What is the slope of the line represented by the equation: y = 7x

We have the solve using the quadratic equation as;

Step 2:

a = 1

b = -5

c = -14

Step 3:

What 1: (-5)²

What 2: 1

What 3: -14

What 4: 1

The quadratic equation is expressed as;

ax² + bx + c = 0

x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex]/2a

From the information given, we have that;

x² -5x - 14 = 0

Now, substitute the values, we get;

x = - (-5) ± [tex]\sqrt{(-5)^2 - 4 * 1 * -14}[/tex]/ 2(1)

find the square and substitute the values, we have;

x = 5 ± [tex]\sqrt{25 + 56}[/tex]/2

Add the values, we have;

x = 5 ± √81/2

Find the square root

x = 5 ±9/2

x = 5 ± 4. 5

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Thus, beginning with a 1 = 5, the formula a n = a n-1 + 7 can be used to recursively find the nth term of the sequence.

A sequence in mathematics is an ordered collection of numbers that is typically defined by a formula or rule. Every number in the series is referred to as a term, and its location within the sequence is referred to as its index. Depending on whether the list of terms stops or continues indefinitely, sequences can either be finite or infinite. By their patterns or uniformity, sequences can be categorised, and the study of sequences is crucial to many areas of mathematics, such as calculus, number theory, and combinatorics. Mathematical, geometrical, and Fibonacci sequences are a few examples of popular sequence types.

given

The sequence's terms are all different by 7 (i.e., 12 - 5 = 19 - 12 = 26 - 19 =... = 7).

The following is a definition of a recursive formula for the nth element of the sequence:

a 1 = 5 (the first term of the series is 5) (the first term of the sequence is 5)

For n > 1, each term is derived by adding 7 to the preceding term, so a n = a n-1 + 7.

Thus, beginning with a 1 = 5, the formula a n = a n-1 + 7 can be used to recursively find the nth term of the sequence. For instance, we have

a_2 = a_1 + 7 = 5 + 7 = 12

a_3 = a_2 + 7 = 12 + 7 = 19

a_4 = a_3 + 7 = 19 + 7 = 26

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a. The point estimate for the birth weights is 2714.58, b. the value of tq is 1.70814, and c. the margin of error for the confidence interval is 124.3. d. The confidence interval for birth weights is (2503, 2927). e. No conclusions can be drawn since the confidence interval contains 2500.

a. The point estimate for the birth weights is 2714.58. This is the average of the sample data and is used as an estimate for the population mean.

b. The value of tq is 1.70814. This is the t-value associated with the given confidence level and degrees of freedom.

c. The margin of error for the confidence interval is 124.3. This is calculated using the formula ME = tq * (s/√n), where tq is the t-value, s is the sample standard deviation, and n is the sample size.

d. The confidence interval for birth weights is (2503, 2927). This is calculated by taking the point estimate and subtracting and adding the margin of error to get the lower and upper bounds of the interval.

e. No conclusions can be drawn since the confidence interval contains 2500. This means that the true population mean could be less than 2500, greater than 2500, or equal to 2500.

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If S1 and S2 are two sets of vectors that each span V, then S1 ∪ S2 also spans V.

Let S1 and S2 be two sets of vectors that each span V. We need to show that S1 ∪ S2 also spans V.

Let v be any vector in V. Since S1 spans V, there exist vectors u1, u2,..., un in S1 and scalars a1, a2,..., an such that:

v = a1u1 + a2u2 + ... + anun

Similarly, since S2 spans V, there exist vectors w1, w2,..., wm in S2 and scalars b1, b2,..., bm such that:

v = b1w1 + b2w2 + ... + bmwm

Now, since S1 ∪ S2 contains all the vectors in S1 and S2, we can write v as a linear combination of the vectors in S1 ∪ S2:

v = a1u1 + a2u2 + ... + anun + b1w1 + b2w2 + ... + bmwm

Therefore, S1 ∪ S2 spans V.

In conclusion, if S1 and S2 are two sets of vectors that each span V, then S1 ∪ S2 also spans V.

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48500 has been invested in total. Total invested at the end: $289,279.40. This exemplifies the need to allow your savings to increase over time.

An investments is a procurement made with both the intention of making money or increasing capital. Appreciate seems to be the term for just an asset's value growing over time. When someone invests in something, they do it with the intention of using it to generate cash later on instead of for current consumption.

Investing is a wise method to use your money and may possibly increase your wealth. When your make intelligent investment choices, your cash can increase in value and outpace inflation.

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The converse of Theorem 6.6 states that if a group G is such that every proper subgroup is cyclic, then G is cyclic. This statement is false, as shown by the following counterexample:

Let G = {e, a, b, ab}, where e is the identity element, and a and b are two distinct elements such that ab = ba.

This group is not cyclic because it does not contain an element of order 4, and thus cannot be generated by a single element. However, every proper subgroup is cyclic. For example, the subgroup {e, a} is cyclic, and the subgroup {e, b} is cyclic.

Therefore, this example provides a counterexample to the converse of Theorem 6.6.

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The value of ST in the given triangle is is √73.

A right triangle's three sides are related in Euclidean geometry by the Pythagorean theorem, also known as Pythagoras' theorem. According to this statement, the areas of the squares on the other two sides add up to the size of the square whose side is the hypotenuse.

Here, we have

Given: In a triangle

TR = 8

SR = 3

ST =?

We apply here Pythagoras theorem and we get

SR² + TR² = ST²

3² + 8² = ST²

9 + 64 = ST²

73 = ST²

ST = √73

Hence, the value of ST is √73.

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To find the exact values of all six trigonometric functions of 660°, we need to first convert the angle to one that falls within the range of 0° to 360°. We can do this by subtracting 360° from the given angle until we get a value within the desired range.

660° - 360° = 300°

Now we can find the exact values of the trigonometric functions of 300° using the unit circle:

sin 300° = -√3/2
cos 300° = 1/2
tan 300° = -√3
csc 300° = -2/√3
sec 300° = 2
cot 300° = -1/√3

Therefore, the exact values of all six trigonometric functions of 660° are:
sin 660° = -√3/2
cos 660° = 1/2
tan 660° = -√3
csc 660° = -2/√3
sec 660° = 2
cot 660° = -1/√3

Problem 6: Verify the identity: sin x + cos x cotx = CSC X.

To verify this identity, we can start by simplifying the left-hand side of the equation:

sin x + cos x cotx
= sin x + cos x (cos x / sin x)
= sin x + (cos^2 x / sin x)
= (sin^2 x + cos^2 x) / sin x

Since sin^2 x + cos^2 x = 1, we can simplify further:

= 1 / sin x
= csc x

Therefore, the left-hand side of the equation simplifies to the same value as the right-hand side, verifying the identity.

sin x + cos x cotx = csc x

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Simona is left with 7 cups of milk.

What is Mixed fraction?

An example of a mixed fraction is one that consists of both a whole integer and a fractional component. A mixed fraction is, for instance, 3 1/7. It's also known as a jumbled number.

Conversion procedures for a mixed fraction to a simple fraction

Step 1: Multiplying the denominator of the mixed fraction by the whole number component is the first step.

Step 2: To the end result achieved in Step 1, add the numerator.

Step 3: Format the improper fraction in numerator/denominator form using the sum from step 2 as the denominator.

Simona has 8 3/4 cups of milk .

She uses 1 1/2 cups of milk to make the cake and 1/4 cup of the milk to make frosting for the cake.

So, cups of milk left = total cups of milk - cups of milk used for cake

                                = 8 3/4 - 1 1/2 - 1/4

                                = 35/4 - 3/2 - 1/4

                                = (35 - 6 - 1)/4

                                = 28/4

                                = 7 cups of milk.

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By applying simplification and factoring concepts, it can be concluded that:

1. (-5x⁻³ y⁻⁵) (3x⁵ y⁻⁵) = -15x² / y¹⁰

3. 20x² – 12x – 14 = 2(10x² - 6x - 7)

5. 2x(x - 1) + 3(x - 1) = (x - 1)(2x + 3)

6. 12x² – 15x + 8x – 10 = (3x + 2)(4x - 5)

7. 3x² – 13x – 10 = (3x + 2)(x - 5)

Simplification is the process of rewriting an expression in a simpler or easier-to-understand form, while still maintaining the same values.

Factoring means to factor a number means to break it up into numbers that can be multiplied together to get the original number.

Q1: Simplifying (-5x⁻³ y⁻⁵) (3x⁵ y⁻⁵)

Multiplying the number and applying rule (-x) = x, we get:

= -15x⁻³ · x⁵ · y⁻⁵· y⁻⁵

Apply rule xᵃxᵇ = xᵃ⁺ᵇ, we get:

= -15x²· y⁻¹⁰

Apply rule x⁻ᵃ = 1/xᵃ, we get:

= -15x² / y¹⁰

Q3: Factoring 20x² – 12x – 14

Divide each term by 2, and we get:

= 2(10x² - 6x - 7)


Q5: Factoring 2x(x - 1) + 3(x - 1)

Factoring out common term (x - 1), we get:

= (x - 1)(2x + 3)

Q6: Factoring 12x² – 15x + 8x – 10

Factoring out 4x from 12x² + 8x, we get:

= 4x(3x + 2)

Factoring out -5 from – 15x – 10, we get:

= -5(3x + 2)

Now the full expression becomes:

= 4x(3x + 2) - 5(3x + 2)

Factoring out common term (3x + 2), we get:

= (3x + 2)(4x - 5)

Q7: Factoring 3x² – 13x – 10

Break expression into groups:

= 3x² + 2x – 15x – 10

Factoring out x from 3x² + 2x, we get:

= x(3x + 2)

Factoring out -5 from – 15x – 10, we get:

= -5(3x + 2)

Now the full expression becomes:

= x(3x + 2) - 5(3x + 2)

Factoring out common term (3x + 2), we get:

= (3x + 2)(x - 5)

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Solving a quadratic equation we can see that the 3 consecutive numbers are:

4, 5, and 6.

First, we can write 3 consecutive integers as:

x, (x + 1), and (x +2 )

The square of the first increased by the last is 22, then we can write:

x^2 + (x + 2) = 22

x^2 + x + 2 - 22 = 0

x^2 +x  - 20 = 0

Using the quadratic formula we will get the solutions:

[tex]x = \frac{-1 \pm \sqrt{1^2 - 4*1*-20} }{2} \\\\x = \frac{-1 \pm 9}{2}[/tex]

We know that x is positive, then the solution is:

x = (-1 + 9)/2 = 4

The 3 consecutive numbers are:

4, 5, and 6.

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To obtain 400 liters of 11% acid solution, you need to mix  390 liters of the 10% acid solution and 10 liters of the 50% acid solution to obtain 400 liters of 11% acid solution.

Let x be the number of liters of 10% acid solution and y be the number of liters of 50% acid solution.

We can set up a system of two equations to represent the given information:

x + y = 400 (total volume of the mixture is 400 liters)

0.10x + 0.50y = 0.11(400) (the amount of acid in the mixture is 11% of the total volume)

Simplifying the second equation:

0.10x + 0.50y = 44

We can now use either substitution or elimination method to solve for x and y.

Using substitution, we can solve for y in terms of x from the first equation:

y = 400 - x

Substituting this into the second equation:

0.10x + 0.50(400-x) = 44

Simplifying and solving for x:

0.10x + 200 - 0.50x = 44

-0.40x = -156

x = 390

So the chemist needs 390 liters of the 10% acid solution and 10 liters of the 50% acid solution to obtain 400 liters of 11% acid solution.

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An angle which is supplementary to ∠AGB is ∠BGD

Two angles that sum up to 180 degrees are referred to as supplementary angles. In other words, the sum of the measurements of two additional angles equals 180 degrees.

Angles A and B, for instance, are supplementary if angle A is 70 degrees and angle B is 110 degrees. This is because 70 + 110 = 180.

Given that,

The arrangement which has multiple rays,

And it is known that,

The sum of angles of supplementary angles are 180°

∠AGB & ∠BGD has the sum of 180°,

So it can be state that ∠BGD is supplementary to the angle ∠AGB

Therefore, the supplementary angle is ∠BGD

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The value of y when x is 12 is 2 (option C)

Inverse variation is the relationship between two variables, such that if the value of one variable increases then the value of the other variable decreases. Example is the price of a commodity and the quantity acquired, the higher the price, the lower of commodity bought and vice- versa.

Inverse relationship between two quantities x and y is expressed as:

x= ky

where k is the constant

k = 6

when x = 12

12 = 6y

divide both sides by 6

y = 12/6

y = 2

therefore the value of y when x is 12 is 2

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The inequalities shown by the graph are y < 3, x > -1, x < 3, and y >-2.

The given graph has four lines showing different inequalities.

One undotted line is parallel to the x-axis and is at y = 3. The shaded region is below y = 3

Hence, the inequality will be y < 3

Another dotted line is parallel to the x-axis and is at y = -3. The shaded region is above y = -2

Hence, the inequality will be y > -2

Another dotted line is parallel to the y-axis and is at x = -1. The shaded region is to the right of x = -1

Hence, the inequality will be x > -1

Another dotted line is parallel to the y-axis and is at x = 3 The shaded region is to the left of x = 3

Hence, the inequality will be x < 3

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a)\( -9 \)

b)\( \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \).

(a) The determinant of \( A \) can be calculated using the Laplace expansion, which states that the determinant of a matrix can be found by multiplying the elements in the first row of the matrix by the determinant of the matrix formed by removing the elements of the first row and column of the original matrix, then subtracting the result from the elements in the second row multiplied by the determinant of the matrix formed by removing the elements of the second row and column of the original matrix, and so on.

Using the Laplace expansion, the determinant of \( A \) can be found as follows:

\( \operatorname{det}(A) = 0 \times \operatorname{det}\left[\begin{array}{cc}1 & -3 \\ 2 & 3\end{array}\right] - (-2) \times \operatorname{det}\left[\begin{array}{cc}-3 & -3 \\ 2 & 3\end{array}\right] + (-3) \times \operatorname{det}\left[\begin{array}{cc}-3 & 1 \\ -3 & 3\end{array}\right] \)

\( \operatorname{det}(A) = 0 \times 18 + 2 \times (-18) + 3 \times 9 \)

\( \operatorname{det}(A) = 0 - 36 + 27 \)

\( \operatorname{det}(A) = -9 \)

Therefore, the determinant of \( A \) is \( -9 \).

(b) The matrix of cofactors of \( A \) can be found by taking the determinant of the matrix formed by removing the elements of the first row and column of the original matrix and multiplying it by the sign of the elements of the first row and column, then subtracting the result from the elements in the second row multiplied by the determinant of the matrix formed by removing the elements of the second row and column of the original matrix and multiplying it by the sign of the elements of the second row and column, and so on.

Using this method, the matrix of cofactors of \( A \) can be found as follows:

\( \left[\begin{array}{ccc}C_{11} & C_{12} & C_{13} \\ C_{21} & C_{22} & C_{23} \\ C_{31} & C_{32} & C_{33}\end{array}\right] = \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \)

Therefore, the matrix of cofactors of \( A \) is \( \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \).

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b.4+3cos²x is the simplification of the given trigonometric identity

Explanation:
Using the identity sin²x + cos²x = 1, we can simplify the expression:

4-4sin²x/(cot²x) + 7cos²x
= 4 (1-sin²x)/(cot²x) + 7cos²x
= 4 cos²x/cot²x + 7cos²x
= 4sin²x + 7cos²x

= 4sin²x + 4cos²x + 3cos²x

=4+3cos²x

Hence, the answer is b. 4 + 3cos²x

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To find an equation that goes through the point (8.1) and is perpendicular to 2y + 4x = 12, we can first rearrange the given equation into slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept:

2y + 4x = 12

2y = -4x + 12

y = -2x + 6

So the slope of the given equation is -2.

Since we want a line that is perpendicular to this line and passes through the point (8,1), we know that the slope of our new line will be the negative reciprocal of -2, which is 1/2.

Now we can use the point-slope form of the equation of a line to write the equation:

y - 1 = (1/2)(x - 8)

Simplifying this equation, we get:

y - 1 = (1/2)x - 4

y = (1/2)x - 3

Therefore, the equation that goes through the point (8,1) and is perpendicular to 2y + 4x = 12 is y = (1/2)x - 3.

Answer:

To find the equation of a line that goes through a given point and is perpendicular to a given line, we can use the following steps:

Rewrite the given line in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.

Determine the slope of the line that is perpendicular to the given line. The slope of a line perpendicular to a line with slope m is -1/m.

Use the point-slope form of the equation of a line to write the equation of the line that goes through the given point with the slope found in step 2.

Given the point (8, 1) and the line 2y + 4x = 12, we can rewrite the line in slope-intercept form by solving for y:

2y + 4x = 12

2y = -4x + 12

y = -2x + 6

The slope of the given line is -2.

The slope of the line perpendicular to the given line is -1/-2 = 1/2.

Using the point-slope form of the equation of a line, we can write the equation of the line that goes through the point (8, 1) with slope 1/2:

y - 1 = (1/2)(x - 8)

Simplifying this equation, we get:

y - 1 = (1/2)x - 4

y = (1/2)x - 3

Therefore, the equation of the line that goes through the point (8, 1) and is perpendicular to the line 2y + 4x = 12 is y = (1/2)x - 3.

Step-by-step explanation:

The value of expression (9.5×10-6)÷(5×104) is 0.1712

Consider a mathematical expression (9.5×10-6)÷(5×104)

We use PEDMAS rule to solve this expression.

We know that the PEMDAS rule gives the order of mathematical operations.

PEMDAS means we solve an expression in following order : parentheses, exponents, multiplication, division, addition, and subtraction.

Here (9.5×10-6)÷(5×104) we have two parentheses

Consider the first parentheses

(9.5×10 - 6)

= 95 - 6

= 89

Consider the second parentheses

(5×104) = 520

Now we solve (9.5×10 - 6)÷(5×104) = 89 ÷ 520

                                                       = 0.1712

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In order to fill the entire shape, one must use 1 cm x 1 cm x 1 cm wooden blocks, with the total number of blocks equaling the volume of the shape in cm³. In this case, the number of blocks needed is 1 cm³, or one block.

Length is a measurement of distance or amount. It is commonly used to describe the size of an object or the distance between two points. Length can be measured in a variety of ways including inches, feet, yards, centimeters, miles, and kilometers. Length is also used to measure time, the extent of something, and the amount of material or substance.

To figure out how many 1 cm x 1 cm x 1 cm wooden blocks are required to fill the entire shape, one must first calculate the volume of the shape. The volume is calculated by multiplying the length, width, and height of the shape, which in this case is all 1 cm. Therefore, the volume of the shape is 1 cm x 1 cm x 1 cm = 1 cm³.

Next, one must calculate the total volume of all the blocks needed to fill the shape. Since each block is 1 cm x 1 cm x 1 cm, the total volume of the blocks is equal to the volume of the shape, which is 1 cm³.

Therefore, in order to fill the entire shape, one must use 1 cm x 1 cm x 1 cm wooden blocks, with the total number of blocks equaling the volume of the shape in cm³. In this case, the number of blocks needed is 1 cm³, or one block.

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In order to fill the entire shape, one must use 1 cm x 1 cm x 1 cm wooden blocks, with the total number of blocks equaling the volume of the shape in cm³. In this case, the number of blocks needed is 1 cm³, or one block.

Length is a measurement of distance or amount. It is commonly used to describe the size of an object or the distance between two points. Length can be measured in a variety of ways including inches, feet, yards, centimeters, miles, and kilometers. Length is also used to measure time, the extent of something, and the amount of material or substance.

To figure out how many 1 cm x 1 cm x 1 cm wooden blocks are required to fill the entire shape, one must first calculate the volume of the shape. The volume is calculated by multiplying the length, width, and height of the shape, which in this case is all 1 cm. Therefore, the volume of the shape is 1 cm x 1 cm x 1 cm = 1 cm³.

Next, one must calculate the total volume of all the blocks needed to fill the shape. Since each block is 1 cm x 1 cm x 1 cm, the total volume of the blocks is equal to the volume of the shape, which is 1 cm³.

Therefore, in order to fill the entire shape, one must use 1 cm x 1 cm x 1 cm wooden blocks, with the total number of blocks equaling the volume of the shape in cm³. In this case, the number of blocks needed is 1 cm³, or one block.

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Complete questions as follows-

A solid wooden block in the shape of a rectangular prism has a length, width, and height of centimeter, centimeter, and centimeter, respectively. The volume of the block is cubic centimeter. The number of cubic wooden blocks with a side length of centimeter that can be cut from the rectangular block is .

C) (i) How many 1 cm x 1 cm x 1 cm wooden blocks will he need to fill the entire shape outlined?​

Answer:

Step-by-step explanation:

1000

Answer:

That is the answer

Step-by-step explanation:

The ratio of amount of flour to amount of water is 8 : 3. 5 cups of flour require 15/8 cups of water

An equation is an expression that shows the relationship between two or more numbers and variables. Equations can either be linear, quadratic, cubic and so on depending on the degree.

From the recipe, 2 cups of flour require 3/4 cups of water

a) The ratio of amount of flour to amount of water = 2 cups of flour / (3/4) cups of water = 8/3 = 8 : 3

b) 2 cups of flour require 3/4 cups of water

5 cups of flour = 5 cups of flour * 3/4 cups of water per 2 cups of flour = 5 * (3/4)÷2 = 5 * 3/8 = 15/8 cups of water

5 cups of flour require 15/8 cups of water

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Answer: To determine the effective rate of Zoe's loan, we can use the formula:

Effective rate = (1 + (nominal rate/number of compounding periods))^number of compounding periods - 1

Since the nominal rate is compounded monthly, the number of compounding periods is 12.

Plugging in the values, we get:

Effective rate = (1 + (0.039/12))^12 - 1

Effective rate = 0.0407 or 4.07%

Therefore, the effective rate of Zoe's loan is 4.07%, rounded to the nearest hundredth. The correct response is 3.97%.

Step-by-step explanation:

The points are (0,0) and (0,-1/2)

What is a trigonometric function?

The right-angled triangle's angle and the ratio of its two side lengths are related by the trigonometric functions, which are actual functions. They are extensively employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many others.

Here, we have

Given: y = 4cot 4x

y = -1/2(cot(2x+π/4))

We have to draw the graph of a given function.

y = 4cot 4x

y = -1/2(cot(2x+π/4))

We put the different values of x and get the value of y.

y = 4cot 4x

x = 0

y = 0

y = -1/2(cot(2x+π/4))

when x= 0

y = -1/2

Hence, the points are (0,0) and (0,-1/2)

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(i)The value of x is either 29.326 or -28.226, such that such that |a + b| = |a| + |b|

To find the value of x such that |a + b| = |a| + |b|, we need to first find the magnitudes of a, b, and a+b.

The magnitude of a is |a| = √(1^2 + 2^2 + 2^2) = √9 = 3.

The magnitude of b is |b| = √(2^2 + (6x-3)^2 + 4^2) = √(4 + 36x^2 - 36x + 9 + 16) = √(36x^2 - 36x + 29).

The magnitude of a+b is |a+b| = √((1+2)^2 + (2+6x-3)^2 + (2+4)^2) = √(9 + (6x-1)^2 + 36) = √(6x^2 - 12x + 46).

Now, we can set |a+b| = |a| + |b| and solve for x:
√(6x^2 - 12x + 46) = 3 + √(36x^2 - 36x + 29)

Squaring both sides gives:
6x^2 - 12x + 46 = 9 + 36x^2 - 36x + 29 + 6√(36x^2 - 36x + 29)

Simplifying and rearranging terms gives:

-30x^2 + 24x - 8 = 3√(36x^2 - 36x + 29)
Squaring both sides again gives:
900x^4 - 1440x^3 + 672x^2 - 128x + 64 = 324x^2 - 324x + 87
Simplifying and rearranging terms gives:
900x^4 - 1440x^3 + 348x^2 + 196x - 23 = 0

Using the quadratic formula, we can find the value of x:

x = (-(-1440) ± √((-1440)^2 - 4(900)(348)(196)(-23)))/(2(900))
x = (1440 ± √(2073600 + 2731680000))/(1800)
x = (1440 ± √(2733753600))/(1800)
x = (1440 ± 52344)/(1800)
x = (1440 + 52344)/(1800) or x = (1440 - 52344)/(1800)
x = 29.326 or x = -28.226

Therefore, the value of x is either 29.326 or -28.226.

(ii) The value of y such that there exists a vector d satisfying a × d = c is -1.75, we need to first find the cross product of a and d:

a × d = [(2d3 - 2d2), (2d1 - d3), (d2 - 2d1)]
Now, we can set a × d = c and solve for y:
[(2d3 - 2d2), (2d1 - d3), (d2 - 2d1)] = [-2, 8y + 4, 1]

This gives us the system of equations:

2d3 - 2d2 = -2
2d1 - d3 = 8y + 4
d2 - 2d1 = 1

Solving for d1, d2, and d3 in terms of y gives:

d1 = (8y + 10)/3
d2 = (16y + 22)/3
d3 = (24y + 34)/3

Substituting these values back into the first equation gives:

2(24y + 34)/3 - 2(16y + 22)/3 = -2

Simplifying and rearranging terms gives:

8y + 12 = -2
8y = -14
y = -14/8
y = -1.75
Therefore, the value of y is -1.75.

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It is not possible to solve for x and find the length to the nearest whole number. Please provide the complete equation or additional information to help solve for x.

To find the length x to the nearest whole number, we need to use the given information and follow these steps:

1. Start with the given equation: x≈
2. Solve for x by simplifying the equation.
3. Once you have found the value of x, round it to the nearest whole number.

Without additional information, it is not possible to solve for x and find the length to the nearest whole number. Please provide the complete equation or additional information to help solve for x.

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Answer:

Last answer choice: 4

Step-by-step explanation:

The set of inputs to the graphed function is he set of all x values for which the function has a defined value

Looking at the answer choices we see that the graph does not go the negative x region nor does it have a value for 0

So x = 4 is an input, and the resultant output y from the graph = 0

Answer

Last answer choice: 4

let's firstly convert the mixed fractions to improper fractions and them sum them up.

[tex]\stackrel{mixed}{7\frac{5}{12}}\implies \cfrac{7\cdot 12+5}{12}\implies \stackrel{improper}{\cfrac{89}{12}}~\hfill \stackrel{mixed}{11\frac{2}{3}} \implies \cfrac{11\cdot 3+2}{3} \implies \stackrel{improper}{\cfrac{35}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{89}{12}+\cfrac{35}{3}\implies \cfrac{(1)89~~ + ~~(4)35}{\underset{\textit{using this LCD}}{12}}\implies \cfrac{89+140}{12}\implies \cfrac{229}{12}\implies {\Large \begin{array}{llll} 19\frac{1}{12} \end{array}}[/tex]