The expression 7/12x - y/6x² in its simplest form is (7x - 2y)/(12x²).
We have,
To simplify the expression 7/12x - y/6x², we need to find a common denominator for the two terms.
The common denominator is 12x^2.
Multiplying the first term by x/x and the second term by 2/2, we get:
(7x)/(12x²) - (2y)/(12x²)
Combining the two terms, we get:
(7x - 2y)/(12x²)
Therefore,
7/12x - y/6x² in its simplest form is (7x - 2y)/(12x^2).
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The sum of two numbers is 5 the product of the same two numbers is 20
The two numbers are 4 and 1.
What are the two numbers?To solve the problem, we will use algebraic equations.
We will call 2 numbers x and y. So, we know that:
------ x + y = 5 (equation 1)
------ xy = 20 (equation 2)
We will solve for y in terms of x:
y = 5 - x
We will substitute for y into equation 2 and simplify:
x(5 - x) = 20
5x - x^2 = 20
x^2 - 5x + 20 = 0
As a quadratic equation which will be solved using the quadratic formula, the solutions are x = 4 and x = 1. We can check that these solutions satisfy both equation 1 and equation 2.
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HELP I NEED TO TURN THIS IN IN 10 MINUTES!!
The doubling period of a bacterial population is 15 minutes. At time t=110 minutes, the bacterial population was 70000
What was the initial population at time t=0?
Find the side of the bacterial population after 5 hours
Answer:
Step-by-step explanation:
1. the initial population at t=0 is 1
2. 16
The product of two numbers is 126 . The smaller number is 5 less than the larger number. Which of the following equations can be used to solve for the larger number?
Answer:
Step-by-step explanation:
45
I need help ASAP!!
The length of a rectangle is 4 meters longer than its width.
The area of the rectangle is
117m^2.
What is the width of the rectangle?
HINT: you can use DESMOS for this kind of problem.
Answer:
w(w + 4) = 117
w^2 + 4w = 117
w^2 + 4w - 117 = 0
(w - 9)(w + 13) = 0
w = 9 meters
The width of the rectangle is 9 meters, and the length of the rectangle is 13 meters.
Write an equation for the parabola that has the
given vertex and passes through the given point.
Vertex
(0,0)
Point
(3,18)
[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} h=0\\ k=0\\ \end{cases}\implies y=a(~~x-0~~)^2 + 0\hspace{4em}\textit{we also know that} \begin{cases} x=3\\ y=18 \end{cases} \\\\\\ 18=a(3-0)^2+0\implies 18=9a\implies \cfrac{18}{9}=a\implies 2=a \\\\\\ y=2(~~x-0~~)^2 + 0\implies \boxed{y=2x^2}[/tex]
Triangle ABC ~ triangle DEF.
triangle ABC with side AB labeled 11, side CA labeled 7.6 and side BC labeled 7.9 and a second triangle DEF with side DE labeled 2.2
Brainliest for right answer!!!!
Will give Brainliest and points!!!!
Determine the measurement of FD.
FD = 1.52
FD = 1.58
FD = 1.1
FD = 5.5
Answer:
The answer is **FD = 1.52**.
Since triangle ABC ~ triangle DEF, we know that the ratio of their corresponding sides is equal. So, we have:
```
AB/DE = AC/DF = BC/EF
```
We are given that AB = 11, DE = 2.2, and AC = 7.6. Substituting these values into the first equation, we get:
```
11/2.2 = 7.6/DF
```
Cross multiplying, we get:
```
11 * DF = 2.2 * 7.6
```
```
DF = (2.2 * 7.6) / 11
```
```
DF = 1.52
```
Step-by-step explanation:
Please help me out‼️‼️‼️‼️〽️
We can see that the dot plot is seen below.
What is a dot plot?We can see here that An example of a graphical representation of data is a dot plot. It is a number line with dots above each value to indicate the frequency or count of that value.
Depending on the type of data being shown, the dots are often arranged either horizontally or vertically.
Dot plots are known to be useful for showing the distribution of data, particularly for small data sets.
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Engineers and architects often use transformed shapes to design objects or structures. Analyze a building or structure around you and describe the transformations that you see using geometric vocabulary. How does the transformed shape contribute to the design of the object?
and give me an answer that I can actually use please
Answer:
Many buildings and structures around us involve transformed shapes in their design. For example, a skyscraper may have a rectangular base that is transformed into a triangular shape as it reaches higher levels. This transformation is achieved by using a technique called tapering, where the building's width gradually decreases as it goes up, resulting in a triangular shape at the top.
Another common transformation is the use of rotation, which is seen in the design of many cylindrical structures like water towers or chimneys. The cylinder is rotated around its axis to create a three-dimensional shape.
These transformed shapes contribute to the design of the object in many ways. For instance, the triangular shape of a skyscraper's top helps to reduce wind resistance and improve stability. Tapering also allows more sunlight to reach street level and reduces the impact of shadows on the surrounding area. In the case of cylindrical structures, rotation can provide structural stability while minimizing the amount of material used in the construction.
Overall, the use of transformed shapes in building and structure design helps to achieve specific aesthetic and functional goals, from stability to energy efficiency.
Step-by-step explanation:
Answer:
The Empire State Building is a skyscraper in Midtown Manhattan, New York City, on Fifth Avenue between West 33rd and 34th Streets. It has a roof height of 1,250 feet (381 m), and with its antenna spire included, it stands a total of 1,454 feet (443.2 m) high. Its name is derived from the nickname for New York, the Empire State.
The Empire State Building is an example of a transformed shape. The original shape is a square, but the architects transformed it into a triangle by adding a spire to the top. The spire adds height and visual interest to the building. It also helps to make the building more stable.
The use of transformed shapes in the design of the Empire State Building contributes to its overall aesthetic appeal. The building is both visually striking and structurally sound. It is a testament to the skill and ingenuity of the architects who designed it.
Here are some other examples of transformed shapes in buildings and structures:
* The Parthenon in Athens, Greece, is a rectangular building with a triangular pediment at each end. The pediments are decorated with sculptures that depict scenes from Greek mythology.
* The Eiffel Tower in Paris, France, is a wrought iron lattice tower that was built for the 1889 World's Fair. The tower is a transformed shape of a regular hexagon.
* The Gateway Arch in St. Louis, Missouri, is a stainless steel arch that spans the Mississippi River. The arch is a transformed shape of a catenary curve.
These are just a few examples of the many ways that transformed shapes are used in the design of buildings and structures. Transformed shapes can be used to add visual interest, create a sense of movement, or simply to make a building more structurally sound.
Step-by-step explanation:
Jasica Parker would like to have $83,000 to buy a new car in 7 years. To accumulate $83,000 in 7 years, how much should she invest monthly in a sinking fund with 3% interest compounded monthly?
Jasica should invest $878.84 per month in a sinking fund with 3% interest compounded monthly to accumulate $83,000 in 7 years.
How much should Jasica invest monthly in a sinking fund with 3% interest?To determine how much Jasica should make in a sinking fund, we can use the formula for the future value of an annuity due:
FV = PMT x [tex](((1 + r/n)^nt[/tex] - 1) / (r/n))
Where:
FV = future value
PMT = monthly payment
r = interest rate (as a decimal)
n = number of compounding periods per year
t = number of years
In this issue, we are solving for PMT.
Given:
FV = $83,000,
r = 0.03 (3% expressed as a decimal),
n = 12 (monthly compounding),
t = 7 years.
Plugging in the values, we have:
$83,000 = PMT x [tex](((1 + 0.03/12)^(12*7)[/tex] - 1) / (0.03/12))
Simplifying:
$83,000 = PMT x (94.4523)
PMT = $83,000 / 94.4523
PMT = $878.84 (rounded to the nearest cent)
Therefore, Jasica should invest $878.84 per month in a sinking fund with 3% interest compounded monthly.
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Tell whether the ordered pair is a solution of the equation
Y=6x; (0,3)
Answer:
Yeeeaaa, no.
Hope this helps!
Step-by-step explanation:
( x, y )
Plug the numbers of the ordered pair into the equation: y = 6x
3 = 6 × ( 0 )
3 = 0
Three does not equal zero...
3 [tex]\neq[/tex] 0
15 POINTS!!!!! HELP DUE IN 10 MINS!!!!!!!!!
Use the graph to answer the question.
Determine the line of reflection.
Reflection across the x-axis
Reflection across x = −6
Reflection across the y-axis
Reflection across y = −6
A line of reflection, also known as a line of symmetry, is a line that divides a figure into two congruent parts that are mirror images of each other.
When a figure is reflected across a line of reflection, every point on one side of the line has a corresponding point on the other side of the line that is equidistant from the line.
To determine the line of reflection for the given graph:
- Reflection across the x-axis: The line of reflection is the x-axis.
- Reflection across x = -6: The line of reflection is a vertical line passing through x = -6.
- Reflection across the y-axis: The line of reflection is the y-axis.
- Reflection across y = -6: The line of reflection is a horizontal line passing through y = -6.
Thus, the line of reflection is the perpendicular bisector of every segment joining a point to its image after reflection.
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how to solve for the below problems
The Taylor polynomial of degree 3 for sin(x) for x near 0 is,
sin (x) = x - 1/6 x³
The ratio is sin (x) / x = 1 - 1/6 x².
Limit is 1.
Given function is sin(x).
We have to find the Taylor Polynomial for sin (x).
We know that,
f(x) = sin(x), so f(0) = sin (0) = 0
f'(x) = cos (x), so f'(0) = cos (0) = 1
f''(x) = -sin (x), so f''(0) = sin (0) = 0
f³(x) = -cos (x), so f³(0) = -cos(0) = -1
Taylor polynomial is,
sin (x) = {[f(0) (x - k)⁰] / 0!} + {[f'(0) (x - k)¹] / 1!} + {[f''(0) (x - k)²] / 2!} + {[f³(0) (x - k)³] / 3!}
Here c = 0.
sin (x) = 0 + x + 0 + (-x³/6)
sin (x) = x - 1/6 x³
The ratio,
sin (x) / x = (x - 1/6 x³) / x = 1 - 1/6 x²
When x tends to 0 in the expression, 1 - 1/6 x², the value tends to 1 - 0 = 1.
Hence the required Taylor polynomial is sin (x) = x - 1/6 x³.
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Need help please !! And I need an explanation too
He covered a distance of 5 miles for 5 days of the total days of training. The total distance he covered = 6 miles.
How to calculate the distance covered by Anthony during his training?The total number of days Anthony used for training = 8 days.
The number of days he covered 1/4 mile = 2days
The number of days he covered 1/2 mile = 1 day
The number of days he covered 1 mile = 5 days.
Therefore that total distance that he used for the training = 2(1/4)+1(1/2)+5(1)
= 0.5+0.5+5
= 6 miles.
The number of days he covered the highest distance would be for 5 days.
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show that the solution to the differential equation dp/dt=-0.1P is P=495e^1.1t
We have shown that the solution to the differential equation dp/dt = -0.1P is P = 495e^(1.1t).
We have,
To show that the solution to the differential equation dp/dt = -0.1P is
P = 495e^(1.1t),
we can use separation of variables and integration.
Starting with the differential equation:
dp/dt = -0.1P
We can separate the variables by dividing both sides by P and multiplying both sides by dt:
dp/P = -0.1 dt
Integrate both sides:
∫ dp/P = -0.1 ∫ dt
Integrating the left-hand sid.
ln|P| = -0.1t + C
where C is the constant of integration.
To solve for C, we can use an initial condition.
Suppose that when t = 0, P = P0.
Then we have:
ln|P0| = -0.1(0) + C
ln|P0| = C
Substituting this value of C back into the equation for P.
ln|P| = -0.1t + ln|P0|
ln|P/P0| = -0.1t
Taking the exponential of both sides.
P/P0 = e^(-0.1t)
Multiplying both sides by P0.
P = P0 e^(-0.1t)
We can substitute P0 = 495 (since P(0) = 495 is given in the solution) and e^(-0.1t) = e^(1.1t)/e^t.
P = 495 e^(1.1t)/e^t
Simplifying the expression by combining the exponentials.
P = 495 e^(0.1t)
which is the same as the given solution.
Therefore,
We have shown that the solution to the differential equation dp/dt = -0.1P is P = 495e^(1.1t).
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Find the measure of angle AEF in regular hexagon ABCDEF.
Answer:
30°
Step-by-step explanation:
You want the measure of angle AEF in regular hexagon ABCDEF.
Interior anglesThe interior angles of a regular hexagon are ...
180° -(360°/6) = 120°
Angle AEF is 90° less than this, so is ...
angle AEF = 120° -90°
angle AEF = 30°
__
Additional comment
Angle AEF is also a base angle of isosceles triangle AEF, which has angle F = 120°. The base angles are (180° -120°)/2 = 30°.
Geomerty Math PLSSS ANSWER
Answer: first do multiplcation for each part then add everythink to find total volume
Step-by-step explanation:
the rectangular wall measures 14 ft by 12 feet. Each square foot of wallpaper costs 2.90. Find the cost of covering the wall with paper?
Answer:
487.20
Step-by-step explanation:
1. find the area of a rectangle ( length x width)
14ft x 12ft = 168ft²
2. Multiply the number of feet needed to becovered by the price of one foot of paper
168ft x 2.90 = 487.20
Slope! answer the questions below please i need help! and i need a good grade!!!
The equation of a line for the given graph is y=2x+5.
From the given graph, the coordinate points are (0, 5) and (1, 7)
Part A:
Slope = (7-5)/(1-0)
= 2
Part B:
The slope mean for the relationship between the number of races and the number of track meets 2 races per track
Part C:
Substitute m=2 and (x, y)=(0, 5) in y=mx+c, we get
5=2(0)+c
c=5
Part D:
Substitute m=2 and c=5 in y=mx+c, we get
y=2x+5
Therefore, the equation of a line for the given graph is y=2x+5.
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Find the volume of the shape below. Round to the nearest tenth. Use
the pi button on the calculator.
12 ft
Volume=
4 ft
ft3
The volume of the cone with a diameter of 4ft and height 12ft is approximatelly 50.3 ft³
What is the volume of the cone?A cone is simply a 3-dimensional geometric shape with a flat base and a curved surface pointed towards the top.
The volume of a cone is expressed as;
V = (1/3)πr²h
The figure in the image is a cone.
Diameter of the base of the cone d = 4ft
Radius r = diameter/2 = 4/2 = 2ft
Height h = 12ft
Plug the given values into the above formula and solbr for the volume.
V = (1/3)πr²h
V = (1/3) × π × r² × h
V = (1/3) × π × (2 ft )² × 12ft
V = 50.3 ft³
Therefore, the volume is 50.3 ft³.
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Help me please find EC
The length of segment EC is 24 in the given triangle
A midsegment of a triangle is a segment that connects the midpoints of two sides of a triangle.
3x=2(x+4)
Apply distributive property on RHS
3x=2x+8
Subtract 2x from both sides
x=8
The segment EC =3x
=3(8)
=24
Hence, the length of EC is 24 in the given triangle
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The equation P = 24+2.94w represents Barrington's
water bill, where:
P is the price per month, and w is the amount of water they
use in one month, in thousands of gallons.
Answer the below questions. Round any decimals to two
places.
dollars when they use 0
dollars for every one-thousand
1. Barrington pays … type your answer…
gallons of water.
2. They pay type your answer....
gallons of water used.
3. Barrington paid type your answer...
thousand gallons last month.
dollars when they used 11-
Barrington pays 24 for 0 gallons of water and Barrington pays 55.9 for 11 gallons of water
Calculating the amount paid for gallons usedGiven that we have
P = 24 + 2.9w
When they used 0 gallons, we have
P = 24 + 2.9(0)
P = 24
When they used 11 gallons, we have
P = 24 + 2.9(11)
P = 55.9
Hence, the amount paid for 11 gallons is 55.9
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how to solve the power series below
The first five coefficients are explained.
Given is power series, f(x) = eˣ about x = 4 as [tex]\sum_{\infty}^{n=0}C_n}(x+4)^n[/tex]
f(x) = eˣ
a = 4,
The general form of a Taylor series is:
f(x) = [tex]\sum_{n=0}^{\infty}\frac{f'(a)}{n!} (x-a)^n[/tex]
Note that since the function is a basic exponential function, its derivative is:
f'(x) = eˣ
That is, the function is the same for whatever order of differentiation. So, let us substitute our values here,
f(x) = [tex]\sum_{n=0}^{\infty}\frac{e^4}{n!} (x-4)^n[/tex]
The general expression for the coefficients is: [tex]C_n = \frac{e^4}{n!}[/tex]
The first coefficient is: [tex]C_0 = e^4[/tex]
The second coefficient is: [tex]C_1 = e^4[/tex]
The third coefficient is: [tex]C_2 = 1/2e^4[/tex]
The fourth coefficient is: [tex]C_3 = 1/6e^4[/tex]
And lastly,
[tex]C_4 = 1/24e^4[/tex]
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Triangle ABC has vertices at A(−3, 3), B(0, 7), and C(−3, 0). Determine the coordinates of the vertices for the image if the preimage is translated 3 units up.
A′(−3, 0), B′(0, 4), C′(−3, −3)
A′(−3, 6), B′(0, 10), C′(−3, 3)
A′(−6, 3), B′(−3, 7), C′(0, 0)
A′(0, 3), B′(3, 5), C′(0, 0)
The coordinates of the vertices for the image if the preimage is translated 3 units up is : A′(−3, 6), B′(0, 10), C′(−3, 3).
The correct option is (B)
Translations:If we are given the translated image of something, we need to work backwards given the translation rules. For example, if we have a general translation of (x +a, y +b), then to find pre-translation coordinates, we do: (x−a, y−b).
We have the Triangle ABC has vertices at A(−3, 3), B(0, 7), and C(−3, 0).
Now, let's consider the translation that moves the triangle 3 units up. This means that we need to add 3 to the y-coordinate of each vertex to get the coordinates of the image.
So, the coordinates of the vertices of the image triangle, let's call it A'B'C', will be:
A' = (-3, 3+3) = (-3, 6)
B' = (0, 7+3) = (0, 10)
C' = (-3, 0+3) = (-3, 3)
The coordinates of the vertices for the image if the preimage is translated 3 units up is : A′(−3, 6), B′(0, 10), C′(−3, 3)
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Can someone please tell me what's the answer to convert 35 deca to km and m. my school is about to start
Answer:
1km:100decameter(dam)
Step-by-step explanation:
so 35dam:0.35km
and 35dam:0.00035m
2. Find the length of MN in the triangle below. M A. 2√23 B. 3√13 C. 4√6 D. 8√2
[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{24}\\ a=\stackrel{adjacent}{22}\\ o=\stackrel{opposite}{MN} \end{cases} \\\\\\ MN=\sqrt{ 24^2 - 22^2} \implies MN=\sqrt{ 92 }\implies MN=2\sqrt{23}[/tex]
An example of an early application of statistics was in the year 1817. A study of chest
circumference among a group of Scottish men exhibited an approximately normal
distribution. Their chest circumference ranged from 33 to 48 in., with a mean chest
measurement of 40 in. and a standard deviation of 2 in. Use the Empirical rule to help
you understand the distribution of chest circumferences in the study.
What range of chest measurements contains 68% which falls closest to the mean?
What would you expect the chest measurements to be for the 2.5% of the men with
the smallest chest measurements in the population?
a) The range of chest measurements contains 68% which falls closest to the mean is between 38 inches and 42 inches
b) The chest measurements for the 2.5% of the men with the smallest chest measurements in the population to be approximately 36 inches
Given data ,
The Empirical rule, also known as the 68-95-99.7 rule, is a statistical guideline that describes the approximate distribution of data in a normal distribution.
Approximately 68% of the data falls within one standard deviation (σ) of the mean (μ)
Approximately 95% of the data falls within two standard deviations of the mean (μ ± 2σ)
Approximately 99.7% of the data falls within three standard deviations of the mean (μ ± 3σ)
It would be within one standard deviation of the mean for the range of chest measures that accounts for 68% of the data and is closest to the mean. Since the standard deviation is 2 inches and the mean chest measurement is 40 inches, we can get the range as follows:
Mean - 1 standard deviation = 40 - 2 = 38 inches
Mean + 1 standard deviation = 40 + 2 = 42 inches
b)
We may look at the bottom end of the distribution to obtain the chest dimensions for the 2.5% of males with the smallest chest measurements in the population. The empirical rule states that 2.5% or less of the data goes outside of two standard deviations of the mean. So, using the following formula, we can get the chest size of the 2.5% of men:
Mean - 2 standard deviations = 40 - 2(2) = 36 inches
Hence , the standard deviations are solved
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solve: 63+48÷(23-11)×14
Answer:
119
Step-by-step explanation:
Firstly, we need to solve the expression inside the parentheses, which is 23-11. This gives us 12. Then we need to carry out the division to get 48 divided by 12, which is 4. We can then multiply 4 by 14 to get 56. Finally, we add 56 to 63 which gives us the answer of 119. Therefore, the solution to the expression 63+48÷(23-11)×14 is 119.
CRITICAL THINKING The total area of the polygon is 176 square feet. What is the value of $x$ ?
A drawing of a polygon. It consists of a rectangle with two triangles on either side. Length of the rectangle is 16 feet. The width of the rectangle is 8 feet and is same as the height of the triangles. Lengths of the base of each triangle is labeled as x.
$x=$
ft
The value of x is, x = 6 ft
Now, We can formulate;
Area of the polygon = area of the square + 2(area of the triangle)
Here, We have;
Area of the polygon = 176 ft²
So, Area of the square = length × width
= 16 × 8
= 128
And, Area of the two triangles = 2( 1/2 x base x height)
= 2(1/2 × x × 8)
= 8x
Now, Plug in the above values into the equation for area of the polygon.
Thus: We get;
176 = 128 + 8x
Subtract 128 from each side
176 - 128 = 8x
48 = 8x
Divide both sides by 8
6 = x
x = 6 ft
Thus, The value of x is, x = 6 ft
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If the went in the oven at 3:40pm and it needs to bake for 35 minutes. What time will it be fully baked
well, first of all, you don't want to go into the oven, is too hot and you'll get burned, so you may not want to do that.
now, if we start to bake something at 3:40pm and it requires 35 minutes, it'll be done by 3:40 + 35, or 3pm and 40 + 35 minutes, or 3pm plus 75 minutes or 3pm plus 60 + 15 minutes, but since 60 minutes is 1hr, that'd be 3pm plus 1hr plus 15 minutes, 4:15pm.
It costs a car company $25,000,000 to develop and market the model of a new car. The company sells each car for $30,000 . Which of the following represents the number of cars, c , that the car company must sell to make over $5,000,000 in profit?
Answer: so if it cosst 25,000,000 dollars to market a car and they sell it for 30,000 dollars they would need to sell 167 cars to get 5.1 million dollars or 166 for 5.0 million