What is the mass of an object, when the volume of it is 50.0 mL and the density is 1.5
g/mL?

Answer:

28.01

Explanation:

this is the molar mass

Answer: F

Explanation: I did that test yesterday lol

Both containers have the same number of molecules= 5.62 x 10²³

Given

22.4 L of hydrogen gas

22.4 L of oxygen gas

25°C and 1 atm.

Required

true statement

Solution

Conditions at T 25 ° C and P 1 atm are stated by RTP (Room Temperature and Pressure). Vm in this condition = 24 liters / mol

and from Avogadro's Law :

At the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

So two gas have the same molecules

1 mol = 6.02 x 10²³ molecules

24 L = 1 mol, so for 22.4 L :

[tex]\tt \dfrac{22.4~L}{24~L}\times 6.02\times 10^{23}~molecules=5.62\times 10^{23}~molecules[/tex]

Lightbulb 1 has the lowest  percentage of energy lost as waste : 25%

Given

The input, output, and waste energy of Lightbulb

Required

The lowest  percentage of energy lost as waste.

Solution

Lightbulb 1 :

[tex]\tt \%energy~lost=\dfrac{50}{200}\times 100\%=25\%[/tex]

Lightbulb 2 :

[tex]\tt \%energy~lost=\dfrac{30}{100}\times 100\%=30\%[/tex]

Lightbulb 3:

[tex]\tt \%energy~lost=\dfrac{100}{150}\times 100\%=66.7\%[/tex]

Answer: lightbulb 1: 200 joules in, 50 joules wasted, 150 joules out

Explanation:

half-reactions

cathode(reduction) : Ni2+(aq) + 2e → Ni(s)

anode(oxidation) : Mg (s) → Mg²⁺ (aq) + 2e−

Given

Ni and Mg reaction

Required

the half-reactions

Solution

we determine which is the more reduced / oxidized of the two elements by looking at the voltaic series or the standard potential value

In voltaic series  

Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

If we look at the Mg metal located to the left of the Ni metal, so the Mg metal is more easily oxidized and can reduce the Ni metal which is on the right

Mg oxidation

Mg(s) – Mg2+(aq) + 2e

Ni reduction

Ni2+(aq) + 2e → Ni(s)

Answer:0.9375, the second question is 1, the third question is 400, and the last is  3

Explanation: I just did the worksheet in my Chem class, and it was quite easy I didn't feel like going to all your questions and answering them so there ya go!

Protons

Explanation: the atomic number is the same as the number of protons

Answer:

the speed of the wave is 96.6

Explanation:

to find do frequency x wavelength

Answer:

Atoms of both isotopes of carbon contain 6 protons. Atoms of carbon-12 have 6 neutrons, while atoms of carbon-14 contain 8 neutrons. A neutral atom would have the same number of protons and electrons, so a neutral atom of carbon-12 or carbon-14 would have 6 electrons.

Explanation:

Answer:

17g

Explanation:

Using the relation :

Volume = mass / molar mass

Volume of ammonia = 22.4 litres

Mole of gas at stp :

1 M of NH3 = 22.4 litres

Chemical formula for ammonia = NH3

The molar mass :

NH3 =14 + (1*3) = 14 + 3 = 17

Volume of ammonia = 1 M

Mass = volume * molar mass

Mass = 1 * 17

Mass = 17g

Answer:

Solvent

Explanation:

When one substance dissolves into another, a solution is formed. A solution is a homogeneous mixture consisting of a solute dissolved into a solvent

Answer:

Other forms of energy can convert to mechanical energy

Explanation:

For example the electric or magnetic energy in a motor can convert to mechanical energy, or another example is when you put two magnets together they will clip together due to the magnetic energy that they have.

Answer:

Explanation:

Mass number = No of neutrons + no of protons

Let no of protons be p , No of neutrons = p + 12

Putting the given values

88 = p + 12 + p

76 = 2p

p = 38

n = 50

a ) Atom is Strontium ( Sr )

Electronic configuration

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²

b ) Sr²⁺

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶

Answer:

B) rate of growth I'd say

Explanation:

it sounds better I don't think anyone would use height of plants if they want to sound professional

Answer:

D. beaker on edge

Explanation:

Answer: Silver Fluoride + Ferric Carbonate = Ferric Fluoride + Silver Carbonate

Reaction Type

Double Displacement (Metathesis)

Reactants

Silver Fluoride - AgF

Argentous Fluoride Silver(I) Fluoride

Molar Mass of AgF Bond Polarity of AgF Oxidation State of AgF

Ferric Carbonate - Fe2(CO3)3

Molar Mass of C3Fe2O9 Oxidation State of C3Fe2O9

Products

Ferric Fluoride - FeF3

Molar Mass of F3Fe Oxidation State of F3Fe

Silver Carbonate - Ag2CO3

Silver(I) Carbonate

Molar Mass of CAg2O3 Oxidation State of CAg2O3

Explanation: did u understand that? if not pls contact me in the contacts ty

a. 7 protons, 7 electrons, 10 neutrons

b. 19 protons, 19 electrons, 26 neutrons

c. 53 protons, 53 electrons, 84 neutrons

Given

Atom and mass number

Required

The number of each subatomic particle

Solution

a. Nitrogen atom(atomic number = 7)

mass number = 17 amu

atomic number=number of protons=number of electrons(in neutral atom)

so number of protons=number of electrons = 7

mass number = protons+neutron

17 = 7 + neutrons

number of neutrons = 17-7=10

b. Potassium atom (atomic number = 19)

mass number = 45 amu

atomic number=number of protons=number of electrons(in neutral atom)

so number of protons=number of electrons = 19

mass number = protons+neutron

45 = 19 + neutrons

number of neutrons = 45-19=26

c. Iodine atom ((atomic number = 53)

mass number = 137 amu

atomic number=number of protons=number of electrons(in neutral atom)

so number of protons=number of electrons = 53

mass number = protons+neutron

137 = 53 + neutrons

number of neutrons = 137-53=84

C. Decreasing the temperature

D. Raising the pressure​

Given

Reaction

2SO₂+O₂⇔2SO₃+energy

Required

Changes to  the formation of products

Solution

The formation of SO₃ is an exothermic reaction (releases heat)

If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)  

While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient  

in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2

As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)

And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater

Answer:

C. Decreasing the temperature

D. Raising the pressure​

Explanation:

A.P.E.X

Answer: C. A redox reaction at two electrodes causes electrons to flow

Explanation:

A galvanic cell work like a a redox reaction at two electrodes causes electrons to flow.

Redox reactions include a modification inside the oxidation state of the substrate. Losing of electrons or a rise in an element's oxidation state are both considered to be oxidation. Gaining electrons or lowering an object's or its atoms' oxidation state are both considered reductions.

An electrochemical cell wherein an electric current being produced spontaneously is called a galvanic cell as well as voltaic cell, respectively called just after scientists Luigi Galvani as well as Alessandro Volta. reduction-oxidation processes

In order to create a conduit for the passage of electrons through into the wire, each half-reaction in a galvanic cell is connected to the other by a wire, which allows the movement of electrons to be separated in the oxidation and reduction processes.

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Answer: wut the are you asking for like an essay

Explanation:

Answer:

CuO is a basic oxide and when it reacts with water it gives Cu(OH)2 which is a base as it gives Cu2+ and OH− ions when dissolved in water.

The relative molecular mass of acid A : 50 g/mol

Given

40.0 cm³(40 ml) of 0.2M sodium hydroxide

0.2g  of a dibasic acid

Required

the relative molecular mass of acid A

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence(number of H⁺/OH⁻)

NaOH ⇒ n = 1

Dibasic acid =  diprotic acid (such as H₂SO₄)⇒ n = 2

mol = M x V

Input the value in the formula :(1 = NaOH, 2=dibasic acid)

0.2 x 40 x 1 = M₂ x V₂ x 2

M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A

The relative molecular mass of acid A (M) :

[tex]\tt M_A=\dfrac{mass }{mol}=\dfrac{0.2~g}{4.10^{-3}}=50~g/mol[/tex]

Answer:

6.17 L

Explanation:

The outgoing voltage : 72 V

Given

Vp=primary=120 V

Np=10

Ns=6

Required

the secondary voltage

Solution

[tex]\tt \dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}[/tex]

Input the value :

[tex]\tt \dfrac{120}{V_s}=\dfrac{10}{6}\\\\V_s=\dfrac{120\times 6}{10}=72~V[/tex]

Answer:

The correct answer is 1.66 atm ≅ 1.7 atm

Explanation:

Given:

T₁ = -13°C + 273 = 260 K (initial temperature)

T₂ = 15°C + 273 = 288 K (final temperature)

P₁ = 1.5 atm

P₂= ?

We use the mathematical expression of Gay Lussac's Law to calculate P₂, as follows:

P₁/T₁ = P₂/T₂

P₂= P₁/T₁ x T₂ = (1.5 atm)/(260 K) x 288 K = 1.66 atm ≅ 1.7 atm

Since the law says that the temperature of a gas is directly proportional to the pressure, when the temperature is increased, the pressure increases.

The standard cell notation of a galvanic cell made with aluminum and magnesium is option A. Al3+(aq) | Al(s) || Mg(s) | Mg2(aq).

The right side is the cathode and the left side is the anode. The cell is represented by the convention that the metal is written first, then the metal ions present in the electrolyte. And these two should be separated by a vertical line. Zinc becomes the cathode of the galvanic cell.

Galvanic cells consist of two different metal electrodes connected by a conductive solution electrolyte, which are also connected externally to complete an electrical circuit. Cell notation or cell representation in chemistry is a simple way of representing reactions in an electrochemical cell. The silver half-cell is reduced due to its high standard reduction potential. Tin half-cells are oxidized.

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Answer: C

Explaination: