What is true about multiples of 6?
Each multiple will always be divisible by 3.

Each multiple will always end in a 6 or a 2.
Every multiple is an odd number.
Every other multiple is an odd number

Answer: C. 85°

Step-by-step explanation:

Answer:

I look lik dis almost dreads and then them types of braces and my eye brows look like that and I got a tattoo on my face but my eyes are blue and I have contacts so no more glasses

Answer:

x = 5

Step-by-step explanation:

[tex]6x - 20 = 2x \\ - 20 = 2x - 6x \\ - 20 = - 4x \\ \frac{ - 20}{ - 4} = x = 5[/tex]

Answer:

D

Step-by-step explanation:

Hope this is correct and helps

Answer:

D

Step-by-step explanation:

I'm not completely sure but A is constant cuz it don't move B is increasing C is same as A and D Is decreased

Answer:

1.6 (decimal), 1 6/10 (proper), and 8/5 (improper)

Step-by-step explanation:

If it’s 2/5 in 1/4 and to get one while you need four 1/4 you need to multiply to get how much it can fill in that 4/4. To do this multiply 2/5 by 4 which is 1.6 (decimal) and 1 6/10 fractional. Or if you want it improper, 8/5

Answer:

Step-by-step explanation:

Gogli complexes packages proteins, while endoplasmic reticulums transport proteins made by the gogli complexes around the cell.

The formula ½ bh finds the area of a triangle.

Please check the picture.

Answer:

Triangle

Step-by-step explanation:

b -  base of the triangle

h - height or altitude

Answer:

I believe it is C but it's good to double check

Step-by-step explanation:

Answer:

Step-by-step explanation:

b

Answer:

18+3

Step-by-step explanation:

3x6= 18

and 18+3=21

Answer:

7.5m

:) hoped this helped!

Step-by-step explanation:

Answer: 20

Step-by-step explanation:

Answer:

1, 11x + 3y + 15z

2, 3x + 12y + -5z

Step-by-step explanation:

all you need to do is combined the like terms and make sure the signs (positive and negative signs) are right

Answer:

AAS

Step-by-step explanation:

I'm pretty sure its this, but im sorry if im wrong!

⸻➤[tex]{\pink{\tt{Mixedfarming}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\sf\red{hope\:it\:helps\:you}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}[/tex]

[tex]\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}[/tex]

[tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b}

Answer:

Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].

Step-by-step explanation:

Angle sum identity for cosine:

[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].

Double-angle identity for cosine and sine:

[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].

[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].

The secant of an angle is the inverse reciprocal of the cosine of that angle:

[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].

Apply these identities to rewrite the left-hand side of the equation.

[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].

Solve the rewritten equation:

[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].

Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].

The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].

If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].

Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],

Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.

Answer:

I can't help you if there's no picture lol

Answer:

A = -3

Step-by-step explanation:

-16-7(-3)=5

Answer:

We need the options

Step-by-step explanation:

...

Answer:

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1                               7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7                               7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2                                 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14                            7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3                                 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21                            7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4                                 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28                            7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5                                 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35                          7(5) - 1 = 35 - 1 = 34

Answer:

5x+2x= 7x....

Step-by-step explanation:

There is no value that would make them equal.  If u subsitute x by 1, 2, 3 you get 7, 14, 21. When u substitute for 7x-1, all the values are 1 less than 7, 14, 21.

I must speak in your language

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[tex]\large\underline{\sf{Solution-}}[/tex]

We have to evaluate the given expression.

[tex] \rm = \sqrt{ \dfrac{1 - \sin(x) }{1 + \sin(x) } } [/tex]

If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} } [/tex]

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } } [/tex]

We know that:

[tex] \rm \longmapsto { \sin}^{2}(x) + \cos^{2}(x) = 1[/tex]

[tex] \rm \longmapsto \cos^{2}(x) = 1 - { \sin}^{2}(x)[/tex]

Therefore, the expression becomes:

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}} [/tex]

[tex] \rm = \dfrac{1 - \sin(x)}{\cos(x)}[/tex]

[tex] \rm = \dfrac{1}{\cos(x)} - \dfrac{ \sin(x) }{ \cos(x) } [/tex]

[tex] \rm = \sec(x) - \tan(x) [/tex]

[tex] \sqrt{ \frac{ \cos(n) }{1 + \: \sin(n) } } [/tex]

see the attachment!!

hope it helps

#carryolearning

Answer:

5

Step-by-step explanation:

7 x 5 =  35

35 + 3 = 38

The required simplified value of the given expression is 210

As mentioned in the question,
To raise the fraction to its highest terms by supplying the missing numerator.7/8=x/240.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
according to the question,
7 / 8 = x / 240
x = 7/8 × 240
x = 7 × 30
x = 210

Thus, the required simplified value of the given expression is 210.

Learn more about simplification here:

https://brainly.com/question/12501526

#SPJ2

Answer:

Answer:18.5

Step-by-step explanation:

10+8=18

18*5=90

90/4

22.5-4=18.5

Have a happy day! <3Miss Hawaii

Answer:

16

Step-by-step explanation:

sum of 8 and 10=18

5 times of sum of 8 and

10= 18×5=80

1/4 of 5 times of sum of 8 and

10= 1/4×80=20

and then subtracted 4 from

20 =20-4=16

Answer:

Step-by-step explanation:

65% of 51 = [tex]\dfrac{65}{100}*51[/tex]

                = 0.65 *51

                = 33.15

Answer:

y = x-7

Step-by-step explanation:

Slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

2y -2x = -14

Add 2x to each side

2y-2x+2x= 2x-14

2y = 2x-14

Divide by 2

2y/2 = 2x/2 -14/2

y = x-7

Answer:

a) = 4.198

b) = 4.146

Step-by-step explanation:

a) 15.444/6+0.232*7

do pemdas

=15.444/6+(0.232*7)

=(15.444/6)+1.624

=2.574+1.624

a) = 4.198

b) (1.709+0.364)*6/3

pemdas again

=(2.073) *6 / 3

=12.438 / 3

b) =4.146

Hope this helps :)

Answer:

A 4.198 and b is 2.073

Step-by-step explanation:

i hope this is right

Answer:

a) 68

b)60

Step-by-step explanation:

a) 85% = 0.85

0.85 * 80 = 68

b) let x be the unknown number.

35% = 0.35

0.35x = 21

x = 60

Answer:

Step-by-step explanation:

a, 85% of 80

85% of 80

= 85/100*80

=85/100*80

=0.85*80

=68.

b, 21 is 35%

21 is 35%

=21*35/100

=21*0.35

=7.35.

hope this helps you dear and have a nice day

The probability distribution for all possible values of X are given in the discrete probability table ;

Fair coin = {H, T}

card = {J, Q, K, A}

Sample space :

Probability of winning ; P(Winning) = 2/8 = 1/4 = 0.25

Probability of not winning ;

1 - P(wininng) = 1 - 1/4 = 3/4 = 0.75

X : ____ winning ____ not winning

P(X) : ____ 0.25 ________ 0.75

Learn more : https://brainly.com/question/25274933