Answer:
Step-by-step explanation:
(-5)(-3) = 15
(-6)(-8)= 48
(48)(15)= 720
the sign is positive
two negatives = a positive
four negatives = a positive
Answer:
Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive
Step-by-step explanation:
Please show me the work!
Answer:
9/2π cm/s
Step-by-step explanation:
Volume of the spherical balloon V= 4/3πr³
Rate of change of volume dV/dt = dV/dr * dr/dt
dV/dr = 3(4/3πr²)
dV/dr = 4πr²
dV/dr = 4π(2)²
dV/dr = 16π
If V = 72cm²/s
72 = 16π*dr/dt
dr/dt = 72/16π
dr/dt = 9/2π cm/s
Hence the radius is changing at 9/2π cm/s
Gina ate lunch at a cafe. she ordered a ham sandwich for $8.75 and soup for $4.35. The tax was 7.5%. What was the amount of tax for Gina’s meal?
Answer:
$0.98
Step-by-step explanation:
First, add $8.75 & $4.35.
8.75 + 4.35 = $13.10 in total
Then find the tax by multiply 7.5% (3/40) times 13.10.
3/40 * 131/10
393/400 = 0.9825, which rounds down to $0.98 in tax
The probability that a first year student entering a certain private college needs neither a developmental math course nor a developmental English is 61% while 21% require a developmental math course and 37% require a developmental English course.
Find the probability that a first year student requires both a development math course and a developmental English course.
Answer:
7.77%
Step-by-step explanation:
When dealing with calculating a sequence of probabilities for an specific event such as this one you simply need to multiply the seperate probabilities of each part of the event happening together. Which in this case would be 21% and 37%. We first need to convert these percentages into decimal form by dividing each of them by 100. Once we have the decimal form we multiply them together to find the answer.
21% / 100 = 0.21
37% / 100 = 0.37
0.21 * 0.37 = 0.0777 ... multiply by 100 to get percent form
0.0777 * 100 = 7.77%
Finally, we can see that the probability that a first-year student requires both a developmental math course and a developmental English course is 7.77%
The probability that a first year student requires both a development math course and a developmental English course is 7.77%
Calculation of the probability:Since The probability that a first year student entering a certain private college needs neither a developmental math course nor a developmental English is 61% while 21% require a developmental math course and 37% require a developmental English course.
So, the probability is
[tex]= 0.21 \times 0.37[/tex]
= 7.77%
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can anyone help me ?
Answer: i think u got it write its that one
Step-by-step explanation:
HELP! WILL MARK BRAINLIEST!
Answer:
thank for the free point
Find the slope of the line from the table.
X
1
4
7
10
у
7
5
3
1
1
Kamama is making a quilt. She started with a hexagon that she loves. If Kamama wants the rest of her hexagons to be congruent, which transformations can
she use?
Please choose all of the transformations that she can use to create a congruent image.
Fun fact: Kamama is a Cherokee name meaning Butterfly.
Reflection
Translation
Dilation
Rotation
Based on the fact that Kamama wants her hexagons to be congruent, the transformations that she can use are:
ReflectionTranslationRotationWhat transformations give congruent shapes?In order to have congruent shapes, there are three transformations that can be used.
Firstly, it is important to note that congruent shapes have the same size and the same shape. They are identical except for their orientation which may be different.
A reflection would create a congruent shape that would have the same size and angles but the orientation should be different. This is the same as a rotation. A translation will often result in congruent shapes that also have the same orientation. This means that Kanama can use any of these transformations.
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Notes: Factorial function (symbols: !) says to multiply all whole numbers from our chosen number down to 1
Answer:
ggg if fdrsyviinoiv fcvui I tzhvii u u y
When using the quotient rule of exponents, you must _____
coefficients and _____
the exponents.
Answer:
When multiplying exponents of the same base, add the exponents. When dividing exponents of the same base, subtract the exponents. When raising a power to a power, multiply the powers.
Step-by-step explanation:
HIIIIIII ILL MARK BRAINLIEST
is this correct?
Answer:
No, it isn't.
Step-by-step explanation:
The point on y = 5 should be on y = 7, and the point on x = 5 should be on x = 7. The attachment shown is what the graph should look like.
after eating La Huerta your subtotal was 25.72$ you want to leave a 15% tip. 15% as a decimal is
Help help help ! :)
Which equation’s line is steeper and explain how you know
The equation's line that is steeper is y = 3x + 7
Slope of a lineFrom the question, we are to determine which of the given equations' line is steeper
The given equations are
y = 3x + 7
and
y = (1/2)x + 9
First, we will compare the equations to the form of an equation of a straight line
The equation of a straight line is of the form
y = mx + c
Where m is the slope
and c is the y intercept
Thus,
The slope of the equation, y = 3x + 7, is 3
and
The slope of the equation, y = (1/2)x + 9, is 1/2
NOTE: The higher the slope of a line, the steeper the line
Hence, the equation's line that is steeper is y = 3x + 7
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Use the graph of the function to find its domain and range. Write the domain and range in interval notation.
Answer:
domain: [-4, ∞)
range: [-6, ∞)
Step-by-step explanation:
look at the graph. for domain, you want the x-values included in the interval. the endpoint at -4 means that the domain begins at -4. since the graph extends to positive infinity, then include that in domain with an parentheses not bracket since there's no endpoint.
for range, do the same thing but for y-values.
The domain and the range of a function are the possible x and y values it can take
The domain of the function is: [tex][-4, \infty)\\[/tex].The range of the function is: [tex][-6,\infty)[/tex]The domain
From the graph, the x-value starts at x = -4, and it continues to the right.
The dot at x = -4, means that -4 is inclusive of the x values.
The arrow at the other end means that, the value increases to infinity.
So, the domain of the function is: [tex][-4, \infty)\\[/tex]
The range
From the graph, the y-value starts at y = -6, and the curve open upwards
The arrow at the other end means that, the value increases to infinity.
So, the range of the function is: [tex][-6,\infty)[/tex]
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50 POINTS!!!!
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=-16x^2+212x+139
-3/4x + 5 = -4 What is the value of x?
Answer:
12
Step-by-step explanation:
The indefinite integral of ((6e^4x)(e^arctan(3e^4x)))/(1+9e^8x)
Answer:
[tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{e^\big{arctan(3e^{4x})}}{2} + C[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Integration
Integrals[Indefinite Integrals] Integration Constant CIntegration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
U-SolveStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integrand] Rewrite: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \int {\frac{6e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = 6\int {\frac{e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex]Step 3: integrate Pt. 2
Set variables for u-substitution.
Set u: [tex]\displaystyle u = 4x[/tex][u] Differentiate [Basic Power Rule, Multiplied Constant]: [tex]\displaystyle du = 4 \ dx[/tex]Step 4: Integrate Pt. 3
[Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{4e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex][Integral] U-Substitution: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(3e^u) + u}}{1 + 9e^\big{2u}}} \, du[/tex]Step 5: Integrate Pt. 4
Set variables for u-substitution #2.
Set v: [tex]\displaystyle v = 9e^{2u} + 1[/tex] [v] Differentiate [Exponential Differentiation, Chain Rule]: [tex]\displaystyle dv = 18e^{2u} \ du[/tex][v] U-Solve: [tex]\displaystyle u = ln \Big( \frac{\sqrt{v - 1}}{3} \Big)[/tex][dv] U-Solve: [tex]\displaystyle du = \frac{e^{-2u}}{18} \ dv[/tex][U-Solve] Rewrite u: [tex]\displaystyle e^u = \frac{\sqrt{v - 1}}{3}[/tex]Step 6: Integrate Pt. 5
[Integral] U-Solve: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(3(\frac{\sqrt{v - 1}}{3})) + ln(\frac{\sqrt{v - 1}}{3})}}{1 + 9(\frac{\sqrt{v - 1}}{3})^2} \frac{1}{18e^{2u}}\, dv[/tex][Integral] Simplify: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{\sqrt{v - 1}e^\big{arctan(\sqrt{v - 1})}}{3[1 + v - 1]} \frac{1}{18(\frac{\sqrt{v - 1}}{3})^2}\, dv[/tex][Integral] Simplify: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{\sqrt{v - 1}e^\big{arctan(\sqrt{v - 1})}}{3v} \frac{1}{2(v - 1)}\, dv[/tex][Integral] Simplify: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(\sqrt{v - 1})}}{6v\sqrt{v - 1}} \, dv[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{1}{4}\int {\frac{e^\big{arctan(\sqrt{v - 1})}}{v\sqrt{v - 1}} \, dv[/tex]Step 7: Integrate Pt. 6
Set variables for u-substitution #3.
Set z: [tex]\displaystyle z = arctan(\sqrt{v - 1})[/tex][z] Differentiate [Arctrig Differentiation, Chain Rule]: [tex]\displaystyle dz = \frac{1}{2v\sqrt{v - 1}} \ dv[/tex]See attachment for rest of work (would not fit entire answer in answering box).
Urgent! Please help me! Math question. Please.
Answer:
A and C
Step-by-step explanation:
First because "AAS" is when we know two angles and one side (which is not between the angles). To solve an AAS triangle. use the three angles add to 180° to find the other angle. then The Law of Sines to find each of the other two sides.
And then C because all angles have to equal to the other angle pattern
Some one please help
I have attached the question
Answer:
a number question's answer is a power 2. and is c power 1
At age 30 you deposit $150 at the end of each month into an IRA that pays 4% interest compounded monthly. In the previous question, we found that the value of the annuity at age 65 would be $137,059.64. How much interest did you earn?
According to the given statement the interest that we earn is
= $74,059 . 64
What Is an Annuity's Present Value?The present value of an annuity seems to be the current worth of future annuity payments based on a predetermined rate of return, as well as discount rate. The higher the discount rate, the smaller the annuity's present value.
According to the given data:monthly payment is 150
at the age = 30
interest rate = 4
till age of = 65
At age 65, the annuity would be worth $137,059.64.
We only need to determine the amount of interest. = ?
for monthly payments, we need to take n, which equals 12 points now total interest. determined by future value. Substitute minus p m t multiplied by n multiplied by t for all values now.
the amount of interest = deposited amount x year x no of year invested
= 150 x 12x(65-30)
present value = 63000
At age 65, the annuity would be worth $137,059.64.
We know that the interest is = balance - capital
= 137,059.64 - 63000
= $74,059 . 64
According to the given statement the interest that we earn is
= $74,059 . 64
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A magazine survey of a five-year period considered 100 featured actors. The
table to the right shows the "worst" ten actors, in terms of how much their
films returned per dollar that the actor earned.
The set of actors with at least a return of $7.50 are {H, J, K}
What are the set of actors?The actors that would be included in this set include actors that earn an amount equal to $7.50 or an amount greater than $7.50.
A set can be described as a collection of objects whose elements are fixed and cannot be changed. Thus, elements in this set would include those who earn more than or equal to $7.50.
To write a set in a roster form, the elements in the set are written in a row within curly brackets or braces - { }. The elements in the set are then separated by commas.
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The area of the figure is
square units.
Answer:
80 square units
Step-by-step explanation:
The figure given can be decomposed to have two trapezoids of equal dimensions and a rectangle.
Area of the figure = (2*area of a trapezoid) + (area of a rectangle)
Area of the 2 trapezoids:
Area of the two trapezoid = 2(½(a + b)*h)
Where,
a = 2 + 6 + 2 = 10 units
b = 6 units
h = 2 units
Plug in the values:
Area of the two trapezoid = 2(½(10 + 6)*2)
= 2(½(16)*2)
Area = 32 units²
Area of the rectangle:
Area = length × width
Length = 8 units
Width = 6 units
Area = 8 × 6 = 48 units²
✔️Area of the figure = 32 + 48 = 80 units²
just read the picture and thats the question
Answer:
a) The negative sign indicates that progression is decreasing in time and decreases by 18 percent each month.
b) Antonio is expected to make a profit of 37445.17 in 7 months from now.
Step-by-step explanation:
a) The equation described on statement represents a geometrical progression, which is defined as:
[tex]y = C_{o}\cdot (1+ r)^{x}[/tex] (1)
Where:
[tex]C_{o}[/tex] - Initial amount, measured in monetary units.
[tex]r[/tex] - Rate, dimensionless. (The progression is increasing when [tex]r > 0[/tex], and decreasing when [tex]-1 < r < 0[/tex])
[tex]x[/tex] - Time, measured in months.
[tex]y[/tex] - Profit, measured in monetary units.
Given that [tex]y = 150,210\cdot (0.82)^{x}[/tex], we calculated the rate below:
[tex]1+r = 0.82[/tex]
[tex]r = 0.82-1[/tex]
[tex]r = -0.18[/tex]
The negative sign indicates that progression is decreasing in time and decreases by 18 percent each month.
b) If we know that [tex]x = 7[/tex], then the expected amount for Antonio in 7 months from now is:
[tex]y = 150,210\cdot (0.82)^{7}[/tex]
[tex]y = 37445.17[/tex]
Antonio is expected to make a profit of 37445.17 in 7 months from now.
Use the distributive property to write an expression that is equivalent to:
3(x + 5)
Answer: 3x + 15
Step-by-step explanation:
In order to use the distributive property, you simply multiply the number on the outside by both the number inside the parenthesis
So, in this case, we would multiply 3 by X and 3 by 5
3 times x = 3x
3 times 5 =15
Your new equation is then made by adding these two together
3x+15
Answer 3x + 15
what is the result if you decrease the sum of 78.932 and 721.832 by 389.823 pls
Answer:
410.941
Step-by-step explanation:
Pleaseee help me on this question
Answer:
B
Step-by-step explanation:
For every 1 liter of water, 0.07 kilograms of salt must be added. They are asking for 0.5 liters of water, which is half of 1 liter. So therefore, they need half of 0.07 kilograms of salt, which is 0.035 kilograms
Answer:
0.035 kg.
Step-by-step explanation:
0.5 liter is 1/2 liter
0.07kilograms / 2 = 0.035kg
y= 1/3 x+2
y = -x-2
Write solution as an ordered pair
Answer: (-3,1)
Step-by-step explanation:
inputting the two equations into a graphing calculator tells us that these two lines intersect at the point (-3,1)
25% discount for AED 4000
Answer:
The 25% discount on AED 4000 will be: 1000 AED
Step-by-step explanation:
Given
The amount = 4000Discount = 25%In order to determine a 25% discount on the amount AED 4000, all we need means is to multiply 25/100 or (0.25) by 4000.
i.e
Discount amount = 25% of 4000
= 25/100 × 4000
= 0.25 × 4000
= 1000 AED
Thus, the 25% discount on AED 4000 will be: 1000 AED
Of the following fractions: 3/7, 5/8, 7/13, and 11/19, which is the largest?
Answer:
Step-by-step explanation:The largest fraction is 5/8
1. In the first week, he spent $16 on lunches. How much was in his account then?
Answer:
hen he deposited some more money and his account balance was $28.
Step-by-step explanation:
Answer:7
Step-by-step explanation:
An airplane is flying at a constant speed of 500 mph at a bearing of 45° north of west. A 40 mph wind is blowing due south. What are the plane's actual speed and direction? Draw a diagram and show your work to justify your answer. Round the speed to the nearest tenth and the direction to the nearest degree. (5 points)
Answer:I’m pretty sure I got this one right too
Step-by-step explanation:
The actual speed of the airplane is 472.56 mph in the direction of 41.57° north of west.
What are the x and y-components of a vector?"In a two-dimensional coordinate system, any vector can be broken into x -component and y -component according to axis."
We can assume, east as the positive x- axis and north as the positive y-axis, respectively.
Similarly, west as the negative x- and south as the negative y-axis, respectively.
Therefore, the x- and y-components of the speeds.
Now, for the airplane:
x-component: - 500 × cos(45°) mph = - 353.55 mph
y-component: 500 × sin(45°) mph = 353.55 mph
For the wind:
y-component: -40 mph
Therefore, sum of the x-components = -353.55 mph
Similarly, sum of the y-components = (353.55 - 40) mph = 313.55 mph
Now, the actual speed =
[tex]\sqrt{(-353.55)^{2} + (313.55)^{2}}[/tex] mph
= [tex]\sqrt{223313.6}[/tex] mph
= 472.56 mph
Now, the direction of the airplane is:
tan(Ф) = [tex]\frac{313.55}{- 353.55}[/tex]
⇒ Ф = tan⁻¹( [tex]\frac{313.55}{- 353.55}[/tex])
⇒ Ф = - 41.57°
The actual speed of the airplane is 472.56 mph in the direction of 41.57° north of west.
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