Answer:
An induction is the process a new recruit goes through to be introduced to the company and their new role. ... Beyond the initial days, the induction programme continues for many months, so that the new employee can fully integrate into life in the company and settle into their role to become a valuable member of staff.
Explanation:
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A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Answer:
After 3secondsExplanation:
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Using the formula for calculating speed expressed as;
Speed = Distance/Time
Given;
Distance = 3km = 3000m
Speed = 1000m/s
Required
How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)
From the formula;
Time = Distance/speed
Time = 3000/1000
Time = 3seconds
Hence the sound of the aircraft is heard after 3 seconds
if a block weight 60N and is lying on a side with area 2m by 3m. what is the pressure exerted on the surface?
Answer:
10 Pa
Explanation:
Pressure is defined as force per unit area.
Mathematically, P= F/A where P is pressure, F is force and A is area.
Force, F = 60 N
Area, A = 2*3 = 6m²
P = 60/6 = 10 Pa
I need help with magnitudes of net force
An object 2.7 cmtall is placed12 cmin front of a mirror. •What type of mirror and what radius of curvature are needed to createan upright image that is 5.4 cm in height? •What is the magnification of the image?
Answer:
a. Concave mirror, radius of curvature = 16 cm b. magnification = 2
Explanation:
a. Since the image is upright and larger than the object, we need a concave mirror.
We know image height, h'/object height, h = -image distance, d'/object distance, d
h'/h = -d'/d
Using the real is positive convention,
h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.
So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm
2 = -d'/12
d' = -2 × 12 cm
= -24 cm
Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror
1/+12 + 1/- 24 = 2/r
1/12(1 - 1/2) = 2/r
1/12(1/2) = 2/r
1/24 = 2/r
r/2 = 24
r = 2 × 24
r = 48 cm
b.
magnification = image height, h'/object height,h = + 5.4 cm/+ 2.7 cm = 2
as an object falls a greater distance, does the speed at which it is falling increase or decrease
Answer:
Increase
Explanation:
If an object is falling for a greater distance, it will gain momentum and speed up.
(-243)^-6/5 evaluate the expression
Answer:
[tex] \frac{1}{ - 729} [/tex]
Explanation:
(-243)^-6/5
[1/(-243)] ^6/5
[tex]( \frac{1}{ - 243} ) {}^{6 \div 5} [/tex]
[tex] (\frac{1}{( - 3)} ) {}^{5} ) {}^{6 \div 5} [/tex]
[tex]( \frac{1}{ - 3} ) {}^{6} [/tex]
[tex] \frac{1}{ - 729} [/tex]
0.0884 moles of a diatomic gas
are in a piston. When the piston
is compressed, the temperature
drops by 18.8 K, and 83.7 J of
heat flow out. Find W.
(Be careful with + and - signs.
+W = expansion, +Q = added,
+AU = temp goes up)
(Unit = J)
Answer:
W = - 118.24 J (negative sign shows that work is done on piston)
Explanation:
First, we find the change in internal energy of the diatomic gas by using the following formula:
[tex]\Delta\ U = nC_{v}\Delta\ T[/tex]
where,
ΔU = Change in internal energy of gas = ?
n = no. of moles of gas = 0.0884 mole
Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)
Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K
ΔT = Rise in Temperature = 18.8 K
Therefore,
[tex]\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J[/tex]
Now, we can apply First Law of Thermodynamics as follows:
[tex]\Delta\ Q = \Delta\ U + W[/tex]
where,
ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)
W = Work done = ?
Therefore,
[tex]-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\[/tex]
W = - 118.24 J (negative sign shows that work is done on piston)
Answer:
-49.2
Explanation:
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I'm getting conflicting information on brainly about this question. It's either fly-by or GPS satellites...
What constitute the most common way that images of space are captured?
A. Fly-by missions
B. Drones landing on planets
C. GPS satellites in Earth's orbit
D. Astronauts visiting the
international space center
Answer:
C
Explanation:
GPS satellites in Earth's orbit constitute the most common way that images of space are captured.
I hope this helps! And this is the real answer.
Indentify the following types of reflection.
Answer:
first is regular reflection and 2nd is irregular
derivative equation of F = kx
Given that,
The equation is "F=kx"
To find,
The derivative equation.
Solution,
We are given with the given equation which is as follows :
F = kx ...(1)
Where, F is force, k is spring constant and x is distance covered by the spring
Differentiate equation (1) wrt x.
[tex]\dfrac{dF}{dx}=\dfrac{d}{dx}(kx)\\\\\dfrac{dF}{dx}=k[/tex]
As k is constant.
Hence, this is the required solution.
When a fan is switched on, it undergoes an angular acceleration of 150 rad/s2. How long will it take to achieve its maximum angular velocity of 50 rad/s?
Answer:
The time to attain the maximum angular velocity is 0.33 s.
Explanation:
Given;
angular acceleration of the fan, α = 150 rad/s²
maximum angular velocity, [tex]\omega_f[/tex] = 50 rad/s
When a fan is switched on, the initial angular velocity, [tex]\omega_i = 0[/tex]
The time to attain the maximum angular velocity is given by;
[tex]\omega_f = \omega_i +\alpha t\\\\50 = 0 + 150t\\\\t = \frac{50}{150}\\\\t = 0.33 \ s[/tex]
Therefore, the time to attain the maximum angular velocity is 0.33 s.
A 3 kg mass is travelling in a circle of 0.1 m radius with a speed of 2 m/s. What is the centripetal acceleration?
a = v² / R = (2 m/s)² / (0.1 m) = 40 m/s²
3. If an x-ray imaging system is operated at 800 mA, 2000 ms, the total
mAs will be?
What happens to liquid nitrogen when it gets warmer?
Answer:
see below
Explanation:
It boils (or evaporates) and becomes gaseous nitrogen like water turns to water vapor when it gets warm enough
Mistakes were made" is a classic passive voice confession. President Ronald Reagan famously said "mistakes were made" by his administration during the Iran Contra scandal. But some people said he wasn't directly taking the blame. This is why some writers choose to use the passive voice. It can sidestep the question of who did something.
Based on this passage, a writer may use the passive voice to
A
give the reader all known information about a criminal and his or her crimes.
B
clarify the person who was responsible for a crime.
C
describe a crime without blaming anyone for committing it.
D
take responsibility for committing a crime.
Find the total current through this circuit
Answer:
I=0.02[amp]
Explanation:
Since the resistors are connected in series, we can find the total resistance.
[tex]Rt = 100 + 300+50\\Rt = 450[ohm][/tex]
Now we can use ohm's law which tells us that the voltage is equal to the product of resistance by the current.
[tex]V =I*R\\I=V/R\\I=9/450\\I=0.02[amp][/tex]
how much power an appliance uses
Answer:
it depends on the appliance
Explanation:
bigger appliances will use more power, smaller appliances will use a lesser amount
Uranium-235 undergoes fission, forming krypton-92, barium-141, and 3
neutrons. The mass of the uranium-235 is greater than the total mass of the
products. Which statement explains this difference in mass?
A. Some of the mass was transformed into neutrons during the
process.
O B. Mass was destroyed and disappeared during the process.
C. Some of the mass was transformed into gases during the
process.
D. Mass was transformed into energy during the process.
Answer:
C
Explanation:
Some of the mass
Answer:
D. Mass was transformed into energy during the process.
A projectile is fired vertically from Earth's surface with an initial speed of 3.1 km/s. Neglecting air drag, how far above the surface of Earth will it go
Answer:
The maximum height reached by the projectile is 490.31 km.
Explanation:
Given;
initial velocity of the projectile, u = 3.1 km/s = 3100 m/s
acceleration due to gravity, g = 9.8 m/s²
The maximum height reached by the projectile is calculated as;
v² = u² - 2gh
where;
v is the final velocity of the projectile at maximum height = 0
h is the maximum height reached by the projectile
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (3100²) / (2 x 9.8)
h = 490306.122 m
h = 490.31 km
Therefore, the maximum height reached by the projectile is 490.31 km.
• The net force acting on an object equals the applied force plus the force of friction.
True or False
Answer:
false
Explanation:
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What are the precautionary measures against earthquake?
Answer:
Seek shelter under stable tables or under door frames.
If outside, stay away from buildings, bridges and electricity pylons and move to open areas.
Avoid areas at risk from secondary processes, such as landslides, rockfall and soil liquefaction.
From
Measures against earthquakeswww.planat.ch › earthquake › measures-eb
A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an insulating material with dielectric constant of 40. If a potential is applied to this device of 2.0 mV, how much charge will accumulate on this capacitor, in terms of the number of charge carriers?
Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = [tex]\pi r^2[/tex]
V = Potential applied = 2 mV
k = Dielectric constant = 40
[tex]\epsilon_0[/tex] = Electric constant = [tex]8.854\times 10^{-12}\ \text{F/m}[/tex]
Capacitance is given by
[tex]C=\dfrac{k\epsilon_0A}{d}[/tex]
Charge is given by
[tex]Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}[/tex]
Number of electron is given by
[tex]n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}[/tex]
The number of charge carriers that will accumulate on this capacitor is approximately 289282.
In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt
This question is incomplete, the complete question is;
In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt /pi
Answer: the pt/pi is 15.3846%
Explanation:
Given that;
Background = 13 mV
corrected signal = 91 mV - 13 mV = 78 mV
with attenuator = 25 mV - 13 mV = 12 mV
pt/pi = ?
so pt/pi = 12/78 × 100
= 15.3846%
Therefore the pt/pi is 15.3846%
The graph represents the reaction 2H2 + 02 32H20 as it reaches
equilibrium. Based on the graph, which two statements about this reaction
are true?
Concentration (mol/L)
le
-H₂O
Time (s)
A. The rate of formation of products is equal to the rate of formation
of reactants only after point 4
B. After point 2, the rate of formation of products is equal to the rate
of formation of reactants.
C. At point 2, the concentrations of H20, O2, and H2 are all changing
toward their equilibrium concentrations.
D. At point 1. more reactants are converted to products than
products are converted to reactants.
Answer:
C and D
Explanation:
Answer:
C. at point 2 the concentrations of H20...O2... & H2 are all changing
toward their equilibrium concentrations
D. at point 1 more reactants are converted to products than
products are converted to reactants
What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are separated by 100 m?
Answer: 1.67 x 10^-7N
Explanation:
After concluding his research, which statements would Virchow agree with? Check all that apply.
O Living things come from nonliving things.
Cells can come from nonliving materials.
Frogs can come from mud.
O Living things can only
comeyom living things.
Cells come from pre-existing cells.
Answer:
A Living things can only come from living things.
B Cells come from pre-existing cells.
Explanation:
sorry if wrong e d g e 2022
Answer: D,E
Explanation:
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The batter swings and misses the 40 m/s (90 mph) fastball, and the ball (mass 150 grams) ends up at rest in the catcher's mitt. How much work does the catcher perform on the ball
Answer:
The work done by the catcher is 120 J.
Explanation:
Given;
velocity of the fastball, v = 40 m/s
mass of the fastball, m = 150 g = 0.15 kg
Based on work-energy theorem, the work done by the catcher is equal to the kinetic energy of the fastball.
The kinetic energy of the fastball is given as;
K.E = ¹/₂mv²
K.E = ¹/₂ x 0.15 x 40²
K.E = 120 J
Therefore, the work done by the catcher is 120 J.
Which one of the following statements contain a simile?
Answer:
I don't know if its just me, but I don't see the statements so I'm not sure how to help answer your question.
If 65 kW is to be transmitted over two 0.100 ohm lines, estimate how much power is saved if the voltage is stepped up from 120 V to 1200 V
Answer: 5.91kw
Explanation:
given data:
power = 65kw
voltage stepped up = 120v t0 1200
R 0.100
Solution:
when the it is stepped to 120v
[tex]P = VI \\65000/ 120I\\ I = 541.7A\\[/tex]
power loss
[tex](I^{2} )R*2\\= (541.7^{2})0.100*2\\= 58536.2w[/tex]
when it is stepped to 1200v
[tex]\frac{65000}{1200} \\ I = 54.17A\[/tex]
[tex](I^{2} )R*2\\= (54.17^{2})0.100*2\\= 586.9w[/tex]
total power saved
[tex]= 65kw - 58.5kw - 0.59kw\\= 5.91kw[/tex]
A 100 g ball collides elastically with a 300 g ball that is at rest. If the 100 g ball was traveling
in the positive x-direction at 6.20 m/s before the
collision, what are the velocities of the two
balls after the collision?
Answer:
The magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).
Explanation:
We can find the velocity of the two balls after the collision by conservation of linear momentum and energy:
[tex] P_{1} = P_{2} [/tex]
[tex] m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
Where:
m₁: is the mass of the ball 1 = 100 g = 0.1 kg
m₂: is the mass of the ball 2 = 300 g = 0.3 kg
[tex]v_{1_{i}}[/tex]: is the initial velocity of the ball 1 = 6.20 m/s
[tex]v_{2_{i}}[/tex]: is the initial velocity of the ball 2 = 0 (it is at rest)
[tex]v_{1_{f}}[/tex]: is the final velocity of the ball 1 =?
[tex]v_{2_{f}}[/tex]: is the initial velocity of the ball 2 =?
[tex] m_{1}v_{1_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
[tex] v_{1_{f}} = v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}} [/tex] (1)
Now, by conservation of kinetic energy (since they collide elastically):
[tex] \frac{1}{2}m_{1}v_{1_{i}}^{2} = \frac{1}{2}m_{1}v_{1_{f}}^{2} + \frac{1}{2}m_{2}v_{2_{f}}^{2} [/tex]
[tex] m_{1}v_{1_{i}}^{2} = m_{1}v_{1_{f}}^{2} + m_{2}v_{2_{f}}^{2} [/tex] (2)
By entering equation (1) into (2) we have:
[tex] m_{1}v_{1_{i}}^{2} = m_{1}(v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}})^{2} + m_{2}v_{2_{f}}^{2} [/tex]
[tex] 0.1 kg*(6.20 m/s)^{2} = 0.1 kg*(6.2 m/s - \frac{0.3 kg*v_{2_{f}}}{0.1 kg})^{2} + 0.3 kg(v_{2_{f}})^{2} [/tex]
By solving the above equation for [tex]v_{2_{f}}[/tex]:
[tex]v_{2_{f}} = 3.1 m/s [/tex]
Now, [tex]v_{1_{f}}[/tex] can be calculated with equation (1):
[tex] v_{1_{f}} = 6.20 m/s - \frac{0.3 kg*3.1 m/s}{0.1 kg} = -3.1 m/s [/tex]
The minus sign of [tex] v_{1_{f}}[/tex] means that the ball 1 (100g) is moving in the negative x-direction after the collision.
Therefore, the magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).
I hope it helps you!