What is the Activation Energy for this reaction?
A. 50 kJ
B. 150 kJ
C. 250 kJ
D. 200 kJ

Answer:

89 i would say

Explanation:

Answer:

The correct option is (c).

Explanation:

Given that,

The energy of a photon is, [tex]E=3.38\times 10^{-19}\ J[/tex]

We need to tell the color of this light. We know that, the energy of a photon is given by :

[tex]E=\dfrac{hc}{\lambda}[/tex]

Where

c is the speed of light

[tex]\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3.38 \times 10^{-19}}\\\\\lambda=5.88\times 10^{-7}\ m\\\\\lambda=588\ nm[/tex]

The wavelength of yellow light is approx 580 nm. Hence, we can say that this photon corresponds to yellow light.

Answer:

B. Green

Explanation:

correct on EDGE2021

Answer:

d no light can only change things by warming them up , so it cannot cause the paper to change colur

Answer:

Nikola Tesla was a Serbian-American inventor, electrical engineer, mechanical engineer, and futurist best known for his contributions to the design of the modern alternating current electricity supply system.

Answer:

Ingles porfavor

Explanation:

Answer:

j type the question into wolfram it gives you answer plus explanation

Answer:

C. Reflects only

Answer:

31.92 h

Explanation:

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 1

Amount remaining (N) = ⅛

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

⅛ = 1/2ⁿ × 1

Cross multiply

2ⁿ = 8

Express 8 in index form with 2 as the base.

2ⁿ = 2³

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 10.64 h

Number of half-lives (n) = 3

Time (t) =?

n = t / t½

3 = t / 10.64

Cross multiply

t = 3 × 10.64

t = 31.92 h

Therefore, it will take 31.92 h for lead-212 to decay to one-eighth its original strength.

Answer:

1.31×10⁻⁴ C or 131 μC

Explanation:

From the question,

Applying Coulomb's Law,

F = kqq'/r²..................... Equation 1

Where F = Force between the charges, q = first charge, q' = second charge, r = distance between the charges, k = coulomb's constant.

make q' the subject of the equation

q' = F×r²/(kq)

q' = Fr²/kq................ Equation 2

Given: F = 1240 N, r = 16.4 cm = 0.164 m, q = 28.4 μC = 2.84×10⁻⁵ C,

Constant: k = 8.98×10⁹ Nm/C²

Substitute these values into equation 2

q' = (1240×0.164²)/[(2.84×10⁻⁵)×(8.98×10⁹)

q' = (33.35104)/(25.5032×10⁴)

q' = 1.31×10⁻⁴ C

q' = 131 μC

Answer:

a lot of force is the answer

Explanation:

happy Ramadan kid

Answer: The first answer for the first problem, and the 2nd answer for the second problem

Explanation: For the first one, if it is absolute zero, the molecules would not move at all.

For the second one, the temperature of the sample will increase due to the movement.

Answer:

Gravity such as magnets

Explanation:

Hope this helped

Answer:

Imma just add it since i got it right. Well its the first one.

Explanation:

Mine is A temporary magnet is only able to create its own magnetic field while in the presence of a stronger magnet. In other words, these types of magnets need assistance from a larger force in order to be able to attract other objects and magnets.

Answer:

Any time

Explanation:

5. All the resistors in this circuit, the 18 Ω resistor included, are in parallel. The voltage drop across each resistor is the same, which is the equivalent to the potential difference of the battery. That is, 36 V [choice K].

6. The ammeter is in series with the branch containing a 12 Ω resistor. Since the voltage drop across this resistor is 36 V, the current in this branch will be I = V/R = (36 V)/(12 Ω) = 3.0 A [choice D].

7. The equivalent resistance of the circuit can be calculated as follows:

1/R = 1/12 + 1/9 + 1/18 = 1/4; thus, R = 4.0 Ω [choice G].

8. Electrical power can be defined as electrical work/time, and electrical work can be given by W = qV. If P = qV/t and q/t = I (charge flowing per unit time is equal to current), then P = VI. From Ohm's law, V = IR, and I = V/R. Substituting V/R for I in the power equation, P = V²/R.

For this circuit, the V = 36 V and R (the equivalent resistance) = 4.0 Ω. So, the power loss in the circuit is P = (36 V)²/(4.0 Ω) = 324 W [choice J].

Answer:

planets move in elliptical orbit.

Explanation:

this is because planets are formed closer to the sun while the comets are formed further.

The Sun is home to 99.85% of all stuff in the Solar System.All objects in our solar system orbit the Sun.The movement of planets is elliptical in nature.

Our solar system consists of the Sun, Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, as well as the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

It consists of the planets' satellites, as well as numerous comets, asteroids, and meteoroids, as well as the interplanetary medium. The Sun is home to 99.85% of all stuff in the Solar System.

The movement of planets is elliptical due to the fact that planets are present closer to the sun while the comets are present farther away from the sun as compared to the planets.

Hence the movement of planets is elliptical in nature.

To learn more about the solar system refer to the link;

https://brainly.com/question/12075871

The formula for momentum is p = m*v

The conservation of momentum suggests:

m*vi = m*vf (initial mass times initial velocity = final mass times final velocity or initial momentum = final momentum)

(0.0010)(52.2) = (0.0010 + 3.3)vf

vf = (0.0010)(52.2)/(0.0010 + 3.3) = 0.0522/3.301 ≈ 0.01581 m/s

To the nearest thousandth  ≈ .016 m/s

Answer:

its kainda blurry aploude another pic

Answer:

2

Explanation:

Answer:

It is D

Explanation: Use of these terms stretches back to World War I. One American field order from September 1918 noted, “The First Army will attack at H-Hour on D-Day with the object of forcing the evacuation of the St. Mihiel salient.” Other nations had their own shorthand. In World War I, the French used the code date “le Jour J,” while the British called their operation start days “Z-Day” and “Zero Hour.”

Hope this helps

You and your younger sister (who weighs half as much you do) are at a skating rink. You and your sister's both move backward but your sister accelerates at a greater rate.

The time rate of change of velocity with time.

As both are holding each other, they will be pushed backwards because the skating they wear makes them to move backwards. The equal and opposite force is applied on each other.

The force F =mass x acceleration.

The lesser mass greater will be the acceleration. Your sister with half weight of yours will accelerate more.

Thus, you and your sister's both move backward but your sister accelerates at a greater rate.

Learn more about acceleration.

https://brainly.com/question/12550364

#SPJ2

Answer:

But once the core runs out of hydrogen, the star starts to contract again briefly, until a shell of hydrogen around the core becomes hot enough to fuse into helium. When this happens, the radiation pushes the outer layers of the star far out into space, turning the star into a red giant

Explanation:

Correct?

Answer:

4km/m

Explanation:

She was going at 2km/m, so 2 kilometers per minute. She has 2 minutes therefore she needs to double her rate to 4 kilometers per minute.

Answer:

1)    v = 2.5 m / s, 2)  v = -0.5 m / s

Explanation:

For this exercise we will use the kinematics relations

1) velocity is defined by

         v = [tex]\frac{dx}{dt}[/tex]dx / dt

this definition serves for the instantaneous and the average velocity if the displacements are linear in time

         v = 20/8

         v = 2.5 m / s

b) for this part we use

          v = [tex]\frac{\Delta x}{\Delta t}[/tex]

         Δx = x_f -x₀

we must place a reference system, where the direction to the right is positive

         x_f = -2 m

         x₀ = +3 m

         Δx = -2 -3

         Δx = -5 m

we calculate

         v = -5 / 10

         v = -0.5 m / s

this value is a scalar

Answer:

   V = 12V,  V = 8V

Explanation:

a) In this series circuit the equivalent resistance is

          Req - R1 + R2

          Req = 30 + 20

          Eeq = 50 Ω

b) see attached

c) the circuit current is

          i = V / Req

          i = 20/50

          i = 0.4 A

voltages are>

         V = 0.4 30

          V = 12V

           V = 0.4 20

            V = 8V

Answer:

0.026 yards per minute because 13/500=0.26 which would find what fraction of a minute it would take to swim 1 yard

Answer:

a. i His weight and the normal force on him due to the ground

ii The weight and the normal force are balance

b. There are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.

Explanation:

a. i Describe the forces that are acting on a person who is standing still on a sidewalk

His weight and the normal force on him due to the ground act on him while the person is standing on the sidewalk

ii. identify whether the forces are balanced or unbalanced.

The weight and the normal force are balance because, the person does not move in the vertical or horizontal direction.

b. Describe how the forces would change if the person started walking.

When the person starts walking, the backward push due to his leg on the ground and the frictional force between his feet and the ground now acts on him in the horizontal direction. The frictional force acts in the forward direction and tends to move him forward. His weight and normal force on his feet still act vertically and are both balanced since he does not move in the vertical direction.

So, there are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.

Answer:

2

Explanation:

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body       Mass (gram)     Engine      Force (newtons)

1                   500                 1                     25

2                  1500                2                    20

3                  750                  3                    30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

 20    = 0.5 x acceleration

Acceleration [tex]$=\frac{20}{0.5}$[/tex]

                      [tex]$=\frac{200}{5}$[/tex]

                      [tex]$= 40 \ m/s^2$[/tex]

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of [tex]$ 40 \ m/s^2$[/tex] at the start of the launch.

Answer:

5 m/s

Explanation:

use speed=distance/time

300/60=5

Answer:

a) 45 s , b)    vₐ = 90 m / s, v_b = 162 m / s, c)     x_b = 3.328 10⁴ m

Explanation:

We can solve this exercise using the kinematic relations

Vehicle A

              xₐ = v₀ₐ t + ½ aₐ t²

vehicle B

starts two seconds later

             x_b = v_{ob} (t-2) + ½  a_b (t-2) ²

as cars start from rest their initial velocities are zero

at the point where they meet, the position must be the same for both vehicles

             xa = 0 + ½ aₐ t²

             xb = 0 + ½ a_b (t-2) ²

             ½ aₐ t² = ½ a_b (t-2) ²

            [tex]\sqrt{ \frac{a_a}{a_b} }[/tex] t = (t-2)

              t (1 - \sqrt{  \frac{a_a}{a_b} }) = 2

             t (1 - ⅔, ) = 2

            t = 2 / 0.4444

             t = 45 s

b)

the speed of each car

                vₐ = voa + aa t

                vₐ = 0 + 2 45

                vₐ = 90 m / s

                v_b = 3.6 45

                v_b = 162 m / s

c) xb = 0 + ½ ab (t-2) ²

       x_b = ½ 3.6 (45-2) ²

       x_b = 3.328 10⁴ m

Answer:

its very easy

Explanation: