if it started at the surface with a volume of 2. 00L. Under a pressure of 752. 0 mmHg and a temperature of 20. 0°C? On your dive you take it to a place where the pressure is 2943 mmHg, and the temperature is 0. 245°C
The new volume of the volleyball would be 0.506 L.
To find the new volume, we can use the combined gas law, which states that P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature. We can first convert the initial pressure of 752.0 mmHg to atm, which is 0.987 atm.
Then, we can convert the initial temperature of 20.0°C to Kelvin, which is 293.15 K. Plugging these values along with the initial volume into the equation, we get:
(0.987 atm)(2.00 L)/(293.15 K) = (2943 mmHg)(V2)/(273.15 K)
Solving for V2, we get V2 = 0.506 L.
Therefore, the new volume of the volleyball would be 0.506 L when taken to a place with a pressure of 2943 mmHg and a temperature of 0.245°C.
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2. A bull of mass 250 kg is moving at a momentum of 750 kg m/s. Find its velocity.
Answer:
3m/s
Explanation:
momentum = mass×velocity
750kg m/s = 250kg × velocity
750kg m/s /250kg = velocity
3 m/s = velocity
Momentum = Mass × velocity
Velocity = Momentum/mass
Velocity = 750/250
Velocity = 3 m/s
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Titan, with a radius of 2. 58 x 10^6 m, is the largest moon of the planet Saturn. If the mass of Titan is 1. 35 x10^23 kg, what is the acceleration due to gravity on the surface of this moon?
A. 1. 35 m/s^2
B. 3. 49 m/s^2
C. 3. 49 x 10^6 m/s^2
D. 1. 35 x 10^6 m/s^2
The acceleration due to gravity on the surface of Titan can be calculated using the formula g = GM/[tex]R^{2}[/tex], where G is the gravitational constant, M is the mass of the moon, and R is the radius of the moon. Therefore, the correct answer is B.
Plugging in the given values, we get g = (6.67 x [tex]10^{-11}[/tex] [tex]Nm^{2}/kg^{2}[/tex])(1.35 x [tex]10^{23}[/tex] kg)/[tex](2.58* 10^{6}m)^{2}[/tex] = 3.49 [tex]m/s^{2}[/tex].
This means that an object on the surface of Titan would experience a gravitational acceleration of 3.49 [tex]m/s^{2}[/tex], which is about one-seventh of the acceleration due to gravity on Earth.
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The lowest note on a piano is
27. 5 Hz. To fit inside the piano,
the string for the low note can't be
longer than 1. 20 m. If it takes the
full length, what is the speed of
the wave in the string?
(Unit = m/s)
The lowest note on a piano is 27. 5 Hz. To fit inside the piano, the string for the low note can't be longer than 1. 20 m. If it takes the full length, the speed of the wave in the string is 33.0 m/s.
The speed of a wave in a string can be calculated using the formula [tex]v = \sqrt{(T/\mu)}[/tex], where v is the speed of the wave, T is the tension in the string, and μ is the linear density of the string.
To calculate the linear density of the string, we can use the formula μ = m/L, where m is the mass of the string and L is its length. Since we know that the length of the string for the lowest note on the piano is 1.20 m, we can assume that this is the length of the string if it takes the full length.
The frequency of the lowest note on the piano is 27.5 Hz. The wavelength (λ) of the wave can be calculated using the formula [tex]\lambda = v/f,[/tex]where f is the frequency of the wave. For the lowest note on the piano, the wavelength is equal to the length of the string: λ = 1.20 m.
We can use the wavelength and frequency to calculate the speed of the wave in the string: [tex]v = \lambda f = 1.20 \;m \times 27.5\; Hz = 33.0\; m/s.[/tex]
Therefore, if the string for the lowest note on the piano takes the full length of 1.20 m, the speed of the wave in the string is 33.0 m/s.
In summary, the speed of a wave in a string can be calculated using the formula [tex]v = \sqrt{(T/\mu)[/tex], where T is the tension in the string and μ is the linear density of the string.
By assuming that the length of the string for the lowest note on the piano is 1.20 m and using the frequency and wavelength of the wave, we can calculate the speed of the wave in the string.
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How do you convert 1440 am (amplitude modulation) to hertz (hz)?
This is because kilohertz means 1000 hertz, so by multiplying the AM frequency in kilohertz by 1000, we obtain the frequency in hertz. So 1440 kHz is equal to 1,440,000 Hz.
AM (amplitude modulation) is a type of radio transmission where the amplitude of the carrier wave is varied in proportion to the information signal.
It is specified in terms of frequency in kilohertz (kHz). To convert 1440 AM to Hz, we need to multiply it by 1000.
Therefore, 1440 AM = 1440 kHz = 1440000 Hz.
This is because kilohertz means 1000 hertz, so by multiplying the AM frequency in kilohertz by 1000, we obtain the frequency in hertz. So 1440 kHz is equal to 1,440,000 Hz.
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what conclusion is best supported by the image?
A) The field’s direction changes with the current’s direction.
B) The field weakens farther from the wire.
C) The field increases with greater current.
D) The field’s strength changes with the current’s direction.
The field’s direction changes with the current’s direction this conclusion is best supported by the image. Hence option A is correct.
Current is a flow of charges. it is denoted by i and expressed in ampere A. Mathematically it is expressed as i = q/t, where q is the amount of charge and t is time. Current is nothing but amount of charges flown in the unit time in the electric wire. Charge is expressed in coulomb C and time in second s. hence coulomb per second (C/s) is ampere A. Charge on electron is 1.60217663 × 10⁻¹⁹ which is called as elementary charge.
There are two types of the current, Convectional current and non-conventional current. Convectional current is the current flows from positive to negative. Non convectional current flows direction from negative to positive. Note that flow of electrons is from negative to positive. Hence direction of flow of conventional current is from positive to negative.
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Explain the relation between area, distance and capacitance
The capacitance of a capacitor is: directly proportional to the area of the conductive plates and inversely proportional to the distance between them.
The capacitance (C) of a capacitor is the measure of its ability to store an electrical charge. It is dependent on the surface area (A) of the conductive plates, the distance (d) between these plates, and the permittivity (ε) of the dielectric material that separates the plates. The relationship between these factors can be described by the following formula:
C = ε × (A / d)
In this equation, the area (A) and the distance (d) play crucial roles in determining the capacitance of a capacitor. As the surface area of the plates increases, the capacitance also increases because a larger surface area allows for more charge to be stored. Conversely, as the distance between the plates decreases, the capacitance increases as well since the electric field between the plates becomes stronger, allowing for a higher charge storage capacity.
In summary, the capacitance of a capacitor is directly proportional to the area of the conductive plates and inversely proportional to the distance between them. By adjusting these factors, one can tailor the capacitance of a capacitor to meet specific requirements in various electronic devices and circuits.
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A 200-N solid sphere 0. 20 m in radius rolls without slipping 6. 0 m down a ramp that is inclined at 34° with the horizontal. What is the angular speed of the sphere at the bottom of the slope if it starts from rest?
The angular speed of the sphere at the bottom of the ramp is approximately 7.64 rad/s.
We can use the conservation of energy principle. The total mechanical energy of the system (kinetic energy + potential energy) will be conserved, assuming there is no friction.
1. Find the potential energy of the sphere at the top of the ramp:
U = mgh
where m = 200 N, g = [tex]9.8 m/s^2[/tex], and h = d*sin(θ)
h = 6.0 m * sin(34°) = 3.40 m
U = (200 N)*([tex]9.8 m/s^2[/tex])*(3.40 m) = 6616 J
2. Find the kinetic energy of the sphere at the bottom of the ramp:
[tex]K = (1/2)*I*w^2 + (1/2)*mv^2[/tex]
where I is the moment of inertia of the sphere, w is the angular speed, and v is the linear speed of the sphere.
Since the sphere is rolling without slipping, we can use the relationship between linear and angular speed:
v = r*w
Also, for a solid sphere, the moment of inertia is I = (2/5)*m*r^2.
Substituting these values, we get:
[tex]K = (1/2)*(2/5)*m*r^2*w^2 + (1/2)*mv^2[/tex]
[tex]K = (1/5)*m*r^2*w^2 + (1/2)*mv^2[/tex]
At the bottom of the ramp, the sphere has no initial linear or angular speed, so v = 0.
3. Equate the initial and final energies to find the final angular speed:
K + U = U_f
where U_f = 0 (since the sphere has reached the bottom of the ramp and has no potential energy).
Substituting the values of K and U, we get:
[tex](1/5)*m*r^2*w^2 = -U[/tex]
[tex](1/5)*200 N*(0.20 m)^2*w^2 = -6616 J[/tex]
Solving for w, we get:
[tex]w = \sqrt{(-5*6616 J / (2*200 N*(0.20 m)^2))}[/tex]
w ≈ 7.64 rad/s
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