What is the approximate distance between the points (–9, –9) and (1, 3)?

To test the claim that the outcomes of rolling the modified die are not equally likely, we can use a chi-square goodness-of-fit test. We will use a significance level of 0.05.

The null hypothesis is that the outcomes are equally likely. The alternative hypothesis is that the outcomes are not equally likely.

First, we need to calculate the expected frequencies assuming that the outcomes are equally likely.

Since the die has six sides, each outcome has a probability of 1/6. Therefore, the expected frequency for each outcome is 200/6 = 33.33.

To calculate the test statistic [tex]x^2[/tex], we can use the formula:

[tex]x^2 = Σ (observed frequency - expected frequency)^2 / expected frequency[/tex]

where Σ is the sum over all outcomes.

Using the observed and expected frequencies given in the problem, we get:

[tex]x^2 = (27 - 33.33)^2 / 33.33 + (31 - 33.33)^2 / 33.33 + (42 - 33.33)^2 / 33.33 + (40 - 33.33)^2 / 33.33 + (28 - 33.33)^2 / 33.33 + (32 - 33.33)^2 / 33.33[/tex]

[tex]x^2 = 3.02[/tex]

The degrees of freedom for this test is 6 - 1 = 5 (since there are 6 sides on the die).

Using a chi-square distribution table (or calculator), we can find the critical value for a significance level of 0.05 and 5 degrees of freedom to be 11.070.

Since the test statistic x^2 = 3.02 is less than the critical value of 11.070, we fail to reject the null hypothesis.

Therefore, we do not have enough evidence to conclude that the outcomes of rolling the modified die are not equally likely.

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Answer:

Add the lengths:

5x - 16 + 2x - 4 = 7x - 20

The length of AC in triangle ABC is 24 inches.

In triangle ABC, let point D be on side AC such that AB = BD = DC = 12 inches. We are given that the measure of angle BDC is twice the measure of angle ABD.

To find the length of AC, we can use the Law of Cosines. This law relates the lengths of the sides of a triangle to the cosine of one of its angles. In this case, we can apply the Law of Cosines to triangle ABD to find the length of AD:

AD^2 = AB^2 + BD^2 - 2 * AB * BD * cos(ABD)

Since AB = BD = 12 inches, we have:

AD^2 = 12^2 + 12^2 - 2 * 12 * 12 * cos(ABD)

AD^2 = 288 - 288 * cos(ABD)

Now, let's consider triangle BDC. We are given that the measure of angle BDC is twice the measure of angle ABD. Let's denote the measure of angle ABD as x. Therefore, the measure of angle BDC is 2x.

Since the sum of angles in a triangle is 180 degrees, we can write:

x + 2x + angle BCD = 180

3x + angle BCD = 180

angle BCD = 180 - 3x

Now, let's apply the Law of Cosines to triangle BDC to find the length of BC:

BC^2 = BD^2 + CD^2 - 2 * BD * CD * cos(BDC)

BC^2 = 12^2 + 12^2 - 2 * 12 * 12 * cos(2x)

BC^2 = 288 - 288 * cos(2x)

Since AD = DC, we have AD = 12 inches. Now we can write the equation for the total length AC:

AC = AD + DC

AC = 12 + 12

AC = 24 inches

Therefore, the length of AC in triangle ABC is 24 inches.

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In the proportion,  the cost of 0.7kg apple is Rs.62.65 .

What is proportion?

A percentage is created when two ratios are equal to one another. We write proportions to construct equivalent ratios and to resolve unclear values. a comparison of two integers and their proportions. According to the law of proportion, two sets of given numbers are said to be directly proportional to one another if they grow or shrink in the same ratio.

Here cost of 1kg apples = 89.50

Then cost of 0.7 kg apple = x.

Now using proportion,

=> 1   = 89.50

   0.7=  x

=> x = [tex]\frac{89.50\times0.7}{1}[/tex]

=> x = 62.65.

Hence the cost of 0.7kg apple is Rs.62.65 .

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Using area formula for rectangles, we can find the new area of the rectangle to be 7350m².

The new dimensions are:

Length = 105m

Breadth = 70m

A rectangle is a quadrilateral with parallel opposite sides and equal angles. There are a lot of rectangular objects all around us. Each rectangle's two defining characteristics are its length and breadth. A rectangle's longer and shorter sides are its width and length, respectively.

Here in the question,

Dimensions of the rectangle are as follows:

Length, l = 42m.

Width, w = 28m.

Scale factor here is 1: 5/2

Now,

Let the new width be x.

The new width will be:

28/x = 1/ (5/2)

Cross multiplying:

⇒ 28 × 5/2 = x

⇒ x = 70m.

So, new width = 70m.

Now, let new length be x.

So,

42/x = 1/ (5/2)

Cross multiplying:

⇒ x = 42 × 5/2

⇒ x = 105m.

So, the new length = 105m.

Now new area will be:

70 × 105

= 7350m².

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The correct answer is option (d) (x, y) → (x + 1/3, y + 1/3).

The dilation is a type of transformation that changes the size of the object, but not the shape. It can be represented by a rule in which each point of the original object is multiplied or divided by a constant factor. In this case, since the center of dilation is the origin, we can find the constant factor by dividing the coordinates of the corresponding points of the two rectangles.

Let's take the point Q(x, y) in rectangle QRST and its corresponding point Q'(x', y') in rectangle Q'R'S'T'. Since the dilation is centered at the origin, we have:

x' = k * x

y' = k * y

where k is the constant factor of dilation. We can find k by dividing the corresponding sides of the rectangles. For example, the length of QR is 4 units, and the length of Q'R' is 4/3 units. Therefore, k = 4/3.

Using this value of k, we can find the coordinates of any point in rectangle QRST that corresponds to a point in rectangle Q'R'S'T'. For example, point R(6, 2) in rectangle QRST corresponds to point R'(6 + 1/3, 2 + 1/3) = (20/3, 7/3) in rectangle Q'R'S'T'.

Hence, the correct answer is (x, y) → (x + 1/3, y + 1/3).

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Answer:

The total area of the "t" figure is 20 square units.

The figure is made up of a triangle, a square, and a rectangle.

The area of the triangle is (1/2)(base)(height) = (1/2)(4)(3) = 6 square units.

The area of the square is 4^2 = 16 square units.

The area of the rectangle is 2(4)(3) = 24 square units.

The total area of the figure is 6 + 16 + 24 = 46 square units.

However, the question asks for the area of the composite region, which is the shaded region in the figure. The shaded region is a triangle with base 4 units and height 3 units. The area of this triangle is (1/2)(base)(height) = (1/2)(4)(3) = 6 square units.

Therefore, the area of the composite region is 6 square units.

Here is a diagram of the figure with the areas of each shape labeled:

[Image of the "t" figure with the areas of each shape labeled]

Answer:

Step-by-step explanation:

I don't have enough information to answer this.

Answer:

3. 254.34 mm^2

4. 615.44 cm^2

5. 314 in^2

6. 7.065 in^2

7. 3.14 cm^2

8. 1.76625 ft^2

Step-by-step explanation:

AREA FORMULA: π * r^2

This question is asking to use 3.14 or 22/7 for x.

The following steps will use 3.14.

3. r = 9 mm (r^2 = 81 mm)

A = 81 * 3.14 = 254.34 mm^2

4. r = 14 cm (r^2 = 196 cm)

A = 196 * 3.14 = 615.44 cm^2

5. r = 10 in (r^2 = 100 in)

A = 100 * 3.14 = 314 in^2

Questions 6-8 show the diameter of the circle.

Divide by 2 to find the radius, then plug that into the area formula

6. r = 1.5 in (r^2 = 2.25 in)

A = 2.25 * 3.14 = 7.065 in^2

7. r = 1 cm (r^2 = 1 cm)

A = 1 * 3.14 = 3.14 cm^2

8. r = 0.75 ft (r^2 = 0.5625 ft)

A = 0.5625 * 3.14 = 1.76625 ft^2

The center of mass of the metal plate with density rho(x,y) = αx+ βy g/cm2 must lie on the line x + y = 7/6.

To find the center of mass of the metal plate, we need to calculate the coordinates of its centroid (X, Y). The coordinates of the centroid are given by:

X = (1/M) ∬(R) x ρ(x,y) dA, Y = (1/M) ∬(R) y ρ(x,y) dA

where M is the total mass of the plate, R is the region of integration (0 ≤ x ≤ 1, 0 ≤ y ≤ 1), and dA is the differential area element.

We can calculate the total mass M of the plate as follows:

M = ∬(R) ρ(x,y) dA = α/2 + β/2 = (α + β)/2

Using the given density function, we can calculate the integrals for X and Y:

X = (1/M) ∬(R) x ρ(x,y) dA = (2/αβ) ∬(R) x(αx+βy) dA = (2/3)(α+β)

Y = (1/M) ∬(R) y ρ(x,y) dA = (2/αβ) ∬(R) y(αx+βy) dA = (2/3)(α+β)

Thus, the coordinates of the centroid are (X, Y) = ((2/3)(α+β), (2/3)(α+β)).

Now, if we substitute X + Y = (4/3)(α+β) into the equation x + y = 7/6, we get:

x + y = 7/6

2x + 2y = 7/3

2(x+y) = 4/3(α+β)

x+y = (2/3)(α+β)

which shows that the centroid lies on the line x + y = 7/6. Therefore, the center of mass must also lie on this line.

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|r| = 7/80 < 1, the series is convergent. The sum = 0/(1-7/80) = 0. the sum of the geometric series is 0.

The geometric series with first term 0 and common ratio 7/80 is given by 0, 7/80, (7/80)², (7/80)³, ... In general, the nth term is (7/80)ⁿ⁻¹.

To determine whether this series is convergent or divergent, we can use the formula for the sum of an infinite geometric series:

sum = a/(1-r)

where a is the first term and r is the common ratio. In this case, a = 0 and r = 7/80.

If |r| < 1, then the series converges to the sum given by the above formula. If |r| ≥ 1, then the series diverges.

In this case, |r| = 7/80 < 1, so the series is convergent. The sum is given by:

sum = 0/(1-7/80) = 0

Therefore, the sum of the geometric series is 0.

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Properties B and C together ensure that there exists a 'c' in (-1, 1) at which f'(c) = 0.
Your answer: 1. B and C only

Which properties ensure that there exists ?

a 'c' in (-1, 1) at which f'(c) = 0, given f(-1) = f(1) = and the properties A, B, and C.

First, let's define the properties:
f(1) = 2
f is continuous on (-1, 1]
f(x) = (22/3) - x^2

To ensure that there exists a 'c' in (-1, 1) at which f'(c) = 0, we will use the Mean Value Theorem (MVT). MVT states that if a function is continuous on a closed interval and differentiable on an open interval, then there exists at least one 'c' in the interval where the derivative is 0.

Looking at property B, it states that f is continuous on (-1, 1], which satisfies the first condition of the MVT. Property C provides a specific function for f(x), which is differentiable on (-1, 1) since it is a polynomial function. Therefore, properties B and C together ensure that there exists a 'c' in (-1, 1) at which f'(c) = 0.

Your answer: 1. B and C only

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A sequence of transformations that maps figure 1 onto figure 2 and then figure 2 onto figure 3 include the following: D. a translation followed by a rotation.

In Mathematics and Geometry, a translation can be defined as a type of rigid transformation which moves every point of the object in the same direction, as well as for the same distance.

This ultimately implies that, a translation is a type of rigid transformation  that does not change the orientation of the original geometric figure (pre-image).

In Mathematics, a rotation is a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.

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Complete Question:

Which sequence of transformations maps figure 1 onto figure 2 and then figure 2 onto figure 3?

a reflection followed by a translation

a rotation followed by a translation

a translation followed by a reflection

a translation followed by a rotation

The area of the panel left after she cuts the hole is 5.215 ft²

Given that a circular hole of 1 foot by foot has been cut out of a rectangular panel of 3 feet by 2 feet,

We need to find the area of the remaining part after the cutting of the hole,

So, we will find the same by subtracting the area of the hole from the area of the panel.

So, area of the hole = π×radius² = 3.14×0.5² = 0.785 ft²

Area of the panel = length × width = 3 × 2 = 6 ft²

Area remaining part = 6-0.785 = 5.215 ft²

Hence the area of the panel left after she cuts the hole is 5.215 ft²

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the answer is Q1 = 27.5

Able Cable offers the fastest mean downloading speed among the three providers with a speed of 4.0 Mbps.

We can calculate the mean (average) download speed for each provider and compare them to determine which company offers the fastest mean downloading speed.

Based on the given data, the mean download speed for each provider is:

City Net: (3.6 + 3.7 + 3.7 + 3.6 + 3.9) / 5 = 3.7 megabits per second (Mbps)

Able Cable: (3.9 + 3.9 + 4.1 + 4.0 + 4.1) / 5 = 4.0 Mbps

Tel-N-Net: (3.9 + 3.7 + 4.0 + 3.6 + 3.8) / 5 = 3.8 Mbps

Therefore, Able Cable offers the fastest mean downloading speed among the three providers with a speed of 4.0 Mbps.

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The combination of these side lengths uniquely determines the shape of the triangle.

Hi! To draw a triangle with side lengths 3 inches, 5 inches, and 6 inches, make sure that the sum of any two sides is greater than the third side. In this case, 3 + 5 > 6, 3 + 6 > 5, and 5 + 6 > 3, so a triangle can be formed.

Yes, this is the only triangle you can draw using these side lengths.

The reason is that the side lengths are fixed, and according to the triangle inequality theorem, the combination of these side lengths uniquely determines the shape of the triangle.

The combination of these side lengths uniquely determines the shape of the triangle.

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The maps scale is 1 inch = 6 miles. This means that for every inch on the map, it represents 6 miles in real-life distance.

To determine the scale, we need to know the relationship between the distance on the map and the actual distance. In this case, the distance on the route map between Hugo's house and his work is 3 inches, and the actual distance he travels by bus is 18 miles.

To find the scale, we can set up a proportion using the given information:

(distance on the map in inches) / (actual distance in miles) = (1 inch) / (x miles)

Now, we can plug in the known values:

(3 inches) / (18 miles) = (1 inch) / (x miles)

To solve for x, we can cross-multiply:

3 inches * x miles = 18 miles * 1 inch

3x = 18

Now, divide both sides by 3:

x = 6

So, the scale of the map is 1 inch = 6 miles.

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If Ann takes a boat then the distance between Ann's home and the market across the lake is approximately 29 km.

To find the distance from Ann's home to the market, we can use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In this case, Ann's home, the market, and the point where she crosses the lake form a right triangle, with the distance she travels across the lake being the hypotenuse.

To calculate the distance, we can use the following formula:

c^2=a^2+b^2

where c is the distance from Ann's home to the market, a is the distance from her home to the point where she crosses the lake, and b is the distance from the market to the point where she crosses the lake.

We know that a = 20 km and b = 21 km, so we can plug these values into the equation:

c^2=20^2+21^2

c^2=400+441

c^2=841

To solve for c, we take the square root of both sides of the equation:

c=sqrt(841)

c=29

Therefore, the distance from Ann's home to the market is approximately 29 km, when she takes the shortest path across the lake directly toward the market.

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To solve this problem, we need to use related rates. Let's start by drawing a diagram:

```
        /\
       /  \
      /    \
     /      \
    /        \
   /__________\
```

We know that the radius of the conical pile is always two times its height, so we can label the diagram as follows:

```
        /\
       /  \
      /    \
     /      \
    /        \
   /__________\
  /|    r=2h   \
 / |___________\
```

Now we need to find an equation that relates the height of the pile to its radius. We can use the formula for the volume of a cone:

```
V = (1/3)πr^2h
```

We want to solve for h in terms of r:

```
V = (1/3)πr^2h
3V/πr^2 = h
```

Now we can differentiate both sides of this equation with respect to time:

```
d/dt (3V/πr^2) = d/dt h
0 = (3/πr^2) dV/dt - (2/πr^3) dr/dt
```

We're given that the height is increasing at a rate of 2 cm/s when the pile is 11 cm high, so we know that:

```
dh/dt = 2 cm/s
h = 11 cm
```

We want to find the rate at which sand is leaving the bin, which is given by `dV/dt`. We can solve for this using the equation we derived:

```
0 = (3/πr^2) dV/dt - (2/πr^3) dr/dt
dV/dt = (2/3)πr^2 (dh/dt) / r
```

Now we just need to plug in the values we know:

```
dh/dt = 2 cm/s
h = 11 cm
r = 2h = 22 cm

dV/dt = (2/3)π(22)^2 (2) / 22
dV/dt = 264π/3
```

So the rate at which sand is leaving the bin when the pile is 11 cm high is `264π/3 cm^3/s`.

To solve this problem, we can use the relationship between the radius and height of the conical pile, as well as the given rate of height increase.

Since the radius (r) is always two times the height (h), we have r = 2h. The volume (V) of a cone is given by the formula V = (1/3)πr^2h. We can substitute r with 2h, so V = (1/3)π(2h)^2h.

Now, let's differentiate both sides with respect to time (t):

dV/dt = (1/3)π(8h^2)dh/dt

When the height is 11 cm, the rate of height increase (dh/dt) is 2 cm/s. We can substitute these values into the equation:

dV/dt = (1/3)π(8(11)^2)(2)

Solving for dV/dt:

dV/dt ≈ 2046.92 cm³/s

At that instant, the sand is leaving the bin at a rate of approximately 2046.92 cm³/s.

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She would have to work for 11 hours to pay these bills without her FSA/HSA.

Emma went to the doctor 9 times last month, which means she had to pay a total of 9 x $20 = $180 in copays.

Without her FSA/HSA, she would have to work to earn $180 after taxes. Since she pays 17 percent in taxes, the amount she would have to earn before taxes is $180 / (1 - 0.17) = $216.87.

To earn $216.87, she would have to work for $216.87 / $20 per hour = 10.84 hours.

Rounding up, she would have to work for 11 hours to pay these bills without her FSA/HSA.

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The value of the account is 1.05 times as large as the previous year

There is a 2-column table with 6 rows representing the value of a savings account at the end of each year for 6 years. The relationship between the years and the value of the account is exponential, and there is a rate of change in this exponential relationship.

To find the rate of change in this exponential relationship, you can follow these steps:

1. Divide the value of the account in the second year by the value of the account in the first year: 5,512.50 / 5,250 = 1.05.

2. Since the relationship is exponential and the rate of change is constant, the account's value will increase by the same factor every year. In this case, the rate of change is 1.05, which means that after each year, the value of the account is 1.05 times as large as the previous year.

In summary, the rate of change in the exponential relationship between the increasing years and the increasing value of the account is 1.05, meaning that after each year, the value of the account is 1.05 times as large as the previous year.

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The value of KL as shown in the image is 12 units

An equation is an expression that shows how numbers and variables using mathematical operators.

Two triangles are said to be similar, if the ratio of their corresponding sides are in the same proportion.

For the triangle shown, since triangle XYZ is similar to triangle JKL, hence:

KL/XY  = KJ / XZ

substituting, KJ = 10.44:

KL / 8.7 = 11.31 / 8.2

KL = 12

The value of KL is 12 units

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The total length of the race is approximately 28.24 miles.

To determine the total length of the race, we can use the given information: Piotr has completed 24 miles, which represents 85% of the race. We can set up a proportion to find the total length. Let 'x' represent the full length of the race:

(24 miles) / x = 85% / 100%

To solve for 'x', we can first convert the percentage to a decimal by dividing 85 by 100, resulting in 0.85:

24 / x = 0.85

Next, we can cross-multiply:

0.85 * x = 24

Now, we can solve for 'x' by dividing both sides by 0.85:

x = 24 / 0.85

x ≈ 28.24 miles

Therefore, the total length of the race is approximately 28.24 miles. Piotr has completed 85% of this distance, which means he has run 24 miles and has around 4.24 miles remaining to finish the race.

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Answer:

a) £54

b) £1908

Step-by-step explanation:

a) use £1800 × 3% = £54

b) use £1800 + ( 54 × 2) = £1908

Therefore, the value of x to the nearest hundredth is approximately 72.73 units.

A triangle is a geometrical shape that consists of three straight sides and three angles. It is a polygon with three vertices, and the sum of its interior angles always adds up to 180 degrees. Triangles are classified based on the length of their sides and the measure of their angles. The most common types of triangles are equilateral, isosceles, and scalene, based on the length of their sides, and acute, right, and obtuse, based on the measure of their angles. Triangles have a wide range of applications in mathematics, physics, engineering, and other fields.

Here,

Therefore, in this triangle, sin(67°) = 67/x, where x is the length of the hypotenuse.

We can rearrange this equation to solve for x:

x = 67 / sin(67°)

Using a calculator, we find that sin(67°) is approximately 0.921, so:

x = 67 / 0.921

x ≈ 72.73

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The velociraptor's speed is 2 m/s, and its velocity is -0.3 m/s [w].

To calculate the speed and velocity of the velociraptor, we need to first find the total distance it covered and the displacement.

Total distance = 5m + 10m + 3m + 2m = 20m

Displacement = Final position - Initial position

Displacement = (2m [w]) - (5m [e])

Displacement = -3m [w]

Velocity is defined as displacement per unit time, while speed is defined as distance per unit time.

Velocity = Displacement / Time

Velocity = -3m [w] / 10s

Velocity = -0.3 m/s [w]

Speed = Total distance / Time

Speed = 20m / 10s

Speed = 2 m/s

Therefore, the velociraptor's speed is 2 m/s, and its velocity is -0.3 m/s [w].

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The value of measure of RU is,

⇒ 149°

We have to given that;

In circle,

m RS = 88 degree

m ST = 35 degree

Hence, We can formulate;

The value of measure of RU is,

⇒ 360° - ( 88° + 35° + 88°)

⇒ 360° - 211°

⇒ 149°

Thus, The value of measure of RU is,

⇒ 149°

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The volume of the table tent 3 cmH8 cm12 cm is 288 cubic cm.

The volume of the table tent can be found by multiplying the length, width, and height of the tent.

Volume = length x width x height

In this case, the length is 12 cm, the width is 8 cm, and the height is 3 cm.

Volume = 12 cm x 8 cm x 3 cm

Volume = 288 cubic cm

Therefore, the volume of the table tent is 288 cubic cm.

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The circle's x value will continue to be the same as the arc ST. So, x has a value of 40 degrees.

A circle's centre is the point from which all of the distances to the other points on the circle are equal. The radius of the circle is the measurement at issue.

Every point on a circle is a geometric shape that is equally separated from the centre.

The location of any point that is evenly separated from the fixed point known as the circle's centre can also be characterised as it.

The distance from any point on a circle to the centre is known as the radius of the circle.

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