what is the mass percent of carbon in decane c {10}h {22}? use two decimal places in atomic masses. only give the numeric value of your answer.

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Answer 1

The mass percent of carbon in decane, C{10}H{22}, is 12.11%.

This can be determined by using the atomic mass of each element. Carbon has an atomic mass of 12.01 and Hydrogen has an atomic mass of 1.008.

When calculating the mass percent, you must first determine the total molar mass of the compound.

The total molar mass of decane is calculated by multiplying the atomic mass of each element by the number of atoms of that element in the molecule.

For example, the total molar mass of decane is calculated by multiplying 12.01 (atomic mass of carbon) by 10 (the number of carbon atoms) and 1.008 (atomic mass of hydrogen) by 22 (the number of hydrogen atoms).

This yields a total molar mass of 142.256.

The mass percent of carbon can be determined by dividing the total molar mass of carbon by the total molar mass of decane and then multiplying by 100.

This is calculated by dividing 12.01 (atomic mass of carbon) by 142.256 (total molar mass of decane) and then multiplying by 100, which yields a mass percent of 12.11%.

The mass percent of carbon in decane, C{10}H{22}, is 12.11%.

This was determined by calculating the total molar mass of decane, which is 142.256, and then dividing the total molar mass of carbon by the total molar mass of decane and then multiplying by 100.

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Related Questions

calculate the molarity of the two solutions. the first solution contains 0.500 mol of naoh in 2.30 l of solution.

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The molarity of the first solution containing 0.500 mol of NaOH in 2.30 l of the solution is 0.217 M.

The molarity of a solution is defined as the number of moles of solute per liter of solution. In order to calculate the molarity of the given solution, we need to divide the number of moles of solute by the volume of the solution given in liters. Using the formula for molarity, we have;

Molarity = Number of moles of solute / Volume of solution in liters

Given, Number of moles of solute = 0.500 mol

Volume of solution = 2.30 L

Substitute the values of the given information into the molarity formula; Molarity = 0.500 mol / 2.30 L = 0.217 M

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What is the nature of the bond indicated?
A. Nonpolar Covalent
B. Polar Covalent
C. Ionic
D. Metallic

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The nature of the bond indicated in the diagram above would be the nonpolar covalent bond. That is option A.

What is a Nonpolar Covalent bond?

A Nonpolar Covalent bond is defined as the type of chemical bond that is formed when electrons are shared equally between two atoms.

While polar covalent bond is defined as the type of chemical bond that is formed when electrons are shared unequally between two atoms.

For example, molecular oxygen (O2) is nonpolar because the electrons will be equally distributed between the two oxygen atoms.

Therefore the type of bond that is indicated in the diagram above is a nonpolar covalent bond.

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49.2 ml of a 0.524 m solution of hno3 is titrated with fe(oh)3. it takes 85 ml of fe(oh)3 to reach the equivalence point. what is the concentration (molarity) of the fe(oh)3? answer to 2 decimal places

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The Fe(OH)₃ solution has a content of 0.304 M.

In this titration, HNO₃ is the acid and Fe(OH)₃ is the base. At the equivalence point, all the H+ ions from the HNO₃ react with all the OH- ions from the Fe(OH)₃ to form water and the salt, Fe(NO₃)₃. We can use the balanced chemical equation for the reaction to determine the stoichiometric ratio of HNO₃ to Fe(OH)₃ and calculate the molarity of Fe(OH)₃.

The balanced chemical equation for the reaction is:

HNO₃ + 3Fe(OH)₃ → Fe(NO₃)₃ + 3H₂O

From the equation, we see that 1 mole of HNO₃ reacts with 3 moles of Fe(OH)₃. Therefore, the number of moles of HNO₃ in the solution can be calculated as:

moles of HNO₃ = Molarity of HNO₃ x Volume of HNO₃ solution in liters

moles of HNO₃ = 0.524 M x (49.2 mL / 1000 mL/L)

moles of HNO₃ = 0.0258 mol

At the equivalence point, the number of moles of Fe(OH)₃ added is equal to the number of moles of HNO₃ in the solution. Therefore, we can calculate the molarity of Fe(OH)₃ as:

Molarity of Fe(OH)₃ = moles of Fe(OH)₃ added / Volume of Fe(OH)₃ solution in liters

Since the volume of the Fe(OH)₃ solution added is 85 mL, or 0.085 L, we can calculate the moles of Fe(OH)₃ as:

moles of Fe(OH)₃ = moles of HNO₃ = 0.0258 mol

Therefore, the molarity of Fe(OH)₃ is

Molarity of Fe(OH)₃ = 0.0258 mol / 0.085 L

Molarity of Fe(OH)₃ = 0.304 M

Thus, the concentration (molarity) of the Fe(OH)₃ solution is 0.304 M, rounded to two decimal places.

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how many moles of N2 gas are produced by the decomposition of 9.1 mol of NaN3

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2 Sodium azide(s) 2 Sodium(s) + 3 Nitrogen(g) is the balanced chemical equation for the breakdown of sodium azide (Sodium azide). As a result, 13.65 moles of Nitrogen gas will be created from 9.1 mol of Sodium azide.

How does Avogadro's law contain Nitrogen?

According to Avogadro's law, a gas's total number of atoms or molecules is directly proportional to the volume of gas that gas occupies at a given pressure and temperature. The formula for Avogardro's equation is V = k n or V1/n1 = V2/n2.

We can use the following ratio to determine how many moles of Nitrogen gas are created by the breakdown of 9.1 mol of Sodium azide:

2 mol Sodium azide / 3 mol Nitrogen = 9.1 mol Sodium azide/ x mol Nitrogen

where x represents the quantity of Nitrogen generated in moles.

After finding x, we obtain:

x = 9.1 mol Sodium azide × 3 mol Nitrogen / 2 mol Sodium azide

x = 13.65 mol Nitrogen

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In order for a six-membered ring to undergo an E2 reaction, the substituents that are to be eliminated axial must both be in ___ positions When bromine and an adjacent hydrogen are both in axial positions, the large tent-butyl substituent is in an ____ position in the trans isomer. Because a large substituent is more stable in an ___ position than in an ____ position, elimination of the ___ isomer occurs through its more stable chair conformer, whereas elimination of the ___ isomer has to occur through its less stable chair conformer. The ____ isomer, therefore, reacts more rapidly in an E2 reaction
equatorial cis axial
trans

Answers

In order for a six-membered ring to undergo an E2 reaction, the substituents that are to be eliminated axially must both be in equatorial positions.

This is because when bromine and an adjacent hydrogen are both in axial positions, the large tent-butyl substituent is in a cis position in the trans isomer.

Because a large substituent is more stable in a cis position than in an axial position, elimination of the trans isomer occurs through its more stable chair conformer, while elimination of the cis isomer has to occur through its less stable chair conformer. The cis isomer, therefore, reacts more rapidly in an E2 reaction.

because the more stable conformer has to be destabilized in order for the reaction to proceed. As a result, the reaction rate is much higher for the trans isomer than for the cis isomer.

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What do these two changes have in common?
boiling sugar to make caramel
using a large magnet to remove pieces of iron from a junkyard

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Boiling sugar to make caramel and using a large magnet to remove pieces of iron from a junkyard are two very different processes, but they have one thing in common: they both involve a physical change.

A physical change is a change in a substance that does not result in the formation of a new substance with different chemical properties. In other words, the substance does not undergo a chemical reaction, but rather a change in its physical properties.

Boiling sugar to make caramel is a physical change because the sugar undergoes a change in its physical properties, such as color, texture, and taste, without undergoing a chemical reaction. The sugar molecules are heated to the point where they break down and re-form into a new substance with new properties, but the chemical composition of the sugar remains the same.

Using a large magnet to remove pieces of iron from a junkyard is also a physical change because the magnet is not altering the chemical properties of the iron, but only its physical location. The magnet is attracting and removing the iron from the junkyard, but the iron itself is not undergoing a chemical reaction.

In both cases, the substances are undergoing a physical change, but their chemical properties remain unchanged.

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a sample of 500 oxygen atoms contains a mixture of 20o (20.0040754 amu) and 23o (23.01570 amu). the weighted average of oxygen atoms 22.76272353 amu. how many 20o atoms are present in this sample?

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The number of 20o atoms present in the given sample of 500 oxygen atoms is 301.

The weighted average is a measure of central tendency that takes into account the varying weights (or importance) of the different values in a data set. A weighted average is calculated by multiplying each value by its weight and dividing it by the sum of the weights. It is also referred to as a weighted mean or weighted arithmetic mean. The formula for the weighted average is,

weighted average = (w1x1 + w2x2 + w3x3 + … wn xn) / (w1 + w2 + w3 + … wn)

Where,x1, x2, x3, … xn are the values of the individual observations w1, w2, w3, … wn are the respective weights of the individual observations to solve the given problem. A sample of 500 oxygen atoms contains a mixture of 20o (20.0040754 amu) and 23o (23.01570 amu). The weighted average of oxygen atoms is 22.76272353 amu. We have to find how many 20o atoms are present in this sample.

Here,20o atoms have a mass of 20.0040754 amu23o atoms have a mass of 23.01570 amu

The average mass of 500 oxygen atoms is 22.76272353 amu. Therefore,

500 oxygen atoms weigh= 500 x 22.76272353 = 11381.36176 amu.

average atomic mass of oxygen = 20o atoms (20.0040754 amu) and 23o atoms (23.01570 amu)

Atomic mass of oxygen = [(number of 20o atoms x mass of 20o atoms) + (number of 23o atoms x mass of 23o atoms)] / Total number of oxygen atoms

Let's consider a number of 20o atoms to be ‘x’.Therefore, the number of 23o atoms = (500 - x). Substituting the given values in the above formula, we get,

22.76272353 = [(x x 20.0040754) + ((500 - x) x 23.01570)] / 50022.76272353 = (20.0040754x + 11507.825 - 23.01570x) / 50022.76272353 x 500 = 11507.825 - 3.0116246xx = 301.05 ≈ 301Number of 20o atoms = 301.

Hence, 301 number of 20o atoms are present in this sample.

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A mixture of oxygen carbon dioxide and nitrogen has a total pressure of 0. 97-atm what is the partial pressure of 02 if the pco2 is 0. 70-atm and the pn2 is 0. 12-atm

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The partial pressure of O2 is 0.15 atm if the pco2 is 0. 70-atm and the pn2 is 0

we have a mixture of three gases: oxygen (O2), carbon dioxide (CO2), and nitrogen (N2).

We are given the total pressure of the mixture, which is 0.97 atm, as well as the partial pressures of CO2 and N2, which are 0.70 atm and 0.12 atm, respectively.

To find the partial pressure of O2, we need to subtract the partial pressures of CO2 and N2 from the total pressure.

Partial pressure of O2 = Total pressure - Partial pressure of CO2 - Partial pressure of N2

Partial pressure of O2 = 0.97 atm - 0.70 atm - 0.12 atm

Partial pressure of O2 = 0.15 atm

Therefore, the partial pressure of O2 is 0.15 atm.

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if a 9.48g of hydrosulfuric acid is reacte with 6.35g of silver nitrate calculate the mass in g of solid silver sulifde formed

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Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

When 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate, the reaction forms solid silver sulfide. The equation for this reaction is:

H₂S + 2 AgNO₃ → Ag₂S + 2 HNO₃.

To calculate the mass of silver sulfide formed, we need to use the mole ratio of the two reactants. We know that the molecular weight of silver nitrate is 169.88 g/mol and the molecular weight of hydrosulfuric acid is 34.08 g/mol.

Using the mole ratio, we can find the moles of each reactant:

9.48 g/34.08 g/mol = 0.2786 moles of H₂S and 6.35 g/169.88 g/mol = 0.0373 moles of AgNO₃.

Since the reaction forms 1 mole of Ag₂S for every 2 moles of AgNO3, we can calculate the moles of Ag₂S formed: (0.0373 moles of AgNO₃ x 1 mole of Ag₂S)/2 moles of AgNO₃ = 0.01865 moles of AgS.

Now, using the molecular weight of silver sulfide (119.97 g/mol), we can calculate the mass of silver sulfide formed: 0.01865 moles of Ag₂S x 119.97 g/mol = 2.238 g of Ag₂S.

Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

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some advantages of using photoredox dyes compared to transition metal catalysts include (select all that apply):

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Some advantages of using photoredox dyes compared to transition metal catalysts include increased selectivity, cost-effectiveness, broad substrate scope, and enhanced reaction efficiency.

Selectivity refers to the ability to promote a single desired reaction and minimize unwanted side reactions. Photoredox dyes tend to have higher selectivity than transition metal catalysts, meaning they are more effective at promoting the desired reaction while reducing the formation of byproducts.

Cost-effectiveness is an important factor when it comes to chemical reactions. Photoredox dyes tend to be cheaper than transition metal catalysts, making them more appealing for those on a budget.

The broad substrate scope of photoredox dyes allows for the reaction of a wide variety of compounds, whereas transition metal catalysts are usually limited to certain types of substrates.

Finally, photoredox dyes often have enhanced reaction efficiency compared to transition metal catalysts. This means they can carry out the same reaction faster and with a higher yield.

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What is the mass of 0.928 moles of Ti(SO3)2

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1) You know the number of moles, you can easily work out the molar mass of Ti(SO3)2 (titanium sulfite), but you don't know the actual mass

2) By adding the mass of the atoms that make up titanium sulfite, you should get something like 207.9934 g/mol

3) To find the actual mass, you times the molar mass and the moles together

Final Answer = 193g

which is the best colored indicator to use in the titration of 0.1 m ch3cooh(aq) with naoh(aq)? why? look up ka values in the appendix. indicator pka bromocresol green 4.8 bromothymol blue 6.8 phenolphthalein 9.2 group of answer choices