What is the common denominator of 7/9 and 6/7

Answers

Answer 1

Answer: 126

Step-by-step explanation: I belive that is the answer


Related Questions

May someone please help me with this question thank you.

Answers

Answer: 3rd option

Step-by-step explanation:

5500        55

-------- = ----------  

   p          100

Suppose that 2000$ is initially invested in an account at a fixed interest rate, compounded continuously. Suppose also that, after five years, the amount of money in the account is $2403 . Find the interest rate per year.

Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

% per year

Answers

Answer:

13400

Step-by-step explanation:

Using completion of square find a general solution to ax^(2) + bx + 1 = 0. What are the conditions for both the solutions to be real and for both to be complex numbers.

Answers

To find a general solution to the equation ax^(2) + bx + 1 = 0 using the completion of the square, we need to follow these steps:

1. Divide the entire equation by a to get x^(2) + (b/a)x + 1/a = 0.

2. Move the constant term to the right side of the equation: x^(2) + (b/a)x = -1/a.

3. Complete the square by adding (b/2a)^(2) to both sides of the equation: x^(2) + (b/a)x + (b/2a)^(2) = -1/a + (b/2a)^(2).

4. Factor the left side of the equation: (x + b/2a)^(2) = -1/a + (b/2a)^(2).

5. Take the square root of both sides of the equation: x + b/2a = ±√(-1/a + (b/2a)^(2)).

6. Solve for x: x = -b/2a ± √(-1/a + (b/2a)^(2)).

This is the general solution to the equation.

The conditions for both solutions to be real are that the discriminant, -1/a + (b/2a)^(2), is greater than or equal to 0. This means that b^(2) - 4a >= 0.

The conditions for both solutions to be complex numbers are that the discriminant, -1/a + (b/2a)^(2), is less than 0. This means that b^(2) - 4a < 0.

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Question content area top
Part 1
The functions f and g are defined as
​f(x)=7x
and
​g(x)=x−5.
​a) Find the domain of​ f, g,
f+​g,
f−​g,
​fg, ff,
fg​,
and
gf.
​b) Find
​(f+​g)(x),
​(f−​g)(x),
​(fg)(x), (ff)(x),
fg(x)​,
and
gf(x).

Answers

gf(x) = (x-5)(7x)

Part 1
a) The domain of f is all real numbers, since 7x is defined for all real numbers x. The domain of g is all real numbers, since x-5 is defined for all real numbers x. The domain of f+g is all real numbers, since the sum of two real numbers is a real number. The domain of f-g is all real numbers, since the difference of two real numbers is a real number. The domain of fg is all real numbers for which the product 7x(x-5) is defined, which is all real numbers except for x=5. The domain of ff is all real numbers, since the product of two real numbers is a real number. The domain of fg is all real numbers, since the product of two real numbers is a real number. The domain of gf is all real numbers, since the product of two real numbers is a real number.

b) (f+g)(x) = 7x + x - 5 = 8x - 5
(f-g)(x) = 7x - x + 5 = 6x + 5
(fg)(x) = 7x(x-5)
(ff)(x) = (7x)^2
fg(x) = (7x)(x-5)
gf(x) = (x-5)(7x)

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Question 5 (1 point)
cosx
1−sinx

−tanx=?
a)
cscx
b)
secx
c)
1−secx
d)
1−cscx

Answers

The value of −tanx is 1−secx, which is option c) in the given choices.

The correct answer is option c) 1−secx.

To find the value of −tanx, we can use the identity tanx = sinx/cosx. Multiplying both sides of the equation by −1 gives us −tanx = −sinx/cosx.

We can then substitute the value of cosx from the given equation into the equation for −tanx:

−tanx = −sinx/(1−sinx)

Multiplying both sides of the equation by (1−sinx) gives us:

−tanx(1−sinx) = −sinx

Distributing the −tanx on the left side of the equation gives us:

−tanx + tanx*sinx = −sinx

Rearranging the equation and factoring out sinx gives us:

tanx*sinx + sinx = tanx

sinx(tanx + 1) = tanx

Dividing both sides of the equation by (tanx + 1) gives us:

sinx = tanx/(tanx + 1)

Using the identity 1/cosx = secx, we can substitute secx for 1/cosx in the equation:

sinx = (sinx/cosx)/(sinx/cosx + 1/cosx)

Simplifying the equation gives us:

sinx = sinx/(sinx + secx)

Cross multiplying and rearranging the equation gives us:

sinx*(sinx + secx) = sinx

sinx^2 + sinx*secx = sinx

Subtracting sinx from both sides of the equation gives us:

sinx^2 + sinx*secx - sinx = 0

Factoring out sinx gives us:

sinx(sinx + secx - 1) = 0

Setting each factor equal to 0 gives us:

sinx = 0 or sinx + secx - 1 = 0

Solving for secx in the second equation gives us:

secx = 1 - sinx

Therefore, the value of −tanx is 1−secx, which is option c) in the given choices.

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PLEASE HELP 100 POINTS WHOEVER GETS CORRECT NOW!!!!!!


Emily uses 1 2/3 cups of sugar and 3 1/4 cups flour to make muffins. She says she has 1 2/3 more cups of flour than sugar. Do you agree? Explain.


A. Yes; 3 1/4 − 1 2/3 = 1 2/3.


B.

No; the difference between 3 1/4 and 1 2/3 is 1 1/2 , not 1 2/3.


C. No; the difference between 3 1/4 and 1 2/3 is 1 7/12, not 1 2/3
.

D. No; the sum of 3 1/4 and 1 2/3 is 4 11/12, not 1 2/3

Answers

Answer:

c

Step-by-step explanation:

1 2/3 = 5/3 = 20/12

3 1/4 = 13/4 =39/12

Question 13 A polynomial, P(x), has real coefficients and also has zeros at 1,1+i, and 2-i. Then this polynomial must have a degree of

Answers

The polynomial P(x) must have a degree of 4.

This is because a polynomial with real coefficients must have complex zeros in conjugate pairs. This means that if 1+i is a zero of the polynomial, then its conjugate, 1-i, must also be a zero. Similarly, if 2-i is a zero, then its conjugate, 2+i, must also be a zero. Therefore, the polynomial P(x) must have zeros at 1, 1+i, 1-i, 2-i, and 2+i. Since a polynomial's degree is equal to the number of its zeros, the polynomial must have a degree of 4.

In summary, a polynomial with real coefficients and zeros at 1, 1+i, and 2-i must have a degree of 4.

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"Use the Law of Sines to solve (if possible) the triangle. If two
solutions exist, find both. Round your answers to two decimal
places.
A = 21° , a = 9.5, b = 22
Case 1:
B=? C=? c=?
Case 2:
B=? C=? c=?"

Answers

The two possible solutions for the given triangle are:

Case 1: $B = 51.92°$, $C = 107.08°$, $c = 25.93$

Case 2: $B = 128.08°$, $C = 30.92°$, $c = 13.45$

Both solutions exist and are rounded to two decimal places.

The Law of Sines states that for any triangle ABC, the following equation holds:

$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$

Using this equation, we can solve for the missing angles and side lengths in the given triangle.

Case 1:
To find angle B, we can rearrange the equation to get:

$\sin B = \frac{b \sin A}{a}$

Plugging in the given values:

$\sin B = \frac{22 \sin 21°}{9.5}$

$\sin B = 0.789$

Taking the inverse sine of both sides:

$B = \sin^{-1}(0.789)$

$B = 51.92°$

To find angle C, we can use the fact that the sum of the angles in a triangle is 180°:

$C = 180° - A - B$

$C = 180° - 21° - 51.92°$

$C = 107.08°$

Finally, to find side c, we can use the Law of Sines again:

$\frac{c}{\sin C} = \frac{a}{\sin A}$

Rearranging and plugging in the given values:

$c = \frac{a \sin C}{\sin A}$

$c = \frac{9.5 \sin 107.08°}{\sin 21°}$

$c = 25.93$

So the solution for Case 1 is:

$B = 51.92°$, $C = 107.08°$, $c = 25.93$

Case 2:
In this case, we need to consider the possibility of an obtuse angle B. To find this angle, we can use the fact that the sine of an obtuse angle is the same as the sine of its supplement:

$\sin B = \sin (180° - B)$

So we can find the supplement of the angle we found in Case 1:

$B = 180° - 51.92°$

$B = 128.08°$

Plugging this value back into the Law of Sines equation, we can find the other missing values:

$C = 180° - A - B$

$C = 180° - 21° - 128.08°$

$C = 30.92°$

$c = \frac{a \sin C}{\sin A}$

$c = \frac{9.5 \sin 30.92°}{\sin 21°}$

$c = 13.45$

So the solution for Case 2 is:

$B = 128.08°$, $C = 30.92°$, $c = 13.45$

Therefore, the two possible solutions for the given triangle are:

Case 1: $B = 51.92°$, $C = 107.08°$, $c = 25.93$

Case 2: $B = 128.08°$, $C = 30.92°$, $c = 13.45$

Both solutions exist and are rounded to two decimal places.

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HELP PLS BRAINLIEST AND FIVE STAR IF ALL OF THESE ARE CORRECT
a)√(x^2-14x+49)=x-7
b)√(4x^2-20x+25)=5-2x
C)√(y^4+2y^2+1)=y^2+1
d)√(x^2+2x+1)=x+1
e)√(y^2-20y+100)=y-10
f)√(y^6-2y^3+1)=y^3-1

pls answer all pls pls pls
(also the answer is most likely NOT all real numbers or no solutions)

Answers

The solution to the all six equations is that they have infinite many real solutions

How to determine the solution to the equations

Expression (a)

We have:

√(x^2-14x+49)=x-7

Squaring both sides we get:

x^2 - 14x + 49 = x^2 - 14x + 49

Evaluate the like terms

0 = 0

This means that the equation has infinite many solutions

Expression (b)

Here, we have:

√(4x^2-20x+25)=5-2x

Squaring both sides we get:

4x^2-20x+25 = 25 - 20x + 4x^2

Evaluate the like terms

0 = 0

This means that the equation has infinite many solutions

For the remaining expressions, we have the following (using the above steps)

Expression (c)

√(y^4+2y^2+1) = y^2 + 1

y^4 + 2y^2 + 1 = y^4 + 2y^2 + 1

0 = 0

Expression (d)

√(x^2+2x+1)=x+1

x^2 + 2x + 1 = x^2 + 2x + 1

0 = 0

Expression (e)

√(y^2-20y+100)=y-10

y^2 - 20y + 100 = y^2 - 20y + 100

0 = 0

Expression (f)

√(y^6-2y^3+1)=y^3-1

y^6-2y^3+1 = y^6-2y^3+1

0 = 0

Hence, the equations have infinite solutions

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The function y = f(x) is graphed below. What is the average rate of change of the
function f(x) on the interval -5 ≤ x ≤ 0?

Answers

The requried rate of change of the function f[x] on the interval -5 ≤ x ≤ 0 is F(x)' = -11/5.

What is the rate of change?

Rate of change is defined as the change in value with rest to the time is called rate of change.

Here,
From the graph we have,
F(-5) = 1 and F(0) = -10

So the rate of change is given as,
F(x)' = F(0) - F(-5) / 0 + 5
F(x)' = -10 - 1 / 5
F(x)' = -11/5

Thus, the requried rate of change of the function f[x] on the interval -5 ≤ x ≤ 0 is F(x)' = -11/5.

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3.[10points]Suppose{v1​,…,vk​}is an orthogonal basis of a subspaceVofRnand{w1​,…,wℓ​}is an orthogonal basis ofV⊥. (a) Show that{v1​,…,vk​,w1​,…,wℓ​}is an orthogonal set. (b) Show that{v1​,…,vk​,w1​,…,wℓ​}is basis ofRn. (c) Show thatdimV+dimV⊥=n

Answers

(a) To show that {v1​,…,vk​,w1​,…,wℓ​} is an orthogonal set, we must show that the inner product of any two distinct vectors in this set is 0.

(b) To show that {v1​,…,vk​,w1​,…,wℓ​} is a basis of Rn, we must show that any vector in Rn can be written as a linear combination of these vectors.

(c) To show that dim V + dim V⊥ = n, we must show that the number of vectors in {v1​,…,vk​,w1​,…,wℓ​} is equal to n.

Let v and w be any two distinct vectors in the set {v1​,…,vk​,w1​,…,wℓ​}. By definition, since {v1​,…,vk​} is an orthogonal basis of a subspace V of Rn and {w1​,…,wℓ​} is an orthogonal basis of V⊥, we have that v and w are either in V or in V⊥, but not both.

Thus, if v is in V, then we have  = 0, because w is in V⊥. Similarly, if w is in V⊥, then  = 0, because v is in V. Therefore,  = 0 for any two distinct vectors v and w in {v1​,…,vk​,w1​,…,wℓ​}, which implies that {v1​,…,vk​,w1​,…,wℓ​} is an orthogonal set.

(b) Let x be any vector in Rn. Since {v1​,…,vk​} is a basis of V, x can be written as a linear combination of the vectors in {v1​,…,vk​}, that is, x = a1v1 + a2v2 + ... + akvk.

Since {w1​,…,wℓ​} is a basis of V⊥, x can also be written as a linear combination of the vectors in {w1​,…,wℓ​}, that is, x = b1w1 + b2w2 + ... + bℓwℓ.

Combining these two equations, we can write x = (a1v1 + a2v2 + ... + akvk) + (b1w1 + b2w2 + ... + bℓwℓ). Thus, any vector in Rn can be written as a linear combination of the vectors in {v1​,…,vk​,w1​,…,wℓ​}, which implies that {v1​,…,vk​,w1​,…,wℓ​} is a basis of Rn.

By definition, {v1​,…,vk​} is an orthogonal basis of a subspace V of Rn, so dim V = k. Similarly, {w1​,…,wℓ​} is an orthogonal basis of V⊥, so dim V⊥ = ℓ. Thus, the number of vectors in {v1​,…,vk​,w1​,…,wℓ​} is k + ℓ = n, which implies that dim V + dim V⊥ = n.

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Write a polynomial f(x) that satisfies the given conditions. Degree 3 polynomial with integer coefficients with zeros 8i and 6/5
f(x) = The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high, sales will drop. If the price is too low, the revenue brought in may not cover the cost to produce the shirts. After months of data
collection, the sales team determines that the monthly profit is approximated by f(p)=-50p+2050p-20,700, where p is the price per shirt and f(p) is the monthly profit based on that price.
(a) Find the price that generates the maximum profit.
(b) Find the maximum profit.
(c) Find the price(s) that would enable the company to break even. If there is more than one price, use the "and" button.

Answers

a) maximum profit 20.5.

b) maximum profit 20,025.

c)  price 10.35

The given function, f(p)=-50p+2050p-20,700, is not a degree 3 polynomial. It is a degree 1 polynomial or a linear function. Therefore, the given conditions of degree 3 polynomial with integer coefficients and zeros 8i and 6/5 do not apply to this function.

Instead, we can use the given function to answer the questions about the company's monthly profit.

(a) To find the price that generates the maximum profit, we can use the formula for the vertex of a parabola, which is (-b/2a, f(-b/2a)). In this case, a = -50 and b = 2050.
The price that generates the maximum profit is -b/2a = -2050/(2*-50) = 20.5.

(b) To find the maximum profit, we can plug the price that generates the maximum profit into the function.
f(20.5) = -50(20.5) + 2050(20.5) - 20,700 = 20,025.

(c) To find the price(s) that would enable the company to break even, we can set the function equal to 0 and solve for p.
0 = -50p + 2050p - 20,700
20,700 = 2000p
p = 10.35

Therefore, the price that would enable the company to break even is 10.35. There is only one price that would enable the company to break even.

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A robot can complete 7 tasks in ⅖
hour. Each task takes the same amount of time. How long does it take the robot to complete one​ task?

Answers

Answer: [tex]\frac{2}{35}[/tex] hour

Step-by-step explanation:

      We will divide the time it takes it to do 7 tasks (⅖ hour) by the number of tasks it does in that time frame (7 tasks) to find the time per task.

[tex]\frac{2}{5}[/tex] hour / 7 tasks = [tex]\frac{2}{5} *\frac{1}{7}[/tex] = [tex]\frac{2}{35}[/tex] hour or about 3.43 minutes

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Find the equation for the line that passes through the point
(4,−4) , and that is parallel to the line with the equation
−6x−2y=14 .

Answers

The equation for the line that passes through the point (4, -4) and is parallel to the line with the equation -6x - 2y = 14 is y = -3x + 8.

To find the equation for the line that passes through the point (4, -4) and is parallel to the line with the equation -6x - 2y = 14, we first need to find the slope of the given line. We can do this by rearranging the equation to solve for y and putting it in slope-intercept form, y = mx + b.

-6x - 2y = 14

-2y = 6x + 14

y = -3x - 7

The slope of the given line is -3. Since the line we are trying to find is parallel to the given line, it will have the same slope. Therefore, the slope of the line we are trying to find is also -3.

Now, we can use the point-slope form of a linear equation, y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is a point on the line, to find the equation of the line. Plugging in the slope and the point (4, -4), we get:

y - (-4) = -3(x - 4)

y + 4 = -3x + 12

y = -3x + 8

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Someone help me get all these right - WILL MARK BRAINLIEST!
1. 4x+6=8x-22

2.find the slope: (-6,8) and (-4, -12)

3.4x+5y=24

4. Evealuate the function. f(x)=7x-1 for f(-5)

Answers

The value of x in the function 4x+6=8x-22 is 7.

The slope is equal to -10.

The slope-intercept form of the function 4x+5y=24 is y = -4x/5 + 24/5.

The value of f(-5) is equal to -36.

How to calculate the slope of a line?

In Mathematics, the slope of any straight line can be determined by using this mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Substituting the given points into the slope formula, we have the following;

Slope, m = (-12 - 8)/(-4 + 6)

Slope, m = -20/2

Slope, m = -10.

4x+6=8x-22

8x - 4x = 22 + 6

4x = 28

x = 7.

4x + 5y = 24

5y = -4x + 24

y = -4x/5 + 24/5

For f(-5), we have:

f(x)=7x-1

f(-5)=7(-5)-1

f(-5) = -36.

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A carpenter builds boekshelves and tables for a flving- Each bookshelf takes eoe box of screws, two
2×4
s, and four sheets of plywood to make. Each table takes two boxes of serews, fwo
2×4
k, an three sheets of plyaced. The capenter has 75 boxes of screws,
952×4
's, and 255 shects of plywood on hand. in order to maimize their proft using these materials on hand, the carpenter has determined that they most buld 11 shelves and 24 tables. Hew many of each of the meterials (boxes of screws,
2×4
s, and sheets of plywood) are lefovec, nhen the carpenter builds 18 shelves and 24 tables? The carpenter hat benes of screws,
2×4
's, and theets of plywood leftoven A carpenter buldes bookshelves and tables for a Ining. Each booksheif takes one box of wcrews, two
2×45
, and four sheets of plywood to make. Each table takes two boves of screns, two
2×4
s, and three sheets of plyweod. The carpenter has 75 bewes of screws,
952×43
, and 155 sheets of pliwood on hend. In order to maximite their proff usimp these materias co hand, the carpentee has determined that they must buid 18 shelves and 24 tabies. How many of coch of the matersis (bokes of ucrews,
2×43
, and sheets of Elywoed) ore leftove, when the carpenter buibs as ahelves and 24 tables? The campenter has boxes of screws,
2×4
s.s, and sheets of plywood leftover?

Answers

After building 18 shelves and 24 tables, the carpenter will have 9 boxes of screws, 80 2x4s, and 39 sheets of plywood leftover.

To find the leftover materials, we need to calculate the total materials used to build 18 shelves and 24 tables, and then subtract that from the total materials the carpenter had on hand.

For 18 shelves, the carpenter used 18 boxes of screws, 36 2x4s, and 72 sheets of plywood. For 24 tables, the carpenter used 48 boxes of screws, 48 2x4s, and 72 sheets of plywood.

So, the carpenter used 66 boxes of screws, 84 2x4s, and 144 sheets of plywood in total.

Subtracting this from the materials on hand, we get 9 boxes of screws, 80 2x4s, and 39 sheets of plywood leftover.

Therefore, the carpenter can potentially use these leftover materials for future projects or sell them to recoup some of their costs.

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25.4% of flowers of a certain species bloom "early" (before May 1st). You work for an arboretum and have a display of these flowers. All probabilities here to 3 decimal places.
a) In a row of 48 flowers, what is the probability that 13 will bloom early?
b) In a row of 48 flowers, what is the probability that fewer than 13 will bloom early?
c) As you walk down the row of 48 these flowers, how many early blooming flowers do you expect to observe (on average)? (Keep your answer as a decimal.)
d) In a row of 48 flowers, what is the probability that at least 13 will bloom early?
e) In a row of 48 flowers, what is the probability that between 9 and 14 (inclusive) will bloom early?
f) What is the standard deviation of the number of flowers that bloom early in a row of 48 flowers (to 4 decimal places here!!!) ?

Answers

According to the given information, the probabilites are a) 0.159, b)0.107, d) 0.893 e) 0.662 c) expected value is 12.192 f) standard deviation is 3.0121.

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event.

a) Using the binomial probability formula, we have:

P(X = 13) = (48)^13 * (0.254)^13 * (0.746)^35

= 0.159

So the probability that 13 out of 48 flowers will bloom early is 0.159.

b) To find the probability that fewer than 13 flowers will bloom early, we can find the cumulative probability up to 12:

P(X < 13) = P(X = 0) + P(X = 1) + ... + P(X = 12)

= ∑(48 choose k) * (0.254)^k * (0.746)^(48-k) from k=0 to 12

= 0.107

So the probability that fewer than 13 flowers will bloom early is 0.107.

c) The expected value of a binomial distribution is given by n*p, where n is the number of trials and p is the probability of success. In this case, we have:

E(X) = 48 * 0.254

= 12.192

So on average, we expect to observe about 12.192 early blooming flowers.

d) To find the probability that at least 13 flowers will bloom early, we can use the complement rule and find the probability that 12 or fewer flowers will bloom early, and subtract that from 1:

P(X ≥ 13) = 1 - P(X < 13)

= 1 - 0.107

= 0.893

So the probability that at least 13 flowers will bloom early is 0.893.

e) To find the probability that between 9 and 14 flowers (inclusive) will bloom early, we can find the cumulative probability from 9 to 14:

P(9 ≤ X ≤ 14) = P(X = 9) + P(X = 10) + ... + P(X = 14)

= ∑(48 choose k) * (0.254)^k * (0.746)^(48-k) from k=9 to 14

= 0.662

So the probability that between 9 and 14 flowers (inclusive) will bloom early is 0.662.

f) The variance of a binomial distribution is given by np(1-p), and the standard deviation is the square root of the variance. In this case, we have:

Var(X) = 48 * 0.254 * (1-0.254)

= 9.078

SD(X) = sqrt(Var(X))

= sqrt(9.078)

= 3.0121 (rounded to 4 decimal places)

So the standard deviation of the number of flowers that bloom early in a row of 48 flowers is approximately 3.0121.

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The linear regression equation for a data set is y = 3.2x - 1.2. The actual value at = 4 is 14. What is the residual value
at x = 4?
2.4
B 8.0
11.6
D 12.8

Answers

Answer: 11.6

Step-by-step explanation: plug in x for 4. 3.2(4)-1.2 = 11.6

42w to the 2 power +15w to the 2 power–3w to the 2 power

Answers

Answer:

54w²

Step-by-step explanation:

42w² + 15w²-3w²

42w²+ 15w²= 57w²

57w²-3w²= 54w²

 please help me with this linear problem.

Answers

Answer:

the ans is f(x)=1.7x+21,472

The equation of the function is exponential and the function is f(x) = 21472(1.017)ˣ.

How to solve exponential equation?

The population of a small town in Connecticut is 21,472 and the expected population growth is 1.7% each year.

Let's use a function to represent the town's population x years from now.

Hence,

1.7% = 1.7  / 100 = 0.017

Therefore,

f(x) = 21472(1 + 0.017)ˣ

Hence,

f(x) = 21472(1.017)ˣ

Therefore, the function is exponential.

The equation of the function is f(x) = 21472(1.017)ˣ

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Cos ^4 x rewrite the expression as an equivalent expression that does not contain powers are trigonometric functions greater than 1.

Answers

Recall that:

cos^2(x) = (1 + cos(2x))/2
cos(2x) = 2cos^2(x) - 1
Using these identities, we can rewrite cos^4(x) as follows:

cos^4(x) = (cos^2(x))^2
= [(1 + cos(2x))/2]^2
= (1/4) + (1/2)cos(2x) + (1/4)cos^2(2x)
= (1/4) + (1/2)cos(2x) + (1/4)[2cos^2(x) - 1]^2
= (1/4) + (1/2)cos(2x) + (1/4)[4cos^4(x) - 4cos^2(x) + 1]

Now, we can simplify the expression by collecting like terms and grouping the powers of cos(x) together:

cos^4(x) = (1/4) + (1/2)cos(2x) + (1/4)[4cos^4(x) - 4cos^2(x) + 1]
= (3/4)cos^4(x) - (1/2)cos^2(x) + (5/4)
= (3/4)[1 - sin^2(x)]^2 - (1/2)[1 - sin^2(x)] + (5/4)

This final expression is equivalent to cos^4(x) and does not contain any powers of trigonometric functions greater than 1.

50x8+25 take away what equals 225?

Answers

50 x 8 + 25 is 425 so just take away 200 to get 225

Answer:

1.8 i think

Step-by-step explanation:

i used a calculator

help please!!!!!! as soon as possible

Answers

Answer:

Step-by-step explanation:

ok so first u do 12 times 2 and then divide by 3

There's a screen shot thank you so much have a good day! <3

Answers

Answer: 6 and 12

Step-by-step explanation:

explain why the x-coordinates of the points where the graphs of the equations y=x^2-x and y=20 intersect are the solutions of the equation x^2-x=20

Answers

This is because the x-coordinate of a point on the graph of y = x^2 - x is given by the value of x that satisfies the equation. Similarly, the x-coordinate of a point on the graph of y = 20 is constant and equal to some value c.

Explaining why the x-coordinates of the points where graphs intersect is the solution

To find the x-coordinates of the points where the graphs of the equations y = x^2 - x and y = 20 intersect, we need to solve the system of equations:

y = x^2 - x

y = 20

Since both equations are equal to y, we can set them equal to each other:

x^2 - x = 20

Now, if we solve for x, we will get the x-coordinates of the points where the two graphs intersect.

Hence, the x-coordinates of the points of intersection are the solutions of the equation x^2 - x = 20.

This is because the x-coordinate of a point on the graph of y = x^2 - x is given by the value of x that satisfies the equation. Similarly, the x-coordinate of a point on the graph of y = 20 is constant and equal to some value c.

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I have 5 mathematics books, 4 astronomy, and 3 physics books. I have always fancied both math and physics but don’t like these books to touch each other. I feel astronomy plays well with both subjects so astronomy can touch either. In how many ways can I arrange the books on a shelf if:

-All the books are different
-I want subjects grouped together
-Math and physics cannot touch

1. How many ways can I arrange the books.
2. What if I let the math and physics books touch?

Answers

1.) The total number of ways in which the books can be arranged so that mathematics and physics cannot touch = 478,961,280.

2.) The total number of ways the books can be arranged when math and physics books touch = 479,001,600

What is permutation?

Permutation is defined as the expression that shows how objects can be arranged in a definite order.

The total number of mathematics books = 5

The total number of astronomy books = 4

The total number of physics = 3

The total number of books that the student has in possession = 5+4+3 = 12.

The arrangement of the books so that math and physics cannot touch = 12!-8!

= 479001600 - 40320

= 478,961,280

The arrangement of the books so that math and physics can touch = 12! = 479,001,600

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If x has a remainder of 5 when divide by 6 and x>10, what is the smallest possible value of x ?

Answers

The smallest possible value of x is 11.

To find the smallest possible value of x, we can use the formula x = 6n + 5, where n is an integer. This formula represents the fact that x has a remainder of 5 when divided by 6.

If we plug in different values for n, we can find the smallest possible value of x that is greater than 10.

When n = 1, x = 6(1) + 5 = 11
When n = 2, x = 6(2) + 5 = 17
When n = 3, x = 6(3) + 5 = 23

Therefore, the smallest possible value of x that is greater than 10 is 11, so the answer is 11.

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What is the ratio of red to blue squares in its simplest form?
Red Blue
00

Answers

The ratio of red to blue squares is given by the division of the number of red squares by the number of blue squares.

How to obtain the ratio?

The ratio between two amounts, a and b, is obtained applying a proportion, as the ratio is the division of the amount a by the amount b.

The amounts for this problem are given as follows:

Amount a: number of red squares.Amount b: number of blue squares.

Hence the ratio is given by the division of the number of red squares by the number of blue squares.

For example, for 10 red and 20 blue squares, the ratio is given as follows:

r = 10:20 = 1:2.

Missing Information

The problem is incomplete, hence the general procedure to obtain the ratio is presented.

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1 3 1 2. The augmented matrix of a system of linear equations is given: , determine value(s) of k if 2 k - 2 (a) the system has no solution, (b) the system has one solution, (c) the system has infinit

Answers

The augmented matrix of a system of linear equations is given: , determine value(s) of k if 2 k - 2 if  the system has no solution there are no values of k that will make the system inconsistent.  The system has one solution for all values of k except k = 4.The system has infinitely many solutions if k = 0, a unique solution if k ≠ 0 and k ≠ 4, and no solutions if k = 4



To determine the value(s) of k for each case, we will perform row reduction on the augmented matrix and analyze the resulting echelon form.

1 3 1 | 0

2 k - 2 | 0

R2 - 2R1 -> R2

1 3 1 | 0

0 k - 4 | 0

Case (a): If k = 4, then the second row becomes all zeros except for the last entry, which means we have an inconsistent system with no solutions. If k ≠ 4, then we can use back-substitution to find the solution(s):

k - 4 = 0 => k = 4

Since this contradicts our assumption, there are no values of k that will make the system inconsistent.

Case (b): If k ≠ 4, then the echelon form shows that we have a leading coefficient in each row and the system has a unique solution. If k = 4, then the second row becomes all zeros except for the last entry, which means we have an inconsistent system with no solutions.

Case (c): If k = 0, then the second row reduces to 0 = 0, which means we have a free variable and infinitely many solutions. If k ≠ 0 and k ≠ 4, then the echelon form shows that we have a leading coefficient in each row and the system has a unique solution. If k = 4, then the system is inconsistent with no solutions.

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If A and B are two independent events in certain sample space S,
then show that A^c and B^c are also independent where "c" denotes
the complement operator

Answers

P(A ∩ B) = P(A)P(B) and P(Ac ∩ Bc) = P(Ac)P(Bc).

The complement operator “c” refers to the inverse of an event. Therefore, for two independent events A and B in a sample space S, the inverse events Ac and Bc are also independent. This is because the probability of two independent events occurring is equal to the product of their individual probabilities. Therefore, the probability of two inverse events occurring is equal to the product of their individual probabilities.

Mathematically, this is expressed as follows: P(A ∩ B) = P(A)P(B) and P(Ac ∩ Bc) = P(Ac)P(Bc).

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