What is the value of x in the equation −25x−2=18?

Answer:

£225

Step-by-step explanation:

12.5% × £200

>> £25

Since we want to increase £200 by 12.5%, then we will add the increment to the £200 to get;

£200 + £25 = £225

Answer: £25

Step-by-step explanation: Take £200 and multiply by 12.5% and you get  £25. I hope this helped!

Answer:

The slope of the line is 1

In point-slope form:

y = x + 1

Answer: 1

Step-by-step explanation: the rise is 1 and the run is also 1 so 1/1 equals 1

Answer:

476.37

Step-by-step explanation:

$12.98/hr at KF (Key Food)
$x/36.7, so look at it fractionally.
36.7x12.98
This wil be 476.366
Rounding to the nearest hundredth is 2 decimal places (tenths, hundredths).
476.366 will be 476.37

The bus tickets and price are illustrations of a quadratic function, and the maximum revenue the bus company can earn is $5107.6

The variable representation used in this scenario are:

The price is given as:

Price = $156

The number of seats is given as:

Seats = 56

When the bus is at half capacity, we have:

Seats = 28

As the price decreases by $5, the rider gains 2 more.

So, the revenue equation is:

y = (156 - 5x)(28 + 2x)

Expand

y = 4368 - 140x + 312x - 10x²

Differentiate

y' = 0 - 140 + 312 - 20x

Evaluate the sum

y' = 172 - 20x

Equate to 0

172 - 20x =0

Add 20x to both sides

20x = 172

Divide both sides by 20

x = 8.6

Substitute x = 8.6 in y = (156 - 5x)(28 + 2x)

y = (156 - 5 * 8.6)(28 + 2 * 8.6)

Evaluate

y = 5107.6

Hence, the maximum revenue the bus company can earn is $5107.6

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The equation that shows Courtney rode 180 mlles more than Breanna rode is c = b + 180

An equation is an expression that shows the relationship between two or more numbers and variables.

Let b represent the number of miles rode by Breanna and c represent that of Courtney.

c = b + 180

The equation that shows Courtney rode 180 mlles more than Breanna rode is c = b + 180

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Answer:

Rebecca did a shorter run then Stacy

Rebecca ran a longer distance than Josie

Josie ran a longer distance than Finn

Step-by-step explanation:

if Rebecca’s distance was shorter than Stacy’s and longer than Josie, then Stacy’s running distance would have to be more that Josie’s and Finn’s.

1.Stacy

2.Rebecca

3.Josie

4.Finn

Answer: [tex](x-7)^2+(y+2)^2=11^2[/tex] ; [tex]A=121\pi[/tex]

Step-by-step explanation:

I have never done a problem like this, so this is my first time attempting it.

The standard form for the equation of a circle is:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

Begin by grouping the 'x' terms and 'y' terms:

[tex](x^2-14x)+(y^2+4y-68)=0[/tex]

Complete the square for the second polynomial:

[tex](\frac{b}{2} )^2=(\frac{4}{2} )^2=4[/tex]

[tex](x^2-14x)+(y^2+4y+4-4-68)=0[/tex]

[tex](x^2-14x)+(y^2+4y+4)-4-68=0[/tex]

[tex](x^2-14x)+(y^2+4y+4)-72=0[/tex]

[tex](x^2-14x)+(y+2)^2-72=0[/tex]

Do the exact same process with the other polynomial:

[tex](x^2-14x-72)+(y+2)^2=0[/tex]

Complete the square:

[tex](\frac{14}{2} )^2=49[/tex]

[tex](x^2-14x+49-49-72)+(y+2)^2=0[/tex]

[tex](x^2-14x+49)-49-72+(y+2)^2=0[/tex]

[tex](x^2-14x+49)-121+(y+2)^2=0[/tex]

[tex](x-7)^2-121+(y+2)^2=0[/tex]

Bring the 121 to the other side to get:

[tex](x-7)^2+(y+2)^2=121[/tex]

[tex](x-7)^2+(y+2)^2=11^2[/tex]

The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

[tex]A=\pi r^2=121\pi[/tex]

Answer:

28 bottles

HOPE THIS HELPS! :)

Answer:

Your answer is 180

Step-by-step explanation:

180 x 5 = 900

The expression is [tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex].  The simplified expression as [tex]{x^{72}y^{72} }[/tex]. Option B is correct.

Given that,

The expression is [tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex]

We have to simplify the expression.

Simplify the expression means solving a math problem is the same thing as simplifying an expression. You basically attempt to write an expression as simply as you can when you simplify it. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.

Take the expression

=[tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex]

Multiply the powers

=[tex]\frac{x^{76}y^{84} }{x^{4} y^{12} }[/tex]

Divide the x and y terms

=[tex]{x^{72}y^{72} }[/tex]

Therefore, We got the simplified expression as [tex]{x^{72}y^{72} }[/tex]. Option B is correct.

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The required table of values for equation y=5-2x is;

x | y

0   5

1    3

2    1

3   -1

Tables of values are values used to represent functions.

Given the linear function expressed as y = 5 - 2x, we are to form a tables of values for the function.

Using the values of x = 0, 1, 2, and 3

If x = 0

y = 5 - 2(0)

y = 5

If x = 1

y = 5 - 2(1)

y = 3

If x = 2

y = 5 - 2(2)

y = 1

If x = 3

y = 5 - 2(3)

y = -1

Hence the required table of values for equation y=5-2x is;

x | y

0   5

1    3

2    1

3   -1

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Answer:

Step-by-step explanation:

4x − 1 = 19

solving for x, x = 5

2x − 4 = 10

x=7

2x + 2y = 48

x=24-7

y=24-x

5x + 2y = 90

x=18-2y/5

y=45-5x/2

all the situations I could find hope this helps for each equation.

The solution of the linear equation is k =0.5.

An equation is a mathematical statement, which has an equal sign (=) between the algebraic expression.

Linear equations are the equations of degree 1.

The given linear equation is;

[tex]\rm 6k + 10.5 = 3k + 12[/tex]

The value of k is determined in the following steps given below.

[tex]\rm 6k + 10.5 = 3k + 12\\\\6k-3k=12-10.5\\\\3k = 1.5\\\\k = \dfrac{1.5}{3}\\\\k = 0.5[/tex]

Hence, the solution of the linear equation is k =0.5.

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Answer:

[tex]\boxed{\tt x=45^o}[/tex]

Step-by-step explanation:

The two angles together are supplementary, which means that they add up to 180°

[tex]\tt (2x+45)^o+x^o=180^o[/tex]

Now, let's solve for x:-

[tex]\tt 2x+45+x^o=180^o[/tex]

[tex]\tt 3x+45^o=180[/tex]

[tex]\tt 3x=135^o[/tex]

[tex]\tt x=45^o[/tex]

_____________________

Correct Question :-

Calculate the circumference of the shape below.

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \\ [/tex]

We know :-

[tex] \bigstar\boxed{ \rm Circumference_{(circle)} = 2\pi r}[/tex]

[tex] \\ [/tex]

Steps :-

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2\pi r[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2\pi \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2 \times \dfrac{22}{7} \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{125}{10} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{ \cancel{125} {}^{25} }{ \cancel{10} {}^{2} } \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{25}{2} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{ \cancel{44}}{7} \times \dfrac{25}{ \cancel2} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{22}{7} \times \dfrac{25}{1} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{550}{7} \\ [/tex]

[tex] \\[/tex]

[tex] \dashrightarrow\bf Circumference_{(circle)} =78.6 \: m\{approx \} \\ [/tex]

[tex] \\[/tex]

~[tex] \pmb{\cal W\frak{indy}M\frak{int}}[/tex]

Answer:

16

Step-by-step explanation:

Lets first solve the right side :)

(3^5)^4 -> 3^20 = 3486784401

Now lets solve the left side :)

When we multiply the bases to exponets, we add the exponets together :)

Lets see what numbers equal 20 when added :)

4 + 4 = 8 Nope!!

4 + 5 = 9 Not at all!!

4 + 20 = 24 Too big!!

4 + 16 = 20 Perfect!!

Have an amazing day!!

Please rate and mark brainliest!!

Answer:

The answer you are looking for is in D- 16

Explanation:

Included in attachment

Answer:

a

Step-by-step explanation:

a is 8 .52 so its to low and the change was 8.72

Usando un sistema de ecuaciones, se encuentra que ese número es n = -3 o n = 3.

Un sistema de ecuaciones es cuando dos o más variables están relacionadas y las ecuaciones se construyen para encontrar los valores de cada variable.

En este problema, la variable es el número n.

El quintuple de un número cuadrado disminuido en 9 da como resultado 36, o sea, la ecuación es:

5n² - 9 = 36

5n² = 45

n² = 9

n = -3 o n = 3.

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Answer:

x= 4 and y=7

Step-by-step explanation:

Bellow is the graph of the two systems, you can find the coordinates (4,7) were they intersect.

Because of this the two equations are true

7= 4+3 (True)

Answer:

[tex]25\sqrt{3} \ [units^2].[/tex]

Step-by-step explanation:

1) one side of the given rectangle can be calculated as:

10*sin30°=5 [units].

2) another side of the given rectangle can be calculated as:

10*cos30°=5√3 [units].

3) finally, the area required is:

5*5√3=25√3 [units²].

Answer:

B. origin

Step-by-step explanation:

It is usually right at the center of a graph, the point (0,0) It is where you start from to graph points.

Answer:

algebros....

Step-by-step explanation:

Answer: The answer is 80

Step-by-step explanation:

Answer:

Gary baked 80 muffins on Sunday

Step-by-step explanation:

I can set up a proportion, knowing that 24/x = 3/10, where x is the total number of muffins baked on Sunday.  By cross multiplying, I get 240 = 3x.  By dividing both sides by 3, I find x = 80.

Based on the information provided in the histogram, the percent of students that type less than 30 words per minute is 30%.

A histogram is used to represent data graphically. The histogram is made up of rectangles whose area is equal to the number of students and whose width is equal to the words per minute.

Percentage of students who type less than 30 words per minute = (number of students that type less than 30 words per minute) / total number of students) x 100

[(10 + 5) / 50] x 100 = 30%

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Answer:

6/1

Step-by-step explanation:

The reciprocal is always the opposite. for example, the reciprocal of 9/10 is 10/9

Answer:

6 or 6/1

Step-by-step explanation:

The opposite reciprocal is when a fraction is flipped upside down (the reciprocal part) and with the signs changed (the opposite).

For -1/6

[tex]\frac{-1}{6} < ==flip\ the\ fraction\\\\\frac{6}{-1}\\\\ -6 < ==change\ the\ sign\\\\6[/tex]

Hope this helps!

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Number of blocks having volume of 2 m³ in the wall ~

[tex]\qquad \tt \dashrightarrow \: \dfrac{600}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:300 \: \: blocks[/tex]

Step-by-step explanation:

No of blocks will a wall will have =

Volume of wall / volume of one block

putting the known values ,

No of blocks = 600m³/2m³

No. Of blocks = 300 blocks

I believe she will have 8 rolls of toilet paper left after one year.

She started with 36, then gave away 4, so then she would have 32 left for herself, then she used 2 every month so if you deduct 2 rolls every month for 12 months she would use 24 in one year. So 32-24 is 8.

Answer:

A = 0.43      B = 0.49

Step-by-step explanation:

For A: The options are between 0.40 and 0.45. A is plotted on the 3rd line from 0.40. That makes the answer 0.43.

For B: It is in the middle of 0.45 and 0.50. It is plotted on the 4th line from 0.45, which is 0.49.

A = 0.43; B = 0.49

The population density is the ratio of the number of geese to the area. Then the greatest population density in pond C is 128.

The population density is defined as the number of objects present in the unit area.

The formula is given as

[tex]\rm Population\ density = \dfrac{number\ of \ object}{total \ area}[/tex]

The table shows the number of resident geese living in four different ponds. a 3-column table has 4 rows.

Then the greatest population density of the geese will be

[tex]\rm Population\ density = \dfrac{192}{1.5} = 128[/tex]

More about the population density link is given below.

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Answer:

pond B

Step-by-step explanation:

edg 2022

Answer:xponential function has an initial value of 500 and a decay rate of 15%. Compare the average rate of change for the interval 0

Step-by-step explanation: