An electric current causes the magnetic field around the wire. The correct answer is A.
The magnetic field around a wire is caused by the flow of electric current through the wire. When an electric current passes through a wire, it generates a magnetic field that forms circular lines of magnetic flux around the wire. This phenomenon is described by Ampere's law, which states that a magnetic field is produced by an electric current and its strength is directly proportional to the magnitude of the current.
The relationship between the electric current and the magnetic field can be understood using the right-hand rule. If you wrap your right hand around the wire with your thumb pointing in the direction of the current, the curled fingers indicate the direction of the magnetic field lines.
Therefore, an electric field is generated by an electric charge, not by an electric current. While an electric field can exist around a wire if there is a potential difference (voltage) applied across it, it is the flow of electric current that primarily generates the magnetic field.
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; we call this
1. When distance increases____, electrostatic force
relationship____
proportional *
1 poi
decreases; directly
increases; inversely
decreases; inversely
increases; directly
Answer:
decreases;inversely
Testosterone is used to treat breast cancer ? True or false?
Answer:
True
Explanation:
Because I had a test on this
I have long brown hair and dark brown eyes should I wear a red green or blue long dress
a 1220 kg automobile travels at 75 m/s. what net work would be required to bring it to a stop
Answer:
W = - 3431250 [N]
Explanation:
In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the initial mechanical energy of a body plus the work done on this body must be equal to the final mechanical energy of the body. We must remember that the mechanical energy of a body is equal to the sum of kinetic energies plus potential energy plus elastic energy.
In this problem, we only have kinetic energy.
[tex]E_{1}+W_{1-2}=E_{2}\\where:\\E_{1}=E_{pot}+E_{kine}+E_{elas}\\E_{pot} = 0\\E_{elas}=0\\E_{kine}=\frac{1}{2} *m*v^{2}[/tex]
And we have:
m = mass = 1220 [kg]
v = velocity = 75 [m/s]
As the carriage stops the final kinetic energy is zero.
Now replacing:
[tex]\frac{1}{2} *1220*(75)^{2} +W_{1-2}=0\\W_{1-2}= - 3431250[N][/tex]
Note: The negative force means that the force has to be carried out by the carriage. That is, no external force acts on the car to stop it.
g A raindrop charged to 10 mC experiences electric field of 10,000 V/m from a tip of a tree branch. What is the electric force acting on the raindrop
Answer:
The electric force acting on the raindrop is 100 N.
Explanation:
Given;
charge of the raindrop, Q = 10 mC = 0.01 C
electric field strength, E = 10,000 V/m = 10,000 N/C
The force acting on the raindrop is given as;
Electric Force = electric field strength x charge of the raindrop
F = EQ
F = (10,000 N/C) (0.01 C)
F = 100 N
Therefore, the electric force acting on the raindrop is 100 N.
Both the pressure and volume of an ideal gas of diatomic molecules are doubled. The ratio of the new internal energy to the old both measured relative to the internal energy at 0 K is
Answer:
The ratio of the new internal energy to the old is 4
Explanation:
let the old pressure of the gas = P₁
let the old volume of the gas = V₁
then, the new pressure of the gas = 2P₁
the new volume of the gas = 2V₁
The internal energy of the gas is given as;
PV = nRT
PV = k
P₁V₁ = P₂V₂
[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]
The ratio of the new internal energy to the old is 4
Shelley is in an elevator that is traveling downward and slowing down at a rate of
0.950 m/s2. If Shelley has a mass of 73.2 kg, what is her apparent weight during this
period?
Answer:
N = 648.55[N]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
∑F = Forces applied [N]
m = mass = 73.2 [kg]
a = acceleration = 0.950 [m/s²]
Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.
By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.
[tex]-m*g + N = -m*a\\[/tex]
where:
g = gravity acceleration = 9.81 [m/s²]
N = normal force (or weight) measured by the scale = 83.4 [N]
Now replacing:
[tex]-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N][/tex]
The acceleration has a negative sign, this means that the elevator is descending at that very moment.
Amy is in a tuck and skiing straight down a 30° slope. Air resistance pushes backward on her with a force of 10 N. The coefficient of dynamic friction between her skis and the snow is 0.08. Amy’s mass is 60 kg. What is the resultant of the external forces that act on Amy?
The resultant of the external forces that act on Amy are the force due to gravity, friction and air resistance which equals 243.26 N
Given that,
Force due to air resistance, [tex]F_{air}[/tex] = 10 N
Angle of slope, θ = 30°
Mass, m = 60 kg
Coefficient of dynamic friction, μ = 0.08
Force due to gravity, w = m g
w = 60 * 9.8 = 588 N
Since the slope is at an angle, the weight exerted on the ground is not along the axis of slope. So resolving the axis into its vertical and horizontal components,
cos θ = [tex]w_{y}[/tex] / w
[tex]w_{y}[/tex] = 588 * cos 30°
[tex]w_{y}[/tex] = 509.2 N
Frictional force, [tex]F_{fr}[/tex] = μ * [tex]F_{N}[/tex]
where,
[tex]F_{N}[/tex] = Normal force = [tex]w_{y}[/tex]
[tex]F_{N}[/tex] = 509.2 N
[tex]F_{fr}[/tex] = 0.08 * 509.2
[tex]F_{fr}[/tex] = 40.74 N
sin θ = [tex]w_{x}[/tex] / w
[tex]w_{x}[/tex] = 588 * sin 30°
[tex]w_{x}[/tex] = 294 N
Force due to gravity, [tex]F_{g}[/tex] = [tex]w_{x}[/tex]
[tex]F_{g}[/tex] = 294 N
The resultant of external forces acting on Amy, [tex]F_{R}[/tex] = [tex]F_{g}[/tex] - [tex]F_{air}[/tex] - [tex]F_{fr}[/tex]
[tex]F_{R}[/tex] = 294 - 10 - 40.74
[tex]F_{R}[/tex] = 243.26 N
Therefore, the resultant of the external forces that act on Amy is 243.26 N
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A cyclist travels from point A to point B for 10 minutes. During the first 2.0 minutes of her trip, she maintains a uniform acceleration of 0.076 m/s2. She then travels at constant velocity for the next 5.0 minutes. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 minutes later
What is the acceleration during the last 3.0 minutes
Answer:
im not really good at explaining, but i found this website url:
https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/
same question just with the explanation
Arrange the temperatures 40 ºF, 40 ºC, and 40 K from highest to lowest.
Answer: 40 Celsius, 40 Fahrenheit, and 40 Kelvin
Work: I just converted them to Fahrenheit, and here's their Fahrenheit form, and with this information, I put them from highest to lowest.
- 40 Kelvin: -387.67 degrees
- 40 Celsius: 104 degrees
I hope this helps, and Happy Holidays! :)
Answer:
40 °C > 40 °F > 40 K
General Formulas and Concepts:
Chemistry
Fahrenheit to Celsius Conversion: C = 5/9(F - 32)Celsius to Kelvin Conversion: K = C + 273.15Explanation:
Step 1: Define
40 °F
40 °C
40 K
Step 2: Convert
40 °F = 5/9(40 - 32) = 4.4444... °C = 4.4444... + 273.15 = 277.594 K
40 °C = 40 + 273.15 = 313.15 K
Step 3: Compare
40 K < 277.594 K < 313.15 K
40 K < 40 °F < 40 °C
40 °C > 40 °F > 40 K
Alex kicks a soccer ball with a force of 250 N. The force is applied to the soccer ball for 0.05 seconds. What is the impulse applied to the ball?
Answer:
12.5 Ns.
Explanation:
From the question given above, the following data were obtained:
Force (F) = 250 N.
Time (t) = 0.05 s
Impulse =?
Impulse can be obtained by using the following formula:
Impulse = force × time
Impulse = 250 × 0.05
Impulse = 12.5 Ns
Thus, the Impulse applied to the ball is 12.5 Ns.
why do we use days and hours instead of seconds
A more precisely defined value for the measurement of a second is now necessary due to decades of technological and scientific advancements. Right now, the second serves as the foundational unit of time in the International System of Units (SI).
What is the time?Time is the continuous progression of existence and events that take place in what seems to be an irrevocable order from the past through the present and into the future. This is one of the quantities that make up numerous measurements which are used to compare the lengths of events or even the gaps between them, order events in time, and measure the rates at which those quantities in the physical world or in conscious experience change. In relation to the four spatial dimensions, time is frequently considered a fourth dimension.
Although time is long gone to been a crucial topic for research in philosophy, theology, and science, any definition of time that is universally applicable and free of roundness has ever been reached by academics.
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Days and hours are often used as units of time instead of seconds because they are more practical and convenient for measuring longer durations.
There are a few reasons why we use days and hours instead of seconds in everyday life.
Days and hours are more intuitive for humans to understand. It is easier to conceptualize a day or an hour than it is to conceptualize a second. For example, we can say that it takes 24 hours to make a day, or that it takes 60 minutes to make an hour. These units of time are also more relatable to our daily lives.
Days and hours are more practical for many applications. For example, it is more practical to measure the length of a day or an hour than it is to measure the length of a second. This is because days and hours are longer units of time, and they are more divisible.
Days and hours are more compatible with our calendars and timekeeping systems. Our calendars are based on days and hours, and our timekeeping systems are also based on days and hours. This makes it easier to keep track of time and schedule events.
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A water-skier of mass 75.0 kg initially at rest is being pulled due east by a horizontal towrope. The rope exerts a force of 365 N (east). The water (and air) exerts a combined average frictional force of 190 N (in the opposite direction). How fast will the skier be moving after a distance of 38.0 m?
Answer:
The skier will be moving at 13.31 m/s.
Explanation:
To calculate the velocity of the skier we need to find the acceleration, as follows:
[tex] \Sigma F = ma [/tex]
[tex] F_{r} - F_{f} = ma [/tex]
Where:
[tex] F_{r}[/tex]: is the force due to the rope = 365 N
[tex] F_{f}[/tex]: is the combined average frictional force = 190 N
m: is the mass = 75.0 kg
[tex] a = \frac{365 N - 190 N}{75.0 kg} = 2.33 m/s^{2} [/tex]
Now, we can calculate the velocity of the skier by using the following kinematic equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
[tex] v_{f}[/tex]: is the final velocity =?
[tex] v_{0}[/tex]: is the initial velocity = 0 (the skier is initially at rest)
d: is the distance = 38.0 m
[tex] v_{f} = \sqrt{2*2.33 m/s^{2}*38.0 m} = 13.31 m/s [/tex]
Therefore, the skier will be moving at 13.31 m/s.
I hope it helps you!
What makes ramps useful simple machines?
By increasing the distance, the force
required decreases
b. By increasing the distance, the required
work decreases
c. By increasing the force, the required
distance decreases
Answer:
It reduces the force necessary to move a load a certain distance up by providing a path for the load to move at a low angle to the ground.
Explanation:
A wire is carrying current vertically downward. What is the direction of the force due to Earth's magnetic field on the wire?
A wire is carrying current vertically downward.
What is the direction of the force due to Earth's magnetic field on the wire?
a) horizontally towards the east
b) horizontally towards the west
c) horizontally towards the south
d) horizontally towards the north vertically upward
Answer: The correct option is A ( horizontally towards the east)
Explanation:
Magnetic field is a region around a magnet or a current- carrying conductor, where a magnetic force is experienced. The magnetic effect of electric current was first discovered in the early 1820 by Oersted. Using a wire that had current flowing through it and a pivoted magnetic needle, he discovered that the direction of deflection depended on the direction of the current and whether the wire was above or below the needle.
From the way the needle turns when current when current carrying wire is held parallel to it, he therefore concluded that:
--> a current has magnetic field all round it,
--> the magnetic field is in a direction perpendicular to the current.
The above discovery was now modified in Fleming's left hand rule which states that when conductor carrying current is placed in a magnetic field, the conductor will experience a force perpendicular to both the field and the flow of current.
Therefore from the question, a vertical wire carrying current in DOWNWARD direction is placed in a HORIZONTAL magnetic field directed to the NORTH. The direction of the force on the wire is to the EAST.
Two 2.9 kg physical science textbooks on a bookshelf are 0.14 m apart. What is the magnitude of the gravitational attraction between the books?
Taking into account the Universal Law of Gravitation, the magnitude of the gravitational attraction between the books is 2.86×10⁻⁸ N.
Universal Law of GravitationThe Universal Law of Gravitation establishes that bodies experience a force of attraction towards other bodies with mass, called gravitational force.
The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.
Mathematically it is expressed as follows:
[tex]F=G\frac{Mm}{d^{2} }[/tex]
where:
G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex].M and m are the masses of the bodies that interact.d is the distance that separates them.Magnitude of the gravitational attraction between the booksIn this case, you know:
G= 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex]M= m= 2.9 kgd= 0.14 mReplacing in the Universal Law of Gravitation:
[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{2.9 kgx2.9 kg}{(0.14 m)^{2} }[/tex]
Solving:
[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{8.41 kg^{2} }{0.0196 m^{2} }[/tex]
F= 2.86×10⁻⁸ N
Finally, the magnitude of the gravitational attraction between the books is 2.86×10⁻⁸ N.
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An astronaut measures her mass by means of a device consisting of a chair attached to a large spring.Her mass can be determined from the period of the oscillations she undergoes when set into motion.If her mass together with the chair is 170 kg, and the spring constant is 1250 N/m, what time is required for her to undergo 10 full oscillations?
Answer:
23 seconds
Explanation:
Step one:
given data
mass m= 170kg
The spring constant is 1250 N/m
Required
The period required for 10 oscillations
Step two:
The expression relating period, mass, and spring constant is
[tex]T=2 \pi \sqrt{\frac{m}{k} } \\[/tex]
substituting our data we have
[tex]T=2 *3.142 \sqrt{\frac{170}{1250} } \\\\T=6.284* \sqrt{0.136}\\\\T=6.284*0.3687\\T=2.3s[/tex]
A Period is defined as the time required to complete one full oscillation
hence, having found the period to be 2.3 seconds, the time required for 10 oscillations will be 2.3*10= 23seconds
What is matter ?
...
Explanation:
a matter is solid gas and liquid
Answer:
matter is anything made of mass which occupys volume
Explanation:
matter is a thing which concludes mass and mentioned and also has volume ( volume is defined as space too) so everything is made of matter
if you putsome sugar in tea,the tea will became sweet even if you do not stir it explain using idae of moving particals
If it is not stirred, then the tea right at the surface of the solute becomes saturated with dissolved sugar molecules, meaning that it is more difficult for the additional solute to dissolve. The sugar cube would eventually dissolve because random motions of the tea molecules would bring enough fresh solvent into contact with the sugar, but the process would take much longer.
A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is greater than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water. Major categories of solute include:
Gaseous
Liquid
Solid
a homogenous mixture made up of two or more different substances, where a solute is a substance that dissolves in a solvent. In relation to the amount of solvent (like salt) present, the concentration of a solute in a solution is a measurement of how much of that solute is dissolved in the solvent.
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Two friends grab different sides of a textbook and pull with forces of 6.7 N to the east and 4.4 N to the west, respectively. What would be the magnitude and direction of the force a third friend would need to exert on the textbook in order to balance the other two forces?
Explanation:
This equation for acceleration can be used to calculate the acceleration of an object that is acted on by a net force. For example, Xander and his scooter have a total mass of 50 kilograms. Assume that the net force acting on Xander and the scooter is 25 Newtons. What is his acceleration? Substitute the relevant values into the equation for acceleration:
Answer:
a=Fm=25 N50 kg=0.5 Nkg
The Newton is the SI unit for force. It is defined as the force needed to cause a 1-kilogram mass to accelerate at 1 m/s2. Therefore, force can also be expressed in the unit kg • m/s2. This way of expressing force can be substituted for Newtons in Xander’s acceleration so the answer is expressed in the SI unit for acceleration, which is m/s2:
a=0.5 Nkg=0.5 kg⋅m/s2kg=0.5 m/s2
100 Points!
A projectile is launched in the horizontal direction. It travels 2.050 m horizontally while it falls 0.450 m vertically and then strikes the floor. How long is the projectile in the air? Show your work.
B. What is the original velocity of the projectile described? Show your work.
Answer:
A) 0.303 s (3 s.f.)
B) 6.76 ms⁻¹ (3 s.f.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the projectile separately.
Part AAs the projectile is fired horizontally, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 9.8 ms⁻²
Resolving vertically, taking ↓ as positive:
[tex]s=0.450\quad u=0\quad a=9.8[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\0.450&= (0)t+\dfrac{1}{2}(9.8)t^2\\0.450&= 4.9t^2\\t^2&= \dfrac{0.450}{4.9}\\t&=\sqrt{\dfrac{0.450}{4.9}\\t &=0.3030457634...\\ \implies t&=0.303\:\sf s\;\;(3\:s.f.)\\\end{aligned}[/tex]
Part BThe horizontal component of velocity is constant, as there is no acceleration horizontally.
Resolving horizontally, taking → as positive:
[tex]s=2.050 \quad a=0 \quad t=0.3030457634...[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\2.050&= u(0.3030457634...)+\dfrac{1}{2}(0)(0.3030457634...)^2\\2.050&= 0.3030457634...u\\u&= \dfrac{2.050}{0.3030457634...}\\ u &=6.764654873...\\\implies u & = 6.76\:\sf ms^{-1}\;\;(3\:s.f.)\end{aligned}[/tex]
A contact lens is made of plastic with an index of refraction of 1.60. The lens has an outer radius of curvature of 2.08 cm and an inner radius of curvature of 2.48 cm. What is the focal length of the lens?
Answer:
The value [tex]f = 21.49 \ cm[/tex]
Explanation:
From the question we are told that
The index of refraction is [tex]n = 1.60[/tex]
The outer radius of curvature is [tex]R = 2.08 \ cm = 0.0208 \ m[/tex]
The inner radius is [tex]r = 2.48 \ cm = 0.0248 \ m[/tex]
Generally from Maker's equation we have that
[tex]\frac{1}{f} = [n - 1 ][\frac{1}{(R)} - \frac{1}{r} ][/tex]
=> [tex]\frac{1}{f} = [1.60 - 1 ][\frac{1}{( 0.0208 )} - \frac{1}{0.0248} ][/tex]
=> [tex]\frac{1}{f} = 4.65[/tex]
=> [tex]f = 0.2149 \ m[/tex]
=> [tex]f = 21.49 \ cm[/tex]
A person with a bacterial infection is taking amoxicillin, which is an antibiotic. The bacteria that are causing the infection have mutated and fight off the amoxicillin.
Which best summarizes this mutation?
Answer:
I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.
Explanation:
I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!
Answer:
Answer is B!
Explanation:
I took the cumulative exam and got 100%
In the space below, draw a falling stone with the following forces acting on it:
It’s weight, 8.0N
Air resistance, 2.4N
Please write the answer on a piece of paper.Giving brainliest
The free body diagram of the falling stone's motion involves the weight of the stone acting downwards and the air resistance acting upwards.
What is free body diagram?A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.
the given forces on the falling stone include;
weight of the falling stone, W = 8.0 N, this force is acting downwards
Air resistance, R, = 2.4N, this is a frictional force resisting the stone motion. This force is acting upwards.
Free body diagram of the stone's motion↑ R = 2.4 N
Ф
↓ W = 8.0 N
Thus, the free body diagram of the falling stone's motion involves the weight of the stone acting downwards and the air resistance acting upwards.
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In the Vomitus carnival ride, passengers travel in a horizontal 4.0 m radius circle. For safe operation, the maximum sustained acceleration that riders may experience is 20 m/s2 , approximately twice the free fall acceleration. What is the period of the ride when it is being operated at the maximum acceleration?
Answer:
The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.
Explanation:
We can use the centripetal acceleration here:
[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]
Let's find the angular velocity ω at the maximum acceleration.
[tex]20=\omega^{2}*4[/tex]
[tex]\omega=2.24 rad/s[/tex]
The period is given by:
[tex]T=\frac{2\pi}{\omega}[/tex]
[tex]T=\frac{2\pi}{2.24}[/tex]
Therefore, the period will be T=2.81 s.
I hope it helps you!
A pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s, therefore the pig is __________during the next 2 seconds.
Question 7 options:
moving faster in the negative direction
moving faster in the positive direction
moving slower in the positive direction
moving slower in the in the negative direction
Answer:
Moving slower in the negative direction.
Explanation:
This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.
motion is a change in
Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .
Answer:
The value is [tex]L = 0.0073 \ H[/tex]
Explanation:
From the question we are told that
The number of turns is [tex]N = 650 \ turns[/tex]
The length is [tex]l = 28 \ cm = 0.28 \ m[/tex]
The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]
Generally the cross-sectional area is mathematically represented as
[tex]A = \pi * r^2[/tex]
=> [tex]A = 3.142 * 0.035^2[/tex]
=> [tex]A = 0.00384 \ m^2[/tex]
Generally the inductance is mathematically represented as
[tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]
=> [tex]L = 0.0073 \ H[/tex]
A stunt man drives a car at a speed of 20m/s off a 30-m-high cliff. The road leading to the cliff is inclined upward at an angle of 20 degrees. How far from the base of the cliff does the car land?
The car lands at a distance of 60 m from the base of the cliff.
s = ut + 1 / 2 a[tex]t^{2}[/tex]
s = Displacement
u = Initial velocity
t =Time
a = Acceleration
u = 20 m / s
[tex]s_{y}[/tex] = 30 m
θ = 20°
g = 9.8 m / s²
Resolving the velocity into its horizontal and vertical components
sin θ = [tex]u_{y}[/tex] / u
[tex]u_{y}[/tex] = - 20 sin 20°
[tex]u_{y}[/tex] = - 6.84 m / s
Considering only the vertical components,
[tex]s_{y}[/tex] = [tex]u_{y}[/tex] t + 1 / 2 g t²
30 = - 6.84 t + 4.9 t²
4.9 t² + ( - 6.84 ) t - 30 = 0
This is in the form of a quadratic equation,
t = - ( - 6.84 ) + √ [ ( - 6.84 )² - ( 4 * 4.9 * ( - 30 ) ) ] / 2 ( 4.9 )
t = 3.2 sec
The distance we need to calculate is in horizontal direction,
[tex]v_{x}[/tex] = [tex]s_{x}[/tex] / t
[tex]s_{x}[/tex] = 20 cos 20° / 3.2
[tex]s_{x}[/tex] = 60 m
Therefore, the car lands at a distance of 60 m from the base of the cliff.
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The mass of an electron is 9.11 x 10-31 kg. If you want to increase the speed of the
electron from 90% of the speed of light to 95% of the speed of light (where the
speed of light is 2.997x108 m/s), the amount of work that must be done is:
8.2 x 10-13)
0 3.2× 10-13 ,
O 2.6% 10-13 ,
O 7.4× 10-14 ,
3.8 x 10-15)
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