What is the weighted mean, if each unit has the following weightings? (4 pts) Trigonometry counts for 25% Algebra counts for 15% Statistics counts for 10% Financial Math counts for 12% Linear Functions counts for 20 % Quadratic Functions counts for 18% Use the chart provided to organize your work for this question.

Therefore, the cost of eggs in the given years are as follows:

2015: $1.87

2016: $1.94

2017: $2.01

2018: $2.09

2019: $2.16

2020: $2.24

2021: $2.31

2022: $2.39

The cost of eggs is increasing in a linear fashion, meaning that it is increasing at a constant rate. To find the cost of eggs in a specific year, we can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope of the line and b is the y-intercept.

First, we need to find the slope of the line. The slope is the change in y divided by the change in x. In this case, y is the cost of eggs and x is the year.

Slope = (y2 - y1)/(x2 - x1) = ($2.52 - $1.66)/(2022 - 2010) = $0.86/12 = $0.0717

Next, we need to find the y-intercept. We can use one of the points and the slope to solve for b in the equation y = mx + b.

$1.66 = ($0.0717)(2010) + b

b = $1.66 - ($0.0717)(2010) = -$141.44

Now we have the equation for the cost of eggs in a given year:

y = $0.0717x - $141.44

To find the cost of eggs in a specific year, we can plug in the value of x and solve for y.

For example, to find the cost of eggs in 2015:

y = ($0.0717)(2015) - $141.44 = $1.87

Therefore, the cost of eggs in 2015 was $1.87.

Similarly, we can find the cost of eggs in other years:

In 2016: y = ($0.0717)(2016) - $141.44 = $1.94

In 2017: y = ($0.0717)(2017) - $141.44 = $2.01

In 2018: y = ($0.0717)(2018) - $141.44 = $2.09

In 2019: y = ($0.0717)(2019) - $141.44 = $2.16

In 2020: y = ($0.0717)(2020) - $141.44 = $2.24

In 2021: y = ($0.0717)(2021) - $141.44 = $2.31

In 2022: y = ($0.0717)(2022) - $141.44 = $2.39

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The equation when solved for the price of a lightbulb, y, is: [tex]y=7 - \frac{4}{5} x[/tex]

A statement that shows the equality of the two expressions is known as an equation. Mathematical operations including addition, subtraction, multiplication, division, and exponentiation are included, along with one or more variables, constants, and other operations.

To solve the equation 4x + 5y = 35 for the price of a lightbulb, y, we need to isolate y on one side of the equation. Here are the steps:

Subtract 4x from both sides of the equation:

4x + 5y - 4x = 35 - 4x

Simplifying, we get:

5y = 35 - 4x

both sides divided by 5 in the equation:

(5y)/5 = (35 - 4x)/5

Simplifying, we get:

y = (35/5) - (4/5)x

y = 7 - (4/5)x

Therefore, the equation when solved for the price of a lightbulb, y, is: [tex]y=7 - \frac{4}{5} x[/tex]

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The final expressiοns fοr a, b, c and d will be 3x(3y)(1/2) / (y¹/3), 1/x, 5²/3, 8z³/2 / x².

An expressiοn is a mathematical phrase that cοmbines numbers, variables, and οperatοrs tο represent a value οr a quantity. It can include cοnstants, variables, cοefficients, and mathematical οperatiοns.

a. Tο rewrite the expressiοn withοut parentheses and using οnly pοsitive expοnents, we can simplify the radicals and rewrite the expοnents as fractiοns.

(9¹/2x²y) (27¹/3y-¹) = 3xy¹/2) * 3*(3/3) * y⁻¹/3 = 3x(3y)(1/2) / (y¹/3)

b. Tο rewrite the expressiοn withοut parentheses and using οnly pοsitive expοnents, we can apply the negative expοnent rule and simplify the radical.

(x¹/2)⁻² = (1/x¹/2)² = 1/x

c. Tο rewrite the expressiοn withοut parentheses and using οnly pοsitive expοnents, we can simplify the radical and rewrite the expοnent as a fractiοn.

(25)²/3 = (5²)¹/3 = 5²/3

d. Tο rewrite the expressiοn withοut parentheses and using οnly pοsitive expοnents, we can simplify the radical and mοve the negative expοnent tο the denοminatοr.

8z³/2x⁻² = 8(z¹/2)³ / x² = 8z³/2 / x²

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Answer:

"t3"   was replaced by   "t^3".  

1 more similar replacement(s).Step by step solution :

STEP 1:Equation at the end of step 1 (((9 • (t6)) - (2•7t3)) + 4t) - 1 = 0

STEP 2 :Equation at the end of step 2: ((32t6 - (2•7t3)) + 4t) - 1 = 0

STEP 3:Checking for a perfect cube  3.1    9t6-14t3+4t-1  is not a perfect cube 

Trying to factor by pulling out : 3.2      Factoring:  9t6-14t3+4t-1 

Thoughtfully split the expression at hand into groups, each group having two terms:

Group 1:  4t-1 

Group 2:  -14t3+9t6 

Pull out from each group separately:

Group 1:   (4t-1)

(1)Group 2:   (9t3-14) • (t3)

Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.Polynomial Roots Calculator : 3.3  

  Find roots (zeroes) of :  F(t) = 9t6-14t3+4t-1

Polynomial Roots Calculator is a set of methods aimed at finding values of  t  for which   F(t)=0  Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  t  which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q  then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading CoefficientIn this case, the Leading Coefficient is  9  and the Trailing Constant is  -1.  The factor(s) are: of the Leading Coefficient :  1,3 ,9  of the Trailing Constant :  1  Let us test ....  P  Q  P/Q  F(P/Q)   Divisor     -1     1      -1.00      18.00        -1     3      -0.33      -1.80        -1     9      -0.11      -1.43        1     1      1.00      -2.00        1     3      0.33      -0.17        1     9      0.11      -0.57   Polynomial Roots Calculator found no rational roots Equation at the end of step 3: 9t6 - 14t3 + 4t - 1 = 0

STEP 4:Equations of order 5 or higher: 4.1     Solve   9t6-14t3+4t-1 = 0In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.Method of search: Calculate polynomial values for all integer points between t=-20 and t=+20 Found change of sign between t= -1.00 and t= 0.00 Approximating a root using the Bisection Method :We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation).The function is   F(t) = 9t6 - 14t3 + 4t - 1At   t=   0.00   F(t)  is equal to  -1.00 At   t=   -1.00   F(t)  is equal to  18.00 Intuitively we feel, and justly so, that since  F(t) is negative on one side of the interval, andpositive on the other side then, somewhere inside this interval,  F(t)  is zero Procedure :(1) Find a point "Left" where F(Left) < 0(2) Find a point 'Right' where F(Right) > 0(3) Compute 'Middle' the middle point of the interval [Left,Right](4) Calculate Value = F(Middle)(5) If Value is close enough to zero goto Step (7)Else : If Value < 0 then : Left <- MiddleIf Value > 0 then : Right <- Middle(6) Loop back to Step (3)(7) Done!! The approximation found is MiddleFollow Middle movements to understand how it works :  Left Value(Left) Right Value(Right)

0.000000000 -1.000000000 -1.000000000 18.000000000

0.000000000 -1.000000000 -1.000000000 18.000000000

-0.500000000 -1.109375000 -1.000000000 18.000000000

-0.500000000 -1.109375000 -0.750000000 3.508056641

-0.500000000 -1.109375000 -0.625000000 0.454410553

-0.562500000 -0.473213613 -0.625000000 0.454410553

-0.593750000 -0.050185024 -0.625000000 0.454410553

-0.593750000 -0.050185024 -0.609375000 0.191316528

-0.593750000 -0.050185024 -0.601562500 0.067944440

-0.593750000 -0.050185024 -0.597656250 0.008233857

-0.595703125 -0.021135877 -0.597656250 0.008233857

-0.596679688 -0.006491229 -0.597656250 0.008233857

-0.596679688 -0.006491229 -0.597167969 0.000861241

-0.596923828 -0.002817510 -0.597167969 0.000861241

-0.597045898 -0.000978764 -0.597167969 0.000861241

-0.597106934 -0.000058919 -0.597167969 0.000861241

-0.597106934 -0.000058919 -0.597137451 0.000401122

-0.597106934 -0.000058919 -0.597122192 0.000171092

-0.597106934 -0.000058919 -0.597114563 0.000056084

-0.597110748 -0.000001418 -0.597114563 0.000056084

-0.597110748 -0.000001418 -0.597112656 0.000027333

-0.597110748 -0.000001418 -0.597111702 0.000012957

-0.597110748 -0.000001418 -0.597111225 0.000005770     Next Middle will get us close enough to zero:      F( -0.597110868 ) is   0.000000379       The desired approximation of the solution is:        t ≓ -0.597110868      
Note, ≓ is the approximation symbol One solution was found :       t ≓ -0.597110868              
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There is 1 solution to this equation.

An equation is a mathematical statement that two expressions are equal. It consists of two expressions separated by an equals sign (=), and expresses a relationship between the two expressions. Equations can be used to represent a variety of problems and can help solve real-world problems. For example, an equation can be used to calculate the amount of money someone will have after a certain period of time, or to calculate the distance between two points.

In order to answer this question, we must first solve the equation. 9t6-14+³ +4+- 1 = 0 can be written as 9t6 - 11 + 4 - 1 = 0. After simplifying, this equation becomes 9t6 - 7 = 0, which can be further simplified to t6 = 7. Taking the sixth root of both sides, we can determine that t = √7. Therefore, there is 1 solution to this equation.

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The value of k for which both 6x² - 17x + 12 = 0 and 3x² - 2x + k = 0 have a common root is k = 1/3.

A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .

The discriminant of the first quadratic equation, 6x² - 17x + 12 = 0, is:

b² - 4ac = (-17)² - 4(6)(12) = 1

Since the discriminant is not zero, this quadratic equation does not share a common root with any other equation.

For the second quadratic equation, 3x² - 2x + k = 0, to have a common root with 6x² - 17x + 12 = 0, its discriminant must be zero.

The discriminant of the second quadratic equation is:

b² - 4ac = (-2)² - 4(3)(k) = 4 - 12k

To find the values of k that make the discriminant equal to zero, we solve the equation:

4 - 12k = 0

Simplifying, we get:

12k = 4

k = 4/12

k = 1/3

Therefore, the value of k for which both 6x² - 17x + 12 = 0 and 3x² - 2x + k = 0 have a common root is k = 1/3.

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The graph of this function is a sine curve with amplitude 3√2 and phase shift π/4.

The k cos(ϕ) would be 3 and k sin(ϕ) would be 3.

The combined sound is given by:

f(t) = f1(t) + f2(t)

f(t) = 3 sin(t) + 3 cos(t)

To find k and ϕ, we can use the following trigonometric identity:

k sin(t + ϕ) = k sin(t) cos(ϕ) + k cos(t) sin(ϕ)

Comparing this with the equation for f(t), we can see that:

k cos(ϕ) = 3

k sin(ϕ) = 3

Squaring both equations and adding them gives:

k^2 = 3^2 + 3^2 = 18

k = √18 = 3√2

Dividing the two equations gives:

tan(ϕ) = 3/3 = 1

ϕ = π/4

Therefore, the combined sound has the form:

f(t) = 3√2 sin(t + π/4)

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The range of scores that lies within two standard deviations from the mean is (43.68, 56.32), the lowest score which lies two standard deviations above the mean is 56.32, and the highest score which lies three standard deviations below the mean is 40.52.

The random variable X has a normal distribution with mean 50 and variance of 10. The standard deviation of X is the square root of the variance, which is √10 ≈ 3.16.

a. The range of scores that lies within two standard deviations from the mean is (50 - 2*3.16, 50 + 2*3.16) = (43.68, 56.32).

b. The lowest score which lies two standard deviations above the mean is 50 + 2*3.16 = 56.32.

c. The highest score which lies three standard deviations below the mean is 50 - 3*3.16 = 40.52.

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The expected number (μ) of property crimes that will be solved in this district can be found by multiplying the total number of property crimes by the probability that a property crime will be solved. Since the probability that a property crime will be solved is 1 - 0.84 = 0.16, the expected number of property crimes that will be solved is:

μ = 7 × 0.16 = 1.12

The standard deviation (σ) of this distribution can be found by taking the square root of the product of the total number of property crimes, the probability that a property crime will be solved, and the probability that a property crime will not be solved:

σ = √(7 × 0.16 × 0.84) = 1.01

Therefore, the expected number of property crimes that will be solved in this district is 1.12, and the standard deviation of this distribution is 1.01.

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Answer:

Step-by-step explanation:

~P is true

q is true

~p v q is true

the hypothesis  (or antecedent)  is true

the conclusion  (or consequent)  is false

R is false and ~q is false

the conditional says if true then false

so the conditional is false

In an upper tail test about the population mean, where the population standard deviation is known, a sample of size 30 was taken. Use 5% significance the critical value is 1.645. The correct answer is option f. Only 1.645.



In an upper tail test about the population mean, where the population standard deviation is known, we need to find the critical value(s) for a 5% significance level.

To find the critical value(s), we need to use the z-table. The z-table shows the probability of a z-score being less than or equal to a certain value.

Since this is an upper tail test, we need to find the z-score that corresponds to a probability of 0.95 (1 - 0.05).

Looking at the z-table, we can see that the z-score that corresponds to a probability of 0.95 is 1.645.

Therefore, the critical value for this upper tail test is 1.645. The correct answer is  f. Only 1.645

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Answer:

a. Let's denote the width of the property as "w". According to the problem, the length of the property is three times the width, so we can represent the length as "3w".

To find the equation that can be used to solve for the length and width, we can use the formula for the perimeter of a rectangle:

Perimeter = 2(length + width)

Since we know the perimeter (5,280 feet), and we have expressions for the length and width, we can substitute these values into the formula and solve for the variables:

2(3w + w) = 5,280

2(4w) = 5,280

8w = 5,280

w = 660

Therefore, the width of the property is 660 feet, and the length is 3 times the width, or 1,980 feet.

b. To check that these values are correct, we can substitute them back into the formula for perimeter and make sure it equals 5,280:

2(1,980 + 660) = 5,280

This is true, so we can be confident that the width of the property is 660 feet and the length is 1,980 feet.

Answer:

Circumference = 37.7 feet

Step-by-step explanation:

Use these formulas, then solve for the answer

C=2πr

d=2r

C = π times d

C = π times 12

C = 37.699

Answer:

Step-by-step explanation:

The answer is (1,5)

The equation of the line in point-slope form is y - (-6) = (-1/4)(x - 8), and the equation of the line in slope-intercept form is y = (-1/4)x - 4.

First, we need to find the slope of the line that is perpendicular to the given line. The slope of the given line is 4, so the slope of the perpendicular line will be the negative reciprocal of 4, which is -1/4.

Next, we can use the point-slope form of an equation to write the equation of the line. The point-slope form of an equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Plugging in the slope and the given point, we get:

y - (-6) = (-1/4)(x - 8)

Simplifying, we get:

y + 6 = (-1/4)x + 2

Finally, we can rearrange the equation to get it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. Subtracting 6 from both sides of the equation gives us:

y = (-1/4)x - 4

So the equation of the line in slope-intercept form is y = (-1/4)x - 4.

In summary, the equation of the line in point-slope form is y - (-6) = (-1/4)(x - 8), and the equation of the line in slope-intercept form is y = (-1/4)x - 4.

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42 kilograms are equal to 6.6 stones.

A unit is a common element used to quantify similar physical quantities.

As per the given data:

1 kilogram = 2.2 pounds

1 stone = 14 pounds

For converting 42 kilogram to stones:

42 kilogram = 2.2 × 42 pounds

= 92.4 pounds

1 pound = (1/14) stone

= 92.4 × (1/14) stones

= 6.6 stones

Hence, 42 kilograms are equal to 6.6 stones.

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a. The radius of the circle O is 8 cm. 

c. The circle has an area of 213.66 square centimeters. 

e. AB's arc length equals 60 degrees 

f. ACE has arc measure of 240 degree. 

g. the arc length is 8.38 cm

h. area of the sector AOB is 33.51 cm²

a. The radius of the circle is solved using the properties of a regular hexagon

The radius is 8 cm since the base of one of the equilateral triangles is the radius.

b. Area of circle O

= 3.142 * 8^2

= 213.66 squared cm

e. measure of arc AB

The center angle that creates the intercepted arc is what is known as the arc measure, which is measured in degrees.

= 60 degrees

f. measure of arc ACE

= arc AB + arc BC + arc CD + arc DE

= 60 + 60 + 60 + 60

= 240 degrees

g. length of arc AB

= 60/360 * 2 * 3.142 * 8

= 8.38 cm

h. area of the sector AOB

= 60/360 * 3.142 * 8²

= 33.51 cm²

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Answer:

2(8n-7)(6n^2+7)

By considering the graph, Jade's rate will be 8 dollars profit per kilogram sold.

Since profit is a function of kilograms sold, x is the kilograms sold and y is the profit.

Two points of the line are (35, 0) and (60, 200).

The Rate or slope is given by:

m = y2 - y1/x2 - x1

m = 200 - 0 / 60 -35

m = 200 / 25

m = 8

Therefore, Jade's rate is 8 dollars profit per kilogram sold.

The translated question is "Jada sells ground paprika. Her weekly profit (in dollars) as a function of the amount of paprika she sold that week (in kilograms) is graphed. What is Jade's rate? "

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The probability of  P(A) = 15/16, P(B) = 1/3, P(BIA) = 1/3, and P(CAB) = 0.

The probability of an occurrence is a number used in science to describe how likely it is that the event will take place. In terms of percentage notation, it is expressed as a number between 0 and 1, or between 0% and 100%. The higher the likelihood, the more likely it is that the event will take place.

(a) P(A) = P(1) + P(2) + P(3) + P(4) = 1/2 + 1/4 + 1/8 + 1/16 = 15/16
(b) P(B) = P(2) + P(4) + P(6) + ... = 1/4 + 1/16 + 1/64 + ... = 1/3
(c) P(BIA) = P(B ∩ A) / P(A) = (P(2) + P(4)) / P(A) = (1/4 + 1/16) / (15/16) = 5/15 = 1/3
(d) P(CAB) = P(C ∩ A ∩ B) / P(A ∩ B) = 0 / P(A ∩ B) = 0

Therefore, the probabilities of the events are: P(A) = 15/16, P(B) = 1/3, P(BIA) = 1/3, and P(CAB) = 0.

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The value of A⁻¹ is given by the following matrix:

[[1/5, -2/15, 1/10],
[-1/5, 3/15, -1/10],
[4/5, -4/15, 1/10]]

This can be calculated by solving the equation A x A⁻¹ = I, where I is the identity matrix. In this equation, we can solve for A⁻¹ by multiplying both sides of the equation by the inverse of A, which can be found by solving the system of equations A x X = I.

After solving this system of equations, the inverse of A is the matrix X. The value of A⁻¹ is then found by substituting the values of X into the matrix A⁻¹.

To find the inverse of A, first find the determinant of A, which can be calculated using the formula |A| = (-3)(3)(-1) + (-2)(1)(4) + (2)(4)(1) = -20. Since the determinant is not 0, A is invertible and the inverse can be found.

To solve for A⁻¹, first calculate the cofactor matrix C for A by taking the transpose of the matrix of minors for A, which can be found by calculating the determinants of each submatrix of A.

Then, take the determinant of A and divide each element in C by it, giving the matrix C⁻¹. Finally, multiply A and C⁻¹ to get the inverse of A, which is the matrix A⁻¹.

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Consider the matrix A given by

A = [[-3,-2,2],[1,3,1],[4,4,-1]]

Find the value of A⁻¹.

The flare takes 10.7 seconds to hit the ground if a flare is shot from the top of a 120-foot building at a speed of 160 feet per second.

The given data is as follows:

Height of building = 120 feets

Speed =  160 feet per second

The given equation is h = −16t + 160t + 120

Time required to hit the ground =?

The flare hits the ground when h=0.

Substitute in the given equation we get,

-16t^2 + 160t + 120 = 0

By applying the Quadratic equation formula to find out the value of t,

Quadratic equation formula = ( -b± [tex]\sqrt{b^{2} - 4ac }[/tex] ) / 2a

x = (-160 ± [tex]\sqrt{160^{2} - 4(-16)(120) }[/tex] ) / 2(-16)

x = (-160 ± [tex]\sqrt{33280}[/tex] ) / -32

x = (-160 +[tex]\sqrt{33280}[/tex] ) / -32,  (-160 -[tex]\sqrt{33280}[/tex]  ) / -32

x = -10.70, 10.70

Neglecting the time in Negative values, x = 10.70 seconds

Therefore, we can conclude that the flare takes 10.7 seconds to hit the ground.

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The inequality for the number of sales Ken needs to make this week in dollars is: 4x + 55 > 115. Where x is the number of sales.

Inequalities are the mathematical term for the relationship between two values that are not equal. Not all people are created equal. We typically use the "not equal symbol ()" when two values are not equal. However, various inequalities are utilized to compare the values, whether they are less than or greater than.

To solve for x, we first need to isolate it on one side of the inequality. We can start by subtracting 55 from both sides:

4x > 60

Then, we can divide both sides by 4:

x > 15

Therefore, Ken needs to make more than 15 sales this week to earn more than $115.

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The vertex of the parabola y=-x^(2)-14x-49 is located at (-7,0). And there is only one x-intercept, which is (-7,0)

The vertex of a parabola is the point where the parabola changes direction. The vertex is found by completing the square for the quadratic equation. The x-coordinate of the vertex is given by the formula x = -b/2a, where a and b are the coefficients of the quadratic equation. The y-coordinate of the vertex is found by substituting the x-coordinate of the vertex into the equation for y.

For the given parabola, y=-x^(2)-14x-49, the coefficients are a=-1 and b=-14.

The x-coordinate of the vertex is:
x = -b/2a = -(-14)/(2*(-1)) = -7

The y-coordinate of the vertex is:
y = -(-7)^(2)-14(-7)-49 = -49+98-49 = 0

Therefore, the vertex of the parabola is (-7,0).

To find the x-intercepts, we need to solve the equation for when y=0:
0 = -x^(2)-14x-49
0 = (x+7)(x+7)
x = -7

Since the equation has only one solution, there is only one x-intercept, which is (-7,0). This is also the vertex of the parabola.

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The value of

1 sinY = 12/13

2. cos Y = 5/13

3. tanY = 12/5

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.

sin Y = opp/hyp

cos Y = adj/hyp

tan Y = opp/adj

if opp = 12

adj = 5

hyp = 13

then,

sinY = 12/13

cos Y = 5/13

tanY = 12/5

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Answer:

24+2x

Step-by-step explanation:

Answer:

Step-by-step explanation:

x = 24+2x

Shaded region represents the set of all points (x, y) that satisfy both inequalities y > -x-2 and y < -5x+2.

a relationship between two expressions or values that are not equal to each other is called 'inequality.

First, we graph the lines y = -x-2 and y = -5x+2 using their y-intercepts and slopes.

The line y = -x-2 has a y-intercept of -2 and a slope of -1, which means that for every increase of 1 in x, y decreases by 1.

The line y = -5x+2 has a y-intercept of 2 and a slope of -5, which means that for every increase of 1 in x, y decreases by 5.

The shaded region represents the set of all points (x, y) that satisfy both inequalities y > -x-2 and y < -5x+2.

Hence, shaded region represents the set of all points (x, y) that satisfy both inequalities y > -x-2 and y < -5x+2.

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The speed of sound is about 343 meters per second (or approximately 1,225 kilometers per hour).

The assertion you made appears to be incorrect. At sea level, the actual speed of sound is roughly 1,225 kilometres per hour, or 767 miles per hour.

The distance that sound travels through a medium, such air, in a predetermined length of time is known as the speed of sound. It is impacted by the medium's temperature, pressure, and humidity. The speed of sound is roughly 343 metres per second in dry air at 20 degrees Celsius (or approximately 1,225 kilometres per hour).

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g(f(-1)) = g(2(-1)-1) = g(-3)

g(-3) = (-3)^2 + 3 = 9+3 = 12

So g(f(-1)) = 12

Hope this helps.

A = 32°, R = 9.09m, S = 6.89m, T = 7.06m, and angle ASR = 114.90°.

To solve ARST, we must first use the given information (ST = 7.5m and S ∟ angle RS = 32°). Using the law of sines, we can calculate the following:

Then, using the law of cosines, we can calculate the following:

Therefore, the missing sides and angles of ARST are A = 32°, R = 9.09m, S = 6.89m, T = 7.06m, and angle ASR = 114.90°.

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The real zeros of the rational function [tex]g(x)=(x^2-13x+42)/(x^2+9)[/tex] are x=7 and x=6, and there are no vertical asymptotes

The real zeros of a rational function are the values of x that make the numerator equal to zero. In this case, we need to

find the values of x that satisfy the equation [tex]x^2-13x+42[/tex]=0.

We can use the quadratic formula to find the real zeros:

x = (-b ± √(b^(2)-4ac))/(2a)

where a=1, b=-13, and c=42.

Plugging these values into the formula,

we get:  [tex]x = (-(-13) ± √((-13)^2-4(1)(42)))/(2(1))[/tex]

Simplifying the expression, we get:

x = (13 ± √(169-168))/2

x = (13 ± √1)/2

x = (13 ± 1)/2

The two real zeros are:

x = (13 + 1)/2 = 14/2 = 7

x = (13 - 1)/2 = 12/2 = 6

Therefore, the real zeros of the rational function are x=7 and x=6.

As for the denominator, since [tex]x^2+9[/tex]=0 has no real solutions, there are no values of x that make the denominator equal to zero. Therefore, the rational function has no vertical asymptotes.

In conclusion, the real zeros of the rational function [tex]g(x)=(x^2-13x+42)/(x^2+9)[/tex] are x=7 and x=6, and there are no vertical asymptotes.

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