Answer:
Option A. 1.1×10¯²⁴ N
Explanation:
The following data were obtained from the question:
Charge 1 (q1) = - 4e
Charge 2 (q2) = + 3e
Distance apart (r) = 0.05 m
Electric field constant (K) = 9×10⁹ N•m²/C²
Electron (e) = 1.6×10¯¹⁹ C.
Electric Force (F) =..?
Next, we shall determine the value of the two charges.
This is illustrated below:
Charge 1 (q1) = - 4e
Charge 1 (- q1) = 4e
Electron (e) = 1.6×10¯¹⁹ C.
Charge 1 (- q1) = 4 × 1.6×10¯¹⁹ C.
Charge 1 (- q1) = 6.4×10¯¹⁹ C.
Charge 2 (q2) = + 3e
Electron (e) = 1.6×10¯¹⁹ C.
Charge 2 (q2) = 3 × 1.6×10¯¹⁹ C.
Charge 2 (q2) = 4.8×10¯¹⁹ C.
Finally, we shall determine the value of the electric force. This can be obtained as shown below:
Charge 1 (- q1) = 6.4×10¯¹⁹ C.
Charge 2 (q2) = 4.8×10¯¹⁹ C.
Electric field constant (K) = 9×10⁹ N•m²/C².
Distance apart (r) = 0.05 m
Electric Force (F) =..?
F = Kq1q2 /r²
F = (9×10⁹× 6.4×10¯¹⁹× 4.8×10¯¹⁹)/(0.05)²
F = 1.1×10¯²⁴ N
Therefore, the electric force between the two point charge is 1.1×10¯²⁴ N
Stopping distance of vehicles When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (v0) and the braking capacity, or deceleration that is caused by braking. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s2. Find the stopping distance of the car.
Answer:
Stopping distance = 40m
Explanation:
Given the following :
Initial speed of vehicle before applying brakes = 72km/hr
Converting km/hr to m/s:
72km/hr = [(72 * 1000)m] / (60 * 60)
72km/hr = 72,000m / 3600s
72km/hr = 20m/s
Deceleration after applying brakes (-a) (negative acceleration) = - 5m/s^2
From the 3rd equation of motion:
v^2 = u^2 + 2as
Where v = final Velocity ; u= Initial Velocity ; a = acceleration and s = distance
Final velocity when the car stops will be 0
Therefore ;
v^2 = u^2 + 2as
0 = 20^2 + 2(-5)(s)
0 = 400 - 10s
10s = 400
s = 400/10
s = 40m
Therefore, the stopping distance of the car = 40 meters
Calculate the gravitational acceleration of a satellite that is in orbit at a distance of 1.0 x 10^8 meters from the center of the Earth (Mass of Earth is 6.0 × 10^24).
Answer:
[tex]g=0.035\ m/s^2[/tex]
Explanation:
Given that,
Mass of Earth, [tex]m=6\times 10^{24}\ kg[/tex]
We need to find the gravitational acceleration of a satellite that is in orbit at a distance of [tex]10^8\ m[/tex] from the center of the Earth.
Radius of earth is 6,371 km
The formula used to find the gravitational acceleration at a distance is given by :
[tex]g=\dfrac{Gm}{R^2}[/tex]
R = r+d
[tex]g=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(10^8+6371\times 10^3)^2}\\\\g=0.035\ m/s^2[/tex]
So, the gravitational acceleration is [tex]0.035\ m/s^2[/tex].
A vat of nitrogen at its boiling point (-196 degrees C) absorbs 384000 J of heat. How much mass of nitrogen burns off? (Unit = kg)
Answer:
1.92 kg of nitrogen.
Explanation:
The following data were obtained from the question:
Heat absorbed (Q) = 384000 J
Note: Heat of vaporisation (ΔHv) of nitrogen = 5600 J/mol
Next, we shall determine the number of mole of nitrogen that absorbed 384000 J.
This is illustrated below:
Q = mol·ΔHv
384000 = mole of N2 x 5600
Divide both side by 5600
Mole of N2 = 384000/5600
Mole of N2 = 68.57 moles
Next, we shall convert 68.57 moles of nitrogen, N2 to grams.
This can be obtained as follow:
Molar mass of N2 = 2 x 14 = 28 g/mol.
Mole of N2 = 68.57 moles.
Mass of N2 =..?
Mole = mass /molar mass
68.57 = mass of N2 /28
Cross multiply
Mass of N2 = 68.57 x 28
Mass of N2 = 1919.96 g
Finally, we shall convert 1919.96 g to kilograms.
This can be achieved as shown below:
1000g = 1 kg
Therefore,
1919.96 g = 1919.96/1000 = 1.92 kg.
Therefore, 1.92 kg of nitrogen were burned off.
Answer:
Explanation:
i cheat on Acellus cause I dont care about school. If i did I would be going to public school... Im never gonna use this info in my life so I dont bother learning it.
Y=5sin (3x -4t)
Cdculate the wavelength frequency and period.
Pls answer and explanation with formula
explanation
the general form of wave equation is
y=Asin(kx-wt)
we have
y=5sin(3x-4t)
hence the angular frequency
w= 4s^-1
the frequency
f=w/2 pi
f=4/2 pi
f=4/2*3.14
f=0.64 hz
the period
T=1/f
T=1/0.64
T=1.5625=1.6
the wavelength
k=2 pi/lambda
lambda=2 pi/k
k=3
so
lambda=2*3.14/3
lambda=2.09
if my answer is right then mark me brainlist
Which of the following scientists proposed the theories of relativity?
A. Galileo Galilei
B. Johannes Kepler
C. Albert Einstein
D. Sir Isaac Newton
Answer:
c) Albert Einstein,
Explanation:
in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels.
hope this helped
-lvr
Which reverses the flow of current through
an electric motor?
Answer:
a commutator
Explanation:
To a stationary observer, a bus moves south with a speed of 12 m/s. A man
inside walks toward the back of the bus with a speed of 0.5 m/s relative to
the bus. What is the velocity of the man according to a stationary observer?
A. 11 m/s south
B. 12.5 m/s south
C. 11.5 m/s south
D. 0.5 m/s south
ANSWER
C 11.5 m/s
EXPLANATION
Answer:
11.5m/s south
Explanation:
Online classes
Click this link to view O*NET Skills section for Electrical Engineers. Note that common skills are listed toward the top and less common skills are listed toward the bottom. According to O*NET, what are some common skills Electrical Engineers need?
Explanation:
O*NET stands for Occupational Network and it is an online platform for job seekers around the world who are searching for jobs. This platforms provides the job information along with the required qualities, education background, skill sets, etc.
The most common skill sets that are required for an electrical engineers are
1. Analytical skills
2. Monitoring and active learning
3. Decision making
4. Able to manage the personal resources
5. Time management.
6. Should have knowledge about different software.
Find the force acting on it and the acceleration. 15 points. Will give brainliest!
Answer:
[tex]F_{net} = 1905 N[/tex]
[tex]\boxed{a = 7.62 m/s^2}[/tex]
Explanation:
For net force:
Firstly, finding the force of friction:
[tex]F_{k} =[/tex] [tex](micro)_{k} m g cos \theta[/tex]
Where [tex](micro)_{k}[/tex] is the coefficient of friction, m = 250 kg and g = 9.8 m/s²
[tex]F_{k} = (0.17)(25)(9.8) cos (52)\\F_{k} = (41.65)(0.616)\\F_{k} = 25.59 \ N[/tex]
Now, Finding of the pulling box:
[tex]F = mgsin\theta[/tex]
[tex]F = (250)(9.8) Sin (52)\\F = 2450 * 0.788\\F = 1930.6[/tex]
So, The net Force is
[tex]F _{net} = F - F_{k}[/tex]
[tex]F_{net} = 1930.6 -25.6\\[/tex]
[tex]F_{net} = 1905 N[/tex]
For Acceleration:
[tex]F_{net} = m a[/tex]
For a, it is:
=> [tex]a = \frac{F_{net}}{m}[/tex]
=> a = 1905 / 250
=> a = 7.62 m/s²
Which force acts on a body if it is fully or partially immersed in a
liquid?
Answer:
Buoyant Force
Explanation:
That's literally the definition of the buoyant force
A mobile starts and travels 225 m with an acceleration of (- 3.5i + 4.5j) 2 along a rectilinear path. Determine:
a) The time spent
b) The final speed
c) The average speed I hope you can help me.
Answer:
a) 8.89 s
b) 50.6 m/s
c) 25.3 m/s
Explanation:
d = 225 m
v₀ = 0 m/s
a = (-3.5i + 4.5j) m/s²
First, find the magnitude of the acceleration.
a = √((-3.5)² + (4.5)²) m/s²
a = 5.7 m/s²
a) Find t
Δx = v₀ t + ½ at²
225 m = (0 m/s) t + ½ (5.7 m/s²) t²
t = 8.89 s
b) Find v
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (5.7 m/s²) (225 m)
v = 50.6 m/s
c) Find v_avg
v_avg = Δx / t
v_avg = 225 m / 8.89 s
v_avg = 25.3 m/s
Or, for constant acceleration:
v_avg = (v₀ + v) / 2
v_avg = (0 m/s + 50.6 m/s) / 2
v_avg = 25.3 m/s
A point charge +Q is located on the x axis at x = a, and a second point charge –Q is located on the x axis at x = –a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is
Answer:
Net flux through the surface is zero.
Explanation:
Recall that the net electric flux through a closed surface depends on the net charge enclosed inside that surface.
In our case, there are two point charges of exactly opposite charge (net charge - zero), which are located inside the Gaussian surface of radius "2 a" centered at the origin - both charges are located at a distance "a" from the origin of coordinates, therefore inside the Gaussian surface.
Then the net flux through the surface is also ZERO.
A piano has a mass of 99 kg. What is the weight of the piano?
Explanation:
weight of the piano = mg
w = 99 x 10 =990 N
Allocate birr 5000 among the three workers in the ratio 1/3 :1/6 and 5/12.
Answer:
1666.7 ETB (birr)
833.3 ETB (birr)
2083.3 ETB (birr)
Explanation:
The first worker
5000*1/3=1666.7
The second worker
5000*1/6=833.3
The third worker
5000*5/12=2083.3
Hope this helps :) ❤❤❤
please help me with this question
Car at rest:
velocity= 0m/s
Acceleration:
0.2m/s²
Since total time:
3 min = 180s
Formula of acceleration:
acceleration = [final velocity - initial velocity] ÷ [total time]
Velocity at end:
0.2m/s² = [final velocity - 0m/s] ÷ [180s]
0.2m/s² × 180s = [final velocity]
[final velocity] = 36m/s
Distance travelled:
Velocity = displacement(distance) ÷ time
36m/s = displacement(distance) ÷ 180s
displacement(distance) = 36m/s × 180s
displacement(distance) = 6480m
Hey I'm sorry but i do not understand why the answer on your worksheet for distance travelled is 3240m... its half of what my answer is...
sliding friction is _ than the static friction.
Answer:
less
Explanation:
Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.
A firework is initially at rest explodes into 2 pieces one of which weighing 2.0 kg flies to the right at15 m/s the other piece flies to tje left at 20m/s wjat is tge mass of firework before explosion??
Answer:
3.5 kg
Explanation:
use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)
= m1(0) - m1v1f = m2v2f - m2(0)
= (-2.0)(15)/-20
= 1.5 kg
then add the other piece (2.0kg)
1.5 + 2.0 = 3.5 kg
The mass of firework before explosion is 3.50kg.
mass flying to right m1 = 2kg
v1 = 15 m/s
mass flying to left m2 = ?
v2 = - 20m/s
initial velocity u = 0
by conservation of linear momentum
m1v1+ m2v2 = (m1+m2 ) u
2x 15- m2x 20 = 0
m2 = 1.50kg
therefore mass of firework before explosion
m1+m2
2+ 1.50
= 3.50kg
What is mass?Mass is the amount of matter in a physical body. It also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines its gravitational force on other objects. The basic SI unit of mass is the kilogram.
Body mass is always constant. One way to calculate mass:
mass = volume × density. Weight is a measure of the gravitational force acting on a mass. The SI unit of mass is the "kilogram".
To learn more about mass, refer;
https://brainly.com/question/19694949
#SPJ2
Two children push on opposite sides of a door during play. Both push horizontally and perpendicular to the surface of the door. One child pushes with a force of 17.5 N at a distance of 0.59 m from the hinges, and the second child pushes at a distance of 0.47 m.
What force must the second child exert to keep the door from moving? Assume friction is negligible.
Answer:
F₂ = 21.97 N
Explanation:
this is a rotational equilibrium exercise, let's write the formula
∑ τ = 0
F₁ d₁ - F₂ d₂ = 0
force F₁ is 17.5 N and its distance d₁ = 0.59m, the distance d₂ = 0.47m
F₂ = F₁ d₁ / d₂
F₂ = 17.5 0.59 / 0.47
F₂ = 21.97 N
A 115 kg hockey player, Adam, is skating east whenever he tackles a 133 kg player, Bob, skating west at -1.59 m/s. Afterwards, they move together at .250 m/s east. What was Adam's velocity before the collision? (Unit = m/s)
Answer:
2.38 m/s
Explanation:
Momentum is conserved:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
After the collision, they move at the same speed, so v₁ = v₂ = v.
m₁u₁ + m₂u₂ = (m₁ + m₂) v
Plugging in numbers:
(115 kg) u₁ + (133 kg) (-1.59 m/s) = (115 kg + 133 kg) (0.250 m/s)
u₁ = 2.38 m/s
Three children use the same skateboard. i) 20-30kg, ii) 30-40 kg iii) 40-50kg Which child can move the skateboard using the smallest pushing force? Justify your choice.
Answer:
i) 20-30 kg
Explanation:
The child with the smallest mass range of 20-30 kg will require the smallest force to move his skate board because he/she has a smaller inertia force to overcome. The mass of a body is the measure of the inertia forces of the body. The inertia force makes it difficult for a body at rest to start moving, and a body already in motion to stop moving.
When the children try to move the skateboard, they exert a force that is proportional to the product of their mass and the acceleration with which they start moving. This force must exceed their body's inertia force before they would start moving.
from
F = ma
where F is the force required
m is the mass
a is the acceleration
We can see that for the given mass ranges, the children with the larger mass range will require more force in order to move their skateboard. Consequently, the child with the smallest mass range will require the smallest pushing force to move his skate board.
The power source provides a current of 1.86 A at a potential difference of 3.90 V. Calculate the power of the power source. Use the equation:
power = potential difference × current
Choose the correct unit from the box below
C W J
Answer:
W
Explanation:
The unit for Power which is (Volt X Current) is Watts. and the symbol for Watts is W.
Which material allows light to pass through A. opaque materials only
B. transparent materials only C. translucent and opaque materials
D. transparent and translucent materials
Answer:
D. transparent and translucent materials
Explanation:
OPAQUE MATERIALS:
Opaque Materials are those materials that absorb all the light and do not allow the light to pass through them.
TRANSLUCENT MATERIALS:
Translucent materials are those materials, that absorb a portion of light, allowing the light to partially pass through them.
TRANSPARENT MATERIALS:
Transparent materials are those materials that do not absorb the light and allow the light to completely pass through them.
Therefore, the correct option is:
D. transparent and translucent materials
Hydrogen fuel cells are used on the space shuttle to provide the shuttle with all of its electrical energy. Explain why fuel cells are used instead of batteries.
Answer:
Hydrogen used in fuel cells has the energy to weight ratio ten times greater than lithium-ion batteries. Consequently, it offers much greater range while being lighter and occupying smaller volumes. It can also be recharged in a few minutes, similarly to gasoline vehicles.
Which of the following does each different kind of atom represent?
O A. A nucleus
O B. An element
O C. An electron
OD. A neutron
Answer:
B
Explanation:
because atoms make up an element.
Answer:
B
Explanation:
it's b because an element makes up an atom and signifies the number of element in atom e.g (H2) the two signifies the number of atoms
why is string a good force measurer?
Answer:
tension is how much force is being exerted on each end of the string, whereas length is how long the string is. So assuming that the string has finite mass, then the tension on the string should increase proportionally to the string according to Newton's law f=ma.
Explanation:
What is the magnitude of the electrostatic force that the two protons inside the nucleus of a helium atom exert on each other? ( A distance of approximately r = 2*10–15 m separates the two protons.)
Answer:
F = 57.6 N
Explanation:
An electrostatic force is either a force of attraction or repulsion between two charges. When the two charges are like charges, the force is that of repulsion. But when they are of opposite charges, then the force between them is an attractive force.
A proton has a charge of 1.6 × [tex]10^{-19}[/tex] C. The electrostatic force can be determined by;
F = [tex]\frac{kq_{1}q_{2} }{r^{2} }[/tex]
Where: k is a constant, [tex]q_{1}[/tex] is the first charge, [tex]q_{2}[/tex] is the second charge, and r is the distance between the charges.
But, [tex]q_{1}[/tex] = [tex]q_{2}[/tex] = 1.6 × [tex]10^{-19}[/tex] C, k = 9 × [tex]10^{9}[/tex] N[tex]m^{2}[/tex]/[tex]C^{2}[/tex], r = 2 × [tex]10^{-15}[/tex] m. Therefore;
F = [tex]\frac{9*10^{9}*1.6*10^{-19} *1.6*10^{-19} }{(2*10^{-15}) ^{2} }[/tex]
= [tex]\frac{2.304*10^{-28} }{4*10^{-30} }[/tex]
= 57.6 N
The electrostatic force between the protons is 57.6 N.
When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.2 mV. When the current equals 1.40 A, the average flux through each turn of the solenoid is 0.00308 Wb. How many turns does the solenoid have?
Answer:
The solenoid has 213 turns.
Explanation:
The number of the solenoid's turns (N) can be found as follows:
[tex] N = \frac{L*I}{\phi_{B}} [/tex] (1)
Where:
L: is the self-inductance of the solenoid
I: is the current = 1.40 A
[tex]\phi_{B}[/tex]: is the magnetic flux = 0.00308 Wb
The self-inductance of the solenoid (L) is:
[tex] L = \frac{|\epsilon|}{|dI/dt|} [/tex] (2)
Where:
ε: is the induced emf = 12.2x10⁻³ V
dI/dt: is the rate changing of the current = 0.0260 A/s
By entering equation (2) into (1) we can find the number of turns:
[tex] N = \frac{|\epsilon|*I}{\phi_{B}|dI/dt|} = \frac{12.2 \cdot 10^{-3} V*1.40 A}{0.00308 Wb*0.0260 A/s} = 213 [/tex]
Therefore, the solenoid has 213 turns.
I hope it helps you!
PLEASE HELP ME ASAP. IT'S VERY IMPORTANT
Answer:
1) a. 52.41 m/s
b. The skier will be going 15.35 m/s slower
2) 103.68 m
3) 35,127 J
4) a. 88.825 kJ
(b) 16.36 %
5) 3,071.12 J
Explanation:
1) a. The given height of the hill, h = 140.0 m
The mass of the skier at the top of the hill, m = 85.0 kg
The acceleration due to gravity, g = 9.81 m/s²
The initial potential energy, P.E of the skier = m×g×h = 85.0×140.0×9.81 = 116739 J
From the principle of conservation of energy, we have;
The potential energy, P.E. lost = The gain in kinetic energy, K.E.
m×g×h = 1/2×m×v²
116739 J = 1/2×85.0×v²
v² = 116739/(1/2*85.0)= 2746.8 m²/s²
v = √(2746.8 m²/s²) = 52.41 m/s
b. From 70 m up, we have;
The initial potential energy, P.E., of the skier is now = 85.0×70×9.81 = 58,369.5 J
The potential energy, P.E. lost = The gain in kinetic energy, K.E.
58,369.5 J = 1/2×85.0×v²
v² = 58,369.5/(1/2*85.0) = 1373.4 m²/s²
v = 37.06 m/s
The skier will be going 52.41 - 37.06 = 15.35 m/s slower
The skier will be going 15.35 m/s slower
2) From the principle of conservation of energy, the amount of work done (energy used) = The (potential) energy gained by the load
The amount of work done by the electric hoist = 356,000 J
The mass of the load = 350.0 kg
The height to which the load is raised = h
The potential energy gained by the load = m×g×h = 350.0×9.81×h
356,000 J = 350.0×9.81×h
h = 356,000/(350.0*9.81) = 103.68 m
The height to which the load is lifted= 103.68 m
3) The initial potential energy of the roller coaster cart = 600*35.0*9.81 = 206010 J
The final potential energy = 600*28.0*9.81= 164808 J
The velocity at point 3 = 4.5 m/s
The kinetic energy at point 3 = 1/2*600*4.5^2 = 6075 J
The total energy at point 3 = 164808 + 6075 = 170,883 J
The energy loss = The initial potential energy at point 1 - Total energy at point 3
The energy loss = 206010 - 170,883 = 35,127 J
The heat energy due to friction that must have been produced between points 1 and 3 = 35,127 J
4) a. The heat energy absorbed = mass × specific heat capacity for water, [tex]C_{water}[/tex] × Temperature change
The mass of the water = 2.5×10² g = 0.25 kg
[tex]C_{water}[/tex] = 4,180 J/(kg·°C)
Initial temperature = 10.0°C
Final temperature = 95°C
The temperature change = 95.0°C - 10.0°C = 85.0°C
The heat energy absorbed = 0.25*4,180* 85 = 88,825 J = 88.825 kJ
(b) The percentage efficiency = (Heat absorbed/(Heat supplied)) × 100
The heat supplied = 543 kJ
The efficiency = (88.825/543) × 100 = 16.36 %
5) The mass of the box = 115 kg
Force acting on the rope = 255 N
The angle of inclination of the force to the horizontal = 24.5°
The distance the box is displaced = 15.0 m to the right
The work done = Force applied × distance moved in the direction of the force
The work done = Force applied × distance moved in the direction of the force
Given that the load moves a distance 15.0 m to the right,we have;
The component of the force acting in the direction of the movement of the load (to the right) is 225 × cos(24.5°) = 204.74 N
The work done = 204.7*15 = 3071.12 J
The amount of work done = 3,071.12 J
Proved that
V = u+at
Answer:
[tex]\sf Proof \ below[/tex]
Explanation:
We know that acceleration is change in velocity over time.
[tex]\sf a=\frac{\triangle v}{t}[/tex]
[tex]\sf a=\frac{v-u}{t}[/tex]
v is the final velocity and u is the initial velocity.
Solve for v.
Multiply both sides by t.
[tex]\sf at=v-u[/tex]
Add u to both sides.
[tex]\sf at + u=v[/tex]
Answer:
Acceleration = v-u/t when we flip -u and t to right hand side
then -u changes to plus and denominator t changes to numerator
then then this equations becomes v=u+at
Explanation:
A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
1) The time taken to get to the maximum height
ii) the time of flight
Explanation:
It is given that,
The angle of projection is 60 degrees
Initial velocity of the ball is 120 m/s
We need to find the time taken to get to the maximum height and the time of flight.
Time taken to reach the maximum height is given by :
[tex]T=\dfrac{u^2\sin^2\theta}{2g}[/tex]
g is acceleration due to gravity
[tex]T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s[/tex]
(ii) Time of flight,
[tex]t=\dfrac{2u\sin\theta}{g}[/tex]
So,
[tex]t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s[/tex]
Hence, this is the required solution.