what is the volume of 225 moles of a gas at STP

2.39moles of LiOH are required to produce 165 g of LiNO[tex]_3[/tex]. The mole consists of precisely  6.022×10²³  elementary components.

In the Worldwide System of Units, the mole (sign mol) is indeed the unit of material quantity (SI). The quantity of a substance is a measurement about how many elementary units of a certain substance are present in an object as well as sample.

The mole consists of precisely  6.022×10²³  elementary components.

Cr(NO[tex]_3[/tex])[tex]_3[/tex](aq) + LiOH(aq) → LiNO[tex]_3[/tex](aq) + Cr(OH)[tex]_3[/tex]

moles of LiNO[tex]_3[/tex] = 165/68.94=2.39moles

the mole ratio between LiOH and  LiNO[tex]_3[/tex] is 1:1

moles of  LiNO[tex]_3[/tex] = 2.39moles

Therefore, 2.39moles of LiOH are required to produce 165 g of LiNO[tex]_3[/tex].

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You are so radiant that when is tare at you for too long, it feels as though I'm blinded and unsure of everything so I have to look away- is the best paraphrase

What does the song by Edna St. Vincent Millay mean?

Renascence by Edna St. Vincent Millay is a powerful poetry. The poet ponders issues related to pain, aging, rebirth, and faith. The speaker is followed by the reader throughout "Renascence" as she lives, dies, and then is reborn in a fresh, faithful shape.

Like her colleague Robert Frost, Millay was one of the best sonnetists of the twentieth century. Like Frost, she was able to blend modernist viewpoints with established forms to create a distinctive brand of American poetry.

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The initial concentration is 1.8 * 10^36 M.

The stoichiometry is 2A ⇒ B

The rate of disappearance of H2O2 is 4 mol/min

It decreases adhesion and increases cohesion

Not predictable since it can be at any level.

In a decomposition reaction, a single reactant breaks down into two or more products. The order of a decomposition reaction depends on the rate at which the reaction occurs with respect to the concentration of the reactant.

Given that;

ln[A] = ln[A]o - kt

ln(0.0015) = ln[A]o - (0.025 * 60 * 60)

-6.5 = ln[A]o - 90

-6.5 + 90 = ln[A]o

83.5 = ln[A]o

[A]o = e^83.5

[A]o = 1.8 * 10^36 M

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Answer:

Explanation: K+ has a higher ionisation energy than Ca+ , so K has a higher second ionisation energy than Ca .

The balanced equation for the following chemical reactions are:

a. 2Hg(NO₃)₂(s) → 2Hg(l) + 2NO₂(g) + O₂(g)

b. Ca₃(PO₄)₂(aq) + 2H₃PO₄(aq) → 3Ca(H₂PO₄)₂(aq)

c. 3NaOH(aq) + FeCl₃(aq) → Fe(OH)₃(s) + 3NaCl(aq)

A chemical reaction is balanced when the number of atoms of each element in the reactants equals the number of atoms of that element in the products. In other words, the law of conservation of mass is satisfied.

This means that no atoms are created or destroyed during a chemical reaction, they are only rearranged to form different molecules. To balance a chemical equation, coefficients are added in front of the chemical formulas to adjust the number of atoms of each element.

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Explanation:

Refer to pic...........

Answer: Your welcome!

Explanation:

Paragraph 1:

The atmosphere is composed of several layers, each with their own distinct characteristics. The closest layer to the earth is the troposphere which is about 10 miles above the surface of the earth. This layer is where we find most of our weather, temperature changes, and air pollution. The next layer is the stratosphere, which extends from 10 to 50 miles above the earth. This layer is known for its stable temperature and air pressure, as well as its concentration of ozone which absorbs much of the sun's ultraviolet radiation. At the top of the stratosphere is the mesosphere which extends to about 55 miles above the earth. This layer is known for its cold temperatures, making it the perfect place for meteoroids to burn up as they enter the atmosphere. Finally, the thermosphere extends from 55 to 400 miles above the earth, and is known for its extremely high temperatures, allowing for the aurora borealis to be visible here.

Paragraph 2:

To create a model of the atmosphere, one can use colored posterboard to represent the different layers. For example, the troposphere could be colored green to represent the air and clouds while the stratosphere could be colored blue to represent the ozone layer. The mesosphere could be colored orange to represent the burning of meteoroids, and the thermosphere could be colored purple to represent the aurora borealis. For each layer, one could provide a legend telling what each color represents, as well as a note about a special feature of each layer such as the activities that occur in each layer or the objects that can be seen in each layer. Additionally, one could provide the average temperature or temperature range of each layer, as well as how many miles from Earth each layer extends.

Paragraph 3:

Overall, creating a model of the atmosphere is an interesting and educational activity. By representing each layer in a different color, one can learn more about the different characteristics of each layer and how they relate to one another. Additionally, by providing a legend and notes about special features of each layer, one can gain a better understanding of the atmosphere and its components. Through this model, one can gain a better appreciation of the atmosphere and how it functions to protect our planet.

The classification of stars by astronomers helps them to better comprehend the various kinds of stars that exist in our galaxy and the cosmos as a whole.

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Answer:

D

Explanation:

Transfer of electrons from Na to Cl

Na has configuration of 2,8,1 it will lose one electron to Cl with configuration of 2,7 inorder for both to attain an octet configuration

The lines with the arrow that points inwards radiating from the charge from all directions. Therefore, option B is correct.

Electric field is generated by the charged bodies. The electric field lines around a positive charges will always be outward to all directions. The field lines around a negative point charge is always inward from all directions.

At one point, a field line is drawn tangential to the net. As a result, the direction of the electric field at any point is the same as the tangent to the electric field line. Second, the relative strength (magnitude) of the electric field at a point is correlated with the relative density of the field lines around that point. 

Always pointing away from a positive charge and in the direction of a negative point are electric field lines. In actuality, positive charges are where electric fields begin and negative charges are where they end. Field lines never cross one another, too. If they do, it suggests that the electric field there has two directions.

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Answer:

It's a compound.

Pls mrk me brainliest

Answer:

NaCl

Explanation:

a) KCN = Potassium cyanide

b) NaBrO2 = Sodium bromite

c) Sr(OH)2 = Strontium hydroxide

d) CoTe = Cobalt telluride

e) Fe2(CO3)3 = Iron (III) Carbonate

f) Cr(NO3)3 = Chromium(III) nitrate

g) (NH4)2SO3 = Ammonium Sulfite

h) NaH2PO4 = Sodium dihydrogen phosphate

i) KMnO4 = Potassium permanganate

j) Ag2Cr2O7 = Silver dichromate

A chemical molecule known as an ionic compound in chemistry is one that contains ions bound together by the electrostatic forces known as ionic bonding. Despite having both positively and negatively charged atoms, or cations and anions, the compound is generally neutral.

These can be either polyatomic species, like the ammonium (NH+ 4) and carbonate (CO2 3) ions in ammonium carbonate, or straightforward ions, like the sodium (Na+) and chloride (Cl) in sodium chloride.

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The 12g is the maximum amount of solid is dissolved in a solute, ionic solution.

What is solution ?

A steady change in the relative ratios of two or more substances up to the point at which they become homogenous when combined; this point is known as the limit of solubility.

What is solute ?

Solute refers to an object that dissolves in a solution. In fluid solutions, there is a larger concentration of solvent than solute. Salt and water are two excellent examples of substances that we use on a daily basis. Since salt dissolves in water, it serves as the solute.

Therefore, The 12g is the maximum amount of solid is dissolved in a solute, ionic solution.

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It takes approximately 193 g of sodium bromide to make 2.50 litres of 0.750 M NaBr solution.

A substance's molar mass is the mass of one mole. It's measured in grammes per mole (g/mol). The molar mass of an element is equal to its atomic weight in atomic mass units (amu), but the molar mass of a compound is the sum of all the atomic weights in the compound represented in grammes. The idea of molar mass is significant in chemistry because it allows us to convert between mass, moles, and the number of particles in a substance.

We can use the following formula to calculate the mass of sodium bromide required to make the given solution:

mass = moles x molar mass

First, we need to calculate the number of moles of sodium bromide needed:

moles = Molarity x volume

moles = 0.750 mol/L x 2.50 L

moles = 1.875 mol

Next, we need to determine the molar mass of NaBr:

NaBr = 22.99 g/mol + 79.90 g/mol

NaBr = 102.89 g/mol

Finally, we can calculate the mass of NaBr needed:

mass = moles x molar mass

mass = 1.875 mol x 102.89 g/mol

mass = 192.92 g

Therefore, the mass of sodium bromide needed to prepare 2.50 liters of a 0.750 M NaBr solution is approximately 193 g (option C).

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The number of moles of A remaining at the new equilibrium is 1.93 mol.

Partial pressure is the pressure exerted by a single gas component in a mixture of gases, assuming that the other gas components are absent or ideal. In other words, it is the pressure that the gas would exert if it were the only gas in the container at the same volume and temperature.

In a mixture of gases, each gas contributes to the total pressure of the system, which is the sum of the partial pressures of each gas. This is meant to refer to as Dalton's law of partial pressures. The partial pressure of a gas is proportional to its mole fraction in the mixture, which is the ratio of the number of moles of the gas to the total number of moles of all gases in the mixture.

The balanced equation for the reaction is:

A(s) ⇌ B(g) + C(g)

Let's denote the initial amount of A as nA. Since the molar mass of A is not given, we cannot determine its mass directly from the number of moles. However, we know that the initial amount of A is 5.40 moles, so we can write:

nA = 5.40 mol

At equilibrium, the concentration of B is given as 1.40 M. Using the ideal gas law, we can relate the concentration of B to its partial pressure:

PV = nRT

where P is the partial pressure of B, V is the volume of the container, n is the number of moles of B, R is the gas constant, and T is the temperature. Assuming that the volume of the container does not change during the reaction, we can write:

P = nBRT/V

where nB equals the number of moles of B. Since the concentration of B is given as 1.40 M, we have:

nB/V = [B] = 1.40 M

Substituting into the previous equation, we obtain:

P = nBRT/V = (1.40 M)(R)(T)

At equilibrium, the partial pressures of B and C must be equal, so we have:

P = PB = PC

Let's denote the number of moles of B and C as nB and nC, respectively. Since the total number of moles in the system is conserved, we have:

nA = nB + nC

At equilibrium, the number of moles of B is equal to the number of moles of C, so we have:

nB = nC = 0.5(nA)

Substituting into the ideal gas law expression for P, we obtain:

P = PB = PC = nBRT/V = (0.5nA)(R)(T)/V

We can use this equation to calculate the value of P at equilibrium. Then, when the volume of the container is doubled, the new pressure will be:

P' = P/2

At the new equilibrium, the partial pressures of B and C must be equal, so we have:

P' = PB' = PC'

We can use the same logic as before to write:

PB' = PC' = (0.5nA')(R)(T)/(2V)

where nA' is the number of moles of A remaining at the new equilibrium. Setting PB' equal to P' and solving for nA', we obtain:

nA' = nA(P')/(2P) = (5.40 mol)(1/2)/(P/P') = (5.40 mol)(1/2)/(1.40/2) = 1.93 mol

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Precipitation reactions;

2KCl + Pb(NO3)2 ----> PbCl2 + 2KNO3

Ba(NO3)2 + K2SO4 -----> BaSO4 + 2KNO3

Hg2(C2H3O2)2 + 2NaCl -----> Hg2Cl2 + 2NaC2H3O2

Non precipitation reactions

C + O2 ---> CO2

HBr + KOH ----> KBr + H2O

HCl + KOH -----> KCl + H2O

H2O2 + NaOBr ----> NaBr + H2O + O2

A precipitation reaction is a type of chemical reaction that occurs when two aqueous solutions (solutions dissolved in water) are mixed together and form an insoluble solid called a precipitate.

The reaction is characterized by the exchange of ions between the two aqueous solutions, which leads to the formation of the insoluble solid.

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The number of atoms of lithium, Li in 8.1 moles of lithium, Li is 4.88×10²⁴ atoms

From Avogadro's hypothesis, we understood that 1 mole of a substance contains 6.02×10²³ atoms. Thus, we can say that:

1 mole of Li = 6.02×10²³ atoms

With the above information, we can determine the number of atoms in 8.1 moles of lithium, Li. Details below:

1 mole of Li = 6.02×10²³ atoms

Therefore,

8.1 moles of Li = (8.1 mole × 6.02×10²³ atoms) / 1 mole

8.1 moles of Li = 4.88×10²⁴ atoms

Thus, from the above calculation, it is evident that the number of atoms is 4.88×10²⁴ atoms

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Mendel's first generation pea plants with purple flowers would have had two alleles for flower color.

Alleles are different versions or variants of a gene that occupy the same position, or locus, on a chromosome. Each individual inherits two alleles for each gene, one from each parent, which can be either the same (homozygous) or different (heterozygous). These alleles can have different effects on the organism's phenotype (observable trait) and can be dominant or recessive, with dominant alleles masking the expression of recessive ones. For example, in humans, the gene for eye color has different alleles that produce different colors such as brown, blue, or green. The specific combination of alleles that an individual inherits determines their genotype, which in turn influences their phenotype. The study of alleles and their inheritance patterns is a fundamental concept in genetics and has important applications in fields such as medicine, agriculture, and evolutionary biology.

Here,

However, the specific alleles cannot be determined from this information alone. According to Mendel's laws of inheritance, each individual inherits two alleles for each trait, one from each parent. These alleles can be either the same (homozygous) or different (heterozygous). If the two alleles are different, one may be dominant and determine the organism's phenotype (observable trait), while the other may be recessive and not expressed in the phenotype. In the case of Mendel's purple-flowered pea plants, the specific alleles responsible for the purple flower color would have been determined through further experimentation and analysis.

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Hexane, heptane, and octane have molar masses of Hexane (C6H14) has a molecular mass of 6 (12.01 g/mol) and 14 (1.00 g/mol) and heptane (C7H16) has a molecular mass of 7 (12.01 g/mol) and 16 (1.00 g/mol) and 100.21 g/mol.

The mass in grammes of one mole of a chemical is its molar mass.The quantity of atoms, molecules, and ions contained in a substance is measured in terms of moles. A mole of any substance contains 6.022 x 1023 molecules.

Use 100 g of the fuel mixture as an example. Then:

Hexane weight is 28.30 grammes.

15.75 g is the heptane mass.

Octane mass is equal to 100 g, 28.30 g, 15.75 g, and 55.95 g.

The molar masses of hexane, heptane, and octane are:

Molar mass of hexane (C6H14) = 6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

Molar mass of heptane (C7H16) = 7(12.01 g/mol) + 16(1.01 g/mol) = 100.21 g/mol

Molar mass of octane (C8H18) = 8(12.01 g/mol) + 18(1.01 g/mol) = 114.23 g/mol

The number of moles of each component in 100 g of the fuel mixture is:

Moles of hexane = 28.30 g / 86.18 g/mol = 0.3282 mol

Moles of heptane = 15.75 g / 100.21 g/mol = 0.1573 mol

Moles of octane = 55.95 g / 114.23 g/mol = 0.4899 mol

Therefore, the mole fractions of each component are:

Mole fraction of hexane = 0.3282 / (0.3282 + 0.1573 + 0.4899) = 0.3841

Mole fraction of heptane = 0.1573 / (0.3282 + 0.1573 + 0.4899) = 0.1838

Mole fraction of octane = 0.4899 / (0.3282 + 0.1573 + 0.4899) = 0.4321

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The mouthwash is included in 159 bottles, each of which contains about 7.05 kilos of ethanol.

Phenol, 5-methyl-2-(1-methylethyl)-, mixed with 1,3,3-trimethyl-2-oxabicyclo(2.2.2)octane and 5-methyl-2-(1-methylethyl)cyclohexanol. 460.7 molecular weight.

First, we must convert each bottle's mouthwash's pint-to-liter volume:

0.280 pt x 0.4732 L/pt = 0.1324 L

Using the density of the mouthwash in each bottle, we can determine its mass:

0.1324 L x 0.868 g/mL = 0.1149 kg

We can determine the mass of ethanol in each bottle because the mouthwash contains 38.7% ethanol by mass:

0.1149 kg x 0.387 = 0.0444 kg

the total mass of ethanol in 159 bottles of mouthwash:

0.0444 kg/bottle x 159 bottles

= 7.05 kg

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The new freezing point of the solution if it is calculated that the freezing point changes by 1.09 C is -2.17° C.

Change in freezing point = x molality times Kf

Kf is the solvent's (water) freezing point constant, and molality is the solute's molal concentration in the solvent.

We can enter the following values into the algorithm to solve for molality because the freezing point reduction is specified as 1.09°C:

Kf x molality = 1.09

Water has a 1.86°C/m freezing point reduction constant. As a result, we have:

Molality equals 1.09 / 1.86 to 0.586 mol/kg.

We can use: to ascertain the solution's new freezing point:

Change in freezing point = m x I x Kf

As a result, we have:

[tex]T_{f}[/tex] = Kf x m x I = 1.86 °C per mete x 0.586 mol/kg x 2 = 2.17 °C

New freezing point is equal to 0 - 2.17 = -2.17 C.

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Answer:

The relative formula mass of H₂O can be calculated by adding the atomic masses of two hydrogen atoms and one oxygen atom in the molecule. The atomic mass of hydrogen is 1 and the atomic mass of oxygen is 16. So, the relative formula mass of H₂O is:

(2 x 1) + 16 = 18

Explanation:

The molecules of H2O that are produced are:  4.98 × 10²³ molecules of H2O

Process in which one or more substances are converted to one or more different products is called a chemical reaction.

To calculate the number of molecules of H2O produced, we can use the Avogadro's number, which is equal to 6.022 ×  10²³ molecules per mole of substance.

number of molecules = moles of substance × Avogadro's number

number of molecules = 0.829 moles × 6.022 ×  10²³molecules/mol

number of molecules = 4.98 ×  10²³molecules

Therefore, approximately 4.98 ×  10²³ molecules of H2O are produced.

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Answer:

The net ionic equation of 2H+ + SO2 + Ca²+ + 2I → CaSO4 + 2H+ + 2I is C. H+ + SO4²+ Ca²+ + 2I→CaSO4+H*+ I. This equation describes the process of a single replacement reaction, where the hydrogen ions and iodide ions react with the sulfate and calcium ions to form the insoluble compound of calcium sulfate and the remaining hydrogen and iodide ions

Explanation:

Answer:

The ans is simple: O2

Explanation:

Oxygen has 6 electrons on its outer shell and to be in stable form it shares 2 electrons with the other one and forms double bond.

Fluorine is most likely the diatomic element with the mass of 19.08 grammes held in a container at 100°C (F2).

Diatomic molecules are those that contain two atoms. Iodine (I2), fluorine (F2), chlorine (Cl2), bromine (Br2), nitrogen (N2), oxygen (O2), and hydrogen (H2) are all diatomic elements. Diatomic molecules make up the bromine atom, Br2, in the periodic table.

The diatomic molecules of the group 7 elements are present. They have the chemical formulas F2, Cl2, Br2, and I2. Although the forces of attraction between molecules are minimal, the connection between the atoms in a molecule is quite strong. This explains why the boiling points of group 7 elements are low.

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Question:

Which of the following diatomic elements would have a mass of 19.08 grams stored in a container at and 100°C? (R= 0.0821 L atm/ mol K).

Thediatomic element with a mass of 19.08 grams stored in a container at 100°C is hydrogen (H2), which has a pressure of 27.2 atm.

What is Diatomic Elements?

Diatomic elements are chemical elements that exist as two atoms bound together in a molecule. Examples of diatomic elements include oxygen (O2), nitrogen (N2), hydrogen (H2), fluorine (F2), chlorine (Cl2), and iodine (I2).

To determine the diatomic element with a mass of 19.08 grams stored in a container at 100°C, we need to use the ideal gas law, which is given by:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

We can rearrange this equation to solve for the number of moles:

n = PV/RT

We are given the mass of the gas, which we can convert to moles using the molar mass of the element. The molar mass of a diatomic element is simply twice the atomic mass of the element. Using the periodic table, we find the following atomic masses:

H: 1.008

N: 14.007

O: 15.999

F: 18.998

We can calculate the molar mass of each diatomic element:

H2: 2 x 1.008 = 2.016 g/mol

N2: 2 x 14.007 = 28.014 g/mol

O2: 2 x 15.999 = 31.998 g/mol

F2: 2 x 18.998 = 37.996 g/mol

Now we can calculate the number of moles of the gas using the given mass and molar mass:

n = 19.08 g / molar mass

Using the molar masses above, we get:

For H2: n = 19.08 g / 2.016 g/mol = 9.47 mol

For N2: n = 19.08 g / 28.014 g/mol = 0.68 mol

For O2: n = 19.08 g / 31.998 g/mol = 0.60 mol

For F2: n = 19.08 g / 37.996 g/mol = 0.50 mol

Finally, we can use the ideal gas law to calculate the pressure of the gas, assuming a volume of 1 liter:

P = nRT/V = (number of moles) x R x (temperature in Kelvin) / V

Plugging in the values, we get:

For H2: P = 9.47 mol x 0.0821 L atm/mol K x (100+273.15) K / 1 L = 27.2 atm

For N2: P = 0.68 mol x 0.0821 L atm/mol K x (100+273.15) K / 1 L = 1.97 atm

For O2: P = 0.60 mol x 0.0821 L atm/mol K x (100+273.15) K / 1 L = 1.74 atm

For F2: P = 0.50 mol x 0.0821 L atm/mol K x (100+273.15) K / 1 L = 1.45 atm

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The final temperature of the iron metal block is 27.9 ⁰C.

option B.

The final temperature of the iron mixture is calculated by applying interpolation and extrapolation where necessary.

Since the mass of the metal blocks are equal, the final temperature of the iron metal block is calculated as follows;

0.39 ------------- 27 ⁰C

0.90 ------------- 35 ⁰C

0.45 -------------- ?

( 0.45 - 0.39 )/ ( 0.9 - 0.39 ) = ( ? - 27 ) / ( 35 - 27 )

0.1176 = ( ? - 27 ) / ( 8 )

? - 27 = 8 (0.1176)

? - 27 = 0.94

? = 27.94 ⁰C

? ≈ 27.9 ⁰C

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