What is the mass of a 8.45 m3 piece of copper?

Answers

Answer 1

The mass of a 8.45 m3 piece of copper is 7537.4 grams.

What is mass?

Mass is described as a dimensionless quantity representing the amount of matter in a particle or object.

density of copper =8.92g/cm^3

volume = 8.45 x 100 cm^3

mass =  (8.45 x 100) x 8.92

mass = 7537.4 grams.

The relationship between mass, density and volume is that density offers a convenient means of obtaining the mass of a body from its volume or vice versa.

This means that the mass is equal to the volume multiplied by the density (M = Vd), while the volume is equal to the mass divided by the density (V = M/d).

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Related Questions

Last year Steve was shorter than his brother. This year Steve is taller than his brother. What cell process is directly responsible for Steve’s growth?
1 diffusion
2 mitosis
3. Osmosis
4 respiration

Answers

Answer:

he drank milk!!!

Explanation:

1. he told his dad to go get the milk

2. Steve's dad didn't come back until a year!

3. Steve's dad came back and gave him milk!

4. and boom, he grew!!

:)

All living organisms are capable of growing and producing offspring. All eukaryotic organisms including aquatic plants and algae grow through mitosis. Thus the correct option is 2.

What is mitosis?

The mitosis is defined as the step in the cell cycle where the newly formed DNA is separated and results in the formation of two new cells which have the same number and kind of chromosomes as the parent nucleus.

It is defined as a process of asexual reproduction observed in unicellular organisms. The cell division is regarded as the driving process of reproduction at the cellular level. Mitosis is required for the growth of the cells and for the replacement of worn-out cells.

Mitosis helps organisms to grow in size and repair damaged tissue. The process of mitosis generates new cells which are genetically identical to each other.

Thus the correct option is 2.

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Calculate the hydrogen ion concentration in a 3.4 x 10-3 M
solution of KOH.

Answers

Explanation:

[tex]KOH→K {}^{ + } + OH {}^{ - } \\ [OH {}^{ - } ] = 3.4 \times {10}^{ - 3} \\ k _{w} = [OH {}^{ - } ] [H {}^{ + } ] \\ 1 \times {10}^{ - 14} = 3.4 \times {10}^{ - 3} \times [H {}^{ + } ] \\ [H {}^{ + } ] = 2.94 \times {10}^{ - 12} \: M[/tex]

Answer:

2.9 X 10^-12 M

Explanation:

Question (1 point)
Given the model, answer the following questions regarding effusion. The orange spheres have a greater root-mean-square speed than the blue spheres. Assume the balloon has a tiny opening for gas molecules to escape.
1st attempt
Part 1 ( 0.5 point)
See Periodic Table See Hint
Which balloon, A or B, most accurately illustrates the effusion of a gas from the central balloon?
Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 495.0m/s. The root-meah-5quare speed for the blue spheres is 380.0m/ s.

Answers

According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.

What is effusion ?

The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.

Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.

Rate of effusion of Orange / Rate of effusion of blue

= [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue

= 565/ 369

= 1.531

Thus,  Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.

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In carbonated water, when carbon dioxide bubbles are
thoroughly mixed into the water, they become invisible. What
type of mixture is carbonated water?
a solution
b compound
C colloid
d suspension

Answers

Answer: IT’S SOLUTION!!

Explanation:

I’m taking ck-12

The carbonated water is a type of solution. The correct option is a.

What is a solution?

A solution is a uniform mixture of one or more dissolved solutes in a solvent.

A solvent is a substance that dissolves a solute to produce a homogeneous mixture. The substance that dissolves in a solvent to form a homogeneous mixture is referred to as a solute.

Because carbonated water is a mixture, it contains two or more different chemicals. Carbonated water is made up of both water and carbon dioxide.

The amount of each ingredient in carbonated beverages is fixed. All of the components, such as sweetener, water, and carbon dioxide bubbles, are distributed evenly. Homogenous mixtures are those in which the amount of each component is uniform.

Thus, as in carbonated water, when carbon dioxide bubbles are thoroughly mixed into the water, they become invisible, it can be considered as solution, means option a is correct.

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Lewis Structure Practice (No Links Or I will Report)

Answers

Answer:

.. ..

:O = C - Cl:

.. | ..

:Cl:

..

The picture shows a plant that lives in Florida.
This plant lives in other parts of the United States, too. It has a longer growing season in Florida than it does in northern areas of the country,
Which sentence best describes how Florida's warmer weather and longer growing season will affect this plant?
A. It will lose its leaves much sooner than northern plants.
B. It will produce fewer flowers than northern plants.
C. It will not be able to migrate like northern plants.
D. It will have a much shorter dormant period than northern plants.
Revisar progreso
Pregunta 2
de 15
Anterior
Siguiente →

Answers

Answer:

I think its D. Sorry if I'm wrong

Explanation:

What is the molecular weight of H2O

Answers

Answer:

18.015

Explanation:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

name one solid that can be used in place of candle wax while will give the same result​

Answers

Answer:

Paraffin Wax

Explanation:

Paraffin wax is one of the most widely used waxes for candle making. A cheaper alternative, it is a derivable from petroleum, coal or oil. This wax is white and odorless and will keep a consistent appearance throughout your candle's life.

Please solve this fast pleasee i will make u the brainliest
I – FILL IN THE BLANKS:-
1. _____________plastics can be melted by heating and thereafter moulded into desired
shape.
2. Melamine and Bakelite are examples of____________________________.
3. _________________ absorbs sweat.
4. ______________are used for making toothbrush bristles.
5. _____________type of plastic is used for making grocery bags.
6. _____________type of plastic is used for making microwave cooking containers.
7. __________ fibres are obtained from plant and animals.
8. Synthetic fibres are acquired from __________ products.
9. Polythene is the polymer of __________.
10. __________ was the first artificially manufactured fibre.
11. Polyesters are extremely __________ and __________.
12. __________ is used as an alternative for expensive, warm cashmere clothes.
13. The polymer cellulose is made up of a large number of __________ units.
14. Silk fibre is obtained from __________ whereas artificial silk is obtained by chemical
treatment of __________
15. Polythene which is used to make polythene bags is an example of a __________.
16. Plastics do not react with _______________ and ____________________.
17. Plastics are generally ______________-____ than metals.
18. __________ is a special plastic on which oil and water do not stick.
19. We should always remember the 5R principle: __________, __________, __________,

Answers

1. Thermoplastics
2. Thermosetting plastics
4. Nylon
5. Thermoplastics like polythene
6. Thermosetting plastics like melamine
7. Natural
8. Raw
11. Light and durable
13. repeating subunits
14. Naturally from silkworms
15. Thermoplastics
16. Air and water
17. Less-reactive
18. Poly-tetra-fluoroethylene ptfe




What is a molecule of compound made up of?
A one type of atoms
B two or more of the same type of atoms
C two or more of different types of atoms
D two or more of the same type or different types of atoms​

Answers

[tex]\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}[/tex]

D. Two or more of the same type or different types of atoms.

ThanksHope it helps.
D. two or more of the same type or different types of atoms

A student placed four magnets of equal size and mass each the same distance from an electromagnet. She turned the electromagnet on and then quickly turned it off. The diagram below shows how far each magnet traveled toward the electromagnet when the circuit was closed.

four magnets near an electromagnet
What is the order of the magnets by strength from strongest to weakest?

magnet W
magnet X
magnet Y
magnet Z
You have to put them in order

Answers

Four magnets near an electromagnet What is the order of the magnets by strength from strongest to weakest. magnet W,magnet X,electromagnet,magnet Y,magnet Z.

What is electromagnet?

An electromagnet is a type of magnet in which the magnetic field is generated by an electric current. It usually consists of a coil of wire that is wrapped around a core of magnetic material such as iron or steel.

When an electric current passes through the wire, a magnetic field is created around the core, making it a magnet. Electromagnets are used in many different applications, such as motors, generators, and speakers.

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The number of gas molecules in a container is doubled. How will the pressure in the container change if the temperature and volume of the container do not change?

Answers

Answer:

when De molecules are wide open

Explanation:

due to the molecules gas contains

A scientist did a test to compare two substances: substance Q and substance R. At room temperature, both substances are liquid. When the scientist transferred the same amount of energy out of both substances, only one substance changed phase while the other did not. Which substance changed phase, and how did it change?
Responses

a
Substance Q changed phase because the attraction of the molecules was able to overcome their slower movement. Its molecules now move in place.
Substance Q changed phase because the attraction of the molecules was able to overcome their slower movement. Its molecules now move in place.

b
Substance Q changed phase because the strong attraction between molecules made their movement slower. Its molecules now move in place.
Substance Q changed phase because the strong attraction between molecules made their movement slower. Its molecules now move in place.

c
Substance R changed phase because the weak attraction between molecules let them move faster. Its molecules now move around each other.
Substance R changed phase because the weak attraction between molecules let them move faster. Its molecules now move around each other.

d
Substance R changed phase because the attraction was able to overcome the slower molecules. Its molecules now move away from each other.
Substance R changed phase because the attraction was able to overcome the slower molecules. Its molecules now move away from each other.

Answers

Substance R changed phase because the weak attraction between molecules let them move faster.  Option C

What is phase change?

We know that a change of phase has to do with the movement of a material from a given state of matter to the other. Net us note that when there is a change of state, we are going to notice that the force of attraction in the molecule would also change.

Since we know that the substance that we have are liquid at room temperature, we know that the supply of some energy may cause to be bale to change its phase.

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1. what are the methods of vegetative propagation
2.give examples of organisms exihibiting each type
3.tubers-definitio example potatoes

science subject

Answers

Natural vegetative propagation uses bulbils, aerial shoots, roots, underground stems, and subaerial stems. Utilizing unique vegetative components, artificial vegetative propagation is accomplished.

What is vegetative propagation, and how does it work?

The production and growth of a new plant through asexual means or from a plant fragment is known as vegetative propagation. There is no gamete production or fertilization throughout the process of propagation.

What are some instances of vegetative tuber propagation?

In this procedure, tubers—modified roots—grow into new plants. In some plant species, adventitious buds even grow on the roots. If the correct circumstances are present, these buds develop into new plants or sprouts. Sweet potato and dahlia are two examples.

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Propane is used as a fuel for camp stoves. It undergoes combustion to form carbon dioxide and water.
C3H8 +502 – 3 CO2 + 4H20
Determine the number of molecules of propane needed to produce 10.01 liters of carbon dioxide.
CORRECT ANSWER IS: 8.97 x 10^22 molecules C3H8, but what are the steps to get this answer?

Answers

Fuel camp equal width time inchess

Half equations for oxidation of HCL

Answers

Explanation:

The other half of the equation involves the hydrogen ions (initially bonded to the chloride ion in the hydrochloric acid). The hydrogen ions gain the electrons lost by the zinc atom, and bond together to form hydrogen gas. Since the hydrogen ions gain electrons, it is a reduction reaction.


PLEASE HELP ME ASAP
Which type of muscle is responsible for digestion?
A. smooth muscle
B. tendon muscle
C. skeletal muscle
D. cardiac muscle

Answers

Answer:

A

smooth muscle is responsible

smooth muscle lol hhdhdhdhdhhd

Charged Particles
Charge on Particle Number of Particles
Positive 3
Negative 2

A negatively charged substance is brought near the ion. What will most likely happen?


(A) The negatively charged ion will repel the substance.
(B) The negatively charged ion will attract the substance.
(C) The positively charged ion will repel the substance.
(D) The positively charged ion will attract the substance.

Answers

Answer:

D

Explanation:

cause overall charge is +1 so will attract

Which among the following is NOT TRUE regarding solutions?



A.
a solution is a homogeneous mixture of two or more components



B.
in a liquid solution the solution particles can be ions, atoms or molecules and never settle on standing



C.
the solution particle size is much smaller than colloidal particle.



D.
solution particles can be separated by filtration.



E.
air is a gaseous solution of gases, chiefly oxygen and nitrogen.

Answers

Answer:

The answer is D.

Explanation:

I know because I am currently doing this topic in Chemistry as well. I hope it was enough.

The mass of copper nitrate produced from reacting 3.65g of copper and 5.16g of nitric acid​

Answers

The mass of copper nitrate produced in the reaction 3.65g of copper and 5.16g of nitric acid​ is 3.84g.

What gas is produced when copper combines with nitric acid?

Nitric acid reacts with copper

4 HNO3(l) + Cu(s) ==> Cu(NO3)2(s and aq) + 2 NO2(g) + 2 H2O(l)

Deep blue colour characterises the copper nitrate salt that develops. Nitrogen dioxide is the gas that is created when strong nitric acid and copper interact. This maroon mist is nitrogen dioxide.

Copper :

=> mass copper nitrate

=> 3.65g Cu x 1mol of Cu/63.546 g Cu x 1 mol copper nitrate / 1 mol cu x 187.56 g/mol copper nitrate

=> 10.77g

HNO3 (Nitric acid):

=> Mass copper nitrate =3.65 g HNO3 X 1 mol HNO3/63.546 g HNO3 x 1mol of copper nitrate /4 mol HNO3 x 187.56 g/mol copper nitrate.

=> 3.84g.

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Please Help Weak Acid Base Problems!!!
1. Calculate the pH of a 0.100 M NH3 solution Kb = 1.8 x 10^-5
Calculate the pH of a 0.100 M NH3 solution Kb = 1.8 x 10^-5
Initial:
Change:
at Equilibrium:

2. Calculate the Kb from species concentrations
Calculate the Kb for methylamine, CH3NH2, if the pOH of a 0.0100 M CH3NH2 solution is 7.66
Initial:
Change:
at Equilibrium:

3. Calculation of species concentrations from Kb
Calculate the pH of a 0.100 M C5H5N Kb == 1.3 x 10^-3
Initial:
Change:
at Equilibrium:

Answers

Answer:

The procedure for calculating the pH of a solution of a weak base is similar to that of the weak acid in the sample problem. However, the variable x will represent the concentration of the hydroxide ion. The pH is found by taking the negative logarithm to get the pOH, followed by subtracting from 14 to get the pH.

Explanation:

A it is a______________________

Sediments from mountains many miles away are now in the area known as Florida. Which is the best explanation as to how most of these sediments moved so far away from where the mountains are now?

Answers

Answer:

The sediments were transported and deposited by streams and rivers.

Explanation:

:)

Carrying capacity is
A
anything that limits how many organisms can live in an ecosystem.
B
how green plants make carbohydrates.
С
the process of respiration.
D
the number of organisms an ecosystem can support.

Answers

Answer:

It's D the number of organisms an ecosystem can support.

Check if it's right first then if it is, happy to help

Answer:

D: The number of organisms an ecosystem can support

Explanation:

D is the correct answer.

Half equations for oxidation of HCL

Answers

2H + (aq) + Mg(s) → Mg 2+ (aq) + H 2 (g)

How can people REDUCE the amount of trash being put into landfills?
A recycle paper, glass, plastic and metal
B reuse shopping bags and food containers
compost biodegradable materials
D
all of the above

Answers

D All of the above

Each scenario is giving ways of helping the environment

7
QUICK CHECK
Predicting Spontaneity
Identify each of these reactions as being spontaneous or nonspontaneous.
2C₂H₂(g)+50₂(g) → 4CO₂(g)+2H₂O(g)
AG-2,453.1 kJ
3H₂(g)+N₂(g) → 2NH₂(g)
CO₂(g) +2H₂O(g) → CH₂(g) +20₂(g)
DONE
AG=-33.3 kJ
AG=800.7 kJ

Answers

1. The reaction: 2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g) ΔG = -2,453.1 KJ is spontaneous

2. The reaction: 3H₂(g) + N₂(g) → 2NH₂(g) ΔG = -33.3 KJ is spontaneous

3. The reaction: CO₂(g) + 2H₂O(g) → CH₂(g) + 2O₂(g) ΔG = 800.7 KJ is nonspontaneous

How do I determine which reaction is spontaneous or nonspontaneous?

The Gibbs free energy is a core factor in determining whether a reaction is spontaneous or nonspontaneous. Gibbs free energy is given by the following formula:

ΔG = ΔH – TΔS

Where

ΔG is the Gibbs free energy ΔH is the enthalpy changeT is the temperature ΔS is the change in entropy

NOTE

ΔG = Positive (non spontaneous) ΔG = Zero (equilibrium) ΔG = Negative (spontaneous)

With the above information, we can determine which of the reaction is spontaneous and also the one which is nonspontaneous as shown below:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g) ΔG = -2,453.1 KJ. The reaction is spontaneous since ΔG is negative3H₂(g) + N₂(g) → 2NH₂(g) ΔG = -33.3 KJ. The reaction is spontaneous since ΔG is negativeCO₂(g) + 2H₂O(g) → CH₂(g) + 2O₂(g) ΔG = 800.7 KJ. The reaction is nonspontaneous since ΔG is positive

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What is the balanced chemical equation for silicon + oxygen?

Answers

Answer:

SiO2

Explanation:

Si + O2 → SiO2

In an acid-base titration, a student uses 25.62 mL of 0.100 M HCl to reach the endpoint. How many moles of acid is this?
A)2.56 x 10-1 ml HCl
B)2.56 x 10-3 mol HCl
C)2.56 x 10-2 mol HCl

Answers

Answer:

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Explanation:

Given:

Volume of HCL = 25.62 ml

Molarity of HCL = 0.1 M

Find;

Number of mole in HCL

Computation:

Volume of HCL = 25.62 ml

Volume of HCL (in liter) = 25.62 / 1000

Volume of HCL (in liter) = 0.02562 L

Number of mole = Molarity x volume in liter

Number of mole in HCL = Volume of HCL (in liter) x Molarity of HCL

Number of mole in HCL = 0.02562 x 0.1

Number of mole in HCL = 0.002562

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Combustion of 1.125 of an unknown compound containing carbon, hydrogen, and oxygen resulted in 1.649g of CO2 and 0.675g of H2O. If the molar mass is 180g/mol What is the molecular formula?
CxHyOz + O2 → CO2 + H2O

Answers

The molecular formula of the unknown compound, given that it contains carbon, hydrogen, and oxygen is C₆H₁₂O₆

How do I determine the molecular formula?

First, we'll begin by obtaining the mass of carbon, hydrogen and oxygen. Details below:

For Carbon

Mass of CO₂ = 1.649 gMolar mass of CO₂ = 44 g/mol Molar of C = 12 g/mol Mass of C =?

Mass of C = (12 / 44) × 1.649

Mass of C = 0.45 g

For Hydrogen

Mass of H₂O = 0.675 gMolar mass of H₂O = 18 g/mol Molar of H = 2 × 1 = 2 g/mol Mass of H =?

Mass of H = (2 / 18) × 0.675

Mass of H = 0.075 g

For Oxygen

Mass of compound = 1.125 gMass of C = 0.45 gMass of H = 0.075 gMass of O =?

Mass of O = (mass of compound) - (mass of C + mass of H)

Mass of O = 1.125 - (0.45 + 0.075)

Mass of O = 0.6 g

Next, we shall determine the empirical formula. details below:

C = 0.45 gH = 0.075 gO = 0.6 gEmpirical formula =?

Divide by their molar mass

C = 0.45 / 12 = 0.0375

H = 0.075 / 1 = 0.075

O = 0.6 / 16 = 0.0375

Divide by the smallest

C = 0.0375 / 0.0375 = 1

H = 0.075 / 0.0375 = 2

O = 0.0375 / 0.0375 = 1

Thus, the empirical formula of the compound is CH₂O

Finally, we shall determine the molecular formula. Details below:

Molar mass of compound = 180 g/molEmpirical formula = CH₂OMolecular formula =?

Molecular formula = empirical × n = mass number

[CH₂O]n = 180

[12 + (2×1) + 16]n = 180

30n = 180

Divide both sides by 30

n = 180 / 30

n = 6

Molecular formula = [CH₂O]n

Molecular formula = [CH₂O]₆

Molecular formula = C₆H₁₂O₆

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The volume of a fixed amount of gas is doubled, and the absolute temperature is doubled. According to the ideal gas law, how has the pressure of the gas changed? A. It has stayed the same. B. It has decreased to one-half its original value. C. It has increased to four times its original value. D. It has increased to two times its original value.

Answers

Answer:

Option A. It has stayed the same.

Explanation:

To answer the question given above, we assumed:

Initial volume (V₁) = V

Initial temperature (T₁) = T

Initial pressure (P₁) = P

From the question given above, the following data were:

Final volume (V₂) = 2V

Final temperature (T₂) = 2T

Final pressure (P₂) =?

The final pressure of the gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

PV/T = P₂ × 2V / 2T

Cross multiply

P₂ × 2V × T = PV × 2T

Divide both side by 2V × T

P₂ = PV × 2T / 2V × T

P₂ = P

Thus, the final pressure is the same as the initial pressure.

Option A gives the correct answer to the question.

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