What is the weight of Jim's dog? Jim's dog is
lbs *
1 pc
16.23 lb
Weight of John's Dog
Weight of Jim's Dog
?
?

Answer: D

Step-by-step explanation:

the distance is 90m and the time is max 3 to goal so the answer is D

Answer:

3

Step-by-step explanation:

Answer:

3/4 and 2/3....different denominators.....common denominator is 12

Answer:

C.) 109/11

Step-by-step explanation:

because I am on the exam right now

9514 1404 393

Answer:

  18 eagles

Step-by-step explanation:

Assuming Julie went bird-watching on each of those 6 days, she saw a total of ...

  (3 eagles/day)(6 day) = 3·6 eagles = 18 eagles

Answer:

GCF = 7

hope this helps

Answer:

:)

Step-by-step explanation:

21 = 3 • 7,  35 = 5 • 7, 49 = 72

go add the snap carmel.bratz

Answer:

0

Step-by-step explanation:

24z + 12 = 24z + 12

0z = 0

0

Answer:

many solutions or infinite solutions

Step-by-step explanation:

12(2z + 1) = 3(8z + 4)

ok simplify it

24z + 12 = 24z + 12

there's many solutions no matter what you do you'll end out in this

Answer:

b.0.65

Step-by-step explanation:

i think it is I'm sorry if it's not

Answer:

b. 0.65

Step-by-step explanation:

Answer:

Directions: Write the name and composition of the following composer/s below. Space provided for your answer.

Step-by-step explanation:

I hope this answer is Wright

Answer:

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Step-by-step explanation:

Solution:

Suppose grade breakdown for certain college course is as follow:

Homework = 15%

Quizzes = 20%

Project = 10%

Test = 40%

Final exam= 15%

Let G represent the final grade

H represents homework average,

Q represents quizzes and P represent project, T represent test average and F represent final exam.

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Answer:

Step-by-step explanation:

The quadratic factors into (x + 4)(x + 2) When you remove the brackets, you get

x^2

2x

4x

8

They are all added and the 2x and 4x combine to get 6x.

Answer:

F (x) = x^2 + 6x+8 = F = x + 6 + [tex]\frac{8}{x}[/tex]

Step-by-step explanation:

Move all the expressions to the left side of the equation.

F(x)−x2−6x−8=0

Multiply F by x.

Fx−x2−6x−8=0

Move all terms not containing F to the right side of the equation.

Fx=x2+6x+8

Divide each term by x and simplify.

F = x + 6 + [tex]\frac{8}{x}[/tex]

I hope this helps.

Answer:

0.8

Step-by-step explanation:

6/10=0.6

0.6/3=0.2

0.2*4=0.8

I hope it's correct

Given equation : 3x² - 4 = 2x

We have to find discriminant of the equation [tex].[/tex]

⭆ 3x² - 4 = 2x

⭆ 3x² - 2x - 4 = 0

By comparing this equation with ax²+bx+c, we get

Discriminant (D) = b² - 4ac

⭆ D = (-2)² - 4(3)(-4)

⭆ D = 4 + 48

⭆ D = 52

Step-by-step explanation:

4x +8=-12 is the answer

Answer:

c = $35 + $0.23m

Step-by-step explanation:

The expression is c = $35 + $0.23m

c is the cost of nadya's bill

m is the additional minutes

so if she uses more than 200 minutes the cost of her bill wiil be

$35 plus $0.23 multiply by the number of extra minutes spent.

Answer: I think the answer is b

Step-by-step explanation:

Answer:

Nut

Step-by-step explanation:

nut

Answer:

a) 45 g

b) greater (make the graph youself on desmos or something)

c) 9/4

Step-by-step explanation:

area = integral 0 to 3 of x^2 dx = [1/3x^3] 0 to 3 = 9

mass = density * area = 5 * 9 = 45 grams

area = y*deltax = x^2*deltax

x = integral 0 to 3 of 5x^3 dx / mass = (405/4) / 45 = 9/4

Answer:233/6

Step-by-step explanation:

385/6=233

Answer:

The answer is 3.8 and 2.5

Step-by-step explanation:

Lol

Answer:

(4 (x^4 - 20 x^2 - 12))/(3 x^2 (9 x^2 - 32 x - 144))

Step-by-step explanation:

Simplify the following:

(x^2 + x - x - 20 - 12/x^2)/((15 x^2)/4 + 3 x^2 - 24 x - 60 - 48)

Hint: | Put the fractions in x^2 + x - x - 20 - 12/x^2 over a common denominator.

Put each term in x^2 + x - x - 20 - 12/x^2 over the common denominator x^2: x^2 + x - x - 20 - 12/x^2 = x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2:

(x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | Combine x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2 into a single fraction.

x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2 = (x^4 + x^3 - x^3 - 20 x^2 - 12)/x^2:

((x^4 + x^3 - x^3 - 20 x^2 - 12)/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | Group like terms in x^4 + x^3 - x^3 - 20 x^2 - 12.

Grouping like terms, x^4 + x^3 - x^3 - 20 x^2 - 12 = x^4 - 20 x^2 - 12 + (x^3 - x^3):

(x^4 - 20 x^2 - 12 + (x^3 - x^3))/(x^2 ((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48))

Hint: | Look for the difference of two identical terms.

x^3 - x^3 = 0:

((x^4 - 20 x^2 - 12)/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | In (45 x^2)/12, the numbers 45 in the numerator and 12 in the denominator have gcd greater than one.

The gcd of 45 and 12 is 3, so (45 x^2)/12 = ((3×15) x^2)/(3×4) = 3/3×(15 x^2)/4 = (15 x^2)/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2/4 + 3 x^2 - 24 x - 60 - 48))

Hint: | Put the fractions in (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 over a common denominator.

Put each term in (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 over the common denominator 4: (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 = (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4)

Hint: | Combine (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4 into a single fraction.

(15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4 = (15 x^2 + 12 x^2 - 96 x - 240 - 192)/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2 + 12 x^2 - 96 x - 240 - 192)/4)

Hint: | Group like terms in 15 x^2 + 12 x^2 - 96 x - 240 - 192.

Grouping like terms, 15 x^2 + 12 x^2 - 96 x - 240 - 192 = (12 x^2 + 15 x^2) - 96 x + (-192 - 240):

(x^4 - 20 x^2 - 12)/(x^2 ((12 x^2 + 15 x^2) - 96 x + (-192 - 240))/4)

Hint: | Add like terms in 12 x^2 + 15 x^2.

12 x^2 + 15 x^2 = 27 x^2:

(x^4 - 20 x^2 - 12)/(x^2 (27 x^2 - 96 x + (-192 - 240))/4)

Hint: | Evaluate -192 - 240.

-192 - 240 = -432:

(x^4 - 20 x^2 - 12)/(x^2 (27 x^2 - 96 x + -432)/4)

Hint: | Factor out the greatest common divisor of the coefficients of 27 x^2 - 96 x - 432.

Factor 3 out of 27 x^2 - 96 x - 432:

(x^4 - 20 x^2 - 12)/(x^2 (3 (9 x^2 - 32 x - 144))/4)

Hint: | Write ((x^4 - 20 x^2 - 12)/x^2)/((3 (9 x^2 - 32 x - 144))/4) as a single fraction.

Multiply the numerator by the reciprocal of the denominator, ((x^4 - 20 x^2 - 12)/x^2)/((3 (9 x^2 - 32 x - 144))/4) = (x^4 - 20 x^2 - 12)/x^2×4/(3 (9 x^2 - 32 x - 144)):

Answer: (4 (x^4 - 20 x^2 - 12))/(3 x^2 (9 x^2 - 32 x - 144))

Answer:

4/7

Step-by-step explanation:

there are 7 shapes in total, 4 of them are hexagons.

Answer:

14. 24    20. 9

15. 26    21.  -1

16. -4     22. 6

17. 2      23. 6

18. -7     24. 3x +5

19. 42    25. 9b^2 - 3b

Answer:

She drove 384 miles, because 48 x 8 = 384! :)

Step-by-step explanation:

The distance driven by krista is 384 miles.

If the object is going linearly, and at constant speed, then the speed of that object is given by the distance it traveled to the time it took to travel that distance.

If the object traveled D distance in T units time, then that object's speed is

[tex]Speed = S = \dfrac{\: Distance \: traveled}{\: Time \: taken} = \dfrac{D}{T} \: \rm unit \: length/unit \: time[/tex]

Given;

       speed = 48 miles per hour

       time = 8 hours

Speed= distance/time

           distance= speed x time

                          = 48 x 8

                           = 384 miles

Krista drove 384 miles of distance in 8 hours.

Learn more about distance here;

https://brainly.com/question/7359669

#SPJ6

Answer:

5x - 8

Step-by-step explanation:

Unable to solve completely.

Answer:

8< 5x

Step-by-step explanation:

We know that the 8 is less than 5 times a number, so we first put 8 <.

From here, we have the value 5 being multiplied by a number, that number can be any variable unless that specifically state which variable to use.

Hope this helps! :)

(Side Note: If you're talking about inequalities this should work, if not then I'm sure others will post different answers.)

Answer: (a) = b,  49/64

Step-by-step explanation: