Answer:
green horizontal asymptote: y = -2
blue horizontal asymptote: y = -4
Step-by-step explanation: Exponential functions have a horizontal asymptote
2-h=6-k - solve for k
help please
Answer:
k=4+h
...................
7 times a number plus 3 is 38. find the number
Answer:
5
Step-by-step explanation:
7 x 5 = 35
35 + 3 = 38
[tex]Evaluate: \sqrt{ \frac {1 - sin(x)}{1 + sin(x)}} \\ [/tex]
Solve this problem please..
[tex]\large\underline{\sf{Solution-}}[/tex]
We have to evaluate the given expression.
[tex] \rm = \sqrt{ \dfrac{1 - \sin(x) }{1 + \sin(x) } } [/tex]
If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.
[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} } [/tex]
[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } } [/tex]
We know that:
[tex] \rm \longmapsto { \sin}^{2}(x) + \cos^{2}(x) = 1[/tex]
[tex] \rm \longmapsto \cos^{2}(x) = 1 - { \sin}^{2}(x)[/tex]
Therefore, the expression becomes:
[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}} [/tex]
[tex] \rm = \dfrac{1 - \sin(x)}{\cos(x)}[/tex]
[tex] \rm = \dfrac{1}{\cos(x)} - \dfrac{ \sin(x) }{ \cos(x) } [/tex]
[tex] \rm = \sec(x) - \tan(x) [/tex]
[tex] \sqrt{ \frac{ \cos(n) }{1 + \: \sin(n) } } [/tex]
see the attachment!!
hope it helps
#carryolearning
The sum of the first n terms of a sequence is Sn = n(n + 1)(n + 2).
What is the 4th term of the sequence?
O 48
O 120
O 60
O 396
Answer:
60
Step-by-step explanation:
S₄ = 4(4+1)(4+2) = 120
S₃ = 3(3+1)(3+2) = 60
4th term = 120-60=60
neeeeeeed heeeeeelp pleaseeeeeeeee
Answer:
D
Step-by-step explanation:
Hope this is correct and helps
Answer:
D
Step-by-step explanation:
I'm not completely sure but A is constant cuz it don't move B is increasing C is same as A and D Is decreased
Translate the blue shape to the pink shape...
help me quick please
Answer:
I can't help you if there's no picture lol
helpppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Answer:
a) = 4.198
b) = 4.146
Step-by-step explanation:
a) 15.444/6+0.232*7
do pemdas
=15.444/6+(0.232*7)
=(15.444/6)+1.624
=2.574+1.624
a) = 4.198
b) (1.709+0.364)*6/3
pemdas again
=(2.073) *6 / 3
=12.438 / 3
b) =4.146
Hope this helps :)
Answer:
A 4.198 and b is 2.073
Step-by-step explanation:
i hope this is right
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each linear model to its inverse.
Answer:
We need the options
Step-by-step explanation:
...
Hooke’s Law for an elastic spring states that the distance a spring stretches varies directly as the force applied. If a force of 180 newtons stretches a spring 5 cm, how much will a force of 270 newtons stretch the same spring?
Will give Brainliest :)
Answer:
7.5m
:) hoped this helped!
Step-by-step explanation:
Winter fills 2/5 of a water bottle in 1/4
of a minute. How many bottles can
Winter fill in 1 minute?
Answer:
1.6 (decimal), 1 6/10 (proper), and 8/5 (improper)
Step-by-step explanation:
If it’s 2/5 in 1/4 and to get one while you need four 1/4 you need to multiply to get how much it can fill in that 4/4. To do this multiply 2/5 by 4 which is 1.6 (decimal) and 1 6/10 fractional. Or if you want it improper, 8/5
Rebecca is playing a video game that involves planting and cutting down trees. She moves up an energy level for each tree she plants, and she moves down a level for each tree she cuts. If Rebecca reaches energy level 10, she will earn bonus points. Rebecca is currently at energy level 4. The results of her next 3 turns are: Turn 1: 6 trees cut Turn 2: 8 trees planted Turn 3: 1 tree cut Answer the questions to find out whether Rebecca earned bonus points in the next 3 turns. Use the number line to help you add.
Using only addition, write an expression that represents Rebecca's score after these three turns. (Remember that she starts at an energy level of 4.).
Answer:
After turn one she will have 0 points !
Step-by-step explanation:
After turn one she will have 0 points
After turn 2 she will have 8 points
After turn 3 she will have 7 points
She will not earn bonus points because she could not reach ten points
(Hope this helps can I pls have brainlist (crown)☺️)
If you were to solve the following system of equations by using a matrix,
which of the following would be your coefficient matrix?
4x – 3y=7
x + 5y=13
Answer:
I believe it is C but it's good to double check
Step-by-step explanation:
Answer:
Step-by-step explanation:
b
(a) 85% of 80 is what number?
(b) 21 is 35% of what?
Answer:
a) 68
b)60
Step-by-step explanation:
a) 85% = 0.85
0.85 * 80 = 68
b) let x be the unknown number.
35% = 0.35
0.35x = 21
x = 60
Answer:
Step-by-step explanation:
a, 85% of 80
85% of 80
= 85/100*80
=85/100*80
=0.85*80
=68.
b, 21 is 35%
21 is 35%
=21*35/100
=21*0.35
=7.35.
hope this helps you dear and have a nice day
[tex] \sf \: please \: answer \: and \: do \: not \: spam[/tex]
¢αяσυѕєℓ :)
It's based on integrals....
Hello Carousel!
[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
Solve the integral.[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
[tex] \tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex]
First, let's take I as ⇨ [tex]\tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex].
[tex]\tt \:I = \int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x +1}} \: dx \\\tt \: I =\int \: \frac{ x + 2 }{( {x}^{2} + 2x + 1 + x + 2) \sqrt{x + 1}} \: dx \\ \tt \:I =\int \: \frac{ x + 2 }{( ({x + 1}^{2}) + x + 2) \sqrt{x + 1}}[/tex]
Let, x + 1 = m² => dx = 2mdm.
[tex]\tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: m} 2mdm \\ \tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: \bcancel{ m}} 2 \bcancel{m}dm \\ \tt \: I = \: \int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 } 2dm[/tex]
Now, divide the numerator & denominator by m²....we'll get it as...
[tex]\tt \:I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{ {m}^{2} + 1 + \frac{1}{ {m}^{2} } } \: dm \\\tt \: I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{( {m}^{2} + \frac{1}{ {m}^{2} } - 2) + 3} \: dm \\\tt \: I =2\int \: \frac{ (1 + \frac{1}{ {m}^{2} }) \: dm }{ ({m} - \frac{1}{ m } ) ^{2} + 3} [/tex]
Now, let m - 1/m be t => (1 + 1/m²) dm = dt
[tex]\tt \:I =2\int \: \frac{ dt}{ {t}^{2} + 3 } \\ \tt \:I = 2\int \: \frac{ dt}{ {t}^{2} + ( \sqrt{3}) ^{2} }[/tex]
We know, [tex]\tt \:\int \: \frac{dx}{ {x}^{2} + a ^{2} } = \frac{1}{a} tan ^{ - 1} (\frac{x}{a} ) + c[/tex]...therefore...
[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{t}{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 1}[/tex]
Now, substitute the value of 't' in eq. 1..we'll get..
[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{m - \frac{1}{m} }{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 2}[/tex]
Now, substitute the value of 'm' in eq. 2...we'll get...
[tex] \tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}[/tex]
The correct answer is Option B.__________________
The question is really long & tricky but once you get the hang of it you'll be good. Good luck!__________________
Hope it'll help you!
ℓu¢αzz ッ
Please solve... I will mark you brainliest
Answer:
x = 5
Step-by-step explanation:
[tex]6x - 20 = 2x \\ - 20 = 2x - 6x \\ - 20 = - 4x \\ \frac{ - 20}{ - 4} = x = 5[/tex]
3 sss, aas, sas, or not enough information
Answer:
AAS
Step-by-step explanation:
I'm pretty sure its this, but im sorry if im wrong!
What is the number if 4 is subtracted from sum of 1 fourth of 5 times of 8 and 10
Answer:
Answer:18.5
Step-by-step explanation:
10+8=18
18*5=90
90/4
22.5-4=18.5
Have a happy day! <3Miss Hawaii
Answer:
16
Step-by-step explanation:
sum of 8 and 10=18
5 times of sum of 8 and
10= 18×5=80
1/4 of 5 times of sum of 8 and
10= 1/4×80=20
and then subtracted 4 from
20 =20-4=16
Find the unit rate for this situation. Please DO NOT use any extra spaces or
symbols. Simply type in the number amount.
Please Please Help Me. Put the following equation of a line into slope-intercept form, simplifying all fractions.
2y-2x= -14
Answer:
y = x-7
Step-by-step explanation:
Slope intercept form is
y = mx+b where m is the slope and b is the y intercept
2y -2x = -14
Add 2x to each side
2y-2x+2x= 2x-14
2y = 2x-14
Divide by 2
2y/2 = 2x/2 -14/2
y = x-7
[tex]f(x)=\frac{2x}{x-1}[/tex]
[tex]f(a); f(a+h); \frac{f(a+h)-f(a)}{h}[/tex]
13. A bakery is having a buy 4, get 1 free sale on cakes. This sale is eguivalent to what percentage off the regular price of all 5 cakes? A. 196 B. 10%% C. 20 D. 25%6 E. 40%
Answer: 20
Step-by-step explanation:
 Use trigonometric identities to solve each equation within the given domain
sec(x) cos(3x) = 0 from [- x /2 , x /2]
Answer:
Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].
Step-by-step explanation:
Angle sum identity for cosine:
[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].
Double-angle identity for cosine and sine:
[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].
[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].
The secant of an angle is the inverse reciprocal of the cosine of that angle:
[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].
Apply these identities to rewrite the left-hand side of the equation.
[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].
Solve the rewritten equation:
[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].
Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].
The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].
If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].
Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],
Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.
Anna challenges Sarah to a game where Sarah flips a fair coin and then randomly chooses a card from a small deck of cards that includes only 111 jack, 111 queen, 111 king, and 111 ace.The only way Sarah can win is by flipping heads and then choosing either the jack or the queen.If XXX is a random variable that represents Sarah's outcome, drag the bars to graph the probability distribution for all possible values of XXX.
The probability distribution for all possible values of X are given in the discrete probability table ;
X : ____ winning ____ not winning P(X) : ____ 0.25 ________ 0.75Fair coin = {H, T}
card = {J, Q, K, A}
Sample space :
__ H ___ TJ | HJ __ TJQ| HQ __TQK| HK __ TKA| HA __ TATotal possible outcomes = sample space = 8 Winning selection = {HJ, HQ}Probability of winning ; P(Winning) = 2/8 = 1/4 = 0.25
Probability of not winning ;
1 - P(wininng) = 1 - 1/4 = 3/4 = 0.75
X : ____ winning ____ not winning
P(X) : ____ 0.25 ________ 0.75
Learn more : https://brainly.com/question/25274933
major help.......................
Answer: C. 85°
Step-by-step explanation:
Answer:
I look lik dis almost dreads and then them types of braces and my eye brows look like that and I got a tattoo on my face but my eyes are blue and I have contacts so no more glasses
maths help me maths giving 10 point
3. What is the function of a Golgi complex? What
is the function of the endoplasmic reticulum?
Answer:
Step-by-step explanation:
Gogli complexes packages proteins, while endoplasmic reticulums transport proteins made by the gogli complexes around the cell.
65% of 51. Please also show me how to do it because I can't.
Answer:
Step-by-step explanation:
65% of 51 = [tex]\dfrac{65}{100}*51[/tex]
= 0.65 *51
= 33.15
Simplify the following to standard form
1.(9x+7y+8z)+(2x+ -4y+7z)
2. (5x +10y+ -8z) - (2x+ -2y + -3z)
Answer:
1, 11x + 3y + 15z
2, 3x + 12y + -5z
Step-by-step explanation:
all you need to do is combined the like terms and make sure the signs (positive and negative signs) are right
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I must speak in your language
ddddwfdwfd qdqfqfqqdqdqdqddqdqdq
the sum of two numbers is 21 the second number is six times the first one
Answer:
18+3
Step-by-step explanation:
3x6= 18
and 18+3=21