Instructors led an exercise class from a raised rectangular platform at the front of the room. The width of the platform is (x+4) meters long and the area of the rectangular platform is 3x^2+10x−8. Find the length of the platform
The length of the platform is given by the expression -2 + sqrt(3x^2 + 10x) meters.
Let's start by using the formula for the area of a rectangle, which is:
Area = length x width
We are given that the width of the platform is (x+4) meters, so we can write:
Area = length x (x+4)
We are also given that the area of the platform is 3x^2+10x−8, so we can set these two expressions equal to each other and solve for the length:
3x^2+10x−8 = length x (x+4)
Expanding the right side, we get:
3x^2+10x−8 = length x^2 + 4length
Subtracting 4length from both sides, we get:
3x^2+10x−8−4length = length x^2
Rearranging, we get a quadratic equation:
length x^2 + 4length − 3x^2 − 10x + 8 = 0
To solve for length, we can use the quadratic formula:
length = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = 4, and c = -3x^2 - 10x + 8. Plugging in these values, we get:
length = (-4 ± sqrt(4^2 - 4(1)(-3x^2 - 10x + 8))) / 2(1)
Simplifying under the square root:
length = (-4 ± sqrt(16 + 12x^2 + 40x - 32)) / 2
length = (-4 ± sqrt(12x^2 + 40x)) / 2
length = (-4 ± 2sqrt(3x^2 + 10x)) / 2
length = -2 ± sqrt(3x^2 + 10x)
Since the length must be positive, we take the positive square root:
length = -2 + sqrt(3x^2 + 10x)
Therefore, the length of the platform is given by the expression -2 + sqrt(3x^2 + 10x) meters.
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Item 8
Find the measure of a central angle of a regular polygon with 7 sides. Round your answer to the nearest tenth of a degree, if necessary
The measure of a central angle of a regular polygon with 7 sides is approximately 51.4 degrees.
What is the central angle in a regular 7-sided polygon, rounded to the nearest tenth of a degree?For a regular polygon with 7 sides, we can substitute n = 7 into the formula:
central angle = 360 degrees / 7
central angle ≈ 51.4 degrees
A regular polygon is a polygon with equal sides and equal angles. The measure of each interior angle of a regular polygon with n sides is given by the formula:
interior angle = (n-2) x 180 degrees / n
For example, for a regular polygon with 7 sides:
interior angle = (7-2) x 180 degrees / 7
interior angle = 5 x 180 degrees / 7
interior angle ≈ 128.6 degrees
Since a central angle of a regular polygon is an angle formed by two consecutive radii from the center of the polygon, the measure of a central angle is equal to the measure of the exterior angle.
The measure of an exterior angle of a regular polygon with n sides is given by the formula:
exterior angle = 360 degrees / n
For a regular polygon with 7 sides, we can use the formula above to find the measure of each exterior angle:
exterior angle = 360 degrees / 7
exterior angle ≈ 51.4 degrees
Therefore, the measure of a central angle of a regular polygon with 7 sides is approximately 51.4 degrees, rounded to the nearest tenth of a degree as requested.
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Scores at a local high school on the Algebra 1 Midterm are extremely skewed left with a mean of 65 and a standard deviation of 8. A guidance counselor takes a random sample of 10 students and calculates the mean score, x¯¯¯.
(a) Calculate the mean and standard deviation of the sampling distribution of x¯¯¯
(b) Would it be appropriate to use a normal distribution to model the sampling distribution? Justify your answer
The mean of the sampling distribution is 65 and the standard deviation is 2.53. Yes, it would be appropriate to use a normal distribution to model the sampling distribution of x¯¯¯ due to the central limit theorem.
(a) To calculate the mean of the sampling distribution of x¯ ¯ ¯, we can use the formula:
μx¯ ¯ ¯ = μ = 65
This means that the mean of the sampling distribution of x¯ ¯ ¯ is equal to the population mean of 65.
To calculate the standard deviation of the sampling distribution of x¯ ¯ ¯, we can use the formula:
σx¯ ¯ ¯ = σ/√n = 8/√10 ≈ 2.53
This means that the standard deviation of the sampling distribution of x¯ ¯ ¯ is approximately 2.53.
(b) Yes, it would be appropriate to use a normal distribution to model the sampling distribution because of the Central Limit Theorem.
The Central Limit Theorem states that as the sample size increases, the sampling distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.
In this case, we have a sample size of 10, which is relatively small, but it is still large enough for us to assume that the sampling distribution of x¯ ¯ ¯ is approximately normal. Additionally, the population distribution is not too skewed, so this further supports the use of a normal distribution to model the sampling distribution.
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Enzo says that he can draw an enlarge rectangle that is 16 cenimeters by 13 cenimeters which explain enzo is correct
Enzo's statement that he can draw an enlarged rectangle that is 16 centimeters by 13 centimeters is correct. To explain this, we need to understand what it means to enlarge a shape.
Enlargement is the process of making a shape bigger or smaller while maintaining its shape and proportions. In other words, if we enlarge a rectangle, we need to make sure that the length and width are increased by the same factor.
In this case, Enzo has specified the new dimensions of the rectangle as 16 centimeters by 13 centimeters. To create an enlarged rectangle with these dimensions, we need to know the scale factor of the enlargement. The scale factor is the ratio of the length of the enlarged shape to the length of the original shape. In this case, we can find the scale factor by dividing the length of the new rectangle (16 centimeters) by the length of the original rectangle.
Let's assume that the original rectangle has a length of 8 centimeters and a width of 6 centimeters. Dividing 16 by 8 gives us a scale factor of 2. This means that we need to multiply the length and width of the original rectangle by 2 to get the dimensions of the enlarged rectangle.
So, the length of the enlarged rectangle will be 8 x 2 = 16 centimeters, and the width will be 6 x 2 = 12 centimeters. However, Enzo has specified that the width of the enlarged rectangle should be 13 centimeters. This means that we need to adjust the scale factor to make the width of the enlarged rectangle 13 centimeters. Dividing 13 by 6 gives us a scale factor of approximately 2.17.
Multiplying the length and width of the original rectangle by this scale factor gives us the new dimensions of the enlarged rectangle. The length will be 8 x 2.17 = 17.36 centimeters (rounded to two decimal places), and the width will be 6 x 2.17 = 13.02 centimeters (rounded to two decimal places). Therefore, Enzo is correct in saying that he can draw an enlarged rectangle that is 16 centimeters by 13 centimeters.
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Use the Lagrange Error Bound for Pn(x) to find a bound for the error in approximating the quantity with a third-degree Taylor polynomial for the given function f(x) about x = 0.
e^{0.25}. f(x) = e^x Round your answer to five decimal places.
The Lagrange Error Bound for P3(x) is |R3(x)| ≤ 0.00012, where f(x) = [tex]e^x[/tex]and x = 0.
To find the Lagrange Error Bound for the third-degree Taylor polynomial, we need to use the formula: |Rn(x)| ≤ (M / (n + 1)) * [tex]|x - a|^{(n+1)[/tex]
where M is an upper bound for [tex]|f^{(n+1)(x)}|[/tex]on the interval [a,x], and Rn(x) is the remainder or error term in the Taylor series.
For the given function f(x) = [tex]e^x[/tex], we have:
f(x) = [tex]e^x[/tex]
f'(x) = [tex]e^x[/tex]
f''(x) = [tex]e^x[/tex]
f'''(x) = [tex]e^x[/tex]
Since[tex]f^{(4)}(x) = e^x[/tex] is also [tex]e^x[/tex], the maximum value of |f^(4)(x)| on the interval [-0.25,0.25] is [tex]e^{0.25[/tex].
Thus, we can set [tex]M = e^{0.25[/tex] and a = 0. Then, using n = 3 (for the third-degree Taylor polynomial), we have:
|R3(x)| ≤ [tex](e^{0.25 / (3 + 1)}) * |x - 0|^4[/tex]
Simplifying, we get:
|R3(x)| ≤ 0.000125 * x⁴
Since x = 0.25 for this problem, we get:
|R3(0.25)| ≤ 0.000125 * 0.25⁴ = 0.00012
Therefore, the Lagrange Error Bound for P3(x) is |R3(x)| ≤ 0.00012, where f(x) =[tex]e^x[/tex] and x = 0. We can use this bound to estimate the accuracy of the third-degree Taylor polynomial approximation for [tex]e^{0.25[/tex].
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On a coordinate plane, triangle A B C has points (negative 2, 7), (negative 2, 3), and (negative 6, 3) and triangle D E F has points (negative 2, negative 10), (negative 2, negative 2), and (6, negative 2).
Given that StartFraction A B Over D E EndFraction = StartFraction B C Over E F EndFraction = one-half, complete the statements to show that △ABC ~ △DEF by the SAS similarity theorem.
Horizontal and vertical lines are
congruent
.
So, angles
are right angles by definition of perpendicular lines.
All right angles are
.
Therefore, △ABC ~ △DEF by the SAS similarity theorem.
Select the correct answer.
What is the domain of the exponential function shown in the graph?
A. x ≥ -1
B.-∞ < x <∞
C. x< 0
D.x ≤ -1
Answer:
Step-by-step explanation:
cle Graphs MC)The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.circle graph titled San Francisco Residents' 9, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80
help asspppp.............
The value of x and y in the right triangle are 11.31 units and 8 units respectively.
The tangential ratio of ∠P and ∠Q are 16 / 12 and 12 / 16 respectively.
How to find the side and angle of a right triangle?A right angle triangle is a triangle that has one of its angles as 90 degrees. The side of a right angle triangle can be found using trigonometric ratios as follows:
tan 45 = opposite / adjacent
tan 45 = 8 / y
cross multiply
y = 8 / tan 45
y = 8 /1
y = 8 units
Therefore,
sin 45 = opposite / hypotenuse
sin 45 = 8 / x
cross multiply
x = 8 / sin 45
x = 11.313816999
x = 11.31 units
Let's find the tangent ratio of ∠p and ∠q.
Hence,
tan ∠P = 16 / 12
tan ∠Q = 12 / 16
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PLSSS HELPP
1a. Model the periodic motion of the horses using an
equation and a graph.
Horse Equation: Use function notation in degrees. Your
function will graph below.
1a. The period of the motion is the time it takes for the horse to complete one full cycle of motion, and it is given by:
T = 2π/ω.
See attached graph.
1b. The period of the motion is the time it takes for the carousel to complete one full cycle of motion, and it is also given by:
T = 2π/ω.
1a.
let's assume that the motion of the horse can be modeled by a simple harmonic motion. The equation for simple harmonic motion is:
y = A sin(ωt + φ)
where:
y is the displacement from the equilibrium position
A is the amplitude (maximum displacement)
ω is the angular frequency (2π times the frequency)
t is time
φ is the phase angle
Assuming that the horse's motion is in a vertical direction and that the highest point of its motion corresponds to y = 0, we can write the equation as:
y = A sin(ωt)
where A is the amplitude of the motion and ω is the angular frequency.
We can plot this function as a sine wave on a graph, where the horizontal axis represents time and the vertical axis represents displacement. The period of the motion is the time it takes for the horse to complete one full cycle of motion, and it is given by:
T = 2π/ω
To determine when Ivan will get his next opportunity to take a perfect shot, we need to know the period of the horse's motion. Without additional information, it's difficult to estimate the period accurately.
The graph of the carousel equation θ = A cos(ωt) can be labeled as follows:
1b.
The motion of the carousel can also be modeled as a simple harmonic motion, with the equation:
θ = A cos(ωt + φ)
where:
θ is the angular displacement from the equilibrium position
A is the amplitude (maximum angular displacement)
ω is the angular frequency (2π times the frequency)
t is time
φ is the phase angle
The period of the motion is the time it takes for the carousel to complete one full cycle of motion, and it is given by:
T = 2π/ω
To determine when Ivan will get his next opportunity to take a perfect shot, we need to know the period of the carousel's motion. Without additional information, it's difficult to estimate the period accurately.
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Bet you can’t solve this
Answer: The answer is (A
Step-by-step explanation:
The answer isB because A is constant, C is irrelevant, and D is dependent.
Jill's neighborhood has a mean of 3 children per household.
What happens to the mean if a family with 7 children moves
away?
The mean decreases.
The mean remains the same.
The mean increases.
Consider the function f(x) = 1 – 5x², -3 ≤ x ≤ 2. The absolute maximum value is and this occurs at x equals The absolute minimum value is and this occurs at x equals
The absolute maximum value of f(x) on the interval [-3, 2] is 1, which occurs at x = 0. The absolute minimum value of f(x) on the interval [-3, 2] is -49, which occurs at x = 2.
To find the absolute maximum and minimum values of the function f(x) = 1 - 5x² on the interval [-3, 2], we first find the critical points of f(x) and then evaluate f(x) at the critical points and endpoints of the interval.
The derivative of f(x) is:
f'(x) = -10x
Setting f'(x) = 0, we get:
-10x = 0
which has only one critical point at x = 0.
Now, we evaluate f(x) at the critical point and endpoints of the interval:
f(-3) = 1 - 5(-3)² = -44
f(0) = 1 - 5(0)² = 1
f(2) = 1 - 5(2)² = -49
Therefore, the absolute maximum value of f(x) on the interval [-3, 2] is 1, which occurs at x = 0. The absolute minimum value of f(x) on the interval [-3, 2] is -49, which occurs at x = 2.
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A punch recipe requires 2 cups of cranberry juice to make 3 gallons of punch. Using the same recipe, what is the amount of cranberry juice needed for 1 gallon of punch?
Answer:
To make 3 gallons of punch, you need 2 cups of cranberry juice.
We can set up a proportion to find out how much cranberry juice is needed for 1 gallon of punch:
2 cups / 3 gallons = x cups / 1 gallon
To solve for x, we can cross-multiply:
2 cups * 1 gallon = 3 gallons * x cups
2 cups = 3x
x = 2/3 cup
Therefore, you would need 2/3 cup of cranberry juice to make 1 gallon of punch using this recipe.
B. It will be a curve.
C. It will be a line.
D. There is no way to tell.
The given equation on a graph can be described best as C. It will be a line.
Why would this be a line ?The given equation is a linear equation because it has the form y = mx + b, where m is the slope and b is the y-intercept. In this case, the equation can be rewritten as:
y = 3x + 15 - 64
y = 3x - 49
Since it's a linear equation, it will represent a straight line on the graph that can be found by using the equation and some values of x, to find values of y and then plotting them.
In conclusion, the best answer is C. It will be a line.
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The full question is:
An equation is given to be 3x + 15 = 64
What will this be on a graph ?
A. It will be irregular
B. It will be a curve.
C. It will be a line.
D. There is no way to tell.
Do couples get engaged or not? If they are engaged, how long did they date before becoming engaged? A poll of 1000 couples conducted by Bruskin and Goldring Research for Korbel Champagne Cellars gave Time Never Engaged Number of Couples 200 the following information: Time Number of Couples Never Engaged 200 Less than 1 year 240 1 to 2 years 210 More than 2 years 350 What is the sample space in this problem?
The sample space in this problem is the total number of couples surveyed, which is 1000.
The sample space in probability refers to the set of all possible outcomes of an experiment. In this case, the experiment is the survey conducted by Bruskin and Goldring Research, and the possible outcomes are the different categories of time taken by couples before getting engaged.
The given information provides the number of couples in each category, which can be added to find the total number of couples surveyed:
Sample space = Number of couples never engaged + Number of couples engaged for less than 1 year + Number of couples engaged for 1 to 2 years + Number of couples engaged for more than 2 years
Sample space = 200 + 240 + 210 + 350
Sample space = 1000
Therefore, the sample space in this problem is 1000, which represents the total number of couples surveyed by the research firm.
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Which proportion is correct?4/10=3/61/2=7/81/2=3/64/10=7/8
Determine which proportion is correct, we will compare the cross products of each proportion. The correct proportion will have equal cross products. The correct proportion is 1/2 = 3/6.
1. 4/10 = 3/6
To check this proportion, we'll calculate the cross products:
(4 * 6) = (10 * 3)
24 = 30
Since 24 ≠ 30, this proportion is incorrect.
2. 1/2 = 7/8
To check this proportion, we'll calculate the cross products:
(1 * 8) = (2 * 7)
8 = 14
Since 8 ≠ 14, this proportion is incorrect.
3. 1/2 = 3/6
To check this proportion, we'll calculate the cross products:
(1 * 6) = (2 * 3)
6 = 6
Since 6 = 6, this proportion is correct.
4. 4/10 = 7/8
To check this proportion, we'll calculate the cross products:
(4 * 8) = (10 * 7)
32 = 70
Since 32 ≠ 70, this proportion is incorrect
So, the correct proportion is 1/2 = 3/6.
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Fill in the boxes 3(n+7) = (3)( ) + (3)( ) = +
the final result will be 3n + 21
what is ditribustion propety?
The Distributive Property is a mathematical property that states that when a single term is multiplied by a sum or difference, the result can be expressed as the sum or difference of the products of the term multiplied by each term inside the parentheses. It is often used to simplify expressions and equations in algebra. 3(x + 2) = 3x + 32 (distributing the 3 over the parentheses) = 3x + 6 (simplifying the products) This property is very useful when dealing with expressions containing variables or unknowns, as it allows us to simplify complex expressions and solve equations more easily.
using distribution propety
3(n + 7)
= (3)(n) + (3)(7)
= 3n + 21
Hence the final result will be 3n + 21
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A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with a = 19. 0 milligrams. Construct a 95% confidence interval for the
true mean cholesterol content,, of all such eggs.
We can say with 95% confidence that the true mean cholesterol content of all such eggs is between 223.99 milligrams and 232.01 milligrams.
To construct a 95% confidence interval for the true mean cholesterol content of all such eggs, we can use the following formula:
CI = X ± Zα/2 * σ/√n
where:
X = sample mean = 228 milligrams
Zα/2 = the critical value from the standard normal distribution corresponding to a 95% confidence level, which is 1.96
σ = population standard deviation = 19.0 milligrams
n = sample size = 82
Substituting the values into the formula, we get:
CI = 228 ± 1.96 * 19.0/√82
= 228 ± 4.01
= (223.99, 232.01)
Therefore, we can say with 95% confidence that the true mean cholesterol content of all such eggs is between 223.99 milligrams and 232.01 milligrams.
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Find the linearization of the function z = x =√y at the point (-2, 4). L(x, y)=
The linearization of the function z = x =√y at the point (-2, 4) is L(x, y) = 2 + (1/4)(y-4).
To find the linearization of the function z = x =√y at the point (-2, 4), we need to use the formula for the linearization:
[tex]L(x, y) = f(a, b) + f_x(a, b)(x-a) + f_y(a, b)(y-b)[/tex]
where f(a, b) is the value of the function at the point (a, b), f_x(a, b) is the partial derivative of f with respect to x evaluated at (a, b), f_y(a, b) is the partial derivative of f with respect to y evaluated at (a, b), and (x-a) and (y-b) are the distances from the point (a, b) to the point (x, y).
In this case, we have:
f(x, y) = √y
a = -2
b = 4
So, we need to find the partial derivatives f_x and f_y:
[tex]f_x(x, y) = 0f_y(x, y) = 1/(2√y)[/tex]
evaluated at (a, b):
f_x(-2, 4) = 0
f_y(-2, 4) = 1/(2√4) = 1/4
Now, we can plug in all the values into the linearization formula:
[tex]L(x, y) = f(-2, 4) + f_x(-2, 4)(x-(-2)) + f_y(-2, 4)(y-4)L(x, y) = √4 + 0(x+2) + (1/4)(y-4)L(x, y) = 2 + (1/4)(y-4)[/tex]
Therefore, the linearization of the function z = x =√y at the point (-2, 4) is L(x, y) = 2 + (1/4)(y-4).
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What is the ratio of hours spent at soccer practice to hours spent at a birthday party? choose 1 answer:
The ratio of hours spent at soccer practice to hours spent at a birthday party can be represented as 2 for every 3
To provide an accurate ratio, I would need the specific number of hours spent at both soccer practice and the birthday party.
Once you provide that information, you can create the ratio by putting the two numbers in the form 2 for every 3.
For example, if you spent 3 hours at soccer practice and 2 hours at a birthday party, the ratio would be 3:2. This means that for every 3 hours spent at soccer practice, you spent 2 hours at the birthday party.
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The table shows how many hours Sara spent at several activities one Saturday.
Activity "Hours
Soccer practice 2
Birthday party 3
Science project 1
What is the ratio of hours spent at soccer practice to hours spent at a birthday party?
Choose 1 answer:
1 for every 2
B
2 for every 1
2 for every 3
3 for every 2
What is the surface area of the cylinder? Approximate using π = 3.14 and round to the nearest square meter.
a cylinder has radius labeled 2.2 meters and height labeled 6.5 meters
99 square meters
105 square meters
117 square meters
120 square meters
The surface area of the cylinder, rounded to the nearest square meter, is: D. 120 square meters
What is the Surface Area of a Cylinder?The surface area of a cylinder can be calculated by using the formula expressed as:
SA = 2πr(h + r), where r is the radius and h is the height.
Given the following:
π = 3.14
radius (r) = 2.2 m
height of the cylinder (h) = 6.5 m
Plug in the values:
SA = 2 * 3.14 * 2.2 * (6.5 + 2.2)
SA ≈ 120 square meters (rounded to the nearest square meter)
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The average weight of Carl, Carla, Carmen, Clark, and Cathy is 107.6 lb. Cathy weighs 115 lb. What is the average weight of the other four? Show your work.
Answer:
Step-by-step explanation:
Let's start by finding the total weight of all five people:
Total weight = Average weight x Number of people
Total weight = 107.6 x 5
Total weight = 538
We know that Cathy weighs 115 lb, so we can subtract her weight from the total weight to find the total weight of the other four people:
Total weight of other four = Total weight - Cathy's weight
Total weight of other four = 538 - 115
Total weight of other four = 423
To find the average weight of the other four, we can divide the total weight of the other four by the number of people:
Average weight of other four = Total weight of other four / Number of people
Average weight of other four = 423 / 4
Average weight of other four = 105.75 lb
Therefore, the average weight of the other four is 105.75 lb.
Calcula la longitud del puente que se quiere construir entre los puntos A y B, para lo cual se sabe que los ángulos ABO Y OAB miden 32" y 48° respectivamente y que la
distancia entre Ay O medida en línea recta es 120 m. (sugerencia, trace una linea vertical desde o hasta el segemto AB).
La longitude del Puente entre loss punts A y B es de aproximadamente 97.9 metros.
How to calculate the bridge length?Para calcular la longitud del puente entre los puntos A y B, podemos utilizar el teorema del seno en el triángulo OAB.
Primero,trazamos una línea vertical desde O hasta el segmento AB, creando un triángulo rectángulo OAD. La distancia entre A y O, medida en línea recta, es de 120 m.
Luego, utilizando el ángulo OAB, que mide 48 grados, y el ángulo ABO, que mide 32 minutos (o 32/60 grados), podemos encontrar el tercer ángulo del triángulo OAB aplicando la propiedad de que la suma de los ángulos de un triángulo es 180 grados.
El tercer ángulo del triángulo OAB será: 180 - 48 - (32/60) ≈ 101.467 grados.
Ahora, aplicamos el teorema del seno:
sen(OAB) / AO = sen(ABO) / BO
Despejando BO
BO = (AO * sen(ABO)) / sen(OAB)
Sustituyendo los valores conocidos:
BO = (120 * sen(48)) / sen(101.467) ≈ 120 * 0.7431 / 0.9933 ≈ 89.568 m
Por lo tanto, la longitud del puente que se quiere construir entre los puntos A y B es aproximadamente 89.568 metros.
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What is the measure of angle A? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth. m∠A=° Right triangle A B C, with right angle C B A. Side A B is three centimeters, side B C is four centimeters, and side C A is five centimeters.
The measure of angle A is given as follows:
m < A = 53.13º.
What are the trigonometric ratios?The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:
Sine of angle = length of opposite side to the angle divided by the length of the hypotenuse.Cosine of angle = length of adjacent side to the angle divided by the length of the hypotenuse.Tangent of angle = length of opposite side to the angle divided by the length of the adjacent side to the angle.Angle A is opposite to a side of length 4 cm, while the hypotenuse is of 5 cm, hence it's measure is obtained as follows:
sin(A) = 4/5
m < A = arcsin(4/5)
m < A = 53.13º.
Missing InformationWe have a right triangle, in which the side length opposite to angle A is BC = 4, while the hypotenuse is CA = 5.
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Marcus charges 130$ per week to pet sit. Next week he is offering an 18% discount. What is the amount of the discount?
Answer:23.4
Step-by-step explanation: 18 divided by 130
The amount of the discount is $23.40.
The problem asks us to find the amount of the discount given a percentage discount on a known price. To do this, we use the formula for calculating a percentage of a number.
To calculate the discount amount, we need to find 18% of the original price, which is $130 per week.
We can start by calculating 18% of $130:
Discount = 0.18 * $130 = $23.40
Therefore, the amount of the discount is $23.40.
Suppose a population is known to be approximately normal and you are finding a 98% confidence interval with a sample size of 32. Identify the critical value you will use if you are using a
The critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.
When finding a 98% confidence interval for a normally distributed population with a sample size of 32, you will need to use a critical value from the standard normal (z) distribution.
To find the critical value, you can refer to a z-table or use a calculator with statistical functions. For a 98% confidence interval, you will need the z-score that corresponds to the middle 98% of the data, leaving 1% in each tail. This z-score is approximately 2.33.
So, the critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.
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2a=−2+4(a+3)
a =
−4b=−5(3−b)+6
b =
Answer:
a = - 5 , b = 1
Step-by-step explanation:
2a = - 2 + 4(a + 3) ← distribute parenthesis
2a = - 2 + 4a + 12 ( subtract 4a from both sides )
- 2a = 10 ( divide both sides by - 2 )
a = - 5
-------------------------------------------
- 4b = - 5(3 - b) + 6 ← distribute parenthesis
- 4b = - 15 + 5b + 6 ( subtract 5b from both sides )
- 9b = - 9 ( divide both sides by - 9 )
b = 1
Step-by-step explanation:
2a=6(a+3)
2a=6a+18
2a-6a=18
-4a=18
-4a/-4=18/-4
a=-4.5
HELP!! Which statements describe the end behavior of f(x)?f(x)?
Select two answers.
Answer:
As x approaches ∞, y approaches -∞
As x approaches -2.5, y approaches ∞
Step-by-step explanation:
The table shows the number of beads used to make a necklace.
Ginger wants to make a smaller necklace using the same ratio of pink to white beads.
How many different necklaces could Ginger make?
How do you know?
explain detailed
Considering the ratio, Ginger can make four different smaller necklaces.
How to obtain the ratio between two amounts?The ratio between two amounts a and b is given as follows:
a to b.
Which is also the division of the two amounts.
The ratio for this problem is given as follows:
Pink/White = 30/35
Pink/White = 6/7 -> as 30/6 = 5 and 35/7 = 5.
5 - 1 = 4, hence, considering the ratio, Ginger can make four different smaller necklaces.
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Pentagon A'B'C'D'E'A
′
B
′
C
′
D
′
E
′
A, prime, B, prime, C, prime, D, prime, E, prime is the image of pentagon ABCDEABCDEA, B, C, D, E under a dilation with a scale factor of \dfrac{1}{2}
2
1
start fraction, 1, divided by, 2, end fraction.
The length of segment C'D' is given as follows:
C'D' = 2.
What is a dilation?A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.
The length of segment CD is given as follows:
CD = 4. (4 vertical units of difference).
The scale factor is given as follows:
k = 1/2.
Hence the length of segment C'D' is given as follows:
C'D' = 1/2 x 4 = 2.
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