What inertia is present in a stretched rubber?​

Answers

Answer 1

Answer:

You input potential energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this is kind of potential energy is specifically called elastic potential energy.

Answer 2

The inertia in the stretched rubber will be potential energy, i.e., elastic potential energy.

What is inertia?

Law of inertia:

          Newton's First Law of Motion (Inertia) is an object at rest remains at rest,  an object in motion remains in motion at constant speed through straight line unless acted by an unbalanced force.

Moment of inertia:

        The sum of the product of mass  of each particle with the square of its distance from the axis of the rotation is known as inertia or the moment of inertia.

Formula of Moment of Inertia I = Σ miri².

The three types of inertia are as follows:

Inertia of Rest.Inertia of motion.Inertia of Direction.

Inertia is the result of conservation of energy.

Learn more about inertia,

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Related Questions

How do you calculate relative velocity?

Answers

Answer:

Vab=Va-VbVab=Vb-VaExplanation:

Vab is velocity of a relative to b

Vba is velocity of b relative to a

Three students are fighting over a T-shirt. Student 1 exerts a constant force F⃗ 1=F0i^ on the shirt, student 2 exerts a constant force F⃗ 2=−3F0j^ and student 3 exerts a constant force F⃗ 3=−4F0i^+Gj^. (In these expressions F0 and G are positive constants with units of force.) As the three students exert these forces, the T-shirt undergoes a straight-line displacemen 2di^+dj^ where d is a positive constant with units of distance. Find the work done on the T-shirt by student 1.

Answers

Answer:

W₁ = 2F₀d

Explanation:

When a force is applied on a body, due to which the body displaced by some distance, then the work is said to be done. Hence, the work is the dot product of the force nd displacement.

W = F.d

where,

W = Work Done

F = Force Applied

d = Displacement

For student 1:

W = W₁ = ?

F = F₁ = F₀ i

d = 2d i + d j

Therefore,

W₁ = (F₀i).(2di + dj)

W₁ = 2F₀d(i.i) + F₀d(i.j)

W₁ = 2F₀d(1) + F₀d(0)

W₁ = 2F₀d + 0

W₁ = 2F₀d

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