What is the area of a regular hexagon with side length of 12. 7 and apothem length of 11?


PLEASE HELP!

Answer: Therefore, the tip of the pendulum rotated through an angle of approximately 0.31 radians.

Step-by-step explanation:

The length of the arc traveled by the tip of the pendulum is 8 centimeters, and the radius of the pendulum is 26 centimeters. We can use the formula for the length of an arc of a circle to find the radian angle rotated through:

Length of arc = radius * angle in radians

Solving for the angle in radians, we get:

Angle in radians = Length of arc / radius

Plugging in the given values, we get:

Angle in radians = 8 / 26

Simplifying this expression, we get:

Angle in radians = 0.30769...

Rounding this value to the nearest hundredth, we get:

Angle in radians = 0.31

Therefore, the tip of the pendulum rotated through an angle of approximately 0.31 radians.

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2)By using Comparison Test,the series 23-1 5k-1 k=1,is divergent.

3)By using Integral Test the series Ink k k=1 is divergent.

2) To determine the convergence or divergence of the series 23-1 5k - 1 k=1:

For the first series, 23-1 5k-1 k=1, we can use the Limit Comparison Test.

Let's compare it to the series 5k-1 k=1.

We take the limit as k approaches infinity of the ratio of the two series:
lim(k->∞) [(23-1 5k-1) / (5k-1)] = lim(k->∞) [23 / 5] = 23/5
Since this limit is finite and positive, and the series 5k-1 diverges (as it is a p-series with p=1),

we can conclude that the given series also diverges.

3)To determine the convergence or divergence of the series Ink k k=1:
For the second series, Ink k=1, we can use the Integral Test.

We need to check if the following improper integral converges or diverges:
∫(1 to ∞) ln(x) dx
Integrating by parts, we get:
∫(1 to ∞) ln(x) dx = [xln(x) - x]1∞ + ∫(1 to ∞) dx/x
The first term evaluates to -∞, and the second term is the divergent harmonic series.

Therefore, the improper integral and the series both diverge.

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The width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

To solve the problem, we can draw a diagram and use the properties of ellipses.

First, we note that the major axis of the ellipse is 110 yards and the minor axis is 50 yards. We can find the distance between the two foci of the ellipse using the formula c^2 = a^2 - b^2, where c is the distance between the foci, and a and b are the lengths of the semi-major and semi-minor axes.

c^2 = 110^2 - 50^2

c^2 = 10800

c ≈ 104.0

Next, we draw the two foci of the ellipse and the rectangle as shown in the diagram below. We are given that the width of the rectangle is 30 yards (15 yards from either vertex). x be the length of the rectangle.

      A          B

   +-------+-------+

  /                  \

 /                    \

/                      \

C                        D

\                      /

 \                    /

  \                  /

   +-------+-------+

      E          F

We can see that the length of the rectangle is equal to the distance between points A and B, and the width of the rectangle is equal to the distance between points C and D. Using the Pythagorean theorem, we can find the length of the rectangle.

AB^2 = AE^2 + EB^2

AB^2 = (a/2)^2 + (c - b/2)^2

AB^2 = (55)^2 + (104 - 15)^2

AB^2 = 3025 + 7225

AB = sqrt(10250)

AB ≈ 101.2

Therefore, the length of the rectangle is approximately 101.2 yards.

To find the width of the rectangle, we can use the fact that the distance between points C and D is equal to twice the distance between the center of the ellipse and the minor axis. The center of the ellipse is the midpoint of the major axis, and the distance from the center to the minor axis is 25 yards.

CD = 2 * 25 = 50

Therefore, the width of the rectangle is approximately 50 yards.

In summary, the width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

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a) Parametrization for the curve of intersection of 9y2 + z2 = 1 and xyz = 1 is:
x = 1/(z(sqrt((1 - z^2)/9)))
y = ±sqrt((1 - z^2)/9)
z = t

b)Parametrization for the curve of intersection of  x=y_and x2 - y2 =z is

x = t
y = t
z = 0
c)Parametrization for the curve of intersection of  x2 + y2 + z = is

x = r cos(t)
y = r sin(t)
z = 1 - r

a) To find the curve of intersection of the two surfaces [tex]9y^2 + z^2 = 1[/tex] and xyz = 1:

We can solve for one variable in terms of the others.

For example, we can solve for y in terms of z and x using the first equation:
[tex]9y^2 + z^2 = 1[/tex]
[tex]9y^2 = 1 - z^2[/tex]
[tex]y^2 = (1 - z^2)/9[/tex]
y = ±sqrt([tex](1 - z^2)/9)[/tex]
Substituting this into the second equation, we get:
x(sqrt((1 - [tex]z^2)/9))z = 1[/tex]
x = 1/(z(sqrt((1 - [tex]z^2)/9)))[/tex]
So, a parametrization for the curve of intersection is:
x = 1/(z(sqrt((1 - [tex]z^2)/9)))[/tex]
y = ±sqrt((1 - z^2)/9)
z = t
This is defined for all t except at z = ±1.
b) To find the curve of intersection of the two surfaces x = y and [tex]x^2 - y^2 = z:[/tex]

We can substitute x = y into the second equation:
[tex]x^2 - y^2 = z[/tex]
[tex]y^2 - y^2 = z[/tex]
z = 0
So the curve of intersection is just the x = y line.

A parametrization for this line is:
x = t
y = t
z = 0
c) To find a parametrization for the surface [tex]x^2 + y^2 + z = 1:[/tex]

We can use cylindrical coordinates:
x = r cos(t)
y = r sin(t)
z = 1 - r
where 0 ≤ r ≤ 1 and 0 ≤ t < 2π.

This parameterization covers the surface of a unit cylinder with its top and bottom caps removed.

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Using the nth-term test for divergence on the series ∑ 1/n+13 is inconclusive. However, by comparing the series to the divergent harmonic series, we can conclude that ∑ 1/n+13 is also divergent.

We can use the nth-term test for divergence to determine the convergence or divergence of the series

lim n → ∞ (1/n+13) = 0

Since the limit of the nth term is 0, the nth-term test is inconclusive, and we cannot determine the convergence or divergence of the series using this test.

However, we can use the comparison test to show that the series diverges. We can compare the given series to the harmonic series, which we know diverges

1/1 + 1/2 + 1/3 + ...

Since each term of the given series is less than the corresponding term of the harmonic series, the given series must also diverge. Therefore, the series ∑ 1/n+13 is divergent.

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At least 95% of the observed values are expected to lie between mu minus 2 sigma and mu plus 2 sigma.

This is because of the empirical rule, also known as the 68-95-99.7 rule, which states that in a normal distribution, approximately 68% of the observations will fall within one standard deviation of the mean, about 95% of the observations will fall within two standard deviations of the mean, and around 99.7% of the observations will fall within three standard deviations of the mean.

In this case, we are given that x has mean mu and standard deviation sigma. Therefore, about 95% of the values of x are expected to lie between mu minus 2 sigma and mu plus 2 sigma, as this interval covers two standard deviations on either side of the mean.

Mathematically, we can express this as:

P(mu - 2sigma < x < mu + 2sigma) ≈ 0.95

where P is the probability that x falls within the interval mu - 2sigma to mu + 2sigma.

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As per the given information in the question, we can compute that the correct option is C) 11.

According to the question:

[tex]f(x)=x^{2} -6x-4[/tex]

[tex]g(x)=5x+3[/tex]

Therefore,

[tex](f+g)(x)= f(x)+g(x) \\

          =x^{2} -6x-4+5x+3 \\

          =x^2-x-1[/tex]

Now, to find (f+g)(-3):

substituting x=-3 in the above equation

we get,

[tex](f+g)(-3)= (-3)^2-(-3)-1 \\

                         = 9+3-1 \\

                         =11[/tex]

Hence  (f+g)(-3)=11

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Declan swims faster than Madison, with a speed of 7/2 miles per hour compared to Madison's speed of 2/5 miles per hour.

Declan swims faster than Madison. While Madison swims 2/5 mile in an hour, which means her speed is 2/5 miles per hour, Declan swims 7/10 mile in 1/5 hour, which means his speed is 7/2 miles per hour. This indicates that Declan's speed is greater than Madison's speed.

In fact, we can see that Declan's speed is almost 4 times faster than Madison's speed. This means that Declan can cover a greater distance in the same amount of time compared to Madison.

Therefore, based on the given information, we can confidently say that Declan swims faster than Madison.

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Answer:

Step-by-step explanation:

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The size of the student body is approximately 1440 students.

To determine the size of the student body, we'll use the given information that 936 students represent 65% of the total number of students. We can set up a proportion to solve for the unknown total (let's call it "x"):

(65% of x) = 936

To express the percentage as a decimal, divide 65 by 100, which equals 0.65:

0.65 * x = 936

Next, to find the value of x, divide both sides of the equation by 0.65:

x = 936 / 0.65

x ≈ 1440

So, the size of the student body is approximately 1440 students. In this problem, we used the concept of percentage to find out the total number of students in the student body, knowing that 936 students (65%) attended the football game.

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The ranking from worst to best is Portfolio 3, Portfolio 2, and Portfolio 1. So, correct option is B.

To calculate the weighted mean of the RORs for each portfolio, we need to first multiply each ROR by the corresponding portfolio value and then sum the products for each portfolio. We then divide the total by the sum of the portfolio values.

The weighted mean for Portfolio 1 = [(10.4% x $700) + (-29.7% x $12,000) + (37.2% x $600) + (7.5% x $4,400) + (6.3% x $250)] / ($700 + $12,000 + $600 + $4,400 + $250) = -16.8%

Similarly, the weighted mean for Portfolio 2 = 3.8% and for Portfolio 3 = 11.2%.

Based on the results, the list that shows a comparison of the overall performance of the portfolios from worst to best is option b) Portfolio 3, Portfolio 2, Portfolio 1. Portfolio 3 has the highest weighted mean return of 11.2%, followed by Portfolio 2 with a return of 3.8%, and Portfolio 1 has the lowest weighted mean return of -16.8%.

Therefore, correct option is B.

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Complete question is:

ROR     Portfolio 1     Portfolio 2     Portfolio 3

10.4%        $700              $6,000         $3,500

-29.7%    $12,000           $9,000         $5,500

37.2%        $600              $4,500         $5,750

7.5%          $4,400            $2,000        $1,500

6.3%          $250                $1,100          $4,500

Calculate the weighted mean of the RORs for each portfolio. Based on the results, which list shows a comparison of the overall performance of the portfolios, from worst to best?

a) Portfolio 3, Portfolio 1, Portfolio 2

b) Portfolio 3, Portfolio 2, Portfolio 1

c) Portfolio 1, Portfolio 2, Portfolio 3

d) Portfolio 1, Portfolio 3, Portfolio 2

Following shows (sin 7x)/sin x = 64(cos x)^6 - 80(cos x)^4 +24(cos x)^2 - 1:

12sin^3 x - 8sin^

To show that (sin 7x)/sin x is equal to 64(cos x)^6 - 80(cos x)^4 + 24(cos x)^2 - 1, we can use trigonometric identities and algebraic manipulation.

Let's start with the left-hand side of the equation:

(sin 7x)/sin x

Using the trigonometric identity for sin(A + B):

sin(A + B) = sin A cos B + cos A sin B

We can rewrite sin 7x as sin (6x + x):

sin (6x + x) = sin 6x cos x + cos 6x sin x

Now we can substitute sin 7x with sin 6x cos x + cos 6x sin x:

(sin 6x cos x + cos 6x sin x)/sin x

Next, we can simplify this expression by dividing both terms by sin x:

(sin 6x cos x)/sin x + (cos 6x sin x)/sin x

The sin x term cancels out, leaving us with:

sin 6x cos x + cos 6x

Now, we can use the double-angle identity for sin 2A:

sin 2A = 2sin A cos A

To rewrite sin 6x cos x, we can treat it as sin 2A with A = 3x:

sin 6x cos x = 2sin 3x cos 3x

Next, we can use the triple-angle identity for sin 3A:

sin 3A = 3sin A - 4sin^3 A

To rewrite sin 3x, we can treat it as sin A with A = x:

sin 3x = 3sin x - 4sin^3 x

Substituting this into our expression:

2sin 3x cos 3x = 2(3sin x - 4sin^3 x) cos 3x

Expanding further:

= 6sin x cos 3x - 8sin^3 x cos 3x

Now, we can use the double-angle identity for cos 2A:

cos 2A = cos^2 A - sin^2 A

To rewrite cos 3x, we can treat it as cos A with A = x:

cos 3x = cos^2 x - sin^2 x

Substituting this into our expression:

6sin x cos 3x - 8sin^3 x cos 3x = 6sin x (cos^2 x - sin^2 x) - 8sin^3 x (cos^2 x - sin^2 x)

Expanding further:

= 6sin x cos^2 x - 6sin x sin^2 x - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

Now, we can use the Pythagorean identity for sin^2 x + cos^2 x:

sin^2 x + cos^2 x = 1

To rewrite sin^2 x, we can subtract cos^2 x from both sides:

sin^2 x = 1 - cos^2 x

Substituting this back into our expression:

= 6sin x (cos^2 x - (1 - sin^2 x)) - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

= 6sin x (2sin^2 x) - 8sin^3 x cos^2 x + 8sin^3 x sin^2 x

= 12sin^3 x - 8sin^

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Let's break down the information given in the problem:

- Jane became a real estate agent in 1990.

- She sold a house 8 years later (in 1998) for $144,000.

- She sold the same house 11 years after that sale (in 2009), which is 19 years after she became an agent, for $245,000.

To write an equation that represents the value of the house (V) related to the number of years (t) since Jane became a real estate agent, we can use the information from the two sales to find the rate of change in the value of the house over time. We can use this rate of change to write an equation in point-slope form:

V - V1 = m(t - t1)

where V1 is the value of the house at time t1, m is the rate of change in the value of the house, and t is the time since Jane became a real estate agent.

Using the two sales, we can find the rate of change in the value of the house as follows:

m = (V2 - V1) / (t2 - t1)

where V2 is the value of the house at the second sale, t2 is the time of the second sale (19 years after Jane became an agent), V1 is the value of the house at the first sale, and t1 is the time of the first sale (8 years after Jane became an agent).

Substituting the given values, we get:

m = ($245,000 - $144,000) / (19 - 8) = $10,100 per year

Now we can use the point-slope form equation to find the value of the house at any time t since Jane became a real estate agent. Let's choose 1990 as our initial time (t1), so V1 = $0:

V - 0 = $10,100 (t - 0)

Simplifying, we get:

V = $10,100t

Therefore, the equation that represents the value of the house (V) related to the number of years (t) since Jane became a real estate agent is V = $10,100t. Note that this equation assumes a constant rate of change in the value of the house over time, which may not be accurate in real life.

The statement "limit as x goes to infinity of the quotient of f of x and g of x equals 5" means that as x gets larger and larger, the ratio of f(x) to g(x) approaches 5.

If f(x) grows faster than g(x) as x goes to infinity, then the ratio of f(x) to g(x) would approach infinity, not 5.

If f(x) and g(x) grow at the same rate as x goes to infinity, then the ratio of f(x) to g(x) would approach a constant value, not necessarily 5.

Therefore, the statement "limit as x goes to infinity of the quotient of f of x and g of x equals 5" shows that g(x) grows faster than f(x) as x goes to infinity. L'Hôpital's Rule is not necessary to determine this conclusion.

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Answer:

ben earns $9 per hour and $6 for each delivery he makes

Step-by-step explanation:

1) Bona can drive 108 miles if she drove for 3 hour at the same speed as Claire.

2) Janet would take 1.5 hour to complete the journey and Andrew spend half hour more driving than Janet.

1) Bona speed is 44mph

Time taken by Bona is 3 hour

distance travelled by Claire is 144 miles

Time taken by Claire is 4 hour

Claire's speed = distance / time

Claire's speed = 144/4

Claire's speed = 36 mph

Distance travelled by Bona = speed × time

Distance travelled by Bona = 36 × 3

Distance travelled by Bona = 108 miles

2) Janet distance = 60 miles

Janet speed = 40 mph

Time taken by Janet = distance / speed

Time taken by Janet = 60/40

Time taken by Janet = 1.5 hour

Janet would take 1.5 hour to complete the journey

Andrew distance = 80 miles

Andrew speed = 40 mph

Time taken by Andrew = distance / speed

Time taken by Andrew = 80/40

Time taken by Andrew= 2 hour

Andrew spend half hour more driving than Janet.

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Answer:

Step-by-step explanation:

The arc length formula is

[tex]L=\frac{\theta}{360}*2\pi r[/tex]

Theta is the angle that intersects arc HJ. That measure is 180-122 which is 58 degrees. We put that into the formula along with the radius measure of 10 to get:

[tex]L=\frac{58}{360}*2\pi (10)[/tex] which gives us, rounded to the nearest hundredth,

L = 10.12 units

Answer:

Step-by-step explanation:

The value of x is 19 if the lines l and m are parallel.

The lines l and m are parallel

The corresponding angles are equal

We have to find the value of x

6x-9 = 5x+10

Let us take all the variable terms on one side

6x-5x=10+9

x=19

Hence, the value of x is 19 if the lines l and m are parallel.

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The probability of the mouse finding its way out before reaching a dead end or going out in the opening can be estimated by dividing the number of successful outcomes by the total number of trials in the sample.

To create a simulation to determine the probability that the mouse will find its way out before coming to a dead end or going out in the opening, we can follow these steps:

The probability of the mouse finding its way out before reaching a dead end or going out in the opening can be estimated by dividing the number of successful outcomes by the total number of trials in the sample. This simulation approach can help us understand the probability of success in a random maze environment, and also explore the impact of various factors such as maze complexity, size and starting position of the mouse on the outcome.

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If 3 quarts is greater than 4prints, then the measure is not equivalent.

Equivalent units can be used to convert different units to the same unit for comparison. Equivalent means equal. For example , 1 kilogram is equal to 1,000 grams.

For example,

3 teaspoons = 1 tablespoon.

4 tablespoons = 1/4 cup.

5 tablespoons + 1 teaspoon = 1/3 cup.

8 tablespoons = 1/2 cup.

1 quart = 2pints

therefore 3 quarts = 2×3 = 6pints

therefore the statement that 3 quarter is greater than 4 prints is true and not an equivalent measure.

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The closest answer choice is  [tex]27.52 units^2.[/tex]

The area of the circle, we need to find the area of one sector and then multiply it by 16 since there are 16 congruent sectors.

To find the area of one sector, we use the formula:

[tex]Area of sector = (angle/360) * \pi*r^2[/tex]

Since we know the base and height of the highlighted sector, we can use the Pythagorean theorem to find the radius of the circle:

[tex]r^2 = (1.56/2)^2 + (3.92)^2[/tex]

r ≈ 3.969 units

Now we can find the angle of one sector using the formula:

angle = (base/radius) x 180/π

angle ≈ 22.5 degrees

Plugging in the values for angle and radius in the area of sector formula, we get:

[tex]Area of sector =(22.5/360) *\pi (3.969)^2[/tex]

Area of sector ≈ 0.491π

Multiplying this by 16, we get the approximate area of the circle:

Approximate area of circle ≈ 16 x 0.491π

Approximate area of circle ≈ 7.8π

Using a calculator to approximate π as 3.14, we get:

Approximate area of circle ≈ [tex]24.46 units^2[/tex]

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If we are drawing without replacement, the probability is approximately 27.7%, which is closest to option B: 27%.

The probability of drawing a yellow marble on the next draw depends on whether we are drawing with or without replacement.

If we are drawing without replacement, then the probability of drawing a yellow marble is 13 out of the remaining 47 marbles, since we have already drawn 35 white marbles and 13 yellow marbles out of the 48 total marbles.

If we are drawing with replacement, then the probability of drawing a yellow marble on the next draw is still 1/3, or approximately 33.3%.

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So basically you have to drag an angle to the box, example drag DFA to the box, then add what angle it is equal to. You have to calculate the angle and drag it opposite to the DFA. For DFA, it will be 58.

the price per foot of the copper wire is $1.62.

What is the arithmetic operation?

The basic mathematical operations are addition, subtraction, multiplication, and division, which involve manipulating two or more quantities. They are essential to the study of numbers, including the order of operations, and are fundamental to other mathematical areas such as algebra, data management, and geometry. Understanding the rules of arithmetic operations is crucial for solving problems that involve these operations.

There are 3 feet in one yard, so 2 yards of copper wire is equal to 6 feet.

To find the price per foot, we need to divide the total price by the number of feet:

Price per foot = Total price ÷ Number of feet

Price per foot = $9.72 ÷ 6

Price per foot = $1.62

Therefore, the price per foot of the copper wire is $1.62.

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The required equation for the length of the candle is L = 9-0.75t.

Given that a 9-inch candle burns at the rate of 0.75 in per hour we need to determine the equation for the length L of the candle when it burns for t hours,

So, if the candle is burning at the rate of 0.75 in per hour so after burning for t hour the length decreases by 0.75t, from the original length i.e 9 in

So, we can write the equation as =

L = 9-0.75t

Hence the required equation for the length of the candle is L = 9-0.75t.

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o find the coordinates of the gates in the third quadrant, we need to find the points where the circle and the line intersect in the third quadrant.

Substituting y = 2x into x² + y² - 4x = 9, we get:

x² + (2x)² - 4x = 9

5x² - 4x - 9 = 0

Using the quadratic formula, we find:

x = (-(-4) ± √((-4)² - 4(5)(-9))) / (2(5))

x = (4 ± √136) / 10

We can discard the positive root since it is in the first quadrant. The negative root corresponds to the x-coordinate of the point of intersection in the third quadrant:

x = (4 - √136) / 10 ≈ -0.433

Substituting this value into y = 2x, we get:

y = 2(-0.433) ≈ -0.866

Therefore, the ordered pair that represents the location of the gates in the third quadrant is (-0.433, -0.866).

The value of the angle of the arc FE⏜ is calculated as: 20°

The angle of an arc is identified by its two endpoints. The measure of an arc angle is found by dividing the arc length by the circle's circumference, then multiplying by 360 degrees. Formulas for calculating arcs and angles vary based on where they are in reference to the circle.

Now, from the given image, we see that:

FGC⏜ = 220°

∠B = 30°

∠OEC = ∠OCE = 30°

CDE⏜ = 220°

Thus:

FE⏜ = 360° - 220° - 120°

FE⏜ = 20°

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If there were four girls and four boys to choose from, the new sample size is one that will be a total of 16 possible combinations.

When making selections for the student council's representatives, the sample size belongs to the whole of the feasible options.

To know the sample size, we must reason every conceivable permutation involving a single female and a single male.

So, if there were four girls and four boys to choose from, the new sample size would be:

There are:

4 choices for girls

4 choices for boys.

So, for each girl's choice, there would be 4 corresponding choices for boys.

Hence it will be:

4 x  4 = 16

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0.135 or 13.5%  is the probability that he had 3 âhits

The probability that the player had 3 hits in 5 at-bats can be calculated using the binomial probability formula, which is:

P(x) = (nCx) * p^x * (1-p)^(n-x)

where:
- P(x) is the probability of getting x hits
- n is the number of at-bats (in this case, 5)
- x is the number of hits we want to find the probability for (in this case, 3)
- p is the probability of getting a hit in one at-bat (in this case, 0.343)
- (1-p) is the probability of not getting a hit in one at-bat (in this case, 0.657)

Plugging in the values, we get:

P(3) = (5C3) * 0.343^3 * 0.657^(5-3)
P(3) = (10) * 0.039304527 * 0.4305961
P(3) = 0.134912947

Therefore, the probability that the player had 3 hits in 5 at-bats is approximately 0.135 or 13.5%.

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To find the center of the circle, we need to find the midpoint of the diameter segment CD.

Using the midpoint formula, we can find the coordinates of the midpoint M:

Midpoint formula:

M = ( (x1 + x2)/2 , (y1 + y2)/2 )

Plugging in the coordinates of C (-3,5) and D (6,-2):

M = ( (-3 + 6)/2 , (5 - 2)/2 )

M = (1.5, 1.5)

Therefore, the center of the circle is at point M with coordinates (1.5, 1.5).

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