what is the multiplicative inverse of 10 raise to the power 10​

Answer:

c

Step-by-step explanation:

It might be wrong but I think its right

Answer:

36

2^2 = 4

9^0 = 1

The midpoint of the line segment CD whose coordinates (-2,-4) and D (6,2) will be (2, -1).

Let AB be the line segment and C be the mid-point of line segment AB. Let the coordinate of point A (x₁, y₁), the coordinate of point B (x₂, y₂), and the coordinate of the mid-point (x, y).

Then the coordinate of the mid-point of the line segment is given as,

(x, y) = [(x₁ + x₂) / 2, (y₁ + y₂) / 2]

The endpoint of the segment CD is given as C(-2, -4) and D(6, 2). Then the mid-point of the line segment CD will be

(x, y) = [(-2 + 6) / 2, (-4 + 2) / 2]

(x, y) = (4/2, -2/2)

(x, y) = (2, -1)

The midpoint of the line segment CD whose coordinates (-2,-4) and D (6,2) will be (2, -1).

More about the Mid-point link is given below.

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Answer:

In a nutshell, [tex]\frac{3}{5}[/tex] is not equivalent to [tex]\frac{18}{32}[/tex].

Step-by-step explanation:

Now we proceed to demonstrate that Edgar's statement is false:

1) [tex]\frac{3}{5}[/tex] Given

2) [tex]\frac{3}{5} \times \frac{2}{2}[/tex] Modulative property/Existence of multiplicative inverse

3) [tex]\frac{6}{10}[/tex] [tex]\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot b}{c\cdot d}[/tex]

4) [tex]\frac{6}{10}\times \frac{3}{3}[/tex] Modulative property/Existence of multiplicative inverse

5) [tex]\frac{18}{30}[/tex] [tex]\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot b}{c\cdot d}[/tex]/Result

In a nutshell, [tex]\frac{3}{5}[/tex] is not equivalent to [tex]\frac{18}{32}[/tex].

Answer:

14 cars, 42 vans

Step-by-step explanation:

can divide the total by 4, since the number of cars is just 3x the number of vans

x+3x=56

4x=56

56/4

14 cars times 3 plus the original 14

There are 14 cars times 3 plus the original 14.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Given Between 7 and 8 o'clock, there were 56 vehicles in the zoo parking lot. There were 3 times as many vans as cars.

Then it can divide the total by 4, since the number of cars is just 3x the number of vans.

x+3x=56

4x=56

56/4

Therefore, there are 14 cars times 3 plus the original 14.

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Answer:

There are 8 inventors.

Step-by-step explanation:

Given that there are 3 more than twice as many salespeople as inventors.

Also given that the whole company has 27 employees.

i.e.

s + i = 27

substituting s = 3+2i

3 + 2i + i= 27

3 + 3i = 27

3i = 27 - 3

3i = 24

divide both sides by 3

i = 8

VERIFICATION

As the total number of employees is 27.

so the salespeople will be:

s = 3+2i

  = 3 + 2(8)

  = 3 + 16

  = 19

Thus, the total employees are verified as:

s + i = 27

19 + 8 = 27

27 = 27

Step-by-step explanation:

answer A should be correct

Answer:

The number of scooters that need to be produced so that the average cost per scooter is $180 is 430 scooters.

Step-by-step explanation:

Note: This question is not properly structured/written. The question is therefore rewritten properly before answering the question as follows:

To manufacture scooters, the manufacturer has a fixed cost of $34,400 plus a variable cost of $100 per scooter. Find n, the number of scooters, that need to be produced so that the average cost per scooter is $180.

The explanation of the answer is now provided as follows:

The number of scooters can be calculated as follows:

Variable cost per scooter = $100

n = number of scooter = ?

Total variable cost = Variable cost per scooter * n = $100 * n = $100n

Total cost = Fixed cost + Total variable cost = $34,400 + $100n

Average cost per scooter = Total cost / n = $180 ................ (1)

Substituting the value for Total cost into equation (1) and solve for n, we have:

($34,400 + $100n) / n = $180

$34,400 + $100n = $180n

$34,400 = $180n - $100n

$34,400 = $80n

n = $34,400 / $80

n = 430

Therefore, the number of scooters that need to be produced so that the average cost per scooter is $180 is 430 scooters.

Answer:

264 square meters

Step-by-step explanation:

Answer:

a. Correct

b. Incorrect

c. Correct

d. Incorrect

e. Incorrect

Step-by-step explanation:

b. Incorrect because negative hours do not make sense

d. 80 is achieved only with more than 3.89 hours of study, so 3.5 is not enough

e. No, the score is the dependent, it comes out of the formula.

The total number of handshakes was 234.

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Answer:

it's 8x

hope i could help :)

Answer:93

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer: [tex]\dfrac{b}{5}[/tex]

Step-by-step explanation:

Given: Let b = Total number of books.

Total shelves = 5

Number of books on each shelf = (Total number of books) ÷ (Total shelves)

= b  ÷ 5

[tex]=\dfrac{b}{5}[/tex]

The required expression for the number of books on each shelf = [tex]\dfrac{b}{5}[/tex]

Answer: 30-4=x  4+x=30 x=26

Step-by-step explanation: So he has 30 tickets and he gives 2 to each of his friends which means that lee has 26 friends with 4 tickets left over.

Answer:

It depends on the numbers

Step-by-step explanation:

Give some examples

image ????? please attach image and try again

Answer:

x = 280/17 = 16.471

Step-by-step explanation:

Answer:

[tex](f + g)(x) = 7 - 6x[/tex] --- (1)

[tex](f - g)(x) = 6x - 1[/tex] -- (2)

[tex](f . g)(x) =4(5^x)[/tex] ---- (3)

[tex](f / g)(x) = \frac{4}{5^x}[/tex] ----- (4)

[tex](f + g)(x) = -7x-7[/tex] --- (5)

[tex](f - g)(x) = 9x+ 9[/tex] --- (6)

[tex](f . g)(x) = (-8)(x+1)^2[/tex] --- (7)

[tex](f / g)(x) = -\frac{1}{8}[/tex] ----- (8)

[tex]F(t) = \frac{9}{5}t^2 + 32[/tex] ---- (9)

[tex]T(t) = (t - 2)^2 - 4[/tex] --- (10)

Step-by-step explanation:

Given

[tex]f(x) = 3[/tex]

[tex]g(x) = 4 - 6x[/tex]

Solving (1): (f + g)(x)

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = 3 + 4 - 6x[/tex]

[tex](f + g)(x) = 7 - 6x[/tex]

Solving (2): (f - g)(x)

[tex](f - g)(x) =f(x) - g(x)[/tex]

So, we have:

[tex](f - g)(x) =3 - (4 - 6x)[/tex]

[tex](f - g)(x) =3 - 4 + 6x[/tex]

[tex](f - g)(x) =-1 + 6x[/tex]

[tex](f - g)(x) = 6x - 1[/tex]

Given

[tex]f(x) = 4[/tex]

[tex]g(x) = 5^x[/tex]

Solving (3): (f . g)(x)

[tex](f . g)(x) =f(x) * g(x)[/tex]

So, we have:

[tex](f . g)(x) =4 * 5^x[/tex]

[tex](f . g)(x) =4(5^x)[/tex]

Solving (4): (f / g)(x)

[tex](f / g)(x) = \frac{f(x)}{g(x)}[/tex]

So, we have:

[tex](f / g)(x) = \frac{4}{5^x}[/tex]

Given

f(x) = x + 1

g(x) = -8 - 8x

Solving (5): (f + g)(x)

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = x + 1 -8-8x[/tex]

Collect Like Terms

[tex](f + g)(x) = x -8x+ 1 -8[/tex]

[tex](f + g)(x) = -7x-7[/tex]

Solving (6): (f - g)(x)

[tex](f - g)(x) = f(x) - g(x)[/tex]

So, we have:

[tex](f - g)(x) = x + 1 -( -8-8x)[/tex]

[tex](f - g)(x) = x + 1 +8+8x[/tex]

Collect Like Terms

[tex](f - g)(x) = x +8x+ 1 +8[/tex]

[tex](f - g)(x) = 9x+ 9[/tex]

Solving (7): (f . g)(x)

[tex](f . g)(x) = f(x) . g(x)[/tex]

So, we have:

[tex](f . g)(x) = (x+1) . (-8 - 8x)[/tex]

Factorize

[tex](f . g)(x) = (x+1) .(-8) (1 + x)[/tex]

Rewrite as:

[tex](f . g)(x) = (x+1) .(-8) (x+1)[/tex]

[tex](f . g)(x) = (-8)(x+1) (x+1)[/tex]

[tex](f . g)(x) = (-8)(x+1)^2[/tex]

Solving (8): (f / g)(x)

[tex](f / g)(x) = \frac{f(x)}{g(x)}[/tex]

So, we have:

[tex](f / g)(x) = \frac{(x+1)}{(-8-8x)}[/tex]

Factorize

[tex](f / g)(x) = \frac{(x+1)}{-8(1+x)}[/tex]

[tex](f / g)(x) = \frac{1}{-8}[/tex]

[tex](f / g)(x) = -\frac{1}{8}[/tex]

Solving (9):

From the question, we have that:

[tex]F(c) = \frac{9}{5}c + 32[/tex]

[tex]C(t) = t^2[/tex]

Required

Determine function F in terms of c

The implication of this question is to solve for [tex]F(c(t))[/tex]

If [tex]F(c) = \frac{9}{5}c + 32[/tex] and [tex]C(t) = t^2[/tex],

Then

[tex]F(c(t)) = \frac{9}{5}*t^2 + 32[/tex]

[tex]F(c(t)) = \frac{9}{5}t^2 + 32[/tex]

This can be rewritten as:

[tex]F(t) = \frac{9}{5}t^2 + 32[/tex]

Solving (10):

[tex]T(h) = h^2 - 4[/tex]

[tex]h(t) = t - 2[/tex]

Required

Find [tex]T(h(t))[/tex]

If [tex]T(h) = h^2 - 4[/tex]  and   [tex]h(t) = t - 2[/tex], then

[tex]T(h(t)) = (t - 2)^2 - 4[/tex]

This is gotten by substituting t -2 for h

The solution can be rewritten as:

[tex]T(t) = (t - 2)^2 - 4[/tex]

Answer:

[tex] \frac{ - 2}{3} [/tex]

Step-by-step explanation:

if it is right mark me brainliest

Answer: The final answer is 3390.

Step-by-step explanation:

Before answering the question, you have to understand that a linear growth pattern is a straight-line pattern (not exponential growth).

-From 1994 to 1996 are 2 [years]

-In 2 [years], there is a growth of 2734-2570 = 164 [students]

-With a linear growth, we can take the above [number of students] (164) divided by 2 [years] to get a [growth rate] of 82 [students per year]
⇒ [tex]\frac{164}{2} =82[/tex] [[tex]\frac{number of students}{years}[/tex] or number of students per year or growth rate]

-From 1996 to 2004, there are 8 [years]

-Therefore:

8 [years] × 82 [students per years] = 656 [students] => increased in students

-We add 656 [students] increased to 2734 [students] in 1996 = 3390 [students] in 2004

The final answer is 3390.

Hope this help. :D

Answer:

B. 135

Step-by-step explanation:

According to corresponding angles answer is b

135 is congruent to angle 1 and angle 1 is congruent to angle 5

so if angle 1 is 135 then angle 5 is 135

Brainliest please

Hope this helps

Answer:

d.

Step-by-step explanation:

straight angle = 180 degress

135+45=180

Answer:

Step-by-step explanation:

Step-by-step explanation:

15:30

Divide by 5

3:6

1:2

Answer:

3:4

Step-by-step explanation:

speed of cycle=15 km pers

speed of scooter=30 km per s

Now,

Ratio of speed= distance travelled ÷time taken

= (15+30)÷60 (1 hour=60 min)

= 45÷60

= 3÷4

= 3:4

:: The answer is 3:4.

Answer:

d

Step-by-step explanation:

the graph increases then goes horizontal

Answer:

D

Step-by-step explanation:

D is the choice you have to make. The culprit is the word quickly. You can't tell if the speed is increasing quickly or not.

The correct part of d is that the bicycle stays at a constant rate until  the end of the timing of the graph.

Answer:

$2271.54

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Compounded Interest Formula: [tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

Step-by-step explanation:

Step 1: Define

P = 800.00

r = 0.11

n = 1

t = 10

Step 2: Find A

Two triangles are congruent if two pairs of corresponding angles and included sides are congruent.

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

In order to prove △ABC ≅ △DBC by SAS. Then the additional information must be given will be

SAS: Two triangles are congruent if two pairs of corresponding sides and included angles are congruent.

More about the triangle link is given below.

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Answer:

8.5

Step-by-step explanation:

X^2 = 9^2 - 3^2

x^2 = 81 - 9

x^2 = 72

x = √72

x = 8.485