What does 3 3/5 * 2 5/7 equal

Answer:

Step-by-step explanation:

Open box is in rectangular shape. cuboid that is open in the top

l = length = 30 - (2.5 + 2.5 ) = 30 - 5 = 25 cm

h = 2.5 cm

w = width = 30 - (2.5 + 2.5) = 30 - 5 = 25 cm

Surface Area = 2lh + 2wh + lw

                     = 2*25*2.5 + 2* 25*2.5 + 25*25

                    =125 + 125 + 625

                   = 875 square cm

Volume = lwh

             = 25*25*2.5

             = 1562.5 cubic cm

Answer:

7/8 of the game is left. The game lasts for 592 minutes.

Step-by-step explanation:

It is halfway through the first quarter so it is 1/8. So that's 7/8 part of the game left. if 74 minutes of playing time has past, then you do 74*8 so that's 592 minutes.

Answer:

4) 1/8

3)74x8=592

6)592-74= 518

Step-by-step explanation:

Answer:

7.06

Step-by-step explanation:

17/8 = 15/DF

DF = 7.06

Answer:

Equation:  87 + 91 + 86 + x = 360

Solution: 264 + x = 360

x = 360 - 264

x = 96

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

First three Kelsea's test grades : 87, 91 and 86

2. What score must she get on her fourth test to receive at least an A- ?

Define variable:  x that represents the grade needed by Kelsea on her fourth test to receive at least an A-

Equation:  87 + 91 + 86 + x = 360

Solution: 264 + x = 360

x = 360 - 264

x = 96

Now you can understand if the previous work you did is correct

Answer:

Ok so im in 7thgrade so ima try to help answer is x= 8x9

Answer: 5.34

Step-by-step explanation: 18 - 12.66 = 5.34

Answer:

80$

Step-by-step explanation:

total amount of needed=200

Total =Tef +Angelina+Jason

200=90+30+Angelina

Angelina=200-120

Angelina=80$

Answer: 240

Step-by-step explanation:

5/6x=200

(6/5)5/6x=200(6/5)

1x=40(6/1)

x=40(6)

x=240

Answer:

The upper bound on the length of a randomly chosen nail from all nails manufactured by the company is 2.004 cm.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

Then, the mean of the sample means is given by,

[tex]\mu_{\bar x}=\bar x[/tex]

And the standard deviation of the sample means (also known as the standard error) is given by,

[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]

In this case the sample of nails selected is quite large, i.e. n = 100 > 30.

So, the sampling distribution of sample mean length of nails will be approximately normal.

Then according to the Empirical rule, 95% of the normal distribution is contained in the range,

[tex]\mu\pm 2\cdot \frac{s}{\sqrt{n}}[/tex]

Compute the upper bound as follows:

[tex]\text{Upper Bound}=\mu\pm 2\cdot \frac{s}{\sqrt{n}}[/tex]

                     [tex]=2+(2\times\frac{0.002}{\sqrt{100}})\\\\=2+0.0004\\\\=2.004[/tex]

Thus, the upper bound on the length of a randomly chosen nail from all nails manufactured by the company is 2.004 cm.

Answer:

V = 32 in^3

Step-by-step explanation:

The area of the triangle is (1/2)(base)(height), which here comes to:

                                                (1/2)(4 in)(8 in) = 16 in^2.

The volume is (16 in^2)(height) =  (16 in^2)(2 in) = 32 in^3

Answer:

158m^3

Step-by-step explanation:

First, let's figure out the total amount of water in the tank.

It measures 4.5m by 6m by 8m. The volume of a rectangular prism is V=lwh.

Therefore, the volume is:

[tex]V=(4.5)(6)(8)=216 m^3[/tex]

We are told is it filled to the brim, so we can conclude that there are 216 cubic meters of water in the tank.

We used 58 cubic meters of water, so we simply need to subtract that from 216:

[tex]216m^3-58m^3=158m^3[/tex]

There is still 158 cubic meters of water left in the tank.

Answer:

158 m^3

Step-by-step explanation:

Volume of the tank

= 4.5 * 6 * 8

= 216 m^3.

So amount left in the tank

= 216 - 58

= 158 m^3.

Answer:

C. [tex](5-\frac{1}{2})^6[/tex]

Step-by-step explanation:

Given

[tex]15(5)^2(-\frac{1}{2})^4[/tex]

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

[tex]Sum = 2 + 4[/tex]

[tex]Sum = 6[/tex]

Each term of a binomial expansion are always of the form:

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

Where n = the sum above

[tex]n = 6[/tex]

Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion

[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

Substitute 6 for n

[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

By direct comparison of

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

and

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

We have;

[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]

Further comparison gives

[tex]^nC_r = 15[/tex]

[tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]b^r= (-\frac{1}{2})^4[/tex]

[Solving for a]

By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]a = 5[/tex]

[tex]n = 6[/tex]

[tex]r = 4[/tex]

[Solving for b]

By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]

[tex]r = 4[/tex]

[tex]b = \frac{-1}{2}[/tex]

Substitute values for a, b, n and r in

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

Solve for [tex]^6C_4[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]

Check the list of options for the expression on the left hand side

The correct answer is [tex](5-\frac{1}{2})^6[/tex]

Answer:

A. z/y

Step-by-step explanation:

Because the trig ratios are; tangent : opp/adj cos : adj/hyp sin : opp/hyp

because tan of x is z/10, z must be opposite

and because cos of x is 10/y, then y must be the hypotenuse

this means sin of x must be z/y

Answer:

A. sin x = z/y

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

cas if x =1

then 1^2>or=1

1is not >or=1

Answer:

Step-by-step explanation:

Hello,

a. The area of region P is the area of the rectangle 1 * e minus the

[tex]\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^{1}_{0}=e-1[/tex]

So this is e - (e-1) = e - e + 1 = 1

b. The area of region P is the area of the rectangle 1 * e minus P and minus the

[tex]\displaystyle \int\limits^0_1 {e^{-x}} \, dx=[-e^{-x}]^{1}_{0}=-e^{-1}+1[/tex]

So this is

[tex]e - 1 - (-e^{-1}+1) = e-1+e^{-1}-1=e+e^{-1}-2[/tex]

This is around 1.08616127...

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

9 ft

Step-by-step explanation:

a²+b²=c²

20²+b²=25²

400=b²=625

b²=625-400

b²=225

b=15 (the distance up the wall the ladder is to begin with)

20-13=7

7²+b²=25²

49+b²=625

b²=625-49

b²=576

b=24 (The distance up the wall the ladder is after moving it)

24-15=9

Answer:

583.33 cm³

Step-by-step explanation:

From the image attached, the total height (H) of the pyramid is 30 cm, the height of the frustrum (h) = 15 cm, the Frustrum base = lower base = B = 10 cm . To find the length of the upper base (b), we use:

[tex]\frac{b}{H-h}=\frac{B}{H}\\ b=(H-h)\frac{B}{H}\\b=(30-15)\frac{10}{30}=5\\b=5\ cm[/tex]

The volume of the frustrum is given by:

[tex]V=\frac{1}{3}h(B_1+B_2+\sqrt{B_1B_2} )\\ Where\ B_1\ is \ the\ area \ of\ the\ upper\ base= 5cm*5cm=25cm^2\\B_1\ is \ the\ area \ of\ the\ lower\ base= 10cm*10cm=100cm^2\\V=\frac{1}{3}(10)(25+100+\sqrt{25*100} )=583.33\\V=583.33\ cm^3[/tex]

Answer:

x = (3 +/- sqrt(17) / 4.

Step-by-step explanation:

x = [-(-3) +/- sqrt((-3)^2 - 4*2*-1)] / 4

x = (3 +/- sqrt(17) / 4.

Answer:

Consecutive angles in a parallelogram are, D supplementary.

Step-by-step explanation:

Consecutive angles in a parallelogram will always sum to 180 degrees.

Answer:

Supplementary

Step-by-step explanation:

Correct answer in Ap3x. Just took the quiz.

Answer:

The speed of plane = 40 m/s

The speed of the wind = 300 m/s

Step-by-step explanation:

Let the speed of the plane = Y

And the speed of the wind = X

If the plane then travel 340 miles per hour with the wind, that means the plane and the wind are moving in the same direction. Therefore,

X + Y = 340 ..... ( 1 )

Also, 260 miles per hour against the wind. That is, the plane is moving opposite to the direction of the wind. Therefore,

X - Y = 260 ..... ( 2 )

Solve the two equations simultaneously by addition. That will eliminate Y

X + Y = 340

X - Y = 260

2X = 600

X = 600/2

X = 300 m/s

Substitutes X in equation (1)

300 + Y = 340

Make Y the subject of formula by collecting the like terms

Y = 340 - 300

Y = 40 m/s

Therefore, the speed of the plane is 40 m/s. While the speed of the wind is 300 m/s.

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is

[tex]S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}[/tex]

Multiply both sides by r :

[tex]rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n[/tex]

Subtract the latter sum from the first, which eliminates all but the first and last terms:

[tex]S_n-rS_n=a-ar^n[/tex]

Solve for [tex]S_n[/tex]:

[tex](1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}[/tex]

Then as gets arbitrarily large, the term [tex]r^n[/tex] will converge to 0, leaving us with

[tex]S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}[/tex]

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

Answer:

Hey there!

Original Equation

-5x-4y=-8

Multiply by -1

5x+4y=8

Subtract 4y

5x=8-4y

Divide by 5

x=(8-4y)/5

Let me know if this helps :)

Answer:

x = -4/5y + 8/5

Step-by-step explanation:

So to single out x we use the communicative property,

its the moving of numbers and variables to each side of the equation.

So we have,

-5x - 4y = -8

+4y

-5x = 4y - 8

Divide -5 by both sides,

x = -4/5y + 8/5

Thus,

the equation rearanged is x = -4/5y + 8/5.

Hope this helps :)

Answer:

Step-by-step explanation:I think the answer is 12?

Answer:

5 pounds of miniature chocolate and 2 butterscotch hard candies

Step-by-step explanation:

5 x $1.80 =$9 for 5 pounds of candy

2 x $1.00 =$2 for 2 pounds of candy

2 + 5 =7 pounds

7 pounds of candy using $11.00

Answer:

(4,-1)

Step-by-step explanation:

The required coordinate of J is (1, 4). Hence the option c is correct.

Rectangle JKLM is rotated 90° clockwise about the origin.
On a coordinate plane, rectangle J K L M has points (negative 4, 1), (negative 1, 1), (negative 1, negative 1), (negative 4, negative 1).

Rectangle is four sided polygon whose opposites sides are equal and has angle of 90° between its sides.

While rotating the rectangle about origin clock wise, the new coordinates forms of  rectangle J K L M has points  ( 4, 1), (1, 1), (negative 1,  1), (negative1 ,  4).

Thus, the required coordinate of J is (1, 4).

Learn more about rectangles here:
https://brainly.com/question/16021628

#SPJ2

Answer:

x=10

Step-by-step explanation:

The triangles are similar so we can use ratios to solve

6.5      (6.5+6.5)

------ = -----------------------

5              x

6.5      (13)

------ = -----------------------

5              x

Using cross products

6.5x = 65

Divide by 6.5

6.5x/6.5 = 65/6.5

x = 10

Answer:

Domain: (-5,-4,-3,-2,-1,0,1,2,3,4,5)

Range: (0,1,2,3,4, -1, -2)

Step-by-step explanation:

Domain means all of the x-axis values on the graph, so for example in (-2,0), -2 would be part of the domain and 0 part of the range. Therefor, what you would do would be take all of the plots and put all x values as the domain and all y values as the range. Hope this helped!

Answer:

Option 4

Step-by-step explanation:

=> [tex]\frac{4}{5} x^{-9}y^6z^8[/tex]

If there is any variable having a negative exponent, we should move it to its opposite side (Denominator to numerator and vice versa) So that it's exponent become positive.

=> [tex]\frac{4y^6z^8}{5x^9}[/tex]

Answer: D) [tex]\frac{4y^6z^8}{5x^9}[/tex]

Step-by-step explanation:

(4/5)x^-9y^6z^8 = [tex]\frac{4x^{-9}y^6z^8}{5}[/tex]

Any negative exponent can be taken to the other side of the fraction to be positive.  Thus,

[tex]\frac{4x^{-9}y^6z^8}{5}[/tex] = [tex]\frac{4y^6z^8}{5x^9}[/tex]

Hope it helps <3

Answer:

Step 2: addition property of equality

Step 4: multiplication property of equality

Step-by-step explanation:

=>In step 2, from step 1, where you have [tex] -\frac{y}{2} - 6 = 15 [/tex] , to make -6 cross over to the other side of the equation, the addition property of equality was applied. That would ensure the equation remains balanced. Thus, 6 is added to both sides of the equation.

[tex] -\frac{y}{2} - 6 + 6 = 15 + 6 [/tex]

[tex] = -\frac{y}{2} = 21 [/tex]

=>In step 4, the multiplication property of equality was used as both sides of the equation were multiplied by -2, to balance the equation and also solve for y.

Answer:

Step 2 > addition

Step 4 > multiplication

Step-by-step explanation:

Answer:

rational (I think

Step-by-step explanation: