What is the amplitude and period of the function shown below?

The features of the sine function in this problem are given as follows:

Amplitude: 2.

Midline: y = -4.

Period: 3 units.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Here, we have,

The equation is given as follows:

y = 2sin(2πx/3) - 4.

we have to define the sine function:

The standard definition of the sine function is given as follows:

y = Asin(B(x - C)) + D.

For which the parameters are given as follows:

A: amplitude.

B: the period is 2π/B.

C: phase shift.

D: vertical shift.

The function has a minimum value of -6 and a maximum value of -2, for a difference of 4, hence the amplitude is given as follows:

2A = 4.

A = 2.

Without vertical shift, a function with amplitude of 2 would oscillate between -2 and 2, while this one oscillates between -6 and -2, hence the vertical shift is given as follows:

D = -4.

The shortest distance between repetitions can be given by 2 - (-1) = 3, hence the period is of 3 units and the coefficient B is given as follows:

2π/B = 3

B = 2π/3.

The function is at it's midline at the origin, hence it has no phase shift, and thus the equation is given as follows:

y = 2sin(2πx/3) - 4.

More can be learned about trigonometric functions at brainly.com/question/21558626

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d.number​

3
Which number line shows a number equivalent to
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