What is the normality of the solution that results when 4.0g of Al(NO3)3 (MW = 213.0) is dissolved in enough water to give 250mL of solution? What is the molarity of the solution?

Answers

Answer 1

the normality of the solution that results when 4.0g of Al(NO₃)₃ (MW = 213.0) is dissolved in enough water to give 250mL of solution the molarity of the solution is 0.0751 M.

To calculate the normality and molarity of the solution, we need to know the number of moles of Al(NO₃)₃ in the solution.

The number of moles can be calculated as:

moles = mass / molar mass

where mass is the mass of Al(NO₃)₃ and molar mass is the molecular weight of Al(NO₃)₃.

Substituting the given values, we get:

moles = 4.0 g / 213.0 g/mol = 0.01878 mol

The volume of the solution is given as 250 mL, which is equivalent to 0.25 L.

The normality of the solution is defined as the number of equivalents of solute per liter of solution. For Al(NO₃)₃, each mole of the compound produces 3 moles of ions, so the number of equivalents of Al(NO₃)₃ is:

equivalents = moles x 3

Substituting the value of moles, we get:

equivalents = 0.01878 mol x 3 = 0.05634 eq

The normality can now be calculated as:

normality = equivalents / volume

Substituting the given values, we get:

normality = 0.05634 eq / 0.25 L = 0.225 N

Therefore, the normality of the solution is 0.225 N.

The molarity of the solution is defined as the number of moles of solute per liter of solution. The number of moles of Al(NO₃)₃ in 250 mL of solution is the same as the number of moles in 1 L of solution, which is 0.01878 mol. Therefore, the molarity of the solution is:

molarity = moles / volume

Substituting the given values, we get:

molarity = 0.01878 mol / 0.25 L = 0.0751 M

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Related Questions

Discuss two pre-requisite skills needed for students to learn the process of writing balanced chemical and ionic equations

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Answer:

Explanation:Two pre-requisite skills needed for students to learn the process of writing balanced chemical and ionic equations are:

1. Understanding of the periodic table and elements: Students must have a solid foundation in the periodic table, including recognizing elements by their symbols and understanding their properties, groups, and electron configurations.

2. Knowledge of chemical bonding and compound formation: Students should be familiar with the different types of chemical bonds (ionic, covalent, and metallic) and know how to construct chemical formulas for compounds based on their component elements and valence electrons.

using the balanced chemical reaction equations, and the energies of the reactants and products, calculate the combustion of glucose O2 = 498kj/1 mol o2, 1598kj/1mol H2O = 934kj/1mol H2O, use correct units

Answers

One mole of glucose burns to produce several gases. [tex]6600kJ[/tex] of power. Another way to put it is that the burning of glucose releases [tex]6600KJ/mol[/tex] thermal energy.

What's a straightforward explanation of combustion?

A chemical reaction between two or more substances, typically containing oxygen, is called combustion. It results in the production of light and heat in the form of a flame.

The correct chemical formula for the burning of glucose

[tex]C6H12O6 + 6O2 \rightarrow 6CO2 + 6H2O[/tex]

We can determine the change in enthalpy for this reaction by using the values provided for the enthalpies of formation of the reactants and products:

Reactants:

[tex]C_6H_1_2O_6[/tex] : not given

[tex]O2: -498 kJ/mol \times 6 = -2988 kJ/mol[/tex]

Products:

[tex]CO_2[/tex]: not given

[tex]H2O -1598 kJ/mol \times 6 = -9588 kJ/mol[/tex]

[tex]\Delta H = (\epsilon products) - (\epsilon reactants)[/tex]

[tex]\Delta H = (-9588 kJ/mol + 0) - (0 + -2988 kJ/mol)[/tex]

[tex]\Delta H = -6600 kJ/mol[/tex]

Therefore, One mole of glucose burns to produce several gases. [tex]6600kJ[/tex] of power. Another way to put it is that the burning of glucose releases [tex]6600KJ/mol[/tex] thermal energy.

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Acetylene (C₂H₂) gas is often used in welding torches because of the very high heat produced when it reacts with oxygen (O₂) gas, producing carbon dioxide
gas and water vapor. Calculate the moles of water produced by the reaction of 2.2 mol of acetylene. Be sure your answer has a unit symbol, if necessary, and
round it to the correct number of significant figures

Answers

Answer: 2.2 moles

Explanation:

To calculate the moles of water produced, we first need to write down the balanced chemical equation for the combustion of acetylene:

C₂H₂(g) + O₂(g) → CO₂(g) + H₂O(g)

To balance the equation, we need to make sure that there are the same number of atoms for each element on both sides of the equation. The balanced equation is:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

Now we can use stoichiometry to find the moles of water produced:

2.2 mol C₂H₂ * (2 mol H₂O / 2 mol C₂H₂) = 2.2 mol H₂O

So, 2.2 moles of acetylene will produce 2.2 moles of water when reacted with a sufficient amount of oxygen.

How many grams of solute are in the following solution?
250mL of 0.39M acetic acid, CH3CO2H

Answers

There are 5.85 grams of acetic acid (CH3CO2H) in the given solution.

To calculate the grams of solute in the given solution, we first need to calculate the number of moles of solute (acetic acid) present in the solution.

We know the volume of the solution (250 mL) and the molarity of the solution (0.39 M). We can use the following equation to calculate the number of moles of solute:

moles of solute = molarity × volume (in liters)

First, we need to convert the volume from milliliters to liters:

250 mL = 0.250 L

Now we can use the equation to calculate the number of moles of acetic acid:

moles of CH3CO2H = 0.39 M × 0.250 L = 0.0975 moles

Finally, we can use the molar mass of acetic acid to convert the number of moles to grams:

molar mass of CH3CO2H = 60.05 g/mol

grams of CH3CO2H = moles of CH3CO2H × molar mass of CH3CO2H

grams of CH3CO2H = 0.0975 moles × 60.05 g/mol = 5.85 g.

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An unknown element contains 11 protons, 11 neutrons and 12 electrons, which of the following options do you think the unknown element is?

Answers

Answer:Sodium

Explanation:Sodium has 11 protons, 11 nuetrons, and 12 electrons

what is the current produced y 120 volts passing through a resistance of 0.2 ohms?

Answers

Ohm’s Law states:

V= I • R

where V is voltage (volts)
where I is current (amps)
and R is resistance (ohms)

Rearrange the equation to solve for current:

I = V/R

Now plug in what you know:

I = (120 volts)/(0.2 ohms)

Solve for I:

I = 600 amps

Hope this helps!

help please been asking for days LOLLL keep getting the wrong answers.

Answers

Answer:

22.24°C.

Explanation:

The change in temperature of the iron can be calculated using the formula: ΔT = Q / (m * c), where ΔT is the change in temperature, Q is the heat added, m is the mass of the substance and c is the specific heat capacity.

Substituting the given values into the formula: ΔT = 115 cal / (47.0 g * 0.11 cal/g⋅°C) ≈ 22.24°C

So, the change in temperature of the iron is 22.24°C.

What is the base conjugate acid pair in this balanced equation NH3+HNO3→NH4+ + NO3-

Answers

Answer:

The base conjugate acid pair is NH3 and NH4+.

NH3/NH4+

hope this helps!!

12. 50cm³ of alcohol is mixed with 50cm³ of water. The volume of the mixture is 97cm³. Which o the following is the best explanation for this observation red?

Answers

The alcohol and water molecules sharing the same space leads to a more compact arrangement of the molecules in the combination, which is the best explanation for the observed drop in volume.

When alcohol and water are combined, what happens to the volume?

In this illustration, adding water to alcohol results in a final volume that is roughly 10% lower than the combined volumes of the two liquids. The "vanishing volume" results from variations in how the solvent molecules are packed in the mixture compared to the pure components.

Why does the volume drop when alcohol and water are combined?

Alcohol molecules slide into the spaces between the water molecules as it dissolves, reducing the volume.

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If 50cm³ of alcohol is mixed with 50cm³ of water. The volume of the mixture is 97cm³. What is the best explanation for this observation?

A. Water evaporates leading to decrease in volume of the mixture

B. Water and alcohol molecules react and form a compact solution

C. Alcohol being volatile evaporates and decreases the volume of the mixture

D. The alcohol and water molecules sharing the same space leads to the decrease in volume of the mixture

sample gas has a pressure of 6.8 kPa at 539K. If the temperature decreases to 211K, then what will be the new pressure?

Answers

Gay-Lussac's Law-

[tex] \:\:\:\:\:\:\star\longrightarrow \underline{\sf \boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}}[/tex]

[tex] \:\:\:\:\:\:\star\longrightarrow \sf \underline{P_2=\dfrac{P_1 \:T_2}{T_1}}[/tex]

Where-

P₁ is the initial pressure.T₁ is the initial temperatureP₂ is the final pressure.T₂ is the final temperature

As per question, we are given -

P₁ = 6.8 KPaT₁ =539 KT₂= 211K

Now that we are given all the required values, so we can put them into the formula and solve for P₂:-

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{P_1 \:T_2}{T_1}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{6.8\times 211}{539}\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf P_2 = \dfrac{1434.8}{539}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2 = 2.661966.........\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf\underline{ P_2 = 2.7 \:KPa}\\[/tex]

Therefore, If the temperature decreases to 211K, then the new pressure will become 2.7 KPa.

A certain first-order reaction ( A→products
) has a rate constant of 8.70×10−3 s−1
at 45 ∘C
. How many minutes does it take for the concentration of the reactant, [A]
, to drop to 6.25 %
of the original concentration?

Answers

Answer:

time = 1.92 min

Explanation:

By knowing that

[tex]R_R = K_R [A]^{1} = \frac{[A]}{time}[/tex]

Where: RR: rate of forward reaction, KR: rate constant, [A]: A concentration

in the previous equation, [A] is cancelled, then:

[tex]K_R = \frac{1}{time} \\ \\[/tex]

[tex]8.70\times10^{-3} = \frac{1}{time}[/tex]

Then, time = 114.94 seconds = 1.92 minutes

hope you find this easy to understand....

Have any questions? Write in the comments.

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What volume will 1.02 mol of carbon monoxide gas occupy at STP?

Answers

1.02 mol of carbon monoxide gas will occupy a volume of approximately 22.8 liters at STP.

At STP (standard temperature and pressure), the temperature is 273.15 K (0°C) and the pressure is 1 atmosphere (atm). The molar volume of a gas at STP is 22.4 L/mol.

Using the ideal gas law, we can calculate the volume of 1.02 mol of carbon monoxide gas at STP: PV = nRT

where:

P = pressure = 1 atm

V = volume (unknown)

n = moles = 1.02 mol

R = gas constant = 0.0821 L·atm/(mol·K)

T = temperature = 273.15 K

V = (nRT)/P

putting the values,

V = (1.02 mol)(0.0821 L·atm/(mol·K))(273.15 K) / (1 atm)

V = 22.4 L/mol

V = 22.8 L

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Label each change as gradual or rapid:
Hurricane = ________
Volcanic eruption = ________
Regrowth after volcanic eruption = ________
Flooding = ________
Seasonal changes = ________
Oceans increasing temperature = ________
Global warming = ________
Fire = ________

Answers

Hurricane = Rapid

Volcanic eruption = Rapid

Regrowth after volcanic eruption = Gradual

Flooding = Rapid

Seasonal changes = Gradual

Oceans increasing temperature = Gradual

Global warming = Gradual

Fire = Rapid

Answer:

rapid

gradual

rapid

gradual

rapid

Explanation:

Give the IUPAC name for: image attached

Answers

The IUPAC name of the given compound is 1-bromo-3-ethylpentane.

What are the steps involved in writing IUPAC name?

IUPAC (International Union of Pure and Applied Chemistry) naming is a system used to give standardized names to chemical compounds. The steps involved in doing IUPAC naming are as follows:

1. Identify the longest carbon chain: The parent chain is the longest continuous chain of carbon atoms in the molecule.

2. Number the carbon atoms: The carbon atoms in the parent chain are numbered starting from the end nearest to the substituent, and the substituents are given numbers based on the carbon to which they are attached.

3. Identify and name the substituents: Substituents are groups of atoms that replace hydrogen atoms on the parent chain. They are named according to their functional groups.

4. Write the name: The name of the compound is written by listing the names of the substituents in alphabetical order, along with their position on the parent chain.

5. Add prefixes and suffixes: Prefixes are added to indicate the number of substituents on the parent chain, and suffixes are added to indicate the functional group present.

6. Check the name: The final step is to check the name for accuracy and consistency with IUPAC rules.

It's important to note that the naming of complex organic compounds can involve additional rules and naming conventions beyond these basic steps.

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Consider the reaction. 2Pb(s)+O2(g)⟶2PbO(s) An excess of oxygen reacts with 451.4 g of lead, forming 338.4 g of lead(II) oxide. Calculate the percent yield of the reaction.

Answers

The reaction's per cent yield is 69.5%.

Calculation-

We must compare the actual yield of the reaction to the theoretical yield of the reaction to get the per cent yield of the reaction.

First, we need to calculate the amount of Pb reacted using the given mass of Pb:

mass of Pb = 451.4 g

The molar mass of Pb is 207.2 g/mol, so the number of moles of Pb reacted is:

moles of Pb = mass of Pb / molar mass of Pb

moles of Pb = 451.4 g / 207.2 g/mol

moles of Pb = 2.179 mol

The theoretical yield of PbO can be calculated using the molar mass of PbO:

mass of PbO = moles of PbO × molar mass of PbO

mass of PbO = 2.179 mol × 223.2 g/mol

mass of PbO = 486.6 g

Therefore, the theoretical yield of PbO is 486.6 g.

The per cent yield of the reaction is:

per cent yield = (actual yield / theoretical yield) × 100%

per cent yield = (338.4 g / 486.6 g) × 100%

percent yield = 69.5%

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How many moles of gas are in a 34.2 L container at 1 atm of pressure and 273.15 K?

Answers

Answer:

1.525834 (1.53 when accounting for significant figures).

Explanation:

This problem relies on the Ideal Gas Law, PV = nRT, where P is pressure, V is volume, n is moles, R is a specific constant, and T is temperature. In this problem, we are solving for n, moles, so we would rewrite it as n = PV/RT. Since the units here are moles, liters, atmospheres, and kelvin, R would be the value in atmosphere liter per mole kelvin, or 0.0821. From here, you just enter the values in the fraction and calculate.

For the significant figures, I followed the measurement of 34.2 L, giving 3, although an argument could be made for 1 significant figure from 1 atm, I imagine your professor would want something more specific than 2.

I need help with these questions. If you help me i will mark you as most brainiest :) Thank you, have a great day!

Answers

Al, Cu, and Zn, Al are the metals in equations 1 and 2, respectively. Since aluminium is ranked higher on the activity series than copper, it can substitute for copper in chemical reactions.

Which metal in the experiment using metals and water reacts violently and ignites?

Metal and Water Reaction: An Introduction Because of the intense interactions that certain metals have with water, such potassium and sodium, they will ignite if left outside.

Which metal reacts slowly when exposed to cold water yet swiftly when exposed to steam?

Magnesium is therefore the most reactive of the listed metals, and as a result, its pace of reaction will be the quickest (to react with steam). Magnesium does not react with cold water, whereas metals with strong reactivity like potassium (K), sodium (Na), and calcium (Ca) do.