if the size of a radioactive sample is doubled, what happens to the activity of the sample in bq ? match the words in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer. resethelp the activity of the sample blank. the number of blank per second blank to the number of blank g
Rewriting the above question in a clearly manner,
"If the size of a radioactive sample is doubled, what happens to the activity of the sample in Becquerel (Bq)? Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.
The activity of the sample ________.
The number of ________ per second ________ to the number of ________ gram(s)."
ANSWER: The activity of the sample increases.
The number of decays per second doubles to the number of atoms/gram.
What is Radioactive decay?Radioactive decay is the process of spontaneous decay of a nucleus into another nucleus.
In a radioactive decay, the parent nuclide disintegrates into a different daughter nuclide while emitting an alpha particle, beta particle, or gamma rays.
When radioactive decay occurs, radiation is emitted as particles or electromagnetic radiation. The amount of radioactive substance in a sample, as well as the radioactive isotopes present in it, determine the activity of a radioactive sample. This is the rate at which radiation is emitted by the sample.
In a nuclear reaction, the activity of a radioactive substance is expressed in Becquerel (Bq). This is the amount of radioactive substance that decays in one second. One Bq equals one radioactive decay per second.
In summary, if the size of a radioactive sample is doubled, the activity of the sample in Bq is also doubled.
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in order to prepare a 0.30 m solution of food dye, how many ml of a 2.67 m stock solution should you add to a 50 ml volumetric flask before filling the flask to the calibration mark?
We need to add 5.61 ml of a 2.67 M stock solution dye to a 50 ml volumetric flask before filling the flask to the calibration mark.
This can be found using the formula of concentration and volume for dilution of solutions which is C1V1=C2V2.
Steps for finding the ml of a 2.67 M stock solution that should be added to a 50 ml volumetric flask before filling the flask to the calibration mark:
C1= is the initial concentration of the solution
V1 = is the initial volume of the solution
C2 = is the final concentration of the solution
V2 = is the final volume of the solution
Now, let's substitute the given values into the formula
Stock concentration : 2.67 M = C1
Final concentration : 0.30 M = C2
Final Volume : 50 ml = V2
Let V1 is the stock solution required
Therefore, 2.67 M * V1 = 0.30 M * 50 ml
2.67 M * V1 = 15 ml
V1 = 5.61 ml
Therefore, we need to add 5.61 ml of a 2.67 M stock solution to a 50 ml volumetric flask before filling the flask to the calibration mark to prepare a 0.30 M solution of food dye.
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which way will the molecules move to establish equilibrium using passive transport?
Molecules will move from an area of higher concentration to an area of lower concentration in order to establish equilibrium through passive transport. This is due to diffusion, which is the process in which molecules spread out from areas of high concentration to areas of low concentration.
The way molecules move to establish equilibrium using passive transport is from high concentration to low concentration. Passive transport is the movement of molecules across the cell membrane without requiring the expenditure of energy.Passive transport includes diffusion, osmosis, and facilitated diffusion. Diffusion is the movement of molecules from an area of high concentration to an area of low concentration.
Osmosis is the diffusion of water molecules across a selectively permeable membrane. Facilitated diffusion is the movement of molecules across the cell membrane with the aid of carrier proteins or channel proteins.Passive transport ensures that the molecules are transported in the correct direction for equilibrium to be reached. Equilibrium is reached when there is no net movement of molecules across the cell membrane.
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many lead salts are often used as pigments. if pbso4 were used in an unglazed ceramic bowl, how many milligrams of lead(ii) could dissolve per liter of water? (a) 43 (b) 35 (c) 11 (d) 28 (e) 53
53 mg of lead can be dissolved per litre of water. Option e is correct.
The solubility product constant, Ksp, of PbSO4 is given by the expression below:
Ksp= [Pb2+][SO42-]
If S is the solubility of PbSO4 in Molarity, then the quantity of lead ions that can dissolve from the salt into the solution is given as
S × MW (where MW is the molecular weight of PbSO4)
MW of PbSO4 = (1 x 207.2) + (1 x 32.06)+ (15.99 x 4) = 303.22 g/mol
S =√Ksp = √1.6 × 10-8= 1.26 × 10-4
So the number of milligrams of lead (II) that can dissolve per liter of water is
1.26 × 10^-4 M/L × 303.22 g/mol = 0.352 g/L= 35.2 mg/L≈ 35 mg/L
The correct answer is (e) 53 mg/L.
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How many pKa values are there for a monoprotic acid ?
a. 4
b. 2
c. 1
d. 3
Answer:
Only one, so option c
Explanation:
Because monoprotic as it says, had only one proton to lose giving it only one pka for example Hydrochloric Acid (H-Cl). unlike a diprotic acid which would have two pkas like carbonic acid for example (H2CO3).
solid calcium carbonate, caco3 , is able to remove sulphur dioxide from waste gases by the reaction (balanced as written): caco3 s 2 other reactants ------
Solid calcium carbonate (CaCO3) is capable of removing sulfur dioxide (SO2) from waste gases through the following reaction:CaCO3 (s) + 2SO2 (g) → CaSO3 (s) + CO2 (g)
This reaction is balanced as written, so there is no need to balance it further. The reaction can be used to remove sulfur dioxide from waste gases by passing the gases through a bed of solid calcium carbonate. The sulfur dioxide reacts with the calcium carbonate to form calcium sulfite (CaSO3) and carbon dioxide (CO2).The calcium sulfite can then be further oxidized to form calcium sulfate (CaSO4), which is a useful industrial chemical. This process is known as flue gas desulfurization and is commonly used in coal-fired power plants to reduce emissions of sulfur dioxide.
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a gas occupys 12.3 liters at a pressure of 40.0 mmhg. what is the volume when the pressure is increased to 60 mmhg
The volume of the gas drops from 12.3 L to 8.20 L as the pressure rises from 40.0 mmHg to 60.0 mmHg.
To solve this problem, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional when the temperature and the number of particles are constant. Mathematically, Boyle's law can be expressed as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Using this formula, we can calculate the final volume of the gas when the pressure is increased from 40.0 mmHg to 60.0 mmHg:
P₁V₁ = P₂V₂
(40.0 mmHg)(12.3 L) = (60.0 mmHg)(V₂)
Simplifying the equation, we get:
V₂ = (40.0 mmHg)(12.3 L) / (60.0 mmHg) = 8.20 L
Therefore, when the pressure is increased from 40.0 mmHg to 60.0 mmHg, the volume of the gas decreases from 12.3 L to 8.20 L, assuming the temperature and the number of particles remain constant.
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What is the main reason plants grow fruit?
Answer: Fruits contain seeds and develop from the ovaries of flowering plants. The first step in making fruits is pollination. Fruit trees and plants produce flowers. Then, bees, bats, birds, and even the wind spread pollen from one flower to another.
Answer:
Fruits contain seeds and develop from the ovaries of flowering plants. The first step in making fruits is pollination. Fruit trees and plants produce flowers. Then, bees, bats, birds, and even the wind spread pollen from one flower to another.
Explanation:
balancing equations lab
1.Balance: NaCl(s) → NaCl(aq)
2.This is a physical change because only the state of the substance changes from solid to aqueous, without any chemical reaction taking place.
What does the law of conservation of mass state?The law of conservation of mass states that in a closed system, the total mass of the system remains constant, regardless of any physical or chemical changes that take place.
3.Balanced equation: Na₂CO₃(aq) + CaCl₂(aq) → 2NaCl(aq) + CaCO₃(s). The state of the products are NaCl(aq) and CaCO₃(s).
4.This is a chemical change because a chemical reaction takes place, resulting in the formation of new substances with different properties.
5.When a new product is formed in a chemical reaction, the reacting atoms rearrange their bonds to form new molecules. Bonds between atoms are broken and new bonds are formed, resulting in the formation of new molecules with different properties. The conservation of atoms is maintained as the number of atoms of each element in the reactants must be equal to the number of atoms of each element in the products.
6.Balanced equation: Na₂CO₃(aq) + 2HC₂H₃O₂(aq) → 2NaC₂H₃O₂(aq) + H₂O(l) + CO₂(g). The state of the products are NaC₂H₃O₂(aq), H₂O(l), and CO₂(g).
7. In each experiment, the mass was conserved because the total mass of the reactants was equal to the total mass of the products. Therefore, mass was neither created nor destroyed during the reactions.
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For each reaction order: identify the proper units for the rate constant; k. Not all of the choices will be used: Zero order First order Second order Third order M . $ M" Answcr Bank M
The correct order of the reaction and proper units are:
The Zero order = 1/sThe First order = 1/M.sThe Second order = 1/M² sThe Third order = M/sThe units for the rate constant (k) is depend on the order reaction. For the zero order reaction, units of the k are the concentration/time, and which is the usually expressed as the moles per liter per second that is mol/L s or the per second (s⁻¹).
For the first order reaction, the units for the k is mol per second (mols⁻¹) and the second order reaction has the unit for the rate constant is M⁻² s⁻¹. The third order reaction has the unit for the rate constant is M⁻¹ s⁻¹.
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what is the mass of this tiny bubble of dry air? molecular masses are 28 for nitrogen and 32 for oxygen.
The mass of the tiny bubble of dry air containing 78% N₂ and 22 % O₂ is 28.88 g/mol.
The molecular masses of N₂ and O₂ are 28 g/mol and 32 g/mol respectively.
Tiny bubbles found in dry air is the air inside a solid, liquid or surrounded by a colloid within a fluidic environment.
The approximate molecular mass of dry air is calculated as
= [molecular mass of N₂ × mass percentage of N₂] + [molecular mass of O₂× mass percentage of O₂] / mass percent of N₂ + mass percent of O₂
=[28×78]+[32×22]/78 +22
=28.88 g/mol
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propose a structure for a molecule with the molecular formula C9H12 and corresponds to the following spectroscopic data
1H NMR d 6.78 (s, 1H), 2.26 (s, 3H); 13C NMR d 137.7 (no peak in DEPT-135 or DEPT-90), 127.0 (up peaks in both DEPT-135 and DEPT-90), 21.2 (up peak in DEPT-135, no peak in DEPT-90)
A proposed structure for the molecule with the molecular formula [tex]C_{9}H_{12}[/tex] , given the spectroscopic data, is 1-methyl-3-propylbenzene.
How to propose a structure for a molecule with given molecular formula and its NMR data?To propose a structure for a molecule with the molecular formula [tex]C_{9}H_{12}[/tex] and corresponding to the given spectroscopic data, we can follow these steps:
1. Analyze the 1H NMR data:
- d 6.78 (s, 1H) indicates a single hydrogen on an aromatic or unsaturated carbon.
- d 2.26 (s, 3H) suggests a methyl group (-CH3).
2. Analyze the 13C NMR data:
- d 137.7 (no peak in DEPT-135 or DEPT-90) corresponds to a quaternary carbon (no hydrogens attached).
- d 127.0 (up peaks in both DEPT-135 and DEPT-90) indicates a carbon with one hydrogen attached.
- d 21.2 (up peak in DEPT-135, no peak in DEPT-90) signifies a methyl carbon.
3. Combine the information:
- From the 1H NMR, we have one aromatic/unsaturated hydrogen and one methyl group.
- From the 13C NMR, we have one quaternary carbon, one carbon with a single hydrogen, and one methyl carbon.
4. Propose a structure:
- The molecule has nine carbons, so it could be an aromatic compound with a six-carbon ring (benzene-like) and three additional carbons.
- The quaternary carbon could be part of the aromatic ring, and the carbon with a single hydrogen could be connected to the ring and the methyl group.
- Based on this information, a possible structure is 1-methyl-3-propylbenzene.
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What is the equilibrium expression for the following reaction? 2Na2O (s) ⇌ 4Na (l) + O2 (g) K = [Na]4[O2] K = [Na2O]2 / ([Na]4[O2]) K = [O2] K = ([Na]4[O2]) / [Na2O]2 K = [Na]4 / [Na2O]2
The equilibrium expression for the reaction 2Na₂O (s) ⇌ 4Na (l) + O₂ (g) is K = [Na]⁴[O₂].
The equilibrium expression expresses the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. In this case, the balanced chemical equation for the reaction is 2Na₂O (s) ⇌ 4Na (l) + O₂ (g).
The equilibrium constant (K) is defined as the product of the concentrations of the products, each raised to the power of its stoichiometric coefficient, divided by the product of the concentrations of the reactants, each raised to the power of its stoichiometric coefficient. Based on the balanced equation, the equilibrium expression can be written as K = [Na]⁴[O₂].
It is important to note that the concentrations used in the equilibrium expression are always in the units of molarity (mol/L). Also, the equilibrium constant is temperature-dependent, meaning that it can change with changes in temperature, but remains constant at a particular temperature.
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What are foods that contain physical changes
A substance's form or appearance can be changed physically without affecting its chemical makeup.
Cutting fruits and vegetables, melting chocolate, and boiling eggs are examples of foods that go through physical changes.
For instance, slicing fruits and vegetables alter their size and shape, but not their chemical makeup.
Similar to melting chocolate, which transforms it from a solid to a liquid yet keeps its chemical makeup the same.
Physical changes Physical alterations are transformations that modify the physical appearance of matter without altering its chemical content. During the processing or cooking of food, numerous physical changes take place. As an example of a physical alteration, cutting fruits and vegetables modify their size and shape without changing their chemical makeup. Similar to melting, which transforms solid chocolate into liquid without altering its chemical composition. The solidification of melted cheese or the caramelization of sugar are two further instances of physical modifications in food. Food preparation and presentation are significantly influenced by physical changes in the meal.
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For this question, choose THREE answers. Which question should be asked prior to (before) writing the name for H2SO 4 (aq)?
If the H2SO4 formula is understood, the name can be written according to the naming guidelines for acids.
What is the process for making H2SO4?Industrially, sulfuric acid is created when water reacts with sulphur trioxide (see sulphur oxide), which is created chemically by combining oxygen and sulphur dioxide, either through the contact process or the chamber process.
What function does H2SO4 serve in this preparation?In the process of converting ethanol to ethane, H2SO4 serves as a dehydrating agent. It aids in removing water molecule (more particularly , the -OH group from one carbon and -H from the other carbon) in the following reaction: CH3CH2OH.
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The questions that should be asked before writing the name for H₂SO₄ are options 2, 3, and 5.
These questions are relevant because they provide important clues about the compound's naming conventions and help determine the correct name for H₂SO₄. The suffix "-ic" is commonly used for naming the anions of many acids. The suffixes "-ate" and "-ite" are commonly used for naming the anions of many compounds, including acids.
Hydrogen can act as a cation in some compounds, including acids. Recognizing hydrogen's role as a cation helps determine the appropriate naming conventions for the compound.
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Your question is incomplete, most probably the full question is this:
Which question should be asked prior to writing the name for H₂SO₄? Select all that apply.
Does the formula contain a hydrocarbon?Does the anion end in -ic?Does the anion ends in -ate or ite?Does the formula have a polyatomic ion?Does the formula have hydrogen as a cation?a polystyrene molecule has a molar mass of 18,000 g/mol. calculate the number of monomer units (the degree of polymerization) for this molecule.
The polystyrene molecule with a molecular mass of 18,000 g/mol has approximately 173 monomer units.
A polystyrene molecule has a molar mass of 18,000 g/mol.
To calculate the number of monomer units (the degree of polymerization) for this molecule, we need to use the formula for calculating the degree of polymerization:
Degree of polymerization = (Molar mass of polymer) / (Molar mass of monomer)
For polystyrene, the monomer is styrene, which has a molar mass of 104 g/mol.
Using the above formula, we get:
Degree of polymerization = 18,000 g/mol ÷ 104 g/mol= 173.08
Therefore, the number of monomer units (the degree of polymerization) for this polystyrene molecule is approximately 173.
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if the ph of an aqueous solution at 298 k is 4.31, what is the concentration of hydroxide ions in the solution?
If the pH of an aqueous solution at 298 K is 4.31, the concentration of hydroxide ions in the solution is 5.01 x 10^-11 M.
The pH and pOH of a solution are related to the concentration of hydrogen ions (H+) and hydroxide ions (OH-) through the following equations: pH = -log[H+]pOH = -log[OH-]pH + pOH = 14For a neutral solution, [H+] = [OH-], and therefore pH = pOH = 7. For an acidic solution, [H+] > [OH-], and for a basic solution, [H+] < [OH-].To determine the concentration of hydroxide ions in the solution, we can use the relationship between pH and pOH:pH + pOH = 14pOH = 14 - 4.31 = 9.69Now, we can use the equation: pOH = -log[OH-]9.69 = -log[OH-][OH-] = 5.01 x 10^-11 M
Therefore, the concentration of hydroxide ions in the solution is 5.01 x 10^-11 M.
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How many moles of AgCl are produced from .562 moles of NaCl?
Answer: 68.5826%
Explanation:
Need help understanding to solve
Fe₂O3 +2A1→→→→2Fe + Al₂O3
How many grams of Al are needed to completely react with 135 g
Fe₂O3?
How many grams of Al₂O3 can form when 23.6 g Al react with excess
Fe₂O3?
How many grams of Fe₂O3 react with excess Al to make 475 g Fe?
How many grams of Fe will form when 97.6 g Al2O3 form?
Answer:
To solve stoichiometry problems like these, we need to use balanced chemical equations and convert the given quantities into moles using their respective molar masses. Then, we can use the mole ratios from the balanced equation to find the moles of the unknown substance, and convert back to grams if necessary.
Fe₂O3 + 2Al → 2Fe + Al₂O3
How many grams of Al are needed to completely react with 135 g Fe₂O3?
First, we need to find the moles of Fe₂O3 in 135 g:
molar mass of Fe₂O3 = 2(55.85 g/mol) + 3(16.00 g/mol) = 159.70 g/mol
moles of Fe₂O3 = 135 g / 159.70 g/mol = 0.8459 mol
According to the balanced equation, 2 moles of Al react with 1 mole of Fe₂O3:
moles of Al = 2 × moles of Fe₂O3 = 2 × 0.8459 mol = 1.6918 mol
Finally, we can convert the moles of Al to grams using its molar mass:
molar mass of Al = 26.98 g/mol
mass of Al = moles of Al × molar mass of Al = 1.6918 mol × 26.98 g/mol ≈ 45.66 g
Therefore, 45.66 grams of Al are needed to completely react with 135 g Fe₂O3.
How many grams of Al₂O3 can form when 23.6 g Al react with excess Fe₂O3?
First, we need to find the moles of Al in 23.6 g:
moles of Al = 23.6 g / 26.98 g/mol ≈ 0.874 mol
According to the balanced equation, 2 moles of Al react with 1 mole of Al₂O3:
moles of Al₂O3 = 0.5 × moles of Al = 0.5 × 0.874 mol = 0.437 mol
Finally, we can convert the moles of Al₂O3 to grams using its molar mass:
molar mass of Al₂O3 = 101.96 g/mol
mass of Al₂O3 = moles of Al₂O3 × molar mass of Al₂O3 = 0.437 mol × 101.96 g/mol ≈ 44.64 g
Therefore, 44.64 grams of Al₂O3 can form when 23.6 g Al react with excess Fe₂O3.
How many grams of Fe₂O3 react with excess Al to make 475 g Fe?
First, we need to convert the given mass of Fe to moles:
molar mass of Fe = 55.85 g/mol
moles of Fe = 475 g / 55.85 g/mol ≈ 8.504 mol
According to the balanced equation, 2 moles of Al react with 1 mole of Fe:
moles of Al = 0.5 × moles of Fe = 0.5 × 8.504 mol = 4.252 mol
Since Al is in excess, it will not be completely consumed by the reaction. However, we can use the moles of Al to find the moles of Fe₂O3 needed:
moles of Fe₂O3 = 0.5 × moles of Al = 0.5 × 4.252 mol = 2.126 mol
Finally, we can convert
Explanation:
Of the following scientists, identify who was not connected with the development of the atomic theory? 1) Neils Bohr 2) Linas Pauling 3) J. J. Thomson 4) Rutherford 5) Chadwick
Linus pauling
1. In 1913, Niels Bohr proposed a theory for the hydrogen atom, based on quantum theory that some physical quantities only take discrete values. Electrons move around a nucleus, but only in prescribed orbits, and If electrons jump to a lower-energy orbit, the difference is sent out as radiation
3. J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup."
4. Ernest Rutherford found that the atom is mostly empty space, with nearly all of its mass concentrated in a tiny central nucleus. The nucleus is positively charged and surrounded at a great distance by the negatively charged electron
5. In 1932, Chadwick made a fundamental discovery in the domain of nuclear science: he proved the existence of neutrons – elementary particles devoid of any electrical charge.
Linus pauling was the only scientist not related to the development of the atomic theory.
During the 1930s Linus Pauling was among the pioneers who used quantum mechanics to understand and describe chemical bonding–that is, the way atoms join together to form molecules.
based on your calculations, did n-pentane or 1-butanol have a larger δt value? use your understanding of intermolecular forces to explain these results.
Based on the calculations, n-pentane has a larger δt value than 1-butanol.
Intermolecular forces refer to the forces between molecules. In this case, the strength of the intermolecular forces in the two molecules is different, resulting in different δt values. n-pentane is a nonpolar molecule with only van der Waals forces between molecules. These forces are weak compared to the intermolecular forces present in 1-butanol.1-butanol is a polar molecule with intermolecular hydrogen bonds between molecules.
Hydrogen bonds are strong intermolecular forces that increase the boiling point of the molecule. The larger the intermolecular forces, the larger the δt value will be. Since n-pentane only has weak van der Waals forces, it has a smaller δt value than 1-butanol, which has stronger intermolecular hydrogen bonds.
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which of the following would be the least soluble in water? question 5 options: a) ch3ch2ch2nh2 b) ch3ch2ch2ch2nh2 c) ch3ch2ch2ch2ch2ch2nh2 d) ch3nh2 e) ch3ch2nh2
The compound least soluble in water would be Option C, CH3CH2CH2CH2CH2CH2NH2. When an ionic compound is added to water, it splits into cations and anions, which are surrounded by water molecules. When a solute dissolves in a solvent, the solvent's molecules surround the solute's molecules.
The solubility of compounds varies widely depending on their chemical structure. A compound with polar bonds is typically more soluble in polar solvents like water, while a compound with nonpolar bonds is typically more soluble in nonpolar solvents like oil.
Here are the options and their solubility characteristics:
Option A: CH3CH2CH2NH2. This is a primary amine. Primary amines have polar covalent bonds but are less polar than alcohols. They can hydrogen-bond with water, making them moderately soluble in water.Option B: CH3CH2CH2CH2NH2. This is a primary amine with one more carbon than Option A. It is a larger molecule and has a longer nonpolar chain. It is less polar than Option A and less likely to dissolve in water.Option C: CH3CH2CH2CH2CH2CH2NH2. This is a primary amine with six carbons. It is even larger than Option B and less polar. As a result, it is less likely to dissolve in water.Option D: CH3NH2. This is a primary amine with only one carbon. It is polar and has a strong dipole moment, allowing it to dissolve easily in water.Option E: CH3CH2NH2. This is also a primary amine. It has more polar bonds than Option B but fewer than Option A. It is moderately soluble in water.Learn more about solubility: https://brainly.com/question/21717923
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what nacl nacl concentration results when 259 ml 259 ml of a 0.860 m 0.860 m nacl nacl solution is mixed with 552 ml 552 ml of a 0.350 m 0.350 m nacl nacl solution?
When 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution, the concentration of NaCl will be 0.496 M.
What is NaCl?NaCl is the chemical formula for sodium chloride, which is a salt consisting of sodium ions and chloride ions. It is commonly referred to as table salt and is commonly used as a seasoning in cooking and a preservative in food processing.
What is concentration?Concentration refers to the amount of solute that is dissolved in a given amount of solvent or solution. It is generally measured in molarity (M), which is defined as the number of moles of solute per liter of solution. The equation for calculating molarity is as follows:
Molarity (M) = moles of solute / liters of solutionSteps to find out the NaCl concentration:
Given that 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution.
First, find the moles of NaCl in the first solution (259 ml of 0.860 M NaCl).
0.860 M means there are 0.860 moles of NaCl for every liter of solution.
In 259 ml (0.259 L) of this solution, there will be:
moles of NaCl = 0.860 M × 0.259 L = 0.22294 mol NaCl
Next, find the moles of NaCl in the second solution (552 ml of 0.350 M NaCl).
0.350 M means there are 0.350 moles of NaCl for every liter of solution.
In 552 ml (0.552 L) of this solution, there will be:
moles of NaCl = 0.350 M × 0.552 L = 0.1932 mol NaCl
Total moles of NaCl in the final solution = 0.22294 mol + 0.1932 mol = 0.41614 mol NaCl
Finally, calculate the molarity of the final solution (which is the concentration of NaCl):
Molarity = moles of NaCl / liters of solutionThe total volume of the final solution is 259 ml + 552 ml = 811 ml or 0.811 L.
Molarity = 0.41614 mol / 0.811 L = 0.513 M NaCl
Therefore, when 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution, the concentration of NaCl will be 0.496 M.
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What color will a Bunsen burner flame change when a solution containing Sr2+ is added to it? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.a Red b Orange с Yellow d Green
When a solution containing strontium ions ([tex]Sr^{2+}[/tex]) is added to the Bunsen burner flame, it changes the color to red. Therefore, the answer is option A, red.
How does the color of a solution containing ions change in Bunsen flame?A Bunsen burner is a laboratory equipment that produces a single open gas flame, which is used for heating, sterilization, and combustion reactions. A Bunsen burner produces a clean blue flame when it is set to the right mixture of air and gas.
The color of a Bunsen burner flame is determined by the temperature of the flame and the chemicals being burned. The addition of chemicals to a Bunsen burner flame can cause it to change color.
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solution of a monoprotic acid was titrated with NaOH, What is the molar ratio of the acid to the base? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 1:1 b 1:2 с It is impossible to determine from the information given. d :1 2:1
The molar ratio of the acid to the base in this scenario would be 1:1, option a. this is because a monoprotic acid only has one acidic hydrogen ion to donate. hence, on this titration, the stoichiometric ratio of acid to base is 1:1.
while an acid is dissolved in water, it simplest has one acidic hydrogen ion to offer, making it a monoprotic acid. This shows that one mole of the acid can give one mole of H+ ions to a base or any other species. Acetic acid, nitric acid, and hydrochloric acid are some examples of monoprotic acids (CH3COOH). because of their ability to offer actual manage over the amount of acid or base injected, these acids are frequently utilized in an expansion of chemical reactions, along with acid-base titrations. The dissociation constant, Ka, which measures the acid's electricity, can be used to give an explanation for how a monoprotic acid behaves in answer.
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4.1 moles of ammonia (NH3) is formed in the following reaction. How many grams of hydrogen reacted?
3H2 + N2 --> 2NH3
The mass of hydrogen reacted with 4.1 moles of ammonia ([tex]NH_3[/tex]) is 24.6g in the given reaction.
Given the number of moles of ammonia ([tex]NH_3[/tex]) = 4.1
The reaction is as follows: [tex]3H_2 + N_2 -- > 2NH_3[/tex]
From the equation we can see that for 3 moles of hydrogen ([tex]H_2[/tex]) 2 moles of ammonia ([tex]NH_3[/tex]) is produced.
mass of hydrogen reacted = number of moles x molar mass of [tex]H_2[/tex]
mass of hydrogen reacted = 3 * 2 = 6g
mass of [tex]NH_3[/tex] used up = moles x molar of [tex]NH_3[/tex]
mass of ammonia = 2 * 17 = 34g
So for 6g of [tex]H_2[/tex], 34g of ammonia ([tex]NH_3[/tex]) is used.
mass of ammonia reacted with 4.1moles = 4.1 * 34 = 139.4g
Then for 139.4g of [tex]NH_3[/tex] amount of hydrogen needed = 139.4 * 6/34 = 24.6g
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how many atoms are there in 58.7 g of nickel? group of answer choices 1 none of these 6.02 x 1023 28 1.204 x 1024
There are approximately 6.02 x 10²³ atoms in 58.7 g of nickel.
The molar mass of nickel (Ni) is 58.69 g/mol.
Using the formula:
number of moles = mass / molar mass
we can calculate the number of moles of nickel in 58.7 g:
number of moles = 58.7 g / 58.69 g/mol
number of moles = 1.0006 mol
Since one mole of any substance contains Avogadro's number of atoms (6.022 x 10²³), we can calculate the number of atoms of nickel in 1.0006 mol:
number of atoms = 1.0006 mol x 6.022 x 10²³ atoms/mol
number of atoms = 6.025 x 10²³ atoms
Therefore, there are approximately 6.025 x 10²³ atoms in 58.7 g of nickel
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What is the formula mass for copper (II) sulfate pentahydrate?
Answer:249.68 g/mol
Explanation:
Which one of the following is a strong electrolyte?A Carbon disulfideB Ammonium hydroxideC Sodium chlorideD Water
Sodium chloride is the strongest electrolyte among the following examples. Hence, option C is correct.
Generally, strong electrolytes are defined as those electrolytes which completely ionizes into an aqueous solution.
Generally, strong acids and strong bases are considered to be strong electrolytes. Basically, sodium chloride (NaCl) is a salt which is formed from HCl, a strong acid, and a strong base, Sodium hydroxide (NaOH). Since it completely ionizes into Sodium ion (Na⁺) and Cl⁻ ion in solution, it is generally considered to be a strong electrolyte.
NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq)
Hence, sodium chloride is strongest base. Option C is correct.
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describe how the fuel cell obeys the law of conservation of mass
A fuel cell is an electrochemical device that converts chemical energy from a fuel (such as hydrogen) and an oxidizing agent (such as oxygen) into electrical energy, water, and heat.
What is Fuel?
Fuel is a material that is burned or processed to release energy in the form of heat or to produce work. Common examples of fuel include coal, natural gas, gasoline, diesel, and wood. The energy contained within the fuel is released through a chemical reaction, usually with oxygen, to produce heat, light, or other forms of energy. Fuel is used to power a wide range of machinery and devices, including vehicles, power plants, and heating systems.
The reactants (fuel and oxidizing agent) are supplied to the cell, where they undergo a chemical reaction in the presence of a catalyst, producing electricity and the byproduct water.
According to the law of conservation of mass, mass cannot be created or destroyed in a chemical reaction. In the case of a fuel cell, the mass of the reactants (fuel and oxidizing agent) is equal to the mass of the products (water) plus the mass of the electricity produced
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