A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?
Answer:
20 ohms
Explanation:
Resistance=Potential difference÷Electric current
X=260÷13
X=20
People wear special snowshoes when there is a snowfall in the cold countries. Why?
Answer:
The fundamental function of snowshoes is to offer float, allowing you to avoid sinking into snow. Hikers who do not have snowshoes may find themselves knee- or waist-deep in unconsolidated snow if they attempt to traverse it without snowshoes, a practice known as post-holing.
Explanation:
Answer:
Explanation:
I live in a cold country and I own snow shoes. I have to confess I've never thought about this question before.
If the snow is fresh, it is also very loosely packed. If you wear ordinary shoes, the first thing that will happen is that you will sink. How far depends on how deep the snow is. I can see you up to your waist in snow, if the snowfall is heavy enough.
So to prevent that, my snowshoes are 3 feet long and about 1 foot wide, Except for a small hole near the middle, the entire area is covered. I weigh about 140 pounds.
A very small calculation should tell you that if I wear house shoes (mine are 8" long by about 3 inches wide). The pressure is going to be 140 pounds / (2/3 * 1/4) = 140 // 2/12 = 140 / 1/6 = 140 * 6 = 840 pounds / square foot. Trust me, that is a lot of pressure.
What do the snowshoes accomplish?
140 / (3*1) = 46.7 pounds per square foot. You might sink a little, but you are not going down as far as you would with street clothes shoes.
The units are not the normal units you would use, but the ratio is going to be roughly the same. 840 / 46.
All of this is very approximate. That's what physics is all about. Approximations lead you to understanding.
what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is D
Answer:
what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is B
Explanation:
CARRY ON LEARNING
Find the velocity of a body of mass 100 g having kinetic energy of 20 J.
Answer:
Explanation:
Let v be the velocity of object ,
Given that mass of object , m=100 g=
1000
100
kg=0.1 kg
& kinetic energy of object =20 J
K.E =
2
1
mv
2
20=
2
1
×0.1v
2
⟹v
2
=400
⟹v=20 m/s
1+1 =?
2+2=?
3+3=?
1+1 =?
2+2=?
3+3=?
Answer:
here is your answer
1+1=2
2+2=4
4+4=8
Who is the author "talking” to in the third stanza of Flanders field
Answer:
One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.
Explanation:
Gas sample A has a mass of 32.00 grams. Gas sample B has a mass of 28.00
grams. If the two gas samples are both at 25°C, which sample has the greatest
average kinetic energy?
Answer:
I think 32.00
Explanation:
Because the equation is mass times velocity so is you mutiply 32 by 25 and 28 times 25 sample A would be greater.
The sample with the greatest average kinetic energy is sample A
The average kinetic energy of a sample can be estimated by the formula one-half of the mass sample multiplied by the speed (RMS) squared.
Mathematically, we have:
[tex]\mathbf{K.E_{avg} = \dfrac{1}{2}mv_{rms}^2}[/tex]
If the mass of sample A = 32.00 grams, andThe mass of sample B = 28.00Provided that the speed (RMS) is constant, the average kinetic energy of sample A will be greater than the average kinetic energy of sample B because sample A has a greater mass than sample B.
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How much work is required for a 74 kg sprinter to accelerate from rest to 2.2 m/s?
Answer:
179.1 kg
Explanation:
Answer:
Should be 179.1 kg
Explanation:
how much of the light that reaches the earth from the sun is used for photosynthesis
Answer:
Less than one percent of the total energy that reaches Earth is used by plants for photosynthesis
Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
A car of mass 1500 kg is moving with a velocity of 30 m/s. If the velocity-time graph for this car
is a horizontal line parallel to the time axis, then the velocity of the car at the end of 25 s will be
Answer:
v=30m/s
Explanation:
m = 1500kg
v = 30m/s
t = 25s
The velocity time graph is parallel to the time axis,
that means The Velocity is constant. ('constant' means remains same).
Therefore, after 25s, v=30m/s
On some strange planet you find that a 17.4 kg object falls downward 28.8 meters in 5.5 seconds. What is the magnitude of the acceleration due to gravity on this planet
Hi there!
[tex]\large\boxed{g = 1.904 m/s^2}[/tex]
Acceleration of gravity is unaffected by an object's mass.
In the absence of air resistance, we can use the following kinematic equation:
d = vit + 1/2at²
The object falls from rest, so:
d = 1/2at²
The acceleration in this instance is gravity, our unknown. We can rearrange the equation to solve for 'g':
2d/t² = g
2(28.8)/(5.5²) = 1.904 m/s²
What kind of feature results from the convergence of two oceanic plates?
A.
island arcs
B.
massive continental volcanoes
C
rift valleys
D.
tall mountain ranges
Answer:
A
Explanation:
Convergence is pushing them together so C is out of the question.
B and D are wrong because it is an oceanic plate. B and D are for continental plates.
If F = 4.0 N and m = 2.0 kg, what is the magnitude a of the acceleration for the block shown below? The surface is frictionless. *
The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]
The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]
What do you mean by acceleration?Acceleration is the rate of change of velocity with time.
By Newton’s Second law
This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.
Given,
The mass of the block is 2.0 kg.
The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]
a is the acceleration in the horizontal direction.
The acceleration for the block can be determined using Newton’s Second law,
[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]
Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]
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If the ball has a positive electric charge, what should the charge of the coilgun be to push the ball away?
A)positive
B) negative
C)neutral
Answer:
A
Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.
Explain how work and power are different. Give an example of doing the same amount of work, but producing different amounts of power.
Answer:Work is a measurement of energy.
Power is a measurement of energy per time.
So, power measures how fast work is done.
If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.
An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill
Answer:
work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.
The following diagram shows a person exerting a
300.-newton force on the handle of a shovel that
makes an angle of 60. with the horizontal ground.
Determine the magnitude of the component of the
force perpendicular to the ground.
Answer:
260 Newtons
Explanation:
Okay, so what you have to do is know what the question is asking. It wants to know the force perpendicular to the ground. We know perpendicular makes a right angle, so we use the diagram to make it into a right triangle with a degree of 60, and hypotunese of 300 newtons. Now, we use basic trigonometry, we place x on the horizontal side since it perpendicular to the ground. We know it´s sin because x is opposite to 300 which is the hyp.
Sin= opp/hyp
x/300
sin(60)= x/300
300*sin(60)= 259.8, which rounds to
260 Newtons
There is your answer :D. Happy to help.
The component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
What are the components of a Vector?A vector V making an angle θ with the x - axis, can be resolved into two two components along the x and y - axes respectively as →
V = Vcosθ a[x] + Vsinθ a[y]
where -
a[x] is the unit vector along the +x axis
a[y] is the unit vector along the +y axis.
Given is a force of magnitude 300 N acting on the handle that makes an angle of 60° with the horizontal ground.
The component normal to the ground will be the component along the y - axis. The component along the y - axis is the sine component. Suppose that vector F represents the force of magnitude (|F|) 300 N. The component perpendicular to the ground will be -
F [y] = |F| sinθ a[y]
F [y] = 300 x sin(60°) a[y]
F [y] = 300 x 0.87
F [y] = 261 a[y]
Therefore, the component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
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A boy standing on a bridge 150m above the canyon floor throws a stone downward with a speed of 20.0m/s.
A) with what velocity will it hit the ground?
B) How long will it take to descend?
Answer:
57.97m/s
12.1s
Explanation:
Use one of the key equations of accelerated motion and sub in the values
vf^2=vi^2+2aΔd
vf^2=(20)^2+(2*9.8)(150)
vf^2 = 3340
vf = 57.79m/s (square rooted both sides)
now use another equation
Δd = (vi+vf/2)Δt
and rearrange for Δt
Δt = (2Δd-vf)/vi
sub in values
Δt = (2*150-57.79)/20
Δt = 12.1s
mark me as brainliest if this helped!
1 Loudness and pitch are two important properties of a musical sound.
a If a musician plays a softer note, which property has been changed,
loudness or pitch?
b If the musician makes the note lower, which property has been
changed, loudness or pitch?
A piece of wood has a mass of 8g and a volume of 10cm³. Work out the density of the wood in /3 .
no links please just explain how you got the answer.
Answer:
8×10^-3÷10×10^-6=8×10^2=800 kg/m^3
Answer:
2.4/3
Explanation:
first we make 8g/10cm then 0.8 so the only number that can fit for /3 is 2.4
hope helped!
In which of the cases below is friction most helpful?
A.
between a moving box and a ramp
B.
between car tires and a road
C.
between a person and a playground slide
D.
between ice skates and an ice rink
Answer:
between car tires and a road
Explanation:
1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m
Answer:
i think its going to be 150 because its half of 300
Explanation:
Please help thank you!
Answer:
mass, weight
Explanation:
mass is constant, and weight is dependant on your location
Answer:
I think d
Explanation:
because distance j
has to be the last one that's the only one with distance
Terri is excited about the baby she is carrying in her womb. One day, she tells her
cousin that the child is now the size of a grape. Weeks later, she describes the child as
the size of an apple. A few weeks after that, she describes the child as the size of a
banana. "Seriously, Terri, are you having a baby or shopping for groceries?" asks her
cousin. Terri explains that this is just the easiest way to describe the size of the baby
now that it is a(n)
Zygote
O Fetus
O Embryo
Infant
Answer:
Fetus
Explanation:
the outsiders I got nuggets out of the elder and I get to make it in and I got I got
URGENT NEED GIVING POINTS question is how do i find R and the angle THANK YOU
Answer:
Theta = 26.93°
R = 0.38m
Explanation:
Theta = cos^-1(0.74m/0.83m)
Theta = 26.93°
R = sqrt(0.83²-0.74²)
R = 0.38m
What is Space debris ?
Answer:
Space junk, or space debris, is any piece of machinery or debris left by humans in space. It can refer to big objects such as dead satellites that have failed or been left in orbit at the end of their mission. It can also refer to smaller things, like bits of debris or paint flecks that have fallen off a rocket.
Answer:
In addition to derelict man-made objects left in orbit, other examples of space debris include fragments from their disintegration, erosion and collisions or even paint flecks, solidified liquids expelled from spacecraft, and unburned particles from solid rocket motors. Space debris represents a risk to spacecraft.
Explanation:
What is meant by collisions?
Answer:
come into conflict or opposition.
"in his work, politics and metaphysics collide
A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.
Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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In the very distant future, given our best model of the accelerating universe, what will the universe look like?
The models of the universe allow finding the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.
Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.
Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.
In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
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A galaxy spectrum has a redshift of 70,000 km per second. If the Hubble constant is 70 km per second per Mpc (megaparsec), how far away from us in this galaxy
Using the Hubble law v = H₀d where v = recessional speed = 70,000 km per second H₀ = hubble constant = 70 km/s/Mpc and d = distance of galaxy.
Making d subject of the formula, we have
d = v/H₀
Substituting the values of the variables into the equation, we have
d = v/H₀
d = 70000 km/s/70 km/s/Mpc
d = 1000 Mpc
So, the galaxy is 1000 Mpc away from us.
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