Answer:
D=mass /volume
=60/0.002
=30000
Maria listed four important points about einstein’s special theory of relativity. 1) applies to any object moving more slowly than the speed of light 2) applies to objects moving in a straight path 3) describes the relationship between time and space 4) applies to uniformly moving objects which best describes how maria can correct her error? change the first point to "applies to objects moving almost at the speed of light." for point 2, include objects moving in a curved path. for point 3, replace the word "space" with the word "motion." change the fourth point to "applies to accelerating objects."
How Maria can correct her error is by changing the fourth point to "applies to accelerating objects.". Option D. This is further explained below.
What is einstein’s special theory of relativity?Generally, Einstein’s special relativity is simply defined as how speed affects matter, time, and space.
In conclusion, The theory contains a method for defining the link between energy and matter using the speed of light.
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In what way is a touch screen similar to a CCD? In what way is it different?
the mass of an object is 90 kg calculate weight of the same object on the surface of the moon.(acceleration due to gravity on the Moon surface is 1/6 of the value of acceleration due to the Gravity on Earth) also calculate the weight of the same object on earth surface.
Explanation:
the weight of an object is its force exerted by gravity.
on earth we take gravitational acceleration to be 9.8 m/s^2
so the weight of an object on earth is given by F = mg
hence,
F = 90 × 9.8
F = 882 Newtons (weight on earth)
gravitational acceleration on the moon is equal to 9.8/6. so, we can just use the same formula to find the weight on the moon.
F = 90 × 9.8/6
F = 147 Newtons (weight on the moon)
make sure to ask if you need any further guidance.
At 55 mph, how long does it take for a truck to fully stop?.
The time taken by a truck to fully stop will be 2 hours. The time taken is found with the help of Newtons second equation of motion.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data Is;
u is the velocity of truck = 55 mph
v is the final velocity of truck = 0 mph
S is the distance travelled by the truck before stop= 302 feet
1 feet = 0.000189394 mile
302 feet = 302 × 0.000189394 mile= 0.057197 mile
From the Newtons's second equation of motion;
[tex]\rm v^2 = u^2-2as[/tex]
The formula for the acceleration is found as;.
[tex]a = \frac{v-u}{t}[/tex]
By rearranging the equation, we get;
[tex]\rm u^2 =2as \\\\ u^2 =2[ \frac{v-u}{t}]s \\\\ u = \sqrt{2[ \frac{v-u}{t}]s} \\\\ 55 = \sqrt{2[ \frac{55-0}{t}]} \\\\ 55= \frac{2 \times 55}{t} \\\\ t= 2 \ hour[/tex]
Hence, the time taken by a truck to fully stop will be 2 hours.
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Q.01 When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False
True, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.
Relationship between dielectric material and electric field
The electric field in a capacitor separates the negative and positive charges in the dielectric material, this causes an attractive force between each plate and the dielectric.
The dielectric material can store electric energy due to its polarization in the presence of external electric field, which causes the positive charge to store on one electrode and negative charge on the other.
Thus, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.
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What is the origin of all stars?
supernova
dwarfs
protostars
nebulae
Answer:
Protostars
Explanation:
If the strings have different thicknesses, which of the following parameters, if any, will be different in the two strings?.
Answer:
Wave speed and wavelength
Explanation:
A skydiver is jumping from an airplane that is 1,000 meters above the ground. The diver has a mass of 130 kg. What is the potential energy at this height?
mgh
1/2 mv2
What is the potential energy at this height?
Explanation:
POTENTIAL energy is due to a mass's height above the earth and is equal to m * g * h
130 kg * 9.81 m/s^2 * 1000 m = 1275300 J
Which part of the electromagnetic spectrum can humans see?.
Answer:
The visible light spectrum
Explanation:
The visible light spectrum is the segment of the electromagnetic spectrum that the human eye can view.
A measurement of the hotness or coldness of an object can be defined by its... A. potential energy. B. magnetism. C. chemical potential. D. temperature.
Answer:D
Explanation: temperature is the measure of hotness and coldness of a body.
A 10 ohms, a 7 ohms and a 14 ohms resistor are connected in series with a 24 V battery. Calculate the equivalent resistance. Answer in units of ohms.
Answer:
31ohms
Explanation:
in a series u add all the ohms together
Why will a struck tuning fork sound louder when it is held against a table?.
Answer:
1.)the surface of the table is set into vibration
2.)the initial vibration was larger
3.)The entire table vibrates
Explanation:hope this helps :3 have a good day xlXCherryColaXlx..(pls mark me brainliest)
Andrea, whose mass is 48kg, thinks she's sitting at rest in her 5. 0m-long dorm room as she does her physics homework. Within what range is her velocity likely to be?
For Andrea, whose mass is 48kg, thinks she's sitting at rest in her 5. 0m-long, her range is mathematically given as
dv=1.95*10^{-37}ms^{-1}
Within what range is her velocity likely to be?Generally, the equation for the uncertainty principle is mathematically given as
mdxsv=h/2
Therefore
dv=h/(2mdx)
dv=1.054*10^{-39}/2*45*6
dv=1.95*10^{-37}ms^{-1}
In conclusion, range of her velocity
dv=1.95*10^{-37}ms^{-1}
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Which phase of the moon occurs after a waxing gibbous?.
In the rocket, what is the equal and opposite reaction?
Answer:
see below
Explanation:
Gases flying out at high velocity out the back
rocket flying forward
21
The law of universal gravitation can be expressed as
where F is the force of attraction, G is the universal graviational constant (6.674x10-11
N m2 kg-2) m1 is the mass of the first object, m2 is the mass of the second object, and r is th
distance between the centers of the two objects.
A 1.2-kilogram container of sugar sits 2.3 meters away from a 9.4-kilogram bag of flour. Wha
is the gravitational force of attraction between the sugar and the flour?
(4 Points)
mim2
F=G
72
The attractive force between sugar and flour by using Newton's law of gravitation is 14.229 × 10⁻¹¹ N.
What is the Universal law of Gravitation?This law states that every object in the universe attracts each other. The attractive force is directly proportional to the masses of two objects and inversely proportional to the square of the distance between them.
This law is applicable to all the objects with mass in the universe and hence it is called the Universal law of gravitation. It was proposed by Newton.
The attractive force, F =G (m₁×m₂ / r²). m₁,m₂ is the masses of two objects and r is the distance between two masses. G is the gravitational constant and is equal to 6.67×10⁻¹¹Nm²kg⁻².
From the given,
Gravitational constant,G = 6.67×10⁻¹¹Nm²kg⁻²
m₁ (mass of sugar) = 1.2 kg
m₂ (mass of flour) = 9.4 kg
r (distance of separation) = 2.3 m
The attractive force, F = G (m₁×m₂ / r²)
F = 6.67×10⁻¹¹×(1.2×9,4) / (2.3)²
= 14.229 × 10⁻¹¹ N
Thus, the attractive force F = 14.23 × 10⁻¹¹ N.
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If you wanted to decrease the gravitational force between two objects, what would you do?
Question 4 options:
Increase the distance between the two objects.
Decrease the distance between the two objects.
Increase the mass of both of the objects.
Increase the mass of one of the objects.
Answer:
Increase distance
Explanation:
Gravity force = g m1 m2 / r^2
so you can see that increasing the distance r^2 will make the force less
Answer: Increase the distance between the two objects.
Explanation:
Consider what features of objects affect the gravitational force exhibited.
What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s?
10 m/s 2
15 m/s 2
5 m/s 2
–15 m/s 2
Answer:
5
Explanation:
vf = vi + at
20 = 5 + 3a
3a = 15
a = 5
A 200-turn solenoid having a length of 25 cm and a diameter of 10 cm carries a current of 0.29 A. Calculate the magnitude of the magnetic field B inside the solenoid
Hi there!
We can use the following equation to calculate the magnetic field inside of a solenoid:
[tex]B = \mu_0 ni[/tex]
B = Magnetic Field Strength (T)
n = number of loops PER LENGTH
i = current through solenoid (A)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
First, we can solve for 'n' given 'N' (total # of loops) and L (length of solenoid).
[tex]n = \frac{N}{L} = \frac{200}{0.25} = 800[/tex]
Now, we can calculate the magnetic field:
[tex]B = (4\pi \times 10^{-7}) (800)(.29) = \boxed{2.915 \times 10^{-4} T}[/tex]
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 20 m/s when it reaches ground level. What was its speed when its height was half that of its starting point
Answer:
Approximately [tex]14\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
The gravitational potential energy [tex]\text{GPE}[/tex] of this roller coaster is proportional to the height [tex]h[/tex] of the roller coaster.
The kinetic energy [tex]\text{KE}[/tex] of this roller coaster is proportional to the square of speed [tex]v[/tex].
The question states that the track is frictionless. Thus, during the descent, the [tex]\text{GPE}[/tex] of this roller coaster is turned into [tex]\text{KE}[/tex] without any energy loss.
When the roller coaster was at [tex](1/2)[/tex] of the the initial height, only[tex]1 - (1/2) = (1/2)[/tex] of the original [tex]\text{GPE}[/tex] was turned into [tex]\text{KE}[/tex]. The [tex]\text{KE}\![/tex] of this roller coaster at that height would be [tex]1 - (1/2) = (1/2)\![/tex] of the [tex]\text{KE}\!\![/tex] when the roller coaster is at the ground level.
The [tex]\text{KE}[/tex] of the roller coaster is proportional to [tex]v^{2}[/tex] (the square of speed [tex]v[/tex].) Thus, since the [tex]\text{KE}\![/tex] at [tex](1/2)[/tex] the initial height is [tex]1 - (1/2) = (1/2)\![/tex] the [tex]\text{KE}\!\![/tex] at the ground level, the [tex]v^{2}[/tex] at [tex](1/2)\![/tex] the initial height would also be [tex]1 - (1/2) = (1/2)\![/tex] the [tex]v^{2}\![/tex] at the ground level.
Since [tex]v = 20\; {\rm m\cdot s^{-1}}[/tex] at the ground level, [tex]v^{2} = (20\; {\rm m\cdot s^{-1}})^{2}[/tex] at the ground level. The [tex]v^{2}[/tex] at [tex](1/2)[/tex] the initial height would then be:
[tex](1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}[/tex].
Thus, the speed [tex]v[/tex] at [tex](1/2)[/tex] the initial height would be:
[tex]\begin{aligned}& \sqrt{(1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{\frac{1}{2} \times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{200}\; {\rm m\cdot s^{-1}} \\ \approx\; & 14\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
A ray of light hits a mirror at 27 degrees from the normal. What is the angle between the reflected ray and the normal?
Which describes the movement of a fluid during convection?
Warm and cool fluids rise.
Warm and cool fluids sink.
Warm fluid rises and cool fluid sinks.
Warm fluid sinks and cool fluid rises.
Answer:
warm rises cold sinks
Explanation:
When driving on roads that may be slippery: A. Always drive at the maximum speed limit. B. Use cruise control to maintain a steady speed. C. Reduce your following distance. D. Do not make any sudden changes in speed or direction.
When driving on roads that may be slippery, do not make any sudden changes in speed or direction. Option D is correct.
What is a slippery surface?The slick road sign serves as a warning. When the road is wet or ice, drivers should use extra caution and reduce their speed. When the weather is bad, avoid making any rapid changes in direction.
When driving on roads that may be slippery, do not make any sudden changes in speed or direction. It may cause accident because the vehicle can lose their balance.
Hence, option D is correct.
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A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.
Answer:
As Per Provided Information
Moving body has 2m/s² acceleration
Time taken by body is 4 second
We are asked to find the 'change in velocity' ( ∆V) by the body.
Formula Used here
[tex] \boxed{\bf{\Delta \: V \: = acceleration \: \times time \:}}[/tex]
Substituting the given value
[tex] \sf\longrightarrow\Delta\:V \: = 2 \times 4 \\ \\ \\ \sf\longrightarrow\Delta\:V \: =8m {s}^{ - 1} [/tex]
Therefore,
Change in velocity is 8 m/sWhat is the electrical force between q2 and q3? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 1.0 × 1011 n –1.1 × 1011 n –1.6 × 1011 n 1.8 × 1011 n
The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
What is the magnitude of electrical forces between two charges?The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.
The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below
[tex]F = \frac{K \times q_2 \times q_3}{d^{2}}[/tex]
Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
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Answer:B .–1.1 × 10¹¹ N
Explanation:
Got it right on edge
Transfer payments are used to redistribute money to various segments of society. please select the best answer from the choices provided t f
Answer:
True
Explanation:
You pay back what you owe for what youve purchased
Answer: True
Explanation:
Throughout the reflection, make sure you have a copy of the student guide and your data tables. use the drop-down menus to complete the statements. the independent variable in part i, the one that is intentionally manipulated, is the . the independent variable in part ii, the one that is intentionally manipulated, is the . the independent variable in part iii, the one that is intentionally manipulated, is the . the independent variable in part iv, the one that is intentionally manipulated, is the .
The value of the dependent variable is based upon changes in the values of the independent variable.
What is dependent and independent variable?The term independent variable has to do with the variable that is being intentionally manipulated in an experiment. The dependent variable is the variable that changes in value as the independent variable is manipulated.
Now, the question is unclear however, we do know that in an experiment, the value of the dependent variable is based upon changes in the values of the independent variable.
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Answer:
The independent variable in Part I, the one that is intentionally manipulated, is the
✔ type of material
.
The independent variable in Part II, the one that is intentionally manipulated, is the
✔ charge of an object
.
The independent variable in Part III, the one that is intentionally manipulated, is the
✔ movement of a magnet
.
The independent variable in Part IV, the one that is intentionally manipulated, is the
✔ presence of an electric field
.
Explanation:
Jessica is riding on a merry-go-round on an outer horse that sits at a distance
of 8.0 m from the center of the ride. Jessica's sister, Julie, is on an inner horse
located 6.0 m from the ride's center. The merry-go-round turns around once
every 40.0 s. a) Explain which girl is moving with the greater linear speed.
b) What is the centripetal acceleration of Julie and her horse?
a. Jessica's has a greater linear speed.
b. The centripetal acceleration of Julie and her horse is 0.148 m/s².
a) Explain which girl is moving with the greater linear speed.Jessica's has a greater linear speed.
To answer the question, we need to know what Linear speed is.
What is linear speed?This is the tangential speed at which an object in circular motion moves. It is given by v = rω where
r = distance of object from center of circle and ω = angular speed.Now, given that Jessica is riding on a merry-go-round on an outer horse that sits at a distance of 8.0 m from the center of the ride and Jessica's sister, Julie, is on an inner horse located 6.0 m from the ride's center. Also, the merry-go-round is moving at constant angular speed.
Since Linear speed v = rω and ω = constant,
So, v ∝ r.
So, the girl with the greater distance from the center of the merry-go-round would have the greater linear speed.
Since
Jessica is at r' = 8.0 m and Julie is at r" = 6.0 m.Since
v ∝ r, and r' = 8.0 m > r" = 6.0 m,So, Jessica's has a greater linear speed.
b) What is the centripetal acceleration of Julie and her horse?The centripetal acceleration of Julie and her horse is 0.148 m/s².
Centripetal acceleration a = rω² where
r = distance of Julie from center of merry-go-round = 6.0 m and ω = angular speed of merry go round.Since the merry-go-round turns once every 40.0 s, we have that ω = 2π/40.0 s
= π/20.0 s
= 0.157 rad/s
Since a = rω²
Substituting the values of the variables into the equation, we have
a = rω²
a = 6.0 m × (0.157 rad/s)²
a = 6.0 m × 0.0247 rad²/s²
a = 0.148 m/s²
So, the centripetal acceleration of Julie and her horse is 0.148 m/s².
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A dart sketch and describe a potential energy diagram that represents the striking and burning of the match. Remember and label the diagram with the energy changes that occur. Parentheses you may do the sketch by hand or using a drawing program. Parentheses your answer must include potential energy diagram and a written description. Parentheses note you do not have to use actual energy values
Answer:
I love ur pfp! Ok here's a rough image of how a typical energy diagram works. You give a little energy (A) and you get the potential that was in there all along. Kinda like pushing a big rock off a cliff. You do a little work then get a lot of energy out as the PE turns into other forms. In a match it's heat and light
Is this correct?
Explanation:
Why does the luminosity of a high-mass star remain nearly constant as the star burns heavy elements in its core, even though it is producing millions of times more energy per second than it did on the main sequence