The capacitance of two square parallel plates will be 1.777 farads.
What is the capacitance of two parallel plates?The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.
The parallel plate capacitor formula is given by:
C = ε Ad
Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,
C = ε Ad
C = 2.2 x 0.67 x 0.67 x 1.8
C = 1.777 farad
Two parallel square plates will have a capacitance of 1.777 farads.
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i have to find the sound waves and it doesn’t really give any clear instructions. help?
Explanation:
#31 = crest
#32 = Trough
#33 = Wavelength
#34 = Amplitude
-TheUnknownScientist
Answer:
vaat hachi upar vada ni.
Find the velocity of a truck traveling north 50 meters in 20 seconds. Question 2 options: 2.5 m/s 1 m/s North 10 m/s North 2.5 m/s North
Answer:
2.5 m/s North
Explanation:
Took the quiz on K12 it was right
How would gravity cause planets to move if they did not have inertia?
A. Planets would orbit Jupiter, the largest planet
B. Planets would run into one another
C. Planets would be pulled into the sun
D. Planets would move in a straight line away from the sun
Answer: Planets would be pulled into the sun
Explanation:
This is the correct answer.
please help me I promise will mark u brainest
Answer:
Point A
Explanation:
There are 3 states of equilibrium, which are as follows:
1. Stable Equilibrium
2. Unstable Equilibrium
3. Neutral Equilibrium
1. Stable Equilibrium:
A body is said to be in stable equilibrium, if it comes back to its original position, when it is slightly displaced. In this case the center of mass of the body is raised up as compared to the initial position.
Example: A book lying on a table, a map hanging on the wall, a stone suspended by a spring.
2. Unstable Equilibrium:
A body is said to be in unstable equilibrium if it does not come back to its original position when it is slightly displaced. In this case the center of mass of the body is lowered, as compared to the initial position.
Example: A vertical standing pencil, a stick balanced on finger, a funnel resting on its pointed end.
3. Neutral Equilibrium:
A body is said to be in neutral equilibrium, if on being slightly displaced it does not come back to its original position but occupies a new position similar to its original position. In this case the center of mass of the body remains at same height.
Example: A spherical ball on floor, a cone resting in horizontal position.
So, it is clear from the figure that when we will remove displacement the bus will come back to its original position. Therefore, this is the case of stable equilibrium.
So, the center of mass must have raised up. The original center of mass of the bus must be in the center. So, now the center of mass should have moved above center of bus, vertically.
Therefore, the center of mass of the bus is at point A
Someone please help.
Q. A body of mass 10kg falling freely in the gravitational field close to the moon's surface has an acceleration of 1.6 m/s.
what is the gravitational field strength on the moon?
A. 0 N/kg
B. 1.6 N/kg
C. 10 N/kg
D.16 N/kg
Answer:
B is the answer
Explanation:
(50 pts) How are beryllium and carbon made inside a star?
Thanks! :)
Answer:
Stars create new elements in their cores bu squeezing elements together in a process called unclear fusion. First stars fuse hydrogen atoms into heluim. Helium atorm then fuse to create berylluim and so on until fusion in the star’s core has created every element up to icon.
pls help, will give brainliest!
Answer:
Explanation:
Force of gravity is equal to mass times g
Fg=150 N
Fg=mg
150=m(9.81)
m=150/9.81 kg
FnetX=20-10=10 N
Fnetx=ma
10=150/9.81(a)
a=0.654 ms^-2
Note acceleration might need significant figures so it a=0.7 ms^-2
For the normal force, if the object isn't moving up or down. Then you can assume it's equal to the gravitational force which is 150 N.
If the object is accelerating up or down. I don't know how you would find normal force because not enough information.
Given that:
= 2i + 9j ; and ⃗ = -i – 4j . Find . ⃗
Answer:
A.B = -38
Explanation:
A = 2i + 9j and B = -i - 4j.
So, A.B = (2i + 9j).(-i - 4j)
= 2i.(-i) + 2i.(-4j) + 9j.(-i) + 9j.(-4j)
= -2i.i - 8i.j - 9j.i - 36j.j
since i.i = 1, j.j = 1, i.j = 0 and j.i = 0, we have
A.B = -2(1) - 8(0) - 9(0) - 36(1)
A.B = -2 - 0 - 0 - 36
A.B = -38
In this circuit, energy is transferred from a battery to a circuit wire and then to a light bulb, where some of it leaves the system. Starting from the battery, which series shows the correct order of energy transformations taking place in this circuit?
Answer: The correct order of energy transformation is from CHEMICAL ENERGY to ELECTRICAL ENERGY to LIGHT ENERGY
Explanation:
Energy which is simply defined as the ability to perform work is made up of different forms, these include:
- Mechanical energy: Associated with machines at work.
- LIGHT ENERGY: produced by light bulbs
- ELECTRICAL ENERGY: taking in by television set and other electrical appliances.
- CHEMICAL ENERGY: stores in food and other fuels
- Sound energy: Produced by vibrating objects example piano, drums.
According to the law of conservation of energy, energy can neither be created nor destroyed in a closed system, but can be transformed from one form to another, thereby keeping the energy in the closed system constant. From the question, the circuit is an example of a closed system and the order of energy transformation taking place is from the battery (CHEMICAL ENERGY) to ELECTRICAL ENERGY(power source) to LIGHT ENERGY(bulb). I hope this helps, thanks.
Which of these jobs is MOST likely to be open to someone with an associate’s degree (in other words, a two-year college degree)?
A.
computer support specialist
B.
database administrator
C.
operations research analyst
D.
business information manager
a 15-g block of aluminum has a volume of 5.5 cm. what is the density
Answer: 2.72727272......g/cm3^
Explanation:
D = g/cm^3
soo d = 15/5.5
A 15-g block of aluminum has a volume of 5.5 cm. Its density will be 2.73 kg / [tex]cm^{3}[/tex]
What is Density ?Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density is defined as the ratio of mass of the object to the volume of the object. Different substances have different densities.
The mathematical expression for density is as follows: Density=Mass * Volume. The mass of a substance is expressed in kilograms and the volume is expressed in liter.
Density is an important concept because it allows us to determine what substances will float and what substances will sink when placed in a liquid. Generally, substances float so long as their density is less than the density of the liquid they are placed in.
Density Symbol: ρ
Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.
Density = mass / volume
mass = 15 kg
volume = 5.5 [tex]cm^{3}[/tex]
density = 15 / 5.5 = 2.73 kg / [tex]cm^{3}[/tex]
A 15-g block of aluminum has a volume of 5.5 cm. Its density will be 2.73 kg / [tex]cm^{3}[/tex]
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1. If the coefficient of static friction is,μ=.72 for the surface which the man is standing on, then what is the force of friction. Ff=μFn
2. If the velocity of the car below has an initial velocity of 5m/s and is projected at an angle of 60 degrees relative to the horizontal then what is the total time of travel, the range and maximum height?
3.A cyclist is riding with an initial velocity of 16m/s when she notices a cat in front of her. She then slows down and begins coasting with a constant acceleration of -.62m/s2. Find the time it will take the cyclist to stop.
The main kinematic equations,
Vf=Vo+at
(Vf)2=(Vo)2+2aΔx
Δx=Vot+(½)at2
4.A ball with a mass of 5kg is dropped from a height of 20m. How long will it take the ball to reach the ground.
HELP ASAP
Answer:
1. The force of friction [tex]F_f =0.72 \times F_n[/tex]
2. The total travel time is approximately 0.884 seconds
The range is approximately 2.209 m
The maximum height reached is approximately 0.383 m
3. The time it will take the cyclist to stop is approximately 25.806 seconds
4. The time it will take the ball to reach the ground is approximately 2.020 seconds
Explanation:
1. Given that the coefficient of static friction, μ = 0.72, we have;
[tex]F_f = \mu \cdot F_n = 0.72 \times F_n[/tex]
2. The given parameters are;
The initial velocity of the car, v = 5 m/s
The direction of the vehicle = 60° to the horizontal
Therefore, we have;
The vertical component of the velocity, [tex]v_y[/tex] = 5 × sin(60°) = 2.5×√3
[tex]v_y[/tex] = 2.5×√3 m/s
The total travel time, t = 2·u·sin(θ)/g = 2 × 5 × sin(60°)/9.8 ≈ 0.884
The total travel time, t ≈ 0.884 seconds
The range, R = (u²·sin(2·θ))/g = 5² × sin(120°)/9.8 ≈ 2.209
The maximum height is given from the v² = [tex]u_y[/tex]² - 2·g·h
Where;
v = The final velocity = 0 m/s at maximum height
h = [tex]h_{(max)}[/tex] = The maximum height
[tex]u_y[/tex] = The initial vertical velocity = 2.5·√3
∴ 0² = 2.5·√3² - 2 × 9.8 × [tex]h_{(max)}[/tex]
2.5·√3² = 2 × 9.8 × [tex]h_{(max)}[/tex]
[tex]h_{(max)}[/tex] = 2.5·√3²/(2 × 9.8) ≈ 0.383
The maximum height = [tex]h_{(max)}[/tex] = 0.383 m
3. The given parameters are;
The initial velocity of the cyclist, v₀ = 16 m/s
The deceleration of the cyclist, a = -0.62 m/s²
At the point the cyclist stops, the final velocity, [tex]v_f[/tex] = 0
Therefore, from the given kinematic equations, we have;
[tex]v_f[/tex] = v₀ + a·t
Where t, is the time it will take the cyclist to stop
∴ t = ([tex]v_f[/tex] - v₀)/a = (0 - 16)/(-0.62) ≈ 25.806
Therefore, the time it will take the cyclist to stop = t ≈ 25.806 seconds
4. The time, t, it will take the ball to reach the ground, from a height, h = 20 meters is given by the equation of free fall as follows;
h = 1/2·g·t²
Where;
g = The acceleration due to gravity = 9.8 m/s²
Therefore, we have;
t² = h/(1/2·g)
t = √(h/(1/2·g)) = √(20/(1/2 × 9.8)) = 2.0203050891 ≈ 2.02
The time it will take the ball to reach the ground, t ≈ 2.020 seconds.
Ik this is a lot so 15 points and ill give brainliest thank you!! Questions should be very easy tho
**Which organisms carry out photosynthesis?
**What does photosynthesis produce that we need?
**What is the formula for the chemical reaction of photosynthesis?
What is the pigment in plants called? What color light does it absorb?
**In what organelle does photosynthesis occur?
1.plants,most algae and cyanobacteria
2.during photosynthesis cells use carbon dioxide and energy from the sun to make sugar molecules and oxygen
3.carbon dioxide+water---Glucose+oxygen
4.chloryphil
5.it absorbs blue and red good and absorbs green poorly
6 In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll. Chloroplasts are surrounded by a double membrane and contain a third inner membrane, called the thylakoid membrane, that forms long folds within the organelle
The charge per unit length on a long, straight filament is -90.0μC/m . Find the electric field (c) 100cm from the filament, where distances are measured perpendicular to the length of the filament.
The electric field for 100 cm is 1.62 MN/C
Length of the straight filament = (100cm) (1m/100cm) = 1m
Electric field for the straight conductor = [tex]E = \frac{2k_{e} \lambda}{r}[/tex]
E = [2(8.99 × 10^9 N·m^2/C^2)(90.0 × 10^-6 C/m)] / 1 m
E = 1.62 MN/C
The electric field is directed radially inward, toward the filament.
The electric field is a force produced by a charge near its surroundings. This force is exerted on other charges when brought in the vicinity of this field. SI unit of the electric field is N/C (Force/Charge).
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Can light cause the plastic to melt? Why or why not? Does it matter what type of light he shines on the plastic
Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV exposure can make a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.
What is melting of plastic?Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV light can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.
When exposed to ultraviolet (UV) light from the sun, plastics degrade. If exposed to UV light for an extended period of time, it can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules.
Thus, light can cause the plastic to melt.
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Enzo throws a rock horizontally with a speed of 12 m/s from a bridge. It falls for 2.28 s before reaching the
water below with no appreciable air resistance. Just as the rock reaches the water, find
(a) the horizontal component of its velocity.
(b) the speed with which it is moving
(a) The horizontal component of its velocity is 12 m/s.
(b) The speed with which the block is moving at the end of the given time is 25.36 m/s.
What is horizontal component of velocity?The horizontal component of velocity is the velocity of a projectile directed along x - axis or x direction of the projectile path.
The horizontal component of a velocity is not affected by gravity since the velocity is directed along horizontal path.
This causes the horizontal component of velocity to be constant. That is the initial horizontal velocity is equal to the final horizontal velocity.
Since the rock is thrown horizontally, the horizontal component of its velocity will be constant and equal to 12 m/s.
The final speed of the block at end of the 2.28 s will due to change in vertical velocity.
The final vertical velocity of the block is calculated as follows;
v = u + gt
where;
u is the initial vertical velocity = 0v is the final vertical velocity after 2.28 secondsg is acceleration due to gravityt is timev = 0 + gt
v = gt
v = (9.8)(2.28)
v = 22.34 m/s
The resultant final speed if calculated as follows;
v = √(Vx² + Vy²)
where;
Vx is the final horizontal velocity = 12 m/sVy is the final vertical velocity = 22.34 m/sv = √(12² + 22.34²)
v = 25.36 m/s
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Declaration of Independence --- Articles of Confederation--- _________________________ -- U.S. Constitution The events above are in chronological order – what event below should be in the blank? a The Boston Tea Party b The Constitutional Convention c The French & Indian War d Both Boston Tea Party and The French and Indian War are correct
Answer:
b. The Constitutional Convention
Explanation:
The given events in its chronological order :
1. Declaration of Independence ---- 4th July, 1776.
2. Articles of Confederation ---------- 15th November, 1777
3. The Constitutional Convention ---- 25th May, 1787
4. U.S. Constitution ------------------------ 17 September, 1787
The U.S. Constitutional Convection took place in the year 1787 from 25th May to 17th September. It took place at the Pennsylvania State House situated in Philadelphia. The Constitutional Convection of the United States was chaired by George Washington.
He developed a system for predicting planetary positions that remained in use for some 1,500 years.
Answer: Ptolemy or Kepler or Tycho Brache
An airplane travels at 500.0 km/hr W. It encountered a south bound cross-wind and ends up with a velocity of 625 km/hr SW. What was the velocity of the cross-wind? Be sure to record your answer to the correct precision!
Answer:
The velocity of the cross-wind was 375 km/hr South
Explanation:
The given speed of the airplane, v₀ = 500.0 km/hr W
The direction the airplane is headed = West
The direction of the wind encountered = Southbound wind
The final velocity of the airplane, R = 625 km/hr
The final direction of the airplane = South West SW
Let vₐ represent the velocity of the cross-wind
Therefore, we have the given velocities in vector form as follows;
R = -500.0·i - vₐ·j
Also, we have;
[tex]\left | R \right | = 625 = \sqrt{v_0^2 + v_a^2} = \sqrt{(-500)^2 + (-v_a)^2}[/tex]
625² = (-500)² + (-vₐ)²
(-vₐ)² = 625² - (-500)² = 140625
-vₐ = 375
vₐ = -375 km/hr North = 375 km/hr South
The velocity of the cross-wind = vₐ = 375 km/hr South
The magnetic field 40.0 cm away from a long, straight wire carrying current 2.00 A is 1.00μT.(d) The center wire in a coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction. What magnetic field does the cable crew ate at points outside the cable
Magnetic field does the cable crew ate at points outside the cable will be zero .
The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by [tex]B=\frac{u_0I}{2\pi r}[/tex] ...(1) The definition of Ampere's law states that "the line integral of magnetic field strength along a closed path is equal to the current distribution through that loop".Mathematically, Ampere's law circuital law is given by
∫B.dl = u₀I ......(2) where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex] and I is the total current threading in the loop .
It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.
Hence the total current in the loop will be
[tex]I=2+(-2)=0[/tex]
Putting this value of current in equation (2) , we get
[tex]B=0[/tex]
As the total current is zero , so the magnetic field will be zero .
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Magnetic field does the cable crew ate at points outside the cable will be zero .
The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by [tex]B=\frac{u_0I}{2\pi r}[/tex] ...(1) The definition of Ampere's law states that "the line integral of magnetic field strength along a closed path is equal to the current distribution through that loop".Mathematically, Ampere's law circuital law is given by
∫B.dl = u₀I ......(2) where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex] and I is the total current threading in the loop .
It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.
Hence the total current in the loop will be
[tex]I=2+(-2)=0[/tex]
Putting this value of current in equation (2) , we get
[tex]B=0[/tex]
As the total current is zero , so the magnetic field will be zero .
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Magnetic field does the cable crew ate at points outside the cable will be zero .
The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by [tex]B=\frac{u_0I}{2\pi r}[/tex] ...(1) The definition of Ampere's law states that "the line integral of magnetic field strength along a closed path is equal to the current distribution through that loop".Mathematically, Ampere's law circuital law is given by
∫B.dl = u₀I ......(2) where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex] and I is the total current threading in the loop .
It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.
Hence the total current in the loop will be
[tex]I=2+(-2)=0[/tex]
Putting this value of current in equation (2) , we get
[tex]B=0[/tex]
As the total current is zero , so the magnetic field will be zero .
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in order to qualify for the finals in a racing event, a race car must achieve an average speed of 250 km/h on a track with a total length of 1600 m.
In order to qualify for the finals in a racing event the race car wit an average speed of 250 km/h on a track with a total length of 1600 m must finish the track in a time of: 23.04 seg
The formula and procedure we will use to solve this exercise is:
t = x/v
Where:
x = distancet = timev = velocityInformation about the problem:
v =250 km/hx=1600 mt = ?By converting the distance units from (m) to (km) we have:
x=1600 m * 1 km/1000 m
x = 1.6 km
Applying the time formula we have that:
t = x/v
t = 1.6 km / 250 km/h
t = 6.4 *10^-3 h
By converting the time units from (h) to (seg) we have:
t = 6.4 *10^-3 h * 3600 seg/1 h
t= 23.04 seg
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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An uncharged, nonconducting, hollow sphere of radius 10.0cm surrounds a 10.0-μC charge located at the origin of a Cartesian coordinate system. A drill with a radius of 1.00mm is aligned along the z axis, and a hole is drilled in the sphere. Calculate the electric flux through the hole.
The electric flux through the hole is [tex]56.45\ webber[/tex] .
Electric flux is the number of electric field lines cutting through the surface and is measured as surface intregal of electric field over that surfaceMathematically it is given by [tex]\phi_E=E.A \ Nm^2/C[/tex] where E is the electric field and A is the area. Gauss's law states that electric flux through closed surface is equal to the 1 / ε₀ times the charge enclosed by that surface which is given by Ф = q / ε₀ where q is the central charge and ε₀ is the permittivity of the medium.It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.
The whole surface of hollow sphere [tex]= 4\pi r^2[/tex]
[tex]= 4\times 3.14\times (10 \times 10^{-2})^2 \\\\= 12.56\times 10^{-2} m^2[/tex]
Area of the hole ( both side ) [tex]= 2\times \pi r^2[/tex]
[tex]= 2\times 3.14 \times (10^-^3)^2\\= 6.28 \times 10^-^6 m^2[/tex]
According to Gauss's theorem, the flow from a particular charge in the center is given by
[tex]\phi= \frac{10\times10^-^6}{8.85\times 10^-^1^2}\\\\\phi=1.13\times10^6[/tex]
This flux flows through the surface of the sphere, so the flux per unit area which is given by
[tex]= \frac{ 1.13\times 10^6 }{ 12.56\times 10^-^2} \\\\= 8.99 \times 10^6 \ weber / m^2[/tex]
Flux through area of hole is given by :
[tex]= 8.99\times10^6 \times6.28 \times 10^-^6\\ = 56.45 \ weber[/tex]
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what is the answer?
"Choice-C" is the answer.
At t=0 s, a bunny is hopping along at 1.0 m/s. It continues at that speed, until at t=10 s, when the bunny begins to slow down with a constant acceleration. It comes to a complete stop at t=12 s. What is the bunny’s displacement at t=12 s? What is the bunny’s acceleration when slowing down?
The bunny’s displacement at t=12 s is 12 m.
The bunny’s acceleration when slowing down is -0.083 m/s².
What is displacement?The displacement of an object is the change in position of the object.
The displacement of the object at time, t = 12 seconds, is the change in position from time, t = 0 seconds to time, t = 12 seconds.
Δx = v(t₂ - t₁)
Δx = 1 m/s (12 s - 0 s)
Δx = 12 m
Bunny’s acceleration when slowing downThe bunny’s acceleration when slowing down is calculated as follows;
a = (v - u)/(t₂ - t₁)
a = (0 - 1 m/s) / (12 s - 0 s)
a = -0.083 m/s²
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Answer:
The bunny’s displacement at t=12 s is 12 m.
The bunny’s acceleration when slowing down is -0.083 m/s².
A car changes its speed by 2 meters per second each second. What is its acceleration?
A. 4 m/s2
B. 0.5 m/s2
C. 2 m/s2
Answer:
2 m/s²
Explanation:
If changes speed by 2 meters per second each second means:
2 m/s²
Because it changes constantly it veloctity.
Remember the aceleration changes the velocity.
Answer:
c. 2 m/s2
is the right answer.
the unit used for measuring force is called the
Answer:
Newton, symbol N
Explanation:
newton, symbol N
Of all the parts of an atom, which part is the most important in terms of Electricity,Chemistry, and life In general?
1) neutrons
2) Neptune’s
3)protons
4)electrons
Mr. Krabs created a secret ingredient for breath mint that he thinks will "cure" the bad breath people
get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath
to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished
eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the
sandwich, however, it was just a regular breath mint and did not have the secret ingredient. Both
breath mint that would cure their bad breath. Two hours
groups were told that they were getting the
after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported
having better breath than they normally had after eating crabby patties.
2. What is the independent variable?
3. What is the dependent variable?
4. What should Mr. Krabs' conclusion be?
5. Why do you think 10 people in group B reported fresher breath?
The answers to the following questions are 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
1. The group of people who received the normal mint which does not contain Mr. krab's secret ingredient for breath mint is the control group. So, Group B of people are in the control group.
2. Independent variable in the one for which the research is being conducted. So in this case the secret ingredient in the breath mint is the independent variable.
3. Dependent variable is the one that affects the result of the research. So, the bad breath, in this case, is the dependernt variable.
4. The Group A of fifty people received the secret ingredient in breath mint; 30 people it reported better breath. Therefore the mint that has a secret ingredient is successful in reducing the amount of bad breaths in the individual but does not appear to be effective cent percent.
5. The 10 people in group B may have reported fresher breath due to the 'placebo' effect. It is the effect where the physical or mental health of the individual appears to improve after a fake, dummy, or sample treatment is given to him/her.
Therefore, 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
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glycerin at 20ºc fills the space between a hollow sleeve of diameter 14 cm and a fixed coaxial solid rod of diameter 12 cm. the outer sleeve is rotated at 160 rev/min. assuming no temperature change, estimate the torque required, in n∙m per meter of rod length, to hold the inner rod fixed.
The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length
Angular velocity, ω = 160rev/min
ω (rad/s) = (2π×160)/(60) = 16.74rad/s
Tangential velocity,
(V) = ωr
r is radius = 14/2 = 7cm = 0.07m
Tangential velocity of the sleeve
(V)= ωr
V = 16.74 rad/s×0.07m
V = 1.171m/s
Distance between the cylinders,
h= (14-12)/2 = 1cm
h = 0.01 m
Shear stress on glycerin is given by
τ = μ×V/h
μ is the dynamic viscosity of glycerin at 20°C = 1.49 kg/m.s
∴ τ = (1.49 ×1.171 )/(0.01)
τ = 174.4 N/m²
Shearing force (F) = shear stress × area
F = τ × A
F = τ * 2πrL [A=2πrL (area of cylinder )]
F/L = (17.4×2π×0.07)
F/L = 7.649N/m
To hold the inner rod fixed
the opposite torque by inner rod must be equal to torque produced by the shearing force.
Torque/length (N.m/length) = [force/length (N/m) * radius]
τ /L = 7.649 ×0.07 = 0.535N.m/rod length
The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length
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What happens to thermal energy when Kinetic energy is Increased/Decreased?
Answer:If kinetic energy increases, so does the thermal energy, and vice versa.
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