Answer:
Image processing operations implemented with filtering include smoothing, sharpening, and edge enhancement.
Using a variable length array, write a C program that asks the user to enter test scores.Then, the program should calculate the average, determine the lowest test score, determine the letter grade, and display all three.
Answer:
Here is the C program :
#include<stdio.h> // to use input output functions
int main(){ //start of main() function body
int n; //to store the number of tests taken
int test_scores[n], i; //a variable length array test_score
float sum=0,average; //to store the sum and average of test scores
int lowest; //to store the lowest test score
printf("Enter the number of tests taken :");//prompts user to enter number of test scores
scanf("%d",&n); / / reads the value of n from user
printf("Enter test scores: "); //prompts user to enter test scores
for(i=0; i<n; i++) {
scanf("%d",&test_scores[i]); //read the values of input test scores
sum = sum + test_scores[i]; } //calculates the sum of the test scores by adding the values of test scores
average=sum/n; // compute the average by dividing sum of all test scores with the total number of test scores
printf("Average is %.2f",average); //displays the average
printf("\nGrade is "); // prints Grade is
if (average >= 90) { //if value of average is greater than or equal to 90
printf("A"); } //print the grade letter A
else if(average >= 80 && average < 90) { //if value of average is greater than or equal to 80 and less than 90
printf("B"); } //print the grade letter B
else if(average>60 && average<80){ //if value of average is between 60 and 80
printf("C"); } //print the grade letter C
else if(average>40 && average<=60) { //if value of average is greater than 40 and less than or equals to 60
printf("D"); } //print the grade letter D
else { //if the value of average is below 40
printf("F"); } //print the grade letter F
lowest = test_scores[0]; //lowest points to the 1st element of test scores means the first input test score
for (int j = 1; j < n;j++) { //loop iterates through the scores
if (test_scores[j] < lowest) { // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable
lowest = test_scores[j]; } } //then assign that element value of test_score to the lowest
printf("\nLowest test score is: %d.\n", lowest); } //displays the lowest test score
Explanation:
The program is well explained in the comments mentioned with each statement of the code.
The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.
Which is the first step in the process of reading materials critically
Answer:
SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material
Which are true of the Transmission Control Protocol (TCP)? Multiple answers: You can select more than one option A it supports full duplex communication B it has graceful connection shutdown C its connections are logical D its data is sent as a discrete messages E it is an end-to-end protocol
Answer:
A, B, C, D and E
Explanation:
Transmission Control protocol (TCP) is a protocol that describes how connections are made and maintained between devices in a network which will help applications in these devices communicate and transmit data.
The following are some of the features of TCP:
i. It supports full duplex communication: In other words, TCP allows for concurrent transmission of data in both directions.
ii. it has a graceful connection shutdown: TCP allows for graceful termination and closing of connection. This means that when there is no more data to be sent by any of the communicating devices, rather than just close connection from its end, it first informs the other device about its completion and asks if it's safe to close the connection. From there, if the other device then says it doesn't have any data to send either, they then reach a consensus to close the connection at their respective ends.
iii. Its connections are logical: TCP makes use of the reliability and flow control mechanisms which require that it initialize and maintain some status information for each stream of data. This status information containing sockets, sequence numbers and window sizes is called a logical connection.
iv. Data is sent as discrete messages: Like other discrete messages, the IP treats the data in TCP as discrete messages by placing them into the IP datagram and transmitting to the target host.
v. It is an end-to-end protocol: TCP governs the way data is transmitted between two devices at their respective ends to ensure reliable delivery. In other words, it is responsible for the transmission of data from a source to one or more destinations. It sits on the operating system of the source and also on the operating system(s) of the destination(s).
Programming Challenge: Test Average CalculatorUsing a variable length array, write a C program that asks the user to enter test scores.Then, the program should calculate the average, determine the lowest test score, determine the letter grade, and display all three.
Answer:
well you could use variables in C and display them
Explanation:
? Question
Which term describes a population's attitudes and beliefs?
demographics
infographics
psychographics
geographics
psychgraphics
geographics
Answer:
psychographics
Explanation:
The study of people according to their attitudes, aspirations and other psychological criteria
When you sustain program implementation by staying true to the original design, it is termed A. Goals and objectives B. Program fidelity C. Program evaluation D. Program management
Answer:
Program fidelity
Explanation:
In Network Address and Port Translation (NAPT), which best describes the information used in an attempt to identify the local destination address?
Answer:
Hello your question lacks the required options here are the options
source IP and destination IPsource IP and destination portsource IP and source portsource port and destination IPsource port and destination portanswer : source IP and destination port
Explanation:
The information that is used in an attempt to identify the local destination address is the source IP and destination port
source IP is simply the internet protocol address of a device from which an IP packet is sent to another device while destination port are the ports found in a destination device that receives IP packets from source ports they are found in many internet applications
Write a program that reads ten integers, and then display the number of even numbers and odd numbers. Assume that the input ends with 0. Here is the sample run of the program
Answer:
I am writing a JAVA program. Let me know if you want this program in some other programming language.
import java.util.Scanner; // class to take input from user
class EvenOddNum{ //class name
static void EvenOdd(int array[]) { //function that takes an array as input and displays number of even numbers and odd numbers
int even = 0; // counts even numbers
int odd = 0; //counts odd numbers
for(int i = 0 ; i < array.length-1 ; i++){ //loop through the array elements till the second last array element
if ((array[i] % 2) == 1) { // if the element of array is not completely divisible by 2 then this means its an odd number
System.out.println(array[i]+" = odd"); //display that element to be odd
odd++ ; } //adds 1 to the count of odd every time the program reads an odd number
else{ // if above IF condition evaluates to false then the number is an even number
System.out.println(array[i]+" = even"); //display that element to be odd
even++ ; } } //adds 1 to the count of odd every time the program reads an odd number
System.out.println( "Number of even numbers = " + even); //counts the total number of even integers in the array
System.out.println( "Number of odd numbers = " + odd); } //counts the total number of odd integers in the array
public static void main (String[] args){ //start of main function body
Scanner scan= new Scanner(System.in); //creates Scanner class object
int [] integers = new int[10]; //declares an array named integers that stores 10 integers
System.out.print("Enter numbers: "); //prompts user to enter the integers
for(int i = 0;i<integers.length;i++){ //loops to read the input integers
integers[i] = scan.nextInt(); } //scans and reads each integer value
EvenOdd(integers); } } //calls function EvenOdd to display number of even and odd numbers
Explanation:
The program has a method EvenOdd that takes an array of integers as its parameter. It has two counter variables even and odd. even counts the number of even input integers and odd counts the number of odd input integers. The for loop iterates through each element (integer) of the array except for the last one. The reason is that it is assumed that the input ends with 0 so the last element i.e. 0 is not counted. So the loop iterates to length-1 of the array. The number is odd or even is determined by this if condition: if ((array[i] % 2) == 1) A number is even if it is divisible by 2 otherwise its odd. If the element of array is not completely divisible by 2 i.e. the remainder of the division is not 0 then the number is odd. The modulo operator is used which returns the remainder of the division of number by 2. Each time when an odd or even number is determined, the array[i]+" = even" or array[i]+" = odd" is displayed on the output screen for each integer in the array. Here array[i] is the element of the array and even or odd depicts if that element is even or odd. The last two print statement display the total number of even and odd numbers in the array.
Which statement is false?Structures are derived data types.Each structure definition must end with a semicolon.A structure can contain an instance of itself.Structures may not be compared using operators == and !=.
Answer:
A structure can contain an instance of itself
Explanation:
The statement which is known to be false out of the option given is that a structure may comprise or contain an instance of itself. Because to my knowledge, variables of diverse type are always most likely to attributed and contain by a structure.
It is worthy of note that object that aren't similar are utilize in constructing a structure. Another true statement about structure is that a semicolon usually end it's explanation.
The code below takes the list of country, country, and searches to see if it is in the dictionary gold which shows some countries who won gold during the Olympics. However, this code currently does not work. Correctly add try/except clause in the code so that it will correctly populate the list, country_gold, with either the number of golds won or the string "Did not get gold".
1
2 gold = {"US":46, "Fiji":1, "Great Britain":27, "Cuba":5, "Thailand":2, "China":26, "France":10}
3 country = ["Fiji", "Chile", "Mexico", "France", "Norway", "US"]
4 country_gold = []
5
6 for x in country:
7 country_gold.append(gold[x])
8 country_gold.append("Did not get gold")
Answer:
Modify your program by replacing
for x in country:
country_gold.append(gold[x])
country_gold.append("Did not get gold")
with
for x in country:
try:
country_gold.append(gold[x])
except:
country_gold.append("Did not get gold")
Explanation:
The addition of try/except clause in the program is to let the program manage error;
In this case, the program checks for a country in the list country; This is implemented using the following line
for x in country:
If the country exists, the statement in the try block is executed
try:
country_gold.append(gold[x]) ->This appends the country name to the country_gold list
Otherwise, the statement in the except clause is executed
except:
country_gold.append("Did not get gold") -> This appends "Did not get gold" to the country_gold list
To confirm what you've done, you may add the following line of code at the end of the program: print(country_gold)
An admission charge for The Little Rep Theater varies according to the age of the person. Develop a solution to print the ticket charge given the age of the person. The charges are as follows:
a. Over 55: $10.00
b. 21-54: $15.00
c. 13-20: $10.00
d. 3-12: $5.00
e. Under 3: Free
Use a Multiple Alternative IF Statement
Answer:
age = int(input("Enter your age: "))
charge = 0
if age > 55:
charge = 10
if 21 <= age <= 54:
charge = 15
if 13 <= age <= 20:
charge = 10
if 3 <= age <= 12:
charge = 5
if 0 <= age < 3:
charge = 0
print(charge)
Explanation:
*It is in Python.
Ask the user for the age
Check the each given range and set the charge accordingly using if statements
Print the charge
An Open Authorization (OAuth) access token would have a _____ that tells what the third party app has access to
Answer:
scope
Explanation:
An Open Authorization refers to a method that helps to share data using third party services without giving your credentials and there is a mechanism in an Open Authorization that allows to limit the access that the third party app has to an account that is called scope. Because of that, the answer is that an Open Authorization (OAuth) access token would have a scope that tells what the third party app has access to because it is what limits the access the app has to an account and it shows the access given in a consent screen.
1. Two TCP entities communicate across a reliable network. Let the normalized time to transmit a fixed length segment equal 1. Assume that the end-to-end propagation delay is 3 and that it takes 2 to deliver data from a received segment to the transport user. The receiver initially grants a credit of 7 segments. The receiver uses a conservative flow control policy and updates its credit allocation at every opportunity. What is the maximum achievable throughput
Answer:
The answer is "0.77"
Explanation:
The fixed-length segment value = 1
The propagation time of one end to another end is = 3
The Transfer power to move the consumer from the obtained segment = 2
The second last sender assigns a loan = 7 segments
The overall transmission time = 3+2+3 = 8
The maximum throughput value is:
[tex]\to \frac{7}{(1 + 8)}\\\\ \to \frac{7}{9}\\\\\to 0.77[/tex]
The machine has to be returned to the vendor for proper recycling. Which stage of the hardware lifecycle does this scenario belong to?
Answer:
Decommission/Recycle
Explanation:
This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.
g Write a program that asks for the weight of a package and the distance it is to be shipped. This information should be passed to a calculateCharge function that computes and returns the shipping charge to be displayed . The main function should loop to handle multiple packages until a weight of 0 is entered.
Answer:
I am writing a C++ program:
#include <iostream> //to use input output functions
#include<iomanip> // to format the output
using namespace std; // to identify objects like cin cout
void calculateCharge(double weight, double distance); // function prototype
int main(){ //start of main() function body
double w = 0.0, t = 0.0; // w variable is for weight and t is for total
unsigned int d = 0; // d variable is to hold the value of distance
calculateCharge(w, d); } //calls calculateCharge method by passing weight and distance values to this method
void calculateCharge(double weight, double distance){ //method that takes weight and distance as parameters and compute the shipping charge
double charge = 0.0; //to store the value of shipping charges
do { // do while loop to handle multiple packages until a weight of 0 is entered
cout << "Enter weight: " << endl; //prompts user to enter weight
cin >> weight; //reads the input weight value
if (weight == 0){ // if the value of weight is equal to 0
break; } // the loop breaks if value of weight is 0
cout << "Enter distance: " << endl; // if value of weight is not zero then the program precedes by prompting user to enter the value of distance
cin >> distance; //reads the input distance value
cout << fixed << setprecision(2) << endl; //set the precision to 2 means the sets the number of digits of an output to 2 decimal places
if(weight <= 2) //if the value of weight is less than or equals to 2
charge = (distance/500) * 3.10; //compute the charge by this formula
else if(weight > 2 && weight <= 6) //if weight is over 2 kg but not more than 6 kg
charge = (distance/500) * 4.20; //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first
else if(weight > 6 && weight <= 10) // if weight is over 6 kg but not more than 10 kg
charge = (distance/500) * 5.30; //compute shipping charges by this formula
else //if weight is over 10 kg
charge = (distance/500) * 6.40; // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first
cout << "Shipping charges: $" << charge << "\n"; //display the computed shipping charge
} while (weight != 0); //the loop continues to execute until weight 0 is entered
}
Explanation:
The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.
In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.
The screenshot of the program and its output is attached.
_____ are networks that learn and are capable of performing tasks that are difficult with conventional computers.
Answer:
Artificial Neural
Explanation:
An artificial neural is the piece of a computing system designed to simulate the way the human brain analyzes and processes information. It is the foundation of artificial intelligence.
Describe in detail how TCP packets flow in the case of TCP handoff, along with the information on source and destination addresses in the various headers.
Answer:
Following are the answer to this question:
Explanation:
There will be several ways to provide it, although it is simpler to let another front side Will work out a three-way handshake or transfer packages to there with a Server chosen. Its application responds TCP packets with both the destination node of the front end.
The very first packet was sent to a computer as an option. Mention, even so, that perhaps the end of the queue end remains in the loop in this scenario. Rather than obtaining this information from the front end like in the primary healthcare services, you have the advantage of this capability: its selected server helps to generate TCP state.
Define a method printAll() for class PetData that prints output as follows with inputs "Fluffy", 5, and 4444. Hint: Make use of the base class' printAll() method. Name: Fluffy, Age: 5, ID: 4444
Answer and Explanation:
public class petData
{
private int ageYears;
private String fullName;
private int IdNumber;
public void setName (String givenName)
{
fullName = givenName;
return;
}
public void setAge (int numYears)
{
ageYears = numYears;
return;
}
public void setID (int numID)
{
IdNumber = numID;
return;
}
public void printAll ()
{
System.out.print ("Name: " + fullName);
System.out.print (", Age: " + ageYears);
return;
}
}
From the above, we have defined a class petData, with methods setName, setAge, printAll. These methods all make use of the string variable fullName and integer variable ageYears. From the above, setName method sets fullName variable to name given to its string parameter givenName while setAge method does the same with the ageYears variable in initializing it. This is also done by the ID method. These variables are then used by printAll method in printing out the Name and age of the object which would be created with the petData class
E. g: petData dog= new petData();
A technician wants to configure the inbound port of a router to prevent FTP traffic from leaving the LAN.
Which of the following should be placed on the router interface to accomplish this goal?
A. Static routes for all port 80 traffic
B. DHCP reservations for all /24 subnets
C. ACL for ports 20 and 21
D. MAC filtering using wildcards
Answer:
The technician will want to add ACL for ports 20 and 21
Explanation:
The FTP protocol by default will attempt to use 21 for TCP access and 20 for data access. By enabling an Access Control List (ACL) on ports 20 and 21, the technician can prevent FTP traffic from leaving the network on the default ports.
Cheers.
#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The function will look for the search string within the #target string. # #The function should return a string representing where in #the target string the search string was found: # # - If search string is at the very beginning of target # string, then return "Beginning". For example: # string_finder("Georgia Tech", "Georgia") -> "Beginning" # # - If search string is at the very end of target string, # then return "End". For example: # string_finder("Georgia Tech", "Tech") -> "End" # # - If search string is in target string but not at the # very beginning or very end, then return "Middle. For # example: # string_finder("Georgia Tech", "gia") -> "Middle" # # - If search string is not in target string at all, then # return "Not found". For example: # string_finder("Georgia Tech", "Idaho") -> "Not found" # #Assume that we're only interested in the first instance #of the search string if it appears multiple times in the #target string, and that search string is definitely #shorter than target string. # #Hint: Don't be surprised if you find that the "End" case #is the toughest! You'll need to look at the lengths of #both the target string and the search string. #Write your function here!
Answer:
I am writing a Python program:
def string_finder(target,search): #function that takes two parameters i.e. target string and a search string
position=(target.find(search))# returns lowest index of search if it is found in target string
if position==0: # if value of position is 0 means lowers index
return "Beginning" #the search string in the beginning of target string
elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings
return "End" # returns end
elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1
return "Middle" #returns middle
else: #if none of above conditions is true return not found
return "not found"
#you can add an elif condition instead of else for not found condition as:
#elif position==-1
#returns "not found"
#tests the data for the following cases
print(string_finder("Georgia Tech", "Georgia"))
print(string_finder("Georgia Tech", "gia"))
print(string_finder("Georgia Tech", "Tech"))
print(string_finder("Georgia Tech", "Idaho"))
Explanation:
The program can also be written in by using string methods.
def string_finder(target,search): #method definition that takes target string and string to be searched
if target.startswith(search): #startswith() method scans the target string and checks if the (substring) search is present at the start of target string
return "Beginning" #if above condition it true return Beginning
elif target.endswith(search): #endswith() method scans the target string and checks if the (substring) search is present at the end of target string
return "End" #if above elif condition it true return End
elif target.find(search) != -1: #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string
return "Middle" #if above elif condition it true return End
else: #if none of the above conditions is true then returns Not Found
return "Not Found"
Write a Python program that asks the user for a positive, odd value. Once the value is validated determine if the number is Prime (i.e., divisible only by itself and 1.)
Answer:
val = int(input("Enter a positive odd value "))
flag = True # let the number entered is alreay prime
if(val > 2 and val%2 == 1): # prime numbers start from 2
half = int(val/2);
for div in range(2,half): # dividing the number from 2 to half of its number
if(val % div == 0): # if completely divisible
print("Not prime")
flag = False # Changing the status of prime number as false
break
if(flag == True):
print(val, "is a prime number")
else:
print("Invalid input, Please Enter a valid positive odd number")
Explanation:
Steps:
1. Let us take input from the user using input() method.
2. Initially, let the number is prime.
3. If the number is negative or even, the go to else part and ask the user for a valid input and terminate the program by giving a message to user.
(We actually check for values greater than 2 because 1 is not considered as a prime number)
4. If the number is positive and odd, then we keep on dividing the number from 2 to half of its number.
(We actually check for values greater than 2 because 1 is not considered as a prime number)
5. If the number is divisible, we change the status to False and break the loop.
6. If the flag is still True, we print that it is a Prime number else we print that it is not a prime number.
Please refer to the comments section as well and the attached image for proper indentation of the program.
Passing structured query language commands to a web application and getting the website to execute it is called SQL script:______.
A) Injection.
B) Processing.
C) Attacking.
D) Execution.
Answer:
(A) Injection
Explanation:
SQL injection is one of the most common web attacks used by attackers to steal data or compromise a web application (especially the database) by inserting or "injecting" SQL queries or commands through the input data from the web application.
In web applications, form inputs are used to make requests to the database either for validation or submission of data by executing queries in the database. If these queries are interfered with by passing query like commands into the form input fields rather than some regular alphanumeric characters, then we have an SQL injection.
When this happens;
i. the attackers can modify an SQL query to return additional results from the database
ii. the attackers can change a query to interfere with the application's regular logic flow.
iii. the attackers can extract sensitive information about the database such as its version and structure.
Consider the following code segment. It should display a message only if the cost is between 50 and 75 dollars. The message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. if _________________ : print("The cost is in the desired range") What condition should be placed in the blank to achieve the desired behavior
Answer:
In C++ it can be written as:
if(cost>=50&&cost<=75)
{ cout<<"The cost is in the desired range";}
In Python:
if(cost <= 75 and cost>= 50):
print("The cost is in the desired range")
Explanation:
cost>50&&cost<75 covers the requirement that cost should be between 50 and 75 dollars
But the whole statement cost>=50&&cost<=75 covers the requirement that cost should be between 50 and 75 dollars and message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. For example if the value of cost=50 then this message The cost is in the desired range is displayed.
In the above program && in C++, and in Python is used which is a logical operator which means that both the conditions cost <= 75 and cost>= 50 should be true for the if condition to evaluate to true. For example if cost=35 then this message is not printed because both the conditions are false i.e. 35 is neither less than or equal to 75 nor greater than or equal to 50.
Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times the character appears in the phrase. Ex: If the input is:
Answer:
The program written in python is as follows
def countchr(phrase, char):
count = 0
for i in range(len(phrase)):
if phrase[i] == char:
count = count + 1
return count
phrase = input("Enter a Phrase: ")
char = input("Enter a character: ")
print("Occurence: ",countchr(phrase,char))
Explanation:
To answer this question, I made use of function
This line defines function countchr
def countchr(phrase, char):
This line initializes count to 0
count = 0
This line iterates through each character of input phrase
for i in range(len(phrase)):
This line checks if current character equals input character
if phrase[i] == char:
The count variable is incremented, if the above condition is true
count = count + 1
The total number of occurrence is returned using this line
return count
The main method starts here; This line prompts user for phrase
phrase = input("Enter a Phrase: ")
This line prompts user for a character
char = input("Enter a character: ")
This line prints the number of occurrence of the input charcater in the input phrase
print("Occurence: ",countchr(phrase,char))
#The Fibonacci sequence is a number sequence where each #number is the sum of the previous two numbers. The first #two numbers are defined as 0 and 1, so the third number is #1 (0 + 1 = 1), the fourth number is 2 (1 + 1 = 2), the #fifth number is 3 (1 + 2 = 3), the sixth number is 5 #(2 + 3 = 5), and so on.
#
#Below we've started a class called FibSeq. At any time, #FibSeq holds two values from the Fibonacci sequence: #back1 and back2.
#
#Create a new method inside FibSeq called next_number. The #next_number method should:
#
# - Calculate and return the next number in the sequence, # based on the previous 2. # - Update back2 with the former value of back1, and update # back1 with the new next item in the sequence.
#
#This means that consecutive calls to next_number should #yield each consecutive number from the Fibonacci sequence. #Calling next_number 5 times would print 1, 2, 3, 5, and 8.
class FibSeq:
def __init__(self):
self.back1 = 1
self.back2 = 0
def next_number(self):
self.back1=self.back1+self.back2 # updated the back1 value to the next number in the series first
self.back2=self.back1-self.back2 #updated the back2 value with previous back1 value
yield (self.back1) # yielded the next number in the series since it is updated as back1 so yielded back1
f = FibSeq()
for i in range(5): # here i have iterated the series only 5 times u can change it as you like
s=f.next_number()
print(next(s))# here next is an iterator function for the yield generator.
#The code below will test your method. It's not used for
#grading, so feel free to change it. As written, it should
#print 1, 2, 3, 5, and 8.
newFib = FibSeq()
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
Answer:
Here is the next_number method:
def next_number(self): #method to return next number in the sequence
temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable
self.back2 = self.back1 #Updates back2 with the former value of back1,
self.back1 = temporary #update back1 with the new next item in the sequence.
return temporary #
Explanation:
I will explain the working of the above method.
back1 = 1
back2 = 0
At first call to next_number() method:
temporary = back1 + back2
= 1 + 0
temporary = 1
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 1
return temporary
This return statement returns the value stored in temporary variable i.e. 1
Output: 1
back1 = 1
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 1 + 1
temporary = 2
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 2
return temporary
This return statement returns the value stored in temporary variable i.e. 2
output: 2
back1 = 2
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 2 + 1
temporary = 3
self.back2 = self.back1
self.back2 = 2
self.back1 = temporary
self.back1 = 3
return temporary
This return statement returns the value stored in temporary variable i.e. 3
Output: 3
back1 = 3
back2 = 2
At second call to next_number() method:
temporary = back1 + back2
= 3 + 2
temporary = 5
self.back2 = self.back1
self.back2 = 3
self.back1 = temporary
self.back1 = 5
return temporary
This return statement returns the value stored in temporary variable i.e. 5
Output: 5
back1 = 5
back2 = 3
At second call to next_number() method:
temporary = back1 + back2
= 5 + 3
temporary = 8
self.back2 = self.back1
self.back2 = 5
self.back1 = temporary
self.back1 = 8
return temporary
This return statement returns the value stored in temporary variable i.e. 8
Output: 8
Calling next_number 5 times would print 1, 2, 3, 5, and 8.
The complete program along with its output is attached.
Consider these functions:_________.
def f(x) :
return g(x) + math.sqrt(h(x))
def g(x):
return 4 h(x)
def h(x):
return x x + k(x)-1
def k(x):
return 2 (x + 1)
Without actually compiling and running a program, determine the results of the following function calls.
a. x1 = f(2)
b. x2 = g(h(2)
c. x3 = k(g(2) + h(2))
d. x4 - f(0) + f(l) + f(2)
e. x5 - f{-l) + g(-l) + h(-1) + k(-l)
Answer:
x1 = 39
x2 = 400
x3 = 92
x4 = 62
x5 = 0
Explanation:
a. x1 = f(2)This statement calls the f() function passing 2 to the function. The f(x) function takes a number x as parameter and returns the following:
g(x) + math.sqrt(h(x))
This again calls function g() and h()
The above statement calls g() passing x i.e. 2 to the function g(x) and calls function h() passing x i.e. 2 to h() and the result is computed by adding the value returned by g() to the square root of the value returned by the h() method.
The g(x) function takes a number x as parameter and returns the following:
return 4*h(x)
The above statement calls function h() by passing value 2 to h() and the result is computed by multiplying 4 with the value returned by h().
The h(x) function takes a number x as parameter and returns the following:
return x*x + k(x)-1
The above statement calls function k() by passing value 2 to k() and the result is computed by subtracting 1 from the value returned by k() and adding the result of x*x (2*2) to this.
The k(x) function takes a number x as parameter and returns the following:
return 2 * (x + 1)
As the value of x=2 So
2*(2+1) = 2*(3) = 6
So the value returned by k(x) is 6
Now lets go back to the function h(x)
return x*x + k(x)-1
x = 2
k(x) = 6
So
x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9
Now lets go back to the function g(x)
return 4*h(x)
As x = 2
h(x) = 9
So
4*h(x) = 4*9 = 36
Now lets go back to function f(x)
return g(x) + math.sqrt(h(x))
As x=2
g(x) = 36
h(x) = 9
g(x) + math.sqrt(h(x)) = 36 + math.sqrt(9)
= 36 + 3 = 39
Hence
x1 = 39b. x2 = g(h(2) )The above statement means that first the function g() calls function h() and function h() is passed a value i.e 2.
As x=2
The function k() returns:
2 * (x + 1) = 2 * (2 + 1) = 6
The function h() returns:
x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9
Now The function g() returns:
4 * h(x) = 4 * h(9)
This method again calls h() and function h() calls k(). The function k() returns:
2 * (x + 1) = 2 * (9 + 1) = 20
Now The function h() returns:
x*x + k(x)-1 = 9*9 + (20-1) = 81 + 19 = 100
h(9) = 100
Now The function g() returns:
4 * h(x) = 4 * h(9) = 4 * 100 = 400
Hence
x2 = 400c. x3 = k(g(2) + h(2))g() returns:
return 4 h(x)
h() returns:
return x*x + k(x)-1
k(2) returns:
return 2 (x + 1)
= 2 ( 3 ) = 6
Now going back to h(2)
x * x + k(x)-1 = 2*2 + 6 - 1 = 9
Now going back to g(2)
4 h(x) = 4 * 9 = 36
So k(g(2) + h(2)) becomes:
k(9 + 36 )
k(45)
Now going to k():
return 2 (x + 1)
2 (x + 1) = 2(45 + 1)
= 2(46)
= 92
So k(g(2) + h(2)) = 92
Hence
x3 = 92d. x4 = f(0) + f(1) + f(2)Compute f(0)
f() returns:
return g(0) + math.sqrt(h(0))
f() calls g() and h()
g() returns:
return 4 * h(0)
g() calls h()
h() returns
return 0*0 + k(0)-1
h() calls k()
k() returns:
return 2 * (0 + 1)
2 * (0 + 1) = 2
Going back to caller function h()
Compute h(0)
0*0 + k(0)-1 = 2 - 1 = 1
Going back to caller function g()
Compute g(0)
4 * h(0) = 4 * 1 = 4
Going back to caller function f()
compute f(0)
g(0) + math.sqrt(h(0)) = 4 + 1 = 5
f(0) = 5
Compute f(1)
f() returns:
return g(1) + math.sqrt(h(1))
f() calls g() and h()
g() returns:
return 4 * h(1)
g() calls h()
h() returns
return 1*1 + k(1)-1
h() calls k()
k() returns:
return 2 * (1 + 1)
2 * (1 + 1) = 4
Going back to caller function h()
Compute h(0)
1*1 + k(1)-1 = 1 + 4 - 1 = 4
Going back to caller function g()
Compute g(1)
4 * h(1) = 4 * 4 = 16
Going back to caller function f()
compute f(1)
g(1) + math.sqrt(h(1)) = 16 + 2 = 18
f(1) = 18
Compute f(2)
f() returns:
return g(2) + math.sqrt(h(2))
f() calls g() and h()
g() returns:
return 4 * h(2)
g() calls h()
h() returns
return 1*1 + k(2)-1
h() calls k()
k() returns:
return 2 * (2+1)
2 * (3) = 6
Going back to caller function h()
Compute h(2)
2*2 + k(2)-1 = 4 + 6 - 1 = 9
Going back to caller function g()
Compute g(2)
4 * h(2) = 4 * 9 = 36
Going back to caller function f()
compute f(2)
g(2) + math.sqrt(h(2)) = 36 +3 = 39
f(1) = 13.7
Now
x4 = f(0) + f(l) + f(2)
= 5 + 18 + 39
= 62
Hence
x4 = 62e. x5 = f(-1) + g(-1) + h(-1) + k(-1)Compute f(-1)
f() returns:
return g(-1) + math.sqrt(h(-1))
f() calls g() and h()
g() returns:
return 4 * h(-1)
g() calls h()
h() returns
return 1*1 + k(-1)-1
h() calls k()
k() returns:
return 2 * (-1+1)
2 * (0) = 0
Going back to caller function h()
Compute h(-1)
-1*-1 + k(-1)-1 = 1 + 0 - 1 = 0
Going back to caller function g()
Compute g(-1)
4 * h(-1) = 4 * 0 = 0
Going back to caller function f()
compute f(-1)
g(-1) + math.sqrt(h(-1)) = 0
f(-1) = 0
Compute g(-1)
g() returns:
return 4 * h(-1)
g() calls h()
h() returns
return 1*1 + k(-1)-1
h() calls k()
k() returns:
return 2 * (-1+1)
2 * (0) = 0
Going back to caller function h()
Compute h(-1)
-1*-1 + k(-1)-1 = 1 + 0 - 1 = 0
Going back to caller function g()
Compute g(-1)
4 * h(-1) = 4 * 0 = 0
g(-1) = 0
Compute h(-1)
h() returns
return 1*1 + k(-1)-1
h() calls k()
k() returns:
return 2 * (-1+1)
2 * (0) = 0
Going back to caller function h()
Compute h(-1)
-1*-1 + k(-1)-1 = 1 + 0 - 1 = 0
h(-1) = 0
Compute k(-1)
k() returns:
return 2 (x + 1)
k(-1) = 2 ( -1 + 1 ) = 2 ( 0 ) = 0
k(-1) = 0
x5 = f(-1) + g(-1) + h(-1) + k(-1)
= 0 + 0 + 0 + 0
= 0
Hence
x5 = 0What is a real-life example of a Microsoft Access Query?
Explanation:
Microsoft Access is an information management tool that helps you store information for reference, reporting, and analysis. Microsoft Access helps you analyze large amounts of information, and manage related data more efficiently than Microsoft Excel or other spreadsheet applications.
A real-life example of a Microsoft Access Query is a table that stores the names of new customers at a supermarket.
What is Microsoft Access?Microsoft Access is a database management software application designed and developed by Microsoft Inc., in order to avail its end users an ability to create, store and add data to a relational database.
In Microsoft Access, the options that are available on the File tab include the following:
Opening a database.
Selecting a template.
Creating a new database.
In conclusion, a database is an element in Microsoft Access which is an ideal data source and a query would always obtain, generate, or pick information from it.
Read more on Microsoft Access here: brainly.com/question/11933613
#SPJ2
Write a program that writes a series of random numbers to a file. Each random number should be in the range of 1 through 1000. The application should let the user specify how many random numbers the file will hold.
Answer:
The programming language is not stated;
I'll answer this question using python programming language
The program starts here (Lines written in bold are comments and are used for explanatory purpose)
#This line imports the random module into the program
import random
#This line prompts the user to enter the filename
filename = input("Enter file name: ")
#This line prompts the user to enter the number of random numbers to generate
num = int(input("Number of random numbers: "))
#This line adjusts the filename to a .txt file
filename = filename+".txt"
#This line checks if the filename exists; if yes, it creates and open a new file and if otherwise, it uses the existing filr
f = open(filename,'a+')
#This line iterates through the number of random to generate
for i in range(1,num+1):
#This line generates random number within the range of 1 to 1000
n = random.randint(1,1000)
#This line prints the generated random number to file
print(n, file = f)
#This line closes the created file
f.close()
A company wants a recruiting app that models candidates and interviews; displays the total number of interviews on each candidate record; and defines security on interview records that is independent from the security on candidate records. What would a developer do to accomplish this task? Choose 2 answers
a. Create a roll -up summary field on the Candidate object that counts Interview records.
b. Create a master -detail relationship between the Candidate and Interview objects.
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Answer:
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Explanation:
Objects relationships is considered a form of field type that joins two or more objects together such that, after understanding objects and fields, it creates some form of bonding known as object relationships. This helps define security on interview records that is independent from the security on candidate records.
For an example, in a standard object like Account, where a sales representative opens an account, and has had interviews or chats with a few people at that account’s company, and as well made contacts with the likes of executives or IT managers and still stored those contacts’ information in salesforce.
Hence, what would a developer do to accomplish this task is to:
1. Create a lookup relationship between the Candidate and Interview objects.
2. Create a trigger on the Interview object that updates a field on the Candidate object.
Suppose that we want to multiply 500 matrices and we use the optimal parenthesization computed by the MATRIX-CHAIN-ORDER function discussed in class. After finding the optimal parenthesization, how many pairs of round brackets ( ) are printed by the procedure PRINT-OPTIMAL-PARENS(s, 1, 500)?
a. 249
b. 501
c. 251
d. 250
e. 499
f. 500
Answer:
síganme en las claves de ustedes pronto. Seré un buen día. He seguido un poco sobre el Is. He seguido un poco sobre el Is. He seguido un poco sobre el.
is (c)251? correct since i'm not really sure