Answer:
Explanation: I don't know English very well but I will try to explain to you. We need head tag in HTML -> for enter the title of the page, add extra meta data, put a picture title bar of the document and connect with another document
What will be the output?
class num:
def __init__(self, a);
self.number = a
def_mul__(self,b):
* return self.number + b.number
#main program
numA = num(8)
numB = num(4)
result = numA* numb
print(result)
O4
O 12
O 32
4096
the variable a & b and A & B are different. So the only program that work is at #main program.
Hence that A = 8 and B = 4 and the result is A * B so 8*4=32.
Sorry if im wrong
32 will be the output of this question
What is the output?An industry's output is the total amount of goods and services generated within that industry over a specific time period and sold to customers or other firms. An industry's annual production of boxes of cookies or tons of sugar, for instance, can be considered output.
The quantity a person produces in a particular period of time. d.: energy or power given or produced by a device or system (as for storage or for conversion in kind or in characteristics)Here is how we might define these two phrases in business terms: The results are what the business requires or wants to accomplish. The acts or things that help achieve an outcome are called the outputs.
Variables a and b and A and B are distinct. Thus, the #main program is the only program that functions. Because A = 8 and B = 4, the outcome is A * B, which equals 8*4=32.
Therefore, the output of this question
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Pls help I will give points
Answer:
phone !!
Explanation:
since it's a mobile app, that would apply to a handheld device !!
i hope this helps !!
Answer:
any answer except a desktop or laptop, i.e. tablets, phones, pda's, etc.
Explanation:
Mobile apps are designed for handheld mobile devices, even though laptops are technically mobile, they're based upon desktop computer arcitechture, in which mobile apps will not run, I hope this helps.
(Please Help! Timed Quiz!) Messages that have been accessed or viewed in the Reading pane are automatically marked in Outlook and the message subject is no longer in bold. How does a user go about marking the subject in bold again?
*Mark as Read
*Flag the Item for follow-up
*Assign a Category
*Mark as Unread
Answer:
D Mark as Unread
Explanation:
I just took the test
A room has one door, two windows, and a built-in bookshelf and it needs to be painted. Suppose that one gallon of paint can paint 120 square feet. Write a program that prompts the user to input the length and width (in feet) of: The door Each window The bookshelf And the length, width, and height of the room. The program outputs: The amount of paint needed to paint the walls of the room.
Answer:
In Python:
doorLength = float(input("Door Length: "))
doorWidth = float(input("Door Width: "))
windowLength1 = float(input("Window 1 Length: "))
windowWidth1 = float(input("Window 1 Width: "))
windowLength2 = float(input("Window 2 Length: "))
windowWidth2 = float(input("Window 2 Width: "))
shelfLength = float(input("Bookshelf Length: "))
shelfWidth = float(input("Bookshelf Width: "))
totalarea = doorLength * doorWidth + windowLength1 * windowWidth1 + windowLength2 * windowWidth2 + shelfLength*shelfWidth
gallons = totalarea/120
print("Gallons: "+str(gallons))
Explanation:
The next two lines get the dimension of the door
doorLength = float(input("Door Length: "))
doorWidth = float(input("Door Width: "))
The next two lines get the dimension of the first window
windowLength1 = float(input("Window 1 Length: "))
windowWidth1 = float(input("Window 1 Width: "))
The next two lines get the dimension of the second window
windowLength2 = float(input("Window 2 Length: "))
windowWidth2 = float(input("Window 2 Width: "))
The next two lines get the dimension of the shelf
shelfLength = float(input("Bookshelf Length: "))
shelfWidth = float(input("Bookshelf Width: "))
This calculates the total area of the door, windows and bookshelf
totalarea = doorLength * doorWidth + windowLength1 * windowWidth1 + windowLength2 * windowWidth2 + shelfLength*shelfWidth
This calculates the number of gallons needed
gallons = totalarea/120
This prints the number of gallons
print("Gallons: "+str(gallons))
CH4 has how many of each type of atom?
Its easy that moderators that see this answer can think that my answer isn't without explanation.
• Type of atom C (Carbon)
C = 1
• Type of atom H (Hydrogen)
H = 4
You dont understand? JUST SEE THE FORMULA C MEANS ONLY HAVE 1 CARBON ATOM AND H4 MEANS 4 ATOM OF HYDROGEN
oK. have a nice day hope you understands
ANSWER QUICK 50 POINTS
You have the following code in your program.
from array import *
Which line of code would create an array?
D = array([2.5, 3, 7.4])
D = array('f',[2.5, 3, 7.4])
D = array['f',[2.5, 3, 7.4]]
D = array('f',2.5, 3, 7.4)
Answer:
D = array('f',[2.5, 3, 7.4])
Explanation:
is the answer
A variable must be declared with an array type before the array itself can be created. Array types resemble other Java types, with the exception that square brackets are placed after them ( [] ). Thus, option D is correct.
What line of code would create an array?Using the NumPy library, new data types known as arrays can be produced in Python. NumPy arrays are created for numerical studies and only contain one data type.To build an array, use the array() method after importing NumPy. The input for the array() function is a list.
An array, also known as a database system, is a group of things or data that is held in a contiguous memory area in coding and programming. Several instances of the same kind of data are grouped together in an array.
Therefore, D = array('f',2.5, 3, 7.4) line of code would create an array.
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Overview
A big group of 15 guests is getting together at a restaurant for a birthday. The restaurant has 3 tables that can each seat only 5 people. Below you can find some information about the people who are attending the party.
Aysha, Ben, Carla, Damien, Eric, Fan, Genaro, Hannah, Isaias, Jessica, Kyla, Laila, Max, Nazek, Owen
Close Friends (Try to put them together)
Aysha and Damien
Max and Isaias
Nazek and Laila
Owen and Genaro
Ben and Jessica
Genaro and Eric
In a Fight (Try to keep them apart)
Aysha and Genaro
Ben and Hannah
Fan and Max
Damien and Laila
Isaias and Owen
Kyla and Jessica
Objective
Find the best possible arrangement of guests at the party. Draw your solution in the space below. To help you can cross out the letters of the names you’ve assigned in the row below.
A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
Answer:
the answer is in the image below:
Explanation:
what are the pros and Con's of human -computer interaction?
Answer:
pros-you can talk to a man made intelligence without the drama except for system crashes lol
-you can have them as a romantic partner.
cons-there are programmed emotions so it isn’t that real.
romantic emotion can be fake.
Explanation:
Pls awnser I will mark brainliest as soon as possible
Answer:
Andriod
Explanation:
Your computer system looses power while you are working on a project for a very important client
isljgaek jadkghdkjhasdkjfhadskj afhdsfkjdahk dh
Answer:
I never knew that, thank you for telling me! I'll note that down
Vampire Diaries Trivia
Alaric.....?
What were the first vampires called?
How did Elena's parents die?
Answer correctly and you will get Brainliest and 10 points.
Answer:
Alaric Saltzman.
The Originals.
Car crash, ran off Wickery bridge.
Explanation:
Answer:
okkk I got this TVD since forever
Explanation:
Alaric Saltzman
They are called the original vampires (Mikael, Finn, Elijah, Klaus, Kol, and Rebekah)
Elena parents died on the way back home from picking up Elena from a party. They end up driving off the Wickery Bridge. Stefan saved Elena though he was going to save Elena dad first however her dad told Stefan to get Elena.
Given three subroutines of 550, 290, and 600 words each, if segmentation is used then the total memory needed is the sum of the three sizes (if all three routines are loaded). However, if paging is used, then some storage space is lost because subroutines rarely fill the last page completely, and that results in internal fragmentation. Determine the total amount of wasted memory due to internal fragmentation when the three subroutines are loaded into memory using each of the following page sizes:
a. 100 words
b. 600 words
c. 700 words
d. 900 words
Typically, external fragmentation wastes one-third of memory. Internal fragmentation occurs when space inside a designated region is wasted. Thus, option D is correct.
What wasted memory due to internal fragmentation?The mounted-sized block is allotted to a method whenever a request for memory is made. Internal fragmentation is the term used to describe the situation where the memory allotted to the method is a little bigger than the amount requested.
Normally, memory is allocated in uniformly sized blocks, but sometimes a process doesn't use the entire block, leading to internal fragmentation.
Memory fragmentation occurs when a memory allocation request can be satisfied by the whole amount of accessible space in a memory heap, but no single fragment (or group of contiguous fragments) can.
Therefore, when the three subroutines are loaded into memory using each of the following page sizes 900 words.
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In the computing environment the numerical value represented by the pre-fixes kilo-, mega-, giga-, and so on can vary depending on whether they are describing bytes of main memory or bits of data transmission speed. Research the actual value (the number of bytes) in a Megabyte (MB) and then compare that value to the number of bits in a Megabit (Mb). Are they the same or different
Answer:
1024 bytes in a megabyte and there are 8000000 bits in a megabyte. They are different.
Explanation:
There are 8000000 bits and 1024 bytes in one megabyte. They are unique.
What is Megabyte?The megabyte is a multiple of the digital informational unit byte. The suggested unit sign for it is MB. The International System of Units unit prefix mega is a multiplier of 1000,000. As a result, one megabyte is equal to one million bytes of data.
About a million bytes make up a megabyte (or about 1000 kilobytes). Typically, a few megabytes might be required for a 10-megapixel digital camera photograph or a brief MP3 music clip.
1000000 bytes make up one megabyte (decimal). In base 10, 1 MB equals 106 B. (SI). 1048576 bytes make up a megabyte (binary). A megabyte can imply either 1,000,000 bytes or 1,048,576 bytes, according to the Microsoft Press Computer Dictionary. Apparently, Eric S.
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LAB: Even/odd values in an array
Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers in the list. The first integer is not in the list. Assume that the list will always contain less than 20 integers.
Ex: If the input is:
5 2 4 6 8 10
the output is:
all even Ex:
If the input is:
5 1 -3 5 -7 9
the output is:
all odd
Ex: If the input is:
5 1 2 3 4 5
the output is:
not even or odd
Your program must define and call the following two methods. isArrayEven() returns true if all integers in the array are even and false otherwise. isArrayOdd() returns true if all integers in the array are odd and false otherwise.
public static boolean isArrayEven(int[] arrayValues, int arraySize)
public static boolean isArrayOdd(int[] arrayValues, int arraySize)
LabProgram.java
Load default template
1 import java until Scanner
2
3 public class ropa
4
5 /* Define your method here */
6
7 public static void main(Strist args) {
8 /* Type your code here */
9 }
10
11
11
Answer:
In Java:
import java.util.*;
public class Main{
public static boolean isArrayEven(int[] arrayValues, int arraySize){
boolean val = true;
int odd = 0;
for(int i =0;i<arraySize;i++){
if(arrayValues[i]%2!=0){
odd++; }}
if(odd>0){
val = false;}
return val;
}
public static boolean isArrayOdd(int[] arrayValues, int arraySize){
boolean val = true;
int even = 0;
for(int i =0;i<arraySize;i++){
if(arrayValues[i]%2==0){
even++;}}
if(even>0){
val = false;}
return val;
}
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Array Length: ");
int n = input.nextInt();
int[] array = new int[n];
System.out.print("Array Elements: ");
for(int i = 0;i<n;i++){
array[i] = input.nextInt(); }
boolean even = isArrayEven(array,n);
boolean odd = isArrayOdd(array,n);
if(even == true && odd == false){
System.out.print("all even"); }
else if(even == false && odd == true){
System.out.print("all odd"); }
else{
System.out.print("not even or odd"); }
}
}
Explanation:
This declares the isArrayEven method
public static boolean isArrayEven(int[] arrayValues, int arraySize){
This initializes the return value to true
boolean val = true;
This initializes the frequency of odd numbers to 0
int odd = 0;
This iterates through the array
for(int i =0;i<arraySize;i++){
This checks if the current array element is odd
if(arrayValues[i]%2!=0){
If yes, the frequency of odd numbers is incremented by 1
odd++; }}
If the frequency of odd is greater than 1, then the array is not an even array
if(odd>0){
val = false;}
This returns true or false
return val;
}
This declares the isArrayOdd method
public static boolean isArrayOdd(int[] arrayValues, int arraySize){
This initializes the return value to true
boolean val = true;
This initializes the frequency of even numbers to 0
int even = 0;
This iterates through the array
for(int i =0;i<arraySize;i++){
This checks if the current array element is even
if(arrayValues[i]%2==0){
If yes, the frequency of even numbers is incremented by 1
even++;}}
If the frequency of even is greater than 1, then the array is not an odd array
if(even>0){
val = false;}
This returns true or false
return val;
}
The main method begins here
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
This prompts for length of array: System.out.print("Array Length: ");
This gets input for length of array int n = input.nextInt();
int[] array = new int[n];
This prompts for array elements: System.out.print("Array Elements: ");
This gets input for the array
for(int i = 0;i<n;i++){
array[i] = input.nextInt();
}
This calls the isArrayEven method and the result is stored in even
boolean even = isArrayEven(array,n);
This calls the isArrayOdd method and the result is stored in odd
boolean odd = isArrayOdd(array,n);
The following prints the result of the methods
if(even == true && odd == false){
System.out.print("all even"); }
else if(even == false && odd == true){
System.out.print("all odd"); }
else{
System.out.print("not even or odd"); }
A switch on a circuit board can be in two states what are they
Answer:
on and off
Explanation:
Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binary. For an integer x, the algorithm is:
As long as x is greater than 0
Output x % 2 (remainder is either 0 or 1)
x = x // 2
Note: The above algorithm outputs the 0's and 1's in reverse order. You will need to write a second function to reverse the string.
Ex: If the input is:
6
the output is:
110
Your program must define and call the following two functions. The function integer_to_reverse_binary() should return a string of 1's and 0's representing the integer in binary (in reverse). The function reverse_string() should return a string representing the input string in reverse.
def integer_to_reverse_binary(integer_value)
def reverse_string(input_string)
Note: This is a lab from a previous chapter that now requires the use of a function.
Answer:
#include <iostream>//header file
#include <string>//header file
using namespace std;
string integer_to_reverse_binary(int integer_value)//defining a method integer_to_reverse_binary
{
string ret = "";//defining string variable
while (integer_value > 0) //using while loop to check integer_value value is greater than 0
{
ret += '0' + (integer_value % 2);//adding zeros in remainder value
integer_value /= 2;//holding quotient value
}
return ret;//return string value
}
string reverse_string(string input_string)//defining a method reverse_string that holds a parameter user_String
{
string result;//defining a string variable
for (int i = 0; i < input_string.length(); ++i)//use for loop to calculate value
{
result += input_string[input_string.length()-i-1];//add value in result variable
}
return result;//result result variable value
}
int main()//defining main method
{
int num;//defining integer variable
string str;//defining string variable
cin >> num;//input num value
str = integer_to_reverse_binary(num);//use str variable to call the integer_to_reverse_binary method
cout << reverse_string(str) << endl;//printing the reverse_string method value
return 0;
}
Output:
6
110
Explanation:
In this code two string method "integer_to_reverse_binary and reverse_string" is defined that holds one parameter "integer_value and input_string".
In the first method a string variable is defined, that use the while loop to check integer value is greater than 0 and add zeros in the value and return its value as a string.
In the second it reverse the string value and store into the result variable, and in the main method the "num and str" variable is defined, and in the num it takes integer value and pass into the above method and print its return value.
Juan is writing a new program using Python and wants to make sure each step is located on its own line. Which principal of programming is Juan following?
Hand coding
Line coding
Planning & Design
Sequencing
PLEASE HURRYYY THIS IS A FINAL EXAM :C
Answer:
Its sequencing or planning and design not 100%
Explanation:
Answer:
its sequencing
Explanation:
Someone please help ASAP will brainlist
Why were low quality video so often use when Internet connection we’re poorer than they are today
Answer:
The answer is C. "High-quality videos took too long to transfer" in Fundamentals of Digital Media.
what do the three dots : . seen in equations/proof mean
What is another name for control structure
Object
Sequence
Loop
Decision
Answer: Sequence
Brainliest me and reply if im right!
the internet is a network of only ten thousands computers true or false
With saying why true or why false
Thanks
Answer: False
Reason: There's a lot more then 10 thousand computers on the internet.
40 POINTS help please
Answer:
Explanation:
nice dave
What is the function for displaying differences between two or more scenarios side by side?
Macros
Merge
Scenario Manager
Scenario Summary
Answer:
its d
Explanation:
Answer:
scenario summary
Explanation:
______ are special characters that allow you to
search for multiple words at the same time.
-Find expressions
-Defined expressions
-Regular expressions
-Search expressions
Answer:
Defined Expression
Explanation:
This will be your answer
Write a program that calculates the area & perimeter of a rectangle, where
the values for width and length are given by the users.
Answer:
In Python:
Length = float(input("Length: "))
Width = float(input("Width: "))
Area = Length * Width
Perimeter = 2*(Length + Width)
print(Area)
print(Perimeter)
Explanation:
This gets the length from the user
Length = float(input("Length: "))
This gets the width from the user
Width = float(input("Width: "))
This calculates the area
Area = Length * Width
This calculates the perimeter
Perimeter = 2*(Length + Width)
This prints the area
print(Area)
This prints the perimeter
print(Perimeter)
Write a python 3 function named words_in_both that takes two strings as parameters and returns a set of only those words that appear in both strings. You can assume all characters are letters or spaces. Capitalization shouldn't matter: "to", "To", "tO", and "TO" should all count as the same word. The words in the set should be all lower-case. For example, if one string contains "To", and the other string contains "TO", then the set should contain "to".
1.Use python's set intersection operator in your code.
2.Use Python's split() function, which breaks up a string into a list of strings. For example:
sentence = 'Not the comfy chair!'
print(sentence.split())
['Not', 'the', 'comfy', 'chair!']
Here's one simple example of how words_in_both() might be used:
common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
Answer:
def words_in_both(a, b):
a1 = set(a.lower().split())
b1 = set(b.lower().split())
return a1.intersection(b1)
common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
print(common_words)
Explanation:
Output:
{'all', 'of', 'jack'}
The program returns the words which exists in both string parameters passed into the function. The program is written in python 3 thus :
def words_in_both(a, b):
#initialize a function which takes in 2 parameters
a1 = set(a.lower().split())
#split the stings based on white spaces and convert to lower case
b1 = set(b.lower().split())
return a1.intersection(b1)
#using the intersection function, take strings common to both variables
common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
print(common_words)
A sample run of the program is given thus :
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Assuming even parity, find the parity bit for each of the following data units. a. 1001011 b. 0001100 c. 1000000 d. 1110111
Answer:
b. 0001100
Explanation:
1100
1. Write a class Name that stores a person’s first, middle, and last names and provides the following methods:
public Name(String first, String middle, String last)—constructor. The name should be stored in the case given; don’t convert to all upper or lower case.
public String getFirst()—returns the first name
public String getMiddle()—returns the middle name
public String getLast()—returns the last name
public String firstMiddleLast()—returns a string containing the person’s full name in order, e.g., "Mary Jane Smith".
public String lastFirstMiddle()—returns a string containing the person’s full name with the last name first followed by a comma, e.g., "Smith, Mary Jane".
public boolean equals(Name otherName)—returns true if this name is the same as otherName. Comparisons should not be case sensitive. (Hint: There is a String method equalsIgnoreCase that is just like the String method equals except it does not consider case in doing its comparison.)
public String initials()—returns the person’s initials (a 3-character string). The initials should be all in upper case, regardless of what case the name was entered in. (Hint: Instead of using charAt, use the substring method of String to get a string containing only the first letter—then you can upcase this one-letter string. See Figure 3.1 in the text for a description of the substring method.)
public int length()—returns the total number of characters in the full name, not including spaces.
2. Now write a program TestNames.java that prompts for and reads in two names from the user (you’ll need first, middle, and last for each), creates a Name object for each, and uses the methods of the Name class to do the following:
a. For each name, print
first-middle-last version
last-first-middle version
initials
length
b. Tell whether or not the names are the same.
Here is my code. I keep getting a method error with getFullName in the Name.java file. Please help me re-write the code to fix this issue.
//Name.java
public class Name
{
private String firstName, middleName, lastName, fullName;
public Name(String first, String middle, String last)
{
firstName = first;
middleName = middle;
lastName = last;
String fullName = firstName '+' middleName '+' lastName;
}
public String getFirst()
{
return firstName;
}
public String getMiddle()
{
return middleName;
}
public String getLast()
{
return lastName;
}
public String firstMiddleLast()
{
return firstName + ' ' + middleName + ' ' + lastName;
}
public String lastFirstMiddle()
{
return lastName + ", " + firstName + ' ' + middleName;
}
public boolean equals(Name otherName)
{
return fullName.equalsIgnoreCase(otherName.getFullName());
}
public String initials()
{
return firstName.toUpperCase().substring(0,1)
+ middleName.toUpperCase().substring(0,1)
+ lastName.toUpperCase().substring(0,1);
}
public int length()
{
return firstName.length() + middleName.length() + lastName.length();
}
}
//NameTester.java
import java.util.Scanner;
public class NameTester
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
String firstName1 = new String();
String middleName1 = new String();
String lastName1 = new String();
String firstName2 = new String();
String middleName2 = new String();
String lastName2 = new String();
System.out.print("\nPlease enter a first name: ");
firstName1 = input.nextLine();
System.out.print("Please enter a middle name: ");
middleName1 = input.nextLine();
System.out.print("Please enter a last name: ");
lastName1 = input.nextLine();
Name name1 = new Name(firstName1, middleName1, lastName1);
System.out.print("\nPlease enter another first name: ");
firstName2 = input.nextLine();
System.out.print("Please enter another middle name: ");
middleName2 = input.nextLine();
System.out.print("Please enter another last name: ");
lastName2 = input.nextLine();
Name name2 = new Name(firstName2, middleName2, lastName2);
System.out.println();
System.out.println(name1.firstMiddleLast());
System.out.println(name2.firstMiddleLast());
System.out.println(name1.lastFirstMiddle());
System.out.println(name2.lastFirstMiddle());
System.out.println(name1.initials());
System.out.println(name2.initials());
System.out.println(name1.length());
System.out.println(name2.length());
if (name1.equals(name2))
System.out.println("The names are the same.");
else
System.out.println("The names are not the same.");
}
}
i dont know the answer lol thats too long
Explanation:
Find the unknown quantities
Answer:
I = 11/2 = 5.5
R = 60/11 ≈ 5.5Ω
Explanation:
You use V = I·R twice.
Entire circuit: 140 = I·(20+R)
Resistor: 30 = I·R
Solving this system of equations gives:
140 = I·(20+R) = 20I + IR
30 = I·R
140 = 20I + 30
20I = 110
I = 11/2 = 5.5
R = 60/11 ≈ 5.5Ω